David J. Starling Penn State Hazleton PHYS 212

Size: px

Start display at page:

Download "David J. Starling Penn State Hazleton PHYS 212"

Myron Harmon
7 years ago
Views:

1 and and The term inductance was coined by Oliver Heaviside in February David J. Starling Penn State Hazleton PHYS 212

2 and and Objectives (a) Determine the EMF and electric field induced by a changing magnetic flux and determine the direction of this induced EMF. (b) Calculate and explain the process of self- and mutual-inductance of circuits. Relate mutual inductance to the design of a transformer. (c) Describe the behavior of an RL circuit and determine the characteristic time constant for the system. (d) Calculate the energy in a magnetic field or a magnetic dipole in an external field.

3 and We have seen electric flux: Φ E = E d A But we can define the magnetic flux in the same way: Φ B = B d A This is the flux through a loop of wire If B is uniform and perpendicular to the loop: Φ B = BA Magnetic flux has units of T m 2, also called the weber (Wb)

4 Question 1 The ring is rotated clockwise at a constant rate. Which graph best represents Φ B? and

5 What happens if I increase the flux through some loop? and Current flows in the wire! The faster we change the flux, the bigger the current We induce an emf E in the loop: E = dφ B dt

6 and What if there are N turns in my loop (solenoid)? Each turn has an induced emf, so we get: E = N dφ B dt We can change Φ B by Increasing/decreasing the magnetic field B Increasing/decreasing the area A Changing the tilt between B and A

7 and Example 1 A solenoid with 220 turns/cm carries a current of 1.5 A. The current is steadily dropped to 0 over 25 ms. What is the magnitude of the induced emf in the coil C (diameter 2.1 cm and 130 turns) that sits inside the solenoid?

8 The induced emf in a loop is due to an electric field pushing charges around! Work done: W = qe Also work done: W = F d s = q E d s Therefore: E = E d s So Faraday s Law becomes: E = E d s = dφ B dt and

9 Example 2 For the copper loop in the figure below, (a) find the magnitude of the induced electric field E at a position r for a uniform, time-dependent magnetic field; (b) find E when r = 5.2 cm and db/dt = 0.13 T/s. and

10 So what s with the negative sign? The change in flux induces a current The induced current creates a magnetic field This induced magnetic field fights the change in flux There is an opposition to the change E = dφ B dt and

11 and For an increasing B field For a decreasing B field

12 Question 2 A coil of wire approaches a long current at a constant speed. and (a) A current is induced in the coil. (b) The rectangle will be pulled in the direction of the current in the wire. (c) A magnetic force acts on the loop that pushes the loop into the page. (d) There is no effect on the coil.

13 Example 3 A half-circle of radius r = 0.2 m lies in a uniform magnetic field that varies in time according to B = 4t 2 + 2t + 3 (B in T, t in sec), out of the page. The circuit is connected to a 2 V battery and has a total resistance of 2 Ω. and (a) What is the induced emf at t = 10 s? (b) What is the current in the loop at t = 10 s?

14 Example 4 A rectangular wire loop with height H = 2.0 m and width W = 3.0 m is subjected to a non-uniform magnetic field B = 4t 2 x 2 in S.I. units. Find the induced emf in the loop at time t = 0.10 s. and

15 When we put a solenoid in a circuit, how does the circuit behave? If we pass a current through a solenoid, it produces a magnetic field, B = µ 0 ni The flux through the solenoid is Φ B = BA If the solenoid has N loops, the total flux through the whole solenoid is NΦ B, called magnetic flux linkage The ratio of this total flux to the current is the inductance L: Compare to C: L = NΦ B i and C = q V

16 and For an ideal solenoid, L = NΦ B i = (nl)(ba) i = nl(µ 0ni)A i = µ 0 n 2 la The inductance has units of T-m 2 /A, which we call a henry (H). Let s apply Faraday s Law to an inductor: E = d(nφ B) dt = d(li) dt = L di dt Apparently, an inductor produces its own emf This is called self inductance

17 In a circuit, an inductor acts similarly to a battery, producing an emf E(t) = L di/dt; we include it in the loop rule. and E ir L di dt = 0 di dt + R L i = E L What is i?

18 Charging up the current: The solution to di dt + R L i = E L and is i(t) = E R ( ) 1 e t/τ L τ L = L/R. Compare to the RC circuit: V = E ( 1 e t/τ )

19 Dis-charging the current: and The solution to di dt + R L i = 0 is i(t) = E R e t/τ L τ L = L/R. Compare to the RC circuit: V = Ee t/τ

20 and Key points: The inductor is slow to react Initially, the current is zero Eventually, it provides no resistance This process is exponential with τ = L/R

21 Example 5 In the circuit below, E = 18 V, R = 9.0 Ω and L = 2.0 mh. (a) Just after the switch is thrown, what is the total current in the circuit? (b) A long time later, what is the total current in the circuit? and

22 and Example 6 A solenoid with L = 53 mh and R = 0.37 Ω is connected to a battery. How long will it take for the current to reach half its final equilibrium value?

23 Consider a loop of wire being pushed at a speed v: and An emf is induced in the loop E = dφ B /dt = d(blx)/dt = BLdx/dt = BLv The resulting current is i = E/R = BLv/R The resulting force is F = ilb sin(90 ) = B 2 L 2 v/r Power is just P = Fv, so P = B2 L 2 v 2 R

24 and In fact, even if it s just a slab of metal, this emf still generates currents: These are called eddy-currents The eddy currents cause a force to oppose the motion

25 What if we put two coils next to each other? and The magnetic field from coil 1 changes the flux through coil 2 Φ 21 This induces a current in coil 2 This is called mutual inductance: M = N 2Φ 21 i 1 = N 1Φ 12 i 2

26 and The mutual inductance gives rise to an induced emf: M = N 2Φ 21 i 1 = N 1Φ 12 i 2 E 2 = M di 1 dt E 1 = M di 2 dt

27 Question 3 In each of the three cases shown, a time-varying current is flowing through the larger coil that produces a magnetic field. Which orientation has the largest mutual inductance? and (a) Case A (b) Case B (c) Case C (d) All the same (e) Not enough information

28 and Example 7 Two coils are fixed in place. When coil 1 has no current and the current in coil 2 increases at a rate of 15.0 A/s, the emf in coil 1 is 25.0 mv. (a) What is their mutual inductance? (b) When coil 2 has no current and coil 1 has a current of 3.60 A, what is the flux linkage in coil 2?

Direction of Induced Current

Direction of Induced Current Bar magnet moves through coil Current induced in coil A S N v Reverse pole Induced current changes sign B N S v v Coil moves past fixed bar magnet Current induced in coil as