APPLIED THERMODYNAMICS TUTORIAL 2 GAS COMPRESSORS

Size: px
Start display at page:

Download "APPLIED THERMODYNAMICS TUTORIAL 2 GAS COMPRESSORS"

Transcription

1 APPLIED HERMODYNAMICS UORIAL GAS COMPRESSORS I order to omlete this tutorial you should be familiar with gas laws ad olytroi gas roesses. You will study the riiles of reiroatig omressors i detail ad some riiles of rotary omressors. O omletio you should be able to the followig. Desribe the workig riiles of reiroatig omressors. Defie ad alulate swet volume. Defie ad alulate volumetri effiiey. Defie ad alulate isothermal effiiey. Defie ad alulate idiated ower. Dtate the beefits of oolig. Calulate the heat rejeted through oolig. Defie ad alulate the iterstage ressures for multile omressors. Defie olytroi effiiey. Let s start by osiderig the geeral use of omressed air. D.J.Du

2 . COMPRESSED AIR. YPES Air is a exasive substae ad dagerous whe used at high ressures. For this reaso, most aliatios are ofied to thigs requirig low ressures (0 bar or lower) but there are idustrial uses for high ressure air u to 00 bar. he ommo soure of the air is the omressor. here are may tyes of omressors with differet workig riiles ad workig oditios. hese are examles. Reiroatig. Slidig vae omressors. Lobe omressors. Helial srews. Cetrifugal. Axial turbie omressors. he futio of all of them is to draw i air from the atmoshere ad rodue air at ressures substatially higher. Usually a storage vessel or reeiver is used with the omressor. he same riiles are alied to the omressio of other gasses. his tutorial is maily about reiroatig omressors. he other tyes are overed briefly. he reiroatig omressor is robably the most versatile of all the tyes ad is oly out erformed by rotary tyes whe large volumes at low ressures are required. For high ressures, the reiroatig omressor is almost uiversal.. AMOSPHERIC APOUR Air ad vaour mixtures are overed i detail i a later tutorial. We should ote, however, the effets it has o the erformae of a air omressor. Atmosheri air otais WAER APOUR mixed with the other gases. Whe the air is ooled to the dew oit, the vaour odeses ito water ad we see rai or fog. he ratio of the mass of water vaour i the air to the mass of the air is alled the ABSOLUE HUMIDIY. he quatity of water that a be absorbed ito the air at a give ressure deeds uo the temerature. he hotter the air, the more water it a evaorate. Whe the air otais the maximum ossible amout of vaour it is at its dew oit ad rai or fog will aear. he air is the said to have 00% humidity. Whe the air otais o water vaour at all (dry air), it has 0% humidity. his refers to RELAIE HUMIDIY. For examle if the air has 0% humidity it meas that it otais 0% of the maximum that it ould otai. here are various ways to determie the humidity of air ad istrumets for doig this are alled HYGROMEERS. he imortae of humidity to air omressors is as follows. Whe air is suked ito the omressor, it brigs with it water vaour. Whe the air is omressed the ressure ad the temerature of the air goes u ad the result is that the omressed air will have a relative humidity of about 00% ad it will be warm. Whe the air leaves the omressor it will ool dow ad the water vaour will odese. Water will the log the omressor, the reeiver ad the ies. D.J.Du

3 Water auses damage to air tools, ruis ait srays ad orrodes ies ad equimet. For this reaso the water must be removed ad the best way is to use a well desiged omressor istallatio ad distributio etwork.. YPICAL COMPRESSOR LAYOU he diagram below shows the layout of a two stage reiroatig omressor tyially for sulyig a worksho. Figure. Idutio box ad sileer o outside of buildig with ourse sree.. Idutio filter.. Low ressure stage.. Iterooler. 5. High ressure stage. 6. Sileer. 7. Drai tra. 8. After ooler 9. Pressure gauge. 0. Air reeiver.. Safety ressure relief valve.. Sto valve. FREE AIR DELIERY Whe a gas suh as air flows i a ie, the mass of the air deeds uo the ressure ad temerature. It would be meaigless to talk about the volume of the air uless the ressure ad temerature are osidered. For this reaso the volume of air is usually stated as FREE AIR DELIERY or FAD. FAD refers to the volume the air would have if let out of the ie ad retured to atmosheri ressure at the same temerature. he FAD is the volume of air draw ito a omressor from the atmoshere. After omressio ad oolig the air is retured to the origial temerature but it is at a higher ressure. Suose atmosheri oditios are aa ad a (the FAD) ad the omressed oditios are, ad. D.J.Du

4 Alyig the gas law we have a aa a a a F. A. D.. CYCLE FOR RECIPROCAING COMPRESSOR. HEOREICAL CYCLE he diagram shows the basi desig of a reiroatig omressor. he isto reiroates drawig i gas, omressig it ad exellig it whe the ressure iside the ylider reahes the same level as the ressure i the delivery ie. Figure If the isto exels all the air ad there is o restritio at the valves, the ressure - volume yle is as show below. Figure Gas is idued from to at the ilet ressure. It is the traed iside the ylider ad omressed aordig the law C. At oit the ressure reahes the same level as that i the delivery ie ad the outlet valve os oe. Air is the exelled at the delivery ressure. he delivery ressure might rise very slightly durig exulsio if the gas is beig omated ito a fixed storage volume. his is how ressure builds u from swith o. D.J.Du

5 . OLUMERIC EFFICIENCY I reality, the isto aot exel all the gas ad a learae volume is eeded betwee the isto ad the ylider head. his meas that a small volume of omressed gas is traed i the ylider at oit. Whe the isto moves away from the ylider head, the omressed gas exads by the law C util the ressure falls to the level of the ilet ressure. At oit the ilet valve oes ad gas is draw i. he volume draw i from to is smaller tha the swet volume beause of this exasio. Figure he volumetri effiiey is defied as Idued olume vol Swet olume his effiiey is made worse if leaks our ast the valves or isto. he learae ratio is defied as Clearae volume/swet volume. Ideally the roess to ad to are isothermal. hat is to say, there is o temerature hage durig idutio ad exulsio. D.J.Du 5

6 WORKED EXAMPLE No. Gas is omressed i a reiroatig omressor from bar to 6 bar. he FAD is dm /s. he learae ratio is he exasio art of the yle follows the law. C. he rak seed is 60 rev/mi. Calulate the swet volume ad the volumetri effiiey. SOLUION Swet olume Clearae volume 0.05 Cosider the exasio from to o the - diagram. bar 6 bar... 6(0.05). (. ) 0. or.%% of F.A.D. 0.0 m/s. Idued volume Idued volume / m/s Crak seed 6 rev/s so the swet volume 0.057/6.6 dm vol Idued olume Swet olume 0.88 vol 8.8 % D.J.Du 6

7 D.J.Du 7 WORKED EXAMPLE No. Show that if the learae ratio of a ideal sigle stage reiroatig omressor is that the volumetri effiiey is give by ) / ( L H vol where L is the ilet ressure ad H the outlet ressure. SOLUION Swet volume Idued volume - Clearae volume ( ) ( ) / / / / / L H vol L H vol L H vol L H vol vol

8 I real omressors the warm ylider auses a slight temerature rise over the idutio from to. he gas is restrited by the valves ad is slightly less tha. he valves also ted to move so the real yle looks more like this. Figure 5 D.J.Du 8

9 WORKED EXAMPLE No. A sigle stage reiroatig omressor rodues a FAD of dm /s at 0 rev/mi. he ilet oditios are bar ad 0 o C. he olytroi idex is. for the omressio ad exasio. he outlet ressure is 8 bar. he learae volume is 0 m. Due to the restritio of the ilet valve ad the warmig effet of the ylider walls, the ressure at the start of omressio is 0.97 bar ad the temerature is 7 o C. Determie the volumetri effiiey. SOLUION Beause the idutio stroke is either at ostat ressure or ostat temerature, we must solve the swet volume by usig the exulsio stroke, whih is assumed to be at ostat ressure ad temerature. he umbers of the yle oits are as before K 0.97 x60 F. A. D. er stroke dm er stroke xaH he omressed volume exelled Exulsio volume 8x dm x 8x dm 0.. hee. Idued volume Swet volume vol % xx. 0.05dm 8x dm 0.06 dm 0.5 dm a H D.J.Du 9

10 D.J.Du 0. INDICAED POWER he idiated work er yle is the area elosed by the - diagram. he easiest way to fid this is by itegratig with reset to the ressure axis. Figure 6 he roesses to ad to are olytroi C. C / -/ C / Cosider the exressio ) ( ) ( ) / ( / / / / / / C d C d Betwee the limits of ad this beomes ( ) Betwee the limits ad this beomes ( ) he idiated work (iut) is the W ( ) ( ) r r W W W Where r is the ressure ratio. Sie this redues to [ ] r W. Where - is the swet volume.

11 If the learae volume is egleted this beomes W r Sie mr W mr r Note that if the roess was isothermal ad the the itegratio would yield W mr l ( / ) m is the mass omressed eah yle ad W is the idiated work er yle. he idiated ower is foud by multilyig W by the strokes er seod. I.P. W x N where N is the shaft seed i Rev/s If the learae volume is egleted, the mass omressed is the mass exelled. I this ase the atual mass flow rate delivered may be used for m ad W beomes the idiated ower.. ISOHERMAL EFFICIENCY he miimum idiated ower is obtaied whe the idex is a miimum. he ideal omressio is hee isothermal with. he isothermal effiiey is defied as (iso) Isothermal work/atual work ( ) l( / ) ( ) Note that i the ideal ase, ad are the ilet ad outlet temeratures. D.J.Du

12 SELF ASSESSMEN EXERCISE No. Show how the volumetri effiiey of a ideal sigle stage reiroatig air omressor may be rereseted by the equatio vol ( / ) H L Where is the learae ratio, H the delivery ressure ad L the idutio ressure. A reiroatig air omressor followig the ideal yle has a free air delivery of 60 dm /s. he learae ratio is he ilet is at atmosheri ressure of bar. he delivery ressure is 7 bar ad the omressio is olytroi with a idex of.. Calulate the followig. i. he ideal volumetri effiiey. (8.7%) ii. he ideal idiated ower. (.7 kw) D.J.Du

13 . MULIPLE COMPRESSOR SAGES. HE EFFEC OF INERCOOLING he advatage of omressig the fluid i stages is that iteroolers may be used ad the overall omressio is earer to beig isothermal. Cosider the - diagram for a two stage omressor. Figure 7 he yle to is a ormal yle oduted betwee L ad M. he air is exelled durig roess to at M ad ostat temerature. he air is the ooled at the itermediate ressure ad this auses a otratio i the volume so that the volume eterig the high ressure stage is 5 ad ot. he high ressure yle is the a ormal yle oduted betwee M ad H. he shaded area of the diagram reresets the work saved by usig the iterooler. he otimal savig is obtaied by hoosig the orret itermediate ressure. his may be foud as follows.. OPIMAL INERSAGE PRESSURE W W + W where W is the work doe i the low ressure stage ad W is the work doe i the high ressure stage. mr( - ) mr(6-5 ) W + ( -) ( -) (-/) (-/) 6 Sie ad the assumig the same value of for eah stage 6 W mr + mr ( -) ( -) ( / ) ( / ) 6 5 D.J.Du

14 Sie dw mr d ( / ) ( / ) ( )/ / ( ) / ( )/ L m M - mr H M 6 H W mr + mr ( -) L ( -) M For a miimum value of W we differetiate with reset to ad equate to zero. M 5 ad 6 5 H ad M If the iterooler returs the air to the origial ilet temerature so that 5, the equatig to zero reveals that for miimum work M ( L H ) ½ It a further be show that whe this is the ase, the work doe by both stages are equal. Whe K stages are used, the same roess reveals that the miimum work is doe whe the ressure ratio for eah stage is ( L / H ) /K L M D.J.Du

15 WORKED EXAMPLE No.5 A sigle atig reiroatig omressor rus at 60 rev/mi ad takes i air at bar ad 5 o C ad omresses it i stages to 6 bar. he free air delivery is m /s. here is a iterooler betwee eah stage, whih returs the air to 5 o C. Eah stage has oe isto with a stoke of 00 mm. Calulate the followig. he ideal iterstage ressure. he ideal idiated ower er stage. he heat rejeted from eah ylider. he heat rejeted from eah iterooler. he isothermal effiiey. he swet volume of eah stage. he bore of eah ylider. Igore leakage ad the effet of the learae volume. he idex of omressio is. for all stages. SOLUION Pressure ratio for eah stage (6/) / Hee the ressure after stage is x bar. he ressure after the seod stage is x 6 bar he fial ressure is 6 x 6 bar. 88 K. m /R x 0 5 x /(87 x 88) kg/s 88() 0./ K he idiated ower for eah stage is the same so it will be alulated for the st. stage. - mr I. P. x sie m is the mass omressed x 87 x. x 88. I. P. 96 Watts. - D.J.Du 5

16 CYLINDER COOLING Cosider the eergy balae over the first stage. Balaig the eergy we have Figure 8 H A + P(i) H B + Φ (out) Φ (out) P(i) - mc( B - A ) Φ (out) x.005 ( ) Φ (out).78 kw (rejeted from eah ylider) INERCOOLER Now osider the Iterooler. No work is doe ad the temerature is ooled from to 5. Φ (out) mc( - 5) x.005 ( ) 7.9 kw ISOHERMAL EFFICIENCY he ideal isothermal ower mrl(/) er stage. P(isothermal) x 87 x 88 l 7.86 kw (iso) 7.86/ % SWEP OLUMES Cosider the first stage. he F.A.D. is m /s. I the ideal ase where the air is draw i at ostat temerature ad ressure from the atmoshere, the FAD is give by FAD Swet olume x Seed ad the seed is 6 rev/s D.J.Du 6

17 Hee S.. (st. Stage) / m S.. Bore Area x Stroke π D / x 0. D 0.7 m. Now osider the seod stage. he air is retured to atmosheri ressure at ilet with a ressure of bar. he volume draw is hee / of the origial FAD. he swet volume of the seod stage is hee 0.009/ m π D / x 0. hee D 0.7 m By the same reasoig the swet volume of the third stage is S(rd stage) 0.009/ m π D / x 0. D m D.J.Du 7

18 SELF ASSESSMEN EXERCISE No.. A sigle atig stage omressor draws i 8.5 m /mi of free air ad omresses it to 0 bar. he omressor rus at 00 rev/mi. he atmosheri oditios are.0 bar ad 5 0 C. here is a iterooler betwee stages whih ools the air bak to 5 o C. he olytroi idex for all omressios is.. he volumetri effiiey is 90% for the low ressure stage ad 85% for the high ressure stage. Igore the effet of the learae volume. Calulate the followig. he itermediate ressure for miimum idiated work. (6.65 bar) he theoretial idiated ower for eah stage. (.85 kw) he heat rejeted i eah ylider. (6. kw) he heat rejeted by the iterooler. (6.5 kw) he swet volumes of both stages. (. dm ad 5. dm ) What advatage is there i usig a after-ooler? State the effet o your aswers of ot igorig the learae volume ad leakages.. A sigle atig stage omressor draws i free air ad omresses it to 8.5 bar. he omressor rus at 600 rev/mi. he atmosheri oditios are.0 bar ad 5 o C. he iterstage ressure is bar ad the iterooler ools the air bak to 0 o C. he olytroi idex for all omressios is.8. Due to the effet of warmig from the ylider walls ad the ressure loss i the ilet valve, the ressure ad temerature at the start of the low ressure omressio stroke is 0.96 bar ad 5 o C. he high ressure yle may be take as ideal. he learae volume for eah stages is % of the swet volume of that stage. he low ressure ylider is 00 mm diameter ad the stroke for both stages is 60 mm. Calulate the followig. he free air delivery. (5.858m /mi) he volumetri effiiey of the low ressure stage. (86. %) he diameter of the high ressure ylider. (7 mm) he idiated ower for eah stage. (.6 kw ad. kw) D.J.Du 8

19 . A stage reiroatig air omressor has a iterooler betwee stages. he idutio ad exulsio for both stages are at ostat ressure ad temerature. All the omressios ad exasios are olytroi. Negletig the effet of the learae volume show that the itermediate ressure, whih gives miimum, idiated work is M ( L H ) ½ Exlai with the aid of a sketh how the delivery temerature from both yliders varies with the itermediate ressure as it hages from L to H..a. Prove that the ideal volumetri effiiey of a sigle stage reiroatig omressor is vol - (r/-) r is the ressure ratio, is the olytroi idex ad the learae ratio. Sketh urves of vol agaist r for tyial values of ad. b. A two stage reiroatig air omressor works betwee ressure limits of ad 0 bar. he ilet temerature is 5oC ad the olytroi idex is.. Iteroolig betwee stages redues the air temerature bak to 5oC. Fid the free air delivery ad mass of air that a be omressed er kw h of work iut. (0.06 m/kw h.7 kg/kw h) Fid the ratio of the ylider diameters if the isto have the same stroke. Neglet the effet of the learae volume. (d/d 0.7) D.J.Du 9

20 . POLYROPIC or SMALL SAGE EFFICIENCY his is a alterative way of aroahig isetroi effiiey. I this method, the omressio is suosed to be made u of may stages, eah raisig the ressure a small amout. he theory alies to ay tye of omressor. For a adiabati gas omressio the law of omressio ad the gas law may be ombied. d C Divide by d d C d d C d d d Sie differetiate ad C For a isetroi omressio, let the fial temerature be desigated ' ad the hage i temerature be '. d ' + d d...() Isetroi effiiey ad + d ' Figure 9 Let the hage be ifiitesimally smallsuh that ' d ' he ratio is desigated d is alled the POLYROPIC EFFICIENCY. ' D.J.Du 0

21 D.J.Du If we thik of the omressio as beig made u of may tiy stes eah with the same value of. l l ' ' d d Itegrate d d d d d d is the startig temerature ad is the fial temerature. he overall effiiey is 0 ' as exeted. with Comarig SUBSIUE PROCESS POLYROPIC PROCESS ADIABAIC ' ' ' ' r r r r r r r r r r r O his theory may be alied to exasios as well as omressios. It may also be alied to exasios i ozzles. I steam work, it is more usual to use the REHEA FACOR, whih is based o the same riile.

22 WORKED EXAMPLE 6 A omressor draws i air at 5 o C ad 0. bar. he air is omressed to.6 bar with a olytroi effiiey of Determie the temerature ad the isetroi effiiey. ake. SOLUION (0.86) 88 ' 88(5.) is ( 5.) K 6.5K D.J.Du

23 SELF ASSESSMEN EXERCISE No.. Show that for ay omressio roess the overall effiiey is give by r O r where is the olytroi effiiey. Determie the idex of omressio for a gas with a adiabati idex of. ad a olytroi effiiey of 0.9. (.65) Determie the overall effiiey whe the ressure omressio ratio is / ad 8/. (0.879 ad 0.866). A omressor draws i air at. K temerature ad 0.65 bar ressure. he omressio ratio is 6. he olytroi effiiey is Determie the temerature after omressio. ake. (05 K) D.J.Du

3 Energy. 3.3. Non-Flow Energy Equation (NFEE) Internal Energy. MECH 225 Engineering Science 2

3 Energy. 3.3. Non-Flow Energy Equation (NFEE) Internal Energy. MECH 225 Engineering Science 2 MECH 5 Egieerig Sciece 3 Eergy 3.3. No-Flow Eergy Equatio (NFEE) You may have oticed that the term system kees croig u. It is ecessary, therefore, that before we start ay aalysis we defie the system that

More information

RECIPROCATING COMPRESSORS

RECIPROCATING COMPRESSORS RECIPROCATING COMPRESSORS There are various compressor desigs: Rotary vae; Cetrifugal & Axial flow (typically used o gas turbies); Lobe (Roots blowers), ad Reciprocatig. The mai advatages of the reciprocatig

More information

The dimensionless compressibility factor, Z, for a gaseous species is defined as the ratio

The dimensionless compressibility factor, Z, for a gaseous species is defined as the ratio Chater 3 3.4- The Comressibility Fator Equatio of State The dimesioless omressibility fator, Z, for a gaseous seies is defied as the ratio Z = (3.4-1) If the gas behaes ideally Z = 1. The extet to whih

More information

SOLID MECHANICS DYNAMICS TUTORIAL DAMPED VIBRATIONS. On completion of this tutorial you should be able to do the following.

SOLID MECHANICS DYNAMICS TUTORIAL DAMPED VIBRATIONS. On completion of this tutorial you should be able to do the following. SOLID MECHANICS DYNAMICS TUTORIAL DAMPED VIBRATIONS This work overs elemets of the syllabus for the Egieerig Couil Eam D5 Dyamis of Mehaial Systems, C05 Mehaial ad Strutural Egieerig ad the Edeel HNC/D

More information

EDEXCEL NATIONAL CERTIFICATE/DIPLOMA. PRINCIPLES AND APPLICATIONS of THERMODYNAMICS NQF LEVEL 3 OUTCOME 1 -EXPANSION AND COMPRESSION OF GASES

EDEXCEL NATIONAL CERTIFICATE/DIPLOMA. PRINCIPLES AND APPLICATIONS of THERMODYNAMICS NQF LEVEL 3 OUTCOME 1 -EXPANSION AND COMPRESSION OF GASES EDEXCEL NAIONAL CERIFICAE/DIPLOMA PRINCIPLES AND APPLICAIONS of HERMODYNAMICS NQF LEEL 3 OUCOME -EXPANSION AND COMPRESSION OF GASES CONEN Be able to aly thermodyamic riciles to the exasio ad comressio

More information

APPLIED THERMODYNAMICS TUTORIAL 1 REVISION OF ISENTROPIC EFFICIENCY ADVANCED STEAM CYCLES

APPLIED THERMODYNAMICS TUTORIAL 1 REVISION OF ISENTROPIC EFFICIENCY ADVANCED STEAM CYCLES APPLIED HERMODYNAMICS UORIAL REVISION OF ISENROPIC EFFICIENCY ADVANCED SEAM CYCLES INRODUCION his tutorial is designed for students wishing to extend their knowledge of thermodynamics to a more advanced

More information

APPLIED THERMODYNAMICS. TUTORIAL No.3 GAS TURBINE POWER CYCLES. Revise gas expansions in turbines. Study the Joule cycle with friction.

APPLIED THERMODYNAMICS. TUTORIAL No.3 GAS TURBINE POWER CYCLES. Revise gas expansions in turbines. Study the Joule cycle with friction. APPLIED HERMODYNAMICS UORIAL No. GAS URBINE POWER CYCLES In this tutorial you will do the following. Revise gas expansions in turbines. Revise the Joule cycle. Study the Joule cycle with friction. Extend

More information

OUTCOME 1. TUTORIAL No. 2 THERMODYNAMIC SYSTEMS

OUTCOME 1. TUTORIAL No. 2 THERMODYNAMIC SYSTEMS UNI 6: ENGINEERING HERMODYNAMICS Unit code: D/60/40 QCF level: 5 Credit value: 5 OUCOME UORIAL No. HERMODYNAMIC SYSEMS. Understand the arameters and characteristics of thermodynamic systems Polytroic rocesses:

More information

Laws of Exponents. net effect is to multiply with 2 a total of 3 + 5 = 8 times

Laws of Exponents. net effect is to multiply with 2 a total of 3 + 5 = 8 times The Mathematis 11 Competey Test Laws of Expoets (i) multipliatio of two powers: multiply by five times 3 x = ( x x ) x ( x x x x ) = 8 multiply by three times et effet is to multiply with a total of 3

More information

CHAPTER 7: Central Limit Theorem: CLT for Averages (Means)

CHAPTER 7: Central Limit Theorem: CLT for Averages (Means) CHAPTER 7: Cetral Limit Theorem: CLT for Averages (Meas) X = the umber obtaied whe rollig oe six sided die oce. If we roll a six sided die oce, the mea of the probability distributio is X P(X = x) Simulatio:

More information

Example 2 Find the square root of 0. The only square root of 0 is 0 (since 0 is not positive or negative, so those choices don t exist here).

Example 2 Find the square root of 0. The only square root of 0 is 0 (since 0 is not positive or negative, so those choices don t exist here). BEGINNING ALGEBRA Roots ad Radicals (revised summer, 00 Olso) Packet to Supplemet the Curret Textbook - Part Review of Square Roots & Irratioals (This portio ca be ay time before Part ad should mostly

More information

Ekkehart Schlicht: Economic Surplus and Derived Demand

Ekkehart Schlicht: Economic Surplus and Derived Demand Ekkehart Schlicht: Ecoomic Surplus ad Derived Demad Muich Discussio Paper No. 2006-17 Departmet of Ecoomics Uiversity of Muich Volkswirtschaftliche Fakultät Ludwig-Maximilias-Uiversität Müche Olie at http://epub.ub.ui-mueche.de/940/

More information

Basic Elements of Arithmetic Sequences and Series

Basic Elements of Arithmetic Sequences and Series MA40S PRE-CALCULUS UNIT G GEOMETRIC SEQUENCES CLASS NOTES (COMPLETED NO NEED TO COPY NOTES FROM OVERHEAD) Basic Elemets of Arithmetic Sequeces ad Series Objective: To establish basic elemets of arithmetic

More information

THE REGRESSION MODEL IN MATRIX FORM. For simple linear regression, meaning one predictor, the model is. for i = 1, 2, 3,, n

THE REGRESSION MODEL IN MATRIX FORM. For simple linear regression, meaning one predictor, the model is. for i = 1, 2, 3,, n We will cosider the liear regressio model i matrix form. For simple liear regressio, meaig oe predictor, the model is i = + x i + ε i for i =,,,, This model icludes the assumptio that the ε i s are a sample

More information

Thermodynamics worked examples

Thermodynamics worked examples An Introduction to Mechanical Engineering Part hermodynamics worked examles. What is the absolute ressure, in SI units, of a fluid at a gauge ressure of. bar if atmosheric ressure is.0 bar? Absolute ressure

More information

Determining the sample size

Determining the sample size Determiig the sample size Oe of the most commo questios ay statisticia gets asked is How large a sample size do I eed? Researchers are ofte surprised to fid out that the aswer depeds o a umber of factors

More information

Building Blocks Problem Related to Harmonic Series

Building Blocks Problem Related to Harmonic Series TMME, vol3, o, p.76 Buildig Blocks Problem Related to Harmoic Series Yutaka Nishiyama Osaka Uiversity of Ecoomics, Japa Abstract: I this discussio I give a eplaatio of the divergece ad covergece of ifiite

More information

Soving Recurrence Relations

Soving Recurrence Relations Sovig Recurrece Relatios Part 1. Homogeeous liear 2d degree relatios with costat coefficiets. Cosider the recurrece relatio ( ) T () + at ( 1) + bt ( 2) = 0 This is called a homogeeous liear 2d degree

More information

In nite Sequences. Dr. Philippe B. Laval Kennesaw State University. October 9, 2008

In nite Sequences. Dr. Philippe B. Laval Kennesaw State University. October 9, 2008 I ite Sequeces Dr. Philippe B. Laval Keesaw State Uiversity October 9, 2008 Abstract This had out is a itroductio to i ite sequeces. mai de itios ad presets some elemetary results. It gives the I ite Sequeces

More information

GCSE STATISTICS. 4) How to calculate the range: The difference between the biggest number and the smallest number.

GCSE STATISTICS. 4) How to calculate the range: The difference between the biggest number and the smallest number. GCSE STATISTICS You should kow: 1) How to draw a frequecy diagram: e.g. NUMBER TALLY FREQUENCY 1 3 5 ) How to draw a bar chart, a pictogram, ad a pie chart. 3) How to use averages: a) Mea - add up all

More information

CHAPTER 11 Financial mathematics

CHAPTER 11 Financial mathematics CHAPTER 11 Fiacial mathematics I this chapter you will: Calculate iterest usig the simple iterest formula ( ) Use the simple iterest formula to calculate the pricipal (P) Use the simple iterest formula

More information

Lesson 17 Pearson s Correlation Coefficient

Lesson 17 Pearson s Correlation Coefficient Outlie Measures of Relatioships Pearso s Correlatio Coefficiet (r) -types of data -scatter plots -measure of directio -measure of stregth Computatio -covariatio of X ad Y -uique variatio i X ad Y -measurig

More information

The Reduced van der Waals Equation of State

The Reduced van der Waals Equation of State The Redued van der Waals Equation of State The van der Waals equation of state is na + ( V nb) n (1) V where n is the mole number, a and b are onstants harateristi of a artiular gas, and R the gas onstant

More information

1 Computing the Standard Deviation of Sample Means

1 Computing the Standard Deviation of Sample Means Computig the Stadard Deviatio of Sample Meas Quality cotrol charts are based o sample meas ot o idividual values withi a sample. A sample is a group of items, which are cosidered all together for our aalysis.

More information

SAMPLE QUESTIONS FOR FINAL EXAM. (1) (2) (3) (4) Find the following using the definition of the Riemann integral: (2x + 1)dx

SAMPLE QUESTIONS FOR FINAL EXAM. (1) (2) (3) (4) Find the following using the definition of the Riemann integral: (2x + 1)dx SAMPLE QUESTIONS FOR FINAL EXAM REAL ANALYSIS I FALL 006 3 4 Fid the followig usig the defiitio of the Riema itegral: a 0 x + dx 3 Cosider the partitio P x 0 3, x 3 +, x 3 +,......, x 3 3 + 3 of the iterval

More information

Solving Logarithms and Exponential Equations

Solving Logarithms and Exponential Equations Solvig Logarithms ad Epoetial Equatios Logarithmic Equatios There are two major ideas required whe solvig Logarithmic Equatios. The first is the Defiitio of a Logarithm. You may recall from a earlier topic:

More information

Your organization has a Class B IP address of 166.144.0.0 Before you implement subnetting, the Network ID and Host ID are divided as follows:

Your organization has a Class B IP address of 166.144.0.0 Before you implement subnetting, the Network ID and Host ID are divided as follows: Subettig Subettig is used to subdivide a sigle class of etwork i to multiple smaller etworks. Example: Your orgaizatio has a Class B IP address of 166.144.0.0 Before you implemet subettig, the Network

More information

Mathematical goals. Starting points. Materials required. Time needed

Mathematical goals. Starting points. Materials required. Time needed Level A1 of challege: C A1 Mathematical goals Startig poits Materials required Time eeded Iterpretig algebraic expressios To help learers to: traslate betwee words, symbols, tables, ad area represetatios

More information

Section 11.3: The Integral Test

Section 11.3: The Integral Test Sectio.3: The Itegral Test Most of the series we have looked at have either diverged or have coverged ad we have bee able to fid what they coverge to. I geeral however, the problem is much more difficult

More information

Unit 8: Inference for Proportions. Chapters 8 & 9 in IPS

Unit 8: Inference for Proportions. Chapters 8 & 9 in IPS Uit 8: Iferece for Proortios Chaters 8 & 9 i IPS Lecture Outlie Iferece for a Proortio (oe samle) Iferece for Two Proortios (two samles) Cotigecy Tables ad the χ test Iferece for Proortios IPS, Chater

More information

Unit 24: Applications of Pneumatics and Hydraulics

Unit 24: Applications of Pneumatics and Hydraulics Unit 24: Applications of Pneumatics and Hydraulics Unit code: J/601/1496 QCF level: 4 Credit value: 15 OUTCOME 2 TUTORIAL 1 HYDRAULIC PUMPS The material needed for outcome 2 is very extensive so there

More information

Definition. A variable X that takes on values X 1, X 2, X 3,...X k with respective frequencies f 1, f 2, f 3,...f k has mean

Definition. A variable X that takes on values X 1, X 2, X 3,...X k with respective frequencies f 1, f 2, f 3,...f k has mean 1 Social Studies 201 October 13, 2004 Note: The examples i these otes may be differet tha used i class. However, the examples are similar ad the methods used are idetical to what was preseted i class.

More information

ABSTRACT INTRODUCTION MATERIALS AND METHODS

ABSTRACT INTRODUCTION MATERIALS AND METHODS INTENATIONAL JOUNAL OF AGICULTUE & BIOLOGY 156 853/6/8 1 5 9 http://www.fspublishers.org Multiplate Peetratio Tests to Predit Soil Pressure-siage Behaviour uder etagular egio M. ASHIDI 1, A. KEYHANI AND

More information

Sequences and Series

Sequences and Series CHAPTER 9 Sequeces ad Series 9.. Covergece: Defiitio ad Examples Sequeces The purpose of this chapter is to itroduce a particular way of geeratig algorithms for fidig the values of fuctios defied by their

More information

Properties of MLE: consistency, asymptotic normality. Fisher information.

Properties of MLE: consistency, asymptotic normality. Fisher information. Lecture 3 Properties of MLE: cosistecy, asymptotic ormality. Fisher iformatio. I this sectio we will try to uderstad why MLEs are good. Let us recall two facts from probability that we be used ofte throughout

More information

Measures of Spread and Boxplots Discrete Math, Section 9.4

Measures of Spread and Boxplots Discrete Math, Section 9.4 Measures of Spread ad Boxplots Discrete Math, Sectio 9.4 We start with a example: Example 1: Comparig Mea ad Media Compute the mea ad media of each data set: S 1 = {4, 6, 8, 10, 1, 14, 16} S = {4, 7, 9,

More information

Lecture 4: Cauchy sequences, Bolzano-Weierstrass, and the Squeeze theorem

Lecture 4: Cauchy sequences, Bolzano-Weierstrass, and the Squeeze theorem Lecture 4: Cauchy sequeces, Bolzao-Weierstrass, ad the Squeeze theorem The purpose of this lecture is more modest tha the previous oes. It is to state certai coditios uder which we are guarateed that limits

More information

How to use what you OWN to reduce what you OWE

How to use what you OWN to reduce what you OWE How to use what you OWN to reduce what you OWE Maulife Oe A Overview Most Caadias maage their fiaces by doig two thigs: 1. Depositig their icome ad other short-term assets ito chequig ad savigs accouts.

More information

THE ARITHMETIC OF INTEGERS. - multiplication, exponentiation, division, addition, and subtraction

THE ARITHMETIC OF INTEGERS. - multiplication, exponentiation, division, addition, and subtraction THE ARITHMETIC OF INTEGERS - multiplicatio, expoetiatio, divisio, additio, ad subtractio What to do ad what ot to do. THE INTEGERS Recall that a iteger is oe of the whole umbers, which may be either positive,

More information

Confidence Intervals for One Mean

Confidence Intervals for One Mean Chapter 420 Cofidece Itervals for Oe Mea Itroductio This routie calculates the sample size ecessary to achieve a specified distace from the mea to the cofidece limit(s) at a stated cofidece level for a

More information

where: T = number of years of cash flow in investment's life n = the year in which the cash flow X n i = IRR = the internal rate of return

where: T = number of years of cash flow in investment's life n = the year in which the cash flow X n i = IRR = the internal rate of return EVALUATING ALTERNATIVE CAPITAL INVESTMENT PROGRAMS By Ke D. Duft, Extesio Ecoomist I the March 98 issue of this publicatio we reviewed the procedure by which a capital ivestmet project was assessed. The

More information

A Capacity Supply Model for Virtualized Servers

A Capacity Supply Model for Virtualized Servers 96 Iformatia Eoomiă vol. 3, o. 3/009 A apaity upply Model for Virtualized ervers Alexader PINNOW, tefa OTERBURG Otto-vo-Guerike-Uiversity, Magdeburg, Germay {alexader.piow stefa.osterburg}@iti.s.ui-magdeburg.de

More information

Unit 24: Applications of Pneumatics and Hydraulics

Unit 24: Applications of Pneumatics and Hydraulics Unit 24: Applications of Pneumatics and Hydraulics Unit code: J/601/1496 QCF level: 4 Credit value: 15 OUTCOME 2 TUTORIAL 3 HYDRAULIC AND PNEUMATIC MOTORS The material needed for outcome 2 is very extensive

More information

5.4 Amortization. Question 1: How do you find the present value of an annuity? Question 2: How is a loan amortized?

5.4 Amortization. Question 1: How do you find the present value of an annuity? Question 2: How is a loan amortized? 5.4 Amortizatio Questio 1: How do you fid the preset value of a auity? Questio 2: How is a loa amortized? Questio 3: How do you make a amortizatio table? Oe of the most commo fiacial istrumets a perso

More information

I. Why is there a time value to money (TVM)?

I. Why is there a time value to money (TVM)? Itroductio to the Time Value of Moey Lecture Outlie I. Why is there the cocept of time value? II. Sigle cash flows over multiple periods III. Groups of cash flows IV. Warigs o doig time value calculatios

More information

Lesson 15 ANOVA (analysis of variance)

Lesson 15 ANOVA (analysis of variance) Outlie Variability -betwee group variability -withi group variability -total variability -F-ratio Computatio -sums of squares (betwee/withi/total -degrees of freedom (betwee/withi/total -mea square (betwee/withi

More information

output voltage and are known as non-zero switching states and the remaining two

output voltage and are known as non-zero switching states and the remaining two SPACE ECTOR MODULATION FOR THREE-LEG OLTAGE SOURCE INERTERS.1 THREE-LEG OLTAGE SOURCE INERTER The toology of three-leg voltge soure iverter is show i Fig..1. Beuse of the ostrit tht the iut lies must ever

More information

AP Calculus BC 2003 Scoring Guidelines Form B

AP Calculus BC 2003 Scoring Guidelines Form B AP Calculus BC Scorig Guidelies Form B The materials icluded i these files are iteded for use by AP teachers for course ad exam preparatio; permissio for ay other use must be sought from the Advaced Placemet

More information

A probabilistic proof of a binomial identity

A probabilistic proof of a binomial identity A probabilistic proof of a biomial idetity Joatho Peterso Abstract We give a elemetary probabilistic proof of a biomial idetity. The proof is obtaied by computig the probability of a certai evet i two

More information

Confidence Intervals. CI for a population mean (σ is known and n > 30 or the variable is normally distributed in the.

Confidence Intervals. CI for a population mean (σ is known and n > 30 or the variable is normally distributed in the. Cofidece Itervals A cofidece iterval is a iterval whose purpose is to estimate a parameter (a umber that could, i theory, be calculated from the populatio, if measuremets were available for the whole populatio).

More information

INVESTMENT PERFORMANCE COUNCIL (IPC)

INVESTMENT PERFORMANCE COUNCIL (IPC) INVESTMENT PEFOMANCE COUNCIL (IPC) INVITATION TO COMMENT: Global Ivestmet Performace Stadards (GIPS ) Guidace Statemet o Calculatio Methodology The Associatio for Ivestmet Maagemet ad esearch (AIM) seeks

More information

Theorems About Power Series

Theorems About Power Series Physics 6A Witer 20 Theorems About Power Series Cosider a power series, f(x) = a x, () where the a are real coefficiets ad x is a real variable. There exists a real o-egative umber R, called the radius

More information

Estimating Probability Distributions by Observing Betting Practices

Estimating Probability Distributions by Observing Betting Practices 5th Iteratioal Symposium o Imprecise Probability: Theories ad Applicatios, Prague, Czech Republic, 007 Estimatig Probability Distributios by Observig Bettig Practices Dr C Lych Natioal Uiversity of Irelad,

More information

CHAPTER 3 THE TIME VALUE OF MONEY

CHAPTER 3 THE TIME VALUE OF MONEY CHAPTER 3 THE TIME VALUE OF MONEY OVERVIEW A dollar i the had today is worth more tha a dollar to be received i the future because, if you had it ow, you could ivest that dollar ad ear iterest. Of all

More information

Dilution Example. Chapter 24 Warrants and Convertibles. Warrants. The Difference Between Warrants and Call Options. Warrants

Dilution Example. Chapter 24 Warrants and Convertibles. Warrants. The Difference Between Warrants and Call Options. Warrants Chapter 24 Warrats ad Covertibles Warrats The Differece betee Warrats ad Call Optios Warrat Pricig ad the Black-Scholes Model Covertible Bods The Value of Covertible Bods Reasos for Issuig Warrats ad Covertibles

More information

INFINITE SERIES KEITH CONRAD

INFINITE SERIES KEITH CONRAD INFINITE SERIES KEITH CONRAD. Itroductio The two basic cocepts of calculus, differetiatio ad itegratio, are defied i terms of limits (Newto quotiets ad Riema sums). I additio to these is a third fudametal

More information

Mann-Whitney U 2 Sample Test (a.k.a. Wilcoxon Rank Sum Test)

Mann-Whitney U 2 Sample Test (a.k.a. Wilcoxon Rank Sum Test) No-Parametric ivariate Statistics: Wilcoxo-Ma-Whitey 2 Sample Test 1 Ma-Whitey 2 Sample Test (a.k.a. Wilcoxo Rak Sum Test) The (Wilcoxo-) Ma-Whitey (WMW) test is the o-parametric equivalet of a pooled

More information

The Fundamental Forces of Nature

The Fundamental Forces of Nature Gravity The Fudametal Forces of Nature There exist oly four fudametal forces Electromagetism Strog force Weak force Gravity Gravity 2 The Hierarchy Problem Gravity is far weaker tha ay of the forces! Why?!?

More information

WindWise Education. 2 nd. T ransforming the Energy of Wind into Powerful Minds. editi. A Curriculum for Grades 6 12

WindWise Education. 2 nd. T ransforming the Energy of Wind into Powerful Minds. editi. A Curriculum for Grades 6 12 WidWise Educatio T rasformig the Eergy of Wid ito Powerful Mids A Curriculum for Grades 6 12 Notice Except for educatioal use by a idividual teacher i a classroom settig this work may ot be reproduced

More information

Output Analysis (2, Chapters 10 &11 Law)

Output Analysis (2, Chapters 10 &11 Law) B. Maddah ENMG 6 Simulatio 05/0/07 Output Aalysis (, Chapters 10 &11 Law) Comparig alterative system cofiguratio Sice the output of a simulatio is radom, the comparig differet systems via simulatio should

More information

5 Boolean Decision Trees (February 11)

5 Boolean Decision Trees (February 11) 5 Boolea Decisio Trees (February 11) 5.1 Graph Coectivity Suppose we are give a udirected graph G, represeted as a boolea adjacecy matrix = (a ij ), where a ij = 1 if ad oly if vertices i ad j are coected

More information

.04. This means $1000 is multiplied by 1.02 five times, once for each of the remaining sixmonth

.04. This means $1000 is multiplied by 1.02 five times, once for each of the remaining sixmonth Questio 1: What is a ordiary auity? Let s look at a ordiary auity that is certai ad simple. By this, we mea a auity over a fixed term whose paymet period matches the iterest coversio period. Additioally,

More information

*The most important feature of MRP as compared with ordinary inventory control analysis is its time phasing feature.

*The most important feature of MRP as compared with ordinary inventory control analysis is its time phasing feature. Itegrated Productio ad Ivetory Cotrol System MRP ad MRP II Framework of Maufacturig System Ivetory cotrol, productio schedulig, capacity plaig ad fiacial ad busiess decisios i a productio system are iterrelated.

More information

REVIEW OF INTEGRATION

REVIEW OF INTEGRATION REVIEW OF INTEGRATION Trig Fuctios ad Itegratio by Parts Oeriew I this ote we will reiew how to ealuate the sorts of itegrals we ecouter i ealuatig Fourier series. These will iclude itegratio of trig fuctios

More information

Rainbow options. A rainbow is an option on a basket that pays in its most common form, a nonequally

Rainbow options. A rainbow is an option on a basket that pays in its most common form, a nonequally Raibow optios INRODUCION A raibow is a optio o a basket that pays i its most commo form, a oequally weighted average of the assets of the basket accordig to their performace. he umber of assets is called

More information

CS103X: Discrete Structures Homework 4 Solutions

CS103X: Discrete Structures Homework 4 Solutions CS103X: Discrete Structures Homewor 4 Solutios Due February 22, 2008 Exercise 1 10 poits. Silico Valley questios: a How may possible six-figure salaries i whole dollar amouts are there that cotai at least

More information

SECTION 1.5 : SUMMATION NOTATION + WORK WITH SEQUENCES

SECTION 1.5 : SUMMATION NOTATION + WORK WITH SEQUENCES SECTION 1.5 : SUMMATION NOTATION + WORK WITH SEQUENCES Read Sectio 1.5 (pages 5 9) Overview I Sectio 1.5 we lear to work with summatio otatio ad formulas. We will also itroduce a brief overview of sequeces,

More information

Unit 24: Applications of Pneumatics and Hydraulics

Unit 24: Applications of Pneumatics and Hydraulics Unit 24: Applications of Pneumatics and Hydraulics Unit code: J/601/1496 QCF level: 4 Credit value: 15 OUTCOME 2 TUTORIAL 2 HYDRAULIC AND PNEUMATIC CYLINDERS The material needed for outcome 2 is very extensive

More information

Hypothesis testing. Null and alternative hypotheses

Hypothesis testing. Null and alternative hypotheses Hypothesis testig Aother importat use of samplig distributios is to test hypotheses about populatio parameters, e.g. mea, proportio, regressio coefficiets, etc. For example, it is possible to stipulate

More information

Repeating Decimals are decimal numbers that have number(s) after the decimal point that repeat in a pattern.

Repeating Decimals are decimal numbers that have number(s) after the decimal point that repeat in a pattern. 5.5 Fractios ad Decimals Steps for Chagig a Fractio to a Decimal. Simplify the fractio, if possible. 2. Divide the umerator by the deomiator. d d Repeatig Decimals Repeatig Decimals are decimal umbers

More information

Practice Problems for Test 3

Practice Problems for Test 3 Practice Problems for Test 3 Note: these problems oly cover CIs ad hypothesis testig You are also resposible for kowig the samplig distributio of the sample meas, ad the Cetral Limit Theorem Review all

More information

University of California, Los Angeles Department of Statistics. Distributions related to the normal distribution

University of California, Los Angeles Department of Statistics. Distributions related to the normal distribution Uiversity of Califoria, Los Ageles Departmet of Statistics Statistics 100B Istructor: Nicolas Christou Three importat distributios: Distributios related to the ormal distributio Chi-square (χ ) distributio.

More information

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NATIONAL SENIOR CERTIFICATE GRADE MATHEMATICS P EXEMPLAR 04 MARKS: 50 TIME: 3 hours This questio paper cosists of 8 pages ad iformatio sheet. Please tur over Mathematics/P DBE/04 NSC Grade Eemplar INSTRUCTIONS

More information

Chapter 5: Inner Product Spaces

Chapter 5: Inner Product Spaces Chapter 5: Ier Product Spaces Chapter 5: Ier Product Spaces SECION A Itroductio to Ier Product Spaces By the ed of this sectio you will be able to uderstad what is meat by a ier product space give examples

More information

Chatpun Khamyat Department of Industrial Engineering, Kasetsart University, Bangkok, Thailand ocpky@hotmail.com

Chatpun Khamyat Department of Industrial Engineering, Kasetsart University, Bangkok, Thailand ocpky@hotmail.com SOLVING THE OIL DELIVERY TRUCKS ROUTING PROBLEM WITH MODIFY MULTI-TRAVELING SALESMAN PROBLEM APPROACH CASE STUDY: THE SME'S OIL LOGISTIC COMPANY IN BANGKOK THAILAND Chatpu Khamyat Departmet of Idustrial

More information

Bond Valuation I. What is a bond? Cash Flows of A Typical Bond. Bond Valuation. Coupon Rate and Current Yield. Cash Flows of A Typical Bond

Bond Valuation I. What is a bond? Cash Flows of A Typical Bond. Bond Valuation. Coupon Rate and Current Yield. Cash Flows of A Typical Bond What is a bod? Bod Valuatio I Bod is a I.O.U. Bod is a borrowig agreemet Bod issuers borrow moey from bod holders Bod is a fixed-icome security that typically pays periodic coupo paymets, ad a pricipal

More information

2-3 The Remainder and Factor Theorems

2-3 The Remainder and Factor Theorems - The Remaider ad Factor Theorems Factor each polyomial completely usig the give factor ad log divisio 1 x + x x 60; x + So, x + x x 60 = (x + )(x x 15) Factorig the quadratic expressio yields x + x x

More information

PENSION ANNUITY. Policy Conditions Document reference: PPAS1(7) This is an important document. Please keep it in a safe place.

PENSION ANNUITY. Policy Conditions Document reference: PPAS1(7) This is an important document. Please keep it in a safe place. PENSION ANNUITY Policy Coditios Documet referece: PPAS1(7) This is a importat documet. Please keep it i a safe place. Pesio Auity Policy Coditios Welcome to LV=, ad thak you for choosig our Pesio Auity.

More information

Domain 1: Designing a SQL Server Instance and a Database Solution

Domain 1: Designing a SQL Server Instance and a Database Solution Maual SQL Server 2008 Desig, Optimize ad Maitai (70-450) 1-800-418-6789 Domai 1: Desigig a SQL Server Istace ad a Database Solutio Desigig for CPU, Memory ad Storage Capacity Requiremets Whe desigig a

More information

AP Calculus AB 2006 Scoring Guidelines Form B

AP Calculus AB 2006 Scoring Guidelines Form B AP Calculus AB 6 Scorig Guidelies Form B The College Board: Coectig Studets to College Success The College Board is a ot-for-profit membership associatio whose missio is to coect studets to college success

More information

Case Study. Normal and t Distributions. Density Plot. Normal Distributions

Case Study. Normal and t Distributions. Density Plot. Normal Distributions Case Study Normal ad t Distributios Bret Halo ad Bret Larget Departmet of Statistics Uiversity of Wiscosi Madiso October 11 13, 2011 Case Study Body temperature varies withi idividuals over time (it ca

More information

CS103A Handout 23 Winter 2002 February 22, 2002 Solving Recurrence Relations

CS103A Handout 23 Winter 2002 February 22, 2002 Solving Recurrence Relations CS3A Hadout 3 Witer 00 February, 00 Solvig Recurrece Relatios Itroductio A wide variety of recurrece problems occur i models. Some of these recurrece relatios ca be solved usig iteratio or some other ad

More information

3. Greatest Common Divisor - Least Common Multiple

3. Greatest Common Divisor - Least Common Multiple 3 Greatest Commo Divisor - Least Commo Multiple Defiitio 31: The greatest commo divisor of two atural umbers a ad b is the largest atural umber c which divides both a ad b We deote the greatest commo gcd

More information

The following example will help us understand The Sampling Distribution of the Mean. C1 C2 C3 C4 C5 50 miles 84 miles 38 miles 120 miles 48 miles

The following example will help us understand The Sampling Distribution of the Mean. C1 C2 C3 C4 C5 50 miles 84 miles 38 miles 120 miles 48 miles The followig eample will help us uderstad The Samplig Distributio of the Mea Review: The populatio is the etire collectio of all idividuals or objects of iterest The sample is the portio of the populatio

More information

Incremental calculation of weighted mean and variance

Incremental calculation of weighted mean and variance Icremetal calculatio of weighted mea ad variace Toy Fich faf@cam.ac.uk dot@dotat.at Uiversity of Cambridge Computig Service February 009 Abstract I these otes I eplai how to derive formulae for umerically

More information

Trigonometric Form of a Complex Number. The Complex Plane. axis. ( 2, 1) or 2 i FIGURE 6.44. The absolute value of the complex number z a bi is

Trigonometric Form of a Complex Number. The Complex Plane. axis. ( 2, 1) or 2 i FIGURE 6.44. The absolute value of the complex number z a bi is 0_0605.qxd /5/05 0:45 AM Page 470 470 Chapter 6 Additioal Topics i Trigoometry 6.5 Trigoometric Form of a Complex Number What you should lear Plot complex umbers i the complex plae ad fid absolute values

More information

CHAPTER 3 DIGITAL CODING OF SIGNALS

CHAPTER 3 DIGITAL CODING OF SIGNALS CHAPTER 3 DIGITAL CODING OF SIGNALS Computers are ofte used to automate the recordig of measuremets. The trasducers ad sigal coditioig circuits produce a voltage sigal that is proportioal to a quatity

More information

Simple Annuities Present Value.

Simple Annuities Present Value. Simple Auities Preset Value. OBJECTIVES (i) To uderstad the uderlyig priciple of a preset value auity. (ii) To use a CASIO CFX-9850GB PLUS to efficietly compute values associated with preset value auities.

More information

TO: Users of the ACTEX Review Seminar on DVD for SOA Exam FM/CAS Exam 2

TO: Users of the ACTEX Review Seminar on DVD for SOA Exam FM/CAS Exam 2 TO: Users of the ACTEX Review Semiar o DVD for SOA Exam FM/CAS Exam FROM: Richard L. (Dick) Lodo, FSA Dear Studets, Thak you for purchasig the DVD recordig of the ACTEX Review Semiar for SOA Exam FM (CAS

More information

Research Article Sign Data Derivative Recovery

Research Article Sign Data Derivative Recovery Iteratioal Scholarly Research Network ISRN Applied Mathematics Volume 0, Article ID 63070, 7 pages doi:0.540/0/63070 Research Article Sig Data Derivative Recovery L. M. Housto, G. A. Glass, ad A. D. Dymikov

More information

over an MC-MOmni network when has a capacity gain of 2π θ

over an MC-MOmni network when has a capacity gain of 2π θ O the Capaity of Multi-Chael ireless Networks Usig Diretioal Ateas Hog-Nig Dai Ka-ig Ng Rayod Chi-ig og ad Mi-You u The Chiese Uiversity of Hog Kog, Hog Kog {hdai,kwg,wwog}@se.uhk.edu.hk Shaghai Jiao Tog

More information

Learning objectives. Duc K. Nguyen - Corporate Finance 21/10/2014

Learning objectives. Duc K. Nguyen - Corporate Finance 21/10/2014 1 Lecture 3 Time Value of Moey ad Project Valuatio The timelie Three rules of time travels NPV of a stream of cash flows Perpetuities, auities ad other special cases Learig objectives 2 Uderstad the time-value

More information

Handling. Collection Calls

Handling. Collection Calls Hadlig the Collectio Calls We do everythig we ca to stop collectio calls; however, i the early part of our represetatio, you ca expect some of these calls to cotiue. We uderstad that the first few moths

More information

Swaps: Constant maturity swaps (CMS) and constant maturity. Treasury (CMT) swaps

Swaps: Constant maturity swaps (CMS) and constant maturity. Treasury (CMT) swaps Swaps: Costat maturity swaps (CMS) ad costat maturity reasury (CM) swaps A Costat Maturity Swap (CMS) swap is a swap where oe of the legs pays (respectively receives) a swap rate of a fixed maturity, while

More information

LECTURE 13: Cross-validation

LECTURE 13: Cross-validation LECTURE 3: Cross-validatio Resampli methods Cross Validatio Bootstrap Bias ad variace estimatio with the Bootstrap Three-way data partitioi Itroductio to Patter Aalysis Ricardo Gutierrez-Osua Texas A&M

More information

Sole trader financial statements

Sole trader financial statements 3 Sole trader fiacial statemets this chapter covers... I this chapter we look at preparig the year ed fiacial statemets of sole traders (that is, oe perso ruig their ow busiess). We preset the fiacial

More information

Lecture 2: Karger s Min Cut Algorithm

Lecture 2: Karger s Min Cut Algorithm priceto uiv. F 3 cos 5: Advaced Algorithm Desig Lecture : Karger s Mi Cut Algorithm Lecturer: Sajeev Arora Scribe:Sajeev Today s topic is simple but gorgeous: Karger s mi cut algorithm ad its extesio.

More information

Math C067 Sampling Distributions

Math C067 Sampling Distributions Math C067 Samplig Distributios Sample Mea ad Sample Proportio Richard Beigel Some time betwee April 16, 2007 ad April 16, 2007 Examples of Samplig A pollster may try to estimate the proportio of voters

More information

Listing terms of a finite sequence List all of the terms of each finite sequence. a) a n n 2 for 1 n 5 1 b) a n for 1 n 4 n 2

Listing terms of a finite sequence List all of the terms of each finite sequence. a) a n n 2 for 1 n 5 1 b) a n for 1 n 4 n 2 74 (4 ) Chapter 4 Sequeces ad Series 4. SEQUENCES I this sectio Defiitio Fidig a Formula for the th Term The word sequece is a familiar word. We may speak of a sequece of evets or say that somethig is

More information