Question Bank. Calorimetry
|
|
- James Dixon
- 7 years ago
- Views:
Transcription
1 Calorimetry 1. Define the term heat. Ans. It is the sum total of kinetic and potential energy of all the molecules of a given substance. 2. Name the SI unit of heat. Ans. Joule (J) is the SI unit of heat. 3. Define temperature : Ans. The average kinetic energy of all the molecules of a given substance is called temperature. 4. State the SI unit of temperature. Ans. Kelvin (K) is the SI unit of temperature. 5. The temperature of a substance rises by 25 C. How much is the rise on kelvin scale and why? Ans. The rise on kelvin scale is 25 K. It is because, rise in temperature in C = rise in temperature in kelvin. 6. What is a calorimeter? Why is it made of copper? Give two reasons. Ans. A copper vessel along with copper stirrer used in the measurement of heat energy is called calorimeter. Calorimeter is made from copper because, (i) it takes the temperature of the contents within it very quickly. (ii) it has a very low specific heat capacity and hence takes very little amount of heat energy from the contents within it. 1
2 7. (a) Define : (i) Calorie, (ii) Kilocalorie. (b) How many calories are in one kilocalorie? (c) How many joules of energy are in : (i) one calorie, (ii) one kilocalorie? (d) State the SI unit for measuring heat energy. Ans. (a) (i) Calorie : It is the amount of heat energy required to raise the temperature of 1 g of water through 1 C. (ii) Kilocalorie : It is the amount of heat energy required to raise the temperature of 1 kg of water, through 1 C. (b) 1000 calories = 1 kilocalorie (c) (i) 1 calorie = 4.2 J (ii) 1 kilocalorie = 4200 J (d) The SI unit for measurement of heat energy is joule. 8. State three factors, which determine the heat absorbed by a cold body. Ans. (i) Heat absorbed is directly proportional to the mass of the body. (ii) Heat absorbed is directly proportional to the specific heat capacity of the body. (iii) Heat absorbed is directly proportional to the rise in temperature of the body. 2
3 9. (a) Define the following terms : (i) specific heat capacity (ii) thermal capacity or heat capacity. (b) State the SI units of : (i) specific heat capacity (ii) thermal capacity. (c) Which material is calorimeter made of? Ans.(a) (i) The amount of heat energy required to raise the temperature of one kg of a substance through 1 K is called its specific heat capacity. (ii) The amount of heat energy required to raise the temperature of a given mass of a substance through 1 K is called its thermal capacity. (b) (i) The SI unit of specific heat capacity is J kg 1 K 1. (ii) The SI unit of thermal capacity is JK 1. (c) Calorimeter is made from copper. Recently copper has been replaced by aluminium. 10. Specific heat capacity of water is 4200 Jkg 1 k 1. What do you understand by the statement? Ans. From the above statement, it implies that, if the temperature of 1 kg of water is raised through 1 K, then the amount of heat energy required to do so is 4200 J. 3
4 11. The thermal capacity of a vessel is 428 J K 1. What do you understand by the statement? Ans. From the above statement, it implies that, if the temperature of the given vessel is raised through 1 K, then heat energy required to do so is 428 K. 12. The heat capacity of a vessel is 42 J C 1. How much heat energy is required to raise its temperature from 10 C to 20 C? Ans. Rise in temperature = (20 10) C = 10 C Heat energy required to raise its temperature through 10 C = Heat capacity Rise in temperature = 42 J C 1 10 C = 420 J. 13. Some amount of heat energy is supplied to two liquids A and B. The liquid A shows a greater rise in temperature. What can you say about heat capacity of A as compared to that of B? Ans. Heat capacity of A is less than that of B. 14. Why is the base of cooking pan made thick and heavy? Ans. Cooking pans are made from metals such as copper, brass, stainless steel, etc. They have low specific heat capacity and hence rapidly attain the temperature of flame used for heating. This in turn can burn the food. To avoid burning of food the base is made heavy and thick, so that the temperature within the pan is less than the flame and hence the food cooks without burning. 4
5 15. A substance of mass m 1, specific heat capacity c 1 at a temperature T 1 is mixed with another substance of mass m 2, specific heat capacity c 2 at a lower temperature T 2. Deduce the expression for the final temperature of the mixture. State any assumption made, if any. Ans. Let the final temperature of mixture be T Rise in temperature (θ R) = (T T 2 ) Fall in temperature (θ f) = (T 1 T) Now, heat gained by substance at lower temp. = Heat lost by substance at higher temp. m 2 c 2 (T T 2 ) = m 1 c 1 (T 1 T) m 2 c 2 T m 2 c 2 T 2 = m 1 c 1 T 1 m 1 c 1 T m 2 c 2 T + m 1 c 1 T = m 1 c 1 T 1 + m 2 c 2 T 2 (m 2 c 2 + m 1 c 1 )T = m 1 c 1 T 1 + m 2 c 2 T 2 T = mct + m ct mc + mc Why are hot water bottles very efficient for fomentation? Ans.Water has the highest sp. heat capacity of 4.2 Jg 1 C 1. Furthermore, its temperature does not rise beyond 100 C, under normal conditions. Thus, it can store large amount of heat energy at quite a bearable temperature and hence it is ideal for fomentation purposes. 5
6 17. What are land and sea breezes? Explain how are they caused in the coastal regions. Ans. Local winds which blow from the sea to the land during the day-time and from the land to the sea during night-time are called sea and land breezes. Formation of sea breeze : Specific latent heat capacity of land is about five time less, as compared to water. Thus, when the sun shines equally on the sea, as well as on the land, the land gets comparatively hot as compared to the sea. The air above the land gets hot and hence, rises, thereby causing a drop in pressure. To make up for the drop in pressure, the cold air from the sea, blows towards the land, thereby giving rise to sea breeze. Formation of land breeze : At night the sea water, as well as the land radiate heat energy. However, the land radiates heat energy, at much faster rate as compared to the sea, owing to its five times less specific heat capacity, as compared to the sea water. Thus, on the whole, the sea is comparatively warmer as compared to the land. The air above the sea gets warm and rises up. This causes a fall in pressure. To make up for this fall in pressure, the cold air from the land blows towards the sea, thereby giving rise to land breeze. 6
7 18. Discuss the role of high specific heat capacity of water, with reference to the climate in coastal regions. Ans. The climate in coastal regions remains moderate due to the blowing in of the cold air from sea during day-time (sea breeze) and blowing out of the cold air from land to sea (land breeze), during night-time. The land and sea breeze are formed as under : Write here formation of land and sea breeze as in Q Why is water used as a coolant in motor-car radiators? Ans. Water has the highest specific heat capacity of 4.2 Jg 1 C 1 and its temperature does not rise beyond 100 C. Thus, it can absorb large amount of heat from a working engine, which is then radiated out through the radiator. Thus, on this low temperature the engine works efficiently. 20. Why is water sprayed on roads in the evening in hot summer? Ans.Water has the highest specific heat capacity of 4.2 Jg 1 C 1. Thus, water absorbs large amount of heat from the roads, but its own temperature does not rise much. Thus, on the whole the roads get cooled. 21. Why the temperature in hot summer falls sharply, after a sharp shower? Ans. Water has the highest specific heat capacity of 4.2 Jg 1 C 1. Thus, when there is a sharp shower, the water evaporates. In doing so, it absorbs large amount of heat from surroundings, hence temperature falls sharply. 7
8 22. Why do sandy soils get heated up quickly as compared to wet soils? Ans. The specific heat capacity of the sand is about five times less than that of the water. Thus, when sun shines equally on sandy soil and the wet soil, the sandy soil gets heated up rapidly as compared to the wet soil. It is because, water absorbs large amount of heat energy, but its temperature does not rise sufficiently. 23. Why is water considered the best liquid for quenching thirst? Ans. Water has the highest specific heat capacity of 4.2 Jg 1 C 1 and hence it can absorb large amount of heat energy, without rising in temperature sufficiently. Thirst is the natural signal, when body produces more heat energy than required. Thus, water is ideal for quenching thirst, because it can absorb large amount of heat energy. 24. Why is it advisable to pour cold water over burns, caused on the human body, by hot solids? Ans. Water has the highest specific heat capacity of 4.2 Jg 1 C 1. Thus, it can extract large amount of heat energy rapidly from the site of burn and hence gives a lot of relief. 8
9 25. Why does a wise farmer waters his fields, if the forecast says it is going to be frost? Ans. The frost can seriously damage the leaves and fruits of the plants. When a farmer waters his fields, during night, this water gives large amount of heat energy, because 1 g of water will liberate 4.2 J of energy for every 1 C fall in temperature. Thus, the air around the field is saturated with heat energy and its temperature does not fall below 0 C. Thus, no frost is formed. 26. Why are big tubs of water kept in underground cellars for storing fresh fruit and vegetables in cold countries? Ans. During sub-zero temperatures, the water within the cells of fruits and vegetables freezes and hence damages them. To avoid such a damage the huge water tubs are kept. The water gives off 4200 J of heat energy for every one kg for 1 C fall in temperature. Thus, it does not allow the temperature of cellar to fall below 0 C, and hence, their is no damage to fresh fruits or vegetables. 27. Define the following terms : (i)fusion (ii) Melting point Ans. Fusion : The process of changing of a solid in liquid state, at some fixed temperature, by the absorption of heat from some external source is called fusion. Melting point : It is the temperature at which a solid changes into liquid state. 9
10 28. What do you understand by the following terms : (i) latent heat of fusion? (ii) specific latent heat of fusion? (iii) specific latent heat of fusion of ice? (iv) state the value of sp. latent heat of fusion of ice in : (1) the SI system (2) calories? Ans. (i) Latent heat of fusion : It is the amount of heat energy required to change a given mass of solid at its m.p. into its liquid state, without any rise in temperature. (ii) Specific latent heat of fusion : It is the amount of heat energy required to change 1 kg of solid, at its melting point, into its liquid state, without any rise in temperature. (iii) Specific latent heat of fusion of ice : It is the amount of heat energy required to change 1 kg of ice at 0 C, into 1 kg of water at 0 C, without any rise in temperature. (iv) Specific latent heat of fusion of ice is (i) 336,000 Jkg 1 in the SI system (ii) 80 calories g 1 in CGS system. 10
11 29. Bottled drinks are cooled more effectively, when surrounded by lumps of ice than iced water. Or Why do bottled soft drinks get cooled more quickly by ice cubes than by iced water. Ans. Every 1 kg of ice at 0 C absorbs 336,000 J of heat energy to form water at 0 C. As ice can extract 336,000 J of heat energy, more than water at 0 C, therefore, it cools the bottled drinks more effectively. 30. Why does atmospheric temperature fall after a hailstorm? Ans. Ice has the highest sp. latent heat of fusion of 336,000 Jkg 1. Thus, when the hail melts, it absorb large amount of heat energy from the surroundings. Thus, the atmospheric temperature drops. 31. Why does weather become pleasant when it starts freezing in cold countries? Ans. Ice has the highest sp. latent heat of fusion of 336,000 Jkg 1. Thus, every 1 kg of water at 0 C, on freezing releases 336,000 J of heat energy. As enormous amount of heat energy is released in atmosphere, therefore weather becomes pleasant. 32. Why does it gets warm during a snow storm? Ans. Same as Q
12 33. Why does it become bitterly cold when ice melts in cold countries? Ans. Same as Q Specific latent heat of fusion of lead is Jkg 1. What do you understand by the statement? Ans. It means one kg of lead at its melting point, on solidification at the same temperature will release J of heat energy. 35. Given figure shows variation in temperature with time when some wax cools from liquid phase to solid phase. (i) In which part of the curve the wax is in liquid phase? (ii) What does the part QRS represent? (iii) At which point on the curve, the wax will be in the liquid as well as solid phase? (iv) In which part of curve the wax is in solid phase. Ans. (i) Wax is in liquid phase in region PQ. (ii) QRS represents change in state of liquid wax to solid wax at constant temperature. (iii) At point R the wax will be in the solid as well as liquid phase. (iv) Wax is in the solid phase in region ST. 12
13 36. 1 kg of ice at 0 C is heated at a constant rate and its temperature is recorded after every 30 s, till steam is formed at 100 C. Draw a temperature-time graph to represent the change of phase. Ans. 37. The melting point of naphthalene, a crystalline solid, is 80 C and room temperature is 30 C. Liquid naphthalene at 100 C is cooled down to room temperature. Draw a temperature-time graph to represent cooling curve. Ans. 38. Ice-cream appears colder to mouth than water at 0 C. Give a reason. Ans. Ice has the highest sp. latent heat of fusion, i.e., 336 Jg 1. Thus, every one gram of ice on melting in mouth extracts out 336 J of extra heat energy, as compared to water at 0 C. Thus, ice-cream appears colder than water at 0 C. 13
14 39. What do you understand by the following terms? (i) Boiling, (ii) Boiling point. Ans. (i) Boiling : The process of rapid change of a liquid into gaseous state, without any change in temperature, and by the absorption of heat energy from an external source is called boiling. (ii) Boiling point : The constant temperature at which a liquid rapidly changes to its gaseous state is called boiling point. 40. Graph shows change of phases of a substance on temperature-time graph. (a)what do parts AB, BC, and CD represent? (b)what is the melting point of substance? (c) What is the boiling point of substance? Ans.(a) (i) AB represents the solid being heated still it attains a temp T1. (ii) BC represents changes in the state of solid to liquid at constant temperature. (iii) CD represents the liquid being heated till it attains a temperature of T3. (b) The melting point of the substance is T1. (c) The boiling point of the substance is T2. 14
15 Numerical Problems 1. Calculate the amount of heat energy required to raise the temperature of 100 g of copper from 20 C to 70 C (sp. heat capacity of copper = 390 J kg 1 K 1) Ans. Mass of copper (m) = 100 g = 0.1 kg Rise in temperature (θ R ) = (70 20) = 50 C Sp. heat capacity of copper (c) = 390 J kg 1 K 1 Heat required = mcθ R = 390 J kg 1 C 1 = 0.1 kg 390 J kg 1 C 50 C = 1950 J J of heat energy is supplied to raise the temperature of 0.5 kg of lead from 20 C to 40 C. Calculate the specific heat capacity of lead. Ans. Mass of lead (m) = 0.5 kg Rise in temperature (θ R ) = (40 20) C = 20 C Heat required (H) = 1300 J H = mc θ R c = H 1300J mθ 0.5 kg 20 C R = 130 J kg 1 C 1 15
16 3. Find the time taken by a 500 W heater to raise the temperature of 50 kg of a material of specific heat capacity 960 J kg 1 K 1 from 18 C to 38 C. Assume all heat energy supplied by the heater is given to the material. Ans. Power of the heater (P) = 500 W = 500 Js 1 Let the time for which the heater works = t Energy supplied by the heater = P t Rise in temperature of the material = 500 J s 1 t (θ R ) = (38 18) = 20 C = 20 K Mass of the material (m) = 50 kg sp. heat capacity of the material (c) = 960 J kg 1 K 1 Heat energy absorbed by the material = mcθ R = 50 kg 960 J kg 1 K 1 20 K = J Energy supplied by the heater = Heat energy absorbed by the material 500 J s 1 t = J t = J Js = 1920 s = min = 32 min 16
17 4. An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0 C to 15.0 C in 100 s. Calculate : (i) heat capacity of 4.0 kg of liquid, (ii) the specific heat capacity of liquid. Ans. Power of heater (P) = 600 W = 600 Js 1 Time (t) = 100 s Energy supplied by heater = P t = 600 Js s = J Rise in temperature (θ R ) = ( ) C = 5 C = 5 K (i) For 5 K rise in temperature energy required = J For 1 K rise in temperature energy required = J 5K = JK 1 Heat capacity of liquid = JK 1 (ii) Specific heat capacity of liquid = Heat capacity Mass JK 4.0 kg 1 1 = 3000 Jkg K 17
18 5. A piece of iron of mass 2.0 kg has thermal capacity 966 J C 1. Find : (i) the heat energy needed to raise it to 15 C and (ii) its sp. heat capacity in SI unit. Ans. (i) Thermal capacity = 966 J C 1 = 966 JK 1 Rise in temperature = 15 C = 15 K Heat energy required to warm iron = Thermal capacity Rise in temperature = 966 JK 1 15 K = J (ii) Specific heat capacity of iron = Thermal capacity Mass of iron 966 JK kg Jkg K kg of lemon squash at 30 C is placed in a refrigerator, which can remove heat at an average of 30 Js 1. How long will it take to cool lemon squash to 5 C? (sp heat capacity of lemon squash is 4200 J kg 1 C 1). Ans. Mass of lemon squash (m) = 0.5 kg sp. heat capacity of lemon squash (c) = 4200 Jkg 1 C 1 Fall in temperature (θ f) = (30 5) C = 25 C Heat extracted by refrigerator (H) = mcθ f = 0.5 kg 4200 Jkg 1 C 1 25 C = J 18
19 Rate of extraction of heat = 30 Js 1 Time in which lemon squash cools = Js 1 = 1750 s 60 = 1750 s = min g mass of a certain metal at 83 C is immersed in 300 g water at 30 C. The final temperature is 33 C. Calculate the specific heat capacity of the metal. (Assume that specific heat capacity of water is 4.2 Jg 1K 1). Ans. DATA Substances Metal Water Mass 200 g 300 g Sp. heat capacity? 4.2 Jg 1K 1 Initial temp. 83 C 30 C Final temp. = 33 C θ R = (33 30) θ f = (83 33) = 3 C = 3 K = 50 C = 50 K Heat lost by metal = mcθ f = 200 g c 50 K Heat gained by water = mcθ R = 300 g 4.2 Jg 1K 1 3 K = 3780 J Heat lost = Heat gained 19
20 200 g c 50 K = 3780 J c = 3780 J gk = Jg 1K 1 8. You are required to make a water bath of 40 kg, at 40 C, by mixing hot water at 100 C and cold water at 15 C. Calculate the ratio of hot and cold water, which should be mixed. Ans. Let the mass of cold water = x. Mass of hot water = (40 kg x). Substance Mass S.H.C Initial temp. Cold water x 4200 Jkg 1 C 1 15 C Hot water 40 kg x 4200 Jkg 1 C C Heat lost by hot water = Heat gained by cold water. mc θf = mc θr. (40 x) = x (40 x) 12 = 5x. 480 = 17x x = Mass of cold water = kg. = kg. Mass of hot water = ( ) = kg. 20 Final temp. = 40 C θr = (40 15) = 25 C θf = (100 40) = 60 C Mass of hot water : Mass of cold water = : = 1 : 2.4.
21 9. Temperature of 600 g cold water rose by 15 C, when 300 g of hot water at 50 C was added to it. What is the initial temp. of cold water? Ans. Substance Mass S.H.C Initial temp. Final temp. =? (x) Cold water Hot water 600 g 300 g 4.2 Jg 1 C Jg 1 C 1? 50 C θr = 15 C θf = (50 C x) Heat lost by hot water = Heat gained by cold water (50 x) = (50 x) = 30 x = 20 C (Final temp.) Initial temp. of water = (Final temp. θr) = (20 15) = 5 C g of hot water at 80 C is added to 400 g of cold water, when the temperature of cold water rises by 18 C. Calculate the initial temperature of cold water. Ans. Proceed as in Q 9. [Ans. 26 C] 21
22 11. Some amount of heat is given out to 120 g of water and its temperature rises by 10 K. When same amount of heat is given to 60 g of oil, its temperature rises by 40 K. The specific heat capacity of water is 4200 Jkg 1 K 1. Calculate : (i) amount of heat in joules given to water. (ii) specific heat capacity of oil. Ans. (i) Heat absorbed by water = mcθr = = 5040 J. (ii) Heat absorbed by water = Heat absorbed by oil 5040 J = 60 g c 40. c = = 2100 Jkg 1K A metal drill of power 500 W, drills a hole in a metal cube of mass 0.25 kg in 6.5s. The specific heat capacity of lead is 130 J kg 1 C 1. (i) How much heat is generated by metal drill in one second? (ii) Calculate the heat generated in 6.5 s. (iii) If t C, is the rise in temperature of metal cube, state the amount of heat energy absorbed by it in terms of t. (iv) Write down an equation and calculate the value of t. 22
23 Ans.(i) Energy generated by drill in 1 s = P t = s = 500 J. (ii) Energy generated by drill in 6.5 s = = 3250 J. (iii) Energy absorbed by metal = mcθr = t = 32.5 t. (iv) Energy absorbed by metal = Energy generated by drill 32.5 t = 3250 t = = 100 C. 13. An electric heater is of power 1000 W. It heats 0.4 kg of water for 2 minutes. The specific heat capacity of water is 4200 J kg 1K 1. (i) How much heat is liberated by heater in 1 s? (ii) How much heat is liberated by heater in 2 minutes? (iii) If θ C, is the rise in temperature of water, state the amount of heat energy absorbed by it, in terms of θ. (iv) Write down an equation and calculate the value of θ. Ans. Proceed as in Q. 12. [Ans. (i) 1000 J; (ii) 120,000 J; (iii) 1680 θ; (iv) C] 14. A copper calorimeter, weighing 57.5 g, contains 60 g of water at 12 C. 55 g of iron nails at 100 C, are dropped into the calorimeter and stirred rapidly. The final temperature attained by the calorimeter and its contents is 20 C. Calculate the specific heat capacity of iron. (Sp. heat capacity of copper is 0.4 Jg 1 C 1 and that of water is 4.2 Jg 1 C 1. 23
24 Ans. Substance Mass S.H.C Initial temp. Final temp. = 20 C Calorimeter 57.5 g 0.4 Jg 1 C 1 12 C θr = (20 12) = 8 C Cold water Iron 60 g 55 g 4.2 Jg 1 C 1? 12 C 100 C θf = (100 20) = 80 C Heat gained by calorimeter = mcθr = = 184 J Heat gained by cold water = mcθr = = 2016 J Heat lost by iron = mcθf = 55 c 80 = 4400 cg C. Heat lost by iron = Heat gained by calorimeter + Heat gained by water cg C = ( ) = 2200 J c = = 0.5 Jg 1 C A molten metal weighing 150 g, is kept at its melting point, at 800 C. When allowed to solidify at the same temperature, it gives off 7500 J of heat energy. What is the specific latent heat of fusion of metal? If its specific heat capacity is 200 Jkg 1 K 1, how much additional heat will it give out in cooling to 50 C? 24
25 Ans. (i) Heat given off by metal during change of state = mass sp. latent heat of metal 7500 J = 150 g sp. latent heat of fusion of the metal. Sp. latent heat of fusion of the metal = = 50 Jg l (ii) Heat given off by metal on cooling = mcθf = [800 ( 50)] J = 25,500 J. 16. A solid weighing 200 g, is kept at its melting point at 0 C. When allowed to melt at the same temperature, it absorbs J of heat energy. Calculate the specific latent heat of fusion of solid. If its specific heat capacity is 4200 Jkg 1K 1, how much additional heat will it absorb in attaining a temperature of 80 C? Ans Proceed as in [Ans. (i) 336 Jg l, (ii) J] 17. One kg of molten lead at its melting point 327 C, is dropped in 1 kg of water at 20 C. Assuming no heat is lost to surroundings, calculate final temperature of water. [Sp. heat capacity of lead and water is 130 Jkg 1 K 1 and 4200 Jkg 1 K 1 respectively. Sp. latent heat of fusion of lead = J kg 1] 25
26 Ans. Substance Mass S.H.C/S.L.H Lead Water 1 kg 1 kg 130 Jkg 1 C 1 /27000 Jkg Jkg 1 C 1 Initial temp. 327 C 20 C Final temp. =? (x) θ R = (x 20 C) θf = (327 C x) Heat lost by lead to change its state = ml = = J. Heat lost by solid lead from 327 C to final temp. = mcθf = (327 x). Heat gained by water = mcθr = (x 20). Heat gained = Heat lost (x 20) = 130 (327 x) x = x x = x = C kg of molten metal at its melting point 420 C, is dropped into 2 kg of water at 25 C. Assuming no heat is lost to surroundings, calculate the final temperature of water.[sp. heat capacity of metal and water are 250 Jkg 1 K 1 and 4200 Jkg 1 K 1 respectively. Sp. latent heat of fusion of metal = Jkg 1] Ans. Proceed as Q : 17 [Ans C] 26
27 19. A block of lead of mass 1 kg at 27 C was heated in a furnace, till it melts completely. Find the quantity of heat required : (i) To bring the lead block to its melting point, (ii) To completely melt the lead block at its melting point. [m.p of lead = 327 C; sp. heat capacity of lead = 130 Jkg 1 K 1 and sp. latent heat of fusion of lead = 26,000 Jkg 1]. Ans.(i) Heat required to bring the lead to its melting point = mcθr = (327 27) = J (ii) Heat required to melt lead = ml = 1 26,000 = 26,000 J. 20. A block of a metal of mass 0.8 kg at 20 C is heated in a furnace, till it completely melts. Find the quantity of heat required : (i) to bring the metal to its melting point, (ii) to completely melt the metal at its melting point [m.p of metal = 420 C; sp. heat capacity of metal 250 Jkg 1 K 1 and sp. latent heat of fusion of metal = Jkg 1] Ans. Proceed as Q : 19 [Ans. (i) 80,000 J, (ii) J] 21. A refrigerator converts 100 g of water at 20 C to ice at 10 C in 73.5 minutes. Calculate the average rate of heat extraction from water in watts. [Specific heat capacity of ice = 2100 Jkg 1 K 1; sp. heat capacity of water is 4200 J kg 1 K 1 and sp. latent heat of fusion of ice is 336,000 Jkg 1]. Ans. Heat lost by water at 20 C to attain temp. of 0 C = mcθf = kg C = 8400 J 27
28 Heat lost by water at 0 C to form ice at 0 C = mlice = kg 336,000 Jkg 1 = J Heat lost by ice to attain temp. of 10 C = mcθf = kg 2100 J 10 C = 2100 J kg. C Total heat lost= ( ) J = 44,100 J 44,100 J Rate of extraction of heat = = 10 Js 1 = 10 W s 22. A cooling machine freezes 1.2 kg of water at 20 C, into ice at 40 C in 12 minutes. Calculate the average rate of extraction of heat energy in watts. [S.H.C of ice = 2100 Jkg 1 K 1, S.H. C of water = 4200 Jkg 1 K 1, S.L.H of ice = Jkg 1] Ans. Proceed as in Q. 21 [Ans. 336 W] 23. An ice cube of mass 30 g, is dropped in 200 g of water at 30 C, such that all the ice melts. Calculate final temperature of water. [Latent heat of ice = 80 cal g 1; Specific heat capacity of water = 1 cal g 1 C 1] Ans. Substance Mass S.H.C/S.L.H Initial temp. Final temp. =? (x) Ice Water 30 g 200 g 80 cal g 1 1 cal g 1 C 1 0 C 30 C θr = (x 0) = x θf = (30 x) 28
29 Heat gained by ice to form water at 0 C = ml = = = 2400 calories Heat gained by water at 0 C to attain temp. x = mcθr = 30 1 x = 30x. Heat lost by water at 30 C = mcθf = (30 x) = x. Heat gained = Heat lost x = x. 230 x = 3600 x = C g of ice cubes are placed in 500 g of water at 40 C, such that all the ice melts. Calculate final temperature of water. [Latent heat of ice = 80 cal g 1; specific heat capacity of water = 1 cal g 1 C 1] Ans. Proceed as in Q. 23 [Ans C] g of ice at 0 C absorbs 5460 J of heat energy to melt and change to water at 50 C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg 1 K 1. Ans.Mass of ice = 10 g. Heat absorbed by ice to form water at 0 C = m Lice = 10 g Lice Rise in temperature (θ R ) = (50 0) = 50 C. Heat absorbed by water at 0 C to attain temp. of 50 C = mcθr = = 2100 J Total heat absorbed by ice = 10 g Lice J 29
30 Also total heat absorbed by ice = 5460 J 10 g Lice J = 5460 J 10 g Lice = ( ) J = 3360 J Lice = 3360 J 10 g = 336 Jg How much heat is released when 5.0 g of water at 20 C changes to ice at 0 C? [Take sp. heat capacity of water = 4.2 J g 1 C 1, specific latent heat of fusion of ice = 336 Jg 1] Ans. Fall in temperature (θ ) f = (20 0) = 20 C. Heat lost by water to attain temp. of 0 C = mcθf = = 420 J Heat lost by water to form ice at 0 C = mlice = = 1680 J Total amount of heat released by water = ( ) J = 2100 J 27. In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34 C to its freezing point. The specific heat capacity of water is 4.2 J kg 1 K 1. Calculate the specific latent heat of ice. State one assumption made in the above calculation. 30
31 Ans. Fall in temperature of water (θ ) f = (34 0) = 34 C Heat lost by water = mcθ f = = 5712 J Heat gained by ice to form water at 0 C = mlice = 17 g Lice. Heat gained by ice = Heat lost by water 17 g Lice = 5712 J Lice = 5712 J 17 g = 336 Jg Find the result of mixing 10 g of ice at 10 C with 10 g of water at 10 C. [sp. heat capacity of ice = 2.1 Jg 1K 1; sp. latent heat of ice = 336 Jg 1 and specific heat capacity of water = 4.2 J g 1 K 1] Ans. Let the amount of ice which melts = x g Heat gained by ice at 10 C to form ice at 0 C = mc θ R = = 210 J Heat gained by ice at 0 C to melt= mlice = x 336 Total heat gained = 210 J + 336x Heat lost by water at 10 C = mc θ R = = 420 J Heat gained = Heat lost 210 J x = 420 J 336x = ( ) = 210 J x = = g Thus, g of ice melts. 31
32 29. What will be the result of mixing 400 g of copper chips at 500 C with 500 g of crushed ice at 0 C. [sp. heat capacity of copper = 0.42 Jg 1K 1 and sp. latent heat of fusion of ice = 340 Jg 1]. Ans. Let the amount of ice which melts = x g Heat absorbed by ice on melting = mlice = x 340 Fall in temperature of copper chips (θ f ) = (500 0) = 500 C Heat given out by copper chips = mcθf = = J Heat absorbed by ice = Heat given out by copper chips x 340 = x = = g Thus, g of ice will melt. 32
Energy Matters Heat. Changes of State
Energy Matters Heat Changes of State Fusion If we supply heat to a lid, such as a piece of copper, the energy supplied is given to the molecules. These start to vibrate more rapidly and with larger vibrations
More informationFXA 2008. Candidates should be able to : Define and apply the concept of specific heat capacity. Select and apply the equation : E = mcδθ
UNIT G484 Module 3 4.3.3 Thermal Properties of Materials 1 Candidates should be able to : Define and apply the concept of specific heat capacity. Select and apply the equation : E = mcδθ The MASS (m) of
More informationChapter 18 Temperature, Heat, and the First Law of Thermodynamics. Problems: 8, 11, 13, 17, 21, 27, 29, 37, 39, 41, 47, 51, 57
Chapter 18 Temperature, Heat, and the First Law of Thermodynamics Problems: 8, 11, 13, 17, 21, 27, 29, 37, 39, 41, 47, 51, 57 Thermodynamics study and application of thermal energy temperature quantity
More informationChapter 4: Transfer of Thermal Energy
Chapter 4: Transfer of Thermal Energy Goals of Period 4 Section 4.1: To define temperature and thermal energy Section 4.2: To discuss three methods of thermal energy transfer. Section 4.3: To describe
More informationUNIT 6a TEST REVIEW. 1. A weather instrument is shown below.
UNIT 6a TEST REVIEW 1. A weather instrument is shown below. Which weather variable is measured by this instrument? 1) wind speed 3) cloud cover 2) precipitation 4) air pressure 2. Which weather station
More informationChapter 10: Temperature and Heat
Chapter 10: Temperature and Heat 1. The temperature of a substance is A. proportional to the average kinetic energy of the molecules in a substance. B. equal to the kinetic energy of the fastest moving
More informationChapter 10 Temperature and Heat
Chapter 10 Temperature and Heat What are temperature and heat? Are they the same? What causes heat? What Is Temperature? How do we measure temperature? What are we actually measuring? Temperature and Its
More informationChapter 4 Practice Quiz
Chapter 4 Practice Quiz 1. Label each box with the appropriate state of matter. A) I: Gas II: Liquid III: Solid B) I: Liquid II: Solid III: Gas C) I: Solid II: Liquid III: Gas D) I: Gas II: Solid III:
More information2. Room temperature: C. Kelvin. 2. Room temperature:
Temperature I. Temperature is the quantity that tells how hot or cold something is compared with a standard A. Temperature is directly proportional to the average kinetic energy of molecular translational
More informationName: Class: Date: 10. Some substances, when exposed to visible light, absorb more energy as heat than other substances absorb.
Name: Class: Date: ID: A PS Chapter 13 Review Modified True/False Indicate whether the statement is true or false. If false, change the identified word or phrase to make the statement true. 1. In all cooling
More informationSpecific Heat Capacity and Latent Heat Questions A2 Physics
1. An electrical heater is used to heat a 1.0 kg block of metal, which is well lagged. The table shows how the temperature of the block increased with time. temp/ C 20.1 23.0 26.9 30.0 33.1 36.9 time/s
More informationChapter 10 Temperature and Heat
Chapter 10 Temperature and Heat GOALS When you have mastered the contents of this chapter, you will be able to achieve the following goals: Definitions Define each of the following terms, and use it an
More informationPhys222 W11 Quiz 1: Chapters 19-21 Keys. Name:
Name:. In order for two objects to have the same temperature, they must a. be in thermal equilibrium.
More informationTemperature. Temperature
Chapter 8 Temperature Temperature a number that corresponds to the warmth or coldness of an object measured by a thermometer is a per-particle property no upper limit definite limit on lower end Temperature
More informationType: Single Date: Homework: READ 12.8, Do CONCEPT Q. # (14) Do PROBLEMS (40, 52, 81) Ch. 12
Type: Single Date: Objective: Latent Heat Homework: READ 12.8, Do CONCEPT Q. # (14) Do PROBLEMS (40, 52, 81) Ch. 12 AP Physics B Date: Mr. Mirro Heat and Phase Change When bodies are heated or cooled their
More informationChapter Test A. States of Matter MULTIPLE CHOICE. a fixed amount of STAs2 a. a solid. b. a liquid. c. a gas. d. any type of matter.
Assessment Chapter Test A States of Matter MULTIPLE CHOICE Write the letter of the correct answer in the space provided. 1. Boyle s law explains the relationship between volume and pressure for a fixed
More informationTopic Page Contents Page
Heat energy (11-16) Contents Topic Page Contents Page Heat energy and temperature 3 Latent heat energy 15 Interesting temperatures 4 Conduction of heat energy 16 A cooling curve 5 Convection 17 Expansion
More informationTest 5 Review questions. 1. As ice cools from 273 K to 263 K, the average kinetic energy of its molecules will
Name: Thursday, December 13, 2007 Test 5 Review questions 1. As ice cools from 273 K to 263 K, the average kinetic energy of its molecules will 1. decrease 2. increase 3. remain the same 2. The graph below
More informationPreview of Period 5: Thermal Energy, the Microscopic Picture
Preview of Period 5: Thermal Energy, the Microscopic Picture 5.1 Temperature and Molecular Motion What is evaporative cooling? 5.2 Temperature and Phase Changes How much energy is required for a phase
More information5 Answers and Solutions to Text Problems
Energy and States of Matter 5 Answers and Solutions to Text Problems 5.1 At the top of the hill, all of the energy of the car is in the form of potential energy. As it descends down the hill, potential
More informationEvery mathematician knows it is impossible to understand an elementary course in thermodynamics. ~V.I. Arnold
Every mathematician knows it is impossible to understand an elementary course in thermodynamics. ~V.I. Arnold Radiation Radiation: Heat energy transmitted by electromagnetic waves Q t = εσat 4 emissivity
More information5. Which temperature is equal to +20 K? 1) 253ºC 2) 293ºC 3) 253 C 4) 293 C
1. The average kinetic energy of water molecules increases when 1) H 2 O(s) changes to H 2 O( ) at 0ºC 3) H 2 O( ) at 10ºC changes to H 2 O( ) at 20ºC 2) H 2 O( ) changes to H 2 O(s) at 0ºC 4) H 2 O( )
More informationHeat Transfer: Conduction, Convection, and Radiation
Heat Transfer: Conduction, Convection, and Radiation Introduction We have learned that heat is the energy that makes molecules move. Molecules with more heat energy move faster, and molecules with less
More informationScience Department Mark Erlenwein, Assistant Principal
Staten Island Technical High School Vincent A. Maniscalco, Principal The Physical Setting: CHEMISTRY Science Department Mark Erlenwein, Assistant Principal - Unit 1 - Matter and Energy Lessons 9-14 Heat,
More informationMixing Warm and Cold Water
Mixing Warm and Cold Water A Continuing Investigation of Thermal Pollution By Kevin White 1 Context: This lesson is intended for students conducting an ongoing study of thermal pollution. Perhaps, students
More informationAnswer, Key Homework 6 David McIntyre 1
Answer, Key Homework 6 David McIntyre 1 This print-out should have 0 questions, check that it is complete. Multiple-choice questions may continue on the next column or page: find all choices before making
More informationHEAT UNIT 1.1 KINETIC THEORY OF GASES. 1.1.1 Introduction. 1.1.2 Postulates of Kinetic Theory of Gases
UNIT HEAT. KINETIC THEORY OF GASES.. Introduction Molecules have a diameter of the order of Å and the distance between them in a gas is 0 Å while the interaction distance in solids is very small. R. Clausius
More informationHumidity, Condensation, Clouds, and Fog. Water in the Atmosphere
Humidity, Condensation, Clouds, and Fog or Water in the Atmosphere The Hydrologic Cycle Where the Water Exists on Earth Evaporation From the Oceans and Land The Source of Water Vapor for the Atmosphere
More informationSUGGESTED ACTIVITIES
SUGGESTED ACTIVITIES (Thermal Energy) From Invitations to Science Inquiry 2 nd Edition by Tik L. Liem: Activity Page Number Concept Warm a Bottle by Shaking 184 Heat, Friction The Confused Bottles 206
More informationThermochemistry. r2 d:\files\courses\1110-20\99heat&thermorans.doc. Ron Robertson
Thermochemistry r2 d:\files\courses\1110-20\99heat&thermorans.doc Ron Robertson I. What is Energy? A. Energy is a property of matter that allows work to be done B. Potential and Kinetic Potential energy
More information14 HEAT AND HEAT TRANSFER METHODS
CHAPTER 14 HEAT AND HEAT TRANSFER METHODS 469 14 HEAT AND HEAT TRANSFER METHODS Figure 14.1 (a) The chilling effect of a clear breezy night is produced by the wind and by radiative heat transfer to cold
More information1. At which temperature would a source radiate the least amount of electromagnetic energy? 1) 273 K 3) 32 K 2) 212 K 4) 5 K
1. At which temperature would a source radiate the least amount of electromagnetic energy? 1) 273 K 3) 32 K 2) 212 K 4) 5 K 2. How does the amount of heat energy reflected by a smooth, dark-colored concrete
More informationTHE PLANT KINGDOM: THE WATER CYCLE
THE PLANT KINGDOM: THE WATER CYCLE Material: The Water Cycle Nomenclature The Water cycle Model Water Ice Heat Source (lamp with a clamp) Tables Presentation 1: Key Experience 1. Say, Today we are going
More information6 th Grade Science Assessment: Weather & Water Select the best answer on the answer sheet. Please do not make any marks on this test.
Select the be answer on the answer sheet. Please do not make any marks on this te. 1. Weather is be defined as the A. changes that occur in cloud formations from day to day. B. amount of rain or snow that
More information(Walter Glogowski, Chaz Shapiro & Reid Sherman) INTRODUCTION
Convection (Walter Glogowski, Chaz Shapiro & Reid Sherman) INTRODUCTION You know from common experience that when there's a difference in temperature between two places close to each other, the temperatures
More informationREASONING AND SOLUTION
39. REASONING AND SOLUTION The heat released by the blood is given by Q cm T, in which the specific heat capacity c of the blood (water) is given in Table 12.2. Then Therefore, T Q cm 2000 J 0.8 C [4186
More informationHeat Energy FORMS OF ENERGY LESSON PLAN 2.7. Public School System Teaching Standards Covered
FORMS OF ENERGY LESSON PLAN 2.7 Heat Energy This lesson is designed for 3rd 5th grade students in a variety of school settings (public, private, STEM schools, and home schools) in the seven states served
More informationES 106 Laboratory # 2 HEAT AND TEMPERATURE
ES 106 Laboratory # 2 HEAT AND TEMPERATURE Introduction Heat transfer is the movement of heat energy from one place to another. Heat energy can be transferred by three different mechanisms: convection,
More informationForms of Energy. Freshman Seminar
Forms of Energy Freshman Seminar Energy Energy The ability & capacity to do work Energy can take many different forms Energy can be quantified Law of Conservation of energy In any change from one form
More informationHeat and Temperature: Front End Evaluation Report. Joshua Gutwill. October 1999
Heat and Temperature: Front End Evaluation Report Joshua Gutwill October 1999 Keywords: 1 Heat and Temperature Front End Evaluation Report October 28, 1999 Goal:
More informationSeasonal & Daily Temperatures. Seasons & Sun's Distance. Solstice & Equinox. Seasons & Solar Intensity
Seasonal & Daily Temperatures Seasons & Sun's Distance The role of Earth's tilt, revolution, & rotation in causing spatial, seasonal, & daily temperature variations Please read Chapter 3 in Ahrens Figure
More informationYear 10 Investigation. What Makes Ice Melt Fastest? By Rebecca Hogan
Investigation What Makes Ice Melt Fastest? MY WEBSITE: http://whatsubstancemeltsicefastest.weebly.com/ Nature of Investigation: What keeps us cool on hot days? What is used in our cool, refreshing beverages?
More informationNote: You will receive no credit for late submissions. To learn more, read your instructor's Grading Policy
1/7 2009/11/14 上 午 11:10 Manage this Assignment: Chapter 16 Due: 12:00am on Saturday, July 3, 2010 Note: You will receive no credit for late submissions. To learn more, read your instructor's Grading Policy
More informationA Teaching Unit for Years 3 6 children
A Teaching Unit for Years 3 6 children 1 SEREAD and ARGO: Concept Overview for Years 3-6 Teaching Programme This is the overview for the first part of the SEREAD programme link with ARGO. The overview
More informationSECOND GRADE 1 WEEK LESSON PLANS AND ACTIVITIES
SECOND GRADE 1 WEEK LESSON PLANS AND ACTIVITIES WATER CYCLE OVERVIEW OF SECOND GRADE WATER WEEK 1. PRE: Exploring the properties of water. LAB: Experimenting with different soap mixtures. POST: Analyzing
More informationExperiment 1: Colligative Properties
Experiment 1: Colligative Properties Determination of the Molar Mass of a Compound by Freezing Point Depression. Objective: The objective of this experiment is to determine the molar mass of an unknown
More informationEnergy Conversions I. Unit of measure (most common one) Form Definition Example
Energy Conversions I Energy can take many forms, but any one form can usually be converted into another. And no matter what form we talk about, we can use conversion factors to calculate equivalent amounts
More informationThe Water Cycle Now You See It, Now You Don t
The Water Cycle Now You See It, Now You Don t Unit: Salinity Patterns & the Water Cycle l Grade Level: Elementary l Time Required: Introduction - 30 min. - Activity as groups 45min Wrap Up 20 min l Content
More informationScholars Research Library
Available online at www.scholarsresearchlibrary.com Scholars Research Library Archives of Physics Research, 2010, 1 (2):103-111 (http://scholarsresearchlibrary.com/archive.html) ISSN 0976-0970 Lubricating
More informationThe final numerical answer given is correct but the math shown does not give that answer.
Note added to Homework set 7: The solution to Problem 16 has an error in it. The specific heat of water is listed as c 1 J/g K but should be c 4.186 J/g K The final numerical answer given is correct but
More informationWhat is Energy? What is the relationship between energy and work?
What is Energy? What is the relationship between energy and work? Compare kinetic and potential energy What are the different types of energy? What is energy? Energy is the ability to do work. Great, but
More informationWorksheet #17. 2. How much heat is released when 143 g of ice is cooled from 14 C to 75 C, if the specific heat capacity of ice is 2.087 J/(g C).
Worksheet #17 Calculating Heat 1. How much heat is needed to bring 12.0 g of water from 28.3 C to 43.87 C, if the specific heat capacity of water is 4.184 /(g? 2. How much heat is released when 143 g of
More informationA n = 2 to n = 1. B n = 3 to n = 1. C n = 4 to n = 2. D n = 5 to n = 2
North arolina Testing Program EO hemistry Sample Items Goal 4 1. onsider the spectrum for the hydrogen atom. In which situation will light be produced? 3. Which color of light would a hydrogen atom emit
More informationCHAPTER 7 THE SECOND LAW OF THERMODYNAMICS. Blank
CHAPTER 7 THE SECOND LAW OF THERMODYNAMICS Blank SONNTAG/BORGNAKKE STUDY PROBLEM 7-1 7.1 A car engine and its fuel consumption A car engine produces 136 hp on the output shaft with a thermal efficiency
More informationWe will study the temperature-pressure diagram of nitrogen, in particular the triple point.
K4. Triple Point of Nitrogen I. OBJECTIVE OF THE EXPERIMENT We will study the temperature-pressure diagram of nitrogen, in particular the triple point. II. BAKGROUND THOERY States of matter Matter is made
More informationChemistry Unit 3 Reading Assignment Energy and Kinetic Molecular Theory
Chemistry Unit 3 Reading Assignment Energy and Kinetic Molecular Theory The story behind the difficulty we have with energy is fascinating to those of us who struggle with trying to teach energy in a coherent
More informationRusty Walker, Corporate Trainer Hill PHOENIX
Refrigeration 101 Rusty Walker, Corporate Trainer Hill PHOENIX Compressor Basic Refrigeration Cycle Evaporator Condenser / Receiver Expansion Device Vapor Compression Cycle Cooling by the removal of heat
More informationPractice Test. 4) The planet Earth loses heat mainly by A) conduction. B) convection. C) radiation. D) all of these Answer: C
Practice Test 1) Increase the pressure in a container of oxygen gas while keeping the temperature constant and you increase the A) molecular speed. B) molecular kinetic energy. C) Choice A and choice B
More informationWhat Is Heat? What Is Heat?
What Is Heat? Paul shivered inside the wood cabin. It was cold outside, and inside the cabin it wasn t much warmer. Paul could hear the rain beating down on the roof. Every few minutes there would be a
More informationCHAPTER 14 THE CLAUSIUS-CLAPEYRON EQUATION
CHAPTER 4 THE CAUIU-CAPEYRON EQUATION Before starting this chapter, it would probably be a good idea to re-read ections 9. and 9.3 of Chapter 9. The Clausius-Clapeyron equation relates the latent heat
More informationChemistry 13: States of Matter
Chemistry 13: States of Matter Name: Period: Date: Chemistry Content Standard: Gases and Their Properties The kinetic molecular theory describes the motion of atoms and molecules and explains the properties
More informationPREPARATION FOR CHEMISTRY LAB: COMBUSTION
1 Name: Lab Instructor: PREPARATION FOR CHEMISTRY LAB: COMBUSTION 1. What is a hydrocarbon? 2. What products form in the complete combustion of a hydrocarbon? 3. Combustion is an exothermic reaction. What
More information1. The Kinetic Theory of Matter states that all matter is composed of atoms and molecules that are in a constant state of constant random motion
Physical Science Period: Name: ANSWER KEY Date: Practice Test for Unit 3: Ch. 3, and some of 15 and 16: Kinetic Theory of Matter, States of matter, and and thermodynamics, and gas laws. 1. The Kinetic
More informationEXPLANATION OF WEATHER ELEMENTS AND VARIABLES FOR THE DAVIS VANTAGE PRO 2 MIDSTREAM WEATHER STATION
EXPLANATION OF WEATHER ELEMENTS AND VARIABLES FOR THE DAVIS VANTAGE PRO 2 MIDSTREAM WEATHER STATION The Weather Envoy consists of two parts: the Davis Vantage Pro 2 Integrated Sensor Suite (ISS) and the
More informationEnergy and Energy Transformations Test Review
Energy and Energy Transformations Test Review Completion: 1. Mass 13. Kinetic 2. Four 14. thermal 3. Kinetic 15. Thermal energy (heat) 4. Electromagnetic/Radiant 16. Thermal energy (heat) 5. Thermal 17.
More informationCalculating Heat Loss by Mark Crombie, Chromalox
Calculating Heat Loss by Mark Crombie, Chromalox Posted: January 30, 2006 This article deals with the basic principles of heat transfer and the calculations used for pipes and vessels. By understanding
More information1. Thermite reaction 2. Enthalpy of reaction, H 3. Heating/cooling curves and changes in state 4. More thermite thermodynamics
Chem 105 Fri 10-23-09 1. Thermite reaction 2. Enthalpy of reaction, H 3. Heating/cooling curves and changes in state 4. More thermite thermodynamics 10/23/2009 1 Please PICK UP your graded EXAM in front.
More informationExperiment 6 Coffee-cup Calorimetry
6-1 Experiment 6 Coffee-cup Calorimetry Introduction: Chemical reactions involve the release or consumption of energy, usually in the form of heat. Heat is measured in the energy units, Joules (J), defined
More informationSpecific Heat (slope and steepness)
1 Specific Heat (slope and steepness) 10 pages. According to the Physical Science text book, the Specific Heat of a material is DEFINED as the following: Specific heat is the amount of heat energy required
More informationTEACHER BACKGROUND INFORMATION THERMAL ENERGY
TEACHER BACKGROUND INFORMATION THERMAL ENERGY In general, when an object performs work on another object, it does not transfer all of its energy to that object. Some of the energy is lost as heat due to
More informationLet s Make a Cloud. Objective Demonstrate the combination of three natural elements, to form a cloud: water vapor, smoke and air pressure.
Let s Make a Cloud Related Subject: Climate and Weather Group Size: 10-15 Length of Activity: 45 minutes Objective Demonstrate the combination of three natural elements, to form a cloud: water vapor, smoke
More information1/2/3. Finding out about the Water Cycle
The Water Cycle 1/2/3. Finding out about the Water Cycle Aims: To enable pupils to learn and understand what happens at each stage of the Water Cycle To introduce specific vocabulary related to the Water
More informationChapter 12 - Liquids and Solids
Chapter 12 - Liquids and Solids 12-1 Liquids I. Properties of Liquids and the Kinetic Molecular Theory A. Fluids 1. Substances that can flow and therefore take the shape of their container B. Relative
More informationHow does solar air conditioning work?
How does solar air conditioning work? In a conventional air conditioning system; The working fluid arrives at the compressor as a cool, low-pressure gas. The compressor is powered by electricity to squeeze
More informationKINDERGARTEN WATER 1 WEEK LESSON PLANS AND ACTIVITIES
KINDERGARTEN WATER 1 WEEK LESSON PLANS AND ACTIVITIES WATER CYCLE OVERVIEW OF KINDERGARTEN WEEK 1. PRE: Defining the states of matter. LAB: Discovering the properties of water. POST: Analyzing the water
More informationPractical Applications of Freezing by Boiling Process
Practical Applications of Freezing by Boiling Process Kenny Gotlieb, Sasha Mitchell and Daniel Walsh Physics Department, Harvard-Westlake School 37 Coldwater Canyon, N. Hollywood, CA 9164 Introduction
More informationATOMIC ABSORTION SPECTROSCOPY: rev. 4/2011 ANALYSIS OF COPPER IN FOOD AND VITAMINS
1 ATOMIC ABSORTION SPECTROSCOPY: rev. 4/2011 ANALYSIS OF COPPER IN FOOD AND VITAMINS Buck Scientific Atomic Absorption Spectrophotometer, Model 200 Atomic absorption spectroscopy (AAS) has for many years
More informationChapter 3. Thermal Energy
Chapter 3 Thermal Energy In order to apply energy conservation to a falling ball or a roller coaster in the previous chapter, we had to assume that friction (with the air or the track) was negligible.
More informationPartnerships Implementing Engineering Education Worcester Polytechnic Institute Worcester Public Schools
Partnerships Implementing Engineering Education Worcester Polytechnic Institute Worcester Public Schools Supported by: National Science Foundation Weather: 4.H.3 Weather and Classical Instruments Grade
More informationMCQ - ENERGY and CLIMATE
1 MCQ - ENERGY and CLIMATE 1. The volume of a given mass of water at a temperature of T 1 is V 1. The volume increases to V 2 at temperature T 2. The coefficient of volume expansion of water may be calculated
More informationUNIT (1) MEASUREMENTS IN CHEMISTRY
UNIT (1) MEASUREMENTS IN CHEMISTRY Measurements are part of our daily lives. We measure our weights, driving distances, and gallons of gasoline. As a health professional you might measure blood pressure,
More informationEnergy Content of Fuels
Experiment 9 Energy content is an important property of fuels. This property helps scientists and engineers determine the usefulness of a fuel. Energy content is the amount of heat produced by the burning
More informationMixtures. reflect. How is seawater different from pure water? How is it different from rocky soil?
reflect Everything around us is made out of tiny bits of matter. These particles may combine in different ways to produce new materials. Sometimes we need to separate the parts of a material. If we know
More informationGround Source Heat Pumps The Fundamentals. Southington, Connecticut 860 628 4622 John F. Sima III P.E.
Ground Source Heat Pumps The Fundamentals Southington, Connecticut 860 628 4622 John F. Sima III P.E. Winter/Spring 2010 Ground Source Heat Pumps The Fundamentals TOPICS: Heat Pump Terminology Basic Physics
More informationIntermolecular Forces
Intermolecular Forces: Introduction Intermolecular Forces Forces between separate molecules and dissolved ions (not bonds) Van der Waals Forces 15% as strong as covalent or ionic bonds Chapter 11 Intermolecular
More informationWater Cycle Unit Test
Name: Multiple Choice (2 pts each): 1. What is the source of energy for all parts of the water cycle? A. Wind B. The Ocean C. Soil D. The Sun 2. Which of the following processes would result in water pollution?
More informationThermochemistry: Calorimetry and Hess s Law
Thermochemistry: Calorimetry and Hess s Law Some chemical reactions are endothermic and proceed with absorption of heat while others are exothermic and proceed with an evolution of heat. The magnitude
More informationExam on Heat and Energy
Exam on Heat and Energy True/False Indicate whether the statement is true or false. 1. Energy is the ability to cause change. 2. Energy is measured in joules. 3. When you ride a playground swing, your
More informationStudy the following diagrams of the States of Matter. Label the names of the Changes of State between the different states.
Describe the strength of attractive forces between particles. Describe the amount of space between particles. Can the particles in this state be compressed? Do the particles in this state have a definite
More informationCalorimetry: Heat of Vaporization
Calorimetry: Heat of Vaporization OBJECTIVES INTRODUCTION - Learn what is meant by the heat of vaporization of a liquid or solid. - Discuss the connection between heat of vaporization and intermolecular
More informationTemperature affects water in the air.
KEY CONCEPT Most clouds form as air rises and cools. BEFORE, you learned Water vapor circulates from Earth to the atmosphere Warm air is less dense than cool air and tends to rise NOW, you will learn How
More informationGas Laws. The kinetic theory of matter states that particles which make up all types of matter are in constant motion.
Name Period Gas Laws Kinetic energy is the energy of motion of molecules. Gas state of matter made up of tiny particles (atoms or molecules). Each atom or molecule is very far from other atoms or molecules.
More informationPhysical Properties of a Pure Substance, Water
Physical Properties of a Pure Substance, Water The chemical and physical properties of a substance characterize it as a unique substance, and the determination of these properties can often allow one to
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Sample Mid-Term 3 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) If you double the frequency of a vibrating object, its period A) is quartered.
More informationTHIRD GRADE WEATHER 1 WEEK LESSON PLANS AND ACTIVITIES
THIRD GRADE WEATHER 1 WEEK LESSON PLANS AND ACTIVITIES WATER CYCLE OVERVIEW OF THIRD GRADE WATER WEEK 1. PRE: Comparing the different components of the water cycle. LAB: Contrasting water with hydrogen
More informationMinnesota Comprehensive Assessments-Series III
Not for student use. Minnesota Comprehensive Assessments-Series III Science Item Sampler Script Grade 8 S ARE NOT SECURE TEST MATERIALS. THIS ITEM SAMPLER SCRIPT MAY BE COPIED OR DUPLICATED. MINNESOTA
More informationOrder of the Weather Experiments
Order of the Weather Experiments 1. Staying Dry Towel in bottle--student i. Magic Air Pushing the stick down-- Student ii. Air Power Water in funnel--teacher 2. Tipping the Scale Weighing air--student
More informationKINETIC MOLECULAR THEORY OF MATTER
KINETIC MOLECULAR THEORY OF MATTER The kinetic-molecular theory is based on the idea that particles of matter are always in motion. The theory can be used to explain the properties of solids, liquids,
More informationTest Bank - Chapter 3 Multiple Choice
Test Bank - Chapter 3 The questions in the test bank cover the concepts from the lessons in Chapter 3. Select questions from any of the categories that match the content you covered with students. The
More informationName Date Class STATES OF MATTER. SECTION 13.1 THE NATURE OF GASES (pages 385 389)
13 STATES OF MATTER SECTION 13.1 THE NATURE OF GASES (pages 385 389) This section introduces the kinetic theory and describes how it applies to gases. It defines gas pressure and explains how temperature
More information