Chapter 28. Gauss s Law

Transcription

1 Chapter 28. Gauss s Law The nearly spherical shape of the girl s head determines the electric field that causes her hair to stream outward. Using Guass s law, we can deduce electric fields, particularly those with a high degree of symmetry, simply from the shape of the charge distribution. Chapter Goal: To understand and apply Gauss s law.

2 Chapter 28. Gauss s Law Topics: The Concept of Flux Gauss s Law Conductors in Electrostatic Equilibrium Calculating Electric Flux Symmetry Using Gauss s Law

3 Chapter 28. Reading Quizzes

4 The amount of electric field passing through a surface is called A. Electric flux. B. Gauss s Law. C. Electricity. D. Charge surface density. E. None of the above.

5 The amount of electric field passing through a surface is called A. Electric flux. B. Gauss s Law. C. Electricity. D. Charge surface density. E. None of the above.

6 Gauss s law is useful for calculating electric fields that are A. symmetric. B. uniform. C. due to point charges. D. due to continuous charges.

7 Gauss s law is useful for calculating electric fields that are A. symmetric. B. uniform. C. due to point charges. D. due to continuous charges.

8 Gauss s law applies to A. lines. B. flat surfaces. C. spheres only. D. closed surfaces.

9 Gauss s law applies to A. lines. B. flat surfaces. C. spheres only. D. closed surfaces.

10 The electric field inside a conductor in electrostatic equilibrium is A. uniform. B. zero. C. radial. D. symmetric.

11 The electric field inside a conductor in electrostatic equilibrium is A. uniform. B. zero. C. radial. D. symmetric.

12 Chapter 28. Basic Content and Examples

13 The Electric Flux The electric flux measures the amount of electric field passing through a surface of area A whose normal to the surface is tilted at angle from the field. We can define the electric flux more concisely using the dot-product:

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15 EXAMPLE 28.1 The electric flux inside a parallel-plate capacitor QUESTION:

16 EXAMPLE 28.1 The electric flux inside a parallel-plate capacitor

17 EXAMPLE 28.1 The electric flux inside a parallel-plate capacitor

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19 Tactics: Evaluating surface integrals

20 The Electric Flux through a Closed Surface The electric flux through a closed surface is The electric flux is still the summation of the fluxes through a vast number of tiny pieces, pieces that now cover a closed surface. NOTE: A closed surface has a distinct inside and outside. The area vector da is defined to always point toward the outside. This removes an ambiguity that was present for a single surface, where da could point to either side.

21 Gauss s Law For any closed surface enclosing total charge Q in,the net electric flux through the surface is This result for the electric flux is known as Gauss s Law.

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25 Electrostatics of Conductors Using the Gauss law, we can derive a set of important properties about conductors in electrostatic equilibrium. (You may claim that you understand a little electrostatics if you know all the following results. )

26 Interior of Conductors in Electrostatic Equilibrium 1. The electric field is zero at all points within a conductor in electrostatic equilibrium. Otherwise, the electric field would cause electrons to move and thus violate the assumption that all the charges are at rest. 2. There can be no net charge inside any conductor in electrostatic equilibrium. Otherwise, we construct a Gaussian surface around the region with nonvanishing net charge, and we must have non-zero field on the surface--in contradiction with result > The inside of a conductor is completely empty as far as electrostatics is concerned.

27 Boundary of Conductors in Electrostatic Equilibrium 3. All charges on a conductor must be distributed on its surface: surface charge. The electric field outside of conductor can be nonzero. 4. Right outside a conductor, the tangent component of the field must be vanish: otherwise surface charge will move. --> The field on the conductor surface must be perpendicular to the surface.

28 The Normal Component of Field at the outer-surface of Conductor a). Construct a cylindrical Gaussian surface and integrate the field over. b). The flux through the inner disk and side surface is clearly zero c). The flux through the outer disk is given by E A. d). The total flux through the cylinder Is given by the Gauss law. 5. The magnitude of electric field on the outer-surface of a conductor is proportional to the surface charge density.

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30 Cavity inside a Conductor In the presence of a cavity, again there can be no net charge in the interior of a conductor.