Problems. Mr. B s Chemistry. Name. Date Block
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1 Mr. B s Chemistry Name Date Block Problems Answer the following questions. You have 25 minutes, and you may not use a calculator. You may use the periodic table in the back of the book. For each question, circle the letter of your choice. 1. How many milliliters of M H 2 SO 4 are required to neutralize 50.0 ml of M KOH? A ml B ml C ml D ml E ml 2. A sample of oxalic acid, H 2 C 2 O 4, is titrated with standard sodium hydroxide, NaOH, solution. A total of ml of M NaOH is required to completely neutralize ml of the acid. What is the concentration of the acid? A M B M C M D M E M 3. A solution is prepared by mixing 50.0 ml of 0.20 M arsenic acid, H 3 AsO 4, and 50.0 ml of 0.20 M sodium hydroxide, NaOH. Which anion is present in the highest concentration? A. HAsO 4 2 B. OH C. H 2 AsO 4 D. Na + E. AsO H Fe 2+ + Cr 2 O Cr Fe H 2 O This reaction is used in the titration of an iron solution. What is the concentration of the iron solution if it takes ml of M Cr 2 O 7 2 solution to titrate ml of an acidified iron solution? A M B M C M D M E M
2 5. Tungsten metal may be prepared by reducing WO 3 with H 2 gas. How many grams of tungsten may be prepared from mol of WO 3 with excess hydrogen? A g B g C g D. 184 g E g 6. Manganese, Mn, forms a number of oxides. A particular oxide is 63.2% Mn. What is the simplest formula for this oxide? A. MnO B. Mn 2 O 3 C. Mn 3 O 4 D. MnO 2 E. Mn 2 O 7 7. Vanadium forms a number of oxides. In which of the following oxides is the vanadiumto-oxygen mass ratio 2.39:1.00? A. VO B. V 2 O 3 C. V 3 O 4 D. VO 2 E. V 2 O 5 8. How many grams of nitrogen are in 25.0 g of (NH 4 ) 2 SO 4? A g B g C g D g E g 9. Nitrogen forms a number of oxides. Which of the following oxides is 64% nitrogen? A. N 2 O 5 B. N 2 O 4 C. N 2 O 3 D. N 2 O 2 E. N 2 O 10. Sodium sulfate forms a number of hydrates. A sample of a hydrate is heated until all the water is removed. What is the formula of the original hydrate if it loses 43% of its mass when heated? A. Na 2 SO 4 H 2 O B. Na 2 SO 4 2H 2 O C. Na 2 SO 4 6H 2 O D. Na 2 SO 4 8H 2 O E. Na 2 SO 4 10H 2 O
3 11. 3Cu(s) + 8HNO 3 (aq) 3Cu(NO 3 ) 2 (aq) + 2 NO(g) + 4 H 2 O(l) Copper metal reacts with nitric acid according to the above equation. A 0.30-mol sample of copper metal and 10.0 ml of 12 M nitric acid are mixed in a flask. How many moles of NO gas will form? A mol B mol C mol D mol E mol 12. Gold(III) oxide, Au 2 O 3, can be decomposed to gold metal, Au, plus oxygen gas, O 2. How many moles of oxygen gas will form when 221 g of solid gold(iii) oxide is decomposed? The formula mass of gold(iii) oxide is 442. A mol B mol C mol D mol E mol 13. C 4 H 11 N(1) + O 2 (g) CO 2 (g) + H 2 O(l) + N 2 (g) When the above equation is balanced, the lowest whole number coefficient for O 2 is: A. 4 B. 16 C. 22 D. 27 E KMnO H 2 C 2 O H 2 SO 4 K 2 SO MnSO CO H 2 O How many moles of MnSO 4 are produced when 1.0 mol of KMnO 4, 5.0 mol of H 2 C 2 O 4, and 3.0 mol of H 2 SO 4 are mixed? A. 4.0 mol B. 5.0 mol C. 2.0 mol D. 2.5 mol E. 1.0 mol 15. KClO 3 KCl + O 2 After the above equation is balanced, how many moles of O 2 can be produced from 4.0 mol of KClO 3? A. 2.0 mol B. 4.0 mol C. 5.0 mol D. 6.0 mol E. 3.0 mol
4 16. When the following equation is balanced, it is found that 1.00 mol of C 8 H 18 reacts with how many moles of O 2? C 8 H 18 + O 2 CO 2 + H 2 O A mol B mol C mol D mol E mol 17. Ca + 2 H 2 O Ca(OH) 2 + H 2 Calcium reacts with water according to the above reaction. What volume of hydrogen gas, at standard temperature and pressure, is produced from mol of calcium? A L B L C L D L E L 18. 2CrO SnO H 2 O 2 CrO SnO OH How many moles of OH form when 50.0 ml of M CrO 4 2 is added to a flask containing 50.0 ml of M SnO 2 2? A mol B mol C mol D mol E mol 19. A solution containing 0.20 mol of KBr and 0.20 mol of MgBr 2 in 2.0 liters of water is provided. How many moles of Pb(NO 3 ) 2 must be added to precipitate all the bromide as insoluble PbBr 2? A mol B mol C mol D mol E mol
5 Answers and Explanations There are multiple "correct" ways to do these calculations. Only one calculation is shown for each answer. 1. D The reaction is H 2 SO KOH K 2 SO H 2 O 2. C The reaction is H 2 C 2 O NaOH Na 2 C 2 O H 2 O 3. C Moles acid = (50.0 ml)(0.20 mol acid/1000 ml) = mol Moles base = (50.0 ml)(0.20 mol base/1000 ml) = mol There is sufficient base to react completely with only one of the ionizable hydrogens from the acid. This leaves H 2 AsO A Ox = oxidizing agent = Cr 2 O 7 2 ; Red = reducing agent = Fe C The reaction is WO H 2 W + 3 H 2 O ( mol WO 3 )(l mol W/l mol WO 3 ) (183.8 g W/1 mol W) = 9.19 g W 6. D 63.2% Mn leaves 36.8% O 63.2/54.94 = 1.15 Mn 36.8/16.0 = 2.30 O Thus, there is 1 Mn/2 O. 7. C V: 2.39/50.94 = O:1.00/16.0 =
6 0.0469/ = / = 1.33 Multiplying both by three gives: 3 V and 4 O. 8. A (25.0 g(nh 4 ) 2 SO 4 )(l mol(nh 4 ) 2 SO 4 /132 g) (2 mol N/l mol(nh 4 ) 2 SO 4 )(14.0 g N/1 mol N) = 5.30 g C [(6 mol H 2 O)(18 g/mol H 2 O)]/(250 g Na 2 SO 4 6 H 2 O) 100% = 43% 11. B Calculate the moles of acid to compare to the moles of Cu: (10.0 ml)(12 mol/1000 ml) = 0.12 mol The acid is the limiting reactant, and will be used to calculate the moles of NO formed. (0.12 mol acid)(2 mol NO/8 mol acid) = mol 12. E The balanced chemical equation is: 2 Au 2 O 3 4 Au + 3 O 2 (221 g Au 2 O 3 )(l mol Au 2 O 3 /442 g Au 2 O 3 )(3 mol O 2 /2 mol Au 2 O 3 ) = mol O D The balanced equation is: 4 C 4 H 11 N(l) + 27 O 2 (g) 16 CO 2 (g) + 22 H 2 O(1) + 2 N 2 (g) 14. E The KMnO 4 is the limiting reagent. Each mole of KMnO 4 will produce a mole of MnSO D The balanced equation is: 2 KClO 3 2 KCl + 3 O 2 (4.0 mol KClO 3 )(3 mol O 2 /2 mol KCIO 3 ) = 6.0 mol O E The balanced equation is: 2 C 8 H O 2 16 CO H2O (1.00 mol C 8 H 18 )(25 mol O 2 /2 mol C 8 H 18 ) = 12.5 mol O E (0.200 mol Ca)(l mol H 2 /l mol Ca)(22.4 L at STP/l mol H 2 )= 4.48 L 18. C There are mol of CrO 4 2 and an equal number of mol of SnO 2 2. Thus SnO 2 2 is the limiting reactant (larger coefficient in the balanced reaction). ( mol SnO 2 2 )(2 mol OH /3 mol SnO 2 2 ) = mol OH 19. D The volume of water is irrelevant mol of KBr will require 0.10 mol of Pb(NO 3 ) 2
7 0.20 mol of MgBr 2 will require 0.20 mol of Pb(NO 3 ) 2 Total the two yields.
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