4. How many integers between 2004 and 4002 are perfect squares?



Similar documents
Advanced GMAT Math Questions


2006 Geometry Form A Page 1

13. Write the decimal approximation of 9,000,001 9,000,000, rounded to three significant

2014 Chapter Competition Solutions

CSU Fresno Problem Solving Session. Geometry, 17 March 2012

SAT Subject Math Level 2 Facts & Formulas

Parallel and Perpendicular. We show a small box in one of the angles to show that the lines are perpendicular.


PERIMETER AND AREA. In this unit, we will develop and apply the formulas for the perimeter and area of various two-dimensional figures.

Geometry Regents Review

SAT Subject Math Level 1 Facts & Formulas

Baltic Way Västerås (Sweden), November 12, Problems and solutions

Algebra Geometry Glossary. 90 angle

PYTHAGOREAN TRIPLES KEITH CONRAD

DEFINITIONS. Perpendicular Two lines are called perpendicular if they form a right angle.

Definitions, Postulates and Theorems

Chapter 8 Geometry We will discuss following concepts in this chapter.

Conjectures. Chapter 2. Chapter 3

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Tuesday, August 13, :30 to 11:30 a.m., only.

San Jose Math Circle April 25 - May 2, 2009 ANGLE BISECTORS

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Wednesday, January 29, :15 a.m. to 12:15 p.m.

2015 Chapter Competition Solutions

Trigonometric Functions and Triangles

Factoring Polynomials

MATH 21. College Algebra 1 Lecture Notes

43 Perimeter and Area

1 Solution of Homework

Solutions to old Exam 1 problems

CHAPTER 8, GEOMETRY. 4. A circular cylinder has a circumference of 33 in. Use 22 as the approximate value of π and find the radius of this cylinder.

Quick Reference ebook

Solutions to Practice Problems

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Student Name:

Selected practice exam solutions (part 5, item 2) (MAT 360)

Additional Topics in Math

6.1 Basic Right Triangle Trigonometry

Exercise Set 3. Similar triangles. Parallel lines

Section 7.1 Solving Right Triangles

Solutions Manual for How to Read and Do Proofs

GEOMETRIC MENSURATION

Answer Key for California State Standards: Algebra I

CIRCLE COORDINATE GEOMETRY

AMC 10 Solutions Pamphlet TUESDAY, FEBRUARY 13, 2001 Sponsored by Mathematical Association of America University of Nebraska

Biggar High School Mathematics Department. National 5 Learning Intentions & Success Criteria: Assessing My Progress

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Thursday, January 24, :15 a.m. to 12:15 p.m.

Math Review. for the Quantitative Reasoning Measure of the GRE revised General Test

Warm-up Tangent circles Angles inside circles Power of a point. Geometry. Circles. Misha Lavrov. ARML Practice 12/08/2013

1.3. DOT PRODUCT If θ is the angle (between 0 and π) between two non-zero vectors u and v,

Conjectures for Geometry for Math 70 By I. L. Tse

You must have: Ruler graduated in centimetres and millimetres, protractor, compasses, pen, HB pencil, eraser, calculator. Tracing paper may be used.

Warm-up Theorems about triangles. Geometry. Theorems about triangles. Misha Lavrov. ARML Practice 12/15/2013

2004 Solutions Ga lois Contest (Grade 10)

Grade 7 & 8 Math Circles Circles, Circles, Circles March 19/20, 2013

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY


D.3. Angles and Degree Measure. Review of Trigonometric Functions

39 Symmetry of Plane Figures

Math 531, Exam 1 Information.

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Wednesday, January 28, :15 a.m. to 12:15 p.m.

Vocabulary Words and Definitions for Algebra

Visualizing Triangle Centers Using Geogebra

How To Solve The Pythagorean Triangle

Solutions to Exercises, Section 5.1

Area. Area Overview. Define: Area:

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Thursday, August 13, :30 to 11:30 a.m., only.

QUADRATIC EQUATIONS EXPECTED BACKGROUND KNOWLEDGE

Wednesday 15 January 2014 Morning Time: 2 hours

SAT Math Facts & Formulas Review Quiz

SPECIAL PRODUCTS AND FACTORS

Postulate 17 The area of a square is the square of the length of a. Postulate 18 If two figures are congruent, then they have the same.

4. Binomial Expansions

Solutions to Homework 10

WEDNESDAY, 2 MAY 1.30 PM 2.25 PM. 3 Full credit will be given only where the solution contains appropriate working.

Geometry EOC Practice Test #2

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Student Name:

MATH Fundamental Mathematics IV

Section 9-1. Basic Terms: Tangents, Arcs and Chords Homework Pages : 1-18

MA107 Precalculus Algebra Exam 2 Review Solutions

INCIDENCE-BETWEENNESS GEOMETRY

1. Find the length of BC in the following triangles. It will help to first find the length of the segment marked X.

Geometry and Measurement

Solving Quadratic Equations

Just the Factors, Ma am

Right Triangles 4 A = 144 A = A = 64

Intermediate Math Circles October 10, 2012 Geometry I: Angles

5.3 The Cross Product in R 3

2nd Semester Geometry Final Exam Review

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION GEOMETRY. Thursday, January 26, :15 a.m. to 12:15 p.m.

The common ratio in (ii) is called the scaled-factor. An example of two similar triangles is shown in Figure Figure 47.1

ACT Math Vocabulary. Altitude The height of a triangle that makes a 90-degree angle with the base of the triangle. Altitude

Math Placement Test Practice Problems

Algebra I Vocabulary Cards

of surface, , , of triangle, 548 Associative Property of addition, 12, 331 of multiplication, 18, 433

2. If C is the midpoint of AB and B is the midpoint of AE, can you say that the measure of AC is 1/4 the measure of AE?

Circumference Pi Regular polygon. Dates, assignments, and quizzes subject to change without advance notice.

Unit 3: Circles and Volume


Vector Notation: AB represents the vector from point A to point B on a graph. The vector can be computed by B A.

Triangle Trigonometry and Circles

2010 Solutions. a + b. a + b 1. (a + b)2 + (b a) 2. (b2 + a 2 ) 2 (a 2 b 2 ) 2

Transcription:

5 is 0% of what number? What is the value of + 3 4 + 99 00? (alternating signs) 3 A frog is at the bottom of a well 0 feet deep It climbs up 3 feet every day, but slides back feet each night If it started climbing on January, on what date does it get to the top of the well? 4 How many integers between 004 and 400 are perfect squares? 5 Let the operation be defined by a b = a + 3 b What is the value of ( 0) (0 )? 6 The radius of each small circle is /6 of the radius of the large surrounding circle The radius of the middle-sized circle is twice that of either small circle What fraction of the area of the large circle lies outside the three interior circles? 7 What is the number of square units enclosed by the polygon ABCDE? A E B C D

8 What is the value of 004 + 00 003 000? 9 What is the area of the region of the plane satisfying x + y? 0 The square below can be filled in so that each row and each column contains each of the numbers,, 3, and 4 exactly once What does x equal? x 4 Johnny was ill and had to take a test a day late His 96 raised the class average from 7 to 7 How many students, including Johnny, took the test? The pentagon ABCDE has a right angle at A, AB = AE, and ED = DC = CB = If BE = and is parallel to CD, what is the area of the pentagon? A B C D E 3 What value of x satisfies the equation x + 0 + 4 x + 0 =? 4 A quadratic polynomial f satisfies f(x) 0 for all x, f() = 0, and f(3) = 3 What is f(5)?

5 In each hand, a girl holds a different end of a 6-inch long piece of light string that has a heavy bead on it Initially her hands are together How many inches apart must she pull her hands, keeping them at the same height, so that the bead moves upward by 8 inches? 6 Set t = and t n+ = (t n )/(t n + ) What is t 03? 7 If a b and ( a( b) b( a)) =, what is the value of (a + b)/(ab)? 8 In the following figure, AD = AE, and F is the intersection of the extension of ED with the bisector of the angle C If angle B = 40 degrees, how many degrees are there in angle CF E? A F D E G B C 9 Let N = 999,999,999,999,999,999 How many 9 s are in the decimal expansion of N 0 If a, b, and c denote the solutions of the equation x 3 x 5x+8 = 0, what is the value of ab + ac + bc? How many integers n satisfy n 4 + 6n < 6n 3 + n? Let P be the point (8, 0) Suppose P Q is tangent to the circle x +y = 4 at the point Q What is the length P Q? 3 Find all ordered triples of positive integers (a, b, c) for which a 3 b 3 c 3 = 3abc and a = (b + c) 3

4 What is the largest prime p such that there is a prime q for which p + q and p + 7q are both squares? 5 A square is partitioned into 30 non-overlapping triangles, so that each side of the square is a side of one of the triangles We also require that the intersection of any two triangles is either empty, a common vertex, or a common edge How many points in the interior of the square serve as vertices of one or more triangles? 6 How many 4-digit numbers (from 000 to 9999) have at least one digit occurring more than once? 7 What is the sum of all positive integers x for which there exists a positive integer y with x y = 00? 8 A triangle has sides s, s, and s 3 of lengths 0, 9, and x, respectively The angle between s and s 3 is 60 degrees What is the difference of the two possible values for x? 9 What is the sum of all -digit positive integers which exceed the product of their digits by? 30 In the diagram below a circular arc centered at one vertex of a square of side length 4 passes through two other vertices A small circle is tangent to the large circle and to two sides of the square What is the radius of the small circle? 4

3 What is the sum of all positive integers n for which 8 + + n is a perfect square? 3 What is the area of the shaded region in the diagram below? 3 3 3 3 33 Suppose the function f satisfies f(x) + f(x ) = x and f(9) = 94 What is f(94)? 34 What is the number of degrees in the acute angle θ satisfying cos(θ) = +? 35 A number y is selected at random in the interval [0, 0] (with uniform probability distribution) A right triangle with hypotenuse of length 0 is formed with one end of the hypotenuse at the point (0, y) and the other on the nonnegative x-axis The third vertex is at (0,0) What is the probability that the area of the triangle is greater than 5? 36 What is the sum of the reciprocals of all positive integers none of whose prime divisors is greater than 3? That is, what is the value of + + 3 + 4 + 6 + 8 + 9 + 37 How many ordered pairs (x, y) of integers satisfy x + y =? (Note that both positive and negative integers are allowed) 5

38 What is the smallest value of n for which the product is a perfect square? ( )(3 )(4 ) (n ) 39 Note that 649 3 80 = Find an integer a satisfying 649 < a < 0 8 such that a 3b = for some positive integer b < a 40 Suppose triangle ABC is equilateral, and AF = BD = CE = AB 3 What is the ratio of the area of triangle ABC to that of the shaded triangle? C A E F D B 6

Solutions to 004 exam Numbers in brackets are (a) the number of people out of the top 30 who answered the question correctly, and (b) the number of people out of the other 39 who answered the question correctly 5 [30, 37] 5 = x implies x = 5 5 5 50 [9, 3] There are 50 pairs, each summing to 3 Jan 8 [6, 7] It will get to height 3 on Jan, height 4 on Jan,, and height 0 on Jan 8 4 9 [6, 85] 44 = 936, 45 = 05, 63 = 3969, and 64 = 4096 Thus it is the integers from 45 to 63, inclusive 5 5 [6, 0] It is ( + 3 0 ) (0 + 3 ) = 5 3 = 5 + 3 3 6 5/6 [8, 85] Let the radius of the large circle be Then the sum of the areas of the three circles is π( + + ) = π/6, while that of the 36 36 9 large circle is π 7 50 [8, 97] The region can be divided into two trapezoids, divided by the horizontal line through B The area of the top one is 4(4+6)/ = 0 and the area of the bottom one is 6(4 + 6)/ = 30 8 8/7 [6, 48] Divide top and bottom by 000, getting (6 + )/(8 ) 9 6 [5, 6] It is the area inside a diamond with vertices at (±, 0) and (0, ±) minus that in the diamond /4 the size (/ in each direction) Thus it is 3 4 Here we have considered the four quadrants 4 7

0 4 [30, 9] In the diagram below, the bottom row is forced, then the second column, then the top row, and then the third column 4 3 x 3 4 5 [6, 85] If x is the desired number of students, then 7(x )+96 = 7x, and so x = 96 7 + 4 3 3 [, 33] The right triangle ABE has area The vertical displacement from BE to CD is 3 Thus the area of the bottom is ( ) 3 3 7 [6, 80] Let y = 4 x + 0 Then y + y = 0, so y = 3, since y cannot be negative Thus x + 0 = 3 4 4 [8, 9] f(x) = a(x ) and 4a = 3 Thus f(5) = 3 4 4 = 5 4 [4, 64] The bead was initially 3 inches below the level of her hands When it has moved up 8 inches, it will be 5 inches below the level of her hands, and will be 3 inches from each hand Thus each hand will have moved (= 3 5 ) inches out 6 / [4, 8] t = /3 t 3 = / t 4 = 3 t 5 = = t Thus the numbers repeat with period 4, and t 03 = t 3 7 [0, 9] Either a( b) = b( a), in which case a = b, which has been excluded, or a( b) = b( a) This gives a + b = ab, so (a + b)/(ab) = 8 0 [0, 5] Let the desired angle equal x, the base angles of the isosceles triangle ADE equal y, and the two halves of angle C equal z Comparing triangles ADE and ABC yields y = z + 40 Comparing triangles DF G and BCG yields x + y = 40 + z Thus x = 40 40/ 8

9 7 [7, 6] N = (0 8 ) = 0 36 0 8 + Its decimal expansion has 9 s in positions 0 9 through 0 35 0 /4 [6, 0] The desired quantity equals (a + b + c)/(abc) Since (x a)(x b)(x c) = x 3 x 5x + 8, we obtain a + b + c = and abc = 8 4 [6, 35] We must have n(n )(n 6) < 0 Thus the factors n +, n, n, and n 6 must be nonzero, and an odd number of them are negative Hence n =, 3, 4, or 5 60 or 5 [8, 9] If O is the origin, then P OQ is a right triangle with hypotenuse 8 and one leg The other leg is P Q which equals 60 3 (,,) [5, ] The first equation says that a is the largest of the three, and the second equation that a is even Thus a > b + c = a /, and hence 4 > a Thus a =, b =, and c = is the only possibility 4 [, 4] Let p + q = a and p + 7q = b Then 6q = (b a)(b + a) Thus one of b ± a must be even, and hence both are even (since their difference is even) Since q is prime, we must have q =, then b = 4, a =, and p = 5 4 [8, 3] If there are v interior vertices, then the total number of degrees in all the angles (including the interior vertices and the four vertices of the square) is, on the one hand, 30 80 and, on the other hand, 360v + 4 90 Thus 30 = v + 6 4464 [9, 4] There are 9000 4-digit numbers To enumerate those with all digits distinct, we have 9 choices for the first digit (since 0 is excluded), then 9 for the second (ie all digits except the first), 8 for the third, and 7 for the fourth Our answer is 9000 9 9 8 7 9

7 67 [8, 0] Since x y = (x + y)(x y), we need the factorizations of 00 = 7 3 The pair (x + y, x y) can equal any of the following: (00,), (43,7), (9,), or (77,3) Thus the sum of the x-values is (00 + 50 + 0 + 90) = 67 8 6 or 4 [7, 5] The Law of Cosines yields 8 = 00 + x 0x cos(60) Thus x 0x + 9 = 0, so x = (0 ± 00 76) 9 67 [4, 48] (0a + b) ab = implies (0 b)(a ) = and so the numbers are 39 and 8 30 8 [0, ] Let r denote the desired radius The little 45-45-90 triangle in the top right corner with hypotenuse going from the center of the small circle to the top right vertex of the square and one leg along the top edge of the square implies 4 4 r = r (This is two ways of viewing the length of that hypotenuse) Thus r( +) = 4( ) and so r = 4( + )/( ) 3 [0, 0] 8 + + n = k implies n = k (+8) 8 = k (3 4 ) = (k + 3 4 )(k 3 4 ) Thus there exist integers a > b > 0 such that a +b = n, a = k +3 4, and b = k 3 4 Hence b ( a b ) = 3 5, from which we deduce b = 5 and a = 7 Alternatively, + u + v with 0 < u < v is a perfect square if and only if v = u Then 8 + + n must equal i ( + u + u ) Then i + u =, i = 8, so i + u = 3 90/7 or 7 /7 [6, ] Let h denote the width of a strip, y the length of the leg of a white triangle emanating from a vertex of the square, and x the shorter leg of a white triangle Then similar triangles yield y/5 = x/3, y/3 = h/, and (y x)/3 = /(x + y + h) We obtain y = 5 3 x, then h = 0 9 x, then x/9 = /( 34 9 x) so x = 9/ 34 Hence the shaded area is 0 + 0 h = 0 00/34 = 90/7 33 456 [4, 0] f(94) = 94 f(93) = 94 93 + f(9) Continuing this 0

way yields f(94) = 94 93 + + + 0 94 = (94 + 93)(94 93) + + ( + )( ) + 400 94 = 94 + 93 + + + + 306 = (95 94 0) + 306 = 456 34 5 [8, ] We have cos(θ) = cos (θ) = ( 4 ( + )) = We deduce θ equals 45 degrees 35 5 0 [6, 0] We desire the probability that y 00 y > 30 Equality is obtained if y (00 y ) = 900 and so y 4 00y + 900 = 0 Hence y = 0 or 90 The desired probability is ( 90 0)/0 = (3 0 0)/0 = 5 0 36 3 [, 0] It is i,j i 3 j = i i j = 3 j = 3 / /3 37 5 [7, 4] For x, y 0, the equation reduces to (x + y) = xy or (x )(y ) = 4 Thus (x, y ) equals (, ), ±(4, ), or ±(, 4) Note that it cannot equal (, ) since that corresponds to (x, y) = (0, 0) 38 8 [, 4] Writing i = (i )(i+) and removing the square (i+) that occurs in (i )((i+) ), we are asking for the smallest n > for which n(n + ) is a perfect square Here you can just try until you find that it works at n = 8 You can make the numbers a little smaller by letting n = a or a + and removing the 39 8440 [0, 0] We have (649 + 80 3)(649 80 3) = Expand the squares of both factors, obtaining (8440 + 33640 3)(8440 33640 3) = Hence a = 8440 and b = 33640 works 40 7 or 7: [, 0] Let α denote the area of the small triangles, β the area of the quadrilaterals, and γ the area of the desired small equilateral triangle, as indicated below Since the area of triangle CF B is twice

the area of CAF, we obtain (α + β) = β + α + γ, and hence γ = 3α The Law of Cosines says CF = AF +(3AF ) AF (3AF ) cos(60) = 7AF Since triangle ACF is similar to the little triangle in the lower left, their areas are proportional to CF : AF = 7 Thus α + β = 7α and so β = 5α The desired ratio is (γ + 3α + 3β)/γ = (3α + 3α + 5α)/3α = 7 C A E α β β γ α β F D α B