Sample Test 1 SAMPLE TEST 1. CHAPTER 12

Size: px
Start display at page:

Download "Sample Test 1 SAMPLE TEST 1. CHAPTER 12"

Transcription

1 13 Sample Test 1 SAMPLE TEST 1. CHAPTER The molality of a solution is defined as a. moles of solute per liter of solution. b. grams of solute per liter of solution. c. moles of solute per kilogram of solution. d. moles of solute per kilogram of solvent. e. the gram molecular weight of solute per kilogram of solvent. > d moles of solute per kilogram of solvent. 2. What is the molarity of a NH 3 solution which contains 4.25 g of NH 3 in 2.00 L of solution? a M b M c M d M e M > a M 3. What is the percent NaCl by mass in a 1.00 molal aqueous solution? a b c d e > a How many moles of ethanol, must be dissolved in one hundred grams of water to give a 1.5 molal solution? a. 15 b. 1.5 c d e > c When one mole of a nonvolatile nonelectrolyte is dissolved in three moles of a solvent, the vapor pressure of the solution compared to that of the pure solvent is a. 1/4. b. 1/3. c. 1/2. d. 2/3. e. 3/4. > e 3/4. 6. Using Raoult's law, given that the pure vapor pressure of water (M.W g/mol) at 75oC is 290mmHg, the vapor pressure of an aqueous solution at 75oC containing 60g of urea (M.W g/mol), a nonelectrolyte, in 180g of water is a. 29 mmhg. b. 100 mmhg. c. 130 mmhg. d. 190 mmhg. e. 264 mmhg. > e 264 mmhg. 7. According to Henry's Law, the concentration of a gas in solution at a constant temperature is directly proportional to a. the pressure of the gas above the solution. b. the vapor pressure of the pure solvent. c. the mole fraction of solvent present. d. Each of these statements is true. > a the pressure of the gas above the solution. 8. A 60.0-g sample of NaOH ( F.W g/mol) is dissolved in water, and the solution is diluted to give a final volume of 3.00 L. The molarity of the final solution is

2 a M. b M. c M. d M. e M. > a M. 9. How many grams of Na 2 SO 4 (F.W. 142 g/mol) are contained in L of M Na 2 SO 4 solution? a b c d e > a Using Raoult's law, given that the pure vapor pressure of water (M.W g/mol) at 75oC is 290mmHg, the vapor pressure of an aqueous solution at 75oC containing 60g of urea (M.W g/mol), a nonelectrilyte, in 180g of water is a. 29 mmhg. b. 100 mmhg. c. 130 mmhg. d. 190 mmhg. e. 264 mmhg. > e 264 mmhg. 11. The solubility of a gas in a liquid can always be increased by a. increasing the temperature of the solvent. b. decreasing the polarity of the solvent. c. decreasing the temperature of the gas above the solvent. d. decreasing the pressure of the gas above the solvent. e. increasing the pressure of the gas above the solvent. > e increasing the pressure of the gas above the solvent. 12. Which one of the following is not a colligative property? a. osmotic pressure. b. boiling point elevation. c. density d. vapor pressre lowering. e. freezing-point depression > c density 13. If mol of napthalene is dissolved in g of benzene (C 6 H 6 ), what is the molality? a b c d e > c What is the mole fraction of methanol, CH 3 OH (M.W. 32 g/mol), in an ethanol, C 2 H 5 OH (M.W. 46 g/mol), solution that is 60.0% ethanol by mass? a b c d e > c What is the molality of ethyl alcohol, C 2 H 5 OH (M.W g/mol), in an aqueous solution that is 50.0% ethyl alcohol by mass? a b c d e

3 > b Which of the following solutions made up of soluble salts has the highest osmotic pressure? a M NaCl b M CaCl 2 c M Ba(NO 3 ) 2 d M Al(NO 3 ) 3 > c 0.15 M Ba(NO 3 ) Calculate the MOLALITY of C 2 H 5 OH in a water solution which is prepared by mixing 50.0 ml of C 2 H 5 OH with ml of H 2 O at 20 C. The density of the C 2 H 5 OH is g/ml at 20 C. a m b m c m d m e. none of these 18. A solution of two liquids, A and B, shows negative deviation from Raoult's Law. This means that a. the molecules of A interact strongly with other A-type molecules. b. the two liquids have a positive heat of solution. c. molecules of A interact weakly, if at all, with B molecules. d. the molecules of A hinder the strong interaction between B molecules. e. molecules of A interact more strongly with B than A with A or B with B. 19. Which of the following is NOT a colligative property? a. freezing point depression b. boiling point elevation c. osmotic pressure d. solubility e. two of the above 20. The molal freezing point depression constants for benzene and water are 5.12 and 1.86 respectively. When 4.6 g of formic acid (HCOOH) is dissolved in 1.0 kg of benzene, the observed freezing point lowering is 0.26C. When the same amount of formic acid is dissolved in 1.0 kg of water, the freezing point is lowered by 0.19C. To explain these results, we must assume that: a. formic acid is ASSOCIATED in benzene and MONOMERIC in water. b. formic acid is MONOMERIC in benzene and DISSOCIATED in water. c. formic acid is MONOMERIC in benzene and ASSOCIATED in water. d. formic acid is DISSOCIATED in benzene and MONOMERIC in water. e. none of these is true. 21. When one mole of a nonvolatile non-dissociating substance is dissolved in two moles of solvent, the ratio of the vapor pressure of the solution to that of the pure solvent (at the same temperature) is approximately: a. 1/3 b. 1/2 c. 2/3 d. 3/2 e. none of these 22. How many grams of water are needed to give a 3.00 m NH 3 solution if 15 moles of NH 3 are to be dissolved in the water? a. 5 b c. 4.5 d e Determine the molarity of a 25.0% CaCl 2 solution that has a density of g/ml. a b c d e What is the MOLALITY of a solution of 50.0 g of propanol (molar mass = 60.1 g/mol) in 152 ml water, if the density of water is 1.0 g/ml? a) 5.47 m b) m c) m d) m e) none of these 25. How many grams of C 12 H 22 O 11 are needed to dissolve in 250g of water to give a x 10-1 m solution? (M.W. C 12 H 22 O 11 = ) a g b g c g d g e. 1600g 15

4 A solution is made by adding mole of ethyl ether to mole of ethyl alcohol. If the vapor pressures of ethyl ether and ethyl alcohol at 20 o C are 375 torr and 20.0 torr, respectively, the vapor pressure of the solution at 20 o C (assuming ideal behavior) is: a) 79.2 torr b) 316 torr c) 47.5 torr d) 395 torr e) none of these 27. The term "proof" is defined as twice the percent by volume of pure ethanol in solution. Thus, a solution that is 95% (by VOLUME) ethanol is 190 proof. What is the MOLARITY of ethanol in a 92 proof ethanol/water solution? density of ethanol = 0.80 g/cm3 density of water = 1.0 g/cm3 mol. wt. of ethanol = 46 a) 0.46 M b) 0.80 M c) 0.92 M d) 8.0 M e) 17 M 28. Vapor pressure (in torr) at 25 o C benzene (C 6 H 6 ) 94.4 chloroform (CH 3 Cl) Using the above data, calculate the total vapor pressure of a chloroform-benzene solution at 25 o C which contains 50.0 g CH 3 Cl and 50.0 g C 6 H 6. Assume the solution behaves ideally. a) 67.8 torr b) 125 torr c) 141 torr d) 172 torr e) none of these 29. When a nonvolatile solute is added to a volatile solvent, the solution vapor pressure, the boiling point, the freezing point, and the osmotic pressure across a semipermeable membrane. a) decreases, increases, decreases, decreases. b) increases, increases, decreases, increases. c) increases, decreases, increases, decreases. d) decreases, decreases, increases, decreases. e) decreases, increases, decreases, increases. 30. A solute added to a solvent raises the boiling point of the solution because a) the temperature to cause boiling must be great enough to boil not only the solvent but also the solute. b) the solute particles lower the solvent's vapor pressure thus requiring a higher temperature to cause boiling. c) the solute particles raise the solvent's vapor pressure thus requiring a higher temperature to cause boiling. d) the solute increases the volume of the solution, and an increase in volume requires an increase in the temperature to reach the boiling point (derived from PV = nrt). e) two of the above are correct. 31. At a given temperature the vapor pressures of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution prepared by mixing benzene and toluene obeys Raoult's law. At this temperature the vapor pressure of benzene over a solution in which the mole fraction of benzene is equal to is a) 417 torr b) 352 torr c) 98.6 torr d) 253 torr e) none of these 32. A solution of hydrogen peroxide is 30.0% H 2 O 2 by mass and has a density of 1.11 g/cm 3. The MOLARITY of the solution is: a) 7.94 M b) 8.82 M c) 9.79 M d) e) none of these 33. A solution containing g of Mg(NO 3 ) 2 per liter has a density of g/ml. The MOLARITY of the solution is: a) M b) M c) M d) M e) none of these 34. The osmotic pressure, in torr, of a M solution of NaCl in water at 25C is APPROXIMATELY:

5 17 a) b) 15.6 c) 372 d) 186 e) none of these 35. When 100. ml of M HCl is diluted to 250. ml, the resulting MOLARITY of the HCl solution is: a) M b) M c) M d) M e) none of these 36. When 1.50 g of glutamic acid is dissolved in g H 2 O, the resulting solution freezes at C. (K f for H 2 O is 1.86C kg/mol.) The molecular weight of glutamic acid is: a) 14.7 g/mol b) 1.50 g/mol c) 189 g/mol d) 28.0 g/mol e) 147 g/mol 37. Benzene and toluene form an ideal solution. At 298K, what is the mole fraction of benzene in the liquid that is in equilibrium with a vapor that has equal partial pressures of benzene and toluene? At 298K, the vapor pressures of pure benzene and pure toluene are 95 and 28 torr, respectively. a) 0.50 b) 0.77 c) 0.23 d) 0.30 e) none of these 38. In order to calculate the freezing point of an ideal dilute solution of a single, non-dissociating solute in a solvent, the minimum information one must know is: a) the molality (of the solute). b) the molality (of the solute) and the freezing point depression constant of the solvent. c) the same quantities as in (b) plus the freezing point of the pure solvent. d) all of the quantities in (c) plus the molecular weight of the solute. e) all of the quantities in (c) plus the weight of the solvent. 39. The vapor pressure of water at 90C is atm. What is the vapor pressure (in atm) of a solution made by dissolving 1.00 mole of CsF(s) in 1.00 kg of water? Assume that Raoult's law applies. a) atm b) atm c) atm d) atm e) none of these 40. Pentane and hexane form an ideal solution. The components have the following properties: - - molar mass - density - bp - vapor pressure at 25 o C pentane g/ml 36 o C 511 torr hexane g/ml 69 o C 150 torr What is the mole fraction of pentane (X pentane ) in the vapor in equilibrium at 25C with a pentane-hexane solution in which X pentane = 0.30? a) X pentane = 0.23 b) X pentane = 0.29 c) X pentane = 0.59 d) X pentane = 0.68 e) X pentane = What is the mole fraction of ethanol, C 2 H 5 OH, in a methanol solution that is 40.%(w/w) methanol, CH 3 OH, by mass? a b c d Answers to questions: 1. > d moles of solute per kilogram of solvent. 2. > a M 3. > a > c > e 3/4. 6. > e 264 mmhg. 7. > a the pressure of the gas above the solution. 8. > a M. 9. > a > e 264 mmhg. 11. > e increasing the pressure of the gas above the solvent. 12. > c density 13. > c 1.00

6 14. > c > b > c 0.15 M Ba(NO 3 ) > d 8.56 m > e molecules of A interact more strongly with B than A with A or B with B > e solubility > a formic acid is ASSOCIATED in benzene and MONOMERIC in water > c 2/ > e a d g 26. a) 79.2 torr 27. >d) 8.0 M 28. >b) 141 torr 29. >e) decreases, increases, decreases, increases. 30. b) the solute particles lower the solvent's vapor pressure thus requiring a higher temperature to cause boiling. 31. d) 253 torr 32. c) 9.79 M 33. a) M 34. c) c) M 36. e) 147 g/mol 37. c) c) the same quantities as in (b) plus the freezing point of the pure solvent. 39. c) atm 40. c) X pentane = c

48 Practice Problems for Ch. 17 - Chem 1C - Joseph

48 Practice Problems for Ch. 17 - Chem 1C - Joseph 48 Practice Problems for Ch. 17 - Chem 1C - Joseph 1. Which of the following concentration measures will change in value as the temperature of a solution changes? A) mass percent B) mole fraction C) molality

More information

Chapter 14 Solutions

Chapter 14 Solutions Chapter 14 Solutions 1 14.1 General properties of solutions solution a system in which one or more substances are homogeneously mixed or dissolved in another substance two components in a solution: solute

More information

2. Why does the solubility of alcohols decrease with increased carbon chain length?

2. Why does the solubility of alcohols decrease with increased carbon chain length? Colligative properties 1 1. What does the phrase like dissolves like mean. 2. Why does the solubility of alcohols decrease with increased carbon chain length? Alcohol in water (mol/100g water) Methanol

More information

13.3 Factors Affecting Solubility Solute-Solvent Interactions Pressure Effects Temperature Effects

13.3 Factors Affecting Solubility Solute-Solvent Interactions Pressure Effects Temperature Effects Week 3 Sections 13.3-13.5 13.3 Factors Affecting Solubility Solute-Solvent Interactions Pressure Effects Temperature Effects 13.4 Ways of Expressing Concentration Mass Percentage, ppm, and ppb Mole Fraction,

More information

Chapter 13. Properties of Solutions

Chapter 13. Properties of Solutions Sample Exercise 13.1 (p. 534) By the process illustrated below, water vapor reacts with excess solid sodium sulfate to form the hydrated form of the salt. The chemical reaction is Na 2 SO 4(s) + 10 H 2

More information

Solutions. Chapter 13. Properties of Solutions. Lecture Presentation

Solutions. Chapter 13. Properties of Solutions. Lecture Presentation Lecture Presentation Chapter 13 Properties of Yonsei University homogeneous mixtures of two or more pure substances: may be gases, liquids, or solids In a solution, the solute is dispersed uniformly throughout

More information

Chapter 13: Properties of Solutions

Chapter 13: Properties of Solutions Chapter 13: Properties of Solutions Problems: 9-10, 13-17, 21-42, 44, 49-60, 71-72, 73 (a,c), 77-79, 84(a-c), 91 solution: homogeneous mixture of a solute dissolved in a solvent solute: solvent: component(s)

More information

Solution concentration = how much solute dissolved in solvent

Solution concentration = how much solute dissolved in solvent Solutions 1 Solutions Concentration Solution concentration = how much solute dissolved in solvent Coffee crystal = solute Water = solvent Liquid Coffee = solution so a solute is dissolved in solvent to

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. A.P. Chemistry Practice Test: Ch. 11, Solutions Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Formation of solutions where the process is

More information

Chapter 11 Properties of Solutions

Chapter 11 Properties of Solutions Chapter 11 Properties of Solutions 11.1 Solution Composition A. Molarity moles solute 1. Molarity ( M ) = liters of solution B. Mass Percent mass of solute 1. Mass percent = 1 mass of solution C. Mole

More information

1) What is the overall order of the following reaction, given the rate law?

1) What is the overall order of the following reaction, given the rate law? PRACTICE PROBLEMS FOR TEST 2 (March 11, 2009) 1) What is the overall order of the following reaction, given the rate law? A) 1st order B) 2nd order C) 3rd order D) 4th order E) 0th order 2NO(g) + H 2(g)

More information

Determination of Molar Mass by Boiling Point Elevation of Urea Solution

Determination of Molar Mass by Boiling Point Elevation of Urea Solution Determination of Molar Mass by Boiling Point Elevation of Urea Solution CHRISTIAN E. MADU, PhD AND BASSAM ATTILI, PhD COLLIN COLLEGE CHEMISTRY DEPARTMENT Purpose of the Experiment Determine the boiling

More information

Chemistry Ch 15 (Solutions) Study Guide Introduction

Chemistry Ch 15 (Solutions) Study Guide Introduction Chemistry Ch 15 (Solutions) Study Guide Introduction Name: Note: a word marked (?) is a vocabulary word you should know the meaning of. A homogeneous (?) mixture, or, is a mixture in which the individual

More information

Chapter 13 Properties of Solutions

Chapter 13 Properties of Solutions Chemistry, The Central Science, 10th edition Theodore L. Brown; H. Eugene LeMay, Jr.; and Bruce E. Bursten Chapter 13 Properties of are homogeneous mixtures of two or more pure substances. In a solution,

More information

EXERCISES. 16. What is the ionic strength in a solution containing NaCl in c=0.14 mol/dm 3 concentration and Na 3 PO 4 in 0.21 mol/dm 3 concentration?

EXERCISES. 16. What is the ionic strength in a solution containing NaCl in c=0.14 mol/dm 3 concentration and Na 3 PO 4 in 0.21 mol/dm 3 concentration? EXERISES 1. The standard enthalpy of reaction is 512 kj/mol and the standard entropy of reaction is 1.60 kj/(k mol) for the denaturalization of a certain protein. Determine the temperature range where

More information

CHEM 36 General Chemistry EXAM #1 February 13, 2002

CHEM 36 General Chemistry EXAM #1 February 13, 2002 CHEM 36 General Chemistry EXAM #1 February 13, 2002 Name: Serkey, Anne INSTRUCTIONS: Read through the entire exam before you begin. Answer all of the questions. For questions involving calculations, show

More information

Colligative Properties

Colligative Properties CH302 LaBrake and Vanden Bout Colligative Properties PROBLEM #1: Give the molecular formula, the van t hoff factor for the following Ionic Compounds as well as guess the solubility of the compounds. If

More information

Thermodynamics of Mixing

Thermodynamics of Mixing Thermodynamics of Mixing Dependence of Gibbs energy on mixture composition is G = n A µ A + n B µ B and at constant T and p, systems tend towards a lower Gibbs energy The simplest example of mixing: What

More information

David A. Katz Department of Chemistry Pima Community College

David A. Katz Department of Chemistry Pima Community College Solutions David A. Katz Department of Chemistry Pima Community College A solution is a HOMOGENEOUS mixture of 2 or more substances in a single phase. One constituent t is usually regarded as the SOLVENT

More information

Phase diagram of water. Note: for H 2 O melting point decreases with increasing pressure, for CO 2 melting point increases with increasing pressure.

Phase diagram of water. Note: for H 2 O melting point decreases with increasing pressure, for CO 2 melting point increases with increasing pressure. Phase diagram of water Note: for H 2 O melting point decreases with increasing pressure, for CO 2 melting point increases with increasing pressure. WATER Covers ~ 70% of the earth s surface Life on earth

More information

Chemistry 51 Chapter 8 TYPES OF SOLUTIONS. A solution is a homogeneous mixture of two substances: a solute and a solvent.

Chemistry 51 Chapter 8 TYPES OF SOLUTIONS. A solution is a homogeneous mixture of two substances: a solute and a solvent. TYPES OF SOLUTIONS A solution is a homogeneous mixture of two substances: a solute and a solvent. Solute: substance being dissolved; present in lesser amount. Solvent: substance doing the dissolving; present

More information

vap H = RT 1T 2 = 30.850 kj mol 1 100 kpa = 341 K

vap H = RT 1T 2 = 30.850 kj mol 1 100 kpa = 341 K Thermodynamics: Examples for chapter 6. 1. The boiling point of hexane at 1 atm is 68.7 C. What is the boiling point at 1 bar? The vapor pressure of hexane at 49.6 C is 53.32 kpa. Assume that the vapor

More information

ESSAY. Write your answer in the space provided or on a separate sheet of paper.

ESSAY. Write your answer in the space provided or on a separate sheet of paper. Test 1 General Chemistry CH116 Summer, 2012 University of Massachusetts, Boston Name ESSAY. Write your answer in the space provided or on a separate sheet of paper. 1) Sodium hydride reacts with excess

More information

To calculate the value of the boiling point constant for water. To use colligative properties to determine the molecular weight of a substance.

To calculate the value of the boiling point constant for water. To use colligative properties to determine the molecular weight of a substance. Colligative Properties of Solutions: A Study of Boiling Point Elevation Amina El-Ashmawy, Collin County Community College (With contributions by Timm Pschigoda, St. Joseph High School, St. Joseph, MI)

More information

Element of same atomic number, but different atomic mass o Example: Hydrogen

Element of same atomic number, but different atomic mass o Example: Hydrogen Atomic mass: p + = protons; e - = electrons; n 0 = neutrons p + + n 0 = atomic mass o For carbon-12, 6p + + 6n 0 = atomic mass of 12.0 o For chlorine-35, 17p + + 18n 0 = atomic mass of 35.0 atomic mass

More information

Four common concentration units 1. Molarity 2. Weight Percent (Wt %), ppm, ppb 3. Molality 4. Mole Fraction. Molarity, M =

Four common concentration units 1. Molarity 2. Weight Percent (Wt %), ppm, ppb 3. Molality 4. Mole Fraction. Molarity, M = Four common concentration units 1. Molarity 2. Weight Percent (Wt %), ppm, ppb 3. Molality 4. Mole Fraction Molarity, M tells you how many s of solute are present in every liter of solution (solute-to-solution)

More information

Freezing Point Depression: Why Don t Oceans Freeze? Teacher Advanced Version

Freezing Point Depression: Why Don t Oceans Freeze? Teacher Advanced Version Freezing Point Depression: Why Don t Oceans Freeze? Teacher Advanced Version Freezing point depression describes the process where the temperature at which a liquid freezes is lowered by adding another

More information

Solutions. A Chem1 Reference Text Stephen K. Lower Simon Fraser University. 1 Solutions 2

Solutions. A Chem1 Reference Text Stephen K. Lower Simon Fraser University. 1 Solutions 2 Solutions A Chem1 Reference Text Stephen K. Lower Simon Fraser University Contents 1 Solutions 2 2 Types of solutions 2 2.1 Gaseous solutions.................................... 4 2.2 Solutions of gases

More information

MOLECULAR WEIGHT BY BOILING POINT ELEVATION

MOLECULAR WEIGHT BY BOILING POINT ELEVATION MOLECULAR WEIGHT BY BOILING POINT ELEVATION BACKGROUND This experiment demonstrates the use of colligative properties. The goal is to measure the molecular weight of a non-volatile solute by determining

More information

n molarity = M = N.B.: n = litres (solution)

n molarity = M = N.B.: n = litres (solution) 1. CONCENTRATION UNITS A solution is a homogeneous mixture of two or more chemical substances. If we have a solution made from a solid and a liquid, we say that the solid is dissolved in the liquid and

More information

Chapter 13 & 14 Practice Exam

Chapter 13 & 14 Practice Exam Name: Class: Date: Chapter 13 & 14 Practice Exam Multiple Choice Identify the choice that best completes the statement or answers the question. 1. Acids generally release H 2 gas when they react with a.

More information

Chemistry B11 Chapter 6 Solutions and Colloids

Chemistry B11 Chapter 6 Solutions and Colloids Chemistry B11 Chapter 6 Solutions and Colloids Solutions: solutions have some properties: 1. The distribution of particles in a solution is uniform. Every part of the solution has exactly the same composition

More information

Chapter 4. Chemical Composition. Chapter 4 Topics H 2 S. 4.1 Mole Quantities. The Mole Scale. Molar Mass The Mass of 1 Mole

Chapter 4. Chemical Composition. Chapter 4 Topics H 2 S. 4.1 Mole Quantities. The Mole Scale. Molar Mass The Mass of 1 Mole Chapter 4 Chemical Composition Chapter 4 Topics 1. Mole Quantities 2. Moles, Masses, and Particles 3. Determining Empirical Formulas 4. Chemical Composition of Solutions Copyright The McGraw-Hill Companies,

More information

Soil Chemistry Ch. 2. Chemical Principles As Applied to Soils

Soil Chemistry Ch. 2. Chemical Principles As Applied to Soils Chemical Principles As Applied to Soils I. Chemical units a. Moles and Avogadro s number The numbers of atoms, ions or molecules are important in chemical reactions because the number, rather than mass

More information

Determination of Molar Mass by Freezing-Point Depression

Determination of Molar Mass by Freezing-Point Depression DETERMINATION OF MOLAR MASS BY FREEZING-POINT DEPRESSION 141 Determination of Molar Mass by Freezing-Point Depression OBJECTIVES: Gain familiarity with colligative properties of nonelectrolyte solutions

More information

Page 2. Base your answers to questions 7 through 9 on this phase diagram

Page 2. Base your answers to questions 7 through 9 on this phase diagram 1. The normal boiling point of water is often depressed at high altitudes. Which of the following explains this phenomenon? t high altitudes, the lower atmospheric pressure equals the equilibrium water

More information

a. Cherry Garcia ice cream: heterogeneous mixture b. mayonnaise: colloid c, d, e. seltzer water, nail polish remover, and brass: solutions

a. Cherry Garcia ice cream: heterogeneous mixture b. mayonnaise: colloid c, d, e. seltzer water, nail polish remover, and brass: solutions Chapter 8 1 Chapter 8 Solutions Solutions to In-Chapter Problems 8.1 A heterogeneous miture does not have a uniform composition throughout a sample. A solution is a homogeneous miture that contains small

More information

Ch 8.5 Solution Concentration Units % (m/m or w/w) = mass of solute x 100 total mass of solution mass of solution = mass solute + mass solvent

Ch 8.5 Solution Concentration Units % (m/m or w/w) = mass of solute x 100 total mass of solution mass of solution = mass solute + mass solvent 1 Ch 8.5 Solution Concentration Units % (m/m or w/w) = mass of solute x 100 total mass of solution mass of solution = mass solute + mass solvent % (v/v) = volume of solute x 100 volume of solution filled

More information

Calculation of Molar Masses. Molar Mass. Solutions. Solutions

Calculation of Molar Masses. Molar Mass. Solutions. Solutions Molar Mass Molar mass = Mass in grams of one mole of any element, numerically equal to its atomic weight Molar mass of molecules can be determined from the chemical formula and molar masses of elements

More information

Unit 2: Quantities in Chemistry

Unit 2: Quantities in Chemistry Mass, Moles, & Molar Mass Relative quantities of isotopes in a natural occurring element (%) E.g. Carbon has 2 isotopes C-12 and C-13. Of Carbon s two isotopes, there is 98.9% C-12 and 11.1% C-13. Find

More information

Everest. Leaders in Vacuum Booster Technology

Everest. Leaders in Vacuum Booster Technology This article has been compiled to understand the process of Solvent Recovery process generally carried out at low temperatures and vacuum. In many chemical processes solute is to be concentrated to high

More information

Chapter 13 - Solutions

Chapter 13 - Solutions Chapter 13 - Solutions 13-1 Types of Mixtures I. Solutions A. Soluble 1. Capable of being dissolved B. Solution 1. A homogeneous mixture of two or more substances in a single phase C. Solvent 1. The dissolving

More information

Chapter 7 : Simple Mixtures

Chapter 7 : Simple Mixtures Chapter 7 : Simple Mixtures Using the concept of chemical potential to describe the physical properties of a mixture. Outline 1)Partial Molar Quantities 2)Thermodynamics of Mixing 3)Chemical Potentials

More information

Review - After School Matter Name: Review - After School Matter Tuesday, April 29, 2008

Review - After School Matter Name: Review - After School Matter Tuesday, April 29, 2008 Name: Review - After School Matter Tuesday, April 29, 2008 1. Figure 1 The graph represents the relationship between temperature and time as heat was added uniformly to a substance starting at a solid

More information

EXPERIMENT # 3 ELECTROLYTES AND NON-ELECTROLYTES

EXPERIMENT # 3 ELECTROLYTES AND NON-ELECTROLYTES EXPERIMENT # 3 ELECTROLYTES AND NON-ELECTROLYTES Purpose: 1. To investigate the phenomenon of solution conductance. 2. To distinguish between compounds that form conducting solutions and compounds that

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Chapter 10 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) A gas at a pressure of 10.0 Pa exerts a force of N on an area of 5.5 m2. A) 1.8 B) 0.55

More information

CHEM 120 Online Chapter 7

CHEM 120 Online Chapter 7 CHEM 120 Online Chapter 7 Date: 1. Which of the following statements is not a part of kinetic molecular theory? A) Matter is composed of particles that are in constant motion. B) Particle velocity increases

More information

Answers and Solutions to Text Problems

Answers and Solutions to Text Problems 9 Answers and Solutions to Text Problems 9.1 a. δ O δ + δ + H H In a water molecule, the oxygen has a partial negative charge and the hydrogens have partial positive charges. b. δ δ + O H δ + δ + δ H H

More information

Concentration of a solution

Concentration of a solution Revision of calculations Stoichiometric calculations Osmotic pressure and osmolarity MUDr. Jan Pláteník, PhD Concentration of a solution mass concentration: grams of substance per litre of solution molar

More information

States of Matter CHAPTER 10 REVIEW SECTION 1. Name Date Class. Answer the following questions in the space provided.

States of Matter CHAPTER 10 REVIEW SECTION 1. Name Date Class. Answer the following questions in the space provided. CHAPTER 10 REVIEW States of Matter SECTION 1 SHORT ANSWER Answer the following questions in the space provided. 1. Identify whether the descriptions below describe an ideal gas or a real gas. ideal gas

More information

Solution a homogeneous mixture = A solvent + solute(s) Aqueous solution water is the solvent

Solution a homogeneous mixture = A solvent + solute(s) Aqueous solution water is the solvent Solution a homogeneous mixture = A solvent + solute(s) Aqueous solution water is the solvent Water a polar solvent: dissolves most ionic compounds as well as many molecular compounds Aqueous solution:

More information

AS1 MOLES. oxygen molecules have the formula O 2 the relative mass will be 2 x 16 = 32 so the molar mass will be 32g mol -1

AS1 MOLES. oxygen molecules have the formula O 2 the relative mass will be 2 x 16 = 32 so the molar mass will be 32g mol -1 Moles 1 MOLES The mole the standard unit of amount of a substance the number of particles in a mole is known as Avogadro s constant (L) Avogadro s constant has a value of 6.023 x 10 23 mol -1. Example

More information

F321 MOLES. Example If 1 atom has a mass of 1.241 x 10-23 g 1 mole of atoms will have a mass of 1.241 x 10-23 g x 6.02 x 10 23 = 7.

F321 MOLES. Example If 1 atom has a mass of 1.241 x 10-23 g 1 mole of atoms will have a mass of 1.241 x 10-23 g x 6.02 x 10 23 = 7. Moles 1 MOLES The mole the standard unit of amount of a substance (mol) the number of particles in a mole is known as Avogadro s constant (N A ) Avogadro s constant has a value of 6.02 x 10 23 mol -1.

More information

#61 Notes Unit 8: Solids/Liquids Ch. Solids/Liquids ** Type of Solid Type of Bonding Properties Examples (compound) (Interparticle Force)

#61 Notes Unit 8: Solids/Liquids Ch. Solids/Liquids ** Type of Solid Type of Bonding Properties Examples (compound) (Interparticle Force) #61 Notes Unit 8: Solids/Liquids Ch. Solids/Liquids ** Type of Solid Type of Bonding Properties Examples (compound) (Interparticle Force) Ionic Ionic -hard NaCl, CaF 2 -high melting pts. Molecular Covalent:

More information

REVIEW QUESTIONS Chapter 8

REVIEW QUESTIONS Chapter 8 Chemistry 51 ANSWER KEY REVIEW QUESTIONS Chapter 8 1. Identify each of the diagrams below as strong electrolyte, weak electrolyte or non-electrolyte: (a) Non-electrolyte (no ions present) (b) Weak electrolyte

More information

Chemistry B11 Chapter 4 Chemical reactions

Chemistry B11 Chapter 4 Chemical reactions Chemistry B11 Chapter 4 Chemical reactions Chemical reactions are classified into five groups: A + B AB Synthesis reactions (Combination) H + O H O AB A + B Decomposition reactions (Analysis) NaCl Na +Cl

More information

Stoichiometry. 1. The total number of moles represented by 20 grams of calcium carbonate is (1) 1; (2) 2; (3) 0.1; (4) 0.2.

Stoichiometry. 1. The total number of moles represented by 20 grams of calcium carbonate is (1) 1; (2) 2; (3) 0.1; (4) 0.2. Stoichiometry 1 The total number of moles represented by 20 grams of calcium carbonate is (1) 1; (2) 2; (3) 01; (4) 02 2 A 44 gram sample of a hydrate was heated until the water of hydration was driven

More information

Formulas, Equations and Moles

Formulas, Equations and Moles Chapter 3 Formulas, Equations and Moles Interpreting Chemical Equations You can interpret a balanced chemical equation in many ways. On a microscopic level, two molecules of H 2 react with one molecule

More information

Liquid phase. Balance equation Moles A Stoic. coefficient. Aqueous phase

Liquid phase. Balance equation Moles A Stoic. coefficient. Aqueous phase STOICHIOMETRY Objective The purpose of this exercise is to give you some practice on some Stoichiometry calculations. Discussion The molecular mass of a compound is the sum of the atomic masses of all

More information

Exp 13 Volumetric Analysis: Acid-Base titration

Exp 13 Volumetric Analysis: Acid-Base titration Exp 13 Volumetric Analysis: Acid-Base titration Exp. 13 video (time: 47:17 minutes) Titration - is the measurement of the volume of a standard solution required to completely react with a measured volume

More information

10. Calculate the mass percent nitrogen in (NH 4 ) 2 CO 3 (molar mass = 96.09 g/mol). a. 29.1 % c. 17.9 % e. 14.6 % b. 35.9 % d. 0.292 % f. 96.

10. Calculate the mass percent nitrogen in (NH 4 ) 2 CO 3 (molar mass = 96.09 g/mol). a. 29.1 % c. 17.9 % e. 14.6 % b. 35.9 % d. 0.292 % f. 96. Chem 171-2-3: Final Exam Review Multiple Choice Problems 1. What is the molar mass of barium perchlorate, Ba(ClO 4 ) 2? a. 189.90 g/mol c. 272.24 g/mol e. 336.20 g/mol b. 240.24 g/mol d. 304.24 g/mol f.

More information

Problem Solving. Stoichiometry of Gases

Problem Solving. Stoichiometry of Gases Skills Worksheet Problem Solving Stoichiometry of Gases Now that you have worked with relationships among moles, mass, and volumes of gases, you can easily put these to work in stoichiometry calculations.

More information

Name Class Date. In the space provided, write the letter of the term or phrase that best completes each statement or best answers each question.

Name Class Date. In the space provided, write the letter of the term or phrase that best completes each statement or best answers each question. Assessment Chapter Test A Chapter: States of Matter In the space provided, write the letter of the term or phrase that best completes each statement or best answers each question. 1. The kinetic-molecular

More information

stoichiometry = the numerical relationships between chemical amounts in a reaction.

stoichiometry = the numerical relationships between chemical amounts in a reaction. 1 REACTIONS AND YIELD ANSWERS stoichiometry = the numerical relationships between chemical amounts in a reaction. 2C 8 H 18 (l) + 25O 2 16CO 2 (g) + 18H 2 O(g) From the equation, 16 moles of CO 2 (a greenhouse

More information

Name Date Class CHEMICAL QUANTITIES. SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages 287 296)

Name Date Class CHEMICAL QUANTITIES. SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages 287 296) Name Date Class 10 CHEMICAL QUANTITIES SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages 287 296) This section defines the mole and explains how the mole is used to measure matter. It also teaches

More information

AP CHEMISTRY 2009 SCORING GUIDELINES (Form B)

AP CHEMISTRY 2009 SCORING GUIDELINES (Form B) AP CHEMISTRY 2009 SCORING GUIDELINES (Form B) Question 3 (10 points) 2 H 2 O 2 (aq) 2 H 2 O(l) + O 2 (g) The mass of an aqueous solution of H 2 O 2 is 6.951 g. The H 2 O 2 in the solution decomposes completely

More information

The Ideal Solution. ChemActivity T15

The Ideal Solution. ChemActivity T15 ChemActivity T15 The Ideal Solution Focus Question: An equi-molar mixture of benzene and toluene is prepared. What will be the composition of the vapor in equilibrium with this solution? Model 1: Benzene

More information

MOLAR MASS AND MOLECULAR WEIGHT Themolar mass of a molecule is the sum of the atomic weights of all atoms in the molecule. Molar Mass.

MOLAR MASS AND MOLECULAR WEIGHT Themolar mass of a molecule is the sum of the atomic weights of all atoms in the molecule. Molar Mass. Counting Atoms Mg burns in air (O 2 ) to produce white magnesium oxide, MgO. How can we figure out how much oxide is produced from a given mass of Mg? PROBLEM: If If 0.200 g of Mg is is burned, how much

More information

CHEMISTRY. Matter and Change. Section 13.1 Section 13.2 Section 13.3. The Gas Laws The Ideal Gas Law Gas Stoichiometry

CHEMISTRY. Matter and Change. Section 13.1 Section 13.2 Section 13.3. The Gas Laws The Ideal Gas Law Gas Stoichiometry CHEMISTRY Matter and Change 13 Table Of Contents Chapter 13: Gases Section 13.1 Section 13.2 Section 13.3 The Gas Laws The Ideal Gas Law Gas Stoichiometry State the relationships among pressure, temperature,

More information

SAMPLE PROBLEM 8.1. Solutions of Electrolytes and Nonelectrolytes SOLUTION STUDY CHECK

SAMPLE PROBLEM 8.1. Solutions of Electrolytes and Nonelectrolytes SOLUTION STUDY CHECK Solutions of Electrolytes and Nonelectrolytes SAMPLE PROBLEM 8.1 Indicate whether solutions of each of the following contain only ions, only molecules, or mostly molecules and a few ions: a. Na 2 SO 4,

More information

ph: Measurement and Uses

ph: Measurement and Uses ph: Measurement and Uses One of the most important properties of aqueous solutions is the concentration of hydrogen ion. The concentration of H + (or H 3 O + ) affects the solubility of inorganic and organic

More information

5. Which temperature is equal to +20 K? 1) 253ºC 2) 293ºC 3) 253 C 4) 293 C

5. Which temperature is equal to +20 K? 1) 253ºC 2) 293ºC 3) 253 C 4) 293 C 1. The average kinetic energy of water molecules increases when 1) H 2 O(s) changes to H 2 O( ) at 0ºC 3) H 2 O( ) at 10ºC changes to H 2 O( ) at 20ºC 2) H 2 O( ) changes to H 2 O(s) at 0ºC 4) H 2 O( )

More information

Other Stoich Calculations A. mole mass (mass mole) calculations. GIVEN mol A x CE mol B. PT g A CE mol A MOLE MASS :

Other Stoich Calculations A. mole mass (mass mole) calculations. GIVEN mol A x CE mol B. PT g A CE mol A MOLE MASS : Chem. I Notes Ch. 12, part 2 Using Moles NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. 1 MOLE = 6.02 x 10 23 representative particles (representative particles

More information

Boyle s law - For calculating changes in pressure or volume: P 1 V 1 = P 2 V 2. Charles law - For calculating temperature or volume changes: V 1 T 1

Boyle s law - For calculating changes in pressure or volume: P 1 V 1 = P 2 V 2. Charles law - For calculating temperature or volume changes: V 1 T 1 Common Equations Used in Chemistry Equation for density: d= m v Converting F to C: C = ( F - 32) x 5 9 Converting C to F: F = C x 9 5 + 32 Converting C to K: K = ( C + 273.15) n x molar mass of element

More information

The Physical Chemistry, Theory and Technique of Freezing Point Determinations

The Physical Chemistry, Theory and Technique of Freezing Point Determinations The Physical Chemistry, Theory and Technique of Freezing Point Determinations Table of Contents Chapter Physical Chemistry Review. Measuring the concentration of solutions.2 Comparison of concentrative

More information

APPENDIX B: EXERCISES

APPENDIX B: EXERCISES BUILDING CHEMISTRY LABORATORY SESSIONS APPENDIX B: EXERCISES Molecular mass, the mole, and mass percent Relative atomic and molecular mass Relative atomic mass (A r ) is a constant that expresses the ratio

More information

Name Date Class CHEMICAL QUANTITIES. SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages 287 296)

Name Date Class CHEMICAL QUANTITIES. SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages 287 296) 10 CHEMICAL QUANTITIES SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages 287 296) This section defines the mole and explains how the mole is used to measure matter. It also teaches you how to calculate

More information

The Gas Laws. Our Atmosphere. Pressure = Units of Pressure. Barometer. Chapter 10

The Gas Laws. Our Atmosphere. Pressure = Units of Pressure. Barometer. Chapter 10 Our Atmosphere The Gas Laws 99% N 2 and O 2 78% N 2 80 70 Nitrogen Chapter 10 21% O 2 1% CO 2 and the Noble Gases 60 50 40 Oxygen 30 20 10 0 Gas Carbon dioxide and Noble Gases Pressure Pressure = Force

More information

7. 1.00 atm = 760 torr = 760 mm Hg = 101.325 kpa = 14.70 psi. = 0.446 atm. = 0.993 atm. = 107 kpa 760 torr 1 atm 760 mm Hg = 790.

7. 1.00 atm = 760 torr = 760 mm Hg = 101.325 kpa = 14.70 psi. = 0.446 atm. = 0.993 atm. = 107 kpa 760 torr 1 atm 760 mm Hg = 790. CHATER 3. The atmosphere is a homogeneous mixture (a solution) of gases.. Solids and liquids have essentially fixed volumes and are not able to be compressed easily. have volumes that depend on their conditions,

More information

ATOMS. Multiple Choice Questions

ATOMS. Multiple Choice Questions Chapter 3 ATOMS AND MOLECULES Multiple Choice Questions 1. Which of the following correctly represents 360 g of water? (i) 2 moles of H 2 0 (ii) 20 moles of water (iii) 6.022 10 23 molecules of water (iv)

More information

LESSON ASSIGNMENT. After completing this lesson, you should be able to: 8-1. Prepare and calculate acid and base solutions.

LESSON ASSIGNMENT. After completing this lesson, you should be able to: 8-1. Prepare and calculate acid and base solutions. LESSON ASSIGNMENT LESSON 8 Concentrated Acids and Bases. TEXT ASSIGNMENT Paragraphs 8-1 through 8-6. LESSON OBJECTIVE After completing this lesson, you should be able to: 8-1. Prepare and calculate acid

More information

Aqueous Solutions. Water is the dissolving medium, or solvent. Some Properties of Water. A Solute. Types of Chemical Reactions.

Aqueous Solutions. Water is the dissolving medium, or solvent. Some Properties of Water. A Solute. Types of Chemical Reactions. Aqueous Solutions and Solution Stoichiometry Water is the dissolving medium, or solvent. Some Properties of Water Water is bent or V-shaped. The O-H bonds are covalent. Water is a polar molecule. Hydration

More information

Essential Maths for Medics and Vets Reference Materials Module 2. Amount and Concentration.

Essential Maths for Medics and Vets Reference Materials Module 2. Amount and Concentration. 2 Amount and concentration: making and diluting solutions 2 Amount and concentration; making and diluting solutions... 2A Rationale... 2B Distinguishing between amount and concentration, g and %w/v...

More information

4.5 Physical Properties: Solubility

4.5 Physical Properties: Solubility 4.5 Physical Properties: Solubility When a solid, liquid or gaseous solute is placed in a solvent and it seems to disappear, mix or become part of the solvent, we say that it dissolved. The solute is said

More information

Exam 4 Practice Problems false false

Exam 4 Practice Problems false false Exam 4 Practice Problems 1 1. Which of the following statements is false? a. Condensed states have much higher densities than gases. b. Molecules are very far apart in gases and closer together in liquids

More information

Experiment 1: Colligative Properties

Experiment 1: Colligative Properties Experiment 1: Colligative Properties Determination of the Molar Mass of a Compound by Freezing Point Depression. Objective: The objective of this experiment is to determine the molar mass of an unknown

More information

HOW TO MAKE STANDARD SOLUTIONS FOR CHEMISTRY

HOW TO MAKE STANDARD SOLUTIONS FOR CHEMISTRY HOW TO MAKE STANDARD SOLUTIONS FOR CHEMISTRY Phillip Bigelow Chemists make two common types of "standard solutions": Molar solutions Normal solutions Both of these solutions are concentrations (or strengths

More information

Temperature. Number of moles. Constant Terms. Pressure. Answers Additional Questions 12.1

Temperature. Number of moles. Constant Terms. Pressure. Answers Additional Questions 12.1 Answers Additional Questions 12.1 1. A gas collected over water has a total pressure equal to the pressure of the dry gas plus the pressure of the water vapor. If the partial pressure of water at 25.0

More information

Chemical Equations & Stoichiometry

Chemical Equations & Stoichiometry Chemical Equations & Stoichiometry Chapter Goals Balance equations for simple chemical reactions. Perform stoichiometry calculations using balanced chemical equations. Understand the meaning of the term

More information

The Mole. 6.022 x 10 23

The Mole. 6.022 x 10 23 The Mole 6.022 x 10 23 Background: atomic masses Look at the atomic masses on the periodic table. What do these represent? E.g. the atomic mass of Carbon is 12.01 (atomic # is 6) We know there are 6 protons

More information

Name: Class: Date: 2 4 (aq)

Name: Class: Date: 2 4 (aq) Name: Class: Date: Unit 4 Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1) The balanced molecular equation for complete neutralization of

More information

Atomic mass is the mass of an atom in atomic mass units (amu)

Atomic mass is the mass of an atom in atomic mass units (amu) Micro World atoms & molecules Laboratory scale measurements Atomic mass is the mass of an atom in atomic mass units (amu) By definition: 1 atom 12 C weighs 12 amu On this scale 1 H = 1.008 amu 16 O = 16.00

More information

IB Chemistry. DP Chemistry Review

IB Chemistry. DP Chemistry Review DP Chemistry Review Topic 1: Quantitative chemistry 1.1 The mole concept and Avogadro s constant Assessment statement Apply the mole concept to substances. Determine the number of particles and the amount

More information

Chemical Reactions in Water Ron Robertson

Chemical Reactions in Water Ron Robertson Chemical Reactions in Water Ron Robertson r2 f:\files\courses\1110-20\2010 possible slides for web\waterchemtrans.doc Properties of Compounds in Water Electrolytes and nonelectrolytes Water soluble compounds

More information

@ Oxford Fajar Sdn. Bhd. (008974-T) 2012. Matter. 1.1 Atoms and Molecules 1.2 Mole Concept 1.3 Stoichiometry

@ Oxford Fajar Sdn. Bhd. (008974-T) 2012. Matter. 1.1 Atoms and Molecules 1.2 Mole Concept 1.3 Stoichiometry 1 Matter 1.1 Atoms and Molecules 1.2 Mole Concept 1.3 Stoichiometry 2 Chemistry for Matriculation Semester 1 1.1 Atoms and Molecules LEARNING OUTCOMES Describe proton, electron and neutron in terms of

More information

CHEM 2423 Extraction of Benzoic Acid EXPERIMENT 6 - Extraction Determination of Distribution Coefficient

CHEM 2423 Extraction of Benzoic Acid EXPERIMENT 6 - Extraction Determination of Distribution Coefficient EXPERIMENT 6 - Extraction Determination of Distribution Coefficient Purpose: a) To purify samples of organic compounds that are solids at room temperature b) To dissociate the impure sample in the minimum

More information

CHEM 105 HOUR EXAM III 28-OCT-99. = -163 kj/mole determine H f 0 for Ni(CO) 4 (g) = -260 kj/mole determine H f 0 for Cr(CO) 6 (g)

CHEM 105 HOUR EXAM III 28-OCT-99. = -163 kj/mole determine H f 0 for Ni(CO) 4 (g) = -260 kj/mole determine H f 0 for Cr(CO) 6 (g) CHEM 15 HOUR EXAM III 28-OCT-99 NAME (please print) 1. a. given: Ni (s) + 4 CO (g) = Ni(CO) 4 (g) H Rxn = -163 k/mole determine H f for Ni(CO) 4 (g) b. given: Cr (s) + 6 CO (g) = Cr(CO) 6 (g) H Rxn = -26

More information

Chapter 3: Stoichiometry

Chapter 3: Stoichiometry Chapter 3: Stoichiometry Key Skills: Balance chemical equations Predict the products of simple combination, decomposition, and combustion reactions. Calculate formula weights Convert grams to moles and

More information

CHAPTER 12. Gases and the Kinetic-Molecular Theory

CHAPTER 12. Gases and the Kinetic-Molecular Theory CHAPTER 12 Gases and the Kinetic-Molecular Theory 1 Gases vs. Liquids & Solids Gases Weak interactions between molecules Molecules move rapidly Fast diffusion rates Low densities Easy to compress Liquids

More information