10 Cl atoms. 10 H2O molecules. 8.3 mol HCN = 8.3 mol N atoms 1 mol HCN. 2 mol H atoms 2.63 mol CH2O = 5.26 mol H atoms 1 mol CH O


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1 Chem 100 Mole conversions and stoichiometry worksheet 1. How many Ag atoms are in.4 mol Ag atoms? Ag atoms 4.4 mol Ag atoms = Ag atoms 1 mol Ag atoms. How many Br molecules are in 18. mol Br molecules? Br molecules 5 = 1 mol Br molecules 18. mol Br molecules Br molecules Al atoms is equal to how many mol Al atoms? 8 1 mol Al atoms Al atoms = mol Al atoms Al atoms H O molecules is equal to how many mol H O molecules? 1 mol H O molecules.9 10 H O molecules = mol H O molecules HO molecules 5. How many mol N atoms are in 8. mol HCN? 1 mol N atoms 8. mol HCN = 8. mol N atoms 1 mol HCN 6. How many mol H atoms are in.6 mol CH O? mol H atoms.6 mol CHO = 5.6 mol H atoms 1 mol CH O 7. How many Cl atoms are in.6 mol CH Cl? mol Cl atoms Cl atoms 4.6 mol CHCl = Cl atoms 1 mol CHCl 1 mol Cl atoms
2 8. How many O atoms are in 6.9 mol Ca(NO )? 6 mol O atoms O atoms mol Ca(NO ) = O atoms 1 mol Ca(NO ) 1 mol O atoms 9. How many mol FeCl are in 15. g FeCl? Molar mass FeCl = (5.45) = 16. g/mol 1 mol FeCl 15. g FeCl = mol FeCl 16. g FeCl 10. How many mol Na CO are in.5 g Na CO? Molar mass Na CO = (.99) (16.00) = g/mol 1 mol Na CO.5 g Na CO = 0. g Na CO g Na CO 11. What mass is.5 mol NaNO? Molar mass NaNO = (16.00) = g/mol g NaNO.5 mol NaNO = 99 g NaNO 1. What mass is 7.6 mol C H 4? 1 mol NaNO Molar mass C H = (1.01) + 4(1.008) = 8.05 g/mol g C H 7.6 mol C H = 05.5 g C H mol CH4 1. How many mol H atoms are in 18. g NH? Molar mass NH = (1.008) = g/mol 1 mol NH mol H atoms 18. g NH =.1 mol H atoms g NH 1 mol NH 14. How many mol O atoms are in.5 g MnO? Molar mass MnO = (16.00) = g/mol 1 mol MnO mol O atoms.5 g MnO = mol O atoms g MnO 1 mol MnO
3 15. How many S atoms are in.5 g Al S? Molar mass Al S = (6.98) + (.06) = g/mol 1 mol AlS mol S atoms S atoms.5 g AlS =.8 10 S atoms g AlS 1 mol AlS 1 mol S atoms 16. How many F atoms are in 5.5 g C H F 4? Molar mass C H F = (1.01) + (1.008) + 4(19.00) = g/mol 4 1 mol CHF4 4 mol F atoms F atoms 5.5 g CHF4 = F atoms g CHF4 1 mol CHF4 1 mol F atoms 17. What mass of O is in 7.56 g H O? Molar mass H O = (1.008) + (16.00) = g/mol Molar mass O = g/mol 1 mol H O mol O g O 7.56 g HO = 7.11 g O g HO 1 mol HO 1 mol O 18. What mass of Cl is in 8. g PCl? Molar mass PCl = (5.45) = 17. g/mol Molar mass Cl = 5.45 g/mol 1 mol PCl mol Cl 5.45 g Cl 8. g PCl = 9.6 g Cl 17. g PCl 1 mol PCl 1 mol Cl For the following 6 questions, consider the following balanced chemical equation: N + H NH Molar mass N = (14.01) = 8.0 g/mol Molar mass H = (1.008) =.016 g/mol Molar mass NH = (1.008) = g/mol 19. How many mol NH can be produced from 7. mol N (assuming H is in excess)? mol NH 7. mol N = 14.5 mol NH 1 mol N
4 0. How many mol H must react with.6 mol N? mol H.6 mol N = 9.78 mol H 1 mol N 1. How many grams of N must react if 5.0 g NH are formed? 1 mol NH 1 mol N 8.0 g N 5.0 g NH = 0.5 g N g NH mol NH 1 mol N. How many grams H will react with 15. g N? 1 mol N mol H.016 g H 15. g N =.0 g H 8.0 g N 1 mol N 1 mol H. If.6 g N and 1.5 g H react together, what mass NH can be produced? Which is the limiting reactant? 1 mol N mol NH g NH.6 g N 8.0 g N 1 mol N 1 mol NH =.87 g NH 1 mol H mol NH g NH 1.5 g H = 8.56 g NH.016 g H mol H 1 mol NH There is enough N to make.87 g NH, and there is enough H to make 8.56 g NH. N is the limiting reactant since it produces the smaller product mass..87 g NH can be produced (this is the theoretical yield). 4. If 5. g N and 15.8 g H react together, what mass NH can be produced? Which is the limiting reactant? 1 mol N mol NH g NH 5. g N 8.0 g N 1 mol N 1 mol NH = 6.47 g NH 1 mol H mol NH g NH 15.8 g H = 89.0 g NH.016 g H mol H 1 mol NH There is enough N to make 6.47 g NH and there is enough H to make 89.0 g NH. N is the limiting reactant because it makes the smaller product mass g NH can be produced (this is the theoretical yield).
5 For the following 6 questions, consider the following balanced chemical equation: C H + 5O 4CO + H O Molar mass C H = (1.01) + (1.008) = 6.06 g/mol Molar mass O = (16.00) =.00 g/mol Molar mass CO = (16.00) = g/mol Molar mass H O = (1.008) = g/mol 5. How many mol of CO can be formed if 8.6 mol C H react (assuming excess O )? 4 mol CO 8.6 mol C H = 16.5 mol CO mol CH 6. How many mol C H will react with 0. mol O? mol C H 0. mol O = 8.1 mol C H 5 5 mol O 7. How many g of H O can be formed if 6. g C H react (assuming excess O )? 1 mol C H mol H O g H O 6. g C H = 5.0 g H O 6.06 g CH mol CH 1 mol HO 8. How many g O will react with 1. g C H? 1 mol C H 5 mol O.00 g O 1. g C H = 7.5 g O 6.06 g CH mol CH 1 mol O 9. If.l g C H and.6 g O react, how many grams CO can be formed? Which is the limiting reactant? 1 mol C H 4 mol CO g CO.1 g C H = 7.0 g CO 6.06 g CH mol CH 1 mol CO 1 mol O 4 mol CO g CO.6g O.00 g O 5 mol O 1 mol CO =.99 g CO There is enough C H to make 7.0 g CO and there is enough O to make.99 g CO. O is the limiting reactant since it produces the smaller product mass..99 g CO can be produced (this is the theoretical yield).
6 0. If 6.6 g C H and.5 g O react, how many grams H O can be formed? Which is the limiting reactant? 1 mol C H mol H O g H O 6.6 g C H 6.06 g C H mol C H 1 mol H O = 1 mol O mol H O g H O.5 g O = 5.0 g H O.00 g O 5 mol O 1 mol HO 4. g HO There is enough C H 5 to make 4. g H O and there is enough O to make 5.0 g H O. C H is the limiting reactant because it produces the smaller product mass. 4. g H O can be produced (this is the theoretical yield).
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