Hylleraas-configuration-interaction nonrelativistic energies for the 1 S ground states of the beryllium isoelectronic sequence. Supplemental Material

Size: px
Start display at page:

Download "Hylleraas-configuration-interaction nonrelativistic energies for the 1 S ground states of the beryllium isoelectronic sequence. Supplemental Material"

Transcription

1 Hylleraas-configuration-interaction nonrelativistic energies for the 1 S ground states of the beryllium isoelectronic sequence. Supplemental Material James S. Sims National Institute of Standards and Technology Gaithersburg, Maryland , USA Stanley A. Hagstrom Departments of Chemistry and Computer Science Indiana University Bloomington, Indiana 47405, USA 1

2 In a previous work Sims and Hagstrom [Phys. Rev. A 83, (2011)] reported Hylleraasconfiguration-interaction (Hy-CI) method variational calculations for the 1 S ground state of neutral beryllium with an estimated accuracy of a tenth of a microhartree. The previous calculations have been extended in our current work to higher accuracy and, by simple scaling of the orbital exponents, to the entire Be 2 1 S isoelectronic sequence. Various tables are presented here which supplement this current work. The Hy-CI wave function for four electon states is Ψ = N C K Φ K, (1) K=1 where the Φ K are configuration state functions (CSFs) which can be written as Φ K = Λ(F K (r 1,r 2,r 3,r 4 )Θ K ) (2) in terms of spatial and spin functions F K (r 1,r 2,r 3,r 4 ) and Θ K (Λ is a projection operator which projects out the state of 1 S symmetry). Since only one spin function Θ K = Θ 1 = αβαβ is used in this work, the CSFs are uniquely specified by the spatial part of the wave function F K (r 1,r 2,r 3,r 4 ) given by a particular choice of r ij factor and Hartree orbital product F K (r 1,r 2,r 3,r 4 ) = r ν K ij 4 {φ Ks (r s )}, (3) where φ Ks (r s ) represents the sth basis orbital in the K th term and ν K is either 0 or 1. The basis orbitals are unnormalized Slater-type orbitals (STOs) φ(r) which are defined as s=1 φ i (r) = r n i 1 e α ir Y m i l i (θ,φ), (4) where Y m l (θ, φ) is a normalized spherical harmonic in the Condon and Shortley phase convention [1]. The STOs we use are fully defined in [2]. An s-type STO has l = 0, a p STO has l = 1, a d STO has l = 2, etc. Table I lists the configuration state function (CSF) basis used in the initial calculations in this work. In Table I and elsewhere, E for each CSF block is the amount that that block lowers the nonrelativistic energy when added to the expansion. The K shell exponents used here in Table I and elsewhere, with one exception, for the Be ground state are K = 2.789, K1 = 10.0, K2 = 15.0, Kp = 5.162, Kd = 5.40, Kf = 6.43, Kg = 5.0 and the L shell orbital exponents are L= , and Lp = 1.596, Ld = 2.35, Lf = 2.5, Lg = The one exception is for the 83,598 Be ground state, where the orbital exponents used were K = 3.75, K1 = 10.0, K2 = 15.0, Kp = 5.55, Kd = 5.74, Kf = 6.468, Kg = 5.0 and the L shell orbital exponents are L= , and Lp = 1.69, Ld = 2.41, Lf = 2.5, Lg = For the rest of the sequence orbital exponents were 2

3 obtained by Z/4 scaling, except for the separately optimized C++ calculation, where the orbital exponents used were K = 4.40, K1 = 10.0, K2 = 15.0, Kp = 5.62, Kd = 5.74, Kf = 6.468, Kg = 5.0 and the L shell orbital exponents are L= , and Lp = 1.69, Ld = 2.41, Lf = 2.5, Lg = In column one are listed the CSF block specifications used to generate the CSF terms for the various block types, in the order electron 1 (α spin), electron 2 (β spin), electron 3 (α spin), electron 4 (β spin). For example, in the first line 1:8s K means the basis orbitals are 1s K through 8s K orbitals (K denoting an orbital exponent appropriate for a K shell electron). All of the listed basis orbitals are used to generate all of the CSFs that are unique for this basis set selection except that N max, the sum of the powers of r in the hartree product (HP), must be less than or equal to 16. The choice of terms is highly regular, there having been no attempt to cut down on the number of terms. The number of unique terms (CSFs) in a block can be computed from the listed basis orbitals and the condition that N max <= 16. For example, consider 1:5s K1 1:5s K1 2:6s L 2:6s L R 1 in the last row of Table I. There are 5 * 6 / 2 = 15 unique pairs of orbitals for electrons 1 and 2, and 6 * 7 / 2 = 21 unique pairs of orbitals for electrons 3 and 4. Since the K shell orbital exponent is different from the L shell orbital, there are (15 * 21) = 315 different CSF terms for this block. The 315 terms in this block are combined with R 1 = {1,r 12,r 34 }, which means combine with 1, r 12,and r 34, respectively, to form (315 * 3) = 945 CSF terms. Applying the condition that r-sum, the sum of the powers of r for the four orbitals in a term, has to be 16, the number of terms for this CSF block is reduced to 666 (see Reference [3] for further details). 3

4 Table I: 38,253 term s, p, d, f Hy-CI expansion for the Be ground state energy in hartrees (see text for the orbital exponents used). In the table, R 1 = {1,r 12,r 34 }, R 2 = {r 13,r 14 }, R = {1,r 12,r 34,r 13,r 14 }, N is the number of terms added and N tot is the cumulative number of terms. All terms are r-sum filtered using N max = 16 (see text). For p 4, the p 0 p 0 p 0 p 0 and p 1 p 1 p 1 p 1 terms were used for each CSF. Terms added N N tot E(N tot ) in hartrees E in µh 1:8s K 1:8s K 1:8s L 1:8s L R :8p Kp 2:8p Kp 1:8s L 1:8s L R :8s K 1:8s K 2:8p Lp 2:8p Lp R :7p Kp 2:7p Kp 2:7p Lp 2:7p Lp R :6p Kp 2:6p Kp 2:6p Lp 2:6p Lp R :6s K 2:6p Kp 1:6s L 2:6p Lp R :5s K 2:5p Kp 1:5s L 2:5p Lp R :6s K 2:6p Kp 2:6p Lp 1:6s L R :5s K 2:5p Kp 2:5p Lp 1:5s L R :6s K 1:6s K 3:7d Ld 3:7d Ld R :7d Kd 3:7d Kd 1:6s L 1:6s L R :6s K 2:6p Kp 2:6p Lp 3:6d Ld R :6p Kp 2:6p Kp 1:6s L 3:6d Ld R :6s K 3:6d Kd 2:6p Lp 2:6p Lp R :6p Kp 1:6s K 2:6p Lp 3:6d Ld R :6d Kd 2:5p Kp 1:4s L 2:5p Lp R :5p Kp 3:6d Kd 1:4s L 2:5p Lp R :6s K 1:6s K 4:7f Lf 4:7f Lf :6s K 1:6s K 4:7f Lf 4:7f Lf r :7f Kf 4:7f Kf 1:6s L 1:6s L R :7d 0Kd 3:7d 0Kd 2:6p 0Lp 2:6p 0Lp R :7d 1Kd 3:7d 1Kd 2:6p 1Lp 2:6p 1Lp R :7d 1Kd 3:7d 1Kd 2:6p 1Lp 2:6p 1Lp :6p 0Kp 2:6p 0Kp 3:7d 0Ld 3:7d 0Ld :6p 0Kp 2:6p 0Kp 3:7d 0Ld 3:7d 0Ld r :6p 1Kp 2:6p 1Kp 3:7d 1Ld 3:7d 1Ld :6p 1Kp 2:6p 1Kp 3:7d 1Ld 3:7d 1Ld r :6p 1Kp 2:6p 1Kp 4:7f 1Lf 4:7f 1Lf :6p 1Kp 2:6p 1Kp 4:7f 1Lf 4:7f 1Lf r :5s K1 1:5s K1 2:6s L 2:6s L R

5 The (Be) wave function 52,405 term expansion was obtained by expanding the atomic orbitals (AOs) used in the 38,253 term calculations to both include higher powers, e.g., 9p K and 9p L, and a different orbital exponent in the case of the p K2 AOs. Table II: 52,405 s, p, d, f Hy-CI expansion for the Be ground state energy in hartrees (see text for the orbital exoonents used). In the table, R 1 = {1,r 12,r 34 }, R 2 = {r 13,r 14 }, R = {1,r 12,r 34,r 13,r 14 }, N is the number of terms added and N tot is the cumulative number of terms. The terms are r-sum filtered using N max = 16 (see text) unless an explicit r-sum N max value is given. For p 4, the p 0 p 0 p 0 p 0 and p 1 p 1 p 1 p 1 terms were used for each CSF. Terms added N N tot E(N tot ) in hartrees E in µh 1:8s K 1:8s K 1:8s L 1:8s L R :9p Kp 2:9p Kp 1:8s L 1:8s L R :8p Kp 2:8p Kp 1:8s L 1:8s L R :8s K 1:8s K 2:9p Lp 2:9p Lp R :8s K 1:8s K 2:8p Lp 2:8p Lp R :7p Kp 2:7p Kp 2:7p Lp 2:7p Lp R :6p Kp 2:6p Kp 2:6p Lp 2:6p Lp R :6s K 2:6p Kp 1:6s L 2:6p Lp R :5s K 2:5p Kp 1:5s L 2:5p Lp R :6s K 2:6p Kp 2:6p Lp 1:6s L R :5s K 2:5p Kp 2:5p Lp 1:5s L R :7s K 1:7s K 3:8d Ld 3:8d Ld R :8d Kd 3:8d Kd 1:7s L 1:7s L R :6s K 3:6d Kd 1:6s L 3:6d Ld R (r-sum 14) :6s K 3:6d Kd 3:6d Ld 1:6s L R (r-sum 14) :6s K 2:6p Kp 2:6p Lp 3:6d Ld R :6p Kp 2:6p Kp 1:6s L 3:6d Ld R :6s K 3:6d Kd 2:6p Lp 2:6p Lp R :6p Kp 1:6s K 2:6p Lp 3:6d Ld R :5d Kd 2:6p Kp 1:5s L 2:6p Lp R :6p Kp 3:7d Kd 1:5s L 2:5p Lp R :6s K 1:6s K 4:7f Lf 4:7f Lf :6s K 1:6s K 4:7f Lf 4:7f Lf r :6s K 1:6s K 4:7f Lf 4:7f Lf R

6 Terms added N N tot E(N tot ) in hartrees E in µh 4:8f Kf 4:8f Kf 1:7s L 1:7s L R :6s K 4:7f Kf 1:5s L 4:7f Lf :6s K 4:7f Kf 1:5s L 4:7f Lf r :6s K 4:7f Kf 1:5s L 4:7f Lf r :6s K 4:7f Kf 4:7f Lf 1:5s L :6s K 4:7f Kf 4:7f Lf 1:5s L r :8d 0Kd 3:8d 0Kd 2:7p 0Lp 2:7p 0Lp R :8d 1Kd 3:8d 1Kd 2:7p 1Lp 2:7p 1Lp R :8d 1Kd 3:8d 1Kd 2:7p 1Lp 2:7p 1Lp r :7p 0Kp 2:7p 0Kp 3:7d 0Ld 3:7d 0Ld R :7p 1Kp 2:7p 1Kp 3:7d 1Ld 3:7d 1Ld R :7p 1Kp 2:7p 1Kp 3:7d 1Ld 3:7d 1Ld r :5p 1Kp 2:7d 1Kd 2:6p 1Lp 3:7d 1Ld (r-sum 12) :5p 1Kp 2:7d 1Kd 2:6p 1Lp 3:7d 1Ld r 12 (r-sum 12) :5p 1Kp 2:7d 1Kd 2:6p 1Lp 3:7d 1Ld r 14 (r-sum12) :5p 1Kp 2:7d 1Kd 3:7d 1Ld 2:6p 1Lp r 14 (r-sum 12) :8f 0Kf 4:8f 0Kf 2:7p 0Lp 2:7p 0Lp r :8f 1Kf 4:8f 1Kf 2:7p 1Lp 2:7p 1Lp :8f 1Kf 4:8f 1Kf 2:7p 1Lp 2:7p 1Lp r :7p 0Kp 2:7p 0Kp 4:7f 0Lf 4:7f 0Lf r :7p 1Kp 2:7p 1Kp 4:7f 1Lf 4:7f 1Lf r :6s K1 1:6s K1 2:6s L 2:6s L R :5s K 3:6d Kd 3:6d Ld 3:6d Ld :5s K 2:6p Kp 3:6d Ld 4:7f Lf :5s K 2:6p Kp 3:6d Ld 4:7f Lf r :6d Kd 4:7f Kf 2:6s L 2:6p Lp r :6s K 2:6p Kp 4:7f Lf 3:6d Ld :6p K2 2:6p K2 1:6s L 1:6s L r The 79,137 and 80,073 term expansions are given next in Table III, then 38,253, 52,405, 79,137, and 80,073 term nonrelativistic energies are compared in Table IV. 6

7 Table III: Hy-CI calculation of the Be ground state energy in hartrees (see text for the orbital exponents used) 79,137 s,p,d,f expansion; 80,073 term s,p,d,f,g expansion. In the table, R 1 = {1,r 12,r 34 }, R 2 = {r 13,r 14 }, R = {1,r 12,r 34,r 13,r 14 }, N is the number of terms added and N tot is the cumulative number of terms. The terms are r-sum filtered using N max = 16 (see text) unless an explicit r-sum N max value is given. For p 4, the p 0 p 0 p 0 p 0 and p 1 p 1 p 1 p 1 terms were used for each CSF. Terms added N N tot E(N tot ) in hartrees E in nh 1:8s K 1:8s K 1:8s L 1:8s L R :9p Kp 2:9p Kp 1:8s L 1:8s L R :8p Kp 2:8p Kp 1:8s L 1:8s L R :8s K 1:8s K 2:9p Lp 2:9p Lp R :8s K 1:8s K 2:8p Lp 2:8p Lp R :7p Kp 2:7p Kp 2:7p Lp 2:7p Lp R :6p Kp 2:6p Kp 2:6p Lp 2:6p Lp R :7s K 2:7p Kp 1:7s L 2:7p Lp R :6s K 2:6p Kp 1:6s L 2:6p Lp R :7s K 2:7p Kp 2:7p Lp 1:7s L R :6s K 2:6p Kp 2:6p Lp 1:6s L R :7s K 1:7s K 3:8d Ld 3:8d Ld R :8d Kd 3:8d Kd 1:6s L 1:6s L R :8d Kd 3:8d Kd 1:7s L 1:7s L R :6s K 3:7d Kd 1:6s L 3:7d Ld R (r-sum 14) :6s K 3:7d Kd 3:7d Ld 1:6s L R (r-sum 14) :6s K 2:6p Kp 2:6p Lp 3:6d Ld R :6p Kp 2:6p Kp 1:6s L 3:6d Ld R :5p Kp 2:5p Kp 1:5s L 3:5d Ld R :6s K 3:7d Kd 2:6p Lp 2:6p Lp R :5s K 3:5d Kd 2:5p Lp 2:5p Lp R :6p Kp 1:5s K 2:5p Lp 3:6d Ld R :6p Kp 1:5s K 2:5p Lp 3:7d Ld R :5d Kd 2:6p Kp 1:5s L 2:6p Lp R :6p Kp 3:7d Kd 1:5s L 2:5p Lp R :6p Kp 3:6d Kd 1:6s L 2:6p Lp R :7s K 1:7s K 4:7f Lf 4:7f Lf R :8f Kf 4:8f Kf 1:7s L 1:7s L R :6s K 4:7f Kf 1:5s L 4:7f Lf R :6s K 4:7f Kf 4:7f Lf 1:5s L R

8 Terms added N N tot E(N tot ) in hartrees E in nh 3:8d 0Kd 3:8d 0Kd 2:7p 0Lp 2:7p 0Lp R :8d 1Kd 3:8d 1Kd 2:7p 1Lp 2:7p 1Lp R :7d 1Kd 3:7d 1Kd 2:6p 1Lp 2:6p 1Lp R :7p 0Kp 2:7p 0Kp 3:7d 0Ld 3:7d 0Ld R :7p 1Kp 2:7p 1Kp 3:7d 1Ld 3:7d 1Ld R :5p 0Kp 3:7d 0Kd 2:6p 0Lp 3:7d 0Ld R (r-sum 12) :5p 1Kp 3:7d 1Kd 2:6p 1Lp 3:7d 1Ld R (r-sum 12) :5p 0Kp 3:7d 0Kd 3:7d 0Ld 2:6p 0Lp R (r-sum 12) :5p 1Kp 3:7d 1Kd 3:7d 1Ld 2:6p 1Lp R (r-sum 12) :8f 0Kf 4:8f 0Kf 2:7p 0Lp 2:7p 0Lp R :8f 1Kf 4:8f 1Kf 2:7p 1Lp 2:7p 1Lp R :5p 0Kp 2:5p 0Kp 4:7f 0Lf 4:7f 0Lf R :5p 1Kp 2:5p 1Kp 4:7f 1Lf 4:7f 1Lf R :6s K1 1:6s K1 2:6s L 2:6s L R :5s K 3:6d Kd 3:6d Ld 3:6d Ld R :6d Kd 3:6d Kd 2:6s L 3:6d Ld R :5s K 2:6p Kp 3:6d Ld 4:7f Lf R :6d Kd 4:7f Kf 2:6s L 2:6p Lp R :6s K 2:6p Kp 4:7f Lf 3:6d Ld R :6d Kd 4:7f Kf 2:6p Lp 2:6s L R :6s K 3:6d Kd 2:6p Lp 4:7f Lf R :6s K 4:7f Kf 2:6p Lp 3:6d Ld R :6s K 4:7f Kf 3:6d Ld 2:6p Lp :6s K 3:6d Kd 4:7f Lf 2:6p Lp :7f Kf 4:7f Kf 2:5s L 3:7d Ld r :5p Kp 1:5s K 2:5p Lp 1:5s L r :5p Kp 1:5s K 1:5s L 2:5p Lp r :7d Kd 1:5s K 1:6s L 3:7d Ld r :7f Kf 1:5s K 4:7f Lf 1:6s L r :5p 1Kp 3:7d 1Kd 2:6p 1Lp 3:7d 1Ld r :5p 1Kp 3:7d 1Kd 3:7d 1Ld 2:6p 1Lp r :8f 1Kf 4:8f 1Kf 2:7p 1Lp 2:7p 1Lp r :6p K2 2:6p K2 1:6s L 1:6s L R :7g Kg 5:7g Kg 1:5s L 1:5s L r 34 (r-sum 20) :5s K 1:5s K 5:7g Lg 5:7g Lg r 12 (r-sum 20) :5s K 1:5s K 5:7g Lg 5:7g Lg r 13 (r-sum 20) :5s K 1:5s K 5:7g Lg 5:7g Lg r 14 (r-sum 20) :5s K 5:7g Kg 5:7g Lg 1:5s L R

9 Table IV: Hy-CI calculations of the Be isoelectronic sequence ground state nonrelativistic energies (in hartrees) for 38,253, 52,405, 79,137, and 80,073 terms in the expansion. All energies are variational except for those labelled (P), which are predicted from least squares fits to energy differences (see Section III), and one labelled (I), an interpolated value (see text). The 80,073 energies are estimated to be accurate to ten nanohartrees. Z System 38,253 result 52,405 result 79,137 result 80,073 result 4 Be B C N (P) O F (P) Ne (I) Na (P) Al (P) (P) 14 Si (P) S Ar V (P) (P) 24 Cr (P) (P) 25 Mn (P) Ni (P) (P) 32 Ge (P) (P) 33 As Sr (P) (P) 43 Tc (P) (P) 48 Cd I (P) (P) 58 Ce (P) (P) 63 Eu Er (P) (P) 73 Ta (P) (P) 78 Pt (P) (P) 83 Bi (P) (P) 9

10 Z System 38,253 result 52,405 result 79,137 result 80,073 result 88 Ra U (P) (P) 113 Uut To test how well the convergence of the r 12 r 34 term type ( double cusp problem ) is treated in Hy-CI, the calculations presented in Table V were done. Table V: Convergence of r 12 r 34 as represented by Hy-CI. N is the number of terms added and N tot is the cumulative number of terms. The terms are filtered using N max = 16 (see text). Terms added N N tot E(N tot ) in hartrees E in µh 1:8s K 1:8s K 1:8s L 1:8s L :7p Kp 2:7p Kp 1:8s L 1:8s L :8s K 1:8s K 2:7p Lp 2:7p Lp :7p Kp 2:7p Kp 2:7p Lp 2:7p Lp :8s K 1:8s K 1:8s L 1:8s L r :8s K 1:8s K 2:7p Lp 2:7p Lp r :8s K 1:8s K 3:7d Ld 3:7d Ld r :8s K 1:8s K 4:7f Lf 4:7f Lf r :8s K 1:8s K 5:7g Lg 5:7g Lg r :8s K 1:8s K 1:8s L 1:8s L r :7p Kp 2:7p Kp 1:8s L 1:8s L r :7d Kd 3:7d Kd 1:8s L 1:8s L r :7f Kf 4:7f Kf 1:8s L 1:8s L r :7g Kg 5:7g Kg 1:8s L 1:8s L r

11 Finally Table VI gives the coefficients for several piecewise Z 1 least square polynomial fits for the 80,073 CSF energy values in Table IV to full precision and Table VII gives both calculated and predicted energies for the whole Z range [4,113]. Table VI: Coefficients for several piecewise Z 1 least square polynomial fits for the 80,073 CSF energy values in Table IV. R max is the maximum Residual. Z=[4,113] Z=[4,18] Z=[18,48] Z=[48,113] n a n a n a n a n R max Table VII: Calculated 80,073 CSF nonrelativistic energy values and predicted energy values obtained from the least squares fit of the whole Z range [4,113]. Energies are in hartrees, energy differences are in nanohartrees. Maximum residual is Z System Data E(Z) Predicted E(Z) Difference 4 Be B C N O F Ne Na Mg Al

12 Z System Data E(Z) Predicted E(Z) Difference 14 Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb

13 Z System Data E(Z) Predicted E(Z) Difference 52 Te I Xe Cs Ba La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac

14 Z System Data E(Z) Predicted E(Z) Difference 90 Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Rf Db Sg Bh Hs Mt Uun Uuu Uub Uut

15 References [1] E. U. Condon and G. H. Shortley. The Theory of Atomic Spectra. Cambridge U. P., Cambridge, England, [2] J. S. Sims and S. A. Hagstrom. One center r ij integrals over Slater-type orbitals. J. Chem. Phys., 55(10): , [3] J. S. Sims and S. A. Hagstrom. Hylleraas-configuration-interaction study of the 1 1 S ground state of neutral beryllium. Phys. Rev. A, 83:032518, [4] J. S. Sims and S. A. Hagstrom. See supplemental material at [URL will be inserted by AIP] for additional material for Hylleraas-configuration interaction nonrelativistic energies for the 1 S ground states of the beryllium isoelectronic sequence. 15

B I N G O B I N G O. Hf Cd Na Nb Lr. I Fl Fr Mo Si. Ho Bi Ce Eu Ac. Md Co P Pa Tc. Uut Rh K N. Sb At Md H. Bh Cm H Bi Es. Mo Uus Lu P F.

B I N G O B I N G O. Hf Cd Na Nb Lr. I Fl Fr Mo Si. Ho Bi Ce Eu Ac. Md Co P Pa Tc. Uut Rh K N. Sb At Md H. Bh Cm H Bi Es. Mo Uus Lu P F. Hf Cd Na Nb Lr Ho Bi Ce u Ac I Fl Fr Mo i Md Co P Pa Tc Uut Rh K N Dy Cl N Am b At Md H Y Bh Cm H Bi s Mo Uus Lu P F Cu Ar Ag Mg K Thomas Jefferson National Accelerator Facility - Office of cience ducation

More information

Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry Answers

Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry Answers Key Questions & Exercises Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry Answers 1. The atomic weight of carbon is 12.0107 u, so a mole of carbon has a mass of 12.0107 g. Why doesn t a mole of

More information

Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry

Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry Why? Chemists are concerned with mass relationships in chemical reactions, usually run on a macroscopic scale (grams, kilograms, etc.). To deal with

More information

All answers must use the correct number of significant figures, and must show units!

All answers must use the correct number of significant figures, and must show units! CHEM 10113, Quiz 2 September 7, 2011 Name (please print) All answers must use the correct number of significant figures, and must show units! IA Periodic Table of the Elements VIIIA (1) (18) 1 2 1 H IIA

More information

CLASS TEST GRADE 11. PHYSICAL SCIENCES: CHEMISTRY Test 6: Chemical change

CLASS TEST GRADE 11. PHYSICAL SCIENCES: CHEMISTRY Test 6: Chemical change CLASS TEST GRADE PHYSICAL SCIENCES: CHEMISTRY Test 6: Chemical change MARKS: 45 TIME: hour INSTRUCTIONS AND INFORMATION. Answer ALL the questions. 2. You may use non-programmable calculators. 3. You may

More information

From Quantum to Matter 2006

From Quantum to Matter 2006 From Quantum to Matter 006 Why such a course? Ronald Griessen Vrije Universiteit, Amsterdam AMOLF, May 4, 004 vrije Universiteit amsterdam Why study quantum mechanics? From Quantum to Matter: The main

More information

ELECTRON CONFIGURATION (SHORT FORM) # of electrons in the subshell. valence electrons Valence electrons have the largest value for "n"!

ELECTRON CONFIGURATION (SHORT FORM) # of electrons in the subshell. valence electrons Valence electrons have the largest value for n! 179 ELECTRON CONFIGURATION (SHORT FORM) - We can represent the electron configuration without drawing a diagram or writing down pages of quantum numbers every time. We write the "electron configuration".

More information

It takes four quantum numbers to describe an electron. Additionally, every electron has a unique set of quantum numbers.

It takes four quantum numbers to describe an electron. Additionally, every electron has a unique set of quantum numbers. So, quantum mechanics does not define the path that the electron follows; rather, quantum mechanics works by determining the energy of the electron. Once the energy of an electron is known, the probability

More information

100% ionic compounds do not exist but predominantly ionic compounds are formed when metals combine with non-metals.

100% ionic compounds do not exist but predominantly ionic compounds are formed when metals combine with non-metals. 2.21 Ionic Bonding 100% ionic compounds do not exist but predominantly ionic compounds are formed when metals combine with non-metals. Forming ions Metal atoms lose electrons to form +ve ions. Non-metal

More information

The Lewis structure is a model that gives a description of where the atoms, charges, bonds, and lone pairs of electrons, may be found.

The Lewis structure is a model that gives a description of where the atoms, charges, bonds, and lone pairs of electrons, may be found. CEM110 Week 12 Notes (Chemical Bonding) Page 1 of 8 To help understand molecules (or radicals or ions), VSEPR shapes, and properties (such as polarity and bond length), we will draw the Lewis (or electron

More information

Electronegativity and Polarity

Electronegativity and Polarity and Polarity N Goalby Chemrevise.org Definition: is the relative tendency of an atom in a molecule to attract electrons in a covalent bond to itself. is measured on the Pauling scale (ranges from 0 to

More information

The Role of Triads in the Evolution of the Periodic Table: Past and Present

The Role of Triads in the Evolution of the Periodic Table: Past and Present The Role of Triads in the Evolution of the Periodic Table: Past and Present Eric Scerri Department of Chemistry and Biochemistry, University of California, Los Angeles, Los Angeles, CA 90095; scerri@chem.ucla.edu

More information

Role of Hydrogen Bonding on Protein Secondary Structure Introduction

Role of Hydrogen Bonding on Protein Secondary Structure Introduction Role of Hydrogen Bonding on Protein Secondary Structure Introduction The function and chemical properties of proteins are determined by its three-dimensional structure. The final architecture of the protein

More information

ORTEC DET-SW-UPG. Latest Software Features. Ease of Use. Source Location with the Detective V3 Software

ORTEC DET-SW-UPG. Latest Software Features. Ease of Use. Source Location with the Detective V3 Software ORTEC DET-SW-UPG Latest Software Features Three Search Modes: Gamma/Neutron total count rate. SNM search mode. Sliding average "monitor" mode. (NEW) User choice of identification schemes: Classify mode

More information

MODERN ATOMIC THEORY AND THE PERIODIC TABLE

MODERN ATOMIC THEORY AND THE PERIODIC TABLE CHAPTER 10 MODERN ATOMIC THEORY AND THE PERIODIC TABLE SOLUTIONS TO REVIEW QUESTIONS 1. Wavelength is defined as the distance between consecutive peaks in a wave. It is generally symbolized by the Greek

More information

Chapter 2 Lecture Notes: Atoms

Chapter 2 Lecture Notes: Atoms Educational Goals Chapter 2 Lecture Notes: Atoms 1. Describe the subatomic structure of an atom. 2. Define the terms element and atomic symbol. 3. Understand how elements are arranged in the periodic table

More information

chemrevise.org 19/08/2013 Periodicity N Goalby chemrevise.org

chemrevise.org 19/08/2013 Periodicity N Goalby chemrevise.org chemrevise.org 19/8/213 eriodicity Goalby chemrevise.org locks An s-block element will always have an electronic structure where the outer electron is filling a s-sublevel. kewise the outer electron of

More information

8. Relax and do well.

8. Relax and do well. CHEM 1314 3:30 pm Section Exam II ohn II. Gelder October 16, 2002 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 8 different pages. The last three pages include a periodic

More information

EXPERIMENT 4 The Periodic Table - Atoms and Elements

EXPERIMENT 4 The Periodic Table - Atoms and Elements EXPERIMENT 4 The Periodic Table - Atoms and Elements INTRODUCTION Primary substances, called elements, build all the materials around you. There are more than 109 different elements known today. The elements

More information

Chapter 8 Atomic Electronic Configurations and Periodicity

Chapter 8 Atomic Electronic Configurations and Periodicity Chapter 8 Electron Configurations Page 1 Chapter 8 Atomic Electronic Configurations and Periodicity 8-1. Substances that are weakly attracted to a magnetic field but lose their magnetism when removed from

More information

Inorganic Chemistry review sheet Exam #1

Inorganic Chemistry review sheet Exam #1 Inorganic hemistry review sheet Exam #1 h. 1 General hemistry review reaction types: A/B, redox., single displacement, elimination, addition, rearrangement and solvolysis types of substances: elements,

More information

Exam 1. Spring 2012/13 CHE 140 Section: 5701 & 5702 100 total points Date: Mon. Feb. 11 & Tue. Feb. 12, 2013

Exam 1. Spring 2012/13 CHE 140 Section: 5701 & 5702 100 total points Date: Mon. Feb. 11 & Tue. Feb. 12, 2013 + 80 points Exam 1 Spring 2012/13 Name: CHE 140 Section: 5701 & 5702 100 total points Date: Mon. Feb. 11 & Tue. Feb. 12, 2013 Directions: Answer the following questions completely. For multiple choice

More information

Chemistry CP Unit 2 Atomic Structure and Electron Configuration. Learning Targets (Your exam at the end of Unit 2 will assess the following:)

Chemistry CP Unit 2 Atomic Structure and Electron Configuration. Learning Targets (Your exam at the end of Unit 2 will assess the following:) Chemistry CP Unit 2 Atomic Structure and Electron Learning Targets (Your exam at the end of Unit 2 will assess the following:) 2. Atomic Structure and Electron 2-1. Give the one main contribution to the

More information

Find a pair of elements in the periodic table with atomic numbers less than 20 that are an exception to the original periodic law.

Find a pair of elements in the periodic table with atomic numbers less than 20 that are an exception to the original periodic law. Example Exercise 6.1 Periodic Law Find the two elements in the fifth row of the periodic table that violate the original periodic law proposed by Mendeleev. Mendeleev proposed that elements be arranged

More information

Ionizing Radiation, Czech Republic, CMI (Czech Metrology Institute)

Ionizing Radiation, Czech Republic, CMI (Czech Metrology Institute) Ionizing Radiation, Czech Republic, (Czech Metrology Institute) Calibration or Measurement RADIOACTIVITY 1.0E+00 1.0E+02 Bq cm -2 C-14 1.0E+01 1.0E+02 Bq cm -2 Co-60 1.0E+01 1.0E+02 Bq cm -2 Sr-90 1.0E+01

More information

REVIEW QUESTIONS Chapter 8

REVIEW QUESTIONS Chapter 8 Chemistry 101 ANSWER KEY REVIEW QUESTIONS Chapter 8 Use only a periodic table to answer the following questions. 1. Write complete electron configuration for each of the following elements: a) Aluminum

More information

PERIODIC TABLE OF GROUPS OF ELEMENTS Elements can be classified using two different schemes.

PERIODIC TABLE OF GROUPS OF ELEMENTS Elements can be classified using two different schemes. 1 PERIODIC TABLE OF GROUPS OF ELEMENTS Elements can be classified using two different schemes. Metal Nonmetal Scheme (based on physical properties) Metals - most elements are metals - elements on left

More information

WASTE STREAM 2Y51 Analytical Services Process Facilities - North Labs

WASTE STREAM 2Y51 Analytical Services Process Facilities - North Labs WASTE STREAM 2Y51 Analytical Services Process Facilities North Labs SITE SITE OWNER WASTE CUSTODIAN WASTE TYPE Sellafield Nuclear Decommissioning Authority Sellafield Limited LLW WASTE VOLUMES Stocks:

More information

Victims Compensation Claim Status of All Pending Claims and Claims Decided Within the Last Three Years

Victims Compensation Claim Status of All Pending Claims and Claims Decided Within the Last Three Years Claim#:021914-174 Initials: J.T. Last4SSN: 6996 DOB: 5/3/1970 Crime Date: 4/30/2013 Status: Claim is currently under review. Decision expected within 7 days Claim#:041715-334 Initials: M.S. Last4SSN: 2957

More information

CHEM 107 (Spring-2005) Final Exam (100 pts)

CHEM 107 (Spring-2005) Final Exam (100 pts) CHEM 107 (Spring-2005) Final Exam (100 pts) Name: ------------------------------------------------------------------------, Clid # ------------------------------ LAST NAME, First (Circle the alphabet segment

More information

B) atomic number C) both the solid and the liquid phase D) Au C) Sn, Si, C A) metal C) O, S, Se C) In D) tin D) methane D) bismuth B) Group 2 metal

B) atomic number C) both the solid and the liquid phase D) Au C) Sn, Si, C A) metal C) O, S, Se C) In D) tin D) methane D) bismuth B) Group 2 metal 1. The elements on the Periodic Table are arranged in order of increasing A) atomic mass B) atomic number C) molar mass D) oxidation number 2. Which list of elements consists of a metal, a metalloid, and

More information

1.- L a m e j o r o p c ió n e s c l o na r e l d i s co ( s e e x p li c a r á d es p u é s ).

1.- L a m e j o r o p c ió n e s c l o na r e l d i s co ( s e e x p li c a r á d es p u é s ). PROCEDIMIENTO DE RECUPERACION Y COPIAS DE SEGURIDAD DEL CORTAFUEGOS LINUX P ar a p od e r re c u p e ra r nu e s t r o c o rt a f u e go s an t e un d es a s t r e ( r ot u r a d e l di s c o o d e l a

More information

Standard Operation Procedure. Elemental Analysis of Solution samples with Inductively Coupled Plasma Mass Spectrometry

Standard Operation Procedure. Elemental Analysis of Solution samples with Inductively Coupled Plasma Mass Spectrometry Standard Operation Procedure Elemental Analysis of Solution samples with Inductively Coupled Plasma Mass Spectrometry Soil & Plant Analysis Laboratory University of Wisconsin Madison http://uwlab.soils.wisc.edu

More information

Nuclear ZPE Tapping. Horace Heffner May 2007

Nuclear ZPE Tapping. Horace Heffner May 2007 ENERGY FROM UNCERTAINTY The uncertainty of momentum for a particle constrained by distance Δx is given, according to Heisenberg, by: Δmv = h/(2 π Δx) but since KE = (1/2) m v 2 = (1/(2 m) ) (Δmv) 2 ΔKE

More information

Web Typography Sucks

Web Typography Sucks Web Typography Sucks Richard Rutter Mark Boulton RR: We re here to talk about web typography sucks - how it does, why it needn t, when it doesn t and how we can all do something about it. Let s talk about

More information

3. What would you predict for the intensity and binding energy for the 3p orbital for that of sulfur?

3. What would you predict for the intensity and binding energy for the 3p orbital for that of sulfur? PSI AP Chemistry Periodic Trends MC Review Name Periodic Law and the Quantum Model Use the PES spectrum of Phosphorus below to answer questions 1-3. 1. Which peak corresponds to the 1s orbital? (A) 1.06

More information

Chemistry: The Periodic Table and Periodicity

Chemistry: The Periodic Table and Periodicity Chemistry: The Periodic Table and Periodicity Name: per: Date:. 1. By what property did Mendeleev arrange the elements? 2. By what property did Moseley suggest that the periodic table be arranged? 3. What

More information

CVD SILICON CARBIDE. CVD SILICON CARBIDE s attributes include:

CVD SILICON CARBIDE. CVD SILICON CARBIDE s attributes include: CVD SILICON CARBIDE CVD SILICON CARBIDE is the ideal performance material for design engineers. It outperforms conventional forms of silicon carbide, as well as other ceramics, quartz, and metals in chemical

More information

X-RAY DATA BOOKLET Center for X-ray Optics and Advanced Light Source Lawrence Berkeley National Laboratory

X-RAY DATA BOOKLET Center for X-ray Optics and Advanced Light Source Lawrence Berkeley National Laboratory X-Ray Data Booklet X-RAY DATA BOOKLET Center for X-ray Optics and Advanced Light Source Lawrence Berkeley National Laboratory Introduction X-Ray Properties of Elements Now Available Order X-Ray Data Booklet

More information

Name period AP chemistry Unit 2 worksheet Practice problems

Name period AP chemistry Unit 2 worksheet Practice problems Name period AP chemistry Unit 2 worksheet Practice problems 1. What are the SI units for a. Wavelength of light b. frequency of light c. speed of light Meter hertz (s -1 ) m s -1 (m/s) 2. T/F (correct

More information

47374_04_p25-32.qxd 2/9/07 7:50 AM Page 25. 4 Atoms and Elements

47374_04_p25-32.qxd 2/9/07 7:50 AM Page 25. 4 Atoms and Elements 47374_04_p25-32.qxd 2/9/07 7:50 AM Page 25 4 Atoms and Elements 4.1 a. Cu b. Si c. K d. N e. Fe f. Ba g. Pb h. Sr 4.2 a. O b. Li c. S d. Al e. H f. Ne g. Sn h. Au 4.3 a. carbon b. chlorine c. iodine d.

More information

Towards a Circular Economy rethinking value chains to boost resource productivity

Towards a Circular Economy rethinking value chains to boost resource productivity Towards a Circular Economy rethinking value chains to boost resource productivity Dr. Markus Zils Returnity Partners Brussels Environment, 29 th Mai 2015 Contents The resource revolution Circular economy

More information

CHAPTER 8 PRACTICE TEST QUESTIONS (END OF CHAPTER 7 TOO)

CHAPTER 8 PRACTICE TEST QUESTIONS (END OF CHAPTER 7 TOO) CHAPTER 8 PRACTICE TEST QUESTIONS (END OF CHAPTER 7 TOO) Information that most likely will be on the front cover of your exam: h i Z 2 ΔE = @ 2.18 x 10 @ 18 f Z 2 f J j @ k n f 2 n i 2 1. Which of the

More information

Sustainable energy products Simulation based design for recycling

Sustainable energy products Simulation based design for recycling Sustainable energy products Simulation based design for recycling Markus A. Reuter (Prof. Dr. Dr. hc) Director: Technology Management, Outotec Oyj Aalto University (Finland), Central South University (China),

More information

Unit 2 Matter and Chemical Change. Unit Test

Unit 2 Matter and Chemical Change. Unit Test Unit Test Student Name Class Section 1 Properties of Matter 1. Aluminum foam is used to create lighter, safer cars. The reason that a lighter car is a safer car is because aluminum foam is A. less rigid

More information

High-tech recycling of critical metals: Opportunities and challenges

High-tech recycling of critical metals: Opportunities and challenges High-tech recycling of critical metals: Opportunities and challenges Application know-how Metals Chemistry material Material science solutions Metallurgy Material solutions Recycling Christina Meskers

More information

6.5 Periodic Variations in Element Properties

6.5 Periodic Variations in Element Properties 324 Chapter 6 Electronic Structure and Periodic Properties of Elements 6.5 Periodic Variations in Element Properties By the end of this section, you will be able to: Describe and explain the observed trends

More information

5.4 Trends in the Periodic Table

5.4 Trends in the Periodic Table 5.4 Trends in the Periodic Table Think about all the things that change over time or in a predictable way. For example, the size of the computer has continually decreased over time. You may become more

More information

Qualitätsmanagement-Handbuch

Qualitätsmanagement-Handbuch U r Kalibrier- und Messmöglichkeiten Qualitätsmanagement-Handbuch Relative erweiterte Messunsicherheit, die sich aus der Standardmessunsicherheit durch Multiplikation mit dem Erweiterungsfaktor k = 2 ergibt.

More information

= 11.0 g (assuming 100 washers is exact).

= 11.0 g (assuming 100 washers is exact). CHAPTER 8 1. 100 washers 0.110 g 1 washer 100. g 1 washer 0.110 g = 11.0 g (assuming 100 washers is exact). = 909 washers 2. The empirical formula is CFH from the structure given. The empirical formula

More information

Concept differences in WD-XRF goniometer systems

Concept differences in WD-XRF goniometer systems X-Ray Conference Norway 14 september 2010 Concept differences in WD-XRF goniometer systems Didier Bonvin & Renaat Van Geel Thermo Fisher Scientific, Ecublens, Switzerland Renaat Van Geel SID Commercial

More information

WASTE STREAM 2F35 Excellox-Type Transport Flasks and French-Design Dry Flasks

WASTE STREAM 2F35 Excellox-Type Transport Flasks and French-Design Dry Flasks SITE SITE OWR WASTE CUSTODIAN WASTE TYPE Sellafield Nuclear Decommissioning Authority Sellafield Limited LLW WASTE VOLUMES Stocks: At 1.4.2013... Future arisings - Total future arisings: 45.4 m³ Comment

More information

XIX. Chemistry, High School

XIX. Chemistry, High School XIX. Chemistry, High School High School Chemistry Test The spring 05 high school Chemistry test was based on learning standards in the Chemistry content strand of the Massachusetts Science and Technology/Engineering

More information

Electronegativity and Polarity MAIN Idea A chemical bond s character is related to each atom s

Electronegativity and Polarity MAIN Idea A chemical bond s character is related to each atom s Section 8.5 Objectives Describe how electronegativity is used to determine bond type. Compare and contrast polar and nonpolar covalent bonds and polar and nonpolar molecules. Generalize about the characteristics

More information

SUS. Company Profile. Ulrich Nell, Feldstr.23, D - 46149 Oberhausen, Tel. 0049(0)208/658535 Fax 0049(0)208/658536

SUS. Company Profile. Ulrich Nell, Feldstr.23, D - 46149 Oberhausen, Tel. 0049(0)208/658535 Fax 0049(0)208/658536 SUS Ulrich Nell, Feldstr.23, D - 46149 Oberhausen, Tel. 0049(0208/658535 Fax 0049(0208/658536 Company Profile SUS was founded in 1986 in Oberhausen in the Ruhr area (close to Düsseldorf, in order to meet

More information

C o a t i a n P u b l i c D e b tm a n a g e m e n t a n d C h a l l e n g e s o f M a k e t D e v e l o p m e n t Z a g e bo 8 t h A p i l 2 0 1 1 h t t pdd w w wp i j fp h D p u b l i c2 d e b td S t

More information

neutrons are present?

neutrons are present? AP Chem Summer Assignment Worksheet #1 Atomic Structure 1. a) For the ion 39 K +, state how many electrons, how many protons, and how many 19 neutrons are present? b) Which of these particles has the smallest

More information

Natural Sciences I. Lecture 15: Elements and the Periodic Table

Natural Sciences I. Lecture 15: Elements and the Periodic Table Natural Sciences I Lecture 5: Elements and the Periodic Table Classifying MATTER Chapter 0 of your text opens with a discussion of the types of chemical bonds, and also includes a review (pp. 4-4) of the

More information

Steven M. Ho!and. Department of Geology, University of Georgia, Athens, GA 30602-2501

Steven M. Ho!and. Department of Geology, University of Georgia, Athens, GA 30602-2501 PRINCIPAL COMPONENTS ANALYSIS (PCA) Steven M. Ho!and Department of Geology, University of Georgia, Athens, GA 30602-2501 May 2008 Introduction Suppose we had measured two variables, length and width, and

More information

Copyrighted by Gabriel Tang B.Ed., B.Sc.

Copyrighted by Gabriel Tang B.Ed., B.Sc. Chapter 8: The Periodic Table 8.1: Development of the Periodic Table Johann Dobereiner: - first to discover a pattern of a group of elements like Cl, Br, and I (called triads). John Newland: - suggested

More information

UNIT (2) ATOMS AND ELEMENTS

UNIT (2) ATOMS AND ELEMENTS UNIT (2) ATOMS AND ELEMENTS 2.1 Elements An element is a fundamental substance that cannot be broken down by chemical means into simpler substances. Each element is represented by an abbreviation called

More information

Periodic Table, Valency and Formula

Periodic Table, Valency and Formula Periodic Table, Valency and Formula Origins of the Periodic Table Mendelѐѐv in 1869 proposed that a relationship existed between the chemical properties of elements and their atomic masses. He noticed

More information

Analyses on copper samples from Micans

Analyses on copper samples from Micans PDF rendering: DokumentID 1473479, Version 1., Status Godkänt, Sekretessklass Öppen Analyses on copper samples from Micans P. Berastegui, M. Hahlin, M. Ottosson, M. Korvela, Y. Andersson, R. Berger and

More information

CODES FOR PHARMACY ONLINE CLAIMS PROCESSING

CODES FOR PHARMACY ONLINE CLAIMS PROCESSING S FOR PHARMACY ONLINE CLAIMS PROCESSING The following is a list of error and warning codes that may appear when processing claims on the online system. The error codes are bolded. CODE AA AB AI AR CB CD

More information

Data Analysis and Validation Support for PM2.5 Chemical Speciation Networks- #82

Data Analysis and Validation Support for PM2.5 Chemical Speciation Networks- #82 Data Analysis and Validation Support for PM2.5 Chemical Speciation Networks- #82 Max R. Peterson and Edward E. Rickman Research Triangle Institute 3040 Cornwallis Road P.O. Box 12194 Research Triangle

More information

COURSE#1022: Biochemical Applications of NMR Spectroscopy. http://www.bioc.aecom.yu.edu/labs/girvlab/nmr/course/ Basic Principles

COURSE#1022: Biochemical Applications of NMR Spectroscopy. http://www.bioc.aecom.yu.edu/labs/girvlab/nmr/course/ Basic Principles COURSE#1022: Biochemical Applications of NMR Spectroscopy http://www.bioc.aecom.yu.edu/labs/girvlab/nmr/course/ Basic Principles LAST UPDATE: 1/11/2012 Reading Selected Readings for Basic Principles of

More information

SCO TT G LEA SO N D EM O Z G EB R E-

SCO TT G LEA SO N D EM O Z G EB R E- SCO TT G LEA SO N D EM O Z G EB R E- EG Z IA B H ER e d it o r s N ) LICA TIO N S A N D M ETH O D S t DVD N CLUDED C o n t e n Ls Pr e fa c e x v G l o b a l N a v i g a t i o n Sa t e llit e S y s t e

More information

Chapter 3. Elements, Atoms, Ions, and the Periodic Table

Chapter 3. Elements, Atoms, Ions, and the Periodic Table Chapter 3. Elements, Atoms, Ions, and the Periodic Table The Periodic Law and the Periodic Table In the early 1800's many elements had been discovered and found to have different properties. In 1817 Döbreiner's

More information

We emphasize Lewis electron dot structures because of their usefulness in explaining structure of covalent molecules, especially organic molecules.

We emphasize Lewis electron dot structures because of their usefulness in explaining structure of covalent molecules, especially organic molecules. Chapter 10 Bonding: Lewis electron dot structures and more Bonding is the essence of chemistry! Not just physics! Chemical bonds are the forces that hold atoms together in molecules, in ionic compounds,

More information

CHAPTER 9 THE PERIODIC TABLE AND SOME ATOMIC PROPERTIES

CHAPTER 9 THE PERIODIC TABLE AND SOME ATOMIC PROPERTIES CHAPTER 9 THE PERIODIC TABLE AND SOME ATOMIC PROPERTIES PRACTICE EXAMPLES 1A 1B A B A Atomic size decreases from left to right across a period, and from bottom to top in a family. We expect the smallest

More information

Periodic Table Questions

Periodic Table Questions Periodic Table Questions 1. The elements characterized as nonmetals are located in the periodic table at the (1) far left; (2) bottom; (3) center; (4) top right. 2. An element that is a liquid at STP is

More information

Ch. 9 - Electron Organization. The Bohr Model [9.4] Orbitals [9.5, 9.6] Counting Electrons, configurations [9.7]

Ch. 9 - Electron Organization. The Bohr Model [9.4] Orbitals [9.5, 9.6] Counting Electrons, configurations [9.7] Ch. 9 - Electron Organization The Bohr Model [9.4] Orbitals [9.5, 9.6] Counting Electrons, configurations [9.7] Predicting ion charges from electron configurations. CHEM 100 F07 1 Organization of Electrons

More information

Electron Configuration Worksheet (and Lots More!!)

Electron Configuration Worksheet (and Lots More!!) Electron Configuration Worksheet (and Lots More!!) Brief Instructions An electron configuration is a method of indicating the arrangement of electrons about a nucleus. A typical electron configuration

More information

Nomenclature and Formulas of Ionic Compounds. Section I: Writing the Name from the Formula

Nomenclature and Formulas of Ionic Compounds. Section I: Writing the Name from the Formula Purpose: Theory: Nomenclature and Formulas of Ionic Compounds 1. To become familiar with the rules of chemical nomenclature, based on the classification of compounds. 2. To write the proper name of the

More information

Bonding Practice Problems

Bonding Practice Problems NAME 1. When compared to H 2 S, H 2 O has a higher 8. Given the Lewis electron-dot diagram: boiling point because H 2 O contains stronger metallic bonds covalent bonds ionic bonds hydrogen bonds 2. Which

More information

CHAPTER 9 ATOMIC STRUCTURE AND THE PERIODIC LAW

CHAPTER 9 ATOMIC STRUCTURE AND THE PERIODIC LAW CHAPTER 9 ATOMIC STRUCTURE AND THE PERIODIC LAW Quantum mechanics can account for the periodic structure of the elements, by any measure a major conceptual accomplishment for any theory. Although accurate

More information

Put the human back in Human Resources.

Put the human back in Human Resources. Put the human back in Human Resources A Co m p l et e Hu m a n Ca p i t a l Ma n a g em en t So l u t i o n t h a t em p o w er s HR p r o f essi o n a l s t o m eet t h ei r co r p o r a t e o b j ect

More information

Electron Configurations, Isoelectronic Elements, & Ionization Reactions. Chemistry 11

Electron Configurations, Isoelectronic Elements, & Ionization Reactions. Chemistry 11 Electron Configurations, Isoelectronic Elements, & Ionization Reactions Chemistry 11 Note: Of the 3 subatomic particles, the electron plays the greatest role in determining the physical and chemical properties

More information

SCPS Chemistry Worksheet Periodicity A. Periodic table 1. Which are metals? Circle your answers: C, Na, F, Cs, Ba, Ni

SCPS Chemistry Worksheet Periodicity A. Periodic table 1. Which are metals? Circle your answers: C, Na, F, Cs, Ba, Ni SCPS Chemistry Worksheet Periodicity A. Periodic table 1. Which are metals? Circle your answers: C, Na, F, Cs, Ba, Ni Which metal in the list above has the most metallic character? Explain. Cesium as the

More information

CHEMISTRY B- FACTOR LABEL PACKET NAME: HR: PAGE 1. Chemistry B. Factor Label Packet

CHEMISTRY B- FACTOR LABEL PACKET NAME: HR: PAGE 1. Chemistry B. Factor Label Packet CHEMISTRY B- FACTOR LABEL PACKET NAME: HR: PAGE 1 Chemistry B Factor Label Packet CHEMISTRY B- FACTOR LABEL PACKET NAME: HR: PAGE 2 PERIODIC TABLE OF ELEMENTS WITH OXIDATION NUMBERS +1 0 H +2 +3-3 He Li

More information

13- What is the maximum number of electrons that can occupy the subshell 3d? a) 1 b) 3 c) 5 d) 2

13- What is the maximum number of electrons that can occupy the subshell 3d? a) 1 b) 3 c) 5 d) 2 Assignment 06 A 1- What is the energy in joules of an electron undergoing a transition from n = 3 to n = 5 in a Bohr hydrogen atom? a) -3.48 x 10-17 J b) 2.18 x 10-19 J c) 1.55 x 10-19 J d) -2.56 x 10-19

More information

Candidate Number. Other Names

Candidate Number. Other Names Centre Number Surname Notice to Candidate. The work you submit for assessment must be your own. If you copy from someone else or allow another candidate to copy from you or if you cheat in any other way,

More information

Chapter 7 Periodic Properties of the Elements

Chapter 7 Periodic Properties of the Elements Chapter 7 Periodic Properties of the Elements 1. Elements in the modern version of the periodic table are arranged in order of increasing. (a). oxidation number (b). atomic mass (c). average atomic mass

More information

NET IONIC EQUATIONS. A balanced chemical equation can describe all chemical reactions, an example of such an equation is:

NET IONIC EQUATIONS. A balanced chemical equation can describe all chemical reactions, an example of such an equation is: NET IONIC EQUATIONS A balanced chemical equation can describe all chemical reactions, an example of such an equation is: NaCl + AgNO 3 AgCl + NaNO 3 In this case, the simple formulas of the various reactants

More information

CHEM 1411 Chapter 5 Homework Answers

CHEM 1411 Chapter 5 Homework Answers 1 CHEM 1411 Chapter 5 Homework Answers 1. Which statement regarding the gold foil experiment is false? (a) It was performed by Rutherford and his research group early in the 20 th century. (b) Most of

More information

2008 U. S. NATIONAL CHEMISTRY OLYMPIAD

2008 U. S. NATIONAL CHEMISTRY OLYMPIAD 2008 U. S. NATIONAL CHEMISTRY OLYMPIAD NATIONAL EXAM PART III Prepared by the American Chemical Society Olympiad Laboratory Practical Task Force OLYMPIAD LABORATORY PRACTICAL TASK FORCE Steve Lantos, Brookline

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Practice Questions - Chapter 7 Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Which one of the following represents an impossible set of

More information

Chem 1A Exam 2 Review Problems

Chem 1A Exam 2 Review Problems Chem 1A Exam 2 Review Problems 1. At 0.967 atm, the height of mercury in a barometer is 0.735 m. If the mercury were replaced with water, what height of water (in meters) would be supported at this pressure?

More information

Lecture 5. elements (Figure 1). In addition, there are many ways of classifying trace elements.

Lecture 5. elements (Figure 1). In addition, there are many ways of classifying trace elements. Lecture 5 Nomenclature for Trace Element Classification We have already grouped elements into two classes, major elements and trace elements (Figure 1). In addition, there are many ways of classifying

More information

TRENDS IN THE PERIODIC TABLE

TRENDS IN THE PERIODIC TABLE Noble gases Period alogens Alkaline earth metals Alkali metals TRENDS IN TE PERIDI TABLE Usual charge +1 + +3-3 - -1 Number of Valence e - s 1 3 4 5 6 7 Electron dot diagram X X X X X X X X X 8 Group 1

More information

Nomenclature of Ionic Compounds

Nomenclature of Ionic Compounds Nomenclature of Ionic Compounds Ionic compounds are composed of ions. An ion is an atom or molecule with an electrical charge. Monatomic ions are formed from single atoms that have gained or lost electrons.

More information

G d y n i a U s ł u g a r e j e s t r a c j i i p o m i a r u c z a s u u c z e s t n i k ó w i m p r e z s p o r t o w y c h G d y s k i e g o O r o d k a S p o r t u i R e k r e a c j i w r o k u 2 0

More information

Chapter 8 - Chemical Equations and Reactions

Chapter 8 - Chemical Equations and Reactions Chapter 8 - Chemical Equations and Reactions 8-1 Describing Chemical Reactions I. Introduction A. Reactants 1. Original substances entering into a chemical rxn B. Products 1. The resulting substances from

More information

Questions on Chapter 8 Basic Concepts of Chemical Bonding

Questions on Chapter 8 Basic Concepts of Chemical Bonding Questions on Chapter 8 Basic Concepts of Chemical Bonding Circle the Correct Answer: 1) Which ion below has a noble gas electron configuration? A) Li 2+ B) Be 2+ C) B2+ D) C2+ E) N 2-2) Of the ions below,

More information

Sample Analysis Design Isotope Dilution

Sample Analysis Design Isotope Dilution Isotope Dilution Most accurate and precise calibration method available Requires analyte with two stable isotopes Monoisotopic elements cannot be determined via isotope dilution Spike natural sample with

More information

SEATTLE CENTRAL COMMUNITY COLLEGE DIVISION OF SCIENCE AND MATHEMATICS. Oxidation-Reduction

SEATTLE CENTRAL COMMUNITY COLLEGE DIVISION OF SCIENCE AND MATHEMATICS. Oxidation-Reduction SEATTLE CENTRAL COMMUNITY COLLEGE DIVISION OF SCIENCE AND MATHEMATICS OxidationReduction Oxidation is loss of electrons. (Oxygen is EN enough to grab e away from most elements, so the term originally meant

More information

University of Missouri and MU Research Reactor Center

University of Missouri and MU Research Reactor Center University of Missouri and MU Research Reactor Center DOE Isotope Workshop August 2008 University of Missouri Research Reactor Center The MURR Center a Global Resource A 10 MW reactor that operates 24

More information

X-RAY FLUORESCENCE INSTRUMENT CALIBRATION

X-RAY FLUORESCENCE INSTRUMENT CALIBRATION X-RAY FLUORESCENCE INSTRUMENT CALIBRATION Theory and Application by Brian Lee Francom A senior thesis submitted to the faculty of Brigham Young University-Idaho in partial fulfillment of the requirements

More information

2. John Dalton did his research work in which of the following countries? a. France b. Greece c. Russia d. England

2. John Dalton did his research work in which of the following countries? a. France b. Greece c. Russia d. England CHAPTER 3 1. Which combination of individual and contribution is not correct? a. Antoine Lavoisier - clarified confusion over cause of burning b. John Dalton - proposed atomic theory c. Marie Curie - discovered

More information

Chalcophile and Key Element Distribution in the Eastern Goldfields: seismic traverse EGF01. Aleks Kalinowski Geoscience Australia, pmdcrc Y2 project

Chalcophile and Key Element Distribution in the Eastern Goldfields: seismic traverse EGF01. Aleks Kalinowski Geoscience Australia, pmdcrc Y2 project pmd CR C Chalcophile and Key Element Distribution in the Eastern Goldfields: seismic traverse EGF01 predictive mineral discovery Aleks Kalinowski Geoscience Australia, pmdcrc Y2 project Aleks.Kalinowski@ga.gov.au

More information