ELECTRON CONFIGURATION

Transcription

1 ELECTRON CONFIGURATION

2 Agenda Electron Configuration (O/S) HW: Complete Questions on the Handouts

3 Bohr s model Electrons orbit the nucleus in energy levels and are held there by electrostatic force of attraction ( attraction between positive nucleus and negatively charged electrons).

4 Bohr - Rutherford diagrams Putting all this together, we get B-R diagrams To draw them you must know the # of protons, neutrons, and electrons. Draw protons (p + ), (n 0 ) in circle (i.e. nucleus ) Draw electrons around in shells He Li Li shorthand 2 p + 2 n 0 3 p + 4 n 0 3 p + 4 n 0 2e 1e Draw BR diagrams for Ar, Ca, Sc.

5 Quantum Mechanics Model Quantum Mechanics Model modern description of the electron in atoms, derived from a mathematical equation (Schrodinger s wave equation). Electrons within an atom can posses only discrete quantities of energy. Schrodinger s equation describes the probability distribution of an electron. 90% probability of finding the electron Orbital

6 Models of the Atom- Review Dalton s Greek model model (400 (1803) B.C.) Thomson s plum-pudding model (1897) Rutherford s model (1909) Bohr s model (1913) Charge-cloud model (present) 1803 John Dalton pictures atoms as tiny, indestructible particles, with no internal structure J.J. Thomson, a British scientist, discovers the electron, leading to his "plum-pudding" model. He pictures electrons embedded in a sphere of positive electric charge New Zealander Ernest Rutherford states that an atom has a dense, positively charged nucleus. Electrons move randomly in the space around the nucleus In Niels Bohr's model, the electrons move in spherical orbits at fixed distances from the nucleus Erwin Schrödinger develops mathematical equations to describe the motion of electrons in atoms. His work leads to the electron cloud model Hantaro Nagaoka, a Japanese physicist, suggests that an atom has a central nucleus. Electrons move in orbits like the rings around Saturn Frenchman Louis de Broglie proposes that moving particles like electrons have some properties of waves. Within a few years evidence is collected to support his idea James Chadwick, a British physicist, confirms the existence of neutrons, which have no charge. Atomic nuclei contain neutrons and positively charged protons.

7 Heisenberg s uncertainty principle We cannot know both the location and velocity of an electron (Heisenberg s uncertainty principle), thus Schrodinger s equation does not tell us the exact location of the electron, rather it describes the probability that an electron will be at a certain location in the atom. Today we say that the electrons are located in a region outside the nucleus called the electron cloud. An orbital is a region of space where there is a high probability of locating an electron.

8 Electron Cloud Energy Levels The energy levels are analogous to the rungs of a ladder. The lowest rung of the ladder corresponds to the lowest energy level. A person can climb up or down a ladder by going from rung to rung. Similarly, an electron can jump from one energy level to another. A person on a ladder cannot stand between the rungs; similarly, the electrons in an atom cannot exist between energy levels.

9 ATOMIC SUBLEVELS Bohr Rutherford atomic theory does not account for all the spectral lines present in Hydrogen. It was proposed that energy levels were divided into sublevels. The letters s, p, d and f were used to identify the sublevels. Each sublevel orbital holds only 2 electrons, but the sublevels contain different numbers of orbitals: s - 1 orbital [maximum 2 e - ] p - 3 orbitals [maximum 6 e - ] d - 5 orbitals [maximum 10 e - ] f - 7 orbitals [maximum 14 e - ]

10 Shapes of s, p, and d-orbitals s orbital 1 orbital p orbitals 3 orbitals d orbitals 5 orbitals

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12 Different energy levels contain only certain sublevels Energy level 1 - s sublevel only Energy level 2 - s and p sublevels only Energy level 3 - s, p and d sublevels only Energy level 4 - s, p, d and f sublevels only Electron configuration denotes the arrangement of the electrons in their energy levels, sublevels and orbitals

13 Size of the orbital in different energy levels n 2 = # of orbitals in an energy level Total # of electrons = 2 n 2 Energy level Due to like charge repulsion, electrons of opposite spin direction can occur together in 1 orbital, maximum of 2 e- /orbital. 1s 2s 3s

14 ELECTRON CONFIGURATION An electron configuration is a written representation of the arrangement of electrons in an atom. 1 st rule - electrons occupy orbital s that require the least amount of energy for the electron to stay there.

15 You notice, for example, that the 4s sublevel requires less energy than the 3d sublevel; therefore, the 4s orbital is filled with electrons before any electrons enter the 3d orbital!!!! So just follow the above chart or the periodic table orbital blocks and you can t go wrong!!!!)

16 Examples: energy level Hydrogen: 1s 1 # of e - in orbital orbital/sublevel Helium: 1s 2 Lithium: 1s 2 2s 1 Carbon: 1s 2 2s 2 2p 2 You try to write the notation for Iron

17 Electron Configurations Orbital Filling Electron Element 1s 2s 2p x 2p y 2p z 3s Configuration H He Li C N O F Ne Na 1s 1 1s 2 NOT CORRECT Violates Hund s Rule 1s 2 2s 1 1s 2 2s 2 2p 2 1s 2 2s 2 2p 3 1s 2 2s 2 2p 4 1s 2 2s 2 2p 5 1s 2 2s 2 2p 6 1s 2 2s 2 2p 6 3s 1

18 Fe = 1s 1 2s 2 2p 6 3s 2 3p 6 4s 2 3d 6 Iron has 26 electrons. 1s 2s 2p x 2p y 2p z 3s 3p x 3p y 3p z 4s 3d 3d 3d 3d 3d e- e- e - e - e - e- e - e - e - e - e - e e - e - e - e e - e - - e - e - e - e - e - e e - e- -

19 Short Hand or Noble Gas Notation: Short Hand or Noble Gas Notation: Use the noble gases that have complete inner energy levels and an outer energy level with complete s and p orbital s. Use the noble gas that just precedes the element you are working with. Ex: Boron is 1s 2 2s 2 2p 1 The noble gas preceding Boron is He, so the short way is [He]2s 2 2p 1 Ex. Sulfur is ls 2 2s 2 2p 6 3s 2 3p 4 Short way: [Ne]3s 2 3p 4

20 Practice Problems: 1.Write electron configuration for the following atom: iodine 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 2 4d 10 5p 5 2.Write shorthand electron configuration for the following: I [Kr] 5s 2 4d 10 5p 5

21 Electron configurations for Ions First, determine if the element will lose or gain electrons. Secondly, what number of electrons will be gained or lost? It is recommended that you write the electron configuration for the atom and then determine what will happen.

22 Cations For cations (positive ions) look at the element and decide how many electrons will be lost when it ionizes and keep that in mind when writing the E. C. The last number in the E. C. will now be LESS than what is written on your periodic table. Ex. Write the electron configuration for stable magnesium ion: 1s 2 2s 2 2p 6 3s 2 is for the atom Mg is a metal and will lose its valence (outer) electrons so the E.C. for Mg 2+ is 1s 2 2s 2 2p 6

23 Anions For anions (negative ions) look at the element and decide how many electrons that element will GAIN when it ionizes. The last number in the E. C. will be MORE than what is written on the periodic table. Ex. Write the electron configuration for stable sulphide ion: 1s 2 2s 2 2p 6 3s 2 3p is for the atom S is a non-metal and will gain 2 electrons to become isoelectronic with a noble gas. so the E.C. for S 2- is 1s 2 2s 2 2p 6 3s 2 3p 6

24 Irregular Electron Configurations Sometimes the electron configuration is NOT what we would predict it to be. Sometimes electrons are moved because (l) it will result in greater stability for that atom or (2) for some unknown reason? It is very important to define stable here. STABLE means: all (equal energy) orbital s are FULL all orbital s are half-full all orbital s are totally empty.

25 Isoelectronicity Two or more entities (atoms, ions) are described as being isoelectronic with each other if they have the same number of electrons or the same electron configuration. Ex: State an neutral entity that is isoelectronic with Cl -. Cl - 1s 2 2s 2 2p 6 3s 2 3p 6 Ar 1s 2 2s 2 2p 6 3s 2 3p 6 Ex: State a charged entity that is isoelectronic with Cl -. S 2-1s 2 2s 2 2p 6 3s 2 3p 6 Ca 2+ 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2

26 1s ( n-2) d 4f 5f (n-1)

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