Chapter 8. Periodic Properties of the Element. Modified by Dr. Cheng-Yu Lai
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1 Chapter 8. Periodic Properties of the Element Modified by Dr. Cheng-Yu Lai
2 Energy Diagram for Hydrogen Atom The energy of a particular orbital is determined by its value of n. All orbitals with the same value of n have the same energy and are said to be degenerate. Hydrogen single electron occupy the lowest energy state, the ground state. If energy is put into the system, the electron can be transferred to higher energy orbital called excited state. For a one-electron hydrogen atom, orbitals on the same energy level have the same energy. That is, they are degenerate. H : 1s1 Orbital Energy Levels for the Hydrogen Atom
3 Electron Energy in Hydrogen-like Charge Atoms 2 Z 18 Eelectron x 10 J 2 n Z = nuclear charge (atomic number) n = energy level or principal quantum number (n) = 1, 2, 3, 4, ***Equation works only for atoms or ions with 1 electron (H, He+, Li2+, etc). Rydberg s constant (RH) = x J Johannes Rydberg ( )
4 Energy Orbitals for Polyelectronic Atoms As the number of electrons increases, though, so does the repulsion between them. Therefore, in manyelectron atoms, orbitals on the same energy level are no longer degenerate. For a given principal quantum level the orbitals vary in energy as follows: Ens< Enp < End < Enf
5 Order of Sublevel Filling in Ground State Electron Configurations Start by drawing a diagram, putting each energy shell on a row and listing the sublevels (s, p, d, f) for that shell in order of energy (from left to right). Next, draw arrows through the diagonals, looping back to the next diagonal each time Pearson Education, Inc. 1s 2s 2p 3s 3p 3d 4s 4p 4d 4f 5s 5p 5d 5f 6s 6p 6d 7s
6 Rules for Electron Configurations of Multielectron Atoms Electron Configuration: A description of which orbitals are occupied by electrons Degenerate Orbitals: Orbitals that have the same energy level. For example, the three p orbitals in a given subshell Ground-State Electron Configuration: The lowest-energy configuration Aufbau Principle ( building up ): A guide for determining the filling order of orbitals 2012 Pearson Education, Inc. Chapter 5/6
7 Ruls for Electron Configurations of Multielectron Atoms Rules of the aufbau principle: 1. Lower-energy orbitals fill before higher-energy orbitals. 2. An orbital can only hold two electrons, which must have opposite spins (Pauli exclusion principle). 3. If two or more degenerate orbitals are available, follow Hund s rule. Hund s Rule: If two or more orbitals with the same energy are available, one electron goes into each until all are halffull. The electrons in the half-filled orbitals all have the same value of their spin quantum number Pearson Education, Inc. Chapter 5/7
8 Electron Configurations of Multielectron Atoms Electron Configuration H: 1s1 1 electron s orbital (l = 0) n= Pearson Education, Inc. Chapter 5/8
9 Electron Configurations of Multielectron Atoms Electron Configuration H: 1s1 He: 1s2 2 electrons s orbital (l = 0) n= Pearson Education, Inc. Chapter 5/9
10 Electron Configurations of Multielectron Atoms Electron Configuration H: He: Li: 1s1 1s2 Lowest energy to highest energy 1s2 2s1 1 electron s orbital (l = 0) n= Pearson Education, Inc. Chapter 5/10
11 Electron Configurations of Multielectron Atoms Electron Configuration H: 1s1 He: 1s2 Li: 1s2 2s1 N: 1s2 2s2 2p3 3 electrons p orbital (l = 1) n= Pearson Education, Inc. Chapter 5/11
12 Orbital Diagrams As protons are added one by one to the nucleus to build up the elements, electrons are similarly added to these hydrogen-like orbitals. Each box represents one orbital. Half-arrows represent the electrons. The direction of the arrow represents the spin of the electron. H : 1s1, He : 1s2, Li : 1s2 2s1, Be : 1s2 2s2 B : 1s2 2s2 2p1, C : 1s2 2s2 2p2.
13 Electron Configurations of Multielectron Atoms Hund s Rule For degenerate orbitals, the lowest energy is attained when the number of electrons with the same spin is maximized. N : 1s2 2s2 2p3, O : 1s2 2s2 2p4, F : 1s2 2s2 2p5, Ne : 1s2 2s2 2p6, Na : 1s2 2s2 2p63s1 OR [Ne] 3s1
14 Electron Configurations of Multielectron Atoms Electron Configuration H: Orbital-Filling Diagram 1s1 1s He: 1s2 Li: 1s2 2s1 N: 1s2 2s2 2p Pearson Education, Inc. Chapter 5/14
15 Electron Configurations of Multielectron Atoms Electron Configuration H: Orbital-Filling Diagram 1s1 1s He: 1s2 1s Li: 1s2 2s1 N: 1s2 2s2 2p Pearson Education, Inc. Chapter 5/15
16 Electron Configurations of Multielectron Atoms Electron Configuration H: Orbital-Filling Diagram 1s1 1s He: 1s2 1s Li: 1s2 2s1 N: 1s2 2s2 2p3 1s 2s 2012 Pearson Education, Inc. Chapter 5/16
17 Electron Configurations of Multielectron Atoms Electron Configuration H: Orbital-Filling Diagram 1s1 1s He: 1s2 1s Li: 1s2 2s1 N: 1s2 2s2 2p3 1s 2s 1s 2s 2012 Pearson Education, Inc. 2p Chapter 5/17
18 Element Lithium Configuration notation Orbital notation 1s22s1 [He]2s1 1s Beryllium 2p [He]2s2 2s 2p 1s22s2p1 [He]2s2p1 1s Carbon 1s22s2p2 Nitrogen 1s22s2p3 Oxygen 1s22s2p4 Fluorine 1s22s2p5 2s 2p [He]2s2p2 1s 2s 2p [He]2s2p3 1s 2s 2p [He]2s2p4 1s 2s 2p [He]2s2p5 1s Neon 2s 1s22s2 1s Boron Noble gas notation 2s 2p 1s22s2p6 [He]2s2p6 1s 2s 2p
19 Electron Configurations of Multielectron Atoms Na: Electron Configuration Shorthand Configuration 1s2 2s2 2p6 3s1 [Ne] 3s1 Ne configuration P: 1s2 2s2 2p6 3s2 3p3 [Ne] 3s2 3p3 Ne configuration K: [Ar] 4s1 1s2 2s2 2p6 3s2 3p6 4s1 Ar configuration Sc: 1s2 2s2 2p6 3s2 3p6 4s2 3d1 Ar configuration [Ar] 4s2 3d1 Valence Shell: Outermost shell electrons.
20 Example 8.1 Electron Configurations Write electron configurations for each element. a. Mg b. P c. Br d. Al Solution a. Mg Magnesium has 12 electrons. Distribute 2 of these into the 1 s orbital, 2 into the 2s orbital, 6 into the 2p orbitals, and 2 into the 3s orbital. Mg 1s2 2s2 2p6 3s2 or [Ne] 3s2 b. P Phosphorus has 15 electrons. Distribute 2 of these into the 1s orbital, 2 into the 2s orbital, 6 into the 2p orbitals, 2 into the 3s orbital, and 3 into the 3p orbitals. P 1s2 2s2 2p6 3s2 3p3 or [Ne] 3s2 3p3 c. Br Bromine has 35 electrons. Distribute 2 of these into the 1s orbital, 2 into the 2s orbital, 6 into the 2p orbitals, 2 into the 3s orbital, 6 into the 3p orbitals, 2 into the 4s orbital, 10 into the 3d orbitals, and 5 into the 4p orbitals. Br 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 or [Ar] 4s2 3d10 4p5 d. Al Aluminum has 13 electrons. Distribute 2 of these into the 1s orbital, 2 into the 2s orbital, 6 into the 2p orbitals, 2 into the 3s orbital, and 1 into the 3p orbital. Al 1s2 2s2 2p6 3s2 3p1 or [Ne] 3s2 3p1 Chemistry: A Molecular Approach, 3rd Edition Nivaldo J. Tro 2014 Pearson Education, Inc.
21 Example 8.2 Writing Orbital Diagrams Write the orbital diagram for sulfur and determine the number of unpaired electrons. Solution Since sulfur s atomic number is 16, it has 16 electrons and the electron configuration 1s2 2s2 2p6 3s2 3p4. Draw a box for each orbital, putting the lowest energy orbital (1s) on the far left and proceeding to orbitals of higher energy to the right. Distribute the 16 electrons into the boxes representing the orbitals, allowing a maximum of 2 electrons per orbital and remembering Hund s rule. You can see from the diagram that sulfur has two unpaired electrons. Two unpaired electrons Chemistry: A Molecular Approach, 3rd Edition Nivaldo J. Tro 2014 Pearson Education, Inc.
22 Valence Electrons The electrons in the outermost principle quantum level of an atom. Atom Valence Electrons Ca 2 N 5 Br 7 Valence electron is the most important electrons to us because they are involved in bonding. Elements with the same valence electron configuration show similar chemical behavior. Inner electrons are called core electrons.
23 Electron Configurations and the Periodic Table Valence Shell: Outermost shell electrons. Li: 2s1 Na: 3s1 Cl: 3s2 3p5 Br: 4s2 4p Pearson Education, Inc. Chapter 5/23
24 Electron Configurations and the Periodic Table
25 Example 8.3 Valence Electrons and Core Electrons Write the electron configuration for Ge. Identify the valence electrons and the core electrons. Solution Write the electron configuration for Ge by determining the total number of electrons from germanium s atomic number (32) and then distributing them into the appropriate orbitals. Ge 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 sodium 1s22s22p63s1 iron 1s22s22p63s23p64s23d6 bromine 1s22s22p63s23p64s23d104p5 barium Chemistry: A Molecular Approach, 3rd Edition Nivaldo J. Tro 1s22s22p63s23p64s23d104p65s24d105p66s Pearson Education, Inc.
26 Irregular Electron Configurations There are a few exceptions to the building-up order prediction for the ground state. Chromium (Z=24) and copper (Z=29) have been found by experiment to have the following ground-state electron configurations: Expected Cr = [Ar]4s23d4 Cu = [Ar]4s23d9 Found experimentally Cr = [Ar]4s13d5 Cu = [Ar]4s13d10 When it does this it becomes either a half fullshell (Cr) or a full one (Cu) this results in a more stable compound with lower energy. It only works if by removing and one electron from the s subshell an a half full or full subshell results Pearson Education, Inc.
27 H He Li Be B C N O F Ne Na Mg Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn 1s1 ELECTRONIC 1s2 CONFIGURATIONS 1s2 2s1 OF ELEMENTS s2 2s2 1s2 2s2 2p1 1s2 2s2 2p2 1s2 2s2 2p3 1s2 2s2 2p4 1s2 2s2 2p5 1s2 2s2 2p6 1s2 2s2 2p6 3s1 1s2 2s2 2p6 3s2 1s2 2s2 2p6 3s2 3p1 1s2 2s2 2p6 3s2 3p2 1s2 2s2 2p6 3s2 3p3 1s2 2s2 2p6 3s2 3p4 1s2 2s2 2p6 3s2 3p5 1s2 2s2 2p6 3s2 3p6 1s2 2s2 2p6 3s2 3p6 4s1 1s2 2s2 2p6 3s2 3p6 4s2 1s2 2s2 2p6 3s2 3p6 4s2 3d1 1s2 2s2 2p6 3s2 3p6 4s2 3d2 1s2 2s2 2p6 3s2 3p6 4s2 3d3 1s2 2s2 2p6 3s2 3p6 4s1 3d5 1s2 2s2 2p6 3s2 3p6 4s2 3d5 1s2 2s2 2p6 3s2 3p6 4s2 3d6 1s2 2s2 2p6 3s2 3p6 4s2 3d7 1s2 2s2 2p6 3s2 3p6 4s2 3d8 1s2 2s2 2p6 3s2 3p6 4s1 3d10 1s2 2s2 2p6 3s2 3p6 4s2 3d10
28 H He Li Be B C N O F Ne Na Mg Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn 1s1 ELECTRONIC 1s2 CONFIGURATIONS 1s2 2s1 OF ELEMENTS s2 2s2 1s2 2s2 2p1 1s2 2s2 2p2 1s2 2s2 2p3 1s2 2s2 2p4 1s2 2s2 2p5 1s2 2s2 2p6 1s2 2s2 2p6 3s1 1s2 2s2 2p6 3s2 1s2 2s2 2p6 3s2 3p1 1s2 2s2 2p6 3s2 3p2 1s2 2s2 2p6 3s2 3p3 1s2 2s2 2p6 3s2 3p4 1s2 2s2 2p6 3s2 3p5 1s2 2s2 2p6 3s2 3p6 1s2 2s2 2p6 3s2 3p6 4s1 1s2 2s2 2p6 3s2 3p6 4s2 1s2 2s2 2p6 3s2 3p6 4s2 3d1 1s2 2s2 2p6 3s2 3p6 4s2 3d2 1s2 2s2 2p6 3s2 3p6 4s2 3d3 1s2 2s2 2p6 3s2 3p6 4s1 3d5 1s2 2s2 2p6 3s2 3p6 4s2 3d5 1s2 2s2 2p6 3s2 3p6 4s2 3d6 1s2 2s2 2p6 3s2 3p6 4s2 3d7 1s2 2s2 2p6 3s2 3p6 4s2 3d8 1s2 2s2 2p6 3s2 3p6 4s1 3d10 1s2 2s2 2p6 3s2 3p6 4s2 3d10
29 Properties and Electron Configuration
30 Exam 5 11/20/13 Ch 8/9/10 45 Multiple choices only from ch8-10 review worksheet. Total points = 135 bank you scores Chem 101 Course Project 15 % Actual Grade ; returned by 12/02/13 3:00pm Password : DSUCHEM101 12/02 week 3 lectures for Course Project Review Please do show up attendance recommended/ required. 12/09/13 ACS exam Monday 3:30pm 5:30 pm- No Make up exam Need to inform chair 20% Actual Grade Chem 101 Student Online Course Evaluations Office hours: M 3:00-4:00 pm, T: 4:00-4:00 pm; W:3:00-4:00 pm Attendance and class participation Online HW Exams (5 exams) Course Project(11/04/13-12/02/13) ACS exam (comprehensive) 10%(5% from Lecture +5 % from Recitation) 13% 42% 15% 20% 100%
31 Element Lithium Configuration notation Orbital notation 1s22s1 [He]2s1 1s Beryllium 2p [He]2s2 2s 2p 1s22s2p1 [He]2s2p1 1s Carbon 1s22s2p2 Nitrogen 1s22s2p3 Oxygen 1s22s2p4 Fluorine 1s22s2p5 2s 2p [He]2s2p2 1s 2s 2p [He]2s2p3 1s 2s 2p [He]2s2p4 1s 2s 2p [He]2s2p5 1s Neon 2s 1s22s2 1s Boron Noble gas notation 2s 2p 1s22s2p6 [He]2s2p6 1s 2s 2p
32 ELECTRONIC CONFIGURATION OF IONS Positive ions (cations) are formed by removing electrons from atoms Negative ions (anions) are formed by adding electrons to atoms Electrons are removed first from the highest occupied orbitals (EXC. transition metals) SODIUM CHLORINE Na 1s2 2s2 2p6 3s1 Na+ 1s2 2s2 2p6 Cl 1s2 2s2 2p6 3s2 3p5 Cl 1s2 2s2 2p6 3s2 3p6 Group 1a atom: [Noble gas] ns1 1 electron removed from the 3s orbital 1 electron added to the 3p orbital -1 egroup 1a ion+: [Noble gas] Group 2a atom: [Noble gas] ns2-2 egroup 2a ion2+: [Noble gas]
33 Positive ions (cations) are formed by removing electrons from atoms Negative ions (anions) are formed by adding electrons to atoms Electrons are removed first from the highest occupied orbitals (EXC. transition metals) SODIUM CHLORINE Na 1s2 2s2 2p6 3s1 Na+ 1s2 2s2 2p6 Cl 1s2 2s2 2p6 3s2 3p5 Cl 1s2 2s2 2p6 3s2 3p6 1 electron removed from the 3s orbital 1 electron added to the 3p orbital Group 6a atom: [Noble gas] ns2 np4 +2 e- Group 6a ion2-: [Noble gas] ns2 np6 Group 7a atom: [Noble gas] ns2 np5 +1 e- Group 7a ion-: [Noble gas] ns2 np6 Chapter 6/ Pearson Education, Inc.
34 Electron Configurations of Ions Positive ions (cations) are formed by removing electrons from atoms Negative ions (anions) are formed by adding electrons to atoms Electrons are removed first from the highest occupied orbitals (EXC. transition metals) Atoms Ions Fe: [Ar] 4s2 3d6-2 e- Fe2+: [Ar] 3d6 Fe: [Ar] 4s2 3d6-3 e- Fe3+: [Ar] 3d5 FIRST ROW TRANSITION METALS Despite being of lower energy and being filled first, electrons in the 4s orbital are removed before any electrons in the 3d orbitals. TITANIUM Ti Ti+ Ti2+ Ti3+ Ti4+ 1s2 2s2 2p6 3s2 3p6 4s2 3d2 1s2 2s2 2p6 3s2 3p6 4s1 3d2 1s2 2s2 2p6 3s2 3p6 3d2 1s2 2s2 2p6 3s2 3p6 3d1 1s2 2s2 2p6 3s2 3p6
35 Electron Configurations of Transition Metal Cations in Their Ground State When transition metals form cations, the first electrons removed are the valence electrons, even though other electrons were added after. Electrons may also be removed from the sublevel closest to the valence shell after the valence electrons. The iron atom has two valence electrons: Fe atom = 1s22s22p63s23p64s23d6 When iron forms a cation, it first loses its valence electrons: Fe2+ cation = 1s22s22p63s23p63d6 It can then lose 3d electrons: Fe3+ cation = 1s22s22p63s23p63d Pearson Education, Inc.
36 Octet Rule Octet rule: Main-group elements tend to undergo reactions that leave them with eight outer-shell electrons. That is, main-group elements react so that they attain a noble-gas electron configuration with filled s and p sublevels in their valence electron shell. An octet means 8 valence electrons. is associated with the stability of the noble gases. Exception: Helium (He) is stable with 2 valence electrons. Electron level arrangement He 2 valence electrons 2 Ne 2, 8 8 Ar 2, 8, 8 8 Kr 2, 8, 18,
37 Metals Form Positive Ions Metals form positive ions by a loss of their valence electrons. with the electron configuration of the nearest noble gas. that have fewer electrons than protons. Group 1A metals ion 1+ Group 2A metals ion 2+ Group 3A metals ion 3+ Copyright 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings 37
38 Formation of a Sodium Ion, Na+ Sodium achieves an octet by losing its one valence electron. 2, 8, 1 2, 8 38 Copyright 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings
39 Learning Check - Aluminum A. The number of valence electrons in aluminum is 1) 1e-. 2) 2e-. 3) 3e-. B. The change in electrons for octet requires a 1) loss of 3e-. 2) gain of 3e-. 3) a gain of 5e-. C. The ionic charge of aluminum is 1) 3-. 2) 5-. 3) 3+. D. The symbol for the aluminum ion is 1) Al3+. 2) Al3-. 3) Al+. 39
40 Formation of Negative Ions In ionic compounds, nonmetals achieve an octet arrangement. gain electrons. form negatively charged ions with 3-, 2-, or 1charges. 40
41 Formation of a Chloride, ClChlorine achieves an octet by adding an electron to its valence electrons. 2, 8, 7 2, 8, 8 Copyright 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings 41
42 Electron Configurations of Ions Matching Oxidation Number Chapter 6/ Pearson Education, Inc.
43
44 Example 8.6 Electron Configurations and Magnetic Properties for Ions Write the electron configuration and orbital diagram for each ion and determine whether each is diamagnetic or paramagnetic. a. Al3+ b. S2 c. Fe3+ Solution a. Al3+ Begin by writing the electron configuration of the neutral atom. Since this ion has a 3+ charge, remove three electrons to write the electron configuration of the ion. Write the orbital diagram by drawing half-arrows to represent each electron in boxes representing the orbitals. Because there are no unpaired electrons, Al3+ is diamagnetic. Al Al3+ [Ne] 3s2 3p1 [Ne] or [He] 2s2 2p6 Diamagnetic Continued b. S2 Write the orbital diagram by drawing half-arrows to represent each electron in boxes representing the orbitals. Because there are no unpaired electrons, S2 is diamagnetic. S S2 [Ne] 3s2 3p4 [Ne] 3s2 3p6 Chemistry: A Molecular Approach, 3rd Edition Nivaldo J. Tro Diamagnetic 2014 Pearson Education, Inc.
45 Example 8.6 Electron Configurations and Magnetic Properties for Ions Continued c. Fe3+ Begin by writing the electron configuration of the neutral atom. Since this ion has a 3+ charge, remove three electrons to write the electron configuration of the ion. Since it is a transition metal, remove the electrons from the 4s orbital before removing electrons from the 3d orbitals. Write the orbital diagram by drawing halfarrows to represent each electron in boxes representing the orbitals. There are unpaired electrons, so Fe3+ is paramagnetic. Fe Fe3+ [Ar] 4s2 3d6 [Ar] 4s0 3d5 Paramagnetic Chemistry: A Molecular Approach, 3rd Edition Nivaldo J. Tro 2014 Pearson Education, Inc.
46 Chapter 8. Periodic Properties of the Element Modified by Dr. Cheng-Yu Lai
47 1. Atomic Radius Definition: Half of the distance between nuclei in covalently bonded diatomic molecule Radius decreases across a period Increased effective nuclear charge due to decreased shielding Radius increases down a group Each row on the periodic table adds a shell or energy level to the atom
48 Table of Atomic Radii
49 Cation Formation Effective nuclear charge on remaining electrons increases. Na atom 1 valence electron 11p+ Valence elost in ion formation Result: a smaller sodium cation, Na+ Remaining e- are pulled in closer to the nucleus. Ionic size decreases.
50 Anion Formation Chlorine atom with 7 valence e17p+ One e- is added to the outer shell. Effective nuclear charge is reduced and the e- cloud expands. A chloride ion is produced. It is larger than the original atom.
51 Ionic Radii
52 Isoelectronic = same electron configuration
53 2. Ionization Energy Ionization Energy (Ei): The amount of energy necessary to remove the highest-energy electron from an isolated neutral atom in the gaseous state The energy required is called the first ionization energy. X(g) + energy X+ + e 2012 Pearson Education, Inc. Chapter 6/53
54 Ionization Energy The energy required to remove an electron from an atom is ionization energy. (measured in kilojoules, kj) The energy required is called the first ionization energy. X(g) + energy X+ + e- The larger the atom is, the easier its electrons are to remove. Ionization energy and atomic radius are inversely proportional. Ionization energy is always endothermic, that is energy is added to the atom to remove the electron. Chemistry: A Molecular Approach, 3rd Edition Nivaldo J. Tro 2014 Pearson Education, Inc.
55 Higher Ionization Energies M + energy M+ + e - M+ + energy M2+ + e- M2+ + energy M3+ + e- # OF VALENCE LECTRONS 2S1 2S2 2S3 2S4 2S5 2S6 2S7 2S8
56 Ionization Energy
57 Worked Example 6.2 Higher Ionization Energies Instructor Resource DVD for Chemistry, 6th Edition John McMurry & Robert C. Fay 2012 Pearson Education, Inc.
58 3. Electron Affinity - EA Energy is released when an neutral atom gains an electron. Gas state M(g) + 1e M1 (g) + EA Electron affinity is defined as exothermic ( ), The more energy that is released, the larger the electron affinity. The more negative the number, the larger the EA Pearson Education, Inc.
59 Electron Affinity Definition - the energy change associated with the addition of an electron Affinity tends to increase across a period Affinity tends to decrease as you go down in a period Electrons farther from the nucleus experience less nuclear attraction Some irregularities due to repulsive forces in the relatively small p orbitals
60 Electron Affinity Definition - the energy change associated with the addition of an electron
61 4. Metallic Character Metallic character is how closely an element s properties match the ideal properties of a metal. More malleable and ductile, better conductors, and easier to ionize Metallic character decreases left to right across a period. Metals found at the left of the period and nonmetals to the right Metallic character increases down the column. Nonmetals found at the top of the middle main group elements and metals found at the bottom 2014 Pearson Education, Inc.
62 Metallic Character in the Periodic Table
63 5. Electronegativity Electronegativity is a measure of an atom s attraction for another atom s electrons. It is an arbitrary scale that ranges from 0 to 4. The units of electronegativity are Paulings. Generally, metals are electron givers and have low electronegativities. Nonmetals are are electron takers and have high electronegativities.
64 The electron affinity is to attract any electron. The electronegativity is to attract the electrons in a covalent bond between that atom and another.
65 Summary of Trends
6.5 Periodic Variations in Element Properties
324 Chapter 6 Electronic Structure and Periodic Properties of Elements 6.5 Periodic Variations in Element Properties By the end of this section, you will be able to: Describe and explain the observed trends
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