4-1 Right Triangle Trigonometry

Size: px
Start display at page:

Download "4-1 Right Triangle Trigonometry"

Transcription

1 Find the exact values of the six trigonometric functions of θ 1 The length of the side opposite θ is 8 is 18, the length of the side adjacent to θ is 14, and the length of the hypotenuse 2 The length of the side opposite θ is 2 hypotenuse is 15 3, the length of the side adjacent to θ is 13, and the length of the Page 1

2 3 The length of the side opposite θ is 9, the length of the side adjacent to θ is 4, and the length of the hypotenuse is 4 The length of the side opposite θ is 12, the length of the side adjacent to θ is 35, and the length of the hypotenuse is 37 5 esolutions Manual - Powered by Cognero The length of the side opposite hypotenuse is 29 θ is, the length of the side adjacent to θ is 26, and the length of the Page 2

3 5 The length of the side opposite θ is hypotenuse is 29, the length of the side adjacent to θ is 26, and the length of the 6 The length of the side opposite θ is 30, the length of the side adjacent to θ is 5 hypotenuse is 35 esolutions 7 Manual - Powered by Cognero, and the length of the Page 3

4 7 The length of the side opposite θ is 6 and the length of the hypotenuse is 10 By the Pythagorean Theorem, the length of the side adjacent to θis = or8 8 The length of the side opposite θ is 8 and the length of the side adjacent to θ is 32 By the Pythagorean Theorem, the length of the hypotenuse is = or8 Use the given trigonometric function value of the acute angle θto find the exact values of the five remaining trigonometric function values of θ esolutions 9sinManual θ= - Powered by Cognero Page 4

5 Use the given trigonometric function value of the acute angle θto find the exact values of the five remaining trigonometric function values of θ 9sin θ= Draw a right triangle and label one acute angle θ Because sin θ= =, label the opposite side 4 and the hypotenuse 5 By the Pythagorean Theorem, the length of the side adjacent to θ is or3 10cos θ= Draw a right triangle and label one acute angle θ Because cos θ= =, label the adjacent side 6 and the hypotenuse 7 By the Pythagorean Theorem, the length of the side opposite θ is or Page 5

6 10cos θ= Draw a right triangle and label one acute angle θ Because cos θ= =, label the adjacent side 6 and the hypotenuse 7 By the Pythagorean Theorem, the length of the side opposite θ is or 11tan θ=3 Draw a right triangle and label one acute angle θ Because tan θ=, label the side opposite θ 3 and =3 or the adjacent side 1 By the Pythagorean Theorem, the length of the hypotenuse is or Page 6

7 11tan θ=3 Draw a right triangle and label one acute angle θ Because tan θ=, label the side opposite θ 3 and =3 or the adjacent side 1 By the Pythagorean Theorem, the length of the hypotenuse is or 12sec θ=8 Draw a right triangle and label one acute angle θ Because sec θ= =8or, label the hypotenuse 8 and the adjacent side 1 By the Pythagorean Theorem, the length of the side adjacent to θ is = or3 Page 7

8 12sec θ=8 Draw a right triangle and label one acute angle θ Because sec θ= =8or, label the hypotenuse 8 and the adjacent side 1 By the Pythagorean Theorem, the length of the side adjacent to θ is = or3 13cos θ= Draw a right triangle and label one acute angle θ Because cos θ= =, label the adjacent side 5 and the hypotenuse 9 By the Pythagorean Theorem, the length of the side opposite θ is or2 Page 8

9 13cos θ= Draw a right triangle and label one acute angle θ Because cos θ= =, label the adjacent side 5 and the hypotenuse 9 By the Pythagorean Theorem, the length of the side opposite θ is or2 14tan θ= Draw a right triangle and label one acute angle θ Because tan θ= =, label the side opposite θ 5 and adjacent side 4 By the Pythagorean Theorem, the length of the hypotenuse is or Page 9

10 14tan θ= Draw a right triangle and label one acute angle θ Because tan θ= =, label the side opposite θ 5 and adjacent side 4 By the Pythagorean Theorem, the length of the hypotenuse is or 15cot θ=5 Draw a right triangle and label one acute angle θ Because cot θ=,labelthesideadjacentto θ as =5 or 5 and the opposite side 1 By the Pythagorean Theorem, the length of the hypotenuse is or 16csc θ=6 esolutions Manual - Powered by Cognero Draw a right triangle and label one acute angle θ Because csc θ = Page 10 =6 or, label the hypotenuse 6 and the

11 16csc θ=6 Draw a right triangle and label one acute angle θ Because csc θ = =6 or, label the hypotenuse 6 and the side opposite θ as 1 By the Pythagorean Theorem, the length of the adjacent side is or 17sec θ= Draw a right triangle and label one acute angle θ Because sec θ= =, label the hypotenuse 9 and the side opposite θ as 2 By the Pythagorean Theorem, the length of the opposite side is or Page 11

12 17sec θ= Draw a right triangle and label one acute angle θ Because sec θ= =, label the hypotenuse 9 and the side opposite θ as 2 By the Pythagorean Theorem, the length of the opposite side is or 18sin θ= Draw a right triangle and label one acute angle θ Because sin θ= =, label the side opposite θ as 8 and the hypotenuse 13 By the Pythagorean Theorem, the length of the adjacent side is or Page 12

13 18sin θ= Draw a right triangle and label one acute angle θ Because sin θ= =, label the side opposite θ as 8 and the hypotenuse 13 By the Pythagorean Theorem, the length of the adjacent side is or Find the value of x Round to the nearest tenth 19 An acute angle measure and the length of the hypotenuse are given, so the sine function can be used to find the length of the side opposite θ 20 An acute angle measure and the length of the side opposite θ are given, so the tangent function can be used to find themanual length- Powered of the side adjacent to θ esolutions by Cognero Page 13

14 20 An acute angle measure and the length of the side opposite θ are given, so the tangent function can be used to find the length of the side adjacent to θ 21 An acute angle measure and the length of the hypotenuse are given, so the cosine function can be used to find the length of the side adjacent to θ 22 An acute angle measure and the length of the side adjacent to θ are given, so the cosine function can be used to find the length of the hypotenuse 23 Manual - Powered by Cognero esolutions Page 14

15 23 An acute angle measure and the length of the side opposite θ are given, so the sine function can be used to find the length of the hypotenuse 24 An acute angle measure and the length of the side adjacent to θ are given, so the tangent function can be used to find the length of the side opposite θ 25 An acute angle measure and the length of the side opposite θ are given, so the tangent function can be used to find the length of the side adjacent to θ esolutions 26 Manual - Powered by Cognero Page 15

16 26 An acute angle measure and the length of the side opposite θ are given, so the sine function can be used to find the length of the hypotenuse 27MOUNTAIN CLIMBINGAteamofclimbersmustdeterminethewidthofaravineinordertosetup equipment to cross it If the climbers walk 25 feet along the ravine from their crossing point, and sight the crossing point on the far side of the ravine to be at a 35º angle, how wide is the ravine? An acute angle measure and the adjacent side length are given, so the tangent function can be used to find the length of the opposite side Therefore, the ravine is about 175 feet wide 28SNOWBOARDINGBradbuiltasnowboardingrampwithaheightof35feetandan18º incline a Draw a diagram to represent the situation b Determine the length of the ramp a Draw a diagram of a right triangle and label one acute angle 18º and the opposite side 35 feet b Because an acute angle measure and opposite side length are given, the sine function can be used to find the Page 16 length of the hypotenuse

17 Therefore, the ravine is about 175 feet wide 28SNOWBOARDINGBradbuiltasnowboardingrampwithaheightof35feetandan18º incline a Draw a diagram to represent the situation b Determine the length of the ramp a Draw a diagram of a right triangle and label one acute angle 18º and the opposite side 35 feet b Because an acute angle measure and opposite side length are given, the sine function can be used to find the length of the hypotenuse Therefore, the length of the ramp is about 113 feet 29DETOURTrafficisdetouredfromElwoodAve,left08mileonMapleSt,andthenrightonOakSt,which intersectselwoodaveata32 angle a Draw a diagram to represent the situation b Determine the length of Elwood Ave that is detoured a Draw a right triangle with acute angle 32º and opposite side length 08 mile Label the side opposite the 32º angle Maple St, the hypotenuse Oak St, and the adjacent side Elwood Ave b Because an acute angle and the length of opposite side are given, the tangent function can be used to find the adjacent side length esolutions Manual - Powered by Cognero Therefore, the length of Elwood Ave that is detoured is about 13 miles Page 17 30PARACHUTINGAparatrooperencountersstrongerwindsthananticipatedwhileparachutingfrom1350feet,

18 Therefore, the length of the ramp is about 113 feet 29DETOURTrafficisdetouredfromElwoodAve,left08mileonMapleSt,andthenrightonOakSt,which intersectselwoodaveata32 angle a Draw a diagram to represent the situation b Determine the length of Elwood Ave that is detoured a Draw a right triangle with acute angle 32º and opposite side length 08 mile Label the side opposite the 32º angle Maple St, the hypotenuse Oak St, and the adjacent side Elwood Ave b Because an acute angle and the length of opposite side are given, the tangent function can be used to find the adjacent side length Therefore, the length of Elwood Ave that is detoured is about 13 miles 30PARACHUTINGAparatrooperencountersstrongerwindsthananticipatedwhileparachutingfrom1350feet, causing him to drift at an 8º angle How far from the drop zone will the paratrooper land? Because an acute angle and the length of the side that is adjacent to the angle are given, the tangent function can be used to find the length of the opposite side So,Manual the paratrooper land esolutions - Powered bywill Cognero about 190 feet away from the drop zone Find the measure of angle θ Round to the nearest degree, if necessary Page 18

19 Therefore, the length of Elwood Ave that is detoured is about 13 miles 30PARACHUTINGAparatrooperencountersstrongerwindsthananticipatedwhileparachutingfrom1350feet, causing him to drift at an 8º angle How far from the drop zone will the paratrooper land? Because an acute angle and the length of the side that is adjacent to the angle are given, the tangent function can be used to find the length of the opposite side So, the paratrooper will land about 190 feet away from the drop zone Find the measure of angle θ Round to the nearest degree, if necessary 31 Because the lengths of the sides opposite and adjacent to θ are given, the tangent function can be used to find θ 32 Because the length of the hypotenuse and side adjacent to θare given, the cosine function can be used to find θ Page 19

20 32 Because the length of the hypotenuse and side adjacent to θare given, the cosine function can be used to find θ 33 Because the length of the hypotenuse and side opposite θare given, the sine function can be used to find θ 34 Because the lengths of the sides opposite and adjacent to θare given, the tangent function can be used to find θ 35 Because the lengths of the sides opposite and adjacent to θare given, the tangent function can be used to find θ Page 20

21 35 Because the lengths of the sides opposite and adjacent to θare given, the tangent function can be used to find θ 36 Because the length of the hypotenuse and side adjacent to θare given, the cosine function can be used to find θ 37 Because the length of the hypotenuse and side opposite θare given, the sine function can be used to find θ 38 Because the lengths of the sides opposite and adjacent to θare given, the tangent function can be used to find θ Page 21

22 38 Because the lengths of the sides opposite and adjacent to θare given, the tangent function can be used to find θ 39PARASAILING KayladecidedtotryparasailingShewasstrappedintoaparachutetowedbyaboatAn800foot line connected her parachute to the boat, which was at a 32º angle of depression below her How high above the water was Kayla? The angle of elevation from the boat to the parachute is equivalent to the angle of depression from the parachute to the boat because the two angles are alternate interior angles, as shown below Because an acute angle and the hypotenuse are given, the sine function can be used to find x Therefore, Kayla was about 424 feet above the water 40OBSERVATION WHEEL TheLondonEyeisa135-meter-tall observation wheel If a passenger at the top of the wheel sights the London Aquarium at a 58º angle of depression, what is the distance between the aquarium and the London Eye? The angle of depression from the top of the wheel to the aquarium is 58º, which means that the angle of elevation from the aquarium to the top of the wheel is also 58º because they are alternate interior angles Draw a diagram of Page 22 a right triangle and label one acute angle 58º and the opposite side 135 m

23 Therefore, Kayla was about 424 feet above the water 40OBSERVATION WHEEL TheLondonEyeisa135-meter-tall observation wheel If a passenger at the top of the wheel sights the London Aquarium at a 58º angle of depression, what is the distance between the aquarium and the London Eye? The angle of depression from the top of the wheel to the aquarium is 58º, which means that the angle of elevation from the aquarium to the top of the wheel is also 58º because they are alternate interior angles Draw a diagram of a right triangle and label one acute angle 58º and the opposite side 135 m Because an acute angle and the side length opposite the angle are given, the tangent function can be used to find x Therefore, the distance between the aquarium and the London Eye is about 84 meters 41ROLLER COASTER Onarollercoaster,375feetoftrackascendata55º angle of elevation to the top before the first and highest drop a Draw a diagram to represent the situation b Determine the height of the roller coaster a Draw a diagram of a right triangle and label one acute angle 55º and the hypotenuse 375 feet b Because an acute angle and the length of the hypotenuse are given, you can use the sine function to find the length of the opposite side Page 23

24 Therefore, the distance between the aquarium and the London Eye is about 84 meters 41ROLLER COASTER Onarollercoaster,375feetoftrackascendata55º angle of elevation to the top before the first and highest drop a Draw a diagram to represent the situation b Determine the height of the roller coaster a Draw a diagram of a right triangle and label one acute angle 55º and the hypotenuse 375 feet b Because an acute angle and the length of the hypotenuse are given, you can use the sine function to find the length of the opposite side Therefore, the height of the roller coaster is about 307 feet 42SKI LIFTAcompanyisinstallinganewskiliftona225-meter-high mountain that will ascend at a 48º angle of elevation a Draw a diagram to represent the situation b Determine the length of cable the lift requires to extend from the base to the peak of the mountain a Draw a diagram of a right triangle and label one acute angle 48º and the opposite side 225 meters b Because an acute angle and the length of the side opposite the angle are given, you can use the sine function to find the length of the hypotenuse So, the company will need about 303 meters of cable esolutions Manual - Powered BothDerekandSamare5feet10inchestallDereklooksata10-foot by Cognero 43BASKETBALL basketball goal withpage an 24 angleofelevationof29,andsamlooksatthegoalwithanangleofelevationof43 IfSamisdirectlyinfrontof Derek, how far apart are the boys standing?

25 So, the company will need about 303 meters of cable 43BASKETBALLBothDerekandSamare5feet10inchestallDereklooksata10-foot basketball goal with an angleofelevationof29,andsamlooksatthegoalwithanangleofelevationof43 IfSamisdirectlyinfrontof Derek, how far apart are the boys standing? Draw a diagram to model the situation The vertical distance from the boys' heads to the rim is 10(12) [5(12) + 10] or 50 inches Label the horizontal distance between Sam and Derek as x and the horizontal distance between Sam and the goal as y From the smaller right triangle, you can use the tangent function to find y From the larger right triangle, you can use the tangent function to find x Therefore, Derek and Sam are standing about 366 inches or 31 feet apart 44PARISAtouristonthefirstobservationleveloftheEiffelTowersightstheMuséeD Orsay at a 14º angle of depressionatouristonthethirdobservationlevel,located219metersdirectlyabovethefirst,sightsthemusée D Orsay at a 68º angle of depression a Draw a diagram to represent the situation b DeterminethedistancebetweentheEiffelTowerandtheMuséeD Orsay Page 25

26 Therefore, Derek and Sam are standing about 366 inches or 31 feet apart 44PARISAtouristonthefirstobservationleveloftheEiffelTowersightstheMuséeD Orsay at a 14º angle of depressionatouristonthethirdobservationlevel,located219metersdirectlyabovethefirst,sightsthemusée D Orsay at a 68º angle of depression a Draw a diagram to represent the situation b DeterminethedistancebetweentheEiffelTowerandtheMuséeD Orsay a st rd b Because the angles of depression from the 1 and 3 levelstothemuséed Orsay are 14 and 68, st rd respectively,theanglesofelevationfromthemuséed Orsaytothe1 and 3 levels are also 14 and 68, respectively Use the tangent function to write an equation for the smaller right triangle in terms of y Next, use the tangent function to write an equation for the larger right triangle in terms of y Set the equations that you found for each triangle equal to one another and solve for x Therefore,thedistancebetweentheEiffelTowerandtheMuséeD Orsay is about 2310 meters 45LIGHTHOUSETwoshipsarespottedfromthetopofa156-foot lighthouse The first ship is at a 27º angle of depression, and the second ship is directly behind the first at a 7º angle of depression a Draw a diagram to represent the situation b Determine the distance between the two ships a Page 26

27 Therefore,thedistancebetweentheEiffelTowerandtheMuséeD Orsay is about 2310 meters 45LIGHTHOUSETwoshipsarespottedfromthetopofa156-foot lighthouse The first ship is at a 27º angle of depression, and the second ship is directly behind the first at a 7º angle of depression a Draw a diagram to represent the situation b Determine the distance between the two ships a b From the smaller right triangle, you can use the tangent function to find y From the larger right triangle, you can use the tangent fuction to find x Therefore, the distance between the two ships is about 964 feet 46MOUNT RUSHMOREThefacesofthepresidentsatMountRushmoreare60feettallAvisitorseesthetop of George Washington s head at a 48º angle of elevation and his chin at a 4476º angle of elevation Find the height of Mount Rushmore From the smaller triangle, you can use the tangent function to find y Page 27

28 Therefore, the distance between the two ships is about 964 feet 46MOUNT RUSHMOREThefacesofthepresidentsatMountRushmoreare60feettallAvisitorseesthetop of George Washington s head at a 48º angle of elevation and his chin at a 4476º angle of elevation Find the height of Mount Rushmore From the smaller triangle, you can use the tangent function to find y From the larger triangle, you can use the tangent function to find y, too Next, set the two equations equal to one another to solve for x Therefore, Mount Rushmore is about 500 feet tall Solve each triangle Round side measures to the nearest tenth and angle measures to the nearest degree 47 Use trigonometric functions to find b and c Page 28

29 Therefore, Mount Rushmore is about 500 feet tall Solve each triangle Round side measures to the nearest tenth and angle measures to the nearest degree 47 Use trigonometric functions to find b and c Because the measures of two angles are given, B can be found by subtracting A from Therefore, b 165,c Use trigonometric functions to find y and z Because the measures of two angles are given, X can be found by subtracting Z from Therefore, y 371,z Use the Pythagorean Theorem to find r Page 29

30 Because the measures of two angles are given, X can be found by subtracting Z from 4-1 Right Triangle Trigonometry Therefore, y 371,z Use the Pythagorean Theorem to find r Use the tangent function to find P Because the measures of two angles are now known, you can find Q by subtracting P from Therefore, P 43, Q 47, and r Use the Pythagorean Theorem to find d Use the cosine function to find D Because the measures of two angles are now known, you can find E by subtracting D from Therefore, D 77, E 13, and d Use trigonometric functions to find j and k Page 30

31 Because the measures of two angles are now known, you can find E by subtracting D from 4-1 Right Triangle Trigonometry Therefore, D 77, E 13, and d Use trigonometric functions to find j and k Because the measures of two angles are given, K can be found by subtracting J from Therefore, j 180,k Use the Pythagorean Theorem to find y Use the sine function to find W Because the measures of two angles are now known, you can find Y by subtracting W from Therefore, and y Use trigonometric functions to find f and h Page 31

32 Because the measures of two angles are now known, you can find Y by subtracting W from 4-1 Right Triangle Trigonometry Therefore, and y Use trigonometric functions to find f and h Because the measures of two angles are given, H can be found by subtracting F from Therefore, f 196,h Use the Pythagorean Theorem to find t Use the tangent function to find R Because the measures of two angles are now known, you can find S by subtracting R from Therefore, and t 81 55BASEBALL Michael s seat at a game is 65 feet behind home plate His line of vision is 10 feet above the field a Draw a diagram to represent the situation b What is the angle of depression to home plate? a Page 32 b Michael s angle of depression to home plate is equivalent to the angle of elevation from home plate to where he is sitting

33 Because the measures of two angles are now known, you can find S by subtracting R from 4-1 Right Triangle Trigonometry Therefore, and t 81 55BASEBALL Michael s seat at a game is 65 feet behind home plate His line of vision is 10 feet above the field a Draw a diagram to represent the situation b What is the angle of depression to home plate? a b Michael s angle of depression to home plate is equivalent to the angle of elevation from home plate to where he is sitting Use the tangent function to find θ Therefore, the angle of depression to home plate is about 56HIKING Jessica is standing 2 miles from the center of the base of Pikes Peak, and looking at the summit of the mountain, which is 14 miles from the base a Draw a diagram to represent the situation b With what angle of elevation is Jessica looking at the summit of the mountain? a b Use the tangent function to find the angle of elevation Therefore, the angle of elevation is about Find the exact value of each expression without using a calculator 57sin 60 Draw a diagram of a 30º-60º-90º triangle Page 33

34 Therefore, the angle of elevation is about Find the exact value of each expression without using a calculator 57sin 60 Draw a diagram of a 30º-60º-90º triangle The length of the side opposite the 60 angle is x and the length of the hypotenuse is 2x 58cot30 Draw a diagram of a 30º-60º-90º triangle The length of the side adjacent to the 30º angle is x and the length of the opposite side is x 59sec30 Draw a diagram of a 30º-60º-90º triangle The length of the hypotenuse is 2x and the length of the side adjacent to the 30º angle is x Page 34

35 59sec30 Draw a diagram of a 30º-60º-90º triangle The length of the hypotenuse is 2x and the length of the side adjacent to the 30º angle is x 60cos45 Draw a diagram of a 45º-45º-90º triangle The side length is x and the hypotenuse is x 61tan60 Draw a diagram of a 30º-60º-90º triangle esolutions Manual - Powered by Cognero The length of the side opposite the 60º is x and the length of the adjacent side is x Page 35

36 61tan60 Draw a diagram of a 30º-60º-90º triangle The length of the side opposite the 60º is x and the length of the adjacent side is x 62csc45 Draw a diagram of a 45º-45º-90º triangle The length of the hypotenuse is x and the side length is x Without using a calculator, find the measure of the acute angle θ that satisfies the given equation 63tan θ = 1 Because tan θ = 1 and tan θ=, it follows that =1Inthe opposite an acute angle is 1 and the adjacent side length is also 1 So, esolutions Manual - Powered by Cognero Therefore, θ = 45 triangle below, the side length =1 Page 36

37 Without using a calculator, find the measure of the acute angle θ that satisfies the given equation 63tan θ = 1 Because tan θ = 1 and tan θ=, it follows that =1Inthe triangle below, the side length =1 opposite an acute angle is 1 and the adjacent side length is also 1 So, Therefore, θ = 45 64cos θ= Because cos θ= and cos θ= length adjacent to the 30º angle is, it follows that = and the hypotenuse is 2 So, In the = triangle below, the side Therefore, θ = 30 65cot θ = Because cot θ = and cot θ=, it follows that = In the length that is adjacent to the 60º angle is 1 and the length of the opposite side is esolutions Manual - Powered by Cognero Therefore, θ = 60 triangle below, the side So, = or Page 37

38 Therefore, θ = 30 65cot θ = Because cot θ = and cot θ=, it follows that = In the triangle below, the side length that is adjacent to the 60º angle is 1 and the length of the opposite side is = So, or Therefore, θ = 60 66sin θ= Because sin θ= and sin θ=, it follows that length opposite an acute angle is 1 and the hypotenuse is = In the So, = triangle below, the side or Therefore, θ =45 67csc θ = 2 Because csc θ = 2 and csc θ=, it follows that =2or In the hypotenuse is 2 and the side length that is opposite the 30º angle is 1 So, triangle below, the = or2 Therefore, θ =30 68sec θ = 2 Page 38

39 Therefore, θ =45 67csc θ = 2 Because csc θ = 2 and csc θ=, it follows that =2or In the hypotenuse is 2 and the side length that is opposite the 30º angle is 1 So, triangle below, the = or2 Therefore, θ =30 68sec θ = 2 Because sec θ = 2 and sec θ=, it follows that =2or In the hypotenuse is 2 and the side length that is adjacent to the 60º angle is 1 So, triangle below, the = or2 Therefore, θ = 60 Without using a calculator, determine the value of x 69 Because an acute angle, the hypotenuse, and the length of the side adjacent to the angle are given, the cosine function can be used to find x Using the properties of triangles, you can find that cos 30º = Page 39

40 Therefore, θ = 60 Without using a calculator, determine the value of x 69 Because an acute angle, the hypotenuse, and the length of the side adjacent to the angle are given, the cosine function can be used to find x Using the properties of triangles, you can find that cos 30º = 70 Because the triangle is a triangle, the legs are the same length 71SCUBA DIVINGAscubadiverlocated20feetbelowthesurfaceofthewaterspotsashipwreckata70º angle of depression After descending to a point 45 feet above the ocean floor, the diver sees the shipwreck at a 57º angle of depression Draw a diagram to represent the situation, and determine the depth of the shipwreck First, draw a diagram to represent the situation Page 40

41 71SCUBA DIVINGAscubadiverlocated20feetbelowthesurfaceofthewaterspotsashipwreckata70º angle of depression After descending to a point 45 feet above the ocean floor, the diver sees the shipwreck at a 57º angle of depression Draw a diagram to represent the situation, and determine the depth of the shipwreck First, draw a diagram to represent the situation Label the horizontal distance from the shipwreck to the point on the ocean floor below the diver as x Label the vertical distance from the point 20 feet below sea level to the point 45 feet below sea level as y Find the complementary angle for each angle of depression Use the tangent function to write an equation for the smaller right triangle in terms of x Use the tangent function to write an equation for the larger right triangle in terms of x Set the two equations equal to one another to solve for y Therefore, the depth of the shipwreck is or about 100 feet Find the value of cos θif θ is the measure of the smallest angle in each type of right triangle Draw a diagram of a triangle The smallest angle will be the angle opposite the side with a length of 3 Page 41

42 Therefore, the depth of the shipwreck is or about 100 feet Find the value of cos θif θ is the measure of the smallest angle in each type of right triangle Draw a diagram of a triangle The smallest angle will be the angle opposite the side with a length of Draw a diagram of a triangle The smallest angle will be the angle opposite the side with a length of 5 74SOLAR POWERFindthetotalareaofthepanelshownbelow The area of the panel is given by, where the width is 10 feet and the length is unknown Notice that the length of the panel is also the hypotenuse of a right triangle with an acute angle of 55º and an opposite side length of 35 feet The sine function can be used to find the hypotenuse of the triangle So, the length of the panel is 427 feet Find the area Page 42

43 74SOLAR POWERFindthetotalareaofthepanelshownbelow The area of the panel is given by, where the width is 10 feet and the length is unknown Notice that the length of the panel is also the hypotenuse of a right triangle with an acute angle of 55º and an opposite side length of 35 feet The sine function can be used to find the hypotenuse of the triangle So, the length of the panel is 427 feet Find the area Therefore, the area of the panel is 427 square feet Without using a calculator, insert the appropriate symbol >, <, or = to complete each equation 75sin45 cot60 Use a graphing calculator to find sin 45º and cot 60º To find cot 60º, find sin 45º 0707 cot 60º 0577 Therefore, sin 45º > cot 60º 76tan60 cot30 Use a graphing calculator to find tan 60º and cot 30º To find cot 30º, find tan 60º 1732 cot 30º 1732 Therefore,tan60 =cot30 77cos30 csc45 Use a graphing calculator to find cos 30º and csc 45º To find csc 45º, find cos 30º 0866 csc 45º 1414 Therefore,cos30 <csc45 78cos30 sin60 Page 43

44 Use a graphing calculator to find tan 60º and cot 30º To find cot 30º, find 4-1 tan 60º 1732 cot 30º Triangle 1732 Right Trigonometry Therefore,tan60 =cot30 77cos30 csc45 Use a graphing calculator to find cos 30º and csc 45º To find csc 45º, find cos 30º 0866 csc 45º 1414 Therefore,cos30 <csc45 78cos30 sin60 Use a graphing calculator to find cos 30º and sin 60º cos 30º 0866 sin 60º 0866 Therefore,cos30 =sin60 79sec45 csc60 sec45 csc60 Use a graphing calculator to find sec 45º and csc 60º To find sec 45ºfind, and to find csc 60ºfind sec 45º 1414 csc 60º 1155 Therefore, sec 45º > csc60 80tan45 sec30 tan45 sec30 Use a graphing calculator to find tan 45º and sec 30º To find sec 30º, find tan 45º = 1 sec 30º 1155 Therefore,tan45 <sec30 81ENGINEERINGDeterminethedepthoftheshaftatthelargeendd of the air duct shown below if the taper of the duct is 35º Draw a diagram of the side-view of the air duct Label the lengths of the top and bottom of the duct 48 in because 4 feet = 4 12 or 48 inches Page 44

45 Use a graphing calculator to find tan 45º and sec 30º To find sec 30º, find 4-1 tan 45º = 1 sec 30ºTriangle 1155 Right Trigonometry Therefore,tan45 <sec30 81ENGINEERINGDeterminethedepthoftheshaftatthelargeendd of the air duct shown below if the taper of the duct is 35º Draw a diagram of the side-view of the air duct Label the lengths of the top and bottom of the duct 48 in because 4 feet = 4 12 or 48 inches Because an acute angle and the length of the hypotenuse are given, you can use the sine function to find x Find the length of the large end of the duct Therefore, the length of the large end of the duct is about 179 inches 82MULTIPLEREPRESENTATIONSIn this problem, you will investigate trigonometric functions of acute angles and their relationship to points on the coordinate plane a GRAPHICALLetP(x, y) be a point in the first quadrant Graph the line through point P and the origin Form a right triangle by connecting the points P, (x, 0), and the origin Label the lengths of the legs of the triangle in terms of x or y Label the length of the hypotenuse as r and the angle the line makes with the x-axis θ b ANALYTICAL Express the value of r in terms of x and y c ANALYTICAL Express sin θ, cos θ, and tan θ in terms of x, y, and/or r d VERBAL Under what condition can the coordinates of point P be expressed as (cos θ, sin θ)? e ANALYTICALWhichtrigonometricratioinvolving θ corresponds to the slope of the line? f ANALYTICALFindanexpressionfortheslopeofthelineperpendiculartothelineinparta in terms of θ a Page 45

46 d VERBAL Under what condition can the coordinates of point P be expressed as (cos θ, sin θ)? e ANALYTICALWhichtrigonometricratioinvolving θ corresponds to the slope of the line? f ANALYTICALFindanexpressionfortheslopeofthelineperpendiculartothelineinparta in terms of θ 4-1 Right Triangle Trigonometry a b By the Pythagorean Theorem, x + y = r So, r = c Use the definitions of the sine, cosine, and tangent functions and the diagram from part a to find sin θ, cos θ, and tan θ d Sample answer: Because cos θ = and sin θ =, when r = 1, cos θ= or x and sin θ= or y Therefore,apointP(x, y) can be written as (cos θ, sin θ) when r = 1 e Find the slope of the line using the points (0, 0) and (x, y) From part c, Therefore, tan θ corresponds to the slope of the line ftheslopeofthelineperpendiculartoalinewithslope it follows that is the negative reciprocal or Because, Therefore, an expression for the slope of the line perpendicular to the line in part a is cot θ 83PROOF Prove that if θ is an acute angle of a right triangle, then tan θ = and cot θ = Sample answer: For an acute angle θ of a right triangle, sin θ = Using these definitions, 84ERROR esolutions Manual - ANALYSIS Powered by Cognero Jason = =,cos θ = =tan θ Similarly,, tan θ = = =,and cot θ = =cot θ and Nadina know the value of sin θ = a and are asked to find csc θ Jason sayspage that46 this is not possible, but Nadina disagrees Is either of them correct? Explain your reasoning

47 Using these definitions, = = =tan θ Similarly, = = =cot θ 84ERROR ANALYSIS Jason and Nadina know the value of sin θ = a and are asked to find csc θ Jason says that this is not possible, but Nadina disagrees Is either of them correct? Explain your reasoning Nadina; the cosecant function is the reciprocal function of the sine function Therefore, if sin θ = a, then csc θ = 0, where a 85Writing in Math Explain why the six trigonometric functions are transcendental functions The trigonometric functions are transcendental functions because they cannot be expressed in terms of algebraic operations For example, there is no way to find the value of θin y = cos θby adding, subtracting, multiplying, or dividing a constant and θ or raising θ to a rational power 86CHALLENGEWrite an expression in terms of θ for the area of the scalene triangle shown Explain Sample answer: If you draw the height of the triangle, it forms two right triangles, as shown Use the sine function to find h Substitute the expression for h into the formula for the area of a triangle, A = Therefore, an expression in terms of θ for the area of the triangle is A = bh 87PROOF Prove that if θ is an acute angle of a right triangle, then (sin θ)2 + (cos θ)2 = 1 esolutions Manual - Poweredof byacognero Draw a diagram right triangle with an acute angle θ Page 47

48 87 PROOF Prove that if θ is an acute angle of a right triangle, then (sin θ) 2 + (cos θ) 2 = 1 SOLUTION: Draw a diagram of a right triangle with an acute angle θ From the definitions of the sine and cosine functions, sin θ = and cos θ = By the Pythagorean Theorem, c 2 = a 2 + b 2 = + = = = 1 Therefore, (sin θ) 2 + (cos θ) 2 = 1 REASONING If A and B are the acute angles of a right triangle and m A < m B, determine whether each statement is true or false If false, give a counterexample 88 sin A < sin B SOLUTION: Find sin A and sin B for various angle measures of a right triangle, where m A < m B m A m B sin A sin B Sample answer: From the table, it appears that when m A < m B, sin A < sin B Therefore, the statement is true Page 48

49 89 cos A < cos B SOLUTION: False; sample answer: In ABC, the m B < m A, cos B 07986, and cos A Therefore, cos B > cos A, and thus the statement is false 90 tan A < tan B SOLUTION: Find tan A and tan B for various angle measures of a right triangle, where m A < m B m A m B tan A tan B Sample answer: From the table, it appears that when m A < m B, tan A < tan B Therefore, the statement is true 91 Writing in Math Notice on a graphing calculator that there is no key for finding the secant, cosecant, or cotangent of an angle measure Explain why you think this might be so SOLUTION: Sample answer: Since cosine is the inverse of secant, sine is the inverse of cosecant, and tangent is the inverse of cotangent, you can find the value of the secant, cosecant, or cotangent by finding the value of its inverse and using the reciprocal key on your calculator 92 ECONOMICS The Consumer Price Index (CPI) measures inflation It is based on the average prices of goods and services in the United States, with the annual average for the years set at an index of 100 The table shown gives some annual average CPI values from 1955 to 2005 Find an exponential model relating this data (year, CPI) by linearizing the data Let x = 0 represent 1955 Then use your model to predict the CPI for 2025 SOLUTION: Linearize the data by finding (x, ln y) Page 49

50 x ln y Calculate the linear regression Please note that the regression was calculated using the actual values of ln y as opposed to the rounded values shown in the table above The rounded regression equation is Graph the linearized data Replace with ln y and solve for y To find the CPI for 2025, find y when x = or 70 According to this model, the CPI in 2025 will be about 5232 Solve each equation Round to the nearest hundredth 93 e 5x = 24 SOLUTION: Page 50

51 94 2e x 7 6 = 0 SOLUTION: 2e x 7 6 = 0 Sketch and analyze the graph of each function Describe its domain, range, intercepts, asymptotes, end behavior, and where the function is increasing or decreasing 95 f (x) = 3 x 2 SOLUTION: Evaluate the function for several x-values in its domain x f (x) Use a smooth curve to connect each of the ordered pairs Page 51

52 96 f (x) = 2 3x SOLUTION: Evaluate the function for several x-values in its domain x f (x) Use a smooth curve to connect each of the ordered pairs Page 52

53 97 f (x) = 4 x + 6 SOLUTION: Evaluate the function for several x-values in its domain x f (x) Use a smooth curve to connect each of the ordered pairs Page 53

54 Solve each equation 98 = SOLUTION: The LCD is (x + 4)(2x 1) 99 = + SOLUTION: The LCD is (x + 1)(x 5) Because the original equation is not defined when x = 5, you can eliminate this extraneous solution Therefore, the only solution is 4 Page 54

55 100 = SOLUTION: = The LCD is (3x + 2)(x + 1) Page 55

56 101 NEWSPAPERS The circulation in thousands of papers of a national newspaper is shown a Let x equal the number of years after 2001 Create a scatter plot of the data b Determine a power function to model the data c Use the function to predict the circulation of the newspaper in 2015 SOLUTION: a Enter the data into a graphing calculator and create a scatter plot b Use the power regression function on the graphing calculator to find values for a and b Rounding to the nearest thousandth, a power function that can be used to model the data is f (x) = x 0149 c Graph the regression equation using a graphing calculator To predict the circulation of the newspaper in 2015, use the TRACE function on the graphing calculator Find the value of y when x = or 14 So, the circulation in 2015 will be about 611,068 Page 56

57 102 SAT/ACT In the figure below, what is the value of z? A 15 B 15 C 15 D 30 E 30 SOLUTION: First, find x Notice that this is a 45º-45º-90º triangle Therefore, the legs of the triangle are the same length Solve for y So, the length of each side is 3(5) or 15 Use the Pythagorean Theorem to find z Therefore, the correct answer is B 103 REVIEW Joseph uses a ladder to reach a window 10 feet above the ground If the ladder is 3 feet away from the wall, how long should the ladder be? F 939 ft G 1044 ft H 1123 ft J 1205 ft SOLUTION: Draw a diagram where x represents the length of the ladder Use the Pythagorean Theorem to find x Therefore, the correct answer is G Page 57

58 104 A person holds one end of a rope that runs through a pulley and has a weight attached to the other end Assume that the weight is at the same height as the person s hand What is the distance from the person's hand to the weight? A 78 ft B 105 ft C 129 ft D 143 ft SOLUTION: Draw a diagram where x represents the distance from the person's hand to the weight Because an acute angle and the length of the side adjacent to the angle are given, you can use the tangent function to find x The distance from the person's hand to the weight is about 78 feet Therefore, the correct answer is A Page 58

59 105 REVIEW A kite is being flown at a 45 angle The string of the kite is 120 feet long How high is the kite above the point at which the string is held? F 60 ft G 60 ft H 60 ft J 120 ft SOLUTION: Draw a diagram where x represents the distance from where the string is being held to the kite Because an acute angle and the length of the hypotenuse are given, you can use the sine function to find x The kite is 60 ft above the point where the string is being held Therefore, the correct answer is G Page 59

RIGHT TRIANGLE TRIGONOMETRY

RIGHT TRIANGLE TRIGONOMETRY RIGHT TRIANGLE TRIGONOMETRY The word Trigonometry can be broken into the parts Tri, gon, and metry, which means Three angle measurement, or equivalently Triangle measurement. Throughout this unit, we will

More information

Parallel and Perpendicular. We show a small box in one of the angles to show that the lines are perpendicular.

Parallel and Perpendicular. We show a small box in one of the angles to show that the lines are perpendicular. CONDENSED L E S S O N. Parallel and Perpendicular In this lesson you will learn the meaning of parallel and perpendicular discover how the slopes of parallel and perpendicular lines are related use slopes

More information

Geometry Notes RIGHT TRIANGLE TRIGONOMETRY

Geometry Notes RIGHT TRIANGLE TRIGONOMETRY Right Triangle Trigonometry Page 1 of 15 RIGHT TRIANGLE TRIGONOMETRY Objectives: After completing this section, you should be able to do the following: Calculate the lengths of sides and angles of a right

More information

4.3 & 4.8 Right Triangle Trigonometry. Anatomy of Right Triangles

4.3 & 4.8 Right Triangle Trigonometry. Anatomy of Right Triangles 4.3 & 4.8 Right Triangle Trigonometry Anatomy of Right Triangles The right triangle shown at the right uses lower case a, b and c for its sides with c being the hypotenuse. The sides a and b are referred

More information

Angles and Quadrants. Angle Relationships and Degree Measurement. Chapter 7: Trigonometry

Angles and Quadrants. Angle Relationships and Degree Measurement. Chapter 7: Trigonometry Chapter 7: Trigonometry Trigonometry is the study of angles and how they can be used as a means of indirect measurement, that is, the measurement of a distance where it is not practical or even possible

More information

Pythagorean Theorem: 9. x 2 2

Pythagorean Theorem: 9. x 2 2 Geometry Chapter 8 - Right Triangles.7 Notes on Right s Given: any 3 sides of a Prove: the is acute, obtuse, or right (hint: use the converse of Pythagorean Theorem) If the (longest side) 2 > (side) 2

More information

How To Solve The Pythagorean Triangle

How To Solve The Pythagorean Triangle Name Period CHAPTER 9 Right Triangles and Trigonometry Section 9.1 Similar right Triangles Objectives: Solve problems involving similar right triangles. Use a geometric mean to solve problems. Ex. 1 Use

More information

Right Triangles A right triangle, as the one shown in Figure 5, is a triangle that has one angle measuring

Right Triangles A right triangle, as the one shown in Figure 5, is a triangle that has one angle measuring Page 1 9 Trigonometry of Right Triangles Right Triangles A right triangle, as the one shown in Figure 5, is a triangle that has one angle measuring 90. The side opposite to the right angle is the longest

More information

Right Triangle Trigonometry

Right Triangle Trigonometry Section 6.4 OBJECTIVE : Right Triangle Trigonometry Understanding the Right Triangle Definitions of the Trigonometric Functions otenuse osite side otenuse acent side acent side osite side We will be concerned

More information

Unit 6 Trigonometric Identities, Equations, and Applications

Unit 6 Trigonometric Identities, Equations, and Applications Accelerated Mathematics III Frameworks Student Edition Unit 6 Trigonometric Identities, Equations, and Applications nd Edition Unit 6: Page of 3 Table of Contents Introduction:... 3 Discovering the Pythagorean

More information

8-3 Dot Products and Vector Projections

8-3 Dot Products and Vector Projections 8-3 Dot Products and Vector Projections Find the dot product of u and v Then determine if u and v are orthogonal 1u =, u and v are not orthogonal 2u = 3u =, u and v are not orthogonal 6u = 11i + 7j; v

More information

8-5 Angles of Elevation and Depression. The length of the base of the ramp is about 27.5 ft.

8-5 Angles of Elevation and Depression. The length of the base of the ramp is about 27.5 ft. 1.BIKING Lenora wants to build the bike ramp shown. Find the length of the base of the ramp. The length of the base of the ramp is about 27.5 ft. ANSWER: 27.5 ft 2.BASEBALL A fan is seated in the upper

More information

Geometry and Measurement

Geometry and Measurement The student will be able to: Geometry and Measurement 1. Demonstrate an understanding of the principles of geometry and measurement and operations using measurements Use the US system of measurement for

More information

9 Right Triangle Trigonometry

9 Right Triangle Trigonometry www.ck12.org CHAPTER 9 Right Triangle Trigonometry Chapter Outline 9.1 THE PYTHAGOREAN THEOREM 9.2 CONVERSE OF THE PYTHAGOREAN THEOREM 9.3 USING SIMILAR RIGHT TRIANGLES 9.4 SPECIAL RIGHT TRIANGLES 9.5

More information

Lesson 1: Exploring Trigonometric Ratios

Lesson 1: Exploring Trigonometric Ratios Lesson 1: Exploring Trigonometric Ratios Common Core Georgia Performance Standards MCC9 12.G.SRT.6 MCC9 12.G.SRT.7 Essential Questions 1. How are the properties of similar triangles used to create trigonometric

More information

MEMORANDUM. All students taking the CLC Math Placement Exam PLACEMENT INTO CALCULUS AND ANALYTIC GEOMETRY I, MTH 145:

MEMORANDUM. All students taking the CLC Math Placement Exam PLACEMENT INTO CALCULUS AND ANALYTIC GEOMETRY I, MTH 145: MEMORANDUM To: All students taking the CLC Math Placement Eam From: CLC Mathematics Department Subject: What to epect on the Placement Eam Date: April 0 Placement into MTH 45 Solutions This memo is an

More information

Graphing Trigonometric Skills

Graphing Trigonometric Skills Name Period Date Show all work neatly on separate paper. (You may use both sides of your paper.) Problems should be labeled clearly. If I can t find a problem, I ll assume it s not there, so USE THE TEMPLATE

More information

Give an expression that generates all angles coterminal with the given angle. Let n represent any integer. 9) 179

Give an expression that generates all angles coterminal with the given angle. Let n represent any integer. 9) 179 Trigonometry Chapters 1 & 2 Test 1 Name Provide an appropriate response. 1) Find the supplement of an angle whose measure is 7. Find the measure of each angle in the problem. 2) Perform the calculation.

More information

Section 7.1 Solving Right Triangles

Section 7.1 Solving Right Triangles Section 7.1 Solving Right Triangles Note that a calculator will be needed for most of the problems we will do in class. Test problems will involve angles for which no calculator is needed (e.g., 30, 45,

More information

Geometry 1. Unit 3: Perpendicular and Parallel Lines

Geometry 1. Unit 3: Perpendicular and Parallel Lines Geometry 1 Unit 3: Perpendicular and Parallel Lines Geometry 1 Unit 3 3.1 Lines and Angles Lines and Angles Parallel Lines Parallel lines are lines that are coplanar and do not intersect. Some examples

More information

Biggar High School Mathematics Department. National 5 Learning Intentions & Success Criteria: Assessing My Progress

Biggar High School Mathematics Department. National 5 Learning Intentions & Success Criteria: Assessing My Progress Biggar High School Mathematics Department National 5 Learning Intentions & Success Criteria: Assessing My Progress Expressions & Formulae Topic Learning Intention Success Criteria I understand this Approximation

More information

The Primary Trigonometric Ratios Word Problems

The Primary Trigonometric Ratios Word Problems The Primary Trigonometric Ratios Word Problems. etermining the measures of the sides and angles of right triangles using the primary ratios When we want to measure the height of an inaccessible object

More information

Algebra and Geometry Review (61 topics, no due date)

Algebra and Geometry Review (61 topics, no due date) Course Name: Math 112 Credit Exam LA Tech University Course Code: ALEKS Course: Trigonometry Instructor: Course Dates: Course Content: 159 topics Algebra and Geometry Review (61 topics, no due date) Properties

More information

Friday, January 29, 2016 9:15 a.m. to 12:15 p.m., only

Friday, January 29, 2016 9:15 a.m. to 12:15 p.m., only ALGEBRA /TRIGONOMETRY The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION ALGEBRA /TRIGONOMETRY Friday, January 9, 016 9:15 a.m. to 1:15 p.m., only Student Name: School Name: The possession

More information

Solutions to Exercises, Section 5.1

Solutions to Exercises, Section 5.1 Instructor s Solutions Manual, Section 5.1 Exercise 1 Solutions to Exercises, Section 5.1 1. Find all numbers t such that ( 1 3,t) is a point on the unit circle. For ( 1 3,t)to be a point on the unit circle

More information

Math Placement Test Practice Problems

Math Placement Test Practice Problems Math Placement Test Practice Problems The following problems cover material that is used on the math placement test to place students into Math 1111 College Algebra, Math 1113 Precalculus, and Math 2211

More information

Trigonometric Functions: The Unit Circle

Trigonometric Functions: The Unit Circle Trigonometric Functions: The Unit Circle This chapter deals with the subject of trigonometry, which likely had its origins in the study of distances and angles by the ancient Greeks. The word trigonometry

More information

ALGEBRA 2/TRIGONOMETRY

ALGEBRA 2/TRIGONOMETRY ALGEBRA /TRIGONOMETRY The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION ALGEBRA /TRIGONOMETRY Thursday, January 9, 015 9:15 a.m to 1:15 p.m., only Student Name: School Name: The possession

More information

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION MATHEMATICS B. Thursday, January 29, 2004 9:15 a.m. to 12:15 p.m.

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION MATHEMATICS B. Thursday, January 29, 2004 9:15 a.m. to 12:15 p.m. The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION MATHEMATICS B Thursday, January 9, 004 9:15 a.m. to 1:15 p.m., only Print Your Name: Print Your School s Name: Print your name and

More information

Trigonometric Functions

Trigonometric Functions Trigonometric Functions 13A Trigonometry and Angles 13-1 Right-Angle Trigonometry 13- Angles of Rotation Lab Explore the Unit Circle 13-3 The Unit Circle 13-4 Inverses of Trigonometric Functions 13B Applying

More information

Geometry Notes PERIMETER AND AREA

Geometry Notes PERIMETER AND AREA Perimeter and Area Page 1 of 57 PERIMETER AND AREA Objectives: After completing this section, you should be able to do the following: Calculate the area of given geometric figures. Calculate the perimeter

More information

Section 6-3 Double-Angle and Half-Angle Identities

Section 6-3 Double-Angle and Half-Angle Identities 6-3 Double-Angle and Half-Angle Identities 47 Section 6-3 Double-Angle and Half-Angle Identities Double-Angle Identities Half-Angle Identities This section develops another important set of identities

More information

South Carolina College- and Career-Ready (SCCCR) Pre-Calculus

South Carolina College- and Career-Ready (SCCCR) Pre-Calculus South Carolina College- and Career-Ready (SCCCR) Pre-Calculus Key Concepts Arithmetic with Polynomials and Rational Expressions PC.AAPR.2 PC.AAPR.3 PC.AAPR.4 PC.AAPR.5 PC.AAPR.6 PC.AAPR.7 Standards Know

More information

Introduction Assignment

Introduction Assignment PRE-CALCULUS 11 Introduction Assignment Welcome to PREC 11! This assignment will help you review some topics from a previous math course and introduce you to some of the topics that you ll be studying

More information

6. Vectors. 1 2009-2016 Scott Surgent (surgent@asu.edu)

6. Vectors. 1 2009-2016 Scott Surgent (surgent@asu.edu) 6. Vectors For purposes of applications in calculus and physics, a vector has both a direction and a magnitude (length), and is usually represented as an arrow. The start of the arrow is the vector s foot,

More information

(15.) To find the distance from point A to point B across. a river, a base line AC is extablished. AC is 495 meters

(15.) To find the distance from point A to point B across. a river, a base line AC is extablished. AC is 495 meters (15.) To find the distance from point A to point B across a river, a base line AC is extablished. AC is 495 meters long. Angles

More information

Right Triangles 4 A = 144 A = 16 12 5 A = 64

Right Triangles 4 A = 144 A = 16 12 5 A = 64 Right Triangles If I looked at enough right triangles and experimented a little, I might eventually begin to notice a relationship developing if I were to construct squares formed by the legs of a right

More information

Higher Education Math Placement

Higher Education Math Placement Higher Education Math Placement Placement Assessment Problem Types 1. Whole Numbers, Fractions, and Decimals 1.1 Operations with Whole Numbers Addition with carry Subtraction with borrowing Multiplication

More information

Trigonometry Hard Problems

Trigonometry Hard Problems Solve the problem. This problem is very difficult to understand. Let s see if we can make sense of it. Note that there are multiple interpretations of the problem and that they are all unsatisfactory.

More information

Dear Accelerated Pre-Calculus Student:

Dear Accelerated Pre-Calculus Student: Dear Accelerated Pre-Calculus Student: I am very excited that you have decided to take this course in the upcoming school year! This is a fastpaced, college-preparatory mathematics course that will also

More information

Semester 2, Unit 4: Activity 21

Semester 2, Unit 4: Activity 21 Resources: SpringBoard- PreCalculus Online Resources: PreCalculus Springboard Text Unit 4 Vocabulary: Identity Pythagorean Identity Trigonometric Identity Cofunction Identity Sum and Difference Identities

More information

Trigonometry Review with the Unit Circle: All the trig. you ll ever need to know in Calculus

Trigonometry Review with the Unit Circle: All the trig. you ll ever need to know in Calculus Trigonometry Review with the Unit Circle: All the trig. you ll ever need to know in Calculus Objectives: This is your review of trigonometry: angles, six trig. functions, identities and formulas, graphs:

More information

Applications of the Pythagorean Theorem

Applications of the Pythagorean Theorem 9.5 Applications of the Pythagorean Theorem 9.5 OBJECTIVE 1. Apply the Pythagorean theorem in solving problems Perhaps the most famous theorem in all of mathematics is the Pythagorean theorem. The theorem

More information

D.3. Angles and Degree Measure. Review of Trigonometric Functions

D.3. Angles and Degree Measure. Review of Trigonometric Functions APPENDIX D Precalculus Review D7 SECTION D. Review of Trigonometric Functions Angles and Degree Measure Radian Measure The Trigonometric Functions Evaluating Trigonometric Functions Solving Trigonometric

More information

Curriculum Map by Block Geometry Mapping for Math Block Testing 2007-2008. August 20 to August 24 Review concepts from previous grades.

Curriculum Map by Block Geometry Mapping for Math Block Testing 2007-2008. August 20 to August 24 Review concepts from previous grades. Curriculum Map by Geometry Mapping for Math Testing 2007-2008 Pre- s 1 August 20 to August 24 Review concepts from previous grades. August 27 to September 28 (Assessment to be completed by September 28)

More information

Extra Credit Assignment Lesson plan. The following assignment is optional and can be completed to receive up to 5 points on a previously taken exam.

Extra Credit Assignment Lesson plan. The following assignment is optional and can be completed to receive up to 5 points on a previously taken exam. Extra Credit Assignment Lesson plan The following assignment is optional and can be completed to receive up to 5 points on a previously taken exam. The extra credit assignment is to create a typed up lesson

More information

Indirect Measurement Technique: Using Trigonometric Ratios Grade Nine

Indirect Measurement Technique: Using Trigonometric Ratios Grade Nine Ohio Standards Connections Measurement Benchmark D Use proportional reasoning and apply indirect measurement techniques, including right triangle trigonometry and properties of similar triangles, to solve

More information

Trigonometry. An easy way to remember trigonometric properties is:

Trigonometry. An easy way to remember trigonometric properties is: Trigonometry It is possible to solve many force and velocity problems by drawing vector diagrams. However, the degree of accuracy is dependent upon the exactness of the person doing the drawing and measuring.

More information

Accelerated Mathematics II Frameworks Student Edition Unit 4 Right Triangle Trigonometry

Accelerated Mathematics II Frameworks Student Edition Unit 4 Right Triangle Trigonometry Accelerated Mathematics II Frameworks Student Edition Unit 4 Right Triangle Trigonometry 1 st Student Edition August 2009 Table of Contents Introduction..3 Eratosthenes Finds the Circumference of the Earth

More information

Using the Quadrant. Protractor. Eye Piece. You can measure angles of incline from 0º ( horizontal ) to 90º (vertical ). Ignore measurements >90º.

Using the Quadrant. Protractor. Eye Piece. You can measure angles of incline from 0º ( horizontal ) to 90º (vertical ). Ignore measurements >90º. Using the Quadrant Eye Piece Protractor Handle You can measure angles of incline from 0º ( horizontal ) to 90º (vertical ). Ignore measurements 90º. Plumb Bob ø

More information

6.1 Basic Right Triangle Trigonometry

6.1 Basic Right Triangle Trigonometry 6.1 Basic Right Triangle Trigonometry MEASURING ANGLES IN RADIANS First, let s introduce the units you will be using to measure angles, radians. A radian is a unit of measurement defined as the angle at

More information

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION INTEGRATED ALGEBRA. Thursday, August 16, 2012 8:30 to 11:30 a.m.

The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION INTEGRATED ALGEBRA. Thursday, August 16, 2012 8:30 to 11:30 a.m. INTEGRATED ALGEBRA The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION INTEGRATED ALGEBRA Thursday, August 16, 2012 8:30 to 11:30 a.m., only Student Name: School Name: Print your name

More information

Summer Math Exercises. For students who are entering. Pre-Calculus

Summer Math Exercises. For students who are entering. Pre-Calculus Summer Math Eercises For students who are entering Pre-Calculus It has been discovered that idle students lose learning over the summer months. To help you succeed net fall and perhaps to help you learn

More information

Trigonometric Functions and Triangles

Trigonometric Functions and Triangles Trigonometric Functions and Triangles Dr. Philippe B. Laval Kennesaw STate University August 27, 2010 Abstract This handout defines the trigonometric function of angles and discusses the relationship between

More information

Lesson 33: Example 1 (5 minutes)

Lesson 33: Example 1 (5 minutes) Student Outcomes Students understand that the Law of Sines can be used to find missing side lengths in a triangle when you know the measures of the angles and one side length. Students understand that

More information

Prentice Hall Mathematics: Algebra 2 2007 Correlated to: Utah Core Curriculum for Math, Intermediate Algebra (Secondary)

Prentice Hall Mathematics: Algebra 2 2007 Correlated to: Utah Core Curriculum for Math, Intermediate Algebra (Secondary) Core Standards of the Course Standard 1 Students will acquire number sense and perform operations with real and complex numbers. Objective 1.1 Compute fluently and make reasonable estimates. 1. Simplify

More information

of surface, 569-571, 576-577, 578-581 of triangle, 548 Associative Property of addition, 12, 331 of multiplication, 18, 433

of surface, 569-571, 576-577, 578-581 of triangle, 548 Associative Property of addition, 12, 331 of multiplication, 18, 433 Absolute Value and arithmetic, 730-733 defined, 730 Acute angle, 477 Acute triangle, 497 Addend, 12 Addition associative property of, (see Commutative Property) carrying in, 11, 92 commutative property

More information

Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question.

Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question. Name: Class: Date: ID: A Q3 Geometry Review Multiple Choice Identify the choice that best completes the statement or answers the question. Graph the image of each figure under a translation by the given

More information

SOLVING TRIGONOMETRIC EQUATIONS

SOLVING TRIGONOMETRIC EQUATIONS Mathematics Revision Guides Solving Trigonometric Equations Page 1 of 17 M.K. HOME TUITION Mathematics Revision Guides Level: AS / A Level AQA : C2 Edexcel: C2 OCR: C2 OCR MEI: C2 SOLVING TRIGONOMETRIC

More information

Chapter 5: Trigonometric Functions of Angles

Chapter 5: Trigonometric Functions of Angles Chapter 5: Trigonometric Functions of Angles In the previous chapters we have explored a variety of functions which could be combined to form a variety of shapes. In this discussion, one common shape has

More information

Trigonometry LESSON ONE - Degrees and Radians Lesson Notes

Trigonometry LESSON ONE - Degrees and Radians Lesson Notes 210 180 = 7 6 Trigonometry Example 1 Define each term or phrase and draw a sample angle. Angle Definitions a) angle in standard position: Draw a standard position angle,. b) positive and negative angles:

More information

Find the length of the arc on a circle of radius r intercepted by a central angle θ. Round to two decimal places.

Find the length of the arc on a circle of radius r intercepted by a central angle θ. Round to two decimal places. SECTION.1 Simplify. 1. 7π π. 5π 6 + π Find the measure of the angle in degrees between the hour hand and the minute hand of a clock at the time shown. Measure the angle in the clockwise direction.. 1:0.

More information

Law of Cosines. If the included angle is a right angle then the Law of Cosines is the same as the Pythagorean Theorem.

Law of Cosines. If the included angle is a right angle then the Law of Cosines is the same as the Pythagorean Theorem. Law of Cosines In the previous section, we learned how the Law of Sines could be used to solve oblique triangles in three different situations () where a side and two angles (SAA) were known, () where

More information

Chapter 5 Resource Masters

Chapter 5 Resource Masters Chapter Resource Masters New York, New York Columbus, Ohio Woodland Hills, California Peoria, Illinois StudentWorks TM This CD-ROM includes the entire Student Edition along with the Study Guide, Practice,

More information

Thnkwell s Homeschool Precalculus Course Lesson Plan: 36 weeks

Thnkwell s Homeschool Precalculus Course Lesson Plan: 36 weeks Thnkwell s Homeschool Precalculus Course Lesson Plan: 36 weeks Welcome to Thinkwell s Homeschool Precalculus! We re thrilled that you ve decided to make us part of your homeschool curriculum. This lesson

More information

How do you compare numbers? On a number line, larger numbers are to the right and smaller numbers are to the left.

How do you compare numbers? On a number line, larger numbers are to the right and smaller numbers are to the left. The verbal answers to all of the following questions should be memorized before completion of pre-algebra. Answers that are not memorized will hinder your ability to succeed in algebra 1. Number Basics

More information

Expression. Variable Equation Polynomial Monomial Add. Area. Volume Surface Space Length Width. Probability. Chance Random Likely Possibility Odds

Expression. Variable Equation Polynomial Monomial Add. Area. Volume Surface Space Length Width. Probability. Chance Random Likely Possibility Odds Isosceles Triangle Congruent Leg Side Expression Equation Polynomial Monomial Radical Square Root Check Times Itself Function Relation One Domain Range Area Volume Surface Space Length Width Quantitative

More information

Section 5-9 Inverse Trigonometric Functions

Section 5-9 Inverse Trigonometric Functions 46 5 TRIGONOMETRIC FUNCTIONS Section 5-9 Inverse Trigonometric Functions Inverse Sine Function Inverse Cosine Function Inverse Tangent Function Summar Inverse Cotangent, Secant, and Cosecant Functions

More information

PRE-CALCULUS GRADE 12

PRE-CALCULUS GRADE 12 PRE-CALCULUS GRADE 12 [C] Communication Trigonometry General Outcome: Develop trigonometric reasoning. A1. Demonstrate an understanding of angles in standard position, expressed in degrees and radians.

More information

Lesson Plan. Students will be able to define sine and cosine functions based on a right triangle

Lesson Plan. Students will be able to define sine and cosine functions based on a right triangle Lesson Plan Header: Name: Unit Title: Right Triangle Trig without the Unit Circle (Unit in 007860867) Lesson title: Solving Right Triangles Date: Duration of Lesson: 90 min. Day Number: Grade Level: 11th/1th

More information

8-2 The Pythagorean Theorem and Its Converse. Find x.

8-2 The Pythagorean Theorem and Its Converse. Find x. 1 8- The Pythagorean Theorem and Its Converse Find x. 1. hypotenuse is 13 and the lengths of the legs are 5 and x.. equaltothesquareofthelengthofthehypotenuse. The length of the hypotenuse is x and the

More information

TRIGONOMETRY Compound & Double angle formulae

TRIGONOMETRY Compound & Double angle formulae TRIGONOMETRY Compound & Double angle formulae In order to master this section you must first learn the formulae, even though they will be given to you on the matric formula sheet. We call these formulae

More information

Lesson 18 Pythagorean Triples & Special Right Triangles

Lesson 18 Pythagorean Triples & Special Right Triangles Student Name: Date: Contact Person Name: Phone Number: Teas Assessment of Knowledge and Skills Eit Level Math Review Lesson 18 Pythagorean Triples & Special Right Triangles TAKS Objective 6 Demonstrate

More information

Algebra Geometry Glossary. 90 angle

Algebra Geometry Glossary. 90 angle lgebra Geometry Glossary 1) acute angle an angle less than 90 acute angle 90 angle 2) acute triangle a triangle where all angles are less than 90 3) adjacent angles angles that share a common leg Example:

More information

Georgia Department of Education Kathy Cox, State Superintendent of Schools 7/19/2005 All Rights Reserved 1

Georgia Department of Education Kathy Cox, State Superintendent of Schools 7/19/2005 All Rights Reserved 1 Accelerated Mathematics 3 This is a course in precalculus and statistics, designed to prepare students to take AB or BC Advanced Placement Calculus. It includes rational, circular trigonometric, and inverse

More information

Page. Trigonometry Sine Law and Cosine Law. push

Page. Trigonometry Sine Law and Cosine Law. push Trigonometry Sine Law and Cosine Law Page Trigonometry can be used to calculate the side lengths and angle measures of triangles. Triangular shapes are used in construction to create rigid structures.

More information

Nonlinear Systems and the Conic Sections

Nonlinear Systems and the Conic Sections C H A P T E R 11 Nonlinear Systems and the Conic Sections x y 0 40 Width of boom carpet Most intense sonic boom is between these lines t a cruising speed of 1,40 miles per hour, the Concorde can fly from

More information

SAT Subject Math Level 2 Facts & Formulas

SAT Subject Math Level 2 Facts & Formulas Numbers, Sequences, Factors Integers:..., -3, -2, -1, 0, 1, 2, 3,... Reals: integers plus fractions, decimals, and irrationals ( 2, 3, π, etc.) Order Of Operations: Arithmetic Sequences: PEMDAS (Parentheses

More information

Square Roots and the Pythagorean Theorem

Square Roots and the Pythagorean Theorem 4.8 Square Roots and the Pythagorean Theorem 4.8 OBJECTIVES 1. Find the square root of a perfect square 2. Use the Pythagorean theorem to find the length of a missing side of a right triangle 3. Approximate

More information

HS Mathematics Item Specification C1 TO

HS Mathematics Item Specification C1 TO Task Model 1 Multiple Choice, single correct response G-SRT.C.6 Understand that by similarity, side ratios in right triangles are properties of the angles in the triangle, leading to definitions of acute

More information

PERIMETER AND AREA. In this unit, we will develop and apply the formulas for the perimeter and area of various two-dimensional figures.

PERIMETER AND AREA. In this unit, we will develop and apply the formulas for the perimeter and area of various two-dimensional figures. PERIMETER AND AREA In this unit, we will develop and apply the formulas for the perimeter and area of various two-dimensional figures. Perimeter Perimeter The perimeter of a polygon, denoted by P, is the

More information

2312 test 2 Fall 2010 Form B

2312 test 2 Fall 2010 Form B 2312 test 2 Fall 2010 Form B 1. Write the slope-intercept form of the equation of the line through the given point perpendicular to the given lin point: ( 7, 8) line: 9x 45y = 9 2. Evaluate the function

More information

(1.) The air speed of an airplane is 380 km/hr at a bearing of. Find the ground speed of the airplane as well as its

(1.) The air speed of an airplane is 380 km/hr at a bearing of. Find the ground speed of the airplane as well as its (1.) The air speed of an airplane is 380 km/hr at a bearing of 78 o. The speed of the wind is 20 km/hr heading due south. Find the ground speed of the airplane as well as its direction. Here is the diagram:

More information

ANALYTICAL METHODS FOR ENGINEERS

ANALYTICAL METHODS FOR ENGINEERS UNIT 1: Unit code: QCF Level: 4 Credit value: 15 ANALYTICAL METHODS FOR ENGINEERS A/601/1401 OUTCOME - TRIGONOMETRIC METHODS TUTORIAL 1 SINUSOIDAL FUNCTION Be able to analyse and model engineering situations

More information

GEOMETRY CONCEPT MAP. Suggested Sequence:

GEOMETRY CONCEPT MAP. Suggested Sequence: CONCEPT MAP GEOMETRY August 2011 Suggested Sequence: 1. Tools of Geometry 2. Reasoning and Proof 3. Parallel and Perpendicular Lines 4. Congruent Triangles 5. Relationships Within Triangles 6. Polygons

More information

SOLVING EQUATIONS WITH RADICALS AND EXPONENTS 9.5. section ( 3 5 3 2 )( 3 25 3 10 3 4 ). The Odd-Root Property

SOLVING EQUATIONS WITH RADICALS AND EXPONENTS 9.5. section ( 3 5 3 2 )( 3 25 3 10 3 4 ). The Odd-Root Property 498 (9 3) Chapter 9 Radicals and Rational Exponents Replace the question mark by an expression that makes the equation correct. Equations involving variables are to be identities. 75. 6 76. 3?? 1 77. 1

More information

Basic Lesson: Pythagorean Theorem

Basic Lesson: Pythagorean Theorem Basic Lesson: Pythagorean Theorem Basic skill One leg of a triangle is 10 cm and other leg is of 24 cm. Find out the hypotenuse? Here we have AB = 10 and BC = 24 Using the Pythagorean Theorem AC 2 = AB

More information

Applications for Triangles

Applications for Triangles Not drawn to scale Applications for Triangles 1. 36 in. 40 in. 33 in. 1188 in. 2 69 in. 2 138 in. 2 1440 in. 2 2. 188 in. 2 278 in. 2 322 in. 2 none of these Find the area of a parallelogram with the given

More information

ALGEBRA 2/TRIGONOMETRY

ALGEBRA 2/TRIGONOMETRY ALGEBRA /TRIGONOMETRY The University of the State of New York REGENTS HIGH SCHOOL EXAMINATION ALGEBRA /TRIGONOMETRY Tuesday, January 8, 014 1:15 to 4:15 p.m., only Student Name: School Name: The possession

More information

1 Introduction to Basic Geometry

1 Introduction to Basic Geometry 1 Introduction to Basic Geometry 1.1 Euclidean Geometry and Axiomatic Systems 1.1.1 Points, Lines, and Line Segments Geometry is one of the oldest branches of mathematics. The word geometry in the Greek

More information

Cumulative Test. 161 Holt Geometry. Name Date Class

Cumulative Test. 161 Holt Geometry. Name Date Class Choose the best answer. 1. P, W, and K are collinear, and W is between P and K. PW 10x, WK 2x 7, and PW WK 6x 11. What is PK? A 2 C 90 B 6 D 11 2. RM bisects VRQ. If mmrq 2, what is mvrm? F 41 H 9 G 2

More information

25 The Law of Cosines and Its Applications

25 The Law of Cosines and Its Applications Arkansas Tech University MATH 103: Trigonometry Dr Marcel B Finan 5 The Law of Cosines and Its Applications The Law of Sines is applicable when either two angles and a side are given or two sides and an

More information

Pythagoras Theorem. Page I can... 1... identify and label right-angled triangles. 2... explain Pythagoras Theorem. 4... calculate the hypotenuse

Pythagoras Theorem. Page I can... 1... identify and label right-angled triangles. 2... explain Pythagoras Theorem. 4... calculate the hypotenuse Pythagoras Theorem Page I can... 1... identify and label right-angled triangles 2... eplain Pythagoras Theorem 4... calculate the hypotenuse 5... calculate a shorter side 6... determine whether a triangle

More information

MCA Formula Review Packet

MCA Formula Review Packet MCA Formula Review Packet 1 3 4 5 6 7 The MCA-II / BHS Math Plan Page 1 of 15 Copyright 005 by Claude Paradis 8 9 10 1 11 13 14 15 16 17 18 19 0 1 3 4 5 6 7 30 8 9 The MCA-II / BHS Math Plan Page of 15

More information

Question Bank Trigonometry

Question Bank Trigonometry Question Bank Trigonometry 3 3 3 3 cos A sin A cos A sin A 1. Prove that cos A sina cos A sina 3 3 3 3 cos A sin A cos A sin A L.H.S. cos A sina cos A sina (cosa sina) (cos A sin A cosa sina) (cosa sina)

More information

TRIGONOMETRY OF THE RIGHT TRIANGLE

TRIGONOMETRY OF THE RIGHT TRIANGLE HPTER 8 HPTER TLE OF ONTENTS 8-1 The Pythagorean Theorem 8-2 The Tangent Ratio 8-3 pplications of the Tangent Ratio 8-4 The Sine and osine Ratios 8-5 pplications of the Sine and osine Ratios 8-6 Solving

More information

Lesson Plan Teacher: G Johnson Date: September 20, 2012.

Lesson Plan Teacher: G Johnson Date: September 20, 2012. Lesson Plan Teacher: G Johnson Date: September 20, 2012. Subject: Mathematics Class: 11L Unit: Trigonometry Duration: 1hr: 40mins Topic: Using Pythagoras Theorem to solve trigonometrical problems Previous

More information

opp (the cotangent function) cot θ = adj opp Using this definition, the six trigonometric functions are well-defined for all angles

opp (the cotangent function) cot θ = adj opp Using this definition, the six trigonometric functions are well-defined for all angles Definition of Trigonometric Functions using Right Triangle: C hp A θ B Given an right triangle ABC, suppose angle θ is an angle inside ABC, label the leg osite θ the osite side, label the leg acent to

More information

Mathematics Placement Examination (MPE)

Mathematics Placement Examination (MPE) Practice Problems for Mathematics Placement Eamination (MPE) Revised August, 04 When you come to New Meico State University, you may be asked to take the Mathematics Placement Eamination (MPE) Your inital

More information

Introduction and Mathematical Concepts

Introduction and Mathematical Concepts CHAPTER 1 Introduction and Mathematical Concepts PREVIEW In this chapter you will be introduced to the physical units most frequently encountered in physics. After completion of the chapter you will be

More information