# Unit 22 One-Sided and Two-Sided Hypotheses Tests

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1 Unit 22 One-Sided and Two-Sided Hypotheses Tests Objectives: To differentiate between a one-sided hypothesis test and a two-sided hypothesis test about a population proportion or a population mean To understand the difference between a statistically significant difference and a clinically significant difference The first hypothesis test we considered when we introduced this topic concerned a claim by the manufacturer of a lighter. The manufacturer's claim was that the lighter would ignite on the first try 75% of the time. This led to the following hypothesis test: H 0 : λ = 0.75 vs. H 1 : λ 0.75 (α = 0.10). Figure 20-1 graphically displays the rejection region for the z test statistic. Algebraically, this rejection region is defined as z or z (i.e., z 1.645). This rejection region is supposed to identify values of the z test statistic which represent a larger distance between p and the hypothesized proportion 0.75 than we would expect from sampling error if H 0 : λ = 0.75 were really true. If the value of the z test statistic is greater than , we would be inclined to believe that the population proportion is larger than the hypothesized 0.75, whereas if the value of the z test statistic is less than 1.645, we would be inclined to believe that the population proportion is smaller than the hypothesized However, after some reflection, you may decide that you really do not care about finding evidence that the population proportion is larger than the hypothesized If it were in fact true that the lighter ignited on the first try more than 75% of the time, then you should be very pleased to find that the lighter actually performs better than the manufacturer claims. With this in mind, it is reasonable for you to decide that you are only concerned about finding evidence that the population proportion is smaller than the hypothesized A hypothesis test which is designed to identify a difference from a hypothesized value in only one direction is called a one-sided test. A hypothesis test which is designed to identify a difference from a hypothesized value in either direction is called a two-sided test. All of the hypothesis tests we have considered up to this point have been two-sided tests. We shall now consider some illustrations where a one-sided test is called for. The procedure to perform a one-sided test is exactly the same as the procedure to perform a two-sided test except for two things: first, the rejection region will consist either of positive values only or of negative values only, but not both; second, the p-value will be calculated by considering only one direction. To illustrate a one-sided test, suppose a substance called PatchUp is designed to repair and inflate a flat bicycle tire when one tube of the substance is squeezed into the tire through the stem. The manufacturer claims that PatchUp will be completely successful 85% of the time. A bicycle club would like to see if there is any evidence that the percentage of times PatchUp is completely successful is less than the claimed 85%. (Since it would be wonderful if the percentage were actually higher than the claimed 85%, the bicycle club has no interest in looking for evidence in this direction.) A 0.10 significance level is chosen for a hypothesis test. In a simple random sample of 152 flat tires, PatchUp is found to be completely successful 123 times. Since 0.85 is the hypothesized value, and n = 152 is the sample size, we can verify that the sample size is sufficiently large for the z-test about a population proportion to be appropriate by noting that (152)(0.85) = and (152)(1 0.85) = 22.8 are each greater than five. We shall now perform the four steps of the hypothesis test. The first step of our hypothesis test is to state the null and alternative hypotheses, and to choose a significance level. Remember that the null hypothesis is what we assume to be true unless there is sufficient evidence against it, and also that our null hypothesis will a statement involving equality; in addition, the alternative hypothesis is a statement we are looking for evidence to support, and also the alternative hypothesis 157

2 is a statement involving inequality. Thinking of our hypothesis as similar to a court trial, we shall assume that the proportion of times PatchUp is completely successful is (at least) 0.85, unless we find sufficient evidence that the proportion is smaller; in other words, 0.85 is our hypothesized value for λ. If we decide on a 0.10 significance level, we can complete the first step of the hypotheses test as follows: H 0 : λ = 0.85 vs. H 1 : λ 0.85 (α = 0.10, one-sided test). It would be perfectly correct to state the null hypothesis as H 0 : λ 0.85, because by not rejecting H 0 we are not only accepting the manufacturer's claim that PatchUp is completely successful 85% of the time, but we are also accepting the possibility that the percentage may be higher than the manufacturer claims. However, since we understand this to be implicit, we have decided to simply state the null hypothesis as H 0 : λ = Together with the significance level stated in parentheses, we have included a reminder that the test is one-sided. The second step of the hypothesis test is to collect data and calculate the value of the test statistic. Since PatchUp was found to be completely successful 123 times out of 152 tries, we find that the sample proportion is p = 123/152 = ; we then calculate the value of our test statistic z as follows: z = λ p λ ( λ ) 0.85( ) n = 152 The third step of the hypothesis test is to define the rejection region, decide whether or not to reject the null hypothesis, and obtain the p-value of the test. Figure 22-1 displays the rejection region graphically. The shaded area corresponds to values of the test statistic z = where p is less than the hypothesized 0.85 and which are unlikely to occur if H 0 : λ = 0.85 is true. In order that this shaded area be equal to α = 0.10, the rejection region is defined by the z-score below which 0.10 of the area lies. From either the bottom of Table A.2 or from the last row in Table A.3, we find that the z-score above which 0.10 of the area lies is z 0.10 = 1.282, which implies that the z-score below which 0.10 of the area lies is We can then define our rejection region algebraically as z Since our test statistic, calculated in the second step, was found to be z = which is in the rejection region, our decision is to reject H 0 : λ = 0.85 ; in other words, our data provides sufficient evidence to suggest that H 1 : λ 0.85 is true. Figure 22-2 graphically illustrates the p-value. Our test statistic was found to be z = 1.408, and the p-value of this hypothesis test is the probability of obtaining a test statistic value z which represents a larger distance below the hypothesized proportion than the observed z = In Figure 22-2, the observed test statistic value z = has been located on the horizontal axis. The shaded area corresponds to test statistic values which represent a larger distance below the 158.

3 hypothesized proportion than the observed z = ; in other words, the shaded area in Figure 22-2 is the p-value of the hypothesis test. From either the bottom of Table A.2 or from the last row in Table A.3, we find that is between z 0.10 = and z 0.05 = 1.645, which implies that the observed test statistic z = is between and This tells us that the area below the z-score is between 0.05 and Therefore, the shaded area in Figure 22-2, which is the p-value, must be between 0.05 and We indicate this by writing 0.05 < p-value < The fact that 0.05 < p-value < 0.10 confirms to us that H 0 is rejected with α = However, it also tells us that H 0 would not be rejected with α = 0.05 nor with α = We see again how the p-value can be treated as a measure of how strongly the observed data supports the H 1. Note that we could use the main part of Table A.2 (or statistical software or a programmable calculator) to obtain a more precise p-value than simply saying 0.05 < p-value < 0.10 ; however, in practice, we are more concerned about how the p-value compares with the commonly chosen significance levels than with an exact value. To complete the fourth step of the hypothesis test, we can summarize the results of the hypothesis test as follows: Since z = and z 0.10 = 1.282, we have sufficient evidence to reject H 0. We conclude that the proportion of times PatchUp is completely successful at repairing and inflating a bicycle tire is less than 0.85 (0.05 < p-value < 0.10 ). Whenever we have data which leads us to reject a null hypothesis, we say that the results of the hypothesis test are statistically significant, and of course when our data suggests that we should not reject a null hypothesis, we say that the results of the hypothesis test are not statistically significant. One feature about one-sided tests is that it is possible to obtain results which are not statistically significant but would have been, if we had originally decided to do a two-sided test. In the simple random sample of 152 flat bicycle tires used in the hypothesis test just completed, PatchUp was found to be completely successful 123 times. For the sake of argument though, let us momentarily pretend that in the simple random sample of 152 flat bicycle tires, PatchUp was found to be completely successful 139 times. This would imply that p = 139/152 = , and the corresponding z statistic would be equal to z = You can easily check that if the test had been two-sided, 159

4 z = would represent a statistically significant result and would suggest that the proportion of times PatchUp is completely successful is actually greater than the claimed However, if we originally decided that the test will be one-sided, then this would not be appropriate to say, since there was originally no interest in this direction. Self-Test Problem A 0.10 significance level is chosen to see if there is any evidence that the percentage of female patrons of the HairCare shop is less than 70%. In a simple random sample of 200 patrons, 133 are female. (a) Complete the four steps of the hypothesis test by completing the table titled Hypothesis Test for Self-Test Problem (b) Verify that the sample size is sufficiently large for the z statistic to be appropriate. (c) Considering the results of the hypothesis test, decide which of the Type I or Type II errors is possible, and describe this error. (d) Decide whether H 0 would have been rejected or would not have been rejected with each of the following significance levels: (i) α = 0.01, (ii) α = (e) What would be an appropriate graphical display for the data used in this hypothesis test? As another illustration of a one-sided test, suppose a 0.05 significance level is chosen for a hypothesis test to see if there is any evidence that the mean disintegration time for a magnesium tablet is greater than 100 seconds. For a simple random sample of 36 tablets, the sample mean disintegration time is found to be seconds and the sample standard deviation is found to be 7.2 seconds; also, it appears that the disintegration times are normally distributed so that the test statistic t n 1 is appropriate. We shall now have you perform each of the four steps of the hypothesis test. 160

5 In the section labeled Step 1 of Table 22-1, state the null and alternative hypotheses, and identify the significance level. In the section labeled Step 2, calculate the appropriate test statistic. In the section labeled Step 3, indicate the rejection region for the test both graphically and algebraically, decide whether or not the H 0 should be rejected, and obtain the p-value. In the section labeled Step 4, summarize the results of the hypothesis test with a statement which includes the observed test statistic value, the tabled value which defines the rejection region, the conclusion, and the p-value. For the first step in Table 22-1, you should have H 0 : µ = 100 vs. H 1 : µ > 100 (α = 0.05, one-sided test). For the second step, you should find that the test statistic is t 35 = For the third step, you should have the rejection described algebraically as t (where t 35;0.05 = is found by averaging t 30;0.05 = and t 40;0.05 = 1.684), you should find that H 0 is rejected, and you should fine that p-value < For the fourth step, you should have the following summary of results: Since t 35 = and t 35;0.025 = , we have sufficient evidence to reject H 0. We conclude that the mean disintegration time for a magnesium tablet is greater than 100 seconds (p-value < ). Self-Test Problem A 0.01 significance level is chosen to see if there is any evidence that the yearly income in a state is more than 42 thousand dollars. The 30 individuals selected for the SURVEY DATA, displayed as Data Set 1-1 at the end of Unit 1, are treated as a simple random sample. (a) Verify that n = 30, x = 45.4 thousand dollars, and s = thousand dollars. (b) Complete the four steps of the hypothesis test by completing the table titled Hypothesis Test for Self-Test Problem (c) Why would a box plot be an appropriate graphical display for the data used in this hypothesis test? (d) Construct the box plot, and comment on whether there is any reason to think the t statistic is not appropriate. (e) Considering the results of the hypothesis test, decide which of the Type I or Type II errors is possible, and describe this error. (f) Decide whether H 0 would have been rejected or would not have been rejected with each of the following significance levels: (i) α = 0.05, (ii) α =

7 Answers to Self-Test Problems 22-1 (a) Step 1: H 0 : λ = 0.7 vs. H 1 : λ < 0.7 (α = 0.10, one-sided) (b) (c) Step 2: p = 133/200 = and z = Step 3: The rejection is z H 0 is not rejected; 0.10 < p-value. Step 4: Since z = and z 0.10 = 1.282, we do not have sufficient evidence to reject H 0. We conclude that the proportion of female patrons of the HairCare shop is not less than 0.7 (0.10 < p-value). 200(0.7) = 140 and 200(1 0.7) = 60 are both larger than 5 implying n is sufficiently large. Since H 0 is not rejected, a Type II error is possible, which is concluding that λ = 0.7 when really λ < 0.7. (d) H 0 would not have been rejected with both α = 0.01 and α = (e) a bar chart or pie chart (a) n = 30, x = 45.4 thousand dollars, and s = thousand dollars are all correct. (b) Step 1: H 0 : µ = 42 vs. H 1 : µ > 42 (α = 0.01, one-sided) (c) (d) (e) Step 2: n = 30, x = 45.4 thousand dollars, s = thousand dollars, and t 29 = Step 3: The rejection is t H 0 is not rejected; 0.10 < p-value. Step 4: Since t 29 = and t 29;0.01 = 2.462, we do not have sufficient evidence to reject H 0. We conclude that the mean yearly income in the state is not more than 42 thousand dollars (0.10 < p-value). Since yearly income is a quantitative variable, a box plot is an appropriate graphical display. The five-number summary is 25, 33, 40.5, 60, 78. Since there are no potential outliers, and the box plot does not look extremely skewed, there is no reason to think that the t statistic is not appropriate. Since H 0 is not rejected, a Type II error is possible, which is concluding that µ = 42 when really µ 42. (f) H 0 would not have been rejected with both α = 0.05 and α = Summary A hypothesis test which is designed to identify a difference from a hypothesized value in only one direction is called a one-sided test. A hypothesis test which is designed to identify a difference from a hypothesized value in either direction is called a two-sided test. A clinically significant difference between the actual value of a parameter and the hypothesized value of the parameter is a difference which is large enough to have some practical impact. A statistically significant difference between the actual value of a parameter and the hypothesized value of the parameter is a difference is one detected by hypothesis test. A statistically significant difference occurs as the result of a hypothesis test, whereas a clinically significant difference occurs as a matter of judgment. A clinically significant difference may or may not be statistically significant, and a statistically significant difference may or may not be clinically significant. 163

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