Number of bits needed to address hosts 8

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1 Advanced Subnetting Example 1: Your ISP has assigned you a Class C network address of You have 3 networks in your company with the largest containing 134 hosts. You need to figure out if you can subnet this. If it can be subnetted you need to calculate the new subnet mask and specify the available network numbers? You need to determine how many bits you have available to work with. Since this is a standard Class C network the last octet is available so you have 8 bits to work with. 1. You need to determine how many bits will be needed to address the largest number of hosts that may exist on a network. This can easily be done by converting the largest number of hosts to binary and counting the bits needed. Largest number of hosts addresses needed in decimal Largest number of hosts addresses converted to binary Number of bits needed to address hosts 8 2. You need to determine how many bits will be needed to address the required number of networks. This can easily be done by converting the required number of networks to binary and counting the bits needed. Network addresses needed in decimal 3 Network addresses needed converted to binary 11 Number of bits needed to address networks 2 3. Add the total number of bits needed together and determine if a solution is possible. In this case = 10 so 10 bits are needed. We only have 8 available so this problem cannot be solved.

2 Example 2: Your ISP has assigned you a Class C network address of You have 3 networks in your company with the largest containing 51 hosts. You need to figure out if you can subnet this. If it can be subnetted you need to calculate the new subnet mask and specify the available network numbers? 1. You need to determine how many bits you have available to work with. Since this is a standard Class C network the last octet is available so you have 8 bits to work with. 2. You need to determine how many bits will be needed to address the largest number of hosts that may exist on a network. This can easily be done by converting the largest number of hosts to binary and counting the bits needed. Largest number of hosts addresses needed in decimal Largest number of hosts addresses converted to binary Number of bits needed to address hosts 6 3. You need to determine how many bits will be needed to address the required number of networks. This can easily be done by converting the required number of networks to binary and counting the bits needed. Network addresses needed in decimal 3 Network addresses needed converted to binary 11 Number of bits needed to address networks 2 4. Add the total number of bits needed together and determine if a solution is possible. In this case = 8 so 8 bits are needed. We have 8 available so this problem can be solved.

3 5. You must then determine the new subnet mask. To do this we take the number of bits needed to address network from the left side of the available bits. Convert the value to decimal and you have the subnet mask. Subnet mask in binary Subnet mask converted to decimal 192 Entire new subnet mask Original plus the changes you made to the host portion Finally you need to determine the network addresses available. This can be done by counting up in binary of the bits you used for the network and converting the result to decimal. Network number without host bits (Both in decimal and in binary) Network number with host bits (in binary) Network number Full network number 00 b 0 d /26 01 b 1 d /26 10 b 2 d /26 11 b 3 d /26

4 Example 3: Your ISP has assigned you a Class B network address of You have 11 networks in your company with the largest containing 98 hosts. You need to figure out if you can subnet this. If it can be subnetted you need to calculate the new subnet mask and specify the available network numbers? 1. You need to determine how many bits you have available to work with. Since this is a standard Class B network the last two octets are available so you have 16 bits to work with. 2. You need to determine how many bits will be needed to address the largest number of hosts that may exist on a network. This can easily be done by converting the largest number of hosts to binary and counting the bits needed. Largest number of hosts addresses needed in decimal Largest number of hosts addresses converted to binary Number of bits needed to address hosts 7 3. You need to determine how many bits will be needed to address the required number of networks. This can easily be done by converting the required number of networks to binary and counting the bits needed. Network addresses needed in decimal 11 Network addresses needed converted to binary 1011 Number of bits needed to address networks 4 4. Add the total number of bits needed together and determine if a solution is possible. In this case = 11 so 11 bits are needed. We have 16 available so this problem can be solved.

5 5. You must then determine the new subnet mask. To do this we take the number of bits needed to address network from the left side of the available bits. Convert the value to decimal and you have the subnet mask. Subnet mask in binary Subnet mask converted to decimal 240 Entire new subnet mask Original plus the changes you made to the host portion

6 6. Finally you need to determine the network addresses available. This can be done by counting up in binary of the bits you used for the network and converting the result to decimal. Network number without host bits (Both in decimal and in binary) Network number with host bits (in binary) Network number Full network number 0000 b 0 d / b 1 d / b 2 d / b 3 d / b 4 d / b 5 d / b 6 d / b 7 d / b 8 d / b 9 d / b 10 d / b 11 d / b 12 d / b 13 d / b 14 d / b 15 d /20

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