# IP Subnetting Colin Weaver, ITdojo

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1 IP Subnetting Colin Weaver, ITdojo Note: This document assumes that subnet zero is NOT used. For a description of subnet-zero, go here ( Subnetting IP networks is one of those things that is extremely easy for some people and painfully confusing for others. I ve done more than my share of subnetting so I figured I d take a stab at trying to lay it out for anyone interested in reading it. Anyhow, here it is: Subnetting by Colin: Using as the example network (we can also write this as /16): /16 is one (1) network. There are 65,534 possible hosts on this network. When subnetting, the objective is to take that one network and break it into multiple smaller networks. Two things: 1) How many networks you divide it into is up to you (your specific needs) (e.g. how many networks you need for your situation) 2) When you break one network up into multiple networks you end up with fewer hosts per network. The most straight-forward way you will be asked to subnet (especially on a test) is along the lines of: "You have been assigned the network listed above. You need to divide this network into at least 50 subnets. What is your new subnet mask as a result of this? Also list the networks." Ask yourself these questions:

2 Given the major network , 1) How many bits (bb) do I have to borrow to get XX subnets (50 in this example)? 2) If I borrow (bb) bits in order to get XX subnets, what is my new subnet mask? 3) What are the networks for this new subnet mask? 4) How many hosts do I have per network? 5) What are those hosts and what is their broadcast address? Answer: Given the major network , 1) How many bits (bb) do I have to borrow to get XX subnets (50 in this example)? Use the "magic equation": 2 N -2= # of networks N = # of bits "borrowed" (2 6 )-2 = 62 networks* * (2 5-2 would only yield 30 networks. We need 50 in this example. 62 is the best we can do and still meet the objectives.) 2) If I borrow (bb) bits in order to get XX subnets, what is my new subnet mask? Knowing that you borrowed six (6) bits, add the decimal values of those six bit positions together to yield the new subnet mask.

3 = 252 So, the new mask is the original mask ( ) plus these six bit positions. New mask: ) What are the networks for this new subnet mask? Determine the networks by examining the decimal value of the last bit position you "borrowed". Look at question #2. You borrowed 6 bits in order to get at least 50 subnets. Borrowing those six bits puts you at the 4 bit-position ( ). That bit position marks the start of the new network range and also marks how the network numbers will grow. So: A) Since this example takes us to the "4" bit-position our first network is B) Since we are at the "4" bit position, our networks grow by 4 each time. 1st network: nd network: rd network: th network: th network: th network: etc... Since this example will give us 62 networks we could keep counting until we finally got up to: 62 nd network:

4 The subnet mask for every one of these networks is ) How many hosts do I have per network? To answer this question you have to as yourself how many "host bits" are left over from the subnetting that you did. When we started we had: In Binary: = = = 255 So: = = The masked bits (a value of 1 in the subnet mask) are the network bits. The unmasked bits (a value of 0 in the subnet mask) are the host bits. Unmasked bits (host bits) = 16 # of hosts = (2 16 ) - 2 # of hosts = For our subnetted networks (using the first subnet as an example):

6 So, for : IP Mask Notes Subnet Address Host Host Host Host Host (a whole bunch of addresses in-between) Host Host Host Host Broadcast Address Note: This document assumes that subnet zero is NOT used.

### Number of bits needed to address hosts 8

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