1 Section 8- Pg. 4 Exercises 2,3 2. Using the z table, find the critical value for each. a) α=.5, two-tailed test, answer: -.96,.96 b) α=., left-tailed test, answer: -2.33, 2.33 c) α=.5, right-tailed test, answer: 2.58 d) α=., right-tailed test, answer: 2.33 e) α=.5, left- tailed test, answer: -.65 f) α=.2, left- tailed test, answer: -2.5 g) α =.5, right- tailed test, answer:.65 h) α=., two- tailed test, answer: i) α=.4, left- tailed test, answer: -.75 j) α=.2, right tailed test, answer: For each conjecture, state the null and alternative hypothesis. a) The average age of community college student is 24.6 years. Answer: : µ=24.6 and : µ 24.6 b) The average income of accountant is $5,497. Answer: : µ=$5,497 and : µ $5,497 c) The average age of attorney is greater than 25.4 years. Answer: : µ=25.4 and : µ>25.4 d) The average score of 5 high school basketball games is less than 88. Answer: : µ=88 and : µ<88 e) The average pulse rate of male marathon runners is less than 7 beats per minute. Answer: : µ=7 and : µ<7 f) The average cost of DVD player is $79.95 Answer: : µ=$79.95 and : µ $79.95
2 g) The average weight loss for sample of people who exercise 3 minutes per day for 6 weeks is 8.2 pounds. Answer: : µ=8.2 and : µ 8.2 Section 8-2 Pg. 42 Exercises 5, 6, 7, 5, 9, 2, 2, ealth Care Expenses The mean annual expenditure per 25- to 34-year-old consumer for health care is $468. This includes health insurance, medical services, and drugs and medical supplies. Students at a large university took a survey, and it was found that for a sample of 6 students, the mean health care expense was $52, and the population standard deviation is $98. Is there sufficient evidence at α =. to conclude that their health care expenditure differs from the national average of $468? Is the conclusion different at α =.5? : µ = 468 : µ 468 (claim) (a two-tailed test) n= 6 X = 52 s = 98 α =. CV.../ 2 =.5,.5 =.995, then look upin the bodyof Table E zcv = test value : z = = = 2.3 s n 98 6 Do not reject at α =.. There is not enough evidence to support the claim that average expenditure differs from $468. If α =.5, C.V=.96. Therefore reject at α = Peanut Production in Virginia. The average production of peanuts in the state of Virginia is 3 pounds per acre. A new plan food has been developed and is tested on 6 individual plots of land. The mean yield with the new plant food is 32 pounds of peanuts per acre with a standard deviation of 578 pounds. At α=.5, can one conclude that the average production has increased? : µ = 3 : µ > 3 (claim) (a right-tailed test) n= 6 X = 32 s = 578 α =.5 CV...5 =.95 thenlook upinthebody of Table E zcv = test value : z = = =.6 s n Since the test value does not fall within the critical region, we don t reject the null hypothesis. Therefore, there is not enough evidence to support the claim that the average production of peanuts in the state of Virginia has increased.
3 7. eights of -Year-Olds The average -year-old (both genders) is 29 inches tall. A random sample of 3 one-year-olds in a large day-care franchise resulted in the following heights. At α =.5, can it be concluded that the average height differs from 29 inches? : µ = 29 : µ 29 (claim) (a two- tailed test) n= 3 X = s = 2.6 α =.5 CV.. zcv = ± test value : z = = =.944 s n Do not reject the null hypothesis. There is enough evidence to reject the claim that the average height differs from 29 inches. 5) State whether the null hypothesis should be rejected on the basis of the given P-value. a) P-value=.258, α=.5, one tailed test If P-value α, reject the null hypothesis. Since.258 >.5, do not reject. b) P-value=.684, α=., two tailed test Since (.684)., reject. c) P-value=.53, α=., one tailed test Since.53 >., do not reject. d) P-value=.232, α=.5, two tailed test Since.232.5, reject. e) P-value=.2, α=., one tailed test Since.2., reject. 9) Burning Calories by playing tennis. A health researcher read that a 2-pound male can burn an average of 546 calories per hour playing tennis. Thirty-six males were randomly selected and tested. The
4 mean of the number of calories burned per hour was Test the claim that the average number of calories burned is actually less than 546, and find the P-value. On the basis of the P-value, should the null hypothesis be rejected at α=.? The standard deviation of the sample is 3. Can it be concluded that the average number of calories burned is less than originally thought? : µ = 546 : µ < 546 (claim) (a left- tailed test) n= 36 X = s = 3 α = z = = = 2.4 s n T.V=-2.4 Look up table E and find the area that corresponds to z=-2.4 The area corresponding to z= -2.4 is.82. Thus P-value is.82. Since.82 <., we reject. Therefore, there is enough evidence to support the claim that the average number of calories burned per hours is less than ) Breaking Strength of Cable. A special cable has a breaking strength of 8 pounds. The standard deviation of the population is 2 pounds. A researcher selects a sample of 2 cables and finds the average breaking strength is 793 pounds. Can one reject the claim that the breaking strength is 8 pounds? Find the P-value. Should the null hypothesis be rejected at α=.? Assume that the variable is normally distributed. : µ = 8 (claim) : µ 8 (a two- tailed test) n= 2 X = 793 σ = 2 α = z = = 2.6 σ n T.V=-2.6 Look up in table E for the area corresponding to the z = The corresponding area is.45. Since this is a two tail test, P-value is 2(.45) =.9. Since.9 <., we reject the null hypothesis. Thus, there is enough evidence to reject the claim that the breaking strength is 8 pounds. 2) Farm Size. The average farm size in the United States is 444 acres. A random sample of 4 farms in Oregon indicated a mean size of 43 acres, and the population standard deviation is 52 acres. At α =.5, can it be concluded that the average farm in Oregon differs from the national mean? Use the P-value method.
5 : µ = 444 : µ 444 (claim) (a two tailed test) n= 4 X = 43 s = 52 α = z = =.7 s n T.V=-.7 Look up in table E for the area corresponding to the z = -.7. The corresponding area is.446. Since this is a two tail test, P-value is 2(. 446) =.892. Is.892 <.5? No. Since P-value is not less than or equal to α, we do not reject the null hypothesis. Therefore, there is not enough evidence to support the claim that the mean differs from ) Sick Days A manager states that in his factory, the average number of days per year missed by the employees due to illness is less than the national average of. The following data show the number of days missed by 4 employees last year. Is there sufficient evidence to believe the manager statement at α=.5? Use the P-value method : µ = : µ < (claim) (a-left tailed test) n= 4 X = 5.25 s 3.63 α = z = = 8.67 s n Use table E to look up the area that corresponds to the z value of -8.67which is.. Thus P-value is... T.V=-8.67 Since. <.5, reject the null hypothesis. ence, there is enough evidence to support the claim that the average number of days per year missed by the employees due to illness is less than the national average of days.
6 Pg. 432 Exercises 8-3 4(a-f), 5, 6, 9,,7 Use the P-value Approach 4. Using Table F, find the P-value interval for each test value. a) t = 2.32, n=5, right-tailed d.f. = n-=5-=4.<p-value<.25 b) t =.945, n=28, two-tailed d.f. =n-=28-=27.5<p-value<. c) t = -.267, n=8, left-tailed d.f. =n-=8-=7.<p-value<.25 d) t =.562, n=7, two-tailed d.f. =n-=7-=6.<p-value<.2 e) t = 3.25, n=24, right-tailed d.f. =n-=24-=23 P-value<.5 f) t = -.45, n=5, left tai7led d.f. =n-=5-=4.<p-value<.25 Use the traditional method of hypothesis testing unless otherwise specified. Assume that the population is approximately normally distributed.
7 5. Veterinary Expenses of Cat Owners According to the American Pet Products Manufacturers Association, cat owners spend an average of $79 annually in routine veterinary visits. A random sample of local cat owners revealed that randomly selected owners spent an average of $25 with s _ $26. Is there a significant statistical difference at a α =.? Traditional Method n=, X = 25, s = 26 α =., df.. = 9 : µ = 79 : µ 79 (claim) (a two-tailed test) CV.. ± t = = = 3.62 s/ n 26 / Do not reject the null hypothesis since the test value does not fall within the critical region. There is not enough evidence to support the claim that the average expense is $79. Is P value α? NO, do not reject the null hypothesis since the P-value is not less than or equal to α =.. There is not enough evidence to support the claim that the average expense is $ Park Acreage A state executive claims that the average number of acres in western Pennsylvania state park is less than 2 acres. A random sample of five parks is selected, and the number of acres is shown. Atα =., is there enough evidence to support the claim?
8 Traditional method n= 5, X = 885.8, s = α =., df.. = 4 : µ = 2 : µ < 2 (claim) (a left- tailed test) CV.. = t = = =.4 s/ n / 5 Do not reject the null hypothesis since the test value does not fall within the critical region. There is not enough evidence to support the claim that the average acreage is less than 2. P-value method n= 5, X = 885.8, s = α =., df.. = 4 : µ = 2 : µ < 2 (claim) (a left- tailed test) t = = =.4 s/ n / 5 P value >. Is P value α? No, do not reject the null hypothesis since the P-value is not less than or equal to α =.. There is not enough evidence to support the claim that the average acreage is less than eights of Tall Buildings A researcher estimates that the average height of the buildings of 3 or more stories in a large city is at least 7 feet. A random sample of buildings is selected, and the heights in feet are shown. At α=.25, is there enough evidence to reject the claim?
9 Traditional method n=, X = 66.5, s = 9. α =.25, df.. = 9 : µ = 7 ( claim) : µ < 7 (a left-tail test) CV.. = t = = = 2.7 s/ n 9./ Reject the null hypothesis since the test value falls within the critical region. There is enough evidence to reject the claim that the average height of the buildings is at least 7 feet. P-value method n=, X = 66.5, s = 9. α =.25, df.. = 9 : µ = 7 ( claim) : µ < 7 (a left-tailed test) t = = = 2.7 s/ n 9./.< P value <.25 Reject the null hypothesis since P-value is less than or equal to α =.25. There is enough evidence to reject the claim that the average height of the buildings is at least 7 feet.. Cost of College The average undergraduate cost for tuition, fees, and room and board for two- year institutions last year was $3,252. The following year, a random sample of 2 twoyear institutions had a mean of $5,56 and a standard deviation of $35. Is there sufficient evidence at the α =. level to conclude that the mean cost has increased? Traditional method n= 2, X = $5,56, s = $3,5 α =., df.. = 9 : µ = 3252 : µ > 3252 (claim) (a right-tailed test) CV. = t = = = s/ n 35 / 2
10 Reject the null hypothesis since the test value falls within the critical region. There is sufficient evidence to support the claim that the average tuition cost has increased. P-value method n= 2, X = $5,56, s = $3,5 α =., df.. = 9 : µ = 3252 : µ > 3252 ( claim) right tail test t = = = s/ n 35 / 2 P value <.5 Is P value α? Is.5.? Yes! Therefore, we reject the null hypothesis. There is sufficient evidence to support the claim that the average tuition cost has increased. 7. Doctor Visits A report by the Gallup Poll stated that on average a woman visits her physician 5.8 times a year. A researcher randomly selects 2 women and obtained these data Atα =.5, can it be concluded that the average is still 5.8 visits per year? n= 2, X = 3.85, s = 2.59 α =.5, df.. = 9 : µ = 5.8 : µ 5.8 ( claim) (a two-tailed test) t = = = 3.46 s/ n 2.59 / 2 P value <. Is P value α?..5? yes, then we reject the null hypothesis. There is enough evidence to support the claim that the mean is not 5.8. Section 8-4 P44 #3, 6, 7, 9. (Use P-value method) 3) After school Snacks. In the Journal of the American Dietetic Association, it was reported that 54% of kids said that they had a snack after school. Test the claim that a random sample of 6 kids was selected
11 and 36 said that they had a snack after school Use α=. and the p-value method. On the basis of the results, should parents be concerned about their children eating a healthy snack? P=.54, n=6, x=36, α=., x 36 pˆ = = =.6 n 6 q=-p, q=-.54, q=.46 o: p=.54(claim) : p.54 A two-tailed test. pˆ p.6.54 z = = =.93. pq (.54)(.46) n 6 Find the area that corresponds to z=.93 in the E-table. The area is Since this is a two tail test, the P-value is 2( )= Then compare P(value) with α >.. Since the P(value) is not less than or equal to α, we do not reject the null hypothesis. There is enough evidence to support the claim that 54% of children have snacks after school. Yes, healthy snacks should be monitor by their parents. 6) Credit Card Usage. For certain year a study reports that the percentage of college students using credit cards was 83%. A college dean of student services feels that this is too high for her university, so she randomly selects 5 students and finds that 4 of them use credit cards. At α=.4, is she correct about her university? P=.83, n=5, x=4, α=.4, x 4 pˆ = = =.8 n 5 q=-p, q=-.83, q=.7 o: p=.83 i: p<.83 (claim) A left-tested test. pˆ p.8.83 z = = =.56 pq (.83)(.7) n 5 Find the area that corresponds to z= -.56 in the E-table. The area is.2877.
12 Thus, the P(value) is Then compare P(value) with α >.4. Since the P(value) is not less than or equal to α, we do not reject the null hypothesis. There is not enough evidence to support the claim that students who use credit cards are less than 83%. 7) Borrowing library Books. For American using library services, the American Library association (ALA)claims that 67% borrow books. A library director feels this is not true, so she randomly selects borrowers and finds that 82 borrowed books. Can he show that the ALA claims is incorrect? Use α=.5? P=.67, n=, x=82, α=.5, x 82 pˆ = = =.82 n q=-p, q=-.67, q=.33 o: p=.67 i: p.67(claim) A two- tailed test. pˆ p z = = = 3.9 pq (.67)(.33) n Find the area that corresponds to z=3.9 in the E-table. The area is Now the P(value) is 2(-.9993)=.4 Then compare P(value) with α..4 <.5. Since the P(value) is less than α, we reject the null hypothesis. There is enough evidence to support the claim that the percentage is not 67%. 9) Football Injuries. A report by the NCAA states that 57.6% of football injuries occur during practices. Ahead trainer claims that this is too high for his conference, so he randomly selects 36 injuries and finds that 7 occurred during practices. Is his claim correct, at α=.5? P=.576, n=36, x=7, α=.5, x 7 pˆ = = =.472 n 36 q=-p, q=-.576, q=.424 o: p=.576 i: p<.576 (claim) A left tailed- test.
13 pˆ p z = = =.26 pq (.576)(.424) n 36 Find the area that corresponds to z= -.26 in the E-table. The area is.38. Thus, the P(value) is.38. Then compare P(value) with α..38 >.5. Since the P(value) is not less than or equal to α, we do not reject the null hypothesis. There is not enough evidence to support the claim that the football injuries during practice is less than 57.6%.
Wording of Final Conclusion Slide 1 8.3: Assumptions for Testing Slide 2 Claims About Population Means 1) The sample is a simple random sample. 2) The value of the population standard deviation σ is known
A Trial Analogy for Statistical Slide 1 Hypothesis Testing Legal Trial Begin with claim: Smith is not guilty If this is rejected, we accept Smith is guilty reasonable doubt Present evidence (facts) Evaluate
CHAPTER 8 Learning Objectives C H A P T E R E I G H T Hypothesis Testing 1 Outline 8-1 Steps in Traditional Method 8-2 z Test for a Mean 8-3 t Test for a Mean 8-4 z Test for a Proportion 8-5 2 Test for
C H 8A P T E R Outline 8 1 Steps in Traditional Method 8 2 z Test for a Mean 8 3 t Test for a Mean 8 4 z Test for a Proportion 8 6 Confidence Intervals and Copyright 2013 The McGraw Hill Companies, Inc.
Hypothesis Testing --- One Mean A hypothesis is simply a statement that something is true. Typically, there are two hypotheses in a hypothesis test: the null, and the alternative. Null Hypothesis The hypothesis
Chapter 8: Hypothesis Testing for One Population Mean, Variance, and Proportion Learning Objectives Upon successful completion of Chapter 8, you will be able to: Understand terms. State the null and alternative
Name: Date: 1. Determine whether each of the following statements is true or false. A) The margin of error for a 95% confidence interval for the mean increases as the sample size increases. B) The margin
Hypothesis testing: Examples AMS7, Spring 2012 Example 1: Testing a Claim about a Proportion Sect. 7.3, # 2: Survey of Drinking: In a Gallup survey, 1087 randomly selected adults were asked whether they
Chapter 8: Hypothesis Testing of a Single Population Parameter THE LANGUAGE OF STATISTICAL DECISION MAKING DEFINITIONS: The population is the entire group of objects or individuals under study, about which
Math 251, Review Questions for Test 3 Rough Answers 1. (Review of some terminology from Section 7.1) In a state with 459,341 voters, a poll of 2300 voters finds that 45 percent support the Republican candidate,
Math 251: Practice Questions for Test III Hints and Answers III.A: The Central Limit Theorem and Sampling Distributions. III.A.1 The heights of 18-year-old men are approximately normally distributed with
Section 7.1 Introduction to Hypothesis Testing Schrodinger s cat quantum mechanics thought experiment (1935) Statistical Hypotheses A statistical hypothesis is a claim about a population. Null hypothesis
Hypothesis Tests for a Population Proportion MATH 130, Elements of Statistics I J. Robert Buchanan Department of Mathematics Fall 2015 Review: Steps of Hypothesis Testing 1. A statement is made regarding
Hypothesis Testing (unknown σ) Business Statistics Recall: Plan for Today Null and Alternative Hypotheses Types of errors: type I, type II Types of correct decisions: type A, type B Level of Significance
Stats Review Chapters 9-10 Created by Teri Johnson Math Coordinator, Mary Stangler Center for Academic Success Examples are taken from Statistics 4 E by Michael Sullivan, III And the corresponding Test
BA 275 Review Problems - Week 5 (10/23/06-10/27/06) CD Lessons: 48, 49, 50, 51, 52 Textbook: pp. 380-394 1. Does vigorous exercise affect concentration? In general, the time needed for people to complete
Section 8.2-8.5 Null and Alternative Hypotheses... The null hypothesis,, is a statement that the value of a population parameter is equal to some claimed value. :=0.5 The alternative hypothesis,, is the
Ch. 8 Hypothesis Testing 8.1 Foundations of Hypothesis Testing Definitions In statistics, a hypothesis is a claim about a property of a population. A hypothesis test is a standard procedure for testing
8-2 Basics of Hypothesis Testing Definitions This section presents individual components of a hypothesis test. We should know and understand the following: How to identify the null hypothesis and alternative
Chapter 8 Hypothesis Testing 1 Chapter 8 Hypothesis Testing 8-1 Overview 8-2 Basics of Hypothesis Testing 8-3 Testing a Claim About a Proportion 8-5 Testing a Claim About a Mean: s Not Known 8-6 Testing
Today: Sections 13.1 to 13.3 ANNOUNCEMENTS: We will finish hypothesis testing for the 5 situations today. See pages 586-587 (end of Chapter 13) for a summary table. Quiz for week 8 starts Wed, ends Monday
Regression Analysis: A Complete Example This section works out an example that includes all the topics we have discussed so far in this chapter. A complete example of regression analysis. PhotoDisc, Inc./Getty
STATISTICS 8, FINAL EXAM NAME: KEY Seat Number: Last six digits of Student ID#: Circle your Discussion Section: 1 2 3 4 Make sure you have 8 pages. You will be provided with a table as well, as a separate
Ch. 10 Chi SquareTests and the F-Distribution 10.1 Goodness of Fit 1 Find Expected Frequencies Provide an appropriate response. 1) The frequency distribution shows the ages for a sample of 100 employees.
Chapter 9 Review Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples selected from normally
Chapter 7 Hypothesis Testing with One Sample 71 Introduction to Hypothesis Testing Hypothesis Tests A hypothesis test is a process that uses sample statistics to test a claim about the value of a population
Chapter 8 Hypothesis Testing Hypothesis In statistics, a hypothesis is a claim or statement about a property of a population. A hypothesis test (or test of significance) is a standard procedure for testing
Chapter Additional: Standard Deviation and Chi- Square Chapter Outline: 6.4 Confidence Intervals for the Standard Deviation 7.5 Hypothesis testing for Standard Deviation Section 6.4 Objectives Interpret
Z-test About One Mean ypothesis Testing Population Mean The Z-test about a mean of population we are using is applied in the following three cases: a. The population distribution is normal and the population
Open book and note Calculator OK Multiple Choice 1 point each MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find the mean for the given sample data.
General Method: Difference of Means 1. Calculate x 1, x 2, SE 1, SE 2. 2. Combined SE = SE1 2 + SE2 2. ASSUMES INDEPENDENT SAMPLES. 3. Calculate df: either Welch-Satterthwaite formula or simpler df = min(n
STT315 Practice Ch 5-7 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Solve the problem. 1) The length of time a traffic signal stays green (nicknamed
Review for Test 5 STA 2023 spr 2014 Name Given the linear correlation coefficient r and the sample size n, determine the critical values of r and use your finding to state whether or not the given r represents
Section 8 6 x 2 Test for a Variance or Standard Deviation 437 This test uses the P-value method. Therefore, it is not necessary to enter a significance level. 1. Select MegaStat>Hypothesis Tests>Proportion
CHAPTER 5. A POPULATION MEAN, CONFIDENCE INTERVALS AND HYPOTHESIS TESTING 5.1 Concepts When a number of animals or plots are exposed to a certain treatment, we usually estimate the effect of the treatment
CHAPTER 9 HYPOTHESIS TESTING The TI-83 Plus and TI-84 Plus fully support hypothesis testing. Use the key, then highlight TESTS. The options used in Chapter 9 are given on the two screens. TESTING A SINGLE
Student: Date: Instructor: Doug Ensley Course: MAT117 01 Applied Statistics - Ensley Assignment: Online 12 - Sections 9.1 and 9.2 1. Does a P-value of 0.001 give strong evidence or not especially strong
Quantitative Methods 2013 Hypothesis Testing with One Sample 1 Concept of Hypothesis Testing Testing Hypotheses is another way to deal with the problem of making a statement about an unknown population
Statistics for Management II-STAT 362-Final Review Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. 1. The ability of an interval estimate to
ch8aprac Express the null hypothesis and the alternative hypothesis in symbolic form. Use the correct symbol (µ, p, ) for the indicated parameter. 1) An entomologist writes an article in a scientific journal
ISyE 2028 Basic Statistical Methods - Fall 2015 Bonus Project: Big Data Analytics Final Report: Time spent on social media Abstract: The growth of social media is astounding and part of that success was
Hypothesis test In statistics, a hypothesis is a claim or statement about a property of a population. A hypothesis test (or test of significance) is a standard procedure for testing a claim about a property
Stats: Test Review Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question Provide an appropriate response. ) Given H0: p 0% and Ha: p < 0%, determine
CHAPTER 11: FACTS ABOUT THE CHI- SQUARE DISTRIBUTION Exercise 1. If the number of degrees of freedom for a chi-square distribution is 25, what is the population mean and standard deviation? mean = 25 and
STATISTICS 151 SECTION 1 FINAL EXAM MAY 2 2009 This is an open book exam. Course text, personal notes and calculator are permitted. You have 3 hours to complete the test. Personal computers and cellphones
STATISTICS/GRACEY EXAM 3 PRACTICE/CH. 8-9 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find the P-value for the indicated hypothesis test. 1) A
9. Basic Principles of Hypothesis Testing Basic Idea Through an Example: On the very first day of class I gave the example of tossing a coin times, and what you might conclude about the fairness of the
ypothesis Testing I The testing process:. Assumption about population(s) parameter(s) is made, called null hypothesis, denoted. 2. Then the alternative is chosen (often just a negation of the null hypothesis),
CHAPTER 10: HYPOTHESIS TESTING WITH TWO SAMPLES Exercise 1. Exercise 2. Exercise 3. Indicate if the hypothesis test is for a. independent group means, population standard deviations, and/or variances known
Third Midterm Exam (MATH1070 Spring 2012) Instructions: This is a one hour exam. You can use a notesheet. Calculators are allowed, but other electronics are prohibited. 1. [40pts] Multiple Choice Problems
Mind on Statistics Chapter 13 Sections 13.1-13.2 1. Which statement is not true about hypothesis tests? A. Hypothesis tests are only valid when the sample is representative of the population for the question
Provide an appropriate response. 1) Suppose that x is a normally distributed variable on each of two populations. Independent samples of sizes n1 and n2, respectively, are selected from the two populations.
Practice for chapter 9 and 10 Disclaimer: the actual exam does not mirror this. This is meant for practicing questions only. The actual exam in not multiple choice. Find the number of successes x suggested
FINAL EXAM REVIEW - Fa 13 Determine which of the four levels of measurement (nominal, ordinal, interval, ratio) is most appropriate. 1) The temperatures of eight different plastic spheres. 2) The sample
Module 2 Probability and Statistics BASIC CONCEPTS Multiple Choice Identify the choice that best completes the statement or answers the question. 1. The standard deviation of a standard normal distribution
Chapter 7 Hypothesis Testing with One Sample 7.1 Introduction to Hypothesis Testing Hypothesis Tests A hypothesis test is a process that uses sample statistics to test a claim about the value of a population
Sample Multiple Choice Questions for the material since Midterm 2. Sample questions from Midterms and 2 are also representative of questions that may appear on the final exam.. A randomly selected sample
Inferences Based on a Single Sample Tests of Hypothesis 11 Inferences Based on a Single Sample Tests of Hypothesis Chapter 8 8. used to decide whether or not to reject the null hypothesis in favor of the
Chapter 10 Hypothesis Testing: Two Means, Paired Data, Two Proportions 10.1 Hypothesis Testing: Two Population Means and Two Population Proportions 1 10.1.1 Student Learning Objectives By the end of this
Final Exam Review MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) A researcher for an airline interviews all of the passengers on five randomly
1 Hypotheses test about µ if σ is not known In this section we will introduce how to make decisions about a population mean, µ, when the standard deviation is not known. In order to develop a confidence
Statistics Class Level Test Mu Alpha Theta State 2008 1. Which of the following are true statements? I. The histogram of a binomial distribution with p = 0.5 is always symmetric no matter what n, the number
CHAPTER IV FINDINGS AND CONCURRENT DISCUSSIONS Hypothesis 1: People are resistant to the technological change in the security system of the organization. Hypothesis 2: information hacked and misused. Lack
The Islamic University of Gaza Faculty of Commerce Department of Economics and Political Sciences An Introduction to Statistics Course (ECOE 130) Spring Semester 011 Chapter 10- TWO-SAMPLE TESTS Practice
Lecture #10 Chapter 10 Correlation and Regression The main focus of this chapter is to form inferences based on sample data that come in pairs. Given such paired sample data, we want to determine whether
Questions about the Assignment For Part II, only one person calculated the 95% confidence interval using the standard error method. Exam #1 Wednesday, July 18 th Exam will be written and in-class. They
Hypothesis Tests for 1 sample Proportions 1. Hypotheses. Write the null and alternative hypotheses you would use to test each of the following situations. a) A governor is concerned about his "negatives"
Section 7.1 - Introduction to Hypothesis Testing Chapter 7 Objectives: State a null hypothesis and an alternative hypothesis Identify type I and type II errors and interpret the level of significance Determine
Independent t- Test (Comparing Two Means) The objectives of this lesson are to learn: the definition/purpose of independent t-test when to use the independent t-test the use of SPSS to complete an independent
BA 275 Review Problems - Week 6 (10/30/06-11/3/06) CD Lessons: 53, 54, 55, 56 Textbook: pp. 394-398, 404-408, 410-420 1. Which of the following will increase the value of the power in a statistical test
Introduction to Hypothesis Testing 9-1 Learning Outcomes Outcome 1. Formulate null and alternative hypotheses for applications involving a single population mean or proportion. Outcome 2. Know what Type
Chapter 9 Hypothesis Testing: Single Mean and Single Proportion 9.1 Hypothesis Testing: Single Mean and Single Proportion 1 9.1.1 Student Learning Objectives By the end of this chapter, the student should
DEFINITION The power of a test is the of a hypothesis. The of the is by using a particular and a value of the that is an to the value assumed in the. POWER AND THE DESIGN OF EXPERIMENTS Just as is a common
Name: Date: 1. A sample of 25 different payroll departments found that the employees worked an average of 310.3 days a year with a standard deviation of 23.8 days. What is the 90% confidence interval for
Probability, Binomial Distributions and Hypothesis Testing Vartanian, SW 540 1. Assume you are tossing a coin 11 times. The following distribution gives the likelihoods of getting a particular number of
Homework #3 is due Friday by 5pm. Homework #4 will be posted to the class website later this week. It will be due Friday, March 7 th, at 5pm. Political Science 15 Lecture 12: Hypothesis Testing Sampling
Hypothesis Testing April 21, 2009 Your Claim is Just a Hypothesis I ve never made a mistake. Once I thought I did, but I was wrong. Your Claim is Just a Hypothesis Confidence intervals quantify how sure
Note to Students: This practice exam is intended to give you an idea of the type of questions the instructor asks and the approximate length of the exam. It does NOT indicate the exact questions or the
Chapter 24 Two-Way Tables and the Chi-Square Test We look at two-way tables to determine association of paired qualitative data. We look at marginal distributions, conditional distributions and bar graphs.
Case l: Watchdog, Inc: Keeping hospitals honest Insurance companies hire independent firms like Watchdog, Inc to review their hospital bills. They pay Watchdog a percentage of the overcharges it finds.
1 Final Review 2 Review 2.1 CI 1-propZint Scenario 1 A TV manufacturer claims in its warranty brochure that in the past not more than 10 percent of its TV sets needed any repair during the first two years
Math Objectives Students will be able to identify the conditions that need to be met to perform inference procedures for the slope of a regression line. Students will be able to interpret the results of
Chapter 8 Student Lecture Notes 8-1 Chapter 8 Introduction to Hypothesis Testing Fall 26 Fundamentals of Business Statistics 1 Chapter Goals After completing this chapter, you should be able to: Formulate
STA2023 Module 10 Test Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. A hypothesis test is to be performed. Determine the null and alternative
Opening Example CHAPTER 13 SIMPLE LINEAR REGREION SIMPLE LINEAR REGREION! Simple Regression! Linear Regression Simple Regression Definition A regression model is a mathematical equation that descries the
blu49076_ch09.qxd 5/1/2003 8:19 AM Page 431 c h a p t e r 9 9 Testing the Difference Between Two Means, Two Variances, and Two Proportions Outline 9 1 Introduction 9 2 Testing the Difference Between Two
Inferential Statistics Sampling and the normal distribution Z-scores Confidence levels and intervals Hypothesis testing Commonly used statistical methods Inferential Statistics Descriptive statistics are
HYPOTHESIS TESTING (ONE SAMPLE) - CHAPTER 7 1 PREVIOUSLY used confidence intervals to answer questions such as... You know that 0.25% of women have red/green color blindness. You conduct a study of men
STAT E-150 - Statistical Methods Assignment 9 Solutions Exercises 12.8, 12.13, 12.75 For each test: Include appropriate graphs to see that the conditions are met. Use Tukey's Honestly Significant Difference