Factoring Polynomials: Factoring by Grouping



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OpenStax-CNX module: m21901 1 Factoring Polynomials: Factoring by Grouping Wade Ellis Denny Burzynski This work is produced by OpenStax-CNX and licensed under the Creative Commons Attribution License 3.0 Abstract This module is from Elementary Algebra by Denny Burzynski and Wade Ellis, Jr. Factoring is an essential skill for success in algebra and higher level mathematics courses. Therefore, we have taken great care in developing the student's understanding of the factorization process. The technique is consistently illustrated by displaying an empty set of parentheses and describing the thought process used to discover the terms that are to be placed inside the parentheses. The factoring scheme for special products is presented with both verbal and symbolic descriptions, since not all students can interpret symbolic descriptions alone. Two techniques, the standard "trial and error" method, and the "collect and discard" method a method similar to the "ac" method), are presented for factoring trinomials with leading coecients dierent from 1. Objectives of this module: know how to factor a polynomial using the grouping method and when to try the grouping method. 1 Overview Using Grouping to Factor a Polynomial Knowing when to Try the Grouping Method 2 Using Grouping to Factor a Polynomial Sometimes a polynomial will not have a particular factor common to every term. However, we may still be able to produce a factored form for the polynomial. The polynomial x 3 + 3x 2 6x 18has no single factor that is common to every term. However, we notice that if we group together the rst two terms and the second two terms, we see that each resulting binomial has a particular factor common to both terms. Factor x 2 out of the rst two terms, and factor 6 out of the second two terms. x 2 x + 3) 6 x + 3) Version 1.4: May 31, 2009 6:51 pm +0000 http://creativecommons.org/licenses/by/3.0/

OpenStax-CNX module: m21901 2 Now look closely at this binomial. Each of the two terms contains the factor x + 3). Factor out x + 3). x + 3) x 2 6 ) is the nal factorization. x 3 + 3x 2 6x 18 = x + 3) x 2 6 ) 3 Knowing when to Try the Grouping Method We are alerted to the idea of grouping when the polynomial we are considering has either of these qualities: 1. no factor common to all terms 2. an even number of terms When factoring by grouping, the sign + or )of the factor we are taking out will usually but not always) be the same as the sign of the rst term in that group. 4 Sample Set A Example 1 Factor 8a 2 b 4 4b 4 + 14a 2 7. 1. We notice there is no factor common to all terms. 2. We see there are four terms, an even number. 3. We see that terms 1 and 2 have +4b 4 in common since the 1st term in the group is +8a 2 b 4. 4. We notice that the 3rd and 4th terms have +7 in common since the 1st term in the group is +14a 2 ). 8a 2 b 4 4b 4 + 14a 2 7 = 2a 2-1)4b 4 +7) 5 Practice Set A Use the grouping method to factor the following polynomials. Exercise 1 Solution on p. 5.) ax + ay + bx + by Exercise 2 Solution on p. 5.) 2am + 8m + 5an + 20n Exercise 3 Solution on p. 5.) a 2 x 3 + 4a 2 y 3 + 3bx 3 + 12by 3 Exercise 4 Solution on p. 5.) 15mx + 10nx 6my 4ny Exercise 5 Solution on p. 5.) 40abx 24abxy 35c 2 x + 21c 2 xy Exercise 6 Solution on p. 5.) When factoring the polynomial 8a 2 b 4 4b 4 +14a 2 7 in Sample Set A, we grouped together terms1 and 2 and 3 and 4. Could we have grouped together terms1 and 3 and 2 and 4? Try this. 8a 2 b 4 4b 4 + 14a 2 7 =

OpenStax-CNX module: m21901 3 Do we get the same result? If the results do not look precisely the same, recall the commutative property of multiplication. 6 Exercises For the following problems, use the grouping method to factor the polynomials. Some polynomials may not be factorable using the grouping method. Exercise 7 Solution on p. 5.) 2ab + 3a + 18b + 27 Exercise 8 xy 7x + 4y 28 Exercise 9 Solution on p. 5.) xy + x + 3y + 3 Exercise 10 mp + 3mq + np + 3nq Exercise 11 Solution on p. 5.) ar + 4as + 5br + 20bs Exercise 12 14ax 6bx + 21ay 9by Exercise 13 Solution on p. 5.) 12mx 6bx + 21ay 9by Exercise 14 36ak 8ah 27bk + 6bh Exercise 15 Solution on p. 5.) a 2 b 2 + 2a 2 + 3b 2 + 6 Exercise 16 3n 2 + 6n + 9m 3 + 12m Exercise 17 Solution on p. 5.) 8y 4 5y 3 + 12z 2 10z Exercise 18 x 2 + 4x 3y 2 + y Exercise 19 Solution on p. 5.) x 2 3x + xy 3y Exercise 20 2n 2 + 12n 5mn 30m Exercise 21 Solution on p. 5.) 4pq 7p + 3q 2 21 Exercise 22 8x 2 + 16xy 5x 10y Exercise 23 Solution on p. 5.) 12s 2 27s 8st + 18t Exercise 24 15x 2 12x 10xy + 8y Exercise 25 Solution on p. 5.) a 4 b 4 + 3a 5 b 5 + 2a 2 b 2 + 6a 3 b 3

OpenStax-CNX module: m21901 4 Exercise 26 4a 3 bc 14a 2 bc 3 + 10abc 2 35bc 4 Exercise 27 Solution on p. 5.) 5x 2 y 3 z + 3x 3 yw 10y 3 z 2 6wxyz Exercise 28 a 3 b 2 cd + abc 2 dx a 2 bxy cx 2 y Exercise 29 Solution on p. 5.) 5m 10 n 17 p 3 m 6 n 7 p 4 40m 4 n 10 qt 2 + 8pqt 2 7 Exercises for Review Exercise 30 here 1 ) Simplify x 5 y 3) x 2 y ). Exercise 31 Solution on p. 5.) here 2 ) Use scientic notation to nd the product of 3 10 5) 2 10 2). Exercise 32 here 3 ) Find the domain of the equation y = 6 x+5. Exercise 33 Solution on p. 5.) here 4 ) Construct the graph of the inequality y 2. Exercise 34 here 5 ) Factor 8a 4 b 4 + 12a 3 b 5 8a 2 b 3. 1 "Basic Properties of Real Numbers: Rules of Exponents" <http://cnx.org/content/m21900/latest/> 2 "Basic Operations with Real Numbers: Scientic Notation" <http://cnx.org/content/m21879/latest/> 3 "Algebraic Expressions and Equations: Terminology Associated with Equations" <http://cnx.org/content/m21849/latest/> 4 "Solving Linear Equations and Inequalities: Linear Equations in Two Variables" <http://cnx.org/content/m21982/latest/> 5 "Factoring Polynomials: The Greatest Common Factor" <http://cnx.org/content/m21913/latest/>

OpenStax-CNX module: m21901 5 Solutions to Exercises in this Module a + b) x + y) 2m + 5n) a + 4) a 2 + 3b ) x 3 + 4y 3) 5x 2y) 3m + 2n) x 8ab 7c 2) 5 3y) yes 2b + 3) a + 9) y + 1) x + 3) a + 5b) r + 4s) 3 4mx 2bx + 7ay 3by) Not factorable by grouping a 2 + 3 ) b 2 + 2 ) Not factorable by grouping x + y) x 3) Not factorable by grouping 4s 9) 3s 2t) a 2 b 2 a 2 b 2 + 2 ) 1 + 3ab) y 5y 2 z + 3xw ) x 2 2z ) m 6 n 7 p 3 8qt 2) 5m 4 n 10 p ) 6 10 3