Colloidal Materials: Part I



Similar documents
A. Types of Mixtures:

Lecture 24 - Surface tension, viscous flow, thermodynamics

Chapter 11 Properties of Solutions

Basic Principles in Microfluidics

Displacement (x) Velocity (v) Acceleration (a) x = f(t) differentiate v = dx Acceleration Velocity (v) Displacement x

Fluid Mechanics: Static s Kinematics Dynamics Fluid

The Viscosity of Fluids

XI / PHYSICS FLUIDS IN MOTION 11/PA

Lecture L2 - Degrees of Freedom and Constraints, Rectilinear Motion

Chapter 13 - Solutions

Physics 9e/Cutnell. correlated to the. College Board AP Physics 1 Course Objectives

Lecture 5 Hemodynamics. Description of fluid flow. The equation of continuity

Lecture L22-2D Rigid Body Dynamics: Work and Energy

The Viscosity of Fluids

Chapter 5 Using Newton s Laws: Friction, Circular Motion, Drag Forces. Copyright 2009 Pearson Education, Inc.

Differential Relations for Fluid Flow. Acceleration field of a fluid. The differential equation of mass conservation

4 Microscopic dynamics

PS-6.2 Explain the factors that determine potential and kinetic energy and the transformation of one to the other.

KINETIC MOLECULAR THEORY OF MATTER

Physics 111: Lecture 4: Chapter 4 - Forces and Newton s Laws of Motion. Physics is about forces and how the world around us reacts to these forces.

Dynamics in nanoworlds

1 The basic equations of fluid dynamics

Forces. Definition Friction Falling Objects Projectiles Newton s Laws of Motion Momentum Universal Forces Fluid Pressure Hydraulics Buoyancy

Physics 1A Lecture 10C

1. Fluids Mechanics and Fluid Properties. 1.1 Objectives of this section. 1.2 Fluids

AP1 Oscillations. 1. Which of the following statements about a spring-block oscillator in simple harmonic motion about its equilibrium point is false?

Lecture 17. Last time we saw that the rotational analog of Newton s 2nd Law is

Micellar structures and Whisky

Particle motion, particle size, and aerodynamic diameter

ZETA POTENTIAL ANALYSIS OF NANOPARTICLES

For Water to Move a driving force is needed

Pure Substances, Mixtures, and Solutions

Chemistry B11 Chapter 6 Solutions and Colloids

Centripetal Force. This result is independent of the size of r. A full circle has 2π rad, and 360 deg = 2π rad.

MEASUREMENT OF VISCOSITY OF LIQUIDS BY THE STOKE S METHOD

7. DYNAMIC LIGHT SCATTERING 7.1 First order temporal autocorrelation function.

CE 204 FLUID MECHANICS

Review D: Potential Energy and the Conservation of Mechanical Energy

01 The Nature of Fluids

39th International Physics Olympiad - Hanoi - Vietnam Theoretical Problem No. 3

SIZE OF A MOLECULE FROM A VISCOSITY MEASUREMENT

Ch 7 Kinetic Energy and Work. Question: 7 Problems: 3, 7, 11, 17, 23, 27, 35, 37, 41, 43

Millikan Oil Drop Experiment Matthew Norton, Jurasits Christopher, Heyduck William, Nick Chumbley. Norton 0

Mechanics 1: Conservation of Energy and Momentum

Centripetal force, rotary motion, angular velocity, apparent force.

Introduction. Emulsify with water. Asphalt Emulsions 101. Asphalt Binder Properties. Why Heat Asphalt? So It Can Be:

Lecture 19: Planet Formation I. Clues from the Solar System

Columbia University Department of Physics QUALIFYING EXAMINATION

Collision of a small bubble with a large falling particle

Name Class Date. In the space provided, write the letter of the term or phrase that best completes each statement or best answers each question.


Fluids and Solids: Fundamentals

Statistical Mechanics, Kinetic Theory Ideal Gas. 8.01t Nov 22, 2004

PHYS 101-4M, Fall 2005 Exam #3. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

du u U 0 U dy y b 0 b

Chapter 8: Rotational Motion of Solid Objects

Physics 181- Summer Experiment #8 1 Experiment #8, Measurement of Density and Archimedes' Principle

Swissmetro travels at high speeds through a tunnel at low pressure. It will therefore undergo friction that can be due to:

Mathematical Modeling and Engineering Problem Solving

Salem Community College Course Syllabus. Course Title: Physics I. Course Code: PHY 101. Lecture Hours: 2 Laboratory Hours: 4 Credits: 4

Chapter 10 Rotational Motion. Copyright 2009 Pearson Education, Inc.

Physics 2A, Sec B00: Mechanics -- Winter 2011 Instructor: B. Grinstein Final Exam

1. The Kinetic Theory of Matter states that all matter is composed of atoms and molecules that are in a constant state of constant random motion

Zeta Potential: A Complete Course in 5 Minutes

Sample Questions for the AP Physics 1 Exam

Center of Gravity. We touched on this briefly in chapter 7! x 2

Copyright 2011 Casa Software Ltd. Centre of Mass

HIGH VOLTAGE ELECTROSTATIC PENDULUM

CHEMISTRY STANDARDS BASED RUBRIC ATOMIC STRUCTURE AND BONDING

Convection in water (an almost-incompressible fluid)

Chapter 28 Fluid Dynamics

11. Rotation Translational Motion: Rotational Motion:

Viscous flow in pipe

Ch 2 Properties of Fluids - II. Ideal Fluids. Real Fluids. Viscosity (1) Viscosity (3) Viscosity (2)

Heating & Cooling in Molecular Clouds

Physics Notes Class 11 CHAPTER 3 MOTION IN A STRAIGHT LINE

Physics 11 Assignment KEY Dynamics Chapters 4 & 5

Bruce B. Weiner, Walther W. Tscharnuter, David Fairhurst Brookhaven Instruments Corporation Holtsville, NY US

Topic 3b: Kinetic Theory

Overview of DLVO Theory

Lecture L5 - Other Coordinate Systems

Chapter 18 Temperature, Heat, and the First Law of Thermodynamics. Problems: 8, 11, 13, 17, 21, 27, 29, 37, 39, 41, 47, 51, 57

Lecture L14 - Variable Mass Systems: The Rocket Equation

Contents. Microfluidics - Jens Ducrée Physics: Navier-Stokes Equation 1

Particle Size Analysis

ENERGY CONSERVATION The First Law of Thermodynamics and the Work/Kinetic-Energy Theorem

Lecture-IV. Contact forces & Newton s laws of motion

PHYS 211 FINAL FALL 2004 Form A

Natural Convection. Buoyancy force

Chapter 27 Static Fluids

Grade 8 Science Chapter 9 Notes

Midterm Solutions. mvr = ω f (I wheel + I bullet ) = ω f 2 MR2 + mr 2 ) ω f = v R. 1 + M 2m

SURFACE TENSION. Definition

Indiana's Academic Standards 2010 ICP Indiana's Academic Standards 2016 ICP. map) that describe the relationship acceleration, velocity and distance.

SYNERGISTIC APPLICATION OF ADVANCED PRIMARY AND SECONDARY WASTEWATER TREATMENT SYSTEMS

Chapter 12 IVP Practice Problems

C-100E Strong Acid Cation Exchange Resin (For use in water softening applications)

New Polyelectrolyte Emulsion Breaker Improves Oily Wastewater Cleanup at Lower Usage Rates

Transcription:

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 Colloidal Materials: Part I Dr. Pallab Ghosh Associate Professor Department of Chemical Engineering IIT Guwahati, Guwahati 781039 India Joint Initiative of IITs and IISc Funded by MHRD 1/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 Table of Contents Section/Subsection Page No. 1.2.1 Definition of colloids 3 1.2.2 Various types of colloid dispersions with examples 4 1.2.3 Classification of colloids 5 1.2.4 Coagulation and flocculation 6 1.2.5 Critical coagulation concentration 6 1.2.6 Thermodynamic and kinetic stabilities of colloids 8 1.2.7 Sedimentation in gravitational field 8 1.2.8 Sedimentation in centrifugal field 10 Exercise 13 Suggested reading 14 Joint Initiative of IITs and IISc Funded by MHRD 2/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 1.2.1 Definition of colloids A colloid is defined as a particle that has some linear dimension between 1 nm and 1 m. A dispersion of such particles is called a colloid dispersion. Some examples are shown in Fig. 1.2.1. (a) (b) Fig. 1.2.1 Examples of colloidal matters: (a) polystyrene latex, and (b) spherical surfactant micelle. Sometimes in applied colloid science, the upper limit of size is extended to much larger values (e.g., several hundreds of micrometres). Examples are emulsions (Fig. 1.2.2) and foams. Fig. 1.2.2 Emulsion of paraffin-oil in water (source: P. Ghosh, Colloid and Interface Science, PHI Learning, New Delhi, 2009; reproduced by permission). Although the size of the particles is very small, a colloid dispersion is quite different from a solution. For example, a true solution passe through parchment or cellophane papers, but a colloid dispersion cannot; only the continuous medium of the dispersion seeps through. Some of the dispersions pass through an ordinary filter paper like a true solution. The particles of the dispersed phase can be viewed easily in an ultramicroscope or an electron microscope. They can be discerned by light scattering. Joint Initiative of IITs and IISc Funded by MHRD 3/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 1.2.2 Various types of colloid dispersions with examples Some examples of colloid dispersions are given in Table 1.2.1. Table 1.2.1 Colloid dispersions Dispersed phase Dispersion medium Name Example Liquid Gas Liquid aerosol Fog, cloud, liquid sprays (e.g., hair spray) Solid Gas Solid aerosol Smoke, dust Gas Liquid Foam Foam on surfactant solutions, fireextinguisher foam Liquid Liquid Emulsion Milk, mayonnaise Solid Liquid Sol, paste, colloid suspension Gold sol, silver iodide sol, toothpaste, pigmented ink, paint Gas Solid Solid foam Insulating foam, expanded polystyrene Liquid Solid Solid emulsion Pearl, bituminous road paving, ice cream Solid Solid Solid suspension, solid dispersion Ruby (gold) glass, carbon in steel Joint Initiative of IITs and IISc Funded by MHRD 4/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 1.2.3 Classification of colloids Freundlich (1926) classified the colloid systems into two categories: (i) lyophilic (or solvent-loving) colloids (ii) lyophobic (or solvent-fearing) colloids If water is the dispersion medium, the terms hydrophilic and hydrophobic colloids are used, respectively. Lyophilic colloid dispersions are formed quite easily by the spontaneous dispersion of the colloid particles in the medium. For example, the swelling of gelatin in water indicates the high affinity between the water and gelatin molecules. Classic examples of the lyophilic colloids are macromolecular proteins, micelles and liposomes. Lyophobic colloids do not pass into the dispersed state spontaneously. They are generally produced by mechanical or chemical action. An example of lyophobic colloid is latex paint. Kruyt (1952) classified colloids as, (i) reversible colloids (ii) irreversible colloids For reversible colloids, the dispersed phase is spontaneously distributed in the surrounding medium by thermal energy. For example, a protein crystal dissolves in water spontaneously. Such spontaneous dispersion leads to an equilibrium size distribution corresponding to the minimum value of the thermodynamic potential. If the dispersed phase is thrown out of the colloid state, its redispersion is achieved easily. The irreversible colloid dispersions, on the other hand, are thermodynamically unstable. To illustrate, a gold crystal, if brought in contact with water, will not generate the sol spontaneously. The subdivision of the gold crystal into small particles can be performed only by supplying a considerable amount of energy. The total free energy of the goldwater interface is a positive quantity. The small entropic gain in the subdivision process is not sufficient to make the formation of sol spontaneous. This type of colloids has a natural tendency to be thrown out of the dispersion medium from the colloid state. Their stability in the colloid state is achieved with considerable difficulty. Joint Initiative of IITs and IISc Funded by MHRD 5/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 1.2.4 Coagulation and flocculation The terms coagulation and flocculation are widely used in colloid chemistry to mean aggregation of the particles. The term coagulation to implies the formation of compact aggregates leading to the macroscopic separation of a coagulum, and the term flocculation is used implying the formation of a loose or open network which may or may not separate macroscopically. Various chemicals (e.g. polymers) are used to induce flocculation or coagulation. These are known as flocculants or coagulants. The intermolecular and surface forces play important roles in the stabilization and coagulation of colloids. 1.2.5 Critical coagulation concentration When the colloid particles are stabilized, the process is known as peptization. The reverse process, i.e., the destabilization of colloids is termed coagulation. Certain ions are necessary to cause peptization or coagulation. The amount of electrolyte required to induce coagulation depends upon the valence of the counterion in the salt. This concentration of electrolyte is known as critical coagulation concentration (CCC) or flocculation value (see Table 1.2.2). Table 1.2.2 Critical coagulation concentrations of some salts for the negatively charged AgI sol Type of electrolyte Formula of the electrolyte CCC (mol/m 3 ) 1:1 LiNO 3 165.00 NaNO 3 140.00 KNO 3 136.00 2:1 Mg(NO 3 ) 2 2.53 Ca(NO 3 ) 2 2.37 Ba(NO 3 ) 2 2.20 3:1 Al(NO 3 ) 3 0.07 La(NO 3 ) 3 0.07 Joint Initiative of IITs and IISc Funded by MHRD 6/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 Ce(NO 3 ) 3 0.07 The valence of the counterion is a very important parameter for the coagulation of a sol. The amount of divalent counterion required to coagulate the AgI colloid is much smaller than the amount of the monovalent counterion. The amount of trivalent counterion required is even less. The effect of valence of counterion on coagulation can be explained by the SchulzeHardy rule. It states that the critical coagulation concentration varies with the inverse sixth-power of the valence of the counterion. The specific nature of these ions is less important. Also, the effect of the valence of the coions (i.e., the ions of the electrolyte having the same charge as the colloid particles) is less significant on coagulation. Example 1.2.1: The critical coagulation concentrations for NaCl, MgCl 2 and AlCl 3 for negatively charged As 2 S 3 colloids are 60 mol/m 3, 0.7 mol/m 3 and 0.09 mol/m 3, respectively. Verify whether these values are consistent with the SchulzeHardy rule or not. Solution: Since the As 2 S 3 colloid particles are negatively charged, the concentrations of the cations are important. If we represent the concentrations of the monovalent, divalent and trivalent cations by c 1, c 2 and c 3, then from the given data on critical coagulation concentration, we have, c1: c2: c 3 60 : 0.7 : 0.09 1: 0.012 : 0.0015 According to SchulzeHardy rule, 1 1 c1: c2: c 3 1: : 1:0.016:0.0014 6 6 2 3 Therefore, the critical coagulation concentration data agree with the SchulzeHardy rule. Joint Initiative of IITs and IISc Funded by MHRD 7/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 1.2.6 Thermodynamic and kinetic stabilities of colloids Association colloids (e.g., surfactant micelles) and microemulsions are examples of thermodynamically stable colloidal systems. Many colloid systems are thermodynamically unstable. However, they are kinetically stable. The well-known examples are emulsions and foams. A system which shows resistance to coagulation is called kinetically stable colloid system. The term colloid stability generally implies kinetic stability. 1.2.7 Sedimentation in gravitational field Let us consider the movement of an uncharged spherical particle through a liquid under the gravitational force (Fig. 1.2.3). For small colloid particles, the flow occurs at very low velocities relative to the sphere. This is known as creeping flow. Two other forces act on the particle: buoyant force and drag force, as shown in the following figure. The buoyant force acts parallel with the gravity force, but in the opposite direction. Fig. 1.2.3 Forces acting on a colloid particle falling downwards by gravity. The drag force appears whenever there is relative motion between a particle and the fluid. It opposes the motion and acts parallel with the direction of the movement, but in Joint Initiative of IITs and IISc Funded by MHRD 8/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 the opposite direction. Let us represent the gravity, buoyant and drag forces by F g, and F d, respectively. Let the mass of the particle be m, and its velocity relative to the fluid be v. The resultant force on the particle is Fg Fb F d. The acceleration of the particle is dv dt. Therefore, we can write the following force balance. F b The gravity force is, dv m Fg Fb Fd dt (1.2.1) Fg mg (1.2.2) By Archimedes principle, the buoyant force is the product of the mass of fluid displaced by the particle and the acceleration under gravity. mρg Fb ρp where ρ is the density of the liquid and (1.2.3) ρ p is the density of the particle. The drag force on the particle is given by Stokes law, Fd 3πμvd (1.2.4) where μ is the viscosity of the liquid and d is the diameter of the particle. Equation (1.2.4) is applicable when the particle Reynolds number dvρ μ is low (say, < 0.1). Two-thirds of the total drag on the particle is due to skin friction, and the rest is due to form-drag. From Eqs. (1.2.1) (1.2.4) we get, dv ρp ρ 3πμvd g (1.2.5) dt ρp m When the particle settles under gravity, the drag always increases with velocity. The acceleration decreases with time and approaches zero. A small colloid particle quickly reaches a constant velocity after a very brief accelerating period. This is the maximum attainable velocity under the circumstances. It is known as the terminal velocity, v t. The equation for v t can be obtained by setting dv dt 0. Therefore, from Eq. (1.2.5) we get, Joint Initiative of IITs and IISc Funded by MHRD 9/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 vt ρp ρ mg ρp 3πμd (1.2.6) Putting 3 m πd gρ p 6 in Eq. (2.6), we get, 2 d g ρp ρ vt (1.2.7) 18μ This is the expression for terminal velocity based on Stokes law. It is evident that when ρp ρ, the particle settles or sediments to the bottom (e.g., paint pigments settle to the bottom of a paint container). When ρp ρ, the converse is true and the particle rises, which is known as creaming (e.g., cream rises to the top of a bottle of milk). The derivation given in this section is based on the following assumptions. (i) Settling is not affected by the presence of other particles in the fluid. This condition is known as free settling. When the interference of other particles is appreciable, the process is termed hindered settling. (ii) The walls of the container do not exert an appreciable retarding effect. (iii) The particle is large compared with the mean free path of the molecules of the fluid. Otherwise, the particles may slip between the molecules and thus attain a velocity that is different from that calculated. If the particles are very small (~100 nm or less), Brownian movement becomes important. The effect of Browning movement can be reduced by applying centrifugal force. The concentrations of dispersions used in industrial applications are usually high so that there is significant interaction between the particles. As a result, hindered settling is observed. The sedimentation rate of a particle in a concentrated dispersion may be considerably less than its terminal falling velocity under free settling conditions. 1.2.8 Sedimentation in centrifugal field It is easy to produce high acceleration in a centrifugal field so that the effects of gravity become negligible. The equation of motion for the particles in a centrifugal field Joint Initiative of IITs and IISc Funded by MHRD 10/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 is similar to the equation for gravitational field, except that the acceleration due to gravity needs to be replaced by the centrifugal acceleration 2 rω, where r is the radius of rotation and ω is angular velocity. Therefore, in this case the acceleration is a function of the position r. For a spherical particle obeying Stokes law the equation of motion is, 3 πd 2 dr ρ 3 6 p ρ rω πμd (1.2.8) dt As the particle moves outwards, the accelerating force increases. Therefore, it never acquires an equilibrium velocity in the fluid. Equation (1.2.8) can be simplified to give, dr d 2 ρp ρ rω 2 rω 2 vt dt 18μ g (1.2.9) Thus, the instantaneous sedimentation velocity dr dt can be considered as the terminal velocity in the gravity field that is increased by a factor equal to the acceleration ratio, 2 rω g. Let us define a sedimentation coefficient s as, dr dt s 2 (1.2.10) rω The sedimentation coefficient represents the sedimentation velocity per unit centrifugal acceleration. It can be determined by measuring the location of a particle along its settling path. Integrating Eq. (1.2.10), we get, ln r2 r1 s 2 ω t2 t1 (1.2.11) Fine colloid particles sediment at a very slow rate under gravity. Swedish chemist Theodor Svedberg (Nobel Prize in Chemistry, 1926) developed a centrifuge which operates at a very high speed (e.g., 5000 10000 rad/s) generating an enormous centrifugal force. This force is much greater than the gravitational force. It is known as ultracentrifuge (Fig. 1.2.4). The dispersion is taken in a specially designed cell and vigorously whirled by special motors. The speed of rotation is so high that an acceleration as high as 10 6 times that of the gravitational acceleration can be attained. Ultracentrifuge not Joint Initiative of IITs and IISc Funded by MHRD 11/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 only hastens the sedimentation process, but it also separates the molecules on the basis of differences in mass, density or shape. The ultracentrifuge has proved to be very effective for macromolecular solutions, especially the proteins. Fig. 1.2.4 Beckman L8-80M ultracentrifuge (photograph courtesy: Beckman Coulter India Pvt. Ltd.) Example 1.2.2: A spherical particle suspended in water is placed in a centrifugal field. The diameter of the particle is 110 7 m. What should be the rotational speed so that the particle moves from 6.5 cm to 7 cm in 60 s? Density of the particle is 7500 kg/m 3. Solution: The sedimentation coefficient is given by, 2 2 d ρ ρ 9 s 3.6 10 7 p 110 7500 1000 18μ 3 18110 s The speed of rotation is, 12 12 ln r2 r1 ln 7 6.5 ω 585.7 9 rad/s st 3.6 10 60 Note that this rotation-speed is equivalent to 5600 revolutions per minute. Joint Initiative of IITs and IISc Funded by MHRD 12/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 Exercise Exercise 1.2.1: Calculate the terminal velocity of a 10 m diameter carbon tetrachloride drop in water. Given: density of carbon tetrachloride = 1600 kg/m 3, viscosity of water = 1 mpa s. What are the assumptions made in your calculation? Exercise 1.2.2: A 1 m diameter quartz particle (density = 2650 kg/m 3 ) suspended in water is placed in a centrifuge. The centrifuge rotates at a speed of 1000 rad/s. Calculate the sedimentation coefficient. What will be radial position of the particle with respect to its initial position after operating the centrifuge for 60 s? Exercise 1.2.3: Answer the following questions. i. Mention the forces which act on a colloid particle when it settles in liquid under gravity. ii. What is terminal velocity? iii. What is the difference between free settling and hindered settling? iv. What is creaming? When does it occur? v. What is the advantage of centrifugal sedimentation over the gravitational sedimentation? vi. Define sedimentation coefficient. vii. Explain the principle of operation of ultracentrifuge. Joint Initiative of IITs and IISc Funded by MHRD 13/14

NPTEL Chemical Engineering Interfacial Engineering Module 1: Lecture 2 Suggested reading Textbooks P. C. Hiemenz and R. Rajagopalan, Principles of Colloid and Surface Chemistry, Marcel Dekker, New York, 1997, Chapter 1. P. Ghosh, Colloid and Interface Science, PHI Learning, New Delhi, 2009, Chapters 1 & 2. Reference books D. F. Evans and H. Wennerström, The Colloidal Domain: Where Physics, Chemistry, Biology, and Technology Meet, VCH, New York, 1994, Chapter 1. J. F. Richardson, J. H. Harker, and J. R. Backhurst, Coulson & Richardson s Chemical Engineering (Vol. 2), Elsevier, New Delhi (2003), Chapter 3. Joint Initiative of IITs and IISc Funded by MHRD 14/14