1 Dragonfly 4 wings. Quantity relationships: How much? How many? How many dragonflies wings are required for 4 dragonflies to be able to fly?

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1 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P1 Quantity relationships: How much How many How many dragonflies wings are required for 4 dragonflies to be able to fly 1 Dragonfly 4 wings

2 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P2 1 4 wings Same Units 5 DF = Same Units DFs

3 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P3 Quantity Relationships in Chemical Reactions: How to solve stoichiometry problems: What we need to know are two subjects as: 1) A balanced chemical reaction. 2) Relationship between mass and e. EXAMPLE: How many es of oxygen are required to burn 2.4 es of ethane gas 2 C 2 H 6 (g) + 7 O 2 (g) 4 CO 2 (g) + 6 H 2 O (l) Given Wanted 2 C 2 H 6 7 O C 2 H 6

4 Same Units Same Units SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P4 2 7 = (C 2 H 6 ) = 7 (O 2 ) 2.4 (C 2 H 6 ) 7 = *********************************************** EXAMPLE: Calculate the number of grams of oxygen that are required to burn 155 g of ethane. 2 C 2 H 6 (g) + 7 O 2 (g) 4 CO 2 (g) + 6 H 2 O (l) Given Wanted 2 C 2 H 6 7 O ( g g ) 155 g C 2 H 6

5 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P5 2 7 = 5.15 = 5.15 Same Units 7 2 Same Units = 18.3 (oxygen) Wanted in gram! e = mass ar mass ar mass of oxygen = (g/) = (g/) = 577 g O 2

6 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P6 EXAMPLE: How many milligrams of Nickel Chloride are in a solution if 53 mg of Silver Chloride is precipitated in the reaction of Silver Nitrate and Nickel Chloride solution 2 AgNO 3 (aq) + NiCl 2 (aq) 2 AgCl (s) + Ni(NO 3 ) 2 (aq) Wanted Given 1 NiCl 2 2 AgCl 53 mg mg (AgCl) AgCl (AgCl) (mg) to (g): 53 mg (1 g/ 1 mg) =.53 g Same Units

7 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P7 (mass) to (e) e = mass / ar mass e of AgCl =.53 g (g/) e of AgCl = = NiCl2 = AgCl 2 AgCl = NiCl 2 Wanted in milligram! e = mass ar mass ar mass of NiCl 2 = (g/) Mass of NiCl 2 = (g/) =.227 g Mass of NiCl 2 = 227 mg

8 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P8 Gas Stoichiometry at Standard Temperature and Pressure: One e of any gas at STP occupies 22.4 L EXAMPLE: What volume of hydrogen, at STP, can be released by 42.7 g of zinc as it reacts with hydrochloric acid Zn (s) + 2 HCl (aq) H 2 (g) + ZnCl 2 (aq) Given Wanted L Zn 42.7 g g ( ) 42.7 g Same Units L =.653

9 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P9 EXAMPLE: 1.3L of gaseous ethylene is burned. What volume of oxygen is required if both gas volume are measured at STP C 2 H 4 (g) + 3O 2 (g) 2CO 2 (g) + 2 H 2 O (l) Given Wanted 1 C 2 H 4 3 O L L 1.3 L L L = 67.2

10 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P1 Gas Stoichiometry at nonstandard condition: In STP condition: T= 273 K, and P =76 torr P V 1 T 1 1 = P 2 T V 2 2 STP = nonstandard In the previous example for the reaction: Zn (s) + 2 HCl (aq) H 2 (g) + ZnCl 2 (aq) We calculated the volume of hydrogen as 14.6 L, now let s change the problem. Instead of measuring the hydrogen volume at STP, let s use t = 21 C and P = 748 torr. T K = = V = STP = nonstandard V 2 = 16. L

11 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P11 14 transistors 22 resistors 18 capacitors How many of the above electronic circuits (ec) can you assemble from 22 resistors, 18 capacitors, and 14 transistors Calculate the theoretical yield of ec: 1 ec 14 T 2 T = 7 ec 1 ec 22 R 4 T = 5.5 ec 5 ec 1 ec 18 C 3 C = 6 ec Resistor is the limiting item, because 22 of resistors give 5 ec.

12 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P12 Limiting Reactants: Example: The fertilizer ammonium nitrate can be made by direct combination of ammonia with nitric acid. If 74.4 g of ammonia is reacted with 159 g of nitric acid, how many grams of ammonium nitrate can be produced Also calculate the mass of unreacted reactant that is in excess. NH 3 + HNO 3 NH 4 NO 3 Convert the number of grams of each reactant to es. NH 3 : 74.4 g 159 g = g HNO 3 : = g 1 NH 4 NO NH 3 = NH 4 NO 1 NH NH NO 2.52 NH NO 4 3 HNO3 = HNO3 The reactant that yields the smaller amount of product is limiting reactant of NH 3 1 of HNO =2.52 of HNO = 1.85 NH 3 left

13 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P = g NH 3 left A mixture of 5. g of H 2 (g) and 1. g of O 2 (g) is ignited. Water forms according to the following combination reaction: 2H 2 (g) +O 2 (g) 2H 2 O(g) Which reactant is limiting How much water will the reaction produce

14 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P14 Percent Yield: The calculated amount of product if is based on the assumption that all of the reactant is converted into product is called the theoretical yield. In laboratory or in industrial production, the actual amount of product isolated from a reaction is usually less than the theoretical yield, and it is called actual yield. General solution: Given: n gram of A Given: actual yield Wanted: %yield αa + βb γc Step 1: Step 2: Step 3: Convert mass of A into the e of A. Calculate the theoretical yield: Number of es A γ α Convert e of C into the mass of C. C A

15 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P15 Step 4: actual yield % Yield = 1 theoretical yield Example: A general chemistry student, preparing copper metal by the reaction of g of copper sulfate with zinc metal, obtained a yield of.392 g copper. What was the percent yield To calculate %yield, we need both the theoretical yield of copper and the actual yield. CuSO 4 (aq) + Zn(s) Cu(s) + ZnSO 4 (aq) Mass to Mole: g CuSO g 4 = CuSO 4 The theoretical yield: Mole to Mass: CuSO 4 1 Cu 1 CuSO Cu g = = g Cu 3 Cu actual yield.392 g % Yield = 1 = 1 = theoretical yield.572 g 77.3 %

16 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P16 Liquid Oxygen Liquid Hydrogen Main Engines

17 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P17 Thermochemical Equations: H 2 (l) + O 2 (l) H 2 O (g) + energy System Gives off heat Exothermic -ΔH 2 NH 3 (g) + energy N 2 (g) + 3 H 2 (g) System Absorbs heat Endothermic +ΔH The SI unit for energy: joule (J) How many kilojoule of energy are released when 73. g C2H6 burns according to: 2C 2 H 6 (g) +7 O 2 (g) 4 CO 2 (g) + 6H 2 O (l)+ 3119KJ 2 C 2 H KJ 73. g g 3.5 ( ) 73. g

18 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P18 ΔH = KJ for the photosynthesis reaction by which plants use energy from the sun to form one e sugar from carbon dioxide and water. How much energy is required to form 454g (1lb) of simple sugar C 6 H 12 O 6 6 CO 2 (g) +6 H 2 O (g) + C 6 H 12 O 6 (s) + 6O 2 (g) 1 Suga KJ 454 g g 18 ( ) 454 g KJ

19 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P19

20 SCC-CH11/UCD-CH41C Chapter: 9 Instructor: J.T. P2

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