Given: P A, V A, v A, m B, P B, and T B. Find: Final specific volume Solution: v final = V final m final m A +m B
|
|
- Harriet Ryan
- 7 years ago
- Views:
Transcription
1 Two tanks are connected as shown in the figure, both containing water. Tank A is at 200 kpa, v A 0.5 m 3 /, V A 1 m 3, and tank B contains 3.5 at 0.5 MPa and 400 C. The valve is now opened and the two tanks come to a uniform state. Find the final specific volume. Given: P A, V A, v A, m B, P B, and T B. Find: Final specific volume v final V final V A +V B m final m A +m B m A V A 1 m3 v A 0.5 m 3 / 2 V B m B v B v B m 3 / (from Table B.1.3 with P 500 kpa, T 400 C) V B 3.5 ( m 3 / ) 2.16 m 3 v final 0.5 m m v final m 3 /
2 A boiler feed pump delivers 0.5 m 3 /s of water at 240 C, 20 MPa. What is the mass flow rate (/s)? What would the percent error be if the properties of saturated liquid at 240 Cwere used in the calculation? What if the properties of saturated liquid at 20 MPa were used instead? Given: Temperature, Pressure, and volumetric flow rate of water. Find: The mass flow rate of water and the percent error for using two different approximation methods. ṁ V v For T 240 Cand P 20,000 kpa, v m3/ (Table B.1.4) ṁ Using v v f T240 C m 3 /: 0.05 m 3 /s m /s / ṁ Error 0.05 m 3 /s m /s / 41.5 /s 40.7 /s 2% 41.5 /s Using v v f P20000 kpa m 3 /: ṁ Error 0.05 m 3 /s m /s / 41.5 /s 24.6 /s 41% 41.5 /s
3 A pressure cooker (closed tank) contains water at 100 C, with the liquid volume being 1/10th of the vapor volume. It is heated until the pressure reaches 2.0 MPa. Find the final temperature. Has the final state more or less vapor than the initial state? Given: Initial temperature, initial volume fraction of water, and final Pressure Find: Final temperature and final fraction of liquid/steam Assumptions: Closed system. Constant volume system. State 1: T Cand V L /V V 10% State 2: P kpa v 2 v 1 Need to find v 1 (there are many ways to do this...here s one) v 1 V 1 V L +V V V L +V V m 1 m L +m V L (V L +V V )v f v g (0.1V V +V V )v f v g 1.1v fv g V vf + VV V v L v g +V V v f 0.1V V v g +V V v f 0.1v g +v f g v f T100 C m 3 / v g T100 C m 3 / v 1 1.1v fv g 1.1 ( m 3 / )( m 3 / ) 0.1v g +v f (0.1)1.6729m 3 / m 3 / m3 / v 2 v m 3 / < v g P2000 kpa m 3 / T 2 T sat P2000 kpa C It s not clear from the problem statement if they want to know if there is more vapor by volume or by mass. By mass: x 1 v 1 v f, v g,1 v f, x 2 v 2 v f, v g,2 v f, x 2 > x 1 so more vapor in final state.
4 By volume: ( VL V V ( VL V V V L m Lv f (1 x)m totalv f V V m V v g xm total v f ) (1 x 2)v f,2 x 2 v g,2 ) 2 2 (1 x)v f xv g ( ) (0.104) > 0.1 so more vapor in final state.
5 A 1-m 3 rigid tank with air at 1 MPa and 400 K is connected to an air line as shown in the figure. The valve is opened and air flows into the tank until the pressure reaches 5 MPa, at which point the valve is closed and the temperature inside is 450 K. a. What is the mass of air in the tank before and after the process? b. The tank eventually cools to room temperature, 300 K. What is the pressure inside the tank then? Given: Volume of tank, initial and final temperatures and pressures. Find: Initial and final mass in tank, pressure after tank cools. Assumptions: Air can be treated as an ideal gas. PV mrt R air kj V 1 m 3 m 1 P 1V (1000 kpa)1 m3 RT kj 8.71 (400 K) m 2 P 2V (5000 kpa)1 m3 RT kj 38.7 (450 K) P final mrt final V (38.7 )(0.287kJ )(300 K) 1 m MPa
6 What is the percent error in specific volume if the ideal gas model is used to represent the behavior of superheated ammonia at 40 Cand 500 kpa? What if the generalized compressibility chart, Fig. D.1, is used instead? From table B.2.2 for the given conditions the specific volume of ammonia is v m 3 /. Ideal Gas Law: Pv RT R ammonia kj/k Table A.5 v RT P Error kj/k(313 K) 500 kpa 4.6% m 3 / Compressibility Chart: T c K Table A.2 P c 11,350 kpa Table A.2 T r T T c 313 K K 0.77 P r P P c Z 0.97 v ZRT P Error kpa 11,350 kpa ( kj/k)313 K 500 kpa 1.4% m 3 /
7 A piston/cylinder contains air at 600 kpa, 290 K and a volume of 0.01 m 3. A constant-pressure process gives 54 kj of work out. Find the final volume and temperature of the air. Given: Initial conditions, constant pressure, work done. Find: Final volume and temperature. Assumptions: Air can be treated as an ideal gas. W PdV W P(V 2 V 1 ) Only for constant pressure process. V 2 W P +V 1 V 2 54 kj 600 kpa +0.01m3 V m3 PV mrt T V P } Constant mr T 1 T 2 V 1 V 2 T 2 T 1 V 2 V K(10) 2900 K
8 A piston/cylinder has 5 m of liquid 20 Cwater on top of the piston (m0) with a cross-sectional are of 0.1 m 2. Air let in under the piston rises and pushes the water out over the top edge. Find the work needed to push all the water out and plot the process on a P-V diagram. Given: Water on top of piston is pushed off by air that pushes piston up. Find: Work done by air. Assumptions: P atm kpa P P air ρ water g(h h)+p atm V V air ha h V air A P ρ water g(h V A )+P atm W PdV ( W ρ water g(h V ) A )+P atm dv W ρ water gh +P atm dv ρ water g V A dv W (ρ water gh +P atm )(V 2 V 1 ) ρ waterg VdV A W (ρ water gh +P atm )(V 2 V 1 ) ρ waterg ( V 2 2A 2 V1 2 ) ρ water 1/v f T20 C 1/ m 3 / 998 /m 3 V 1 0 V 2 HA (5 m)(0.1 m 2 ) 0.5 m 3 g 9.81N/m [ W 998 ( m N ) ] 1000 Pa (0.5 5 m+101.3kpa m 3 0 ) 1 kpa ) 998 m (9.81 N 3 ( (0.5 m 3 2(0.1 m 2 ) 2 0 2) ) W 62.9kJ
ES-7A Thermodynamics HW 1: 2-30, 32, 52, 75, 121, 125; 3-18, 24, 29, 88 Spring 2003 Page 1 of 6
Spring 2003 Page 1 of 6 2-30 Steam Tables Given: Property table for H 2 O Find: Complete the table. T ( C) P (kpa) h (kj/kg) x phase description a) 120.23 200 2046.03 0.7 saturated mixture b) 140 361.3
More informationa cannonball = (P cannon P atmosphere )A cannon m cannonball a cannonball = (P cannon P atmosphere ) πd 2 a cannonball = 5.00 kg
2.46 A piston/cylinder with a cross-sectional area of 0.01 m 3 has a mass of 100 resting on the stops as shown in the figure. With an outside atmospheric pressure of 100 kpa what should the water pressure
More informationFUNDAMENTALS OF ENGINEERING THERMODYNAMICS
FUNDAMENTALS OF ENGINEERING THERMODYNAMICS System: Quantity of matter (constant mass) or region in space (constant volume) chosen for study. Closed system: Can exchange energy but not mass; mass is constant
More informationCHAPTER 7 THE SECOND LAW OF THERMODYNAMICS. Blank
CHAPTER 7 THE SECOND LAW OF THERMODYNAMICS Blank SONNTAG/BORGNAKKE STUDY PROBLEM 7-1 7.1 A car engine and its fuel consumption A car engine produces 136 hp on the output shaft with a thermal efficiency
More informationQUESTIONS THERMODYNAMICS PRACTICE PROBLEMS FOR NON-TECHNICAL MAJORS. Thermodynamic Properties
QUESTIONS THERMODYNAMICS PRACTICE PROBLEMS FOR NON-TECHNICAL MAJORS Thermodynamic Properties 1. If an object has a weight of 10 lbf on the moon, what would the same object weigh on Jupiter? ft ft -ft g
More informationChem 338 Homework Set #5 solutions October 10, 2001 From Atkins: 5.2, 5.9, 5.12, 5.13, 5.15, 5.17, 5.21
Chem 8 Homework Set #5 solutions October 10, 2001 From Atkins: 5.2, 5.9, 5.12, 5.1, 5.15, 5.17, 5.21 5.2) The density of rhombic sulfur is 2.070 g cm - and that of monoclinic sulfur is 1.957 g cm -. Can
More informationDET: Mechanical Engineering Thermofluids (Higher)
DET: Mechanical Engineering Thermofluids (Higher) 6485 Spring 000 HIGHER STILL DET: Mechanical Engineering Thermofluids Higher Support Materials *+,-./ CONTENTS Section : Thermofluids (Higher) Student
More informationa) Use the following equation from the lecture notes: = ( 8.314 J K 1 mol 1) ( ) 10 L
hermodynamics: Examples for chapter 4. 1. One mole of nitrogen gas is allowed to expand from 0.5 to 10 L reversible and isothermal process at 300 K. Calculate the change in molar entropy using a the ideal
More informationHow To Calculate The Performance Of A Refrigerator And Heat Pump
THERMODYNAMICS TUTORIAL 5 HEAT PUMPS AND REFRIGERATION On completion of this tutorial you should be able to do the following. Discuss the merits of different refrigerants. Use thermodynamic tables for
More informationAPPLIED THERMODYNAMICS TUTORIAL 1 REVISION OF ISENTROPIC EFFICIENCY ADVANCED STEAM CYCLES
APPLIED THERMODYNAMICS TUTORIAL 1 REVISION OF ISENTROPIC EFFICIENCY ADVANCED STEAM CYCLES INTRODUCTION This tutorial is designed for students wishing to extend their knowledge of thermodynamics to a more
More informationProblem Set 1 3.20 MIT Professor Gerbrand Ceder Fall 2003
LEVEL 1 PROBLEMS Problem Set 1 3.0 MIT Professor Gerbrand Ceder Fall 003 Problem 1.1 The internal energy per kg for a certain gas is given by U = 0. 17 T + C where U is in kj/kg, T is in Kelvin, and C
More informationPG Student (Heat Power Engg.), Mechanical Engineering Department Jabalpur Engineering College, India. Jabalpur Engineering College, India.
International Journal of Emerging Trends in Engineering and Development Issue 3, Vol. (January 23) EFFECT OF SUB COOLING AND SUPERHEATING ON VAPOUR COMPRESSION REFRIGERATION SYSTEMS USING 22 ALTERNATIVE
More informationUNIT 2 REFRIGERATION CYCLE
UNIT 2 REFRIGERATION CYCLE Refrigeration Cycle Structure 2. Introduction Objectives 2.2 Vapour Compression Cycle 2.2. Simple Vapour Compression Refrigeration Cycle 2.2.2 Theoretical Vapour Compression
More information18 Q0 a speed of 45.0 m/s away from a moving car. If the car is 8 Q0 moving towards the ambulance with a speed of 15.0 m/s, what Q0 frequency does a
First Major T-042 1 A transverse sinusoidal wave is traveling on a string with a 17 speed of 300 m/s. If the wave has a frequency of 100 Hz, what 9 is the phase difference between two particles on the
More informationSheet 5:Chapter 5 5 1C Name four physical quantities that are conserved and two quantities that are not conserved during a process.
Thermo 1 (MEP 261) Thermodynamics An Engineering Approach Yunus A. Cengel & Michael A. Boles 7 th Edition, McGraw-Hill Companies, ISBN-978-0-07-352932-5, 2008 Sheet 5:Chapter 5 5 1C Name four physical
More informationThermodynamics - Example Problems Problems and Solutions
Thermodynamics - Example Problems Problems and Solutions 1 Examining a Power Plant Consider a power plant. At point 1 the working gas has a temperature of T = 25 C. The pressure is 1bar and the mass flow
More information= 1.038 atm. 760 mm Hg. = 0.989 atm. d. 767 torr = 767 mm Hg. = 1.01 atm
Chapter 13 Gases 1. Solids and liquids have essentially fixed volumes and are not able to be compressed easily. Gases have volumes that depend on their conditions, and can be compressed or expanded by
More informationME 201 Thermodynamics
ME 0 Thermodynamics Second Law Practice Problems. Ideally, which fluid can do more work: air at 600 psia and 600 F or steam at 600 psia and 600 F The maximum work a substance can do is given by its availablity.
More informationThermodynamics AP Physics B. Multiple Choice Questions
Thermodynamics AP Physics B Name Multiple Choice Questions 1. What is the name of the following statement: When two systems are in thermal equilibrium with a third system, then they are in thermal equilibrium
More informationAnswer, Key Homework 6 David McIntyre 1
Answer, Key Homework 6 David McIntyre 1 This print-out should have 0 questions, check that it is complete. Multiple-choice questions may continue on the next column or page: find all choices before making
More informationChapter 10: Refrigeration Cycles
Capter 10: efrigeration Cycles Te vapor compression refrigeration cycle is a common metod for transferring eat from a low temperature to a ig temperature. Te above figure sows te objectives of refrigerators
More informationTHE KINETIC THEORY OF GASES
Chapter 19: THE KINETIC THEORY OF GASES 1. Evidence that a gas consists mostly of empty space is the fact that: A. the density of a gas becomes much greater when it is liquefied B. gases exert pressure
More informationOptimal operation of an Ammonia refrigeration cycle
Optimal operation of an Ammonia refrigeration cycle Jørgen Bauck Jensen & Sigurd Skogestad October 6, 2005 1 PSfrag replacements 1 Introduction Cyclic processes for heating and cooling are widely used
More informationChapter 18 Temperature, Heat, and the First Law of Thermodynamics. Problems: 8, 11, 13, 17, 21, 27, 29, 37, 39, 41, 47, 51, 57
Chapter 18 Temperature, Heat, and the First Law of Thermodynamics Problems: 8, 11, 13, 17, 21, 27, 29, 37, 39, 41, 47, 51, 57 Thermodynamics study and application of thermal energy temperature quantity
More informationREFRIGERATION (& HEAT PUMPS)
REFRIGERATION (& HEAT PUMPS) Refrigeration is the 'artificial' extraction of heat from a substance in order to lower its temperature to below that of its surroundings Primarily, heat is extracted from
More informationEXPERIMENT 15: Ideal Gas Law: Molecular Weight of a Vapor
EXPERIMENT 15: Ideal Gas Law: Molecular Weight of a Vapor Purpose: In this experiment you will use the ideal gas law to calculate the molecular weight of a volatile liquid compound by measuring the mass,
More informationTemperature. Number of moles. Constant Terms. Pressure. Answers Additional Questions 12.1
Answers Additional Questions 12.1 1. A gas collected over water has a total pressure equal to the pressure of the dry gas plus the pressure of the water vapor. If the partial pressure of water at 25.0
More informationDiesel Cycle Analysis
Engineering Software P.O. Box 1180, Germantown, MD 20875 Phone: (301) 540-3605 FAX: (301) 540-3605 E-Mail: info@engineering-4e.com Web Site: http://www.engineering-4e.com Diesel Cycle Analysis Diesel Cycle
More informationOpen Cycle Refrigeration System
Chapter 9 Open Cycle Refrigeration System Copy Right By: Thomas T.S. Wan 温 到 祥 著 Sept. 3, 2008 All rights reserved An open cycle refrigeration system is that the system is without a traditional evaporator.
More informationCO 2 41.2 MPa (abs) 20 C
comp_02 A CO 2 cartridge is used to propel a small rocket cart. Compressed CO 2, stored at a pressure of 41.2 MPa (abs) and a temperature of 20 C, is expanded through a smoothly contoured converging nozzle
More informationPopcorn Laboratory. Hypothesis : Materials:
Popcorn Laboratory Problem: Popcorn kernels explode into delightful, edible parcels because of a build-up of pressure inside the kernel during heating. In this experiment you will try to calculate the
More informationA basic introduction to steam
A basic introduction to steam FOR HOT, COLD, MOIST AND DRY, FOUR CHAMPIONS FIERCE. STRIVE HERE FOR MASTERY Milton 1666 Steam Wonderful Steam Very high heat content Recyclable Clean, non toxic Biodegradable
More informationThermodynamical aspects of the passage to hybrid nuclear power plants
Energy Production and Management in the 21st Century, Vol. 1 273 Thermodynamical aspects of the passage to hybrid nuclear power plants A. Zaryankin, A. Rogalev & I. Komarov Moscow Power Engineering Institute,
More informationCHAPTER 3: FORCES AND PRESSURE
CHAPTER 3: FORCES AND PRESSURE 3.1 UNDERSTANDING PRESSURE 1. The pressure acting on a surface is defined as.. force per unit. area on the surface. 2. Pressure, P = F A 3. Unit for pressure is. Nm -2 or
More informationThe Second Law of Thermodynamics
The Second aw of Thermodynamics The second law of thermodynamics asserts that processes occur in a certain direction and that the energy has quality as well as quantity. The first law places no restriction
More informationvap H = RT 1T 2 = 30.850 kj mol 1 100 kpa = 341 K
Thermodynamics: Examples for chapter 6. 1. The boiling point of hexane at 1 atm is 68.7 C. What is the boiling point at 1 bar? The vapor pressure of hexane at 49.6 C is 53.32 kpa. Assume that the vapor
More informationHow does solar air conditioning work?
How does solar air conditioning work? In a conventional air conditioning system; The working fluid arrives at the compressor as a cool, low-pressure gas. The compressor is powered by electricity to squeeze
More informationOUTCOME 2 INTERNAL COMBUSTION ENGINE PERFORMANCE. TUTORIAL No. 5 PERFORMANCE CHARACTERISTICS
UNIT 61: ENGINEERING THERMODYNAMICS Unit code: D/601/1410 QCF level: 5 Credit value: 15 OUTCOME 2 INTERNAL COMBUSTION ENGINE PERFORMANCE TUTORIAL No. 5 PERFORMANCE CHARACTERISTICS 2 Be able to evaluate
More information5. Which temperature is equal to +20 K? 1) 253ºC 2) 293ºC 3) 253 C 4) 293 C
1. The average kinetic energy of water molecules increases when 1) H 2 O(s) changes to H 2 O( ) at 0ºC 3) H 2 O( ) at 10ºC changes to H 2 O( ) at 20ºC 2) H 2 O( ) changes to H 2 O(s) at 0ºC 4) H 2 O( )
More informationChapter 17. For the most part, we have limited our consideration so COMPRESSIBLE FLOW. Objectives
Chapter 17 COMPRESSIBLE FLOW For the most part, we have limited our consideration so far to flows for which density variations and thus compressibility effects are negligible. In this chapter we lift this
More informationThe First Law of Thermodynamics
The First aw of Thermodynamics Q and W are process (path)-dependent. (Q W) = E int is independent of the process. E int = E int,f E int,i = Q W (first law) Q: + heat into the system; heat lost from the
More informationReview - After School Matter Name: Review - After School Matter Tuesday, April 29, 2008
Name: Review - After School Matter Tuesday, April 29, 2008 1. Figure 1 The graph represents the relationship between temperature and time as heat was added uniformly to a substance starting at a solid
More informationUse the correct thermodynamic symbols. Determine the properties of a gas. Determine the properties of vapours. Determine the properties of liquids.
UNIT 61: ENGINEERING THERMODYNAMICS Unit code: D/601/1410 QCF level: 5 Credit value: 15 Students studying this unit should be sure that they can determine the various properties of fluids. If you are already
More informationLesson. 11 Vapour Compression Refrigeration Systems: Performance Aspects And Cycle Modifications. Version 1 ME, IIT Kharagpur 1
Lesson Vapour Compression Refrigeration Systems: Performance Aspects And Cycle Modifications Version ME, IIT Kharagpur The objectives of this lecture are to discuss. Performance aspects of SSS cycle and
More informationMolar Mass of Butane
Cautions Butane is toxic and flammable. No OPEN Flames should be used in this experiment. Purpose The purpose of this experiment is to determine the molar mass of butane using Dalton s Law of Partial Pressures
More informationc KEY EQUATIONS c EXERCISES: THINGS ENGINEERS THINK ABOUT c PROBLEMS: DEVELOPING ENGINEERING SKILLS Problems: Developing Engineering Skills 27
Problems: Developing Engineering Skills 27 c KEY EQUATIONS n 5 m/m (1.8) p. 14 Relation between amounts of matter on a mass basis, m, and on a molar basis, n. T(8R) 5 1.8T(K) (1.16) p. 21 Relation between
More informationSo T decreases. 1.- Does the temperature increase or decrease? For 1 mole of the vdw N2 gas:
1.- One mole of Nitrogen (N2) has been compressed at T0=273 K to the volume V0=1liter. The gas goes through the free expansion process (Q = 0, W = 0), in which the pressure drops down to the atmospheric
More informationWarm medium, T H T T H T L. s Cold medium, T L
Refrigeration Cycle Heat flows in direction of decreasing temperature, i.e., from ig-temperature to low temperature regions. Te transfer of eat from a low-temperature to ig-temperature requires a refrigerator
More informationThe Molar Mass of a Gas
The Molar Mass of a Gas Goals The purpose of this experiment is to determine the number of grams per mole of a gas by measuring the pressure, volume, temperature, and mass of a sample. Terms to Know Molar
More informationEngine Efficiency and Power Density: Distinguishing Limits from Limitations
Engine Efficiency and Power Density: Distinguishing Limits from Limitations Chris F. Edwards Advanced Energy Systems Laboratory Department of Mechanical Engineering Stanford University Exergy to Engines
More informationAS1 MOLES. oxygen molecules have the formula O 2 the relative mass will be 2 x 16 = 32 so the molar mass will be 32g mol -1
Moles 1 MOLES The mole the standard unit of amount of a substance the number of particles in a mole is known as Avogadro s constant (L) Avogadro s constant has a value of 6.023 x 10 23 mol -1. Example
More informationIntroduction to the Ideal Gas Law
Course PHYSICS260 Assignment 5 Consider ten grams of nitrogen gas at an initial pressure of 6.0 atm and at room temperature. It undergoes an isobaric expansion resulting in a quadrupling of its volume.
More informationPOSSIBILITY FOR MECHANICAL VAPOR RE-COMPRESSRION FOR STEAM BASED DRYING PROCESSES
POSSIBILITY FOR MECHANICAL VAPOR RE-COMPRESSRION FOR STEAM BASED DRYING PROCESSES M. Bantle 1, I. Tolstorebrov, T. M. Eikevik 2 1 Department of Energy Efficiency, SINTEF Energy Research, Trondheim, Norway,
More informationENGINEERING INFORMATION Hot water and steam service
ENGINEERING INFORMTION Hot water and steam service WHT IS STEM? Like other substances, water can exist in the form of a solid, when we call it ice; as a liquid when we call it water or as a gas when we
More informationOUTCOME 1 STATIC FLUID SYSTEMS TUTORIAL 1 - HYDROSTATICS
Unit 41: Fluid Mechanics Unit code: T/601/1445 QCF Level: 4 Credit value: 15 OUTCOME 1 STATIC FLUID SYSTEMS TUTORIAL 1 - HYDROSTATICS 1. Be able to determine the behavioural characteristics and parameters
More informationStudy the following diagrams of the States of Matter. Label the names of the Changes of State between the different states.
Describe the strength of attractive forces between particles. Describe the amount of space between particles. Can the particles in this state be compressed? Do the particles in this state have a definite
More information1. A belt pulley is 3 ft. in diameter and rotates at 250 rpm. The belt which is 5 ins. wide makes an angle of contact of 190 over the pulley.
Sample Questions REVISED FIRST CLASS PARTS A1, A2, AND A3 (NOTE: these questions are intended as representations of the style of questions that may appear on examinations. They are not intended as study
More informationEXERCISES. 16. What is the ionic strength in a solution containing NaCl in c=0.14 mol/dm 3 concentration and Na 3 PO 4 in 0.21 mol/dm 3 concentration?
EXERISES 1. The standard enthalpy of reaction is 512 kj/mol and the standard entropy of reaction is 1.60 kj/(k mol) for the denaturalization of a certain protein. Determine the temperature range where
More informationA drop forms when liquid is forced out of a small tube. The shape of the drop is determined by a balance of pressure, gravity, and surface tension
A drop forms when liquid is forced out of a small tube. The shape of the drop is determined by a balance of pressure, gravity, and surface tension forces. 2 Objectives Have a working knowledge of the basic
More informationProblem Set 3 Solutions
Chemistry 360 Dr Jean M Standard Problem Set 3 Solutions 1 (a) One mole of an ideal gas at 98 K is expanded reversibly and isothermally from 10 L to 10 L Determine the amount of work in Joules We start
More informationF321 MOLES. Example If 1 atom has a mass of 1.241 x 10-23 g 1 mole of atoms will have a mass of 1.241 x 10-23 g x 6.02 x 10 23 = 7.
Moles 1 MOLES The mole the standard unit of amount of a substance (mol) the number of particles in a mole is known as Avogadro s constant (N A ) Avogadro s constant has a value of 6.02 x 10 23 mol -1.
More informationMaterials 10-mL graduated cylinder l or 2-L beaker, preferably tall-form Thermometer
VAPOR PRESSURE OF WATER Introduction At very low temperatures (temperatures near the freezing point), the rate of evaporation of water (or any liquid) is negligible. But as its temperature increases, more
More informationSIMULATION OF THERMODYNAMIC ANALYSIS OF CASCADE REFRIGERATION SYSTEM WITH ALTERNATIVE REFRIGERANTS
INTERNATIONAL JOURNAL OF MECHANICAL ENGINEERING AND TECHNOLOGY (IJMET) International Journal of Mechanical Engineering and Technology (IJMET), ISSN 0976 6340(Print), ISSN 0976 6340 (Print) ISSN 0976 6359
More informationGas Laws. The kinetic theory of matter states that particles which make up all types of matter are in constant motion.
Name Period Gas Laws Kinetic energy is the energy of motion of molecules. Gas state of matter made up of tiny particles (atoms or molecules). Each atom or molecule is very far from other atoms or molecules.
More informationAP Physics B 2008 Scoring Guidelines
P Physics B 008 Scoring Guidelines The College Board: Connecting Students to College Success The College Board is a not-for-profit membership association whose mission is to connect students to college
More informationDETERMINING THE MOLAR MASS OF CARBON DIOXIDE
DETERMINING THE MOLAR MASS OF CARBON DIOXIDE PURPOSE: The goal of the experiment is to determine the molar mass of carbon dioxide and compare the experimentally determined value to the theoretical value.
More informationEfficiency of Hydrogen Liquefaction Plants
Efficiency of Hydrogen Liquefaction Plants Takashi FUKANO**, Urs FITZI*, Karl LÖHLEIN*, Isabelle VINAGE* * Linde Kryotechnik AG, CH-8422 Pfungen, Switzerland ** Nippon Sanso Corporation, JP-210-0861 Kawasaki-City,
More informationCommercial refrigeration has been in the environmental. Refrigerant. as a. Basics Considerations PART 1:
PART 1: CO 2 Commercial refrigeration has been in the environmental spotlight for more than a decade, especially as leakage studies have revealed the true effects of hydrofluorocarbon (HFC) emissions.
More informationGases and Kinetic-Molecular Theory: Chapter 12. Chapter Outline. Chapter Outline
Gases and Kinetic-Molecular heory: Chapter Chapter Outline Comparison of Solids, Liquids, and Gases Composition of the Atmosphere and Some Common Properties of Gases Pressure Boyle s Law: he Volume-Pressure
More informationA Performance Comparison of Vapour Compression Refrigeration System Using Eco Friendly Refrigerants of Low Global Warming Potential
International Journal of Scientific and Research Publications, Volume 2, Issue 9, September 2012 1 A Performance Comparison of Vapour Compression Refrigeration System Using Eco Friendly Refrigerants of
More informationPERFORMANCE EVALUATION OF NGCC AND COAL-FIRED STEAM POWER PLANTS WITH INTEGRATED CCS AND ORC SYSTEMS
ASME ORC 2015 3rd International Seminar on ORC Power Systems 12-14 October 2015, Brussels, Belgium PERFORMANCE EVALUATION OF NGCC AND COAL-FIRED STEAM POWER PLANTS WITH INTEGRATED CCS AND ORC SYSTEMS Vittorio
More informationKinetic Theory of Gases
Kinetic Theory of Gases Physics 1425 Lecture 31 Michael Fowler, UVa Bernoulli s Picture Daniel Bernoulli, in 1738, was the first to understand air pressure in terms of molecules he visualized them shooting
More informationAPPLIED THERMODYNAMICS. TUTORIAL No.3 GAS TURBINE POWER CYCLES. Revise gas expansions in turbines. Study the Joule cycle with friction.
APPLIED HERMODYNAMICS UORIAL No. GAS URBINE POWER CYCLES In this tutorial you will do the following. Revise gas expansions in turbines. Revise the Joule cycle. Study the Joule cycle with friction. Extend
More informationWe will study the temperature-pressure diagram of nitrogen, in particular the triple point.
K4. Triple Point of Nitrogen I. OBJECTIVE OF THE EXPERIMENT We will study the temperature-pressure diagram of nitrogen, in particular the triple point. II. BAKGROUND THOERY States of matter Matter is made
More information(1) The size of a gas particle is negligible as compared to the volume of the container in which the gas is placed.
Gas Laws and Kinetic Molecular Theory The Gas Laws are based on experiments, and they describe how a gas behaves under certain conditions. However, Gas Laws do not attempt to explain the behavior of gases.
More informationGases. States of Matter. Molecular Arrangement Solid Small Small Ordered Liquid Unity Unity Local Order Gas High Large Chaotic (random)
Gases States of Matter States of Matter Kinetic E (motion) Potential E(interaction) Distance Between (size) Molecular Arrangement Solid Small Small Ordered Liquid Unity Unity Local Order Gas High Large
More informationCONTENTS. ZVU Engineering a.s., Member of ZVU Group, WASTE HEAT BOILERS Page 2
WASTE HEAT BOILERS CONTENTS 1 INTRODUCTION... 3 2 CONCEPTION OF WASTE HEAT BOILERS... 4 2.1 Complex Solution...4 2.2 Kind of Heat Exchange...5 2.3 Heat Recovery Units and Their Usage...5 2.4 Materials
More informationWhen the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid.
Fluid Statics When the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid. Consider a small wedge of fluid at rest of size Δx, Δz, Δs
More informationThe Second Law of Thermodynamics
Objectives MAE 320 - Chapter 6 The Second Law of Thermodynamics The content and the pictures are from the text book: Çengel, Y. A. and Boles, M. A., Thermodynamics: An Engineering Approach, McGraw-Hill,
More informationThe Fundamentals of Gas Flow Calibration
The Fundamentals of Gas Flow Calibration Application Note Introduction Understanding the fundamentals of gas flow calibration is essential for evaluating calibration systems, estimating the magnitude of
More informationOptimal operation of simple refrigeration cycles Part I: Degrees of freedom and optimality of sub-cooling
Computers and Chemical Engineering 31 (2007) 712 721 Optimal operation of simple refrigeration cycles Part I: Degrees of freedom and optimality of sub-cooling Jørgen Bauck Jensen, Sigurd Skogestad Department
More informationFully Pumped Systems
Fully Pumped Systems (also see the picture gallery and System Basics) The term for any boiler that uses a pump to move all the heat from the boiler to every part of the system is fully pumped. As a rule
More informationTHEORETICAL AND EXPERIMENTAL EVALUATION OF AUTOMOBILE AIR-CONDITIONING SYSTEM USING R134A
THEORETICAL AND EXPERIMENTAL EVALUATION OF AUTOMOBILE AIR-CONDITIONING SYSTEM USING R134A Jignesh K. Vaghela Assistant Professor, Mechanical Engineering Department, SVMIT, Bharuch-392001, (India) ABSTRACT
More informationCHAPTER 12. Gases and the Kinetic-Molecular Theory
CHAPTER 12 Gases and the Kinetic-Molecular Theory 1 Gases vs. Liquids & Solids Gases Weak interactions between molecules Molecules move rapidly Fast diffusion rates Low densities Easy to compress Liquids
More informationModule 5: Combustion Technology. Lecture 34: Calculation of calorific value of fuels
1 P age Module 5: Combustion Technology Lecture 34: Calculation of calorific value of fuels 2 P age Keywords : Gross calorific value, Net calorific value, enthalpy change, bomb calorimeter 5.3 Calculation
More informationIncreasing the evaporation temperature with the help of an internal heat exchanger
Increasing the evaporation temperature with the help of an internal heat exchanger A. TAMBOVTSEV (a), H. QUACK (b) (a,b) Technische Universität Dresden, D-01062, Dresden, Germany (a) Fax: (+49351) 463-37247,
More informationUnit 3: States of Matter Practice Exam
Page 1 Unit 3: States of Matter Practice Exam Multiple Choice. Identify the choice that best completes the statement or answers the question. 1. Two gases with unequal masses are injected into opposite
More informationUnit 24: Applications of Pneumatics and Hydraulics
Unit 24: Applications of Pneumatics and Hydraulics Unit code: J/601/1496 QCF level: 4 Credit value: 15 OUTCOME 2 TUTORIAL 1 HYDRAULIC PUMPS The material needed for outcome 2 is very extensive so there
More informationIEA Workshop Copenhagen Small scale biomass co-generation with modern steam engines
IEA Workshop Copenhagen Small scale biomass co-generation with modern steam engines Dipl.-Ing. Till Augustin October, 7 th 2010 Solid Biomass Cogeneration with Spilling Steam Engines Contents: Who is Spilling
More informationFundamentals of THERMAL-FLUID SCIENCES
Fundamentals of THERMAL-FLUID SCIENCES THIRD EDITION YUNUS A. CENGEL ROBERT H. TURNER Department of Mechanical JOHN M. CIMBALA Me Graw Hill Higher Education Boston Burr Ridge, IL Dubuque, IA Madison, Wl
More informationCOMPARISON OF PROCESS FLOWS: FLUID BED COMBUSTOR AND GLASSPACK
COMPARISON OF PROCESS FLOWS: FLUID BED COMBUSTOR AND GLASSPACK PURPOSE The purpose of this document is to present the assumptions and calculations used to prepare Minergy Drawing 100-0204-PP00 (attached).
More informationModelling and Simulation of the Freezing Systems and Heat Pumps Using Unisim Design
Modelling and Simulation of the Freezing Systems and Heat Pumps Using Unisim Design C. Patrascioiu Abstract The paper describes the modeling and simulation of the heat pumps domain processes. The main
More informationPrinciples of Engine Operation
Internal Combustion Engines ME 422 Yeditepe Üniversitesi Principles of Engine Operation Prof.Dr. Cem Soruşbay Information Prof.Dr. Cem Soruşbay İstanbul Teknik Üniversitesi Makina Fakültesi Otomotiv Laboratuvarı
More informationAnalysis of Ammonia Water (NH3-H2O) Vapor Absorption Refrigeration System based on First Law of Thermodynamics
International Journal of Scientific & Engineering Research Volume 2, Issue 8, August-2011 1 Analysis of Ammonia Water (NH3-H2O) Vapor Absorption Refrigeration System based on First Law of Thermodynamics
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Chapter 10 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) A gas at a pressure of 10.0 Pa exerts a force of N on an area of 5.5 m2. A) 1.8 B) 0.55
More informationME 24-221 THERMODYNAMICS I
Solution to extra problem in chapter 8 Noember 9, 000 Fall 000 J. Murthy ME 4- HERMODYNAMICS I 8.5 Water i ued a the working fluid in a Carnot cycle heat engine, where it change from aturated liquid to
More informationLECTURE 28 to 29 ACCUMULATORS FREQUENTLY ASKED QUESTIONS
LECTURE 28 to 29 ACCUMULATORS FREQUENTLY ASKED QUESTIONS 1. Define an accumulator and explain its function A hydraulic accumulator is a device that stores the potential energy of an incompressible fluid
More informationLiquefied Natural Gas (LNG)
Graduate Diploma in Petroleum Studies Major in Liquefied Natural Gas (LNG) INDUCTION Launching ceremony Week 39, 2012 Administration / Plant visit / Fundamentals of LNG and LNG main risks awareness Module
More informationEXPERIMENT 13: THE IDEAL GAS LAW AND THE MOLECULAR WEIGHT OF GASES
Name Section EXPERIMENT 13: THE IDEAL GAS LAW AND THE MOLECULAR WEIGHT OF GASES PRE-LABORATORY QUESTIONS The following preparatory questions should be answered before coming to lab. They are intended to
More informationACFM vs. SCFM vs. ICFM Series of Technical White Papers from Ohio Medical Corporation
ACFM vs. SCFM vs. ICFM Series of Technical White Papers from Ohio Medical Corporation Ohio Medical Corporation 1111 Lakeside Drive Gurnee, IL 60031 Phone: (800) 448-0770 Fax: (847) 855-6304 info@ohiomedical.com
More information