# Chapter 19. Mensuration of Sphere

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1 8 Chapter Sphere: A sphere is a solid bounded by a closed surface every point of which is equidistant from a fixed point called the centre. Most familiar examples of a sphere are baseball, tennis ball, bowling, and so forth. Terms such as radius, diameter, chord, and so forth, as applied to the sphere are defined in the same sense as for the circle. Thus, a radius of a sphere is a straight line segment connecting its centre with any point on the sphere. Obviously, all radii of the same sphere are equal. Diameter of the sphere is a straight line drawn from the surface and after passing through the centre ending at the surface. The sphere may also be considered as generated by the complete rotation of a semicircle about a diameter. Great and Small Circles: Every section made by a plane passed through a sphere is a circle. If the plane passes through the centre of a sphere, the plane section is a great circle; otherwise, the section is a small circle (Fig. ). Clearly any plane through the centre of the sphere contains a diameter. Hence all great circles of a sphere are equals have for their common centre, the centre of the sphere and have for their radius, the radius of the sphere. Hemi-Sphere: A great circle bisects the surface of a sphere. One of the two equal parts into which the sphere is divided by a great circle is called a hemisphere. 19. Surface Area and Volume of a Sphere: If r is the radius and d is the diameter of a great circle, then (i) Surface area of a sphere = 4 times the area of its great circle

2 9 = 4π r = π d (ii) Volume of a sphere 4 π = π r d (iii) For a spherical shell if R and r are outer and inner radii respectively, then the volume of a shell is = = d ) Example 1: The diameter of a sphere is 1.5m. Find its surface area and volume. Solution: Here d = 1.5m Surface area = 4π r = π d = π(1.5) = 57.5 sq. m. Volume of sphere 4 π = π r d = π (1.5) = cu. m. Example : Two spheres each a 10m diameter are melted down and recast into a cone with a height equal to the radius of its base, Find the height of the cone. Solution: Here d = 10m Radius of cone = height of the cone r = h π Volume of sphere = d π = 10 = π x 1000 = cu. m Volume of two sphere= cu. m. Volume of the cone = volume of two spheres

3 70 Example : 1 π r h 1 π h = = h = x π = 1000 h = 10m How many leaden ball of a 1 cm. in diameter can be cost out of 4 metal of a ball cm in diameter supposing no waste. Solution: Here diameter of leaden ball = 1 4 cm. = d 1 Diameter of metal ball = cm = d Volume of leaden ball = Volume of metal ball = π d1 π 1 = 4 = cu. cm π d π = () = cu. cm Number of leaden ball = Exercise 19(A) Q.1 How many square meter of copper will be required to cover a hemispherical dome 0m in diameter? Q. A lead bar of length 1cm, width cm and thickness cm is melted down and made in four equal spherical bullets. Find the radius of each bullet. Q. A sphere of diameter cm is charged with 157 coulomb of electricity. Find the surface density of electricity. (Hint: surface density = coulomb. Change/sq. cm.)

4 71 Q.4 A circular disc of lead cm in thickness and 1cm diameter, is wholly converted into shots of radius 0.5cm. Find the number of shots. Q.5 The radii of the internal and external surfaces of a hollow spherical shell are m and 5m respectively. If the same amount of material were formed into cube what would be the length of the edge of the cube? Q. A spherical cannon ball, cm in diameter is melted and cast into a conical mould the base of which is 1cm. in diameter. Find the height of the cone. Q.7 A solid cylinder of brass is 10cm. in diameter and m long. How many spherical balls each cm. in radius, can be made from it? 1 Q.8 A hundred gross billiard balls in. in diameter are to be painted. Assuming the average covering capacity of white paint to be 500 sq. in. per gallon, one coat, how many gallons are required to paint the hundred gross billiard balls? (1 gallon = 1 cu. in) Q.9 How many cu. ft. of gas are necessary to inflate a spherical balloon to a diameter of 0in? Q.10 The average weight of a cu. ft. of copper is 555 Lbs. What is the weight of 8 solid spheres of this metal having a diameter of 1in? Q.11 Find the relation between the volumes and the surface areas of the cylinder, sphere and cone, when their heights and diameters are equal. Q.1 A storage tank, in the form of a cylinder with hemisphere ends, 15m. long overall and m. in diameter. Calculate the weight of water, in liters, contained when the tank is one-third full. Q.1 A cost iron sphere of 8cm. in diameter is coated with a layer of lead 7cm thick. Density of lead is gm/cu.cm. Find the total weight of the lead. Answers 19(A) Q sq. m Q..4cm. Q coulomb/sq. cm. Q.4 48 Q m Q. cm Q.7 70 Balls Q.8.9 gallons Q cu. ft. Q Lbs. Q.11 ::1 ; 1:1: Q gms. 5 4 Q liters

5 7 19. Zone (Frustum) of a Sphere: The portion of the surface of a sphere included between two parallel planes, which intersect the sphere, is called a zone. The distance between the two planes is called height or thickness of the zone Volume and Surface Area of the Zone: Let r 1 and r are the radii of the small circles respectively, r is the radius of the great circle and h is the height of the zone, then (i) The volume of the zone of a sphere may be found by taking the difference between segment CDE and ADB (Fig. ), that is π h V = (h r1 r ) (ii) Surface area of the zone = Circumference of the great circle x height of the zone = π r x h (iii) Total surface area of the zone = π r h + π r1 π r (iv) For a special segment of one base, the radius of the lower base r is equal to zero. Therefore, π h V = (h r 1 ) In this case, the total surface area of the segment π r h + π r 19.5 Spherical Segment or Cap of a Sphere: If a plane cuts the sphere into two portions then each portion is known as a segment. The smaller portion is known as minor segment and the larger portion is known as major segment. Bowl is a spherical segment. 1

6 7 19. Volume and Surface Area of Spherical Segment: If r 1 and r are the radius of the segment and sphere respectively and h is the height of the segment, then (i) Volume of the segment of one base = π h (h r ) 1 (ii) (iii) = π h (r h) Volume of the segment of two bases = π h (h + r 1 r ) Surface area = Perimeter of the sphere x height of the zone = π r h 19.7 Sector of Sphere: A sector of a sphere is the solid subtended at the centre of the sphere by a segment cap (Fig. 7). Example 4:

7 74 A sphere is cut by two parallel planes. The radius of the upper circle is 7cm and the lower circle is 0cm. Both circles are on the same side of the sphere. The thickness of the zone is 9cm. Find the volume and the surface area of the zone. Solution: Here r 1 = 7cm r = 0cm, h = 9cm Volume of the zone = π h (h + r 1 r ) = π x 9 {(9) (7) (0) } = π x ( ) = π x x148 = 79.9 cu. cm. In the right triangles OAB and OCD, OB = OA + AB = x + (0) and OD = OC + CD = (x + 9) + (7) Since OB = OD Or OB = OD Or x + 0 = (x + 9) + 7 x = x + 18x = 18x + 10 x = 15cm Now, from (1) OB = OB = 5 OB = r = 5cm So, area of the zone = π r h = π x 5 x 9 = sq. cm. Example 5: What proportion of the volume of a sphere 0cm. in diameter is contained between two parallel planes distant cm from the centre and on opposite side of it? Solution: Here r 1 = cm

8 75 r = cm h = 1cm d = 0cm π Volume of the sphere = d π = (0) = cu. cm Volume of the zone = π h (h + r 1 r ) = π x 1 (1 + ) = π x ( ) = 1.95 cu. cm. Proportion of the volume of the sphere between the zone = or 54% Exercise 19(B) Q.1 The sphere of radius 8cm is cut by two parallel planes, one passing cm. from the centre and the other 7cm. from the centre. Find the area of the zone and volume of the segment between two planes if both are on the same side of the centre. Q. Find the volume of the zone and the total surface area of the zone of a sphere of radius 8cm, and the radius of the smaller end is cm. The thickness of the zone is 1cm. Q. What is the volume of a spherical segment of a sphere of one base if the altitude of the segment is 1cm. and radius of the sphere is cm. Q.4 What percentage of the volume of a sphere 1cm. in diameter is contained between two parallel planes distant 4cm and cm. from the centre and on opposite side of it. Q.5 Find the nearest gallons the quantity of water contains in a bowl whose shape is a segment of sphere. The depth of bowl is 7in. and radius of top is 11 in. (1 gallon = 1 cu. cm.) Q. The core for a cast iron piece has the shape of a spherical segment of two bases. The diameters of the upper and lower bases are ft. and ft. respectively, and the distance between the bases is ft. If the average weight of a cu. ft. of core is 100 Lbs. find the weight of the core.

9 7 Q.7 The bronze base of a statuette has the shape of a spherical segment of one base. The metal has a uniform thickness of 1/8in.; the 1 diameter of the inner sphere is 4 in.; and the altitude of the segment formed by the inner shell is in. find the weight of the bronze base. (The average weight of a cu. ft. bronze is 59 Lbs.) Answers 19(B) Q sq. cm cu. cm Q sq. cm., 194. cu. cm Q cu. m. Q % Q.5.5 gallons Q Lbs. Q Lbs. Summary If r is the radius and d is the diameter of a great circle, then 1. S = Surface area of a sphere = 4π r Or = π d. Volume of sphere 4 π = π r or d. For a spherical shell if R and r are the outer and inner radii respectively, then Volume of the shell 4 π = π(r r ) or (D d ) Zone of sphere If the two parallel planes cut the sphere, then the portion of the sphere between the parallel planes is called the zone of the sphere. π h (i) Volume of the zone = V = (h +r 1 +r ) where r 1, r are the radii of circles of base and top of zone. (ii) Surface area of the zone = circumference of the great circle x height of the zone i.e π r h (iii) Total surface area of the zone = π r h+πr 1 +πr (iv) For a special segment of one base, the radius of the lower base r =0 π h Volume of the segment = V = (h +r 1 ) In this case, Total surface area of the segment = π r h+π r 1

11 78 Objective Type Questions Q.1 Each questions has four possible answers. Choose the correct answer and encircle it. 1. The surface area of a sphere of radius r is (a) 4π r (b) 4π r (c) π r (d) 4 π r. The volume of a sphere of diameter D is 4 (a) D π (b) 4πD (c) D π (d) D π 4. If R and r are the external and internal radii of spherical shell respectively, then its volume is 4 (a) π (R r ) (b) 4 π (R r ) (c) 4π (R r ) (d) π (R r ) 4. If a plane cuts a sphere into two unequal positions then each portion is called (a) circle (b) diameter (c) hemi-sphere (d) segment 5. If two parallel planes cut the sphere by separating two segments, the portion between the planes is called (a) zone (b) volume (c) surface (d) hemisphere. Volume of hemi-sphere is (a) π r 4 (b) π r 1 (c) π r (d) π r 7. Area of cloth to cover tennis ball of radius.5cm is (a) 154 sq. cm (b) 77 sq. cm (c) 08 sq. cm (d) 1 sq.cm 8. Volume of sphere of radius cm is (a) 108 π cu. cm (b) π cu. cm (c) 1 π cu. cm (d) 45 π cu. cm Answers Q.1 (1) b () c () a (4) d (5) d () a (7) a (8) b

12 79 Linear and Area Measure: Linear Measure: 1 inches (in) = 1 foot (ft.) feet = 1 yard (yd) inches = 1 yard 0 yards = 1 Furlong (Fr.) 8 Furlong = 1 Mile (mi) 170 yards = 1 mile 1 meter (m) = 1000 centimeter (cm.) 10 millimeters (mm) = 1 cm. 10 cms = 1 decimeter (dm.) 10 dm = 1 m 10 m = 1 Dekameter (DM.) 10 Dms. = 1 Hectometer (HM.) 1 inch =.54cm 1 ft. = 0.048m 1 yd = m 1 mile = 1.09 Km 1cm = 0.97 in. 1 m =.808 ft. 1 m = 1.09 yd 1 Km = 0.14 mile Area Measure: 1 sq. ft. = 144 sq. in. 1 sq. yd. = 9 sq. ft. 1 sq. yd. = 19 sq. in 1 sq. mi = 40 acres 1 acre = 4840 sq. yd. 1 sq. cm = 100 sq. m.m. 1 sq. m = sq. cm. Capacity: 1 gallon = litres 1 gallon = 10 Lbs 1 cu. ft. of water =. Lbs 1 litre = 1000 cu. cm 1 gallon = 1 cu. inch.

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