How To Understand The Distributed Potential Of A Dendritic Tree



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Systems Biology II: Neural Systems (580.422) Lecture 8, Linear cable theory Eric Young 5-3164 eyoung@jhu.edu Reading: D. Johnston and S.M. Wu Foundations of Cellular Neurophysiology (MIT Press, 1995). Chapters 4 and 13 (esp. pp. 396-411). S.R. Williams and G.J. Stuart Role of dendritic synapse location in the control of action potential output. Trends in Neurosciences 26:147-154 (2003). Neurons are not a single compartment! The figures below show two snapshots of the membrane potential in a model of the dendritic tree of a Purkinje cell from the cerebellum during a dendritic action potential. Note the substantial differences in potential across the dendrites and also how potential spreads through the tree with time. (from De Schutter and Smolen, http://www.bbf.uia.ac.be) 1

Synapses do not distribute randomly over the surface of a neuron. For example, inhibitory synapses are often located on the soma and proximal dendrites, whereas excitatory synapses are located further out on the dendrites. The examples at right show distribution of synaptic terminals of various types (identified by color) on the somas and proximal dendrites of neurons in the dorsal cochlear nucleus (distal dendrites were not reconstructed). Fusiform cells are principal cells and the other two are inhibitory interneurons. Their connections are shown. Rubio, 2004 The questions for this and the next lecture: 1. What difference does it make where a synaptic terminal is located? Is there a difference between these two terminals because of their locations, for example? 2. How do synapses at different locations interact? Do they interact more strongly if they are close together? Is there a difference between the interactions of synapses located on the same versus different dendritic branches? A component of this question is to explain why inhibitory synapses cluster near the soma. 2

Distributed properties of dendritic trees are analyzed using the cable model Δx I i (x-δx) I i (x) #1 #2 #3 I i (x+δx) I m (x-δx) Δx I m (x) Δx I m (x+δx) Δx Ion channels in the membrane go here V i (x-δx) I i (x-δx) V i (x) I i (x) V i (x+δx) I i (x+δx) I m (x) Δx Δx #1 #2 c m Δx #3 r e Δx V e (x-δx) I e (x-δx) V e (x) I e (x) V e (x+δx) I e (x+δx) The full derivation of the cable model is given in the notes attached to this lecture. A brief summary is given below. Applying Kirchoff s current law at one of the nodes, I m (x) = I cap (x) + I ion (x) There are factors of Δx multiplying each term in the model, because the size of the current is proportional to the length of the compartment. These cancel. The membrane current I m (x) is the difference between the current I i (x-δx) flowing into the node and the current I i (x) flowing out of the node. This difference is proportional to the spatial derivative of I i, - I i / x. In turn, I i (x) is proportional to the spatial derivative of membrane potential -(1/ ) V i / x, which is Ohm s law, so the membrane current is the divergence of membrane potential (1 ) 2 V i x. 2 1 2 V i 1 r e 2 V e 3

By the same argument at the extracellular node, 1 r e 2 V e = I m = 1 2 V i Now the transmembrane potential V = V i - V e so 2 V = 2 V i 2 V e = ( )I m so that 1 2 V x = I = I + I 2 m cap ion The current through the capacitos I cap (x)δx = c m Δx V i most general form of the cable equation. 1 2 V x = c V 2 m t + I ion t, which gives the 1 2 V i 1 r e 2 V e To obtain analytical solutions, the membrane is linearized Now the ionic current is given by I ion = (V-E rest ). Because the differential equation is now lineat is possible to change the reference point for the membrane potential from 0 mv across the membrane to the resting potential. This amounts to a change in variable in the differential equation, replacing V-E rest with V. This gives the linear cable equation: Which is usually written as below, defining a length parameter λ and a membrane time constant τ m. λ 2 2 V 1 2 V = c m V t + V = τ V t + V where λ= 1 ( ) and τ m = c m 4

Parameters: it is useful to relate the parameters of the ladder model to properties of the cylinder membrane. c m = cap. per unit length of cylinder = 2πaC = conductance of unit length of cyl. = 2πa /R m = resistance of unit length of cytoplasm = R i /πa 2 where C is the capacitance of a unit area of membrane, 1 µfd/cm 2 R m is the resistance of a unit area of membrane, 10 3-10 5 Ω. cm 2 R i is the resistance of a unit cube of cytoplasm, and a is the radius of the cylinder. 200 Ω. cm THEN the two parameters of the cable equation are given by λ = 1 ( ) 1 = a R m and τ = c m = R m C 2R i Electrotonic processing in dendrites: potentials become smallen amplitude and more spread out in time as they propagate away from the source 0.1τ I(t) Membrane potential V Distance down the cylinder, in units of λ V(x,t) Time, in units of τ λ 2 2 V = τ V t + V V(x,t = 0) = 0 V x x=0 = I(t) and V(x,t) = finite x,t Jack, Noble, & Tsien, 1975 5

Parameters of the cable model: λ is the length constant. To see why, consider the steady-state distribution of membrane potential, say in response to a steady current after a long time. In this situation, V/ t = 0 and the cable equation becomes λ 2 d 2 V dx 2 V = 0 The homogeneous solution takes the form V (x) = Ae x / λ + Be x / λ where A and B are constants determined from the initial conditions. The solutions vary exponentially with distance x divided by λ, showing that λ determines the distance through which disturbances spread along a cable. λ = 1 = R m 2R i a Note that the length constant is proportional to a 1/2, so potentials spread furthen larger cylinders. For a 1 µm dendrite with R m =3x10 4 Ω. cm 2, λ = 866 µm Parameters of the cable model: τ is the time constant. In all solutions to the cable equation, time appears as t/τ, so that τ determines the time scale of solutions, e.g. how long it takes membrane potential to change in response to an injected current. τ = c m = R m C Note that the time constant does not depend on the cylinder size. For a process with R m =3x10 4 Ω. cm 2, τ = 30 ms. This decay time is approximately τ. 6

The cable model at work: EPSCs recorded in the soma show the effects expected, depending on the dendritic source (smaller and slowef initiated further away) soma stimulation sites on dendrites Bekkars and Stevens, 1996 The distance that a potential propagates in a membrane cylindes set by the length constant λ. For this reason, a meaningful measure of the length of a membrane cylindes its electrotonic length, equal to physical length divided by λ. For a semi-infinite cylinder, the potential decays as e -x/λ with distance. For finite cylinders, the decay depends on the boundary condition (or load) at the second end. V-clamped open circuit I(t) V-clamped short circuit L= V(x)? Load X = x / λ Electrotonic length physical length (mm) = L = λ 7

How large is a cell? This can be answered in terms of physical length, as in the picture at right. A more meaningful answes in terms of electrical size, some measure of the electrical coupling between two points. Two measures: 1. Electrotonic length (as defined previously) P 2. The morphoelectrotonic transform (MET), in which distance is defined in terms of voltage attenuation A as follows: then the MET is L PQ = l PQ λ A PR = V R V P resulting potential observed at point R membrane potential produced at point P, say by a synapse R l PQ Q Λ PR = ln A PR Note that Λ PR incorporates both the exponential decay of potential with distance and the effects of branching (which the cumulative electrotonic length L PQ +L QR would not). Justification for the MET: Consider again a semi-infinite cylinder driven by a constant current I 0 at one end, at times where the potential is in steady state. I 0 V(x)=V 0 e-x/λ The voltage gain from the point of current injection to point x is and the MET is A(x) = V (x) V 0 = e x / λ Λ(x) = ln( e x / λ ) = x λ = L(x) so in this special case, the MET corresponds to the electrotonic length. Again, the advantage of the MET is that it takes into account the effects of branching, not relevant in this example. 8

How large is the dendritic tree? NOTE that the MET is different depending on the direction in which it is defined. physical size electrotonic length, equal to length/length const C) Λ IS D) Λ SI MET, dendrite to soma Note smaller! MET, soma to dendrites (note scale!) Zador, 1993 A cell s electrical size depends on the amount of synaptic input it receives. The somaward METs at right are for a cell with no synaptic input (left) and a cell with substantial, randomly occurring, input (right). Note the cell is electrically larger with synaptic input. This is explained as an effect of synaptic input on R m and therefore on λ, since λ = R m 2R i a (λ decreases as R m decreases, making the cell electrically larger.) Bernander et al., 1991 9