LIMITS AND DERIVATIVES

Similar documents
The Derivative as a Function

f(a + h) f(a) f (a) = lim

Average rate of change of y = f(x) with respect to x as x changes from a to a + h:

2.2 Derivative as a Function

correct-choice plot f(x) and draw an approximate tangent line at x = a and use geometry to estimate its slope comment The choices were:

Microeconomic Theory: Basic Math Concepts

= f x 1 + h. 3. Geometrically, the average rate of change is the slope of the secant line connecting the pts (x 1 )).

Review of Fundamental Mathematics

Section 3.7. Rolle s Theorem and the Mean Value Theorem. Difference Equations to Differential Equations

5.1 Derivatives and Graphs

Average rate of change

2.2. Instantaneous Velocity

Calculus 1st Semester Final Review

The Derivative. Philippe B. Laval Kennesaw State University

Definition of derivative

PRACTICE FINAL. Problem 1. Find the dimensions of the isosceles triangle with largest area that can be inscribed in a circle of radius 10cm.

TOPIC 4: DERIVATIVES

Examples of Tasks from CCSS Edition Course 3, Unit 5

18.01 Single Variable Calculus Fall 2006

Chapter 4 One Dimensional Kinematics

To define concepts such as distance, displacement, speed, velocity, and acceleration.

How To Understand The Theory Of Algebraic Functions

Worksheet 1. What You Need to Know About Motion Along the x-axis (Part 1)

Two Fundamental Theorems about the Definite Integral

Mathematics 31 Pre-calculus and Limits

Rolle s Theorem. q( x) = 1

Core Maths C1. Revision Notes

2008 AP Calculus AB Multiple Choice Exam

Derivatives as Rates of Change

3.1 MAXIMUM, MINIMUM AND INFLECTION POINT & SKETCHING THE GRAPH. In Isaac Newton's day, one of the biggest problems was poor navigation at sea.

Mark Howell Gonzaga High School, Washington, D.C.

PLOTTING DATA AND INTERPRETING GRAPHS

GRAPHING IN POLAR COORDINATES SYMMETRY

Basic numerical skills: EQUATIONS AND HOW TO SOLVE THEM. x + 5 = = (2-2) = = 5. x = 7-5. x + 0 = 20.

x 2 + y 2 = 1 y 1 = x 2 + 2x y = x 2 + 2x + 1

Consumer Theory. The consumer s problem

Objectives. Materials

AP CALCULUS AB 2009 SCORING GUIDELINES

Differentiation of vectors

Numerical Solution of Differential Equations

ab = c a If the coefficients a,b and c are real then either α and β are real or α and β are complex conjugates

2.1 Increasing, Decreasing, and Piecewise Functions; Applications

MATH 10550, EXAM 2 SOLUTIONS. x 2 + 2xy y 2 + x = 2

Mark Howell Gonzaga High School, Washington, D.C.

2013 MBA Jump Start Program

1 of 7 9/5/2009 6:12 PM

Microeconomics Sept. 16, 2010 NOTES ON CALCULUS AND UTILITY FUNCTIONS

Calculus with Parametric Curves

AP Calculus BC 2008 Scoring Guidelines

List the elements of the given set that are natural numbers, integers, rational numbers, and irrational numbers. (Enter your answers as commaseparated

= δx x + δy y. df ds = dx. ds y + xdy ds. Now multiply by ds to get the form of the equation in terms of differentials: df = y dx + x dy.

Elements of a graph. Click on the links below to jump directly to the relevant section

AP Calculus AB 2007 Scoring Guidelines Form B

Tangent Lines and Rates of Change

Slope and Rate of Change

Representation of functions as power series

AP Calculus AB 2005 Free-Response Questions

Lecture 2. Marginal Functions, Average Functions, Elasticity, the Marginal Principle, and Constrained Optimization

Student Performance Q&A:

Properties of Real Numbers

An Introduction to Calculus. Jackie Nicholas

Class Meeting # 1: Introduction to PDEs

AP Calculus BC 2006 Free-Response Questions

Lecture 3: Derivatives and extremes of functions

AP Calculus AB Syllabus

MULTIVARIATE PROBABILITY DISTRIBUTIONS

Example SECTION X-AXIS - the horizontal number line. Y-AXIS - the vertical number line ORIGIN - the point where the x-axis and y-axis cross

Graphing Motion. Every Picture Tells A Story

AP Calculus AB 2006 Scoring Guidelines

Estimated Pre Calculus Pacing Timeline

AP Calculus AB First Semester Final Exam Practice Test Content covers chapters 1-3 Name: Date: Period:

88 CHAPTER 2. VECTOR FUNCTIONS. . First, we need to compute T (s). a By definition, r (s) T (s) = 1 a sin s a. sin s a, cos s a

CHAPTER FIVE. Solutions for Section 5.1. Skill Refresher. Exercises

Taylor and Maclaurin Series

Exam 1 Sample Question SOLUTIONS. y = 2x

AP Calculus BC 2001 Free-Response Questions

DERIVATIVES AS MATRICES; CHAIN RULE

Homework #2 Solutions

MA107 Precalculus Algebra Exam 2 Review Solutions

A QUICK GUIDE TO THE FORMULAS OF MULTIVARIABLE CALCULUS

Graphical Integration Exercises Part Four: Reverse Graphical Integration

AP Calculus AB 2010 Free-Response Questions Form B

Calculus AB 2014 Scoring Guidelines

Linear Equations. Find the domain and the range of the following set. {(4,5), (7,8), (-1,3), (3,3), (2,-3)}

ANALYTICAL METHODS FOR ENGINEERS

Visualizing Differential Equations Slope Fields. by Lin McMullin

What does the number m in y = mx + b measure? To find out, suppose (x 1, y 1 ) and (x 2, y 2 ) are two points on the graph of y = mx + b.

Solving Systems of Two Equations Algebraically

W i f(x i ) x. i=1. f(x i ) x = i=1

A Resource for Free-standing Mathematics Qualifications

Notes for EER #4 Graph transformations (vertical & horizontal shifts, vertical stretching & compression, and reflections) of basic functions.

M Polynomial Functions 1

Lecture 3 : The Natural Exponential Function: f(x) = exp(x) = e x. y = exp(x) if and only if x = ln(y)

Angles and Quadrants. Angle Relationships and Degree Measurement. Chapter 7: Trigonometry

Fundamental Theorems of Vector Calculus

Determine If An Equation Represents a Function

Math 120 Final Exam Practice Problems, Form: A

9.2 Summation Notation

When the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid.

Understanding Basic Calculus

Transcription:

2 LIMITS AND DERIVATIVES

LIMITS AND DERIVATIVES 1. Equation In Section 2.7, we considered the derivative of a function f at a fixed number a: f '( a) = lim h! 0 f ( a + h) " f ( a) h In this section, we change our point of view and let the number a vary.

LIMITS AND DERIVATIVES 2.8 The Derivative as a Function In this section, we will learn about: The derivative of a function f.

THE DERIVATIVE AS A FUNCTION 2. Equation If we replace a in Equation 1 by a variable x, we obtain: f '( x) = lim h! 0 f ( x + h) " f ( x) h

THE DERIVATIVE AS A FUNCTION Given any number x for which this limit exists, we assign to x the number f (x). So, we can regard f as a new function called the derivative of f and defined by Equation 2. We know that the value of f at x, f (x), can be interpreted geometrically as the slope of the tangent line to the graph of f at the point (x,f(x)).

THE DERIVATIVE AS A FUNCTION The function f is called the derivative of f because it has been derived from f by the limiting operation in Equation 2. The domain of f is the set {x f (x) exists} and may be smaller than the domain of f.

THE DERIVATIVE AS A FUNCTION Example 1 The graph of a function f is given in the figure. Use it to sketch the graph of the derivative f.

THE DERIVATIVE AS A FUNCTION Example 1 We can estimate the value of the derivative at any value of x by drawing the tangent at the point (x,f(x)) and estimating its slope.

THE DERIVATIVE AS A FUNCTION Example 1 For instance, for x = 5, we draw the tangent at P in the figure and estimate its slope to be about, so 2 f '(5)! 1.5 This allows us to plot the point P (5, 1.5) on the graph of f directly beneath P. 3

THE DERIVATIVE AS A FUNCTION Example 1 Repeating this procedure at several points, we get the graph shown in this figure.

THE DERIVATIVE AS A FUNCTION Example 1 Notice that the tangents at A, B, and C are horizontal. So, the derivative is 0 there and the graph of f crosses the x-axis at the points A, B, and C, directly beneath A, B, and C.

THE DERIVATIVE AS A FUNCTION Example 1 Between A and B, the tangents have positive slope. So, f (x) is positive there. Between B and C, and the tangents have negative slope. So, f (x) is negative there.

THE DERIVATIVE AS A FUNCTION Example 2 a. If f(x) = x 3 - x, find a formula for f (x). b. Illustrate by comparing the graphs of f and f.

THE DERIVATIVE AS A FUNCTION Example 2 a When using Equation 2 to compute a derivative, we must remember that: The variable is h. x is temporarily regarded as a constant during the calculation of the limit.

THE DERIVATIVE AS A FUNCTION Example 2 a Thus, f ( ) ( ) 3 " # 3 " # f ( x + h) $ f ( x) x + h $ x + h $ % x $ x& '( x) = lim = lim % & h! 0 h h! 0 h = lim h! 0 3 2 2 3 3 x + 3x h + 3xh + h " x " h " x + x h 2 2 3 3x + 3xh + h " h 2 2 lim lim(3x 3xh h 1) h! 0 h! 0 = = + + " h =! 2 3x 1

THE DERIVATIVE AS A FUNCTION Example 2 b We use a graphing device to graph f and f in the figure. Notice that f (x) = 0 when f has horizontal tangents and f (x) is positive when the tangents have positive slope. So, these graphs serve as a check on our work in part (a).

THE DERIVATIVE AS A FUNCTION Example 3 If f ( x) = x, find the derivative of f. State the domain of f.

THE DERIVATIVE AS A FUNCTION Example 3 f ( x + h) " f ( x) x + h " x f '( x) = lim = lim h! 0 h h! 0 h " x + h $ x x + h + x # = lim % h! 0 & h x + h + x ' ( ) ( x + h) " x 1 = lim = lim h! 0 h! 0 h x h x x + h + x ( + + ) 1 1 = = x + x 2 x We see that f (x) exists if x > 0, so the domain of f is This is smaller than the domain of f, which is (0,!) (0,!)

THE DERIVATIVE AS A FUNCTION Let s check to see that the result of Example 3 is reasonable by looking at the graphs of f and f in the figure.

THE DERIVATIVE AS A FUNCTION When x is close to 0, x is also close to 0. So, f (x) = 1/(2 x ) is very large. This corresponds to the steep tangent lines near (0,0) in (a) and the large values of f (x) just to the right of 0 in (b).

THE DERIVATIVE AS A FUNCTION When x is large, f (x) is very small. This corresponds to the flatter tangent lines at the far right of the graph of f and the horizontal asymptote of the graph of f.

THE DERIVATIVE AS A FUNCTION Example 4 Find f if f ( x) 1! x = 2 + x 1 " ( x + h) 1" x " f ( x + h) " f ( x) 2 + ( x + h) 2 + x f '( x) = lim = lim h! 0 h h! 0 h = lim h! 0 (1 " x " h)(2 + x) " (1 " x)(2 + x + h) h(2 + x + h)(2 + x) = lim h! 0 2 2 (2 " x " 2 h " x " xh) " (2 " x + h " x " xh) h(2 + x + h)(2 + x) " 3h " 3 3 = lim = lim = " h! 0 h(2 + x + h)(2 + x) h! 0 (2 + x + h)(2 + x) (2 + x) 2

OTHER NOTATIONS If we use the traditional notation y = f(x) to indicate that the independent variable is x and the dependent variable is y, then some common alternative notations for the derivative are as follows: dy df d f '( x) = y ' = = = f ( x) = Df ( x) = Dx f ( x) dx dx dx

OTHER NOTATIONS The symbols D and d/dx are called differentiation operators. This is because they indicate the operation of differentiation, which is the process of calculating a derivative.

OTHER NOTATIONS The symbol dy/dx which was introduced by Leibniz should not be regarded as a ratio (for the time being). It is simply a synonym for f (x). Nonetheless, it is very useful and suggestive especially when used in conjunction with increment notation.

OTHER NOTATIONS Referring to Equation 6 in Section 2.7, we can rewrite the definition of derivative in Leibniz notation in the form dy dx = lim! x " 0! y! x

OTHER NOTATIONS If we want to indicate the value of a derivative dy/dx in Leibniz notation at a specific number a, we use the notation dy dx x= a or dy dx! " # x= a which is a synonym for f (a).

OTHER NOTATIONS 3. Definition A function f is differentiable at a if f (a) exists. It is differentiable on an open interval (a,b) [or ( a,!) or (!", a) or (!",") ] if it is differentiable at every number in the interval.

OTHER NOTATIONS Example 5 Where is the function f(x) = x differentiable? If x > 0, then x = x and we can choose h small enough that x + h > 0 and hence x + h = x + h. Therefore, for x > 0, we have: f ( ) x + h " x x + h " x h '( x) = lim = lim = lim = lim1 = 1 h! 0 h h! 0 h h! 0 h h! 0 So, f is differentiable for any x > 0.

OTHER NOTATIONS Example 5 Similarly, for x < 0, we have x = -x and h can be chosen small enough that x + h < 0 and so x + h = -(x + h). Therefore, for x < 0, x + h " x "( x + h) " (" x) f '( x) = lim = lim h! 0 h h! 0 h " h = lim = lim( " 1) = " 1 h! 0 h h! 0 So, f is differentiable for any x < 0.

OTHER NOTATIONS Example 5 For x = 0, we have to investigate f '(0) f (0 + h) " f (0) = lim h! 0 h 0 + h " 0 = lim h! 0 h (if it exists)

OTHER NOTATIONS Example 5 Let s compute the left and right limits separately: 0 + h " 0 h h lim = lim = lim = lim 1 = 1 + + + + h h h h! 0 h! 0 h! 0 h! 0 and 0 + h! 0 h! h lim = lim = lim = lim (! 1) =! 1!!!! h h h h" 0 h" 0 h" 0 h" 0 Since these limits are different, f (0) does not exist. Thus, f is differentiable at all x except 0.

OTHER NOTATIONS Example 5 A formula for f is given by: '( x) Its graph is shown in the figure. f =! 1 if x > 0 " $ # 1 if x < 0

OTHER NOTATIONS The fact that f (0) does not exist is reflected geometrically in the fact that the curve y = x does not have a tangent line at (0, 0).

OTHER NOTATIONS Both continuity and differentiability are desirable properties for a function to have. The following theorem shows how these properties are related.

OTHER NOTATIONS 4. Theorem If f is differentiable at a, then f is continuous at a. To prove that f is continuous at a, we have to show that lim f ( x ) = f ( a ). x! a We do this by showing that the difference f(x) - f(a) approaches 0.

OTHER NOTATIONS Proof The given information is that f is differentiable at a. That is, f '( a) = lim x! a f ( x) " f ( a) x " a exists. See Equation 5 in Section 2.7.

OTHER NOTATIONS Proof To connect the given and the unknown, we divide and multiply f(x) - f(a) by x - a (which we can do when x! a ): f ( x)! f ( a) f ( x)! f ( a) = ( x! a) x! a

OTHER NOTATIONS Proof Thus, using the Product Law and Equation 5 in Section 2.7, we can write: f ( x) " f ( a) lim[ f ( x) " f ( a)] = lim ( x " a) x! a x! a x " a f ( x) " f ( a) = lim # lim( x " a) x! a x " a x! a = f '( a)! 0 = 0

OTHER NOTATIONS Proof To use what we have just proved, we start with f(x) and add and subtract f(a): lim f ( x) = lim[ f ( a) + ( f ( x) " f ( a)] x! a x! a = lim f ( a) + lim[ f ( x) " f ( a)] x! a x! a = f ( a) + 0 = f ( a) Therefore, f is continuous at a.

OTHER NOTATIONS Note The converse of Theorem 4 is false. That is, there are functions that are continuous but not differentiable. For instance, the function f(x) = x is continuous at 0 because lim f ( x) = lim x = 0 = f (0) x! 0 x! 0 See Example 7 in Section 2.3. However, in Example 5, we showed that f is not differentiable at 0.

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? We saw that the function y = x in Example 5 is not differentiable at 0 and the figure shows that its graph changes direction abruptly when x = 0.

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? In general, if the graph of a function f has a corner or kink in it, then the graph of f has no tangent at this point and f is not differentiable there. In trying to compute f (a), we find that the left and right limits are different.

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? Theorem 4 gives another way for a function not to have a derivative. It states that, if f is not continuous at a, then f is not differentiable at a. So, at any discontinuity for instance, a jump discontinuity f fails to be differentiable.

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? A third possibility is that the curve has a vertical tangent line when x = a. That is, f is continuous at a and lim f '( x) x! a = "

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? This means that the tangent lines become steeper and steeper as. The figures show two different ways that this can happen. x! a

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? The figure illustrates the three possibilities we have discussed.

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? A graphing calculator or computer provides another way of looking at differentiability. If f is differentiable at a, then when we zoom in toward the point (a,f(a)), the graph straightens out and appears more and more like a line. We saw a specific example of this in Figure 2 in Section 2.7.

HOW CAN A FUNCTION FAIL TO BE DIFFERENTIABLE? However, no matter how much we zoom in toward a point like the ones in the first two figures, we can t eliminate the sharp point or corner, as in the third figure.

HIGHER DERIVATIVES If f is a differentiable function, then its derivative f is also a function. So, f may have a derivative of its own, denoted by (f ) = f.

HIGHER DERIVATIVES This new function f is called the second derivative of f. This is because it is the derivative of the derivative of f. Using Leibniz notation, we write the second derivative of y = f(x) as 2 d! dy " d y # $ = 2 dx % dx & dx

HIGHER DERIVATIVES Example 6 If interpret f (x). 3 f ( x) = x! x, find and In Example 2, we found that the first derivative 2 is f '( x) = 3x! 1. So the second derivative is: f ''( x) = ( f ')'( x) = lim h! 0 h! 0 f '( x + h) " f '( x) h 2 2 2 2 2 [3( x + h) " 1] "[3x " 1] 3x + 6xh + 3h " 1" 3x + 1 = lim = lim h! 0 h h! 0 = lim(6x + 3 h) = 6x h

HIGHER DERIVATIVES Example 6 The graphs of f, f, f are shown in the figure. We can interpret f (x) as the slope of the curve y = f (x) at the point (x,f (x)). In other words, it is the rate of change of the slope of the original curve y = f(x).

HIGHER DERIVATIVES Example 6 Notice from the figure that f (x) is negative when y = f (x) has negative slope and positive when y = f (x) has positive slope. So, the graphs serve as a check on our calculations.

HIGHER DERIVATIVES In general, we can interpret a second derivative as a rate of change of a rate of change. The most familiar example of this is acceleration, which we define as follows.

HIGHER DERIVATIVES If s = s(t) is the position function of an object that moves in a straight line, we know that its first derivative represents the velocity v(t) of the object as a function of time: v( t) = s '( t) = ds dt

HIGHER DERIVATIVES The instantaneous rate of change of velocity with respect to time is called the acceleration a(t) of the object. Thus, the acceleration function is the derivative of the velocity function and is, therefore, the second derivative of the position function: In Leibniz notation, it is: dv a = = dt a( t) = v '( t) = s ''( t) 2 d s dt 2

HIGHER DERIVATIVES The third derivative f is the derivative of the second derivative: f = (f ). So, f (x) can be interpreted as the slope of the curve y = f (x) or as the rate of change of f (x). If y = f(x), then alternative notations for the third derivative are: 2 3 d! d y " d y y ''' = f '''( x) = # 2 $ = 3 dx % dx & dx

HIGHER DERIVATIVES The process can be continued. The fourth derivative f is usually denoted by f (4). In general, the nth derivative of f is denoted by f (n) and is obtained from f by differentiating n times. If y = f(x), we write: ( n) ( n y = f ) ( x) = n d y dx n

HIGHER DERIVATIVES Example 7 If f (4) (x). 3 f ( x) = x! x, find f (x) and In Example 6, we found that f (x) = 6x. The graph of the second derivative has equation y = 6x. So, it is a straight line with slope 6.

HIGHER DERIVATIVES Example 7 Since the derivative f (x) is the slope of f (x), we have f (x) = 6 for all values of x. So, f is a constant function and its graph is a horizontal line. Therefore, for all values of x, f (4) (x) = 0

HIGHER DERIVATIVES We can interpret the third derivative physically in the case where the function is the position function s = s(t) of an object that moves along a straight line. As s = (s ) = a, the third derivative of the position function is the derivative of the acceleration function. It is called the jerk. j da = = dt 3 d s dt 3

HIGHER DERIVATIVES Thus, the jerk j is the rate of change of acceleration. It is aptly named because a large jerk means a sudden change in acceleration, which causes an abrupt movement in a vehicle.

HIGHER DERIVATIVES We have seen that one application of second and third derivatives occurs in analyzing the motion of objects using acceleration and jerk.

HIGHER DERIVATIVES We will investigate another application of second derivatives in Section 4.3. There, we show how knowledge of f gives us information about the shape of the graph of f.

HIGHER DERIVATIVES In Chapter 11, we will see how second and higher derivatives enable us to represent functions as sums of infinite series.