Solve Quadratic Equations by Completing the Square

10.5 Solve Quadratic Equations by Completing the Square Before You solved quadratic equations by finding square roots. Now You will solve quadratic equations by completing the square. Why? So you can solve a problem about snowboarding, as in Ex. 50. Key Vocabulary completing the square perfect square trinomial, p. 601 For an expression of the form x 2 1 bx, you can add a constant c to the expression so that the expression x 2 1 bx 1 c is a perfect square trinomial. This process is called completing the square. KEY CONCEPT For Your Notebook Completing the Square Words To complete the square for the expression x 2 1 bx, add the square of half the coefficient of the term bx. Algebra x 2 1 bx 1 1 b } 2 2 2 5 1x 1 b } 2 2 2 E XAMPLE 1 Complete the square Find the value of c that makes the expression x 2 1 5x 1 c a perfect square trinomial. Then write the expression as the square of a binomial. STEP 1 Find the value of c. For the expression to be a perfect square trinomial, c needs to be the square of half the coefficient of bx. c 5 1 5 } 2 2 2 5 25 } 4 Find the square of half the coefficient of bx. STEP 2 Write the expression as a perfect square trinomial. Then write the expression as the square of a binomial. x 2 1 5x 1 c 5 x 2 1 5x 1 25 } 4 Substitute 25 } 4 for c. 5 1x 1 5 } 2 2 2 Square of a binomial GUIDED PRACTICE for Example 1 Find the value of c that makes the expression a perfect square trinomial. Then write the expression as the square of a binomial. 1. x 2 1 8x 1 c 2. x 2 2 12x 1 c 3. x 2 1 3x 1 c 10.5 Solve Quadratic Equations by Completing the Square 663

SOLVING EQUATIONS The method of completing the square can be used to solve any quadratic equation. To use completing the square to solve a quadratic equation, you must write the equation in the form x 2 1 bx 5 d. E XAMPLE 2 Solve a quadratic equation Solve x 2 2 16x 5215 by completing the square. x 2 2 16x 5215 Write original equation. AVOID ERRORS When completing the square to solve an equation, be sure you add the term 1 b } 2 2 2 to both sides of the equation. x 2 2 16x 1 (28) 2 5215 1 (28) 2 Add 1 216 } 2 2 2, or (28) 2, to each side. (x 2 8) 2 5215 1 (28) 2 Write left side as the square of a binomial. (x 2 8) 2 5 49 Simplify the right side. x 2 8 567 x 5 8 6 7 Take square roots of each side. Add 8 to each side. c The solutions of the equation are 8 1 7 5 15 and 8 2 7 5 1. CHECK You can check the solutions in the original equation. If x 5 15: If x 5 1: (15) 2 2 16(15) 0 215 (1) 2 2 16(1) 0 215 215 5215 215 5215 E XAMPLE 3 Solve a quadratic equation in standard form Solve 2x 2 1 20x 2 8 5 0 by completing the square. 2x 2 1 20x 2 8 5 0 2x 2 1 20x 5 8 Write original equation. Add 8 to each side. x 2 1 10x 5 4 Divide each side by 2. AVOID ERRORS Be sure that the coefficient of x 2 is 1 before you complete the square. x 2 1 10x 1 5 2 5 4 1 5 2 Add 1 10 } 2 2 2, or 5 2, to each side. (x 1 5) 2 5 29 Write left side as the square of a binomial. x 1 5 56Î } 29 x 525 6 Ï } 29 Take square roots of each side. Subtract 5 from each side. c The solutions are 25 1 Ï } 29 ø 0.39 and 25 2 Ï } 29 ø 210.39. GUIDED PRACTICE for Examples 2 and 3 Solve the equation by completing the square. Round your solutions to the nearest hundredth, if necessary. 4. x 2 2 2x 5 3 5. m 2 1 10m 528 6. 3g 2 2 24g 1 27 5 0 664 Chapter 10 Quadratic Equations and Functions

E XAMPLE 4 Solve a multi-step problem CRAFTS You decide to use chalkboard paint to create a chalkboard on a door. You want the chalkboard to have a uniform border as shown. You have enough chalkboard paint to cover 6 square feet. Find the width of the border to the nearest inch. STEP 1 Write a verbal model. Then write an equation. Let x be the width (in feet) of the border. Area of chalkboard (square feet) 5 Length of chalkboard (feet) p Width of chalkboard (feet) WRITE EQUATION The width of the border is subtracted twice because it is at the top and the bottom of the door, as well as at the left and the right. 6 5 (7 2 2x) p (3 2 2x) STEP 2 Solve the equation. 65 (7 2 2x)(3 2 2x) Write equation. 65 21 2 20x 1 4x 2 Multiply binomials. 215 5 4x 2 2 20x Subtract 21 from each side. 2 15 } 4 5 x 2 2 5x Divide each side by 4. 2 15 } 4 1 25 } 4 5 x 2 2 5x 1 25 } 4 Add 12 5 } 2 2 2, or 25 } 4, to each side. 2 15 } 4 1 25 } 4 5 1 x 2 5 } 2 2 2 Write right side as the square of a binomial. 5 } 2 5 1 x 2 5 } 2 2 2 Simplify left side. 6Î } 5 }2 5 x 2 5 } 2 Take square roots of each side. 5 } 2 6 Î } 5 }2 5 x Add 5 } 2 to each side. The solutions of the equation are 5 } 2 1 Î } 5 }2 ø 4.08 and 5 } 2 2 Î } 5 }2 ø 0.92. It is not possible for the width of the border to be 4.08 feet because the width of the door is 3 feet. So, the width of the border is 0.92 foot. Convert 0.92 foot to inches. 12 in. 0.92 ft p} 5 11.04 in. Multiply by conversion factor. 1 ft c The width of the border should be about 11 inches. GUIDED PRACTICE for Example 4 7. WHAT IF? In Example 4, suppose you have enough chalkboard paint to cover 4 square feet. Find the width of the border to the nearest inch. 10.5 Solve Quadratic Equations by Completing the Square 665

10.5 EXERCISES SKILL PRACTICE HOMEWORK KEY 5 WORKED-OUT SOLUTIONS on p. WS1 for Exs. 19 and 47 5 STANDARDIZED TEST PRACTICE Exs. 2, 24, 25, 42, and 49 5 MULTIPLE REPRESENTATIONS Ex. 47 1. VOCABULARY Copy and complete: The process of writing an expression of the form x 2 1 bx as a perfect square trinomial is called?. 2. WRITING Give an example of an expression that is a perfect square trinomial. Explain why the expression is a perfect square trinomial. EXAMPLE 1 on p. 663 for Exs. 3 11 COMPLETING THE SQUARE Find the value of c that makes the expression a perfect square trinomial. Then write the expression as the square of a binomial. 3. x 2 1 6x 1 c 4. x 2 1 12x 1 c 5. x 2 2 4x 1 c 6. x 2 2 8x 1 c 7. x 2 2 3x 1 c 8. x 2 1 5x 1 c 9. x 2 1 2.4x 1 c 10. x 2 2 1 } 2 x 1 c 11. x 2 2 4 } 3 x 1 c EXAMPLES 2 and 3 on p. 664 for Exs. 12 27 SOLVING EQUATIONS Solve the equation by completing the square. Round your solutions to the nearest hundredth, if necessary. 12. x 2 1 2x 5 3 13. x 2 1 10x 5 24 14. c 2 2 14c 5 15 15. n 2 2 6n 5 72 16. a 2 2 8a 1 15 5 0 17. y 2 1 4y 2 21 5 0 18. w 2 2 5w 5 11 } 4 19. z 2 1 11z 52 21 } 4 20. g 2 2 2 } 3 g 5 7 21. k 2 2 8k 2 7 5 0 22. v 2 2 7v 1 1 5 0 23. m 2 1 3m 1 5 } 4 5 0 24. MULTIPLE CHOICE What are the solutions of 4x 2 1 16x 5 9? A 2 1 } 2, 2 9 } 2 B 2 1 } 2, 9 } 2 C 1 } 2, 2 9 } 2 D 1 } 2, 9 } 2 25. MULTIPLE CHOICE What are the solutions of x 2 1 12x 1 10 5 0? A 26 6 Ï } 46 B 26 6 Ï } 26 C 66 Ï } 26 D 66 Ï } 46 ERROR ANALYSIS Describe and correct the error in solving the given equation. 26. x 2 2 14x 5 11 27. x 2 2 2x 2 4 5 0 x 2 2 14x 5 11 x 2 2 14x 1 49 5 11 (x 2 7) 2 5 11 x 2 7 56Ï } 11 x 5 7 6 Ï } 11 x 2 2 2x 2 4 5 0 x 2 2 2x 5 4 x 2 2 2x 1 1 5 4 1 1 (x 1 1) 2 5 5 x 1 1 56Ï } 5 x 5 1 6 Ï } 5 666 Chapter 10 Quadratic Equations and Functions

SOLVING EQUATIONS Solve the equation by completing the square. Round your solutions to the nearest hundredth, if necessary. 28. 2x 2 2 8x 2 14 5 0 29. 2x 2 1 24x 1 10 5 0 30. 3x 2 2 48x 1 39 5 0 31. 4y 2 1 4y 2 7 5 0 32. 9n 2 1 36n 1 11 5 0 33. 3w 2 2 18w 2 20 5 0 34. 3p 2 2 30p 2 11 5 6p 35. 3a 2 2 12a 1 3 52a 2 2 4 36. 15c 2 2 51c 2 30 5 9c 1 15 37. 7m 2 1 24m 2 2 5 m 2 2 9 38. g 2 1 2g 1 0.4 5 0.9g 2 1 g 39. 11z 2 2 10z 2 3 529z 2 1 3 } 4 GEOMETRY Find the value of x. Round your answer to the nearest hundredth, if necessary. 40. Area of triangle 5 108 m 2 41. Area of rectangle 5 288 in. 2 x m 3x in. (x 1 6) m (2x 1 10) in. 42. WRITING How many solutions does x 2 1 bx 5 c have if c < 21 b } 2 2 2? Explain. 43. CHALLENGE The product of two consecutive negative integers is 210. Find the integers. 44. CHALLENGE The product of two consecutive positive even integers is 288. Find the integers. PROBLEM SOLVING EXAMPLE 4 on p. 665 for Exs. 45 46 45. LANDSCAPING You are building a rectangular brick patio surrounded by crushed stone in a rectangular courtyard as shown. The crushed stone border has a uniform width x (in feet). You have enough money in your budget to purchase patio bricks to cover 140 square feet. Solve the equation 140 5 (20 2 2x)(16 2 2x) to find the width of the border. 46. TRAFFIC ENGINEERING The distance d (in feet) that it takes a car to come to a complete stop on dry asphalt can be modeled by d 5 0.05s 2 1 1.1s where s is the speed of the car (in miles per hour). A car has 78 feet to come to a complete stop. Find the maximum speed at which the car can travel. 47. MULTIPLE REPRESENTATIONS For the period 198522001, the average salary y (in thousands of dollars) per season of a Major League Baseball player can be modeled by y 5 7x 2 2 4x 1 392 where x is the number of years since 1985. a. Solving an Equation Write and solve an equation to find the year when the average salary was $1,904,000. b. Drawing a Graph Use a graph to check your solution to part (a). 10.5 Solve Quadratic Equations by Completing the Square 667

48. MULTI-STEP PROBLEM You have 80 feet of fencing to make a rectangular horse pasture that covers 750 square feet. A barn will be used as one side of the pasture as shown. a. Write equations for the perimeter and area of the pasture. b. Use substitution to solve the system of equations from part (a). What are the possible dimensions of the pasture? 49. SHORT RESPONSE You purchase stock for $16 per share, and you sell the stock 30 days later for $23.50 per share. The price y (in dollars) of a share during the 30 day period can be modeled by y 520.025x 2 1 x 1 16 where x is the number of days after the stock is purchased. Could you have sold the stock earlier for $23.50 per share? Explain. 50. SNOWBOARDING During a big air competition, snowboarders launch themselves from a half pipe, perform tricks in the air, and land back in the half pipe. a. Model Use the vertical motion model to write an equation that models the height h (in feet) of a snowboarder as a function of the time t (in seconds) she is in the air. b. Apply How long is the snowboarder in the air if she lands 13.2 feet above the base of the half pipe? Round your answer to the nearest tenth of a second. 16.4 ft Initial vertical velocity = 24 ft/sec Cross section of a half pipe at classzone.com 51. CHALLENGE You are knitting a rectangular scarf. The pattern you have created will result in a scarf that has a length of 60 inches and a width of 4 inches. However, you happen to have enough yarn to cover an area of 480 square inches. You decide to increase the dimensions of the scarf so that all of your yarn will be used. If the increase in the length is 10 times the increase in the width, what will the dimensions of the scarf be? MIXED REVIEW PREVIEW Prepare for Lesson 10.6 in Exs. 52 57. Evaluate the expression for the given value of x. (p. 74) 52. 3 1 x 2 6; x 5 8 53. 11 2 (2x) 1 15; x 521 54. 2x 1 18 2 20; x 5210 55. 32 2 x 2 5; x 5 5 56. x 1 14.7 2 16.2; x 5 2.3 57. 29.2 2 (211.4) 2 x; x 524.5 Solve the proportion. (p. 168) 58. 8 } m 2 3 5 4 } 3 59. Solve the equation. 3 } a 5 5 } a 1 5 60. c 1 2 } 5 2c } 2 3 6 5 61. (x 2 4)(x 1 9) 5 0 (p. 575) 62. x 2 2 15x 1 26 5 0 (p. 583) 63. 3x 2 1 10x 1 7 5 0 (p. 593) 64. 4x 2 2 20x 1 25 5 0 (p. 600) 668 EXTRA PRACTICE for Lesson 10.5, p. 947 ONLINE QUIZ at classzone.com

Extension Use after Lesson 10.5 Graph Quadratic Functions in Vertex Form GOAL Graph quadratic functions in vertex form. Key Vocabulary vertex form In Lesson 10.2, you graphed quadratic functions in standard form. Quadratic functions can also be written in vertex form, y 5 a(x 2 h) 2 1 k where a Þ 0. In this form, the vertex of the graph can be easily determined. KEY CONCEPT For Your Notebook Graph of Vertex Form y 5 a(x 2 h) 2 1 k The graph of y 5 a(x 2 h) 2 1 k is the graph of y 5 ax 2 translated h units horizontally and k units vertically. Characteristics of the graph of y 5 a(x 2 h) 2 1 k: y y 5 a(x 2 h) 2 1 k The vertex is (h, k). The axis of symmetry is x 5 h. y 5 ax 2 k (h, k) The graph opens up if a > 0, and the graph opens down if a < 0. (0, 0) h x E XAMPLE 1 Graph a quadratic function in vertex form Graph y 52(x 1 2) 2 1 3. STEP 1 Identify the values of a, h, and k: a 521, h 522, and k 5 3. Because a < 0, the parabola opens down. STEP 2 Draw the axis of symmetry, x 522. y STEP 3 Plot the vertex (h, k) 5 (22, 3). (22, 3) 3 STEP 4 Plot four points. Evaluate the function for two x-values less than the x-coordinate of the vertex. 1 x x 5 23: y 52(23 1 2) 2 1 3 5 2 x 5 25: y 52(25 1 2) 2 1 3 526 x 522 Plot the points (23, 2) and (25, 26) and their reflections, (21, 2) and (1, 26), in the axis of symmetry. STEP 5 Draw a parabola through the plotted points. Extension: Graph Quadratic Functions in Vertex Form 669

E XAMPLE 2 Graph a quadratic function Graph y = x 2 2 8x 1 11. STEP 1 Write the function in vertex form by completing the square. y5 x 2 2 8x 1 11 Write original function. y1 5 (x 2 2 8x 1 ) 1 11 Prepare to complete the square. y1 16 5 (x 2 2 8x 1 16) 1 11 Add 1 28 } 2 2 2 5 (24) 2 5 16 to each side. y 1 16 5 (x 2 4) 2 1 11 y5 (x 2 4) 2 2 5 Write x 2 2 8x 1 16 as a square of a binomial. Subtract 16 from each side. STEP 2 Identify the values of a, h, and k: a 5 1, h 5 4, and k 525. Because a > 0, the parabola opens up. STEP 3 Draw the axis of symmetry, x 5 4. y STEP 4 Plot the vertex (h, k) 5 (4, 25). STEP 5 Plot four more points. Evaluate the function for two x-values less than the x-coordinate of the vertex. 1 1 x 5 4 x x 5 3: y 5 (3 2 4) 2 2 5 524 x 5 1: y 5 (1 2 4) 2 2 5 5 4 Plot the points (3, 24) and (1, 4) and their reflections, (5, 24) and (7, 4), in the axis of symmetry. (4, 25) STEP 6 Draw a parabola through the plotted points. PRACTICE EXAMPLE 1 on p. 669 for Exs. 1 6 EXAMPLE 2 on p. 670 for Exs. 7 12 Graph the quadratic function. Label the vertex and axis of symmetry. 1. y 5 (x 1 2) 2 2 5 2. y 52(x 2 4) 2 1 1 3. y 5 x 2 1 3 4. y 5 3(x 2 1) 2 2 2 5. y 522(x 1 5) 2 2 2 6. y 52 1 } 2 (x 1 4) 2 1 4 Write the function in vertex form, then graph the function. Label the vertex and axis of symmetry. 7. y 5 x 2 2 12x 1 36 8. y 5 x 2 1 8x 1 15 9. y 52x 2 1 10x 2 21 10. y 5 2x 2 2 12x 1 19 11. y 523x 2 2 6x 2 1 12. y 52 1 } 2 x 2 2 6x 2 21 13. Write an equation in vertex form of the parabola shown. Use the coordinates of the vertex and the coordinates of a point on the graph to write the equation. (210, 5) (22, 5) y (26, 1) 21 1 x 670 Chapter 10 Quadratic Equations and Functions