Essential Rules of Thumb

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Essential Rules of Thumb copy available for download from bethesignal.com (PPT-311) Be sure to check out Eric s Rules of Thumb column on EDN.com Dr. Eric Bogatin Signal Integrity Evangelist Teledyne LeCroy www.bethesignal.com Jan 2014 Outline What s a rule of thumb and why do we care Ten incredibly useful rules of thumb Examples Slide 2

t VtPulse SRC3 Vlow=0 V Delay=0 nsec Vhigh=1 V Rise=(2.25*RT) nsec Edge=erf Fall=(2.25*RT) nsec Width=100 nsec Period=100 nsec R R16 R=50 Ohm R R40 R=50 Ohm TLIN TL49 SMA launch Z=Z_SMA Ohm E=360 F=(1/TD_SMA) GHz TLIN TL50 Z=Z_SMA Ohm F=(1/TD_SMA) GHz E=360 TLIN TL48 Z=Z_launch Ohm E=360 F=(1/TD_launch) GHz TLIN TL47 Z=Z_launch Ohm F=(1/TD_launch) GHz E=360 Daughter Card C C4 Ko=Dk1_DC_1 Ae=0 Ao=0 ML2CTL_V CLin10 Subst="Subst1" Daughter Card via Length=Len_DC_1 in W[1]=W1_DC_1 mil W[2]=W2_DC_1 mil S[1]=S_DC_1 mil Layer[2]=2 Layer[1]=2 C=C_DCvia pf ReuseRLGC=no RLGC_File= CLINP TL45 C Ze=(Z11_DCvia+Z12_DCvia) C5 Ohm Zo=(Z11_DCvia-Z12_DCvia) C=C_DCvia pf Ohm Ke=Dk1_DC_1 L=Len_DCvia mil ML2CTL_V CLin9 C Subst="Subst2" C7 Length=Len_CON_1 C=C_BPvia in pf S[1]=S_CON_1 mil W[1]=W1_CON_1 mil Layer[1]=2 W[2]=W2_CON_1 mil Layer[2]=2 RLGC_File= ReuseRLGC=no Connector Backplan Five Critically Important Processes for EVERY Engineer Measure (validate- anchor to reality, characterize) Model (turn physical system into mathematical approximation) Understand Essential Principles just say know Simulate (use virtual prototype to explore design space: rules of thumb, approximations, numerical simulations) 0 Analyze (is it reasonable?, extract useful information make decisions) Differential Response, db -10-20 -30-40 0 1 2 3 4 5 6 7 8 9 10 freq, GHz Rules of Thumb: sometimes an ok answer NOW! is better than a good answer late Numerical simulation: field solver, circuit simulations, Approximations: Analytic approximations, useful for quick estimates and early design tradeoffs Accuracy Rules of thumb v= 6in nsec L= 8 nh in BW = 5 x F clock L self 2d 1 = 5d in + nh w t + 2 Rule of thumb is: better than a guess easier to remember than an equation a lot quicker than a simulation Effort: Slide 4

Bogatin s 10 Rules: (PCD&F Magazine, Aug 10, 2010 or www.bethesignal.com, BTS218)) 1. Answer it depends questions by putting in the numbers 2. Separate myth from reality by putting in the numbers 3. Watch out for the whack-a-mole effect 4. Most important step in solving a problem: find the root cause 5. Apply the Youngman Principle to optimize designs 6. Sometimes an OK answer now! is better than a good answer late 7. Evaluate bang for the buck with virtual prototypes 8. Watch out for mink holes 9. Never perform a measurement or simulation without first anticipating ting what you expect to see 10.There are two kinds of designers: those who have signal integrity problems and those who will Slide 5 Rule #9: Never do a measurement or simulation without first anticipating what you expect to see. If you are wrong, there is a reason- either the set up is wrong or your intuition is wrong. Either way, by exploring the difference, you will learn something If you are right, you get a nice warm feeling that you understand what is going on. Corollary to rule #9: Corollary to rule #9: There are so many ways of screwing up a measurement or simulation, you can never do too many consistency checks

Typical questions to answer with a rule of thumb What is the bandwidth of a signal with a rise time of 0.3 nsec, typical of DDR3? The fab vendor comes back with a line width of 8 mils and dielectric thickness of 8 mils for a 50 Ohm microstrip. Is this reasonable? How much total inductance is in a connector 0.25 inches long? Is this too much for 4 signals lines with 0.3 nsec rise time? How much radiated emissions is expected from 10 ua of common current in a 1 m long cable, in a class B test? Slide 7 Most Important Principle of Applying a Rule of Thumb if all you have is a hammer, everything looks like a nail Slide 8

Cautions when using Rules of Thumb Always start every problem with a rule of thumb Never sign off on a design based on a rule of thumb They help calibrate your engineering intuition: help establish what is reasonable? Not designed to be accurate- designed to be easy to use, easy to remember Usually have their origin in a specific situation: try to be aware of the assumptions If you are concerned about the difference between 50 Ohms and 60 Ohms, don t use a rule of thumb! If you have to use a calculator, do not use a rule of thumb If you want confidence in the answer, don t use a rule of thumb! If you ask too many questions, don t use a rule of thumb! Slide 9 Summary of 10 Rules of Thumb 1. Speed of a signal on a transmission line: v ~ 6 inches/nsec 2. Bandwidth of a signal is related to the rise time of the signal: BW = 0.35/RT 3. If all you know is the clock frequency signal: BW = 5 x F clock 4. Aspect ratio for 50 Ohm Transmission line in FR4: microstrip: w/h = 2, stripline: w/h = 1 5. L and C in a 50 Ohm FR4 transmission line: L perlen ~ 8 nh/inch, C perlen ~ 3.3 pf/in 6. total inductance in a return path: L perlen ~ 10 nh/inch 7. % ground bounce noise = 2% per signal per nh/rt[nsec] 8. skin depth in copper is 2 u @ 1 GHz 9. Attenuation FOM : lossy: 0.2 db/in/ghz, low loss: 0.1 db/inch/ghz 10. 3 m far field E ~ 0.4 uv/m/ua/mhz Slide 10

Rule of Thumb #1: speed of a signal on a transmission line: v ~ 6 inches/nsec V in V Signal path Return path GROUND V in 12 v = Dk inches nsec = 12 12 4 = 2 = = inches inches nsec n sec inches cm 6 15 nsec nsec Slide 11 Examples: v ~ 6 inches/nsec What is the time delay for a 3 foot cable? For how long will a driver see a 50 Ohm load, when the transmission line it is connected to is 6 inches long? Slide 12

. Rule of Thumb #2: Bandwidth of a signal is related to the rise time of the signal: BW = 0.35/RT Bandwidth: the highest sine wave frequency that is significant The edge of a re-created square wave built from a limited number of harmonics (known bandwidth) 100 0.35 BW[GHz] = RT[nsec] Bandwidth (GHz) 10 1 0.1 0.01 0.01 0.1 1 10% to 90% Rise Time (nsec) 10 Slide 13 Example 0.35 BW[GHz] = RT[nsec] and 0.35 RT[n sec] = BW[GHz] What is the bandwidth of a signal with a rise time of 1 nsec? A scope has a bandwidth of 30 GHz. What is the shortest rise time it can record? Slide 14

Rule of Thumb #3: If all you know is the clock frequency signal: BW = 5 x F clock What is the BW for these signals, each with exactly the same F clock? RT[nsec] =? x Period[nsec] Assumption: RT[nsec] = 7% x Period[nsec] 0.35 0.35 BW = 5 x F RT = 0.07 x Period = clock Slide 15 Examples BW = 5 x F clock What is the bandwidth of a 600 MHz clock? What is the bandwidth (@ the TX) of a 5 Gbps PCIe II signal? Slide 16

Rule of Thumb #4: Aspect ratio for a 50 Ohm Transmission line in FR4: microstrip: Line width/dielectric thickness = 2 stripline: Line width/dielectric thickness = 1 w w = 2 x h h microstrip b = 2 x h h = w b w h h stripline Slide 17 Examples Aspect ratio for a 50 Ohm Transmission line in FR4: microstrip: w/h = 2, stripline: w/h = 1 In microstrip in FR4, what dielectric thickness gives 50 Ohms for a line width of 5 mils? In stripline in FR4, what dielectric thickness gives 50 Ohms for a line width of 7 mils? Slide 18

Rule of Thumb #5: L and C in a 50 Ohm FR4 transmission line L perlen ~ 8 nh/inch C perlen ~ 3.3 pf/in Len, TD Z L TD= L C total 0 = total total Ctotal Len TD= c Dk C total TD = Z 0 Len Dk Len pf C c total = = = 3.3 in x Len Z 6 x 50Ω 0 in nsec L = TD x Z total 0 Len Len L = Dk x Z = x 50Ω= 8 x Len total 0 c 6 in n sec nh in Slide 19 Examples L and C in a 50 Ohm FR4 transmission line L perlen ~ 8 nh/inch C perlen ~ 3.3 pf/in How much capacitance is there in a package lead about 0.25 inches long? How much loop inductance is there in a surface trace from a capacitor to a via that is 0.2 inches long? Slide 20

Rule of Thumb #6: total inductance in a return path: L perlen ~ 10 nh/inch w s Total inductance of return path Signal path Return path Total Inductance per length, nh/inch 20 18 16 14 12 10 8 6 4 2 0 5 10 15 20 25 30 35 40 45 50 Trace Width, mils s = 40 mils s = 30 mils s = 20 mils s = 10 mils For w = s L total ~ 10 nh/inch x Len Slide 21 Examples total inductance in a return path: L perlen ~ 10 nh/inch How much total inductance is in a connector that is 0.5 inches long? How much total inductance is there in a via that is 0.064 inches long? Slide 22

Rule of Thumb #7: % ground bounce noise = 2% per signal per nh/rt[nsec] di/dt Voltage di V= L dt When the L is the return path, V is ground bounce V gndbnc = L return di dt di V V V = L = L = L n signal signal gndbnc return return return dt Z0RT Z0RT V di= Z signal 0 dt= RT V V L n L %noise = = L n = n = 2% V Z RT 50 RT RT gndbnc signal return return return signal 0 Ω %noise = 2% per signal per nh/rt[nsec] Slide 23 Examples %noise = 2% per signal per nh/rt[nsec] A package lead has a total inductance in the return path of 5 nh. 3 signals share the return path. If the rise time is 1 nsec, how much ground bounce noise is expected? A connector lead is 0.25 inches long. How much ground bounce will there be if 5 signals share it with a rise time of 0.5 nsec? Slide 24

Rule of Thumb #8: skin depth in copper is 2 u @ 1 GHz Skin depth, δ = 1 πσµ 0 µ r f = 2µ 1 f[ghz] For copper: d = 2µ @ 1 GHz d = 20µ @ 10 MHz signal line dielectric gnd plane Slide 25 Examples skin depth in copper is 2 u @ 1 GHz Above what frequency is the current frequency dependent in ½ oz copper, t = 17u? Surface roughness of VLP (very low profile) copper is about 2 u rms. Above what freq is most of the current seeing the surface roughness and increasing the resistance over smooth copper? Slide 26

Rule of Thumb #9: Attenuation FOM : lossy: 0.2 db/in/ghz, low loss: 0.1 db/inch/ghz d 1 atten [ db/in ] ~ f[ GHz ] + 2.3x f[ GHz ] xdf x Dk w mils [ ] FR4 Example: @ 4 GHz, (8 Gbps) w = 5 mil, Dk = 4.3, Df = 0.02 1 atten[ db / in ] ~ 4+ 2.3 x 4 x 0.02 x 4.3 = 5 Figure of Merit (FOM) ~ 0.22 db/in/ghz 0.4dB / in+ 0.5dB / in= 0.9dB / in Megtron6 Example: @ 4 GHz, (8 Gbps) w = 5 mil, Dk = 3.7, Df = 0.002 1 atten[ db / in ] ~ 4+ 2.3 x 4 x 0.002 x 3.7 = 5 Figure of Merit (FOM) ~ 0.1 db/in/ghz 0.4dB / in+ 0.035dB / in= 0.43dB / in Very expensive material wasted by conductor loss Slide 27 Examples Attenuation FOM : lossy: 0.2 db/in/ghz, low loss: 0.1 db/inch/ghz How much attenuation is expected at the Nyquist in a 20 inch FR4 channel for PCIe III? Is this a lot or a little? How much attenuation is expected at the Nyquist for a 20 Gbps channel in Megtron6 that is 40 inches long? Is this a lot or a little? Slide 28

Rule of Thumb #10: 3 m far field is E ~ 0.4 uv/m/ua/mhz Len ~ (conductive plate) I R Max E 7 f[hz] x I[A] x Len E[V / m] = 4π x 10 R For specific case: Len = 1 m, R = 3 m (Class B) E[uV / m / ua / MHz] = 0.4 Noisy plane Cable shield FCC part 15, class B limits 30 MHz 88 MHz ~ 100 uv/m ~1pF, Z ~ 1k @ 100 MHz chassis V 0.1v comm I comm = ~ = 100uA Zcomm 1kΩ E[uV / m] = 0.4[u V / m / ua / MHz] x 100uA x 100MHz = 4,000uV / m!!!! Slide 29 Examples E ~ 0.4 uv/m/ua/mhz What is the 3 m electric field strength for 10 ua of common current in 1 m of peripheral cable at 10 MHz? is this good or bad? How much common current at ~ 100 MHz in a 1 m cable will fail FCC part 15 class B? (100 uv/m will fail) Slide 30

Summary of the 10 Rules of Thumb 1. Speed of a signal on a transmission line: v ~ 6 inches/nsec 2. Bandwidth of a signal is related to the rise time of the signal: BW = 0.35/RT 3. If all you know is the clock frequency signal: BW = 5 x F clock 4. Aspect ratio for 50 Ohm Transmission line in FR4: microstrip: w/h = 2, stripline: w/h = 1 5. L and C in a 50 Ohm FR4 transmission line: L perlen ~ 8 nh/inch, C perlen ~ 3.3 pf/in 6. total inductance in a return path: L perlen ~ 10 nh/inch 7. % ground bounce noise = 2% per signal per nh/rt[nsec] 8. skin depth in copper is 2 u @ 1 GHz 9. Attenuation FOM : lossy: 0.2 db/in/ghz, low loss: 0.1 db/inch/ghz 10. 3 m far field E ~ 0.4 uv/m/ua/mhz Use them wisely Slide 31