6.1. The Exponential Function. Introduction. Prerequisites. Learning Outcomes. Learning Style



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The Exponential Function 6.1 Introduction In this block we revisit the use of exponents. We consider how the expression a x is defined when a is a positive number and x is irrational. Previously we have only considered examples in which x is a rational number. We consider these exponential functions f(x) =a x in more depth and in particular consider the special case when the base a is the so-called exponential constant: e =2.7182818... We then examine the behaviour of e x as x, called exponential growth and of e x as x called exponential decay. Prerequisites Before starting this Block you should... Learning Outcomes After completing this Block you should be able to... approximate a x when x is irrational assess the behaviour of a x : in particular the exponential function e x understand the terms exponential growth and exponential decay 1 have a good knowledge of indices and their laws 2 have knowledge of rational and irrational numbers 3 know how to take limits Learning Style To achieve what is expected of you... allocate sufficient study time briefly revise the prerequisite material attempt every guided exercise and most of the other exercises

1. Exponents revisited We have seen in Chapter 1 (Block 2) the meaning to be assigned to the expression a p where a is a positive number. We remind the reader that a is called the base and p is called the exponent. There are various cases to consider: If m, n are positive integers a n = a a a with n factors a 1/n means the n th root of a. That is, a 1/n is that positive number which satisfies (a 1/n ) (a 1/n ) (a 1/n )=a where there are n factors on the left hand side. a m/n =(a 1/n ) (a 1/n ) (a 1/n ) where there are m factors. a n = 1 a n For convenience we again list the basic laws of exponents: a m a n = a m+n Key Point a m a n = am n (a m ) n = a mn a 1 = a, and if a 0 a 0 =1 Try each part of this exercise Simplify the expressions (a) bm n b 3 (b) (5am ) 2 a 2 b 2m (a 3 ) 2 Part (a) (i) First simplify the numerator b m n b 3 = Answer Part (a) (ii) Now include the denominator b m n b 3 b 2m = bm+3 n = Answer b2m Part (b)(i) Again simplify the numerator (5a m ) 2 a 2 = Answer Part (b) (ii) Now include the denominator (5a m ) 2 a 2 (a 3 ) 2 = 25a2m+2 a 6 = Answer Engineering Mathematics: Open Learning Unit Level 1 2

What is a x if x is a real number? So far we have given the meaning of a p where p is, at worst, a rational number, that is, one which can be written as a quotient of integers. So, if p is rational, then p = m n where m, n are integers Now consider x as a real number which cannot be written as a rational number. Two common examples of these irrational numbers are x = 2 and x = π. What we shall do is approximate x by a rational by working to a fixed number of decimal places. For example if x = 3.914712334317... then, if we are working to 3 d.p. we would write x 3.915 and this number can certainly be expressed as a rational number: so, in this case x 3.915 = 3915 1000 a x = a 3.914712... a 3.915 = a 3915 1000 and the final term: a 3915 1000 can be determined in the usual way by using your calculator. From henceforth we shall therefore assume that the expression a x is defined for all positive values of a and for all values of x. Try each part of this exercise By working to 3 d.p. find, using your calculator, the value of 3 π/2. Part (a) First, approximate the value of π 2 Answer Part (b) Now determine 3 π/2 Answer 3 Engineering Mathematics: Open Learning Unit Level 1

2. Exponential Functions For a fixed value of the base a the expression a x clearly varies with the value of x: it is a function of x. We draw, in the diagram below, the graphs of (0.5) x, (0.3) x, 1 x, 2 x and 3 x. (0.5) x (0.3) x y 3x 2 x 1 x The functions a x (as different values are chosen for a) are called exponential functions. From the graphs we see (and these are true for all exponential functions): If a>b>0 then a x >b x if x>0 and a x <b x if x<0 The most important and widely used exponential function has the particular base 2.7182818..., a number always denoted by the single letter e: e =2.7182818... It will not be clear to the reader why this particular value is so important. However, its importance will become clear as your knowledge of mathematics increases. The number e is as important as the number π and, like π, is also irrational. That is, e cannot be written as the quotient of two integers. The value of e is stored in most calculators. There are numerous ways of calculating the value of e. For example, it can be shown that the value of e is the end-point of the sequence of numbers: x ( ) 1 2, 1 ( ) 2 3, 2 ( ) 3 4,..., 3 ( ) 16 17,..., 16 ( ) 64 65,... 64 which, in decimal form (each to 6 d.p.) are 2.000000, 2.250000, 2.370370,..., 2.637929,...,2.697345,... This is a slowly converging sequence. However, it does lead to a precise definition for the value of e: ( ) n n +1 e = lim n n Engineering Mathematics: Open Learning Unit Level 1 4

An alternative way of calculating e is to use the (infinite) series: where, we remember, e =1+ 1 1! + 1 2! + 1 3! + 1 4! + + 1 n! +... n! =n (n 1) (n 2)...(3) (2) (1) It can be shown that the first eleven terms of this series provide a value of e with an error of less than 3 10 8. (The reader is encouraged to carry out this calculation). Although all functions of the form a x are called exponential functions we usually refer to e x as the exponential function. Key Point e x is the exponential function y e x 1 The exponential function (and its variants) appear in various areas of mathematics and engineering. For example, the shape of a hanging chain or rope, under the effect of gravity, is well described by a combination of the exponential curves e kx, e kx. The function e x2 plays a major role in statistics; it being fundamental in the important Normal distribution which describes the variability in many naturally occurring phenomena. The exponential function e kx appears directly, again in the area of statistics, in the Poisson distribution which (amongst other things) is used to predict the number of events (which occur randomly) in a given time interval. From now on, when we refer to an exponential function, it will be to the function e x that we will refer. x Now do this exercise Use a calculator to determine the values (to 2 d.p.) (a) e 1.5, (b) e 2, (c) e 17. Answer Now do this exercise Simplify the expression e2.7 e 3(1.2) e 2 and determine its numerical value to 3 d.p. Answer 5 Engineering Mathematics: Open Learning Unit Level 1

3. Exponential growth If a>1 then it can be shown that, no matter how large K is: a x as x xk That is, if K is fixed (though chosen as large as desired) then eventually, as x increases, a x will overtake (and remain ahead of) the value x K as long as a>1. The growth of a x as x increases is called exponential growth, though it is common practice to refer to the growth of the particular function e x as exponential growth. Try each part of this exercise A function f(x) grows exponentially and is such that f(0) = 1 and f(2) = 4. Find the exponential curve that fits through these points. Part (a) First: assume the function is f(x) =e kx where k is to be determined from the given information. Clearly, f(0) = 1 (irrespective of the value of k). Now find the value of k. Part (b) By trying values of k: say0.6, 0.7, 0.8,... find the value such that e 2k =4. Part (c) Now try values of k closer to 0.7. Try k =0.67, 0.68, 0.69,... Answer Answer Part (d) Finally try values closer to 0.69; say k =0.691, 0.692,... Answer We conclude that the exponential function we seek is e 0.693x. We shall see, in Block 4, that a more efficient way of finding the value of k can be used. Engineering Mathematics: Open Learning Unit Level 1 6

4. Exponential decay As we have noted, the behaviour of e x as x is called exponential growth. In a similar manner we characterise the behaviour of the function e x as x as exponential decay. The graphs of e x and e x are shown in the following diagram. e x y e x 1 In fact e x tends to zero so quickly as x that, no matter how large the fixed number K is, x K e x 0 as x Now do this exercise Choose K = 10 in the expression x K e x and calculate x K e x using your calculator for x =5, 10, 15, 20, 25, 30, 35. Answer More exercises for you to try 1. Find, to 3 d.p., the values of (a) 2 8 (b) (5.1) 4 (c) (2/10) 3 (d) (0.111) 6 (e) 2 1/2 (f) π π (g) e π/4 (h) (1.71) 1.71 x 2. Plot y = x 3 and y = e x for 0 <x<7. For which integer values of x is e x >x 5? Answer 7 Engineering Mathematics: Open Learning Unit Level 1

5. Computer Exercise or Activity For this exercise it will be necessary for you to access the computer package DERIVE. Derive is capable of analysing and of displaying exponential functions. For example, to graph the function 3 x simply key in Author:Expression 3 x. DERIVE responds 3 x Then go into the graphics screen and hit the Plot! button to obtain the required graph. If the exponential function is required (that is, with base e =2.7182818...) then the special symbol ê must be used. This symbol is available from the menu on the Author Expression box. You can also use DERIVE to check the limit: lim n ( n +1 We would key in ((n +1)/(n)) n. DERIVE responds with ( ) n n +1 n then hit Calculus:Limit to obtain the Calculus limit screen. In the limit Point box choose (from the list of symbols) and then choose Both in the Approach From section. If you then hit the OK button DERIVE responds with ( ) n n +1 lim n n Finally, hit Simplify:Basic to obtain the response ê which is as expected. The reader could experiment with DERIVE and obtain the limits of: ( ) n ( ) n ( n 1 n +5 n + x lim lim and lim n n n n n n n ) n ) n Engineering Mathematics: Open Learning Unit Level 1 8

End of Block 6.1 9 Engineering Mathematics: Open Learning Unit Level 1

b m n b 3 = b m+3 n Engineering Mathematics: Open Learning Unit Level 1 10

b m+3 n b 2m = bm+3 n 2m = b 3 m n 11 Engineering Mathematics: Open Learning Unit Level 1

(5a m ) 2 a 2 =25a 2m a 2 =25a 2m+2 Engineering Mathematics: Open Learning Unit Level 1 12

(5a m ) 2 a 2 = 25a2m+2 (a 3 ) 2 a 6 =25a 2m+2 6 =25a 2m 4 13 Engineering Mathematics: Open Learning Unit Level 1

π 2 3.1415927... 2 = 1.5707963 1.571 Engineering Mathematics: Open Learning Unit Level 1 14

3 π/2 3 1.571 =5.618 to 3 d.p. 15 Engineering Mathematics: Open Learning Unit Level 1

e 1.5 =4.48, e 2 =0.14, e 17 =2.4 10 7 Engineering Mathematics: Open Learning Unit Level 1 16

e 2.7 e 3(1.2) = e 2.7 e 3.6 e 2 = e 2.7 3.6 2 = e 2.9 =0.055 e 2 17 Engineering Mathematics: Open Learning Unit Level 1

e 2(0.6) =3.32 (too low) e 2(0.7) =4.055 (too high) Engineering Mathematics: Open Learning Unit Level 1 18

e 2(0.67) =3.819 (low) e 2(0.68) =3.896 (low) e 2(0.69) =3.975 (low) 19 Engineering Mathematics: Open Learning Unit Level 1

e 2(0.691) =3.983, (low) e 2(0.692) =3.991 (low) e 2(0.693) =3.999 (low) Engineering Mathematics: Open Learning Unit Level 1 20

x 5 10 15 20 25 30 35 x 10 e x 6.5 10 4 4.5 10 5 1.7 10 5 2.1 10 4 1324 55 1.7 21 Engineering Mathematics: Open Learning Unit Level 1

1. (a) 0.004 (b) 676.520 (c) 125 (d) 0.0 (e) 1.414 (f) 36.462 (g) 2.193 (h) 0.400 2. For integer values of x, e x >x 5 if x 5 Engineering Mathematics: Open Learning Unit Level 1 22