Group Velocity. Lecture 6. Group Velocity, Poynting and Polarisation. Representation. Propagation of Pulses

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Lecture 6 Group Velocity, Poynting and Polarisation Group Velocity Phase velocity is the rate of advance of constant phase surfaces. Phase velocity can exceed velocity of light in vacuum, c. BUT phase velocity really only applies to infinite (time and space) monochromatic (sine) waves These do not exist - or if they do, are boring!! Propagation of Pulses Representation Consider a gaussian pulse in time of width t - ie a sine wave multiplied by a gaussian By Fourier transforms we can show that this can be resolved into a superposition of sine waves, width 2/t In frequency space this is a delta function convolved with a Gaussian Time Space Frequency Space Any superposition of sine waves can be represented as E(t,z) = Int[ E 0 (7) exp i(k(7) z - 7t ), d7] If the integrand is non-zero about a range of frequencies around 7 0 only Change variable to 7 = 7-7 0 k(7) = k(7 0 ) + dk/d7 70 7 (Taylor expansion) E(t,z) = exp i(k(7 0 ) z - 7 0 t ) Int[ E 0 (7) exp -i7 (t - dk/d7 70 z) d7] First term is a carrier wave, propagating at the phase speed Second term is the modulation (information) traveling at the group velocity d7/dk 70 d7/dk = c / n(7) / ( 1 + (7/n) dn/d7 ) The group velocity should be smaller than the speed of light...

Group Velocity in Plasmas n 2 = 1-7 2 p / 7 2 If we assume that 7 p < 7, then n is real and < 1 The phase velocity is c/n which is > c It is left as an exercise for the reader to show that... The group velocity is cn which is < c This is not a general formula - it only applies to plasmas The group velocity is the velocity at which information can propagate There is no information in a monochromatic plane wave MEs in Linear, Isotropic Medium Div[ E ] = '/ Div[ H ] = 0 Curl[ E ] = - 0/0t ( µ H ) Curl[ H ] = 0/0t ( E ) + J = 0 ( 1 + 3 e ) µ = µ 0 ( 1 + 3 m ) Notice that J has not been replaced with the conductivity Poynting Vectors Start with Div[E x H] = H. Curl[E] - E. Curl[H] (general vector relationship) Div[E x H] = - H. 0/0t ( µ H ) - E. 0/0t ( E ) - E. J Div[S] + 0/0t ( ½ µ H 2 + ½ E 2 ) + E. J = 0 Where S = E x H The last term is a Joule heating term The second term is the rate of change of energy in the magnetic and electrostatic fields The first term can be interpreted as the energy flow with the Poynting vector pointing in the direction of energy flow Since S = E x H these form a right-handed set as expected from plane wave consideration Poynting and Plane Waves S = E x H Let s take time averages <S> = < Re(E) x Re(H)> = ½ Re ( E x H* ) But H* = (/µ) k x E* So <S> = ½ (/µ) E 0 2 k The Poynting vector points in the direction of energy flow - the DOP in this case The magnitude is proportional to E 0 2

The General (Ugly) Case Div[E x H*] - i7(µ H.H* + * E.E*) + E.J* = 0 Real part of this equation as the power equation Power dissipated if the real part of 2nd term <> 0 Only true if µ, are complex (imaginary <> 0) Joule Heating occurs through the real part of E.J* If J = )E, then the real part of ) counts Lossless medium has real µ, and imaginary or zero ) The Force of a Plane Wave A plane EM wave passes through a conducting region A current J appears because of the electric field acting on the electrons A force F appears because of the interaction of the moving electrons with the magnetic field F = J x µh (per unit volume) But we can substitute from Mes F = (Curl[H] - 0/0t (E) ) x µh After some substitution (it is left as an exercise..) F = -µh x Curl[H] - E x Curl[E] - µ0/0t (ExH) Third term is zero in steady state In plane wave only E x, H y <> 0 and 0/0x, 0/0y=0 H x Curl[H] -> ½ 0/0z (H 2 y ) k F z = -½ 0/0z (µh 2 y + E 2 x ) = -0U/0z Force per unit volume = rate of decay of energy in waves with distance The Pressure of the Wave The Pressure of the Wave Force per unit volume is also the rate of change of pressure with distance (eg hydrostatic equation) Therefore the pressure p is equal to the energy density U U = ½ (µh 2 y + E 2 x ) for the plane wave Pressure p = S /c In the general case this needs integrating over direction to account for solid angles - but we are ignoring that and using plane waves Pressure is force/unit area Force is rate of change of momentum p 0p/0t = A P = A(1/c) S For a plane wave momentum/unit area is the energy in the beam/unit area divided by the speed of light COMPARE TO PHOTONS Photon energy = 67 Photon momentum = 67/c = 6k In vector terms photon momentum = 6k Total energy in the beam = N 67

Polarisation Some Common Polarisations If light is a vector wave with an electric field and a magnetic field orthogonal to one another Then we can resolve any single wave propagating along the z axis into two parts with electric vectors along the x and y axes respectively - E x and E y BUT it is possible that these are not in phase -there is a specific phase difference between the two waves Restrictions... Not just any pair of fields will do MUST have same frequency (exactly) and a defined phase relationship between then OBSERVABLE features can have many frequencies BUT must have a defined phase relationship which applies for all frequencies OBSERVABLE is formed of many sub-parts each of which is of a single frequency and defined phase relationship 0, m% - total electric vector is a straight line at an angle given by tan -1 (E y /E x ) - linearly polarised (2m+1)%/2 and E y = E x - circularly polarised Anything else - elliptically polarised light All described by the locus of the vector E x cos7t x + E y cos(7t+) y Or in complex notation E x exp i7t x + E y exp i(7t+) y -> E x x + E y exp i y Some Common Polarisations But You Can Only Measure Energy OK so we must characterise things in terms of energy quantities s o = E 2 2 ox + E oy = s 0 = Total energy s 1 = E 2 2 ox - E oy = s 0 sin23cos25 = Difference in energy s 2 = 2 E ox E oy cos(-) = s 0 sin23sin25 s 3 = 2 E ox E oy sin(-) = s 0 cos23 Stokes Parameters - after Lord Stokes of course!

Poincaré Sphere s 2 0 = s 2 1 + s 2 2 2 + s 3 The angles 23 and 2 5 form the latitude and longitude on the sphere All polarisations of a single beam are points on the surfaces of the sphere Eg poles are circular polarisation Eg equator is linear polarisation The Real World See a sum of lots of little wavelets (except lasers!) Stokes parameters are energy-like quantities and can be added up for the sum of a set of wavelets s 0 = <E 2 ox > + <E 2 oy > = s 0 s 1 = <E 2 ox > - <E 2 oy > = s 0 <sin23cos25> s 2 = 2 <E ox E oy cos(-)> = s 0 <sin23sin25> s 3 = 2 <E ox E oy sin(-)> = s 0 <cos23> Natural Light Radiometric Units Natural light does not follow the restrictions on frequency and phase as previous discussion Natural light considered as random superposition of wavelets of random phasing s 2 0 s 2 1 + s 2 2 2 + s 3 For light from a thermal source s 0 <> 0, s 1 = s 2 = s 3 = 0 For white light from a linear polariser s 0 = ±s 1 <> 0, s 2 = s 3 = 0 Defined by history - not by logic!! Energy is the fundamental unit (J) Power is energy per unit time (W) Power per unit solid angle Pointance - W sr -1 - intensity Power per unit area areance - W m -2 -?????? Power per unit area per unit solid angle sterance - W m -2 sr -1 - radiance

Depends Upon Your Point of View For sources interested in... Total power (W) Power into a solid angle (Wsr -1 ) For receivers interested in... Total power per unit area (Wm -2 ) Power per unit area per unit solid angle (Wm -2 sr -1 )