Section 3.3: Geometric Sequences and Series

Similar documents
N V V L. R a L I. Transformer Equation Notes

Repeated multiplication is represented using exponential notation, for example:

Derivation of Annuity and Perpetuity Formulae. A. Present Value of an Annuity (Deferred Payment or Ordinary Annuity)

Chapter System of Equations

Intro to Circle Geometry By Raymond Cheong

Orbits and Kepler s Laws

(Ch. 22.5) 2. What is the magnitude (in pc) of a point charge whose electric field 50 cm away has a magnitude of 2V/m?

Summation Notation The sum of the first n terms of a sequence is represented by the summation notation i the index of summation

r (1+cos(θ)) sin(θ) C θ 2 r cos θ 2

MATHEMATICS FOR ENGINEERING BASIC ALGEBRA

Curvature. (Com S 477/577 Notes) Yan-Bin Jia. Oct 8, 2015

16. Mean Square Estimation

Understanding Financial Management: A Practical Guide Guideline Answers to the Concept Check Questions

A. Description: A simple queueing system is shown in Fig Customers arrive randomly at an average rate of

The Casino Experience. Let us entertain you

Mathematics. Vectors. hsn.uk.net. Higher. Contents. Vectors 128 HSN23100

Infinite Sequences and Series

Money Math for Teens. Introduction to Earning Interest: 11th and 12th Grades Version

SECTION 1.5 : SUMMATION NOTATION + WORK WITH SEQUENCES

I. Supplementary and Relevant Information

We will begin this chapter with a quick refresher of what an exponent is.

Binary Representation of Numbers Autar Kaw

Random Variables and Distribution Functions

Lecture 4: Cauchy sequences, Bolzano-Weierstrass, and the Squeeze theorem

THE ARITHMETIC OF INTEGERS. - multiplication, exponentiation, division, addition, and subtraction

Summary: Vectors. This theorem is used to find any points (or position vectors) on a given line (direction vector). Two ways RT can be applied:

Example 2 Find the square root of 0. The only square root of 0 is 0 (since 0 is not positive or negative, so those choices don t exist here).

2. TRIGONOMETRIC FUNCTIONS OF GENERAL ANGLES

Basic Elements of Arithmetic Sequences and Series

2.016 Hydrodynamics Prof. A.H. Techet

Application: Volume. 6.1 Overture. Cylinders

Sequences and Series

Math 135 Circles and Completing the Square Examples

Soving Recurrence Relations

Learning Objectives. Chapter 2 Pricing of Bonds. Future Value (FV)

Example A rectangular box without lid is to be made from a square cardboard of sides 18 cm by cutting equal squares from each corner and then folding

.04. This means $1000 is multiplied by 1.02 five times, once for each of the remaining sixmonth

Marketing Logistics: Opportunities and Limitations

Finance Practice Problems

Algebra Review. How well do you remember your algebra?

Lecture 5. Inner Product

PROF. BOYAN KOSTADINOV NEW YORK CITY COLLEGE OF TECHNOLOGY, CUNY

LINEAR TRANSFORMATIONS AND THEIR REPRESENTING MATRICES

RIGHT TRIANGLES AND THE PYTHAGOREAN TRIPLETS

n Using the formula we get a confidence interval of 80±1.64

Section 11.3: The Integral Test

Polynomial Functions. Polynomial functions in one variable can be written in expanded form as ( )

Screentrade Car Insurance Policy Summary

Operations with Polynomials

Factoring Polynomials

The dinner table problem: the rectangular case

Physics 43 Homework Set 9 Chapter 40 Key

The LCOE is defined as the energy price ($ per unit of energy output) for which the Net Present Value of the investment is zero.

Lecture 3 Gaussian Probability Distribution

G.GMD.1 STUDENT NOTES WS #5 1 REGULAR POLYGONS

and thus, they are similar. If k = 3 then the Jordan form of both matrices is

INVESTIGATION OF PARAMETERS OF ACCUMULATOR TRANSMISSION OF SELF- MOVING MACHINE

MATH 150 HOMEWORK 4 SOLUTIONS

Our aim is to show that under reasonable assumptions a given 2π-periodic function f can be represented as convergent series

CHAPTER-10 WAVEFUNCTIONS, OBSERVABLES and OPERATORS

Annuities and loan. repayments. Syllabus reference Financial mathematics 5 Annuities and loan. repayments

(1) continuity equation: 0. momentum equation: u v g (2) u x. 1 a

32. The Tangency Problem of Apollonius.

How To Solve The Homewor Problem Beautifully

Trigonometric Form of a Complex Number. The Complex Plane. axis. ( 2, 1) or 2 i FIGURE The absolute value of the complex number z a bi is

Integration by Substitution

Example 27.1 Draw a Venn diagram to show the relationship between counting numbers, whole numbers, integers, and rational numbers.

Cooley-Tukey. Tukey FFT Algorithms. FFT Algorithms. Cooley

Section 5-4 Trigonometric Functions

Listing terms of a finite sequence List all of the terms of each finite sequence. a) a n n 2 for 1 n 5 1 b) a n for 1 n 4 n 2

Two degree of freedom systems. Equations of motion for forced vibration Free vibration analysis of an undamped system

Or more simply put, when adding or subtracting quantities, their uncertainties add.

Factors of sums of powers of binomial coefficients

Sequences and Series

SPECIAL PRODUCTS AND FACTORIZATION

CHAPTER 7: Central Limit Theorem: CLT for Averages (Means)

SAMPLE QUESTIONS FOR FINAL EXAM. (1) (2) (3) (4) Find the following using the definition of the Riemann integral: (2x + 1)dx

Present and future value formulae for uneven cash flow Based on performance of a Business

Periodic Review Probabilistic Multi-Item Inventory System with Zero Lead Time under Constraints and Varying Order Cost

ANNUITIES SOFTWARE ASSIGNMENT TABLE OF CONTENTS... 1 ANNUITIES SOFTWARE ASSIGNMENT... 2 WHAT IS AN ANNUITY?... 2 EXAMPLE QUESTIONS...

Week 3 Conditional probabilities, Bayes formula, WEEK 3 page 1 Expected value of a random variable

NQF Level: 2 US No: 7480

Fast Fourier Transform

Symmetric polynomials and partitions Eugene Mukhin

Continuous Compounding and Annualization

m n Use technology to discover the rules for forms such as a a, various integer values of m and n and a fixed integer value a.

The Handbook of Essential Mathematics

Lesson 15 ANOVA (analysis of variance)

EQUATIONS OF LINES AND PLANES

BINOMIAL EXPANSIONS In this section. Some Examples. Obtaining the Coefficients

Treatment Spring Late Summer Fall Mean = 1.33 Mean = 4.88 Mean = 3.

Skills Needed for Success in Calculus 1

Sequences and Series Using the TI-89 Calculator

MATHEMATICAL INDUCTION

Here are a couple of warnings to my students who may be here to get a copy of what happened on a day that you missed.

Approximating Area under a curve with rectangles. To find the area under a curve we approximate the area using rectangles and then use limits to find

3 The Utility Maximization Problem

Chapter 5: Inner Product Spaces

Transcription:

ectio 3.3: Geometic equeces d eies Geometic equeces Let s stt out with defiitio: geometic sequece: sequece i which the ext tem is foud by multiplyig the pevious tem by costt (the commo tio ) Hee e some exmples of geometic sequeces: ) 9, 8, 36, 7, b), 8, 7, 8, c) 0, 30, 90, 70, 96830 d) 3,, 48, 9, e) 48, 36, 7, The commo tios of ech of these sequeces, i ode fom ) to e), is, 3, 3, 4, 3, 4 espectively. Note tht i ech of them, we c fid the commo tio by tkig y tem d dividig it by the pevious tem. Like y othe sequeces, geometic sequeces c be fiite o ifiite. c) bove is fiite, s the lst tem is specified. The othes e ifiite sequeces. Fo ech of the followig sequeces, stte whethe it is ithmetic, geometic, o eithe. ) 45, 5, 5, b) 5, 3,,, c), 8, 7, 64,, 000 d),,,,,, Aswe ) Geometic, becuse the commo tio is 3.

b) Aithmetic, becuse the commo diffeece d is. c) Neithe, becuse thee is t eithe commo diffeece o tio betwee tems. 3 (I fct, the ptte is tht.) d) Geometic, becuse the commo tio is. Agi, you c defie geometic sequece i oe of thee wys: by listig the tems, by givig ecusive defiitio, o by givig geel defiitio. Recusive Defiitios fo Geometic equeces Let s look t exmple. Give ecusive defiitio fo the sequece, 0, 50, 50, Aswe Recll tht ecusive defiitio hs two pts: listig the fist tem d givig the ptte. I this cse, the ptte is multiplyig the pevious tem by = 5 to get the ext tem. The ecusive defiitio is theefoe 5 Moe geelly, the ecusive defiitio fo y geometic sequece is Geel Fomule fo Geometic equeces <iset vlue hee> Let s exmie the pevious exmple i moe detil to see if we c ecogize y pttes d come up with geel fomul. Rewitig ech tem, we get, 0, 50, 50,... 3, 5, 5, 5,... o the 3 d tem equls the fist times 5 squed, the 4 th tem equls the fist times 5 cubed, d the th tem will equl the fist times 5 ised to the ( ) powe. Moe geelly, the th tem equls the fist tem times ised to the ( ) powe, mely

fo ll geometic sequeces. Wite geel fomul fo the sequece 3, 6,, Aswe This sequece is geometic with the fist tem 3 d commo tio. 3 The geel fomul is the tht = 3 -. Wht is the 0 th tem i the sequece i the sequece 3, 6,,? Aswe This is the sme sequece fom the pevious exmple. We my the use the fomul we deived bove with = 0. 0 0 0 0 3 9 3,57,864 The 0 th tem is,57,864, which povides ice exmple fo how fst geometic sequeces c gow, eve fo smll vlues of. Wite geel fomul fo the sequece 8,, 8, 7,? Wht is the fifteeth tem i this sequece? The fiftieth? Aswe

5 50 3 8 4 3 8 335.43 49 3 8 3.400650 9 3 o the geel fomul is 8 335.43 d 3.4 0 9, espectively. d the fifteeth d fiftieth tems e Geometic eies Recll tht is the sum of the fist tems of seies. Let s look t how fomul fo is deived.... 3 4 3 3... Let s tke tht lst expessio fo d multiply it by to get... The if we dd the ows fo d, we get 3 4 3 3... 3 4... sice ll of the tems i betwee these two ( d ) will ccel. The d The lst fomul bove is the fomul fo the sum of the fist tems fo y geometic seies.

Fid the sum of the fist 0 tems of the seies 3 + 6 + + Aswe This is geometic seies with = 3 d =. We wt to fid 0. 0 3 The sum of the fist 0 tems is 3,45,75. 0 3,45,75 Fid the sum of the fist foty tems of the seies 8 + 8 7. Aswe This is geometic seies with = 8 d = 0 40 3. We wt to fid 40. 8.5 3.538350.5 The sum of the fist foty tems is 3.54 0 7. 7 um of Ifiite Geometic eies Let s tke look t the ifiite seies... 4 8 6 Wht hppes whe we ty to evlute this sum usig the fomul? We c put = ½, = ½, d = ito the fomul, but we will u ito odblock whe we ty to evlute (½).

Let s tke close look t the behviou of (½) fo lge vlues of. As gets lge, the fctio gets eve smlle. I fct, s ppoches, (½) will ppoch zeo. This is tue fo y povided tht <. (If you e ot fmili with the bsolute vlue bs, x, equivlet expessio is tht < <.) Recllig tht d lettig the tem go to zeo, the fo < < fo y ifiite geometic seies, povided tht meets the estictio bove. Let s ow evisit the seies tht stted this discussio,..., d evlute it i the 4 8 6 followig exmple. Evlute.... 4 8 6 Aswe This seies is geometic with = ½ d = ½. The The sum of this seies is. / / / / Evlute 4 + 6 + 3 3 + Aswe This seies is geometic with = 4 d = 3.

4 4 3 4 7 3 3 Evlute 4 6 + 3 3 + Aswe This seies is ideticl to the pevious oe except tht is ow egtive: = 4 d = 3. 4 4 4 3 7 4 4.4 5 5 5 3 3 3 Evlute + 8 + 7 + Aswe This seies is geometic with = d = 3. You my ledy elize wht s goig o, but i cse you do t, let s ively put the vlues ito the fomul d see wht we get: 4 3 Wit! How c the sum of buch of positive umbe be egtive? The swe is tht ou estictio fo is tht it must be betwee d, but =.5. Becuse does ot stisfy the estictio, we cot use the bove fomul fo. Ideed, if you dd up buch of positive umbes tht e icesig s you go up, you c see tht the sum just keeps gettig bigge s we dd moe tems. You could the eithe sy tht the sum is ifiite (dicey) o does ot exist (sfe). But why is it sfe to sy does ot exist i the lst exmple? Let s look t thee sums: ) + 8 + 7 +

b) 8 7 c) 8 + 7 + Ech tem i ) is gettig moe positive, so the sum of tht sequece will be +. Ech tem i b) is gettig moe d moe egtive, so the sum of tht sequece will be. But i the lst tem, the sum oscilltes bck d foth: =, = 6, 3 =, 4 = 9.5, d so o. The sig of is eithe positive o egtive depedig o whethe the umbe of tems you ve dded is eve o odd. Rthe th debtig whethe ifiity is odd o eve (?!), we will just sy tht the sum does ot exist. Evlute j 7 j0 3. Aswe Ick! The best plce to stt is to figue out the fist few tems to detemie the ptte: whe j = 0, whe j =, whe j =, 0 7 7 7 3 7 7 9 3 3 7 7 3 3 3 so ou sequece is 7, 9, 3, This is geometic with = 7 d = 3. The 7 7 3 8 7 40.5 3 3 Evlute k. k 5

Aswe Oce gi, let s figue out the fist few tems to detemie the ptte: whe k = 5, k 5.5 whe k = 6, k 6 3 whe k = 7, k 7 3.5 so ou sequece is.5, 3, 3.5. Wit! This is ithmetic! Not oly tht, but the umbes e icesig. o the sum will be ifiite, o if you pefe, the sum does ot exist. Repetig Decimls Let s exmie 0.7 i some detil to see wht we fid: 0.7 0.777777777... 0.7 0.07 0.007 0.0007... But this is just the sum of ifiite seies with = 0.7 d = 0.. Rewitig d i fctio fom (you ll see why i miute) gives = 7 0 d = 0. The 7 7 0 0 7 0 7 9 0 0 0 9 9 o 0.7 = 7/9. Iteestig! Fid exct fctio fo 0.6. Aswe 0.6 0.66666666... 0.6 0.06 0.006 0.0006...

But this is just the sum of ifiite seies with = 6 0 d = 0. The 6 6 0 0 6 0 6 9 0 0 0 9 9 3 o 0.6 = /3. Fid exct fctio fo 0.8. Aswe 0.8 0.88888... 0.8 0.008 0.00008... But this is just the sum of ifiite seies with = 8 00 d = 00. The 8 8 00 00 8 00 8 90 00 00 00 99 99 o 0.8 = /. ummy Fo geometic sequece, the th tem is give by Fo geometic seies, the sum of the fist tems (th ptil sum) is Fo ifiite geometic seies, the sum is, povided tht < <.