8.2 Magnetic Force on Moving Charges

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8.2 Magnetic Force on Moing Charges Each second, the cyclotron particle accelerator at TRIUMF national laboratory in Vancouer (Figure 1) accelerates trillions of protons to speeds of 224 000 km/s. At this speed, a proton traelling in a straight line would reach the Moon in less than 2 s. The magnetic force of a series of large electromagnets directs the protons in the cyclotron along a spiral path with an increasing radius. These powerful magnets produce a magnetic field oer 10 000 times as strong as Earth s magnetic field. WE LINK The unit of magnetic field strength in the SI system is the tesla (T). A tesla is defined in terms of other SI units by this conersion: Figure 1 The 18 m cyclotron at TRIUMF is the largest in the world. The magnetic force of electromagnets guides protons along an epanding spiral path. tesla the SI unit of measure for describing the strength of a magnetic field; 1 T 5 1 kg C# s 1 T 5 1 kg C# s The magnetic field close to a refrigerator magnet has a magnitude of about 0.001 T. The magnetic field strength near Earth s surface is approimately 50 µt (5 3 10-5 T). An MRI unit, which you read about at the beginning of this chapter, can hae a magnetic field strength of 7 T. We can obsere a magnetic field eerting a force on moing charges using a cathode ray tube and a magnet. In Figure 2(a), a beam of electrons moes across the cathode ray tube. ringing a magnet near the cathode ray tube (Figure 2(b)) shows how a magnetic force deflects the electron beam. (a) Figure 2 (a) Electrons moe straight through the cathode ray tube. (b) When a bar magnet is placed near the electrons, the magnetic force deflects their path. A Charge in a Magnetic Field The eighteenth-century French scientist André-Marie Ampère demonstrated that two current-carrying parallel wires could be made to attract or repel one another depending on the direction of the current in each wire. He also showed that a magnetic field could be made to force a current-carrying conductor to moe. Ampère s discoery applies to more than just electrons flowing in a wire. Magnetic forces act on all types of electric charges, such as electrons, protons, and ions. An important property of the magnetic force is that it depends on the elocity of the charge. The magnetic force is non-zero only if a charge is in motion. This property of the magnetic force is not shared by the graitational force and the electric force. Those forces are both independent of elocity. (b) 386 Chapter 8 Magnetic Fields NEL

Figure 3 shows a particle with positie charge q moing with elocity >. The direction of > is south, the magnetic field > points east, and the magnetic force on the charge is acting ertically upward. Gien a magnetic field > and a charge q moing with elocity >, the magnetic force eerted by > on q is F M 5 q sin u where u is the angle between > and >. In Figure 3, this angle is 908, so in this case, sin u is equal to 1. z (up) (south) Figure 3 q y (east) The magnetic force, just like any other force, is a ector quantity. Notice that the equation proides only the magnitude of the magnetic force. Figure 4 shows how we can also determine the direction of the force using the right-hand rule for a moing charge in a magnetic field. Right-Hand Rule for a Moing Charge in a Magnetic Field If you point your right thumb in the direction of the elocity of the charge ( > ), and your straight fingers in the direction of the magnetic field ( > ), then your palm will point in the direction of the resulting magnetic force (F > M). F M z If q 0, the force will be along z. y Figure 4 You can use the right-hand rule to determine the direction of the magnetic force on a moing charged particle. Applying the right-hand rule to Figure 3, the direction of the magnetic force is ertically upward along the 1z-ais. Using the right-hand rule gies the direction of the force when q is positie in the equation for magnetic force. The magnetic force is up for a positie charge (q. 0) with > and > directed as shown in Figure 4. The force for a negatie charge, such as an electron, is down. Inestigation 8.2.1 Obsering the Magnetic Force on a Moing Charge (page 412) You hae learned how the magnetic force on a moing electric charge relates to the magnitude of the charge, its elocity, and the magnetic field. Now perform Inestigation 8.2.1 to apply this relationship. NEL 8.2 Magnetic Force on Moing Charges 387

The magnetic force has seeral distinctie characteristics. One already mentioned is that F > M depends on elocity. Another characteristic different from graitational and electric forces is that the direction of F > M is always perpendicular to both the magnetic field and the particle s elocity. The direction in which the force acts and the direction of the field are always parallel for electric and graitational fields. In the following Tutorial, you will calculate the magnitude of a magnetic force and use the right-hand rule to determine the direction of the force. Tutorial 1 Calculating the Magnetic Force on Moing Charges A charged particle moing through a magnetic field eperiences a magnetic force. This Tutorial shows how to calculate the magnetic force for a negatie charge and for a positie charge, and determine the direction of deflection of a charge by Earth s magnetic field. Sample Problem 1: Magnetic Force on a Negatie Charge in Motion The electron in Figure 5 moes at a speed of 54 m/s through a magnetic field with a strength of 1.2 T. The angle between the electron s elocity ector and the magnetic field is 908. Assume a alue for the electron s charge of q 5 2e 5 21.60 3 10 219 C. Figure 5 e (a) What is the magnitude of the magnetic force on the electron? Epress your answer in newtons (N), using 1 T 5 1 kg C# s. (b) Use the right-hand rule to determine the direction of the magnetic force. (c) Calculate the graitational force on the electron. The mass of an electron is 9.11 3 10 231 kg. (d) What is the ratio of the graitational force on the electron to the magnetic force on the electron? Solution (a) Gien: q 5 1.60 3 10 219 C; 5 54 m/s; 5 1.2 T; u 5 908 Required: F M Analysis: F M 5 q sin u; use a positie alue for q since we are calculating a magnitude. F M 5 q sin u 5 11.60 3 10 219 C2 a54 m kg b a1.2 s C # b 1 sin 9082 s 5 1.037 3 10 217 kg# m/s 2 F M 5 1.037 3 10 217 N 1two etra digits carried2 Statement: The magnitude of the magnetic force on the electron is 1.0 3 10 217 N. (b) Using the right-hand rule for a positie charge, point the fingers of your right hand in the direction of the magnetic field. Then point your thumb in the direction of the elocity of the particle. Your palm points in the direction of the magnetic force for a positie charge. In this case, the magnetic force for a positie charge points into the page, but the magnetic force for an electron is in the opposite direction of the magnetic force for a positie charge and points out of the page. (c) Gien: m e 5 9.11 3 10-31 kg Required: F g Analysis: The graitational force on the electron is m e g, the product of the mass of the electron and the graitational acceleration. F g 5 m e g 5 19.11 3 10 231 kg2 a9.8 m s 2b F g 5 8.928 3 10 230 N 1two etra digits carried2 Statement: The graitational force on the electron is 8.9 3 10-30 N. (d) Gien: F g 5 8.928 3 10 30 N; F M 5 1.037 3 10 17 N Required: F g F M Analysis: Diide the graitational force by the magnetic force. F g 5 8.928 3 10230 N F M 1.037 3 10 217 N F g 5 8.6 3 10 213 F M Statement: The ratio of the graitational force to the magnetic force on the electron is 8.6 3 10 213 : 1. 388 Chapter 8 Magnetic Fields NEL

Sample Problem 2: Magnetic Force on a Positie Charge in Motion A proton is moing along the -ais at a speed of 78 m/s. It enters a magnetic fi eld of strength 2.7 T. The angle between the proton s elocity ector and the magnetic fi eld is 388 (Figure 6). The mass of a proton is 1.67 3 10 227 kg. Figure 6 38 (a) Calculate the initial magnitude and the direction of the magnetic force on the proton. (b) Determine the proton s initial acceleration. Solution (a) Gien: q 5 1.60 3 10-19 C; 5 78 m/s; 5 2.7 T; u 5 388 Required: magnitude and direction of magnetic force, F M Analysis: Use F M 5 q sin u to calculate the magnitude of the force. Use the right-hand rule to determine the direction of the force. F M 5 q sin u 5 11.60 3 10 219 C2 a78 m kg b a2.7 s C # b 1 sin 3882 s 5 2.075 3 10 217 kg# m/s 2 F M 5 2.075 3 10 217 N 1two etra digits carried2 Point the fi ngers of your right hand in the direction of the magnetic fi eld, and direct your thumb along the elocity ector of the proton. Your palm is facing in the direction of the magnetic force out of the page. Statement: The magnitude of the magnetic force on the proton is 2.1 3 10 217 N. The direction of the magnetic force is out of the page. (b) Gien: F M 5 2.075 3 10 217 N; m 5 1.67 3 10 227 kg Required: acceleration, a Analysis: a 5 F M m a 5 F M m 2.075 3 10 217 kg m s 2 5 1.67 3 10 227 kg a 5 1.2 3 10 10 m/s 2 Statement: The proton s initial acceleration is 1.2 3 10 10 m/s 2. Sample Problem 3: Determining the Effect of Earth s Magnetic Field on the Direction of Lightning Strikes During a thunderstorm, positie charge accumulates near the top of a cloud, and negatie charge accumulates near the bottom of a cloud (Figure 7). When the charge buildup is strong enough, negatie charge moes rapidly from the cloud to the ground as a lightning strike. Assume the charge elocity ector is perpendicular to the ground, and Earth s magnetic fi eld is horizontal, directed north. Determine the direction of the defl ection of this charge by Earth s magnetic fi eld. north cloud Earth Gien: Negatie electric charge moes downward. Earth s magnetic fi eld is directed to the north. Required: direction of defl ection of charge Analysis: The defl ection is in the direction of the magnetic force due to Earth s magnetic fi eld. Apply the right-hand rule for a moing charge in a magnetic fi eld to determine the direction of the magnetic force. Point the fi ngers of your right hand in the direction of the elocity of the positie charge, from the ground toward the cloud. Net, point your fi ngers in the direction of the magnetic fi eld, north. Your palm points in the direction of the resulting magnetic force, into the page, which is west. Statement: When lightning strikes, Earth s magnetic fi eld defl ects the charge toward the west. Figure 7 NEL 8.2 Magnetic Force on Moing Charges 389

Practice 1. A proton with a mass of 1.67 3 10 227 kg is moing horizontally eastward at 9.4 3 10 4 m/s as it enters a magnetic field of strength 1.8 T. The field is directed ertically upward (Figure 8). T/I Figure 8 (a) Calculate the magnitude and direction of the magnetic force on the proton. [ans: 2.7 3 10 214 N [S]] (b) Determine the graitational force on the proton. [ans: 1.6 3 10 226 N] (c) Determine the ratio of the graitational force to the magnetic force on the proton. [ans: 6.0 3 10 213 : 1] 2. Determine the magnitude and direction of the magnetic field for an electron moing upward through a uniform magnetic field with a speed of 3.5 3 10 5 m/s. The particle eperiences a maimum magnetic force of 7.5 3 10 214 N [right]. T/I [ans: 1.3 T [horizontal, into the page]] 3. The cyclotron at TRIUMF accelerates protons from a central injection point outward along an increasing spiral path (Figure 9). The protons reach a speed of 2.24 3 10 8 m/s. Magnets then direct the protons out of the spiral along a linear path toward a target. T/I A in out Figure 9 (a) Suppose a proton passes through a magnetic field that has strength 0.56 T directed ertically upward at the moment just before the proton leaes the spiral. What are the magnitude and direction of the magnetic force on the proton at this moment? [ans: 2.0 3 10-11 N [horizontally outward from the spiral]] (b) What is the magnitude of the magnetic force acting on the proton at the moment just after it leaes the spiral if the only magnetic field around it is Earth s field of 5.5 3 10 25 T? [ans: 2.0 3 10-15 N] 4. An electron moing at a elocity of 6.7 3 10 6 m/s [E] enters a magnetic field with a magnitude of 2.3 T directed at an angle of 478 to the direction of motion and upward in the ertical plane. T/I (a) What are the magnitude and direction of the magnetic force on the electron? [ans: 1.8 3 10 212 N [N]] (b) What is the electron s acceleration? Its mass is 9.11 3 10 231 kg. [ans: 2.0 3 10 18 m/s 2 ] (c) What would the acceleration be if the charged particle were a proton of mass 1.67 3 10 227 kg? [ans: 1.1 3 10 15 m/s 2 ] 390 Chapter 8 Magnetic Fields NEL

8.2 Reiew Summary The formula for calculating the magnitude of the magnetic force on a moing charge is F M 5 q sin u, where u is the angle between > and >. You can use the right-hand rule to determine the direction of the magnetic force on a moing particle. First, point your right thumb in the direction of >. Then, point your fingers in the direction of >. If the charge is positie, your palm indicates the direction of a force on the charge. The direction of force is in the opposite direction for a negatie charge. Questions NEL 1. You hae now learned three forms of the right-hand rule. Eplain the use of each. K/U 2. The charged particle in Figure 10 moes east. It eperiences a force that acts out of the page. Does the particle hae a positie charge or a negatie charge? K/U z y Figure 10 3. A charged particle moing along the 1y-ais passes through a uniform magnetic field oriented in the 1z direction. A magnetic force acts on the particle in the 2 direction. Does the particle hae positie charge or negatie charge? How would the force change if the charge of the particle were tripled but the elocity were haled? K/U 4. A proton moes at a speed of 1.4 3 10 3 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.85 T. T/I (a) Calculate the magnitude of the magnetic force on the proton. (b) What would the magnitude of the magnetic force be if the particle in (a) were an electron? 5. An electron with speed 235 m/s moes through a magnetic field of 2.8 T. The magnitude of the force on the electron is 5.7 3 10 217 N. What angle does the electron s elocity ector make with >? T/I 6. The particle in Figure 11 has a positie charge. Its initial elocity is to the left when it passes into a magnetic field directed into the plane of the page. In which direction is the particle deflected? K/U Figure 11 7. A particle of charge q 5 6.4 mc is moing at an angle of 278 with respect to the y-ais and a speed of 170 m/s. It passes through a uniform magnetic field of magnitude 0.85 T parallel to the y-ais in the y plane. T/I (a) Calculate the magnitude of the magnetic force on the particle. (b) Determine the direction of the magnetic force. (c) What would the magnetic force be on an identical particle traelling at the same speed along the y-ais? Eplain. 8. The particle in Figure 12 has a negatie charge. Its elocity ector lies in the y plane and makes an angle of 758 with the y-ais. If the magnetic field is along the 1 direction, what is the direction of the magnetic force on the particle? T/I z 75 y Figure 12 9. A particle of charge q 5 27.9 mc has a speed of 580 m/s. The particle lies in the y plane and traels at an angle of 558 with respect to the -ais. There is a uniform magnetic field of magnitude 1.3 T parallel to the y-ais. What are the magnitude and direction of the magnetic force on the particle? T/I 10. An alpha particle is a helium nucleus that consists of two protons bound with two neutrons; its mass is 6.644 3 10 227 kg. An alpha particle moing through a perpendicular magnetic field of 1.4 T eperiences an acceleration of 2.4 3 10 3 m/s 2. T/I A (a) What is the force on the alpha particle? (b) What is the alpha particle s speed? 8.2 Magnetic Force on Moing Charges 391