Optics I: lenses and apertures



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Optics I: lenses and apertures CS 178, Spring 2014 Begun 4/8/14, finished 4/10. Marc Levoy Computer Science Department Stanford University

Outline why study lenses? thin lenses graphical constructions, algebraic formulae thick lenses center of perspective, lens as 3D 3D transformation depth of field aberrations & distortion vignetting, glare, and other lens artifacts diffraction and lens quality 2 special lenses telephoto, zoom

Cameras and their lenses single lens reflex (SLR) camera digital still camera (DSC), i.e. point-and-shoot 3

Cutaway view of a real lens 4 Vivitar Series 1 90mm f/2.5 Cover photo, Kingslake, Optics in Photography

Lens quality varies Why is this toy so expensive? EF 70-200mm f/2.8l IS USM $1700 Why is it better than this toy? EF 70-300mm f/4-5.6 IS USM $550 And why is it so complicated? 5 (Canon)

Stanford Big Dish Panasonic GF1 Panasonic 45-200/4-5.6 zoom, at 200mm f/4.6 $300 Leica 90mm/2.8 Elmarit-M prime, at f/4 $2000

Zoom lens versus prime lens 7 Canon 100-400mm/4.5-5.6 zoom, at 300mm and f/5.6 $1600 Canon 300mm/2.8 prime, at f/5.6 $4300

Physical versus geometrical optics (Hecht) Christiaan Huygens 8 light can be modeled as traveling waves the perpendiculars to these waves can be drawn as rays diffraction causes these rays to bend, e.g. at a slit geometrical optics assumes λ 0 no diffraction in free space, rays are straight (a.k.a. rectilinear propagation)

Physical versus geometrical optics (contents of whiteboard) in geometrical optics, we assume that rays do not bend as they pass through a narrow slit this assumption is valid if the slit is much larger than the wavelength, represented on the previous slide by the limit λ 0 physical optics is a.k.a. wave optics 9

Snell s law of refraction (Hecht) 10 as waves change speed at an interface, they also change direction index of refraction nr is defined as x i x t = sinθ i sinθ t = n t n i speed of light in a vacuum speed of light in medium r

Typical refractive indices (n) air = ~1.0 water = 1.33 glass = 1.5-1.8 mirage due to changes in the index of refraction of air with temperature 11

Refraction in glass lenses when transiting from air to glass, light bends towards the normal when transiting from glass to air, light bends away from the normal (Hecht) light striking a surface perpendicularly does not bend 12

Q. What shape should a refractive interface be to make parallel rays converge to a point? (Hecht) A. a hyperbola so lenses should be hyperbolic! 13

Spherical lenses hyperbolic lens 14 (Hecht) spherical lens two roughly fitting curved surfaces ground together will eventually become spherical spheres don t bring parallel rays to a point this is called spherical aberration nearly axial rays (paraxial rays) behave best (wikipedia)

Examples of spherical aberration Canon 135mm soft focus lens (gtmerideth) (Canon) 15

Paraxial approximation object image P e P' assume e 0 Not responsible on exams for orange-tinted slides 16

Paraxial approximation object P u z l e h image P' 17 assume e 0 assume sin u = h / l u (for u in radians) assume cos u z / l 1 assume tan u sin u u

The paraxial approximation is a.k.a. first-order optics assume first term of i.e. sin ϕ ϕ sin φ = φ φ 3 3! + φ 5 5! φ 7 7! +... assume first term of i.e. cos ϕ 1 cos φ = 1 φ 2 2! + φ 4 4! φ 6 6! +... so tan ϕ sin ϕ ϕ these are the Taylor series for sin ϕ and cos ϕ 18 (phi in degrees)

Paraxial focusing object i i' image P (n) (n') equivalent to P' Snell s law: n sin i = n' sin i' paraxial approximation: n i n' i' sinθ i sinθ t = n t n i with n = n i for air n' = n t for glass i, i' in radians θ i, θ t in degrees 19

Paraxial focusing i = u + a u h / z u' h / z' P u z (n) i h (n') i' r a Given object distance z, what is image distance z? z' u' P' n i n' i' 20

Paraxial focusing i = u + a u h / z u' h / z' P u z (n) i h (n') i' r a a = u' + i' a h / r z' u' P' n (u + a) n' (a u') 21 n (h / z + h / r) n' (h / r h / z') n i n' i' n / z + n / r n' / r n' / z' h has canceled out, so any ray from P will focus to P

Focal length r P z (n) (n') z' P' What happens if z is? n / z + n / r n' / r n' / z' n / r n' / r n' / z' z' (r n') / (n' n) 22 f focal length = z

Lensmaker s formula using similar derivations, one can extend these results to two spherical interfaces forming a lens in air so si (Hecht, edited) as d 0 (thin lens approximation), we obtain the lensmaker s formula 1 s o + 1 s i = (n l 1) 1 R 1 1 R 2 23

Gaussian lens formula Starting from the lensmaker s formula 1 s o + 1 s i = (n l 1) 1 R 1 1 R 2, (Hecht, eqn 5.15) and recalling that as object distance so is moved to infinity, image distance si becomes focal length fi, we get 1 f i = (n l 1) 1 R 1 1 R 2 Equating these two, we get the Gaussian lens formula 1 s o + 1 s i = 1 f i.. (Hecht, eqn 5.16) (Hecht, eqn 5.17) 24

From Gauss s ray construction to the Gaussian lens formula object image y o y i s o s i positive is rightward, positive is leftward s i positive is upward y s o 25

From Gauss s ray construction to the Gaussian lens formula object image y o y i s o s i 26 y y i y o = s i s o

From Gauss s ray construction to the Gaussian lens formula f object (positive is to right of lens) image y o y i s o s i y i y o = s i s o and y i y o = s i f f... 1 s o + 1 s i = 1 f y 27

Changing the focus distance to focus on objects at different distances, move sensor relative to lens f f sensor (Flash demo) http://graphics.stanford.edu/courses/ cs178/applets/gaussian.html 1 s o + 1 s i = 1 f 28

Changing the focus distance to focus on objects at different distances, move sensor relative to lens f f sensor at s o = s i = 2 f we have 1:1 imaging, because 1 2 f + 1 2 f = 1 f In 1:1 imaging, if the sensor is 36mm wide, an object 36mm wide will fill the frame. 1 s o + 1 s i = 1 f 29

Changing the focus distance to focus on objects at different distances, move sensor relative to lens f f sensor at s o = s i = 2 f we have 1:1 imaging, because 1 2 f + 1 2 f = 1 f can t focus on objects closer to lens than its focal length f 1 s o + 1 s i = 1 f 30

Recap approximations we sometimes make when analyzing lenses geometrical optics instead of physical optics spherical lenses instead of hyperbolic lenses thin lens representation of thick optical systems paraxial approximation of ray angles the Gaussian lens formula relates focal length f, object distance so, and image distance si these settings, and sensor size, determine field of view 1:1 imaging means so = si and both are 2 focal length so = f is the minimum possible object distance for a lens 31 Questions?

Convex versus concave lenses (Hecht) rays from a convex lens converge rays from a concave lens diverge positive focal length f means parallel rays from the left converge to a point on the right negative focal length f means parallel rays from the left converge to a point on the left (dashed lines above) 32

Convex versus concave lenses (Hecht) rays from a convex lens converge rays from a concave lens diverge 33...producing a real image...producing a virtual image

Convex versus concave lenses (Hecht) 34...producing a real image...producing a virtual image

The power of a lens P = 1 f units are meters -1 a.k.a. diopters my eyeglasses have the prescription right eye: -0.75 diopters left eye: -1.00 diopters Q. What s wrong with me? A. Myopia (nearsightedness) (Pamplona) 35

Combining two lenses using focal lengths 1 f tot = 1 f 1 + 1 f 2 using diopters P tot = P 1 + P 2 example 1 200mm + 1 500mm = 1 143mm -or- 5.0 + 2.0 = 7.0 diopters 36

Close-up filters 1/500mm = +2 diopters (wikipedia) screw on to end of lens power is designated in diopters (usually) 37

Close-up filters Panasonic 45-200 + changes longest focal length from 200mm to 143mm 1 200mm + 1 500mm = 1 143mm -or- 5.0 + 2.0 = 7.0 diopters 38

Close-up filters for a fixed image distance, it reduces the object distance at f=200mm, this len s minimum object distance so = 1000mm at these settings, its effective image distance must be s i = 1 1 f 1 = s o 1 1 200mm 1 1000mm = 250mm 3 closer! 39 with the closeup filter and the same settings of focal length and image distance, the in-focus object distance becomes s o = 1 1 f 1 = s i 1 1 143mm 1 250mm = 334mm

Close-up filters 200mm lens & no closeup filter so = 1000mm 200mm lens & 500D closeup filter so = 334mm poor man s macro lens 40

Magnification object image y o y i s o s i 41 M T! y i y o = s i s o

Close-up filters 200mm lens & no closeup filter so = 1000mm 200mm lens & 500D closeup filter so = 334mm 42 M T = s i s o = 250 1000 = 1: 4 M T = s i s o = 250 334 = 3 : 4

Thick lenses an optical system may contain many lenses, but can be characterized by a few numbers (Smith) 43

Center of perspective 44 (Hecht) in a thin lens, the chief ray from a point traverses the lens (through its optical center) without changing direction in a thick lens, the intersections of this ray with the optical axis are called the nodal points for a lens in air, these coincide with the principal points the first nodal point is the center of perspective

Lenses perform a 3D perspective transform (Flash demo) http://graphics.stanford.edu/courses/ cs178/applets/thinlens.html 45 lenses transform a 3D object to a 3D image; the sensor extracts a 2D slice from that image as an object moves linearly (in Z), its image moves non-proportionately (in Z) (Hecht) as you move a lens linearly relative to the sensor, the in-focus object plane moves non-proportionately as you refocus a camera, the image changes size!

Lenses perform a 3D perspective transform (contents of whiteboard) 46 a cube in object space is transformed by a lens into a 3D frustum in image space, with the orientations shown by the arrows in computer graphics this transformation is modeled as a 4 4 matrix multiplication of 3D points expressed in 4D homogenous coordinates in photography a sensor extracts a 2D slice from the 3D frustum; on this slice some objects will be sharply focused; others may be blurry

Recap more implications of the Gaussian lens formula convex lenses make real images; concave make virtual images the power of a lens (in diopters) is 1 over its focal length when combining two lenses, add their powers adding a closeup filter allows a smaller object distance changing object and image distances changes magnification lenses perform a 3D perspective transform of object space an object s apparent size is inversely proportional to its distance linear lens motions move the in-focus plane non-linearly focusing a lens changes the image size (slightly) 47 Questions?

Depth of field (London) N = f A 48 lower N means a wider aperture and less depth of field

How low can N be? (Kingslake) principal planes are the paraxial approximation of a spherical equivalent refracting surface N = 1 2 sinθ ' 49 lowest possible N in air is f/0.5 lowest N I ve seen in an SLR is f/1.0 Canon EOS 50mm f/1.0 (discontinued)

Cinematography by candlelight Stanley Kubrick, Barry Lyndon, 1975 50 Zeiss 50mm f/0.7 Planar lens originally developed for NASA s Apollo missions very shallow depth of field in closeups (small object distance)

Cinematography by candlelight Stanley Kubrick, Barry Lyndon, 1975 51 Zeiss 50mm f/0.7 Planar lens originally developed for NASA s Apollo missions very shallow depth of field in closeups (small object distance)

Circle of confusion (C) to derive C for a given situation, start from the smallest visual angle we can detect; we ll cover this later in the course 52 C depends on sensing medium, reproduction medium, viewing distance, human vision,... for print from 35mm film, 0.02mm (on negative) is typical for high-end SLR, 6µ is typical (1 pixel) larger if downsizing for web, or lens is poor

Depth of field formula C M T M T! y i y o = s i s o depth of field C depth of focus object image DoF is asymmetrical around the in-focus object plane 53 conjugate in object space is typically bigger than C

Depth of field formula C M T depth of field CU f f C depth of focus U object image DoF is asymmetrical around the in-focus object plane 54 conjugate in object space is typically bigger than C

Depth of field formula C M T CU f f depth of field f N depth of focus C D 2 D 1 object U image 55 D 1 CU / f = U D 1 f / N... D 1 = NCU 2 f 2 + NCU D 2 = NCU 2 f 2 NCU

Depth of field formula D TOT = D 1 + D 2 = 2NCU 2 f 2 f 4 N 2 C 2 U 2 N 2 C 2 U 2 can be ignored when conjugate of circle of confusion is small relative to the aperture 56 where D TOT 2NCU 2 N is F-number of lens C is circle of confusion (on image) U is distance to in-focus plane (in object space) f is focal length of lens f 2

D TOT 2NCU 2 f 2 N = f/4.1 C = 2.5µ U = 5.9m (19 ) f = 73mm (equiv to 362mm) DTOT = 132mm 1 pixel on this video projector C = 2.5µ 2816 / 1024 pixels DEFF = 363mm

N = f/6.3 C = 2.5µ U = 17m (56 ) f = 27mm (equiv to 135mm) DTOT = 12.5m (41 ) 1 pixel on this video projector C = 2.5µ 2816 / 1024 pixels DEFF = 34m (113 )

N = f/5.6 C = 6.4µ U = 0.7m f = 105mm DTOT = 3.2mm 1 pixel on this video projector C = 6.4µ 5616 / 1024 pixels DEFF = 17.5mm

Canon MP-E 65mm 5:1 macro N = f/2.8 C = 6.4µ U = 78mm f = 65mm (use N = (1+MT)N at short conjugates (MT=5 here)) = f/16 DTOT = 0.29mm! (Mikhail Shlemov)

Sidelight: macro lenses 1 s o + 1 s i = 1 f Q. How can the Casio EX-F1 at 73mm and the Canon MP-E 65mm macro, which have similar f s, have such different focusing distances? s o s i normal A. Because macro lenses are built to allow long si this changes so, which changes magnification macro macro lenses are also well corrected for aberrations at short so M T! s i / s o 61

Extension tube: fits between camera and lens, converts a normal lens to a macro lens toilet paper tube, black construction paper, masking tape 62 camera hack by Katie Dektar (CS 178, 2009)

Extension tubes versus close-up filters In past years students have asked about close-focus settings on some standard zoom lenses. These indeed allow macro shots to be captured, but such lenses are not well corrected for operating at close object distances, so they will produce mediocre-quality macro images. Canon 25mm Canon f = 500mm both allow closer focusing, hence greater magnification both degrade image quality relative to a macro lens extension tubes work best with wide-angle lenses; close-up filters work best with telephoto lenses extension tubes raise F-number, reducing light need different close-up filter for each lens filter diameter 63

Extension tubes versus close-up filters versus teleconverters Canon 25mm Canon f = 500mm Nikon 1.4 a teleconverter fits between the camera and lens, like an extension tube they increase f, narrowing FOV & increasing magnification, but they don t change the focusing range like extension tubes, they raise F-number, reducing light, and they are awkward to add or remove see http://www.cambridgeincolour.com/tutorials/macro-extension-tubes-closeup.htm 64

DoF is linear with F-number D TOT 2NCU 2 f 2 (juzaphoto.com) (Flash demo) http://graphics.stanford.edu/courses/ cs178/applets/dof.html 65 f/2.8 f/32

DoF is quadratic with subject distance D TOT 2NCU 2 f 2 (Flash demo) http://graphics.stanford.edu/courses/ cs178/applets/dof.html 66 (London)

Hyperfocal distance 67 the back depth of field D 2 = becomes infinite if U f 2 In that case, the front depth of field becomes D 1 = NCU 2 f 2 NCU NC! H NCU 2 f 2 + NCU = H 2 so if I had focused at 32m, everything from 16m to infinity would be in focus on a video projector, including the men at 17m N = f/6.3 C = 2.5µ 2816 / 1920 pixels U = 17m (56 ) f = 27mm (equiv to 135mm) DTOT = 18.3m on HD projector H = 31.6m (104 ) (Flash demo) http://graphics.stanford.edu/courses/ cs178/applets/dof.html

DoF is inverse quadratic with focal length D TOT 2NCU 2 f 2 (Flash demo) http://graphics.stanford.edu/courses/ cs178/applets/dof.html 68 (London)

Q. Does sensor size affect DoF? D TOT 2NCU 2 f 2 69 as sensor shrinks, lens focal length f typically shrinks to maintain a comparable field of view as sensor shrinks, pixel size C typically shrinks to maintain a comparable number of pixels in the image thus, depth of field DTOT increases linearly with decreasing sensor size on consumer cameras this is why amateur cinematographers are drawn to SLRs their chips are larger than even pro-level video camera chips so they provide unprecedented control over depth of field

Vincent Laforet, Nocturne (2009) Canon 1D Mark IV

DoF and the dolly-zoom if we zoom in (increase f ) and stand further back (increase U ) by the same factor D TOT 2NCU 2 f 2 depth of field stays the same, but background gets blurrier! useful for macro when you can t get close enough 71 50mm f/4.8 200mm f/4.8, moved back 4 from subject (juzaphoto.com)

Macro photography using a telephoto lens (contents of whiteboard) 72 changing from a wide-angle lens to a telephoto lens and stepping back, you can make a foreground object appear the same size in both lenses and both lenses will have the same depth of field on that object but the telephoto sees a smaller part of the background (which it blows up to fill the field of view), so the background will appear blurrier

Parting thoughts on DoF: the zen of bokeh (wikipedia.org) Canon 85mm prime f/1.8 lens 73 the appearance of small out-of-focus features in a photograph with shallow depth of field determined by the boundary of the aperture people get religious about it but not every picture with shallow DoF has evident bokeh...

Natasha Gelfand (Canon 100mm f/2.8 prime macro lens)

Games with bokeh 75 picture by Alice Che (CS 178, 2010) heart-shaped mask in front of lens subject was Christmas lights, but misfocused lights were also under-exposed to maintain their color

Parting thoughts on DoF: seeing through occlusions A student asked how seeing through occlusions relates to depth of field. If a camera / lens combination is providing a shallow depth of field, then it is throwing out of focus those scene features that lay beyond the depth of field. Being out of focus makes a scene feature appear blurry, but this is not the same as capturing a sharp photograph of that scene feature, then blurring it in Photoshop. The difference is that optically produced blurring allows you to see through occlusions, as diagrammed in the next slide, while blurring producing by convolution (as in Photoshop) does not. 76 (Fredo Durand) out-of-focus is not the same as convolving the image i.e. not the same as blurring in Photoshop DoF lets you eliminate occlusions, like a chain-link fence

Seeing through occlusions using a large aperture (contents of whiteboard) for a pixel focused on the subject, some of its rays will strike the occluder, but some will pass to the side of it, if the occluder is small enough the pixel will then be a mixture of the colors of the subject and occluder 77 thus, the occluder reduces the contrast of your image of the subject, but it doesn t actually block your view of it

Tradeoffs affecting depth of field See http://graphics.stanford.edu/ courses/cs178/applets/dof.html 78 (Eddy Talvala)

Recap depth of field (DTOT) is governed by circle of confusion (C), aperture size (N), subject distance (U), and focal length ( f ) depth of field is linear in some terms and quadratic in others if you focus at the hyperfocal distance H = f 2 / NC, everything from H / 2 to infinity will be in focus depth of field increases linearly with decreasing sensor size useful sidelights D TOT 2NCU 2 bokeh refers to the appearance of small out-of-focus features you can take macro photographs using a telephoto lens depth of field blur is not the same as blurring an image f 2 79 Questions?