# Building the AMP Amplifier

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1 Building the AMP Amplifier Introduction For about 80 years it has been possible to amplify voltage differences and to increase the associated power, first with vacuum tubes using electrons from a hot filament; and, since about 1960, with solid state devices transistors (like the 2N3055) and integrated circuits (like the LM317 and the LF411). Amplify means to make larger, and the ratio of the output voltage to the input voltage is called the gain. The voltages to be amplified are sometimes induced in antennas by fields from distant radio transmitters, or are the output of some transducer that turns a physical phenomenon into a voltage; for example, a microphone turns a varying sound pressure into a varying voltage. Operational amplifier integrated circuits are widely used nowadays. They have two inputs and one output. One input is called inverting a plus voltage is turned into minus output; the other input is non-inverting a plus voltage stays plus. Thus a voltage difference between the two inputs is obtained if the two input voltages are not equal. If the same voltage is applied to both inputs there is no output (ideally). This voltage difference between the two inputs is amplified by a large factor A, (open-loop gain). By using a negative feedback circuit, a much lower but stable ratio of output to input voltage, G = Vout V in, can be obtained (closed-loop gain). This also ensures a reduction of noise and gain variations. You will construct a non-inverting dc amplifier with the integrated circuit op-amp, LF411. It has an amplification A of more than 10 5, which means that it can amplify voltages so that tens of microvolt differences between the two inputs can become volts at the output. We will use the LF411 op-amp in a negative-feedback circuit to give a gain, G, of about 90. You will build your amplifier on the other half of the same circuit board that you used for the LVPS (low voltage power supply). The schematic circuit diagram for the amplifier is shown in Figure 1. 1

2 Voltage divider for the LVPS Figure 1: Amplifier Circuit Diagram The LF411 requires two equal plus and minus power supply outputs. We can make this from the LVPS by using the voltage divider shown in Figure 2 with the LVPS set at 12V. Figure 2: Voltage divider for LVPS If the central connection between the two resistors is defined to be the zero-volt level, then we have two power supply outputs; one at +6V and one at 6V with respect to this common zero of voltage, called common. 2

3 LF411 op-amp The op-amp has eight pins: pins 1-4 on one side and pins 5-8 on the other side. Pin 1 is conventionally marked by a dot on the op-amp. The various pin connections are as follows: Figure 3: Op-amp 1) Pin 7 connects to the +6V voltage output of the LVPS. Pin 4 connects to the 6V voltage output of the LVPS. 2) Pin 6 is the output voltage with respect to common. 3) Pin 2 is the inverting input, so a voltage +V 2 with respect to common becomes AV 2 at the output, where A 10 5 is the open-loop amplification. Similarly, a voltage V 2 with respect to common becomes +AV 2 at the output. 4) Pin 3 is the non-inverting input, so a voltage +V in with respect to common becomes +AV in at the output. Similarly, a voltage V in with respect to common becomes AV in at the output. So the two different input voltages input (pins 2 and 3) give an output voltage +A(V in V 2 ). The op-amp amplifies the difference of voltage between its two inputs. If the two input voltages are the same voltage with respect to common, then there is no output voltage. 5) Most op-amps have some dc offset in the output. This can be eliminated by adjusting the potential difference between pin 1 and pin 5 with the 100 kω pot. 6) Pin 8 has no connection. The input voltages to the amplifier go to the non-inverting input (pin 3) through a 9.1kΩ resistor followed by a 0.047µF bypass capacitor between common and input (pin 3), to keep voltage spikes and surges out of the op-amp. 3

4 Negative Feedback The negative feedback circuit is shown in Figure 4. Study this schematic diagram carefully. Notice that the feedback voltage divider consisting of a resistor R 1 = 9.1kΩ from the output (pin 6) to the inverting input of the op-amp (pin 2) and a resistor R 2 = 100Ω connected from the inverting input (pin 2) to the common. These resistors determine the gain of the circuit G = V out V in, which is the ratio of the output voltage at pin 6 to the input voltage at pin 3. Figure 4: The negative feedback circuit The resistors R 1 and R 2 form a voltage divider so the voltage at pin 2 is where β = R 2 V 2 = Vout βv out R1 + R 2 R 2 100Ω 1 = =. R 1 + R 2 9.1kΩ + 100Ω 92 The LF411 op-amp inverts V 2 and then adds the inverted voltage to V in. (This is essentially a voltage subtractor.) The difference between these input voltages is then amplified by a factor A 10 5 to give the output voltage V out = A(V in V 2 ) = A(V in βv out ). We can solve this equation for the gain G which is the ratio of the output voltage to the input voltage at pin 3 V out A A 1 G = = = = 92 V in 1+ βa βa β. Notice that 1 + βa βa >> 1 sinceβa (10 2 )(10 5 ) = The negative feedback circuit reduces the gain to 92. But the important point is that this gain is nearly independent of A, the amplification. The amplification may vary due to factors like temperature changes, dependence 4

5 on voltage inputs, or noise, but the gain, determined by stable components (resistors), is stable. It can be changed by choosing different resistors. Wiring the Amplifier The best way to wire the amplifier is shown in the circuit diagram, (Figure 1), and the diagrams (Figures 5-8) showing the layout of the parts on the board. If you are not sure about the value of a resistor, measure it with your MMM! You should start with the socket with eight legs. This will help get the wiring for the opamp correct. The LF411 op-amp itself is a sensitive component, and can be damaged by static electricity. It should be the last item to be installed. Figures 5-8 are guides to how the amplifier can be wired. Notice that the leads of the socket can be bent in directions that enable them to be connected to various components. Think where these should go and install them in the right place with wires heading toward where they will be connected. Figure 5a: Parts Layout, Topview 5

6 Figure 5b: Schematic Parts Layout, Topview Note: In figure 5a and 5b, there is two bare wires on the topside of the board. The first connects the 6V line from the LVPS to one leg of the 5kΩ pot of the amplifier. The second connects pin 6 to the output B. Figure 6: Wiring Plan, Bottom View 6

7 Figure 7: Schematic Parts Layout, Bottom View Figure 8: Wiring Plan, Bottom View 7

9 Figure 8: Calibration Circuit Connect your second MMM, set on 250mV DC, across the1.3kω resistor, that is, from the lead labeled D in the Figure 8 to common C. Connect lead D to the input A (use your clip lead), and vary the input by turning the 5kΩ pot in both directions so as to make 10 mv steps. Turning the 5kΩ pot in one direction will make the input voltage minus so you will need to reverse the leads of the MMM in order to read the voltage. You will measure the output voltage with your first MMM set on 5DCV (as you did when you were adjusting the offset voltage). Again you may need to reverse the polarity of the MMM as needed. You will only be able to reach a maximum input voltage of 67 mv in either direction. Tabulate your measurements of input and output voltages. AMP Parts 1 op amp, LF411 1 socket, IC 8 pin dual inline 1 potentiometer, 100 kω 1 potentiometer, 5kΩ 3 resistors, 100Ω 12W 2 resistors, 9.1kΩ 12W 1 resistor, 91kΩ 12W 1 resistor, 1.3 kω 12W 1 resistor, 150 kω 12W 1 capacitor, 0.05µF 1 ft wire, #22 red insulated solid 1 ft wire, #22 bare solid 9

10 AMP PARTS 10

11 11

12 Building the AMP (Amplifier) Report: After you have made and tabulated your measurements of input and output voltages for the amplifier, plot the output voltage as a function of input voltage. Determine the gain of the amplifier in the region where the response is linear and compare your value with the theoretical expectation. Does the gain remain constant over the whole range of input voltages? Problem 1: Amplification A negative feedback circuit in an amplifier circuit is shown in the figure below. In this circuit, the resistors have the values R 1 = 9.1kΩ, R 2 = 100Ω, and the open loop amplification is A Pin 3 is non-inverting and pin 2 is inverting. a) What is the output voltage V of the op-amp in terms of the input voltage V in to pin 3, and out the voltage at pin 2, V 2, and the amplification A? (Note: all voltages are with respect to common). b) Derive an expression for the voltage at pin 2, in terms of R 1 and R 2. c) Derive an expression for the closed loop gain G = V V in in terms of R 1, R 2, and A. out d) Calculate the value of the gain G, clearly indicating any approximations you have made. 12

13 Problem 2: Calibration The calibration circuit for the amplifier is shown in the figure below. When the multimeter is set on the 250 mv scale the multimeter has a resistance of 5kΩ. a) When the 5kΩ pot is turned 2/3 of the way in the direction of the +6V line from the 6V end, what is the voltage difference between common C and the 5 kω pot slider? b) When the 5 kω pot is set as in part a), calculate the voltage difference between the common C and point D which is connected via a clip lead to the input A? c) What ouput voltage did you read when your pot was set as in part a) while you were calibrating your amplifier? 13

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