Algebra 1 Chapter 10 Review
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1 Name: Class: Date: ID: A Algebra 1 Chapter 10 Review Multiple Choice Identify the choice that best completes the statement or answers the question Simplify the radical expression. 1 b. 1 c. 6 d. 4 6 Simplify the radical expression by rationalizing the denominator b. 4 1 c. 1 4 d. 3. A square garden plot has an area of 4 ft. Find the length of each side in simplest radical form. b. Calculate the length of each side to the nearest tenth of a foot. 4 ;.45 ft c. 4 4 ; 6 ft b. 6 ; 4.9 ft d. 4 ; 5 ft Find the length of the missing side. If necessary, round to the nearest tenth b. 19 c. 38 d Determine whether the given lengths can be sides of a right triangle m, 4 m, 30 m no b. yes 6. 7 cm, 40 cm, 41 cm no b. yes 1
2 Name: ID: A Determine whether the following statement is sometimes, always, or never true. 7. Two consecutive positive integers form part of a Pythagorean triple. never b. always c. sometimes Simplify the expression b. 6 c. 3 1 d b c. 8 7 d (6 11 )( ) c. 85 b d. 5 b Ê ˆ b. 3 1 d. 13. Find an exact solution for 5 1 x = c. d. c ; 1.1 c. ; 5 b. 5 ;.5 d. 5. Then find the approximate solution to the nearest tenth. 5 ; A 14. The formula r = 1 gives the interest rate r that will allow principal P to grow into amount A in P two years, if the interest is compounded annually. Suppose you have $45 to deposit into an account. Find the interest rate you would need to have $470 in the account at the end of the second year. 5.% b. 105% c. 0.05% d. 5.4%
3 Name: ID: A 15. Find the exact perimeter of the triangle. 68 x b. 68x c. 5x + x 17 d. 68x Solve the equation. Check your solution = m 8 6 b. 144 c. 3 d r + 5 = b. 6 c. 17 d The velocity of sound in air is given by the equation v = t where v is the velocity in meters per second and t is the temperature in degrees Celsius. Find the temperature when the velocity of sound in air is 369 meters per second. Round to the nearest degree. 507º b. 6,535º c. 7,081º d. 67º Solve the equation. Identify any extraneous solutions. 19. w = 7w 0 and 7 are solutions of the original equation. b. 0 is a solution of the original equation. 7 is an extraneous solution. c. 7 is a solution of the original equation. 0 is an extraneous solution. d. 7 is a solution of the original equation. 0 is an extraneous solution. 0. The formula v = 64h can be used to find the velocity v in feet per second of an object that has fallen h feet. Find the velocity of an object that has fallen 5 feet. Round your answer to the nearest hundredth. 800 feet per second c. 00 feet per second b. 30 feet per second d. 40 feet per second 3
4 Name: ID: A 1. Graph the function f(x) = 4 x. c. b. d. Short Answer. The sales of a certain product after an initial release can be found by the equation s = 16 3t + 5, where s represents the total sales (in thousands) and t represents the time in weeks after release. Make a table of values. b. Graph the function. c. Use the graph to estimate the sales 7 weeks after release. 4
5 Name: ID: A Essay 3. In the diagram y = 17. Use the Pythagorean Theorem to find x. Express x as a radical expression in simplest form. Show your work. Ê ˆ 4. Simplify Show your work. Justify each step 5. Solve 3x 1 = 4. Check your solution. If there is no solution, write no solution. Show your work. 5
6 Algebra 1 Chapter 10 Review Answer Section MULTIPLE CHOICE 1. ANS: A PTS: 1 DIF: L REF: 10-1 Simplifying Radicals OBJ: Simplifying Radical Expressions Involving Products STA: CA A1.0 TOP: 10-1 Example 1 KEY: radical expressions Multiplication Property of Square Roots square root. ANS: A PTS: 1 DIF: L REF: 10-1 Simplifying Radicals OBJ: Simplifying Radical Expressions Involving Quotients STA: CA A1.0 TOP: 10-1 Example 7 KEY: radical expressions rationalize radicand in the denominator 3. ANS: B PTS: 1 DIF: L3 REF: 10-1 Simplifying Radicals OBJ: Simplifying Radical Expressions Involving Products STA: CA A1.0 KEY: word problem problem solving radical expressions multi-part question 4. ANS: D PTS: 1 DIF: L REF: 10- The Pythagorean Theorem OBJ: Solving Problems Using the Pythagorean Theorem STA: CA A1.0 CA A1 4. TOP: 10- Example 1 KEY: Pythagorean Theorem right triangle 5. ANS: B PTS: 1 DIF: L REF: 10- The Pythagorean Theorem OBJ: 10-. Identifying Right Triangles STA: CA A1.0 CA A1 4. TOP: 10- Example 3 KEY: right triangle converse of the Pythagorean Theorem converse Pythagorean Theorem 6. ANS: A PTS: 1 DIF: L REF: 10- The Pythagorean Theorem OBJ: 10-. Identifying Right Triangles STA: CA A1.0 CA A1 4. TOP: 10- Example 3 KEY: right triangle converse of the Pythagorean Theorem converse Pythagorean Theorem 7. ANS: C PTS: 1 DIF: L3 REF: 10- The Pythagorean Theorem OBJ: Solving Problems Using the Pythagorean Theorem STA: CA A1.0 CA A1 4. KEY: always sometimes never Pythagorean Theorem Pythagorean triple reasoning 8. ANS: A PTS: 1 DIF: L OBJ: Simplifying Sums and Differences STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example 1 KEY: like radicals combining like radicals 9. ANS: C PTS: 1 DIF: L OBJ: Simplifying Sums and Differences STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example KEY: like radicals combining like radicals radical expressions 10. ANS: D PTS: 1 DIF: L OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example 4 KEY: FOIL radical expressions Multiplication Property of Square Roots 1
7 11. ANS: D PTS: 1 DIF: L3 OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example 5 KEY: radical expressions rationalize conjugates 1. ANS: B PTS: 1 DIF: L3 OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example 5 KEY: conjugates radical expressions FOIL rationalize 13. ANS: A PTS: 1 DIF: L OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example 6 KEY: radical expressions rationalize radical equation Multiplication Property of Square Roots 14. ANS: A PTS: 1 DIF: L3 OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 KEY: radical equation word problem problem solving Division Property of Square Roots 15. ANS: C PTS: 1 DIF: L4 OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 KEY: Pythagorean Theorem radical expressions Multiplication Property of Square Roots 16. ANS: B PTS: 1 DIF: L REF: 10-4 Solving Radical Equations OBJ: Solving Radical Equations STA: CA A1.0 CA A1 5. TOP: 10-4 Example 1 KEY: radical radical equation solving equations 17. ANS: D PTS: 1 DIF: L REF: 10-4 Solving Radical Equations OBJ: Solving Radical Equations STA: CA A1.0 CA A1 5. TOP: 10-4 Example 1 KEY: radical radical equation solving equations 18. ANS: D PTS: 1 DIF: L REF: 10-4 Solving Radical Equations OBJ: Solving Radical Equations STA: CA A1.0 CA A1 5. TOP: 10-4 Example KEY: radical radical equation solving equations word problem problem solving 19. ANS: A PTS: 1 DIF: L REF: 10-4 Solving Radical Equations OBJ: Solving Equations With Extraneous Solutions STA: CA A1.0 CA A1 5. TOP: 10-4 Example 4 KEY: solving equations radical equation extraneous solutions 0. ANS: D PTS: 1 DIF: L3 REF: 10-4 Solving Radical Equations OBJ: Solving Radical Equations STA: CA A1.0 CA A1 5. TOP: 10-4 Example KEY: radical equation word problem problem solving 1. ANS: B PTS: 1 DIF: L REF: 10-5 Graphing Square Root Functions OBJ: Graphing Square Root Functions STA: CA A TOP: 10-5 Example 3 KEY: graphing square root radical expressions
8 SHORT ANSWER. ANS: Week Sales b. c. about $100,000 PTS: 1 DIF: L3 REF: 10-5 Graphing Square Root Functions OBJ: Graphing Square Root Functions STA: CA A TOP: 10-5 Example 3 KEY: graphing square root multi-part question word problem problem solving 3
9 ESSAY 3. ANS: [4] Find the height AC of the triangle. AC + 1 Ê ˆ = 17 AC + 1 = 17 AC = 17 1 Find x. AB = AB = 6 AC = 16 AC = 16 AC = 4 x = x = x = 5 x = 5 x = 4 13 x = 13 [3] answer not in simplest radical form OR one computational error [] two computational errors [1] more than two error OR wrong sides used in equations PTS: 1 DIF: L4 REF: 10- The Pythagorean Theorem OBJ: Solving Problems Using the Pythagorean Theorem STA: CA A1.0 CA A1 4. KEY: Pythagorean Theorem right triangle radical expressions extended response rubric-based question 4
10 4. ANS: [4] Ê ˆ Ê ˆ Ê = ˆ definition of square = Use Foil. = Combine like radicals. = 4(5) (7) Simplify 5 and 49. = Multiply. = Add. [3] answer not in simplest radical form OR one computational error [] two computational errors. [1] more than two errors OR wrong sides used in equations PTS: 1 DIF: L3 OBJ: Simplifying Products and Quotients STA: CA A1.0 CA A1 5.0 TOP: 10-3 Example 4 KEY: FOIL radical expressions extended response rubric-based question 5
11 5. ANS: [4] 3x 1 = 4 3x = Ê ˆ 3x 3x = 3 3x = 9 = ( 3) x = 9 3 Check x = 3 3x 1 = 4 3(3 ) 1 = = = 4 4 3x 1 = 4 has no solution [3] no conclusion stated OR one computational error [] wrong procedure OR two computational errors [1] no work shown OR more than two computational errors PTS: 1 DIF: L3 REF: 10-4 Solving Radical Equations OBJ: Solving Equations With Extraneous Solutions STA: CA A1.0 CA A1 5. TOP: 10-4 Example 5 KEY: radical equation extraneous solutions solving equations extended response rubric-based question 6
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