Solutions to the Diffusion Equation L3 11/2/06

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Transcription:

Solutions to the Diffusion Equation 1

Solutions to Fick s Laws Fick s second law, isotropic one-dimensional diffusion, D independent of concentration "c "t = D "2 c "x 2 Figure removed due to copyright restrictions. See Figure 4.1 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter. Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891. Linear PDE; solution requires one initial condition and two boundary conditions. 2

Steady-State Diffusion When the concentration field is independent of time and D is independent of c, Fick s second law is reduced to Laplace s equation, " 2 c = 0 For simple geometries, such as permeation through a thin membrane, Laplace s equation can be solved by integration. 3

Examples of steady-state profiles (a) Diffusion through a flat plate Figure removed due to copyright restrictions. See Figure 5.1 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter. Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891. (b) Diffusion through a cylindrical shell Figure removed due to copyright restrictions. See Figure 5.2 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter. Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891. 4

Error function solution Interdiffusion in two semi-infinite bodies Figure removed due to copyright restrictions. See Figure 4.2 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter. Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891. Solution can be obtained by a scaling method that involves a single variable, " # x 4Dt ( ) = c c " # % $ x 4Dt & ( = c + )c ' 2 erf # x % $ 4Dt & ( ' 5

erf (x) is known as the error function and is defined by erf( x) " 2 x & e $% 2 d% # 0 An example: c( x < 0,0) = 0;c( x > 0,0) =1;c ("#,t) = 0; c (#,t ) =1; D =10 "16 t = 10 2, 10 3, 10 4, 10 5 Application to problems with fixed c at surface 6

Movie showing time dependence of erf solution 7

Superposition of solutions When the diffusion equation is linear, sums of solutions are also solutions. Here is an example that uses superposition of error-function solutions: Figure removed due to copyright restrictions. See Figure 4.4 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter. Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891. Two step functions, properly positioned, can be summed to give a solution for finite layer placed between two semi-infinite bodies. 8

Superposed error functions, cont d The two step functions (moved left/right by Δx/2): and their sum c left = c 0 2 c right = / c 0 2 ) # x + "x 2&, 1+ erf% ( * + $ 4Dt '-. ) # x / "x 2&, 1+ erf% ( * + $ 4Dt '-. c layer = c 0 2 * # x + "x 2& # erf% () erf x ) "x 2 &- % ( +, $ 4Dt ' $ 4Dt '. / 9

Superposed error functions, cont d An example: c ("#,t) = 0; c (#,t) = 0; c( x $ "%x /2,0) = 0;c ("%x /2 < x < %x /2) =1; c( x & %x /2,0) = 0;%x = 2 '10 "6 ; D =10 "16 t = 10 1, 10 3, 10 4, 10 5 Application to problems with zero-flux plane at surface x = 0 10

Movie showing time dependence of superimposed erf solutions 11

The thin-film solution The thin-film solution can be obtained from the previous example by looking at the case where Δx is very small compared to the diffusion distance, x, and the thin film is initially located at x = 0: c( x,t) = N 2 4"Dt e#x ( 4Dt) where N is the number of source atoms per unit area initially placed at x = 0. 12

Diffusion in finite geometries Time-dependent diffusion in finite bodies can soften be solved using the separation of variables technique, which in cartesian coordinates leads to trigonometric-series solutions. A solution of the form is sought. c( x, y, z,t) = X( x) "Y ( y) " Z( z) "T ( t) 13

Substitution into Fick s second law gives two ordinary-differential equations for onedimensional diffusion: dt dt = "#DT d 2 X dx 2 = "#X where λ is a constant determined from the boundary conditions. 14

Example: degassing a thin plate in a vacuum c( 0 < x < L,0) = c 0 ; c( 0,t) = c( L,t) = 0 The function X(x) turns out to be the Fourier series representation of the initial condition in this case, it is a Fourier sine-series representation of a constant, c 0 : with X n x ) * n=1 ( ) = a n sin % n" x $ L a n = 2c 0 L L # & ( ' $ sin n" # ' * & ) d# % L( 0 15

degassing a thin plate, cont d The function T(t) must have the form: T n t ( ) = T n exp " n2 # 2 & $ % L 2 ' Dt) ( and thus the solution is given by KoM Eq. 5.47: c( x,t) = 4c 0 " 0 1 j=0 * 1 # sin 2 j +1 2 j +1 ( )" x & # 2 j +1, $ % L '( exp %) + $ L 2 ( ) 2 " 2 &- Dt( / '. 16

degassing a thin plate, cont d Example: c( 0,t) = 0; c( L,t) = 0; c( 0 < x < L,0) =1 L =10 "5 ; D =10 "16 17

Other useful solution methods Estimation of diffusion distance from x " 4Dt Superposition of point-source solutions to get solutions for arbitrary initial conditions c(x,0) Method of Laplace transforms Useful for constant-flux boundary conditions, time-dependent boundary conditions Numerical methods Useful for complex geometries, D = D(c), timedependent boundary conditions, etc. 18