The Shallow Water Equations



Similar documents
Physics of the Atmosphere I

When the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid.

Mechanics 1: Conservation of Energy and Momentum

ATM 316: Dynamic Meteorology I Final Review, December 2014

Torque Analyses of a Sliding Ladder

Chapter 28 Fluid Dynamics

Differential Relations for Fluid Flow. Acceleration field of a fluid. The differential equation of mass conservation

Lecture 3. Turbulent fluxes and TKE budgets (Garratt, Ch 2)

du u U 0 U dy y b 0 b

3 Vorticity, Circulation and Potential Vorticity.

CBE 6333, R. Levicky 1 Differential Balance Equations

Figure 1.1 Vector A and Vector F

Scalars, Vectors and Tensors

Basic Equations, Boundary Conditions and Dimensionless Parameters

Let s first see how precession works in quantitative detail. The system is illustrated below: ...

Differential Balance Equations (DBE)

Review D: Potential Energy and the Conservation of Mechanical Energy

Chapter 15 Collision Theory

Lecture L22-2D Rigid Body Dynamics: Work and Energy

Chapter 5 MASS, BERNOULLI AND ENERGY EQUATIONS

Chapter 2. Derivation of the Equations of Open Channel Flow. 2.1 General Considerations

Chapter 6 Work and Energy

Gauss Formulation of the gravitational forces

1 The basic equations of fluid dynamics

Use the following information to deduce that the gravitational field strength at the surface of the Earth is approximately 10 N kg 1.

Work and Conservation of Energy

The Two-Body Problem

NUMERICAL ANALYSIS OF THE EFFECTS OF WIND ON BUILDING STRUCTURES

Chapter 4 Atmospheric Pressure and Wind

Conservation of Momentum and Energy

Contents. Microfluidics - Jens Ducrée Physics: Navier-Stokes Equation 1

Rotation: Moment of Inertia and Torque

APPLIED MATHEMATICS ADVANCED LEVEL

CHAPTER 6 WORK AND ENERGY

Halliday, Resnick & Walker Chapter 13. Gravitation. Physics 1A PHYS1121 Professor Michael Burton

State Newton's second law of motion for a particle, defining carefully each term used.

Chapter 10 Rotational Motion. Copyright 2009 Pearson Education, Inc.

v v ax v a x a v a v = = = Since F = ma, it follows that a = F/m. The mass of the arrow is unchanged, and ( )

D Alembert s principle and applications

Dynamics IV: Geostrophy SIO 210 Fall, 2014

Physics Notes Class 11 CHAPTER 6 WORK, ENERGY AND POWER

The derivation of the balance equations

Lecture 3 Fluid Dynamics and Balance Equa6ons for Reac6ng Flows

Orbits of the Lennard-Jones Potential

Linköping University Electronic Press

Vector Algebra II: Scalar and Vector Products

Chapter 11 Equilibrium

Sound. References: L.D. Landau & E.M. Lifshitz: Fluid Mechanics, Chapter VIII F. Shu: The Physics of Astrophysics, Vol. 2, Gas Dynamics, Chapter 8

Appendix 4-C. Open Channel Theory

Convection in water (an almost-incompressible fluid)

PEDAGOGY: THE BUBBLE ANALOGY AND THE DIFFERENCE BETWEEN GRAVITATIONAL FORCES AND ROCKET THRUST IN SPATIAL FLOW THEORIES OF GRAVITY *

ATMS 310 Jet Streams

Solution Derivations for Capa #11

PHYSICAL QUANTITIES AND UNITS

Physics 41 HW Set 1 Chapter 15

oil liquid water water liquid Answer, Key Homework 2 David McIntyre 1

Notes: Most of the material in this chapter is taken from Young and Freedman, Chap. 13.

Copyright 2011 Casa Software Ltd.

Halliday, Resnick & Walker Chapter 13. Gravitation. Physics 1A PHYS1121 Professor Michael Burton

Awell-known lecture demonstration1

Chapter 13 - Solutions

Ch 7 Kinetic Energy and Work. Question: 7 Problems: 3, 7, 11, 17, 23, 27, 35, 37, 41, 43

MODULE VII LARGE BODY WAVE DIFFRACTION

8.2 Elastic Strain Energy

Lab #4 - Linear Impulse and Momentum

8. Potential Energy and Conservation of Energy Potential Energy: When an object has potential to have work done on it, it is said to have potential

11.1. Objectives. Component Form of a Vector. Component Form of a Vector. Component Form of a Vector. Vectors and the Geometry of Space

Lecture 17. Last time we saw that the rotational analog of Newton s 2nd Law is

2.016 Hydrodynamics Reading # Hydrodynamics Prof. A.H. Techet

Displacement (x) Velocity (v) Acceleration (a) x = f(t) differentiate v = dx Acceleration Velocity (v) Displacement x

Proof of the conservation of momentum and kinetic energy

Sample Questions for the AP Physics 1 Exam

Practice final for Basic Physics spring 2005 answers on the last page Name: Date:

Interactive simulation of an ash cloud of the volcano Grímsvötn

Physics Midterm Review Packet January 2010

Copyright 2011 Casa Software Ltd. Centre of Mass

Gravitational Potential Energy

Physics 9e/Cutnell. correlated to the. College Board AP Physics 1 Course Objectives

3. KINEMATICS IN TWO DIMENSIONS; VECTORS.

Chapter 8: Potential Energy and Conservation of Energy. Work and kinetic energy are energies of motion.

Description of zero-buoyancy entraining plume model

Orbital Mechanics. Angular Momentum

Lecture 4: Pressure and Wind

Salem Community College Course Syllabus. Course Title: Physics I. Course Code: PHY 101. Lecture Hours: 2 Laboratory Hours: 4 Credits: 4

Fluid Mechanics Prof. S. K. Som Department of Mechanical Engineering Indian Institute of Technology, Kharagpur

Open channel flow Basic principle

Chapter 6. Work and Energy

Physics 1A Lecture 10C

Physical Quantities and Units

6 J - vector electric current density (A/m2 )

Chapter 3: Weather Map. Weather Maps. The Station Model. Weather Map on 7/7/2005 4/29/2011

Lecture 17, Wind and Turbulence, Part 2, Surface Boundary Layer: Theory and Principles

So if ω 0 increases 3-fold, the stopping angle increases 3 2 = 9-fold.

For Water to Move a driving force is needed

CONSERVATION LAWS. See Figures 2 and 1.

CHAPTER 9 CHANNELS APPENDIX A. Hydraulic Design Equations for Open Channel Flow

Theory of electrons and positrons

Time dependence in quantum mechanics Notes on Quantum Mechanics

Conservation of Energy Physics Lab VI

Chapter 07 Test A. Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question.

Transcription:

Copyright 2006, David A. Randall Revised Thu, 6 Jul 06, 5:2:38 The Shallow Water Equations David A. Randall Department of Atmospheric Science Colorado State University, Fort Collins, Colorado 80523. A derivation of the shallow water equations The shallow water equations are the simplest form of the equations of motion that can be used to describe the horizontal structure of an atmosphere. They describe the evolution of an incompressible fluid in response to gravitational and rotational accelerations. The solutions of the shallow water equations represent many types of motion, including Rossby waves and inertia-gravity waves. In these notes, we begin with a more complete version of the equations of motion, and simplify to obtain the shallow water equations. Ignoring the effects of friction, the momentum equation is rk Å Du + f k ävo = - p - rgk. () Here r is the density of the air, u is the three-dimensional velocity vector, the total derivative operator DH L ê is defined by DH L ÅÅÅÅÅ ª H L + Hu ÿ L H L, (2) f is the coriolis parameter, k is a unit vector pointing away from the center of the planet, v is the horizontal velocity vector, W is the angular velocity vector associated with the planet s rotation, p is pressure, and g is the magnitude of the acceleration vector due to the planet s gravity. In writing (), we have adopted traditional approximations appropriate to an atmosphere whose depth is shallow compared with the radius of the planet. The continuity equation is r Å + ÿ HruL = 0 ; (3)

2 D. A. Randall it can also be written as Dr ÅÅ + r ÿ u = 0. (4) We now show how () and (4) can be simplified to obtain the shallow water equations. It is convenient to partition pressure and density into equilibrium and departures from equilibrium values. That is, p = p 0 HzL + p Hx, y, z, tl, and r = r 0 HzL + r Hx, y, z, tl. (5) The equilibrium pressure p 0 HzL and the equilibrium density r 0 HzL are defined in such a way that they satisfy the hydrostatic equation d p 0 ÅÅÅÅ d z = -g r 0. (6) Substituting (5) into the momentum equation (), and using (6), we obtain the momentum equation in the form r K Å Du + f k ävo = - p - r gk. (7) The full density still appears on the left-hand side of (7); no approximations have been made in passing from () to (7). On the right-hand side of (7), we see a buoyancy term, which is the product of the perturbation density and the acceleration due to gravity. Now we assume that the fluid is incompressible, that is, r = r 0 is a constant and r = 0. Water is nearly incompressible, and the name shallow water equations comes partly from the use of this incompressibility assumption. For an incompressible fluid, the three-dimensional momentum equation, (7), can be simplified to rk Å Du + 2 W ävo = - p. (8) In addition, the mass conservation equation, (4), reduces to ÿ u = 0. (9) Equations (8) and (9) apply at each point in the three-dimensional fluid. Now we begin to consider how to describe the vertically integrated circulation. We assume that the effects of vertical shear of the horizontal velocity are negligible. Such effects would arise, for example, through the vertical advection of horizontal momentum. The shallow no-shear water equations assumption is reasonable if the fluid is shallow, and this partly accounts for the name shallow water equations.

Revised 7/6/06 5:2:38 3 Now we begin to consider how to describe the vertically integrated circulation. We assume that the effects of vertical shear of the horizontal velocity are negligible. Such effects would arise, for example, through the vertical advection of horizontal momentum. The no-shear assumption is reasonable if the fluid is shallow, and this partly accounts for the name shallow water equations. The next step is to find the form of the horizontal pressure gradient force acting on the shallow, incompressible fluid. Supposed that there exists a free surface of constant or nearly constant pressure, which is also a material surface in the sense that no mass crosses it. This is analogous, for example, to the surface of the ocean. Let h f Hx, y, tl be the height of a this free surface. Let h S Hx, yl be the height of the surface topography and let h * = h f - h S be the depth of the fluid. As mentioned above, we assume that no fluid crosses the free surface. It follows that the height of a parcel embedded in the free surface satisfies Dh f ÅÅÅÅ = whx, y, h f, tl. (0) Similarly, no fluid can cross the lower boundary, so the fluid motion there must follow the topography: Dh S ÅÅÅÅ = w S, () or h S ÅÅÅ + v ÿ h S - w S = 0. (2) When the topographic height is independent of time, we obtain w S Hx, y, h S, tl = v ÿ h S. (3) Using our assumption that the density is constant, and integrating the hydrostatic equation from some arbitrary depth z within the fluid up to the free surface gives phx, y, z, tl - phx, y, h f, tl = -g rhh f - zl. (4) As an upper boundary condition, we have phx, y, h f, tl = p f. (5) D. A. Randall Selected Papers

4 D. A. Randall It follows that p = g rhh f - zl + p f. (6) So, since p = -g rz + p Hx, y, z, tl, we obtain p = g rh f + p f and p = g r 0 h f. (7) Here we have assumed that p f is horizontally uniform. Using (7), we can now write the horizontal momentum equation as Dv ÅÅ + f käv = -g h f. (8) Since we have assumed no vertical shear, this equation applies at any height within the fluid, but the range of heights in question is presumably small since the fluid is shallow. Equation (8) is the form of the momentum equation for the shallow water system. Using the vector identity Hv ÿ L v = @Hv ÿ vl ê 2D + H ävl äv, we can rewrite the momentum equation (8) as v Å Hz + f L k ä v = Igh f. (9) Here K ª v ÿ v ÅÅÅ 2 (20) is the kinetic energy per unit mass, and z = k ÿ H ävl (2) is the relative vorticity. Since the horizontal velocity is independent of z, we can easily integrate the continuity equation, (9), with respect to z, from z = h S to z = h f, to obtain whx, y, h f, tl - w S Hx, y, h S tl = -Hh f - h S L ÿ v. (22) where ÿ v is the horizontal divergence. Substitute (20) and (2) into (22), to obtain Hh f - h S L + ÿ @vhh f - h S LD = 0, (23) The shallow water equations

Revised 7/6/06 5:2:38 5 or, with h * = h f - h S, h* + ÿ Hvh * L = 0. (24) This is the continuity equation for the shallow water system. 2. The vorticity and divergence equations for shallow water The absolute vorticity is the sum of the relative and planetary vorticity, i.e., h ª z + f. (25) The vorticity equation can be derived by applying the operator k ÿ ä to (9): z Å = k ÿ C ä v Å G = k ÿ äc-h Kk äv O - Igh f G = -k ÿ äch Kk äv OG - k ÿ A ä Igh f E = -k ÿ ä@h Hk äv LD = -k ÿ ; h äkk ävo + h C äkk ävog? (26) = -k ÿ CHv ÿ h L - vk h ÿ kog -k ÿ ;h Hv ÿ L k - Kk ÿ O v + kh ÿ vl - vk ÿ ko? = -Hv ÿ h L - h H ÿ vl = - ÿ Hh vl. Because the coriolis parameter does not depend on time, we can write h ê = z ê. Then (26) can be re-written as h Å = - ÿ Hh vl. (27) One of the conclusions that can be drawn from (27) is that if there is no absolute vorticity in the fluid at a certain time, then none will ever form. A purely divergent flow (in the absence of planetary rotation) will remain purely divergent forever, within the framework D. A. Randall Selected Papers considered here.

6 D. A. Randall One of the conclusions that can be drawn from (27) is that if there is no absolute vorticity in the fluid at a certain time, then none will ever form. A purely divergent flow (in the absence of planetary rotation) will remain purely divergent forever, within the framework considered here. The divergence is defined by d ª ÿ v. (28) The divergence equation can be derived from the momentum equation, as follows: d Å = ÿ v = ÿ C-h Kk ävo - Ig h f G = - ÿ Ch Kk ävo - 2 Igh f G = -C h ÿ Kk ävo + h ÿ Kk ävog - 2 Igh f = -; h ÿ Kk ävo + h Cv ÿ K äko - k ÿ H ävlg? - 2 Igh f (29) = h k ÿ H ävl - h ÿ Kk ävo - 2 Igh f = h k ÿ H ävl + h ÿ Kv äko - 2 Igh f = h k ÿ H ävl + k ÿ H h ävl - 2 Igh f = k ÿ @ h äv + h H ävld - 2 Igh f = k ÿ ähh vl - 2 Igh f The shallow water equations

Revised 7/6/06 5:2:38 7 3. Expressing the shallow water equations in terms of the stream function and velocity potential Helmholtz s Theorem states that any vector field V can be separated into rotational and divergent parts, i.e., V = y + V c, where ÿ V y = 0 and ä V c = 0. If the vector field is the horizontal wind, we can define a stream function, y, to express the rotational part, k ä y, and a velocity potential, c, to express the divergent part, c, i.e., v = k ä y + c. (30) The conservation equation for absolute vorticity is can be rewritten in terms of the stream function and velocity potential, as follows: h Å = - ÿ Hh vl = - ÿ Ch Kk ä y + cog = - ÿ Ch Kk ä yog - ÿ Hh cl (3) = - ÿ Hh cl - h ÿ Kk ä yo - h ÿ Kk ä yo = - ÿ Hh cl + k ÿ H h ä yl. For arbitrary scalar functions A and B, define the Jacobian operator JHA, BL by: JHA, BL ª k ÿ H A ä BL. (32) Then we can rewrite (3) as h Å = - ÿ Hh cl + JHh, yl. (33) The divergence equation can be re-written in terms of the stream function and velocity potential as follows: d Å = k ÿ ä Hh vl - 2 Igh f = k ÿ äch Kk ä y + cog - 2 Igh f D. A. Randall Selected Papers

8 = k ÿ äch Kk ä y + cog - 2 D. A. Randall Igh f = k ÿ äch Kk ä yo + h cg - 2 Igh f = k ÿ äch Kk ä yog + k ÿ ä Hh cl - 2 Igh f = k ÿ ; h ä Kk ä yo + h C äkk ä yog? +k ÿ @ h ä c + h H ä cld - 2 Igh f = k ÿ CkH y ÿ h L - yk h ÿ kog +k ÿ ;h CkH ÿ cl - ck ÿ ko Kk ÿ O y + H y ÿ L kg? +k ÿ H h ÿ cl - 2 Igh f = y ÿ h + h 2 y + JHh, cl - 2 Igh f = ÿ Hh yl + JHh, cl - 2 Igh f. The kinetic energy per unit mass, K, which appears in (34), can be expressed in terms of the stream function and velocity potential, as follows: K = v ÿ v ÅÅÅ 2 = ÅÅÅÅÅ CKk ä y + co ÿ Kk ä y + cog 2 = ÅÅÅÅÅ CKk ä yo ÿ Kk ä yo + Kk ä co ÿ c 2 + c ÿ Kk ä yo + c ÿ cg = ÅÅÅÅÅ 2 CKk ä yo ÿ Kk ä yo + ÿ H c cl - c 2 cg + c ÿ Kk ä yo (35) The shallow water equations

Revised 7/6/06 5:2:39 9 = ÅÅÅÅÅ 2 CCKk ä yoäkg ÿ y + ÿ H c cl - c 2 cg + k ÿ H y ä cl = ÅÅÅÅÅ 2 C-Ck äkk ä yog ÿ y + ÿ H c cl - c 2 cg - JHy, cl = ÅÅÅÅÅ 2 C-CkK y ÿ ko - ykk ÿ kog ÿ y + ÿ H c cl - c 2 cg - JHy, cl = ÅÅÅÅÅ 2 A y ÿ y + ÿ H c cl - c 2 ce - J Hy, cl = ÅÅÅÅÅ 2 9A ÿ Hy yl - y 2 ye + ÿ H c cl - c 2 c= - JHy, cl. The Jacobian term of (35) mixes the rotational and divergent flow fields. We can show, however, that the integral of the Jacobian over a closed or periodic domain vanishes. This means that the total (volume-integrated, but not mass-weighted) kinetic energy can be expressed in terms of two cleanly separated contributions: a rotational part, and a divergent part. Finally, the continuity equation can be rewritten in terms of the stream function and velocity potential as follows: h* = - ÿ Hh * vl = - ÿ Ch * Kk ä y + cog = - ÿ Ch * Kk ä yog - ÿ Hh * cl (36) = - ÿ Hh * cl - Ch * ÿ Kk ä yo + h * ÿ Kk ä yog = - ÿ Hh * cl + k ÿ H h * ä yl = - ÿ Hh * cl + JHh *, yl. (35) D. A. Randall Selected Papers

0 D. A. Randall 4. Potential vorticity and potential enstrophy We repeat here for convenience the mass conservation equation [see (24)], i.e., h* + ÿ Hh * vl = 0, (37) and the vorticity conservation equation [see (38)], i.e., h Å + ÿ Hh vl = 0. (38) It is interesting that these two equations have exactly the same form. This seems to say that vorticity is somehow like mass We define the potential vorticity by q ª h h *. (39) Then (39) is immediately equivalent to Hh* ql + ÿ @Hh * vl qd = 0 (40) which expresses conservation of potential vorticity in flux form. The corresponding advective form can be obtained by subtracting q ä (24) from (40). The result is q Å + Hv ÿ L q = 0, (4) which says that q is conserved following a particle. Of course, this implies that any function of q is also conserved. In particular, ÅÅÅÅ 2 q2 is conserved. This quantity is called the potential enstrophy. We easily find that K ÅÅÅÅÅ 2 q2 O + Hv ÿ L K ÅÅÅÅÅ 2 q2 O = 0 (42) from which it follows that Ch* K ÅÅÅÅÅ 2 q2 OG + ÿ Ch * vk ÅÅÅÅÅ 2 q2 OG = 0. (43) The shallow water equations

Revised 7/6/06 5:2:39 5. Energy conservation The kinetic energy equation can be derived by taking v ÿ (9), to obtain K Å + v ÿ K + v ÿ @ghh S + h * LD = 0. (44) The last term of (44) represents conversion between kinetic and potential energy. We have used h f = h S + h *. We can convert the kinetic energy equation to flux form: Hh* KL + ÿ Hv h * KL + h * v ÿ @ghh S + h * LD = 0. (45) The potential energy equation can be derived by multiplying (25) by ghh S + h * L, to obtain Ch* Kgh S + ÅÅÅÅÅ 2 h* OG + ghh S + h * L ÿ Hv h * L = 0. (46) This can be rewritten as Ch* Kgh S + ÅÅÅÅÅ 2 h* OG + ÿ @v h * ghh S + h * LD - h * v ÿ @ghh S + h * LD = 0. (47) The last term represents conversion between kinetic and potential energy. If we add (45) and (47), we get ;h* CK + Kgh S + ÅÅÅÅÅ 2 h* OG? + ÿ 8v h * @K + ghh S + h * LD< = 0. (48) This expresses total energy conservation. D. A. Randall Selected Papers