-- --.. CALCULATION REIEW AND APPROAL NUCLEAR POWER DEPARTMENT Calculation # Number of--pages Title of Calculation: 9e r o L y-, e -Sni& 1: g Origal calculation Q Revised calculation. Revision # O Supersedg calculation. Supersedes calculation # Modification # Other References: Description: Prepared By: IDate: '-t-i( This calculation has been reviewed accordance with QP 3-6. The review was accomplished by one or a combation of the followg (as checked): A review of a representative -3 A detailed review of the sample of repetitive calculca- origal calculation tions A review of the calculation agast a similar calculation previously performed A review by an alternate, simplified or approximate method of calculation Comments: Reviewed By: C Q ate: Dt:Ar~voved 1 a7 'Date-. Form QP 3-6.1 Rev. 0
"-irpose: 'A The purpose of this calculation is to determe the system characteristics for the auxiliary feed pump mi-recirc system. This calc will address pumps P38A & B only. In addition, this calc will determe the equivalent (resistance coefficient) values for the recirc le to the CST. References: 1. Byron Jackson Pump Curve T-30944 and T-30945 for pumps P38A & B respectively.. Crane Technical paper No. 410 3. Letter from Byron Jackson Pumps to WE dated August required mi-recirc flows for the AFW pumps. 4. WE Dwg M-17 rev 4 5. Copes-ulcan Dwg D-166085 rev 9 Rockwell-Edwards Dwg C-46459 rev 5 6. Purchase Order No. 184514 7,1989 regardg 7. Bechtel Dwgs: P-103 rev 7 P-l18 rev 5 P-117 rev 5 M-34 rev 8 M-35 rev 6 M-37 rev 6 Assumptions: 1. Calculation is based on the longest run of system pipg which, by spection is from the P9 aux feedwater pump. Inputs: TDH := 119 psig den := 6.4 lb/ft-3 Q := 70 gpm DISCHARGE LINE: " le fo: P38 head (psig) @ 00 gpm Density of water Required mi recirc flow Schedule 80: d80 := 1.939 Inside dia of " sch 80 pipe
-nt ":=.5 Recirc le pipe entrance / I-A I C :=60 Check valve flow coefficient (full) 7 chk C :=33 Control valve flow coefficient (full) cont f :=.019 Friction factor for " fully turbulent / := 340-f = 6.46 1500 f, " globe valve Ref pg. A-7,/ glb glb Note: is based on sch 160 pipe := 14"f " 90 degree elbow ) A,5[.=..5 '.5 Determe flow meter orifice characteristics:. Typically, B should be the range of 0.5 to 0.75 d := 1.375 Selected orifice diameter / 0 d 0 B := d80 B = 0.709 v/ Q. den RE := 50.6. 4 d80.1. RE = 9.499-10 C :=.705 " schedule 40: Ref Crane Eqn 3-3 Fe cm o-s- 4 c L n'3 ' - ;c ~ Ref Crane Pg A-( 4 P c ;5 x LZ d40 :=.067 Inside dia of " sch 40 pipe 3" schedule 10: d310 := 3.6 Inside dia of 3" sch 10 pipe f3 :=.018 := f3-8 3gate := f3.50 3chk := f3"0 ",.3r Friction factor for 3" fully turbulent/ 3" gate valve 3" check valve 3x3 tee flow thru run
3x3r := 14-f3 390 3x reducer: [3.57 e := -atan[0.66 / 3" 90 elbow I/ B := d40 d310 B = 0.634 3x = 1.066 enlargement 7 3X 4" schedule 10: 4 B d410 := 4.6 diameter of 4 " sch 101 f4 :=.017 friction factor for 4" le := f4-14 490 4" 90 elbow 1, 4" schedule 80: d480 := 3.86 diameter of 4" sch 80 le 6" schedule 10: d610 := 6.357 f6 :=.015 diameter of 6" sch 10 le / friction factor for 6" le / := 0-f6 6x6r Flow thru tee 6x6 L7 := 60-f6 6x6b := 8-f6 6gate := f6-50 6chk := 14-f6 690 Flow thru branch tee 6x6 6" gate valve.7 6" check valve / 6" 90 elbow
-xit := I Exit loss It /I 6x3 reducer: E "= Latan [].5 / d3 10 d610 /.6- [1ii-B 6x3 L J 6x3 = 0.383 enlargement 1 6x4 reducer: e -atanei"05 4.6 B -61 d610 6x4.8- [s[~] 1 ] 4 B Contraction / 10" le fo: dlolo := 10.4 diameter of 10" sch 10 le / flo :=.014 friction factor for i0" le
S := f10.8 10gate 1090 1045 10xl0b 10x6b fl0-14 :=fo.8 flo060 :=f6-60 10" gate valve L7 10" 90 elbow 10" 45 elbow LI-e 1OxlO tee branch flow 10x6 tee branch flow 5- /q, Calculation: pipe loss function: DP(f,L,v,d) :=.00194-f-L-dend Ref Crane 410 eqn 3-5 * velocity function: v(d) := Q d.].7.48.60 Z fittg loss function: DPF(,v) :=.0001078.-den~v Ref Crane 410 eqn 3-14 equivalent resistance coefficient function:.d 4 (dpt,d,q) := dpt- Ref Crane 410 eqn 3-14.00001799-den-q Calculate the pressure loss from the AFW pump discharge to the mi-recirc le tie-: pipg:
v480 := v(d480) U fittgs: 1 := DP(f4,,v480,d480) := 3- tot 490 1 = 0.03 = DPF[ Ntot,v4801 = 0.018 Calculate losses from the mi-recirc le entrance to globe valve: pipe loss: v80 := v(d80) v80 = 7.606 fittgs: 3 := DP(f,10,v80,d80) = 0.458 3 valves: := + I- tot ent 90 4 := DPF[ot,v801 control valve: = 0.766 L/ tot = 0.98 4 5:[Cc 5 kont I = 4.5 5 check valve: dip 6[] Qch 6 = 1. 361 J globe valve: := DPF[,v801 =.514
7 L[gb J 7 restrictg orifice: := 948- [-O] 8 L7]o = 948 8 Flow meter orifice: - := den 9 36-d Calculate pressure loss from globe valve to 3x reducer: = 3.09 9 pipg: v40 := v(d40) v40 = 6.693 X 10 DP(f,6,v40,d40) 0.865 10 fittgs: := + tot 90 3X l := DPFtot,v40] = 0.48 Calculate pressure loss from 3x reducer to 3x6 reducer: pipg: v310 : v(d310) v310 =.691 1 fittgs/valves: := DP(f3,157,v310,d310) :=7- + + 3- + + tot 390 6x3 3x3r 3gate = 0.507 1 3 chk
DPFv310 [ =0.081 ' Calculate pressure loss from 3x6 reducer to condensate storage tank: pipg: v610 := v(d610) v610 = 0.708 := DP(f6,6,v610,d610) = 0.00 14 14 fittgs/valves: :=- + + + + tot 690 6x6b 6x6r exit 6gate :=DPF,v6l0 =0. 009 15 Ntot 0J 15 Calculate suction pipg pressure loss from condensate storage tank to 10x6 tee: pipg: pplg := v(dl010) vl010 = 0.63 / := DP(flO,156,vlO1O,dlOlO) = 0.001 16 16 fittgs/valves: 7 := + 6- + 3- + + - + tot 10gate 1090 1045 ent 10xlOb 10x6b 17 := DPFot,v1010] 17 = 0.00 Calculate suction pipg pressure loss from lox6 tee to 4" 90 elbow: pipg: / = 0.003 / := DP(f6,7,v610,d610) 18 18 fittgs/valves: := + + 4- + + tot 6gate 6chk- 690 6x6b 6: x4 19 := DPF ot,v6101 19 = 0.01 1 Calculate suction pipg pressure loss due to 4" 90 elbow: fittg: 410 := v(d410) v410 = 1.576 I/
DPF F 4101 0 o.004/ Sum the for the system: Z = 96.36 psi / 34.0 11 R Comparg thi value to the pump curve would dicate that the pump is delivergý5;gpm which is greater than the tial assumed flow rate of 70 gpm. Therfore, it is necessary to re-iterate by adjustg the flow rate until SYSTEM = Pump TDH. Trial i 1 3 Q 70 8 80 System 4 FT 305 FT 904 FT Pump TDH 3000 FT 998 FT 998 FT 7 7- Acceptable Calculate equivalent values for the recirc le only based on 80 gpm: 1 := [ + 4 + + + + +,d80,80] 3 1 = 1.889 10 " := [I0 +, d40,801 = 3.4