Lecture 1-2: Properties of the Solar System
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1 Lecture 1-2: Prperties f the Slar System Tpics in this lecture: Planetary rbits Mass distributin Angular mmentum distributin Lecture 1-2: Prperties f the slar system
2 Prperties f the Slar System 1. Planets rbit rughly in the ecliptic plane. 2. Planetary rbits are slightly elliptical, and very nearly circular. 3. Planets and Sun revlve and rbit in a west-t-east directin. The planets bliquity (tilt f rtatin axes t their rbits) are small. Uranus and Venus are exceptins. 4. The planets differ in cmpsitin. Their cmpsitin varies rughly with distance frm the Sun: dense, metal-rich planets are in the inner part and giant, hydrgen-rich planets are in the uter part. 5. Meterites differ in chemical and gelgic prperties frm the planets and the Mn. 6. The rtatin rates f the planets and asterids are similar (5 t 15 hurs). 7. Planet distances frm the Sun bey Bde's law. 8. Planet-satellite systems resemble the slar system. 9. The Ort Clud and Edgewrth-Kuiper Belt f cmets. 10. Planets cntain ~99% f the slar system's AM but Sun cntains >99% f slar system's mass. Lecture 1-2: Prperties f the slar system
3 Orbits f the planets Planets mves arund the Sun in an rbit effected by the Sun s mass, and t a less extent, by ther bdies in the Slar System. Laws gverning planetary mtin was frmulated by Jhannes Kepler and based n Tych Brahe s bservatins. Kepler s Laws: 1. Planets have elliptical rbits with the Sun at ne fcus. 2. As a planet rbits, a line cnnecting the planet t the Sun sweeps ut equal areas in equal times. 3. The square f the rbital perid is prprtinal t the cube f the semimajr axis f the rbit. Lecture 1-2: Prperties f the slar system
4 Orbits f Planets Frm Physical Prcesses in the Slar System by J. Landstreet Lecture 1-2: Prperties f the slar system
5 Planetary Prperties Lecture 1-2: Prperties f the slar system
6 Helisphere (>100 AU frm Sun) Lecture 1-2: Prperties f the slar system
7 Kepler s 1 st Law: Law f Orbits Planets have elliptical rbits with the Sun at ne fcus. Equatin f ellipse: r + r = 2 a a is semimajr axis, b is semiminr axis f ellipse, F and F are fcal pint. Distance f fcus frm ellipse centre is a e, where e is the eccentricity: e = 0 => circle 0 < e < 1 => ellipse e = 1 => parabla e > 1 => hyperbla Lecture 1-2: Prperties f the slar system
8 Kepler s 1 st Law (cnt.) Implies that a planet s distance frm the Sun varies during its rbit. Clsest pint t Sun: perihelin. Farthest pint frm Sun: aphelin. Average f perihelin and aphelin is called the semimajr axis. Lecture 1-2: Prperties f the slar system
9 Elliptical rbits Cnsider a pint at either end f the semiminr axis where r = r. Using the Pythagrean Therem, r 2 = b 2 + (ae) 2 Setting r = a, we may write: a 2 = b 2 + a 2 e 2 => b 2 = a 2 (1 - e 2 ) r Relates semiminr axis t eccentricity and the semimajr axis. Lecture 1-2: Prperties f the slar system
10 Elliptical rbital path Frm figure belw, r 2 =r 2 sin 2 θ + (2ae + rcsθ) 2 Eqn 1 But as r + r = 2a r r = 2a - r, we may write r 2 = 4a 2-4ra + r 2 Eqn 2 Equating the RHS f Eqns 1 and 2: 4a 2-4ra + r 2 = r 2 sin 2 θ + (2ae + rcsθ) 2 = r 2 (sin 2 θ +cs 2 θ) + 4a 2 e 2 + 4aer csθ As sin 2 θ +cs 2 θ = 1 =>4a 2-4ra = 4a 2 e 2 + 4aer csθ Rearranging gives, r(θ) = a(1 e2 ) 1+ ecsθ Eqn 3 Fr 0<e<1, this is the equatin f an ellipse in plar crdinates. Lecture 1-2: Prperties f the slar system
11 Perihelin and aphelin distances If θ = 0, cs θ = 1 and r = a(1 e2 ) 1+ e The planet is at perihelin, the clsest pint t the Sun. = r = a(1 e) a(1 e)(1+ e) (1+ e) θ = 180 θ θ = 0 If θ = 180, cs θ = -1 and r = a(1 e2 ) 1 e = r = a(1+ e) a(1 e)(1+ e) (1 e) The planet at the aphelin, the mst distant pint frm the Sun. Example: The semimajr axis f Mars is AU and the eccentricity is What is the distance f Mars at perihelin? r = a(1-e) = ( ) = AU What is the distance f Mars at aphelin? Lecture 1-2: Prperties f the slar system
12 Kepler s 2 nd Law: Law f areas As a planet rbits, a line cnnecting the planet t the Sun sweeps ut equal areas in equal times. da dt = cnst => Planet mvies faster at perihelin. Lecture 1-2: Prperties f the slar system
13 Kepler s 2 nd Law: Law f areas Angular mmentum f planet: L = r p = m (r v). During Δt, radius vectr sweeps thrugh Δθ = v t Δt / r, where v t is the cmpnent f v perpendicular t r. During this time, the radius vectr has swept ut the triangle, f area A = rv t Δt / 2. As Δt - > 0, da/dt = rv t / 2 = 1 2 r 2 (dθ/dt). Nw, the magnitude f L is given by L = m v t r= m r 2 dθ/dt. F Δθ r ΔA v t v r v => da/dt = L / 2m = cnst i.e. the rate f sweeping ut area is a cnstant. Lecture 1-2: Prperties f the slar system
14 Kepler s 3 rd Law: Law f Perids The square f the rbital perid is prprtinal t the cube f the semimajr axis f the rbit: P 2 ~ a 3 P is the perid measured in years and a is the semimajr axis in AU. Cnsider m 1 and m 2 rbiting at r 1 and r 2. Bth cmplete ne rbit in perid P. Frces due t centripetal acceleratins are: F 1 = m 1 v 1 2 / r 1 = 4 π 2 m 1 r 1 / P 2 F 2 = m 1 v 2 2 / r 2 = 4 π 2 m 2 r 2 / P 2 r 1 r 2 v 2 using v = 2πr / P v 1 m 1 COM a m 2 Lecture 1-2: Prperties f the slar system
15 Kepler s 3 rd Law: Law f Perids As F 1 = F 2 => r 1 / r 2 = m 2 / m 1 (mre massive bdy rbits clser t centre f mass). r 1 r 2 v 2 m 1 Separatin f the bdies is a = r 1 + r 2, and r 1 = m 2 a / (m 1 + m 2 ) v 1 COM a m 2 Cmbining with F 1 and F = F 1 = F 2 = Gm 1 m 2 /a 2 : P 2 = 4 π 2 a 3 / G(m 1 + m 2 ) As M sun (= m 1 ) >> m planet (=m 2 ), cnst = 4 π 2 / GM Sun. Lecture 1-2: Prperties f the slar system
16 Bde s Law Empirical predictin f planet distances frm Sun. Begin with: 0, 3, 6, 12, 24, 48, 96, 192, 384 Planet Distance (AU) Mercury Bde s Law (AU) Nw add 4: 4, 7, 10, 16, 28, 52, 100, 196, 388 Then divide by 10: 0.4, 0.7, 1.0, 1.6, 2.8, 5.2, 10.0, 19.6, 38.8 Sequence is clse t mean distances f planets frm the Sun. Venus Earth Mars Ceres Jupiter Bde s Law r Titus-Bde s Law: r n = n Saturn Uranus Lecture 1-2: Prperties f the slar system
17 Bde s Law (cnt.) r n = n n Planet Mercury Venus Earth Mars Ceres Jupiter Saturn Uranus s-m axis r n Lecture 1-2: Prperties f the slar system
18 Bde s Law (cnt.) Law lead Bde t predict existence f anther planet between Mars and Jupiter - asterids belt later fund. Uranus fitted law when discvered. Neptune was discvered in 1846 at the psitin predicted by Adams, t explain the deviatin f Uranus frm its predicted rbit. Plut s rbit when discvered in 1930 did nt fit the relatin. Nt a planet anymre! Planet Distance (AU) r n (AU) Uranus Neptune Plut Lecture 1-2: Prperties f the slar system
19 The Slar System t scale Lecture 1-2: Prperties f the slar system
20 Mass distributin The density f a planet is measured in g cm -3 (cgs units). Cnvenient because the density f water is 1 g cm -3. T determine vlume, need: Mass Density = Vlume 1. Distance frm Earth. 2. Angular extent f the planet. T determine the mass (frm Kepler s 3 rd Law) we need: 1. Mean Sun-planet separatin. 2. Orbital perid. Lecture 1-2: Prperties f the slar system
21 Mass Distributin (cnt.) The vlume is determined frm: V = 4/3 π R 3 where 2R = 2πdθ / 360. θ d 2R Mass determined frm Newtn s frm f Kepler s 3 rd Law: P 2 = 4 π 2 a 3 / G (m + M ) => m = ( 4 π 2 a 3 / G P 2 ) - M ρ = m / V g cm -3 Cmpare t: Crk: 0.2 Wd: 0.5 Water: 1.0 Basalt: 3.3 Lead: 11.0 Gld: 19.0 Lecture 1-2: Prperties f the slar system
22 Prperties f the planets Frm cnsideratin f size and density, can divide the planets int tw categries: 1. Terrestrial Planets Small size, high density and in the inner slar system. Mercury, Venus, Earth, Mars. 2. Jvian Planets Large size, lw density and in uter slar system: Jupiter, Saturn, Uranus, Neptune. Plut Plut is in categry f wn. It has small size and lw density. Lecture 1-2: Prperties f the slar system
23 Cmpressin vs. cmpsitin: The inner planets Frm their densities, inner planets likely t be cmpsed f rck and sme metal in cres. Might expect that planets less massive than the Earth wuld have lesser densities, because they are less cmpressed at the center by gravity. Amngst the terrestrial planets, this is true fr bth Mars and the Mn, which are bth smaller and less dense than the Earth. Venus is rughly the same size and density as Earth. But, Mercury is bth less massive and mre dense than the Earth. => Has Mercury a different cmpsitin than the Earth? Lecture 1-2: Prperties f the slar system
24 Cmpressin vs. cmpsitin: The uter planets What abut the densities f the uter planets? Might expect the uter planets, which are very massive, t be much mre cmpressed than the inner planets, and s mre dense. In fact, these heavier bdies are less dense than the inner, terrestrial planets. The nly cmpsitin which we can use t cnstruct such massive bdies with such lw densities is a mixture f hydrgen and helium, the tw lightest elements. The cmpsitin f the uter planets is hence mre similar t the Sun and stars than t the inner planets. Lecture 1-2: Prperties f the slar system
25 Angular mmentum distributin The Sun has a relatively slw rtatinal perid f ~26-days. => Like mst G-, K- and M-class stars. The rbital AM is: h rb = mvr = 2πmr 2 /P (r = distance) The spin AM f a inhmgeneus nnspherical rtating bdy is mre difficult t evaluate. The mass f the bdy is 4πρ ave R 3 /3, where R is the radius and ρ ave is the mean density. Lecture 1-2: Prperties f the slar system
26 Angular mmentum f the Sun An average density adpted fr Sun and it is assumed that mass is mstly within 0.6R. This is 0.72 fr a perfect sphere, but the Sun is blate. Mean density = 1.41 g cm -3 Mass = 2 x g Perid at equatr = 26.5 days = s Radius = 6.96 x cm The spin AM is therefre: h Sun = mvr = 4πρR3 3 2πr P R Setting R = 0.6R => Detailed mdelling gives ~1.7 x g cm 2 s -1. h Sun = mvr = 4πρ 2π 3 P (0.6R)5 =1.9ρR 5 /P = g cm 2 s 1 Lecture 1-2: Prperties f the slar system
27 Angular mmentum f the planets The rbital AM is: h rbit = 2πmr2 P Earth m = 5.97 x g r = 1 AU = 1.5 x cm P = 1 year Jupiter m = 1898 x g r = 5.2 AU = 5.2 x 1.5 x cm P = years Saturn m = 586 x g r =9.61 AU P = 29.5 years h rbit = 2π( )( ) = g cm 2 s 1 h rbit = g cm 2 s 1 h rbit = g cm 2 s 1 Jupiter therefre carries ~50% f the ttal AM f the Slar System, while the Jvian planets tgether make up ~99.27% f the ttal! Lecture 1-2: Prperties f the slar system
28 Angular mmentum distributin Planet Mass (x10 27 kg) Perid (years) AM (gcm 2 s -1 ) Mercury x10 45 Venus x10 47 Earth x10 47 Mars x % AM Jupiter x10 50 Saturn x10 49 Uranus x10 49 Neptune x10 49 Plut x % AM =>Sun nly has 0.4% f the ttal AM in slar system. Lecture 1-2: Prperties f the slar system
29 Orbital angular mmenta f the planets Nte the verwhelming imprtance f the Jvian planets. The symbl assciated with each planet: Lecture 1-2: Prperties f the slar system
30 Mass and AM distributins Althugh Sun cntains 99.9% f the mass f Slar System, the uter planets have 98% f system s angular mmentum. This is a serius prblem: material accreting nt the Sun cannt have retained all its riginal AM. There are tw parts t the prblem: 1. Hw des material lse AM and fall int the star in the first place? 2. Hw des the star lse AM and slw dwn? Slar-type stars all rtate at abut the same speed at the Sun. Lecture 1-2: Prperties f the slar system
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