Prime numbers and prime polynomials. Paul Pollack Dartmouth College


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1 Prime numbers and prime polynomials Paul Pollack Dartmouth College May 1, 2008
2 Analogies everywhere! Analogies in elementary number theory (continued fractions, quadratic reciprocity, Fermat s last theorem) Analogies in algebraic number theory (the theory of global function fields vs. the theory of algebraic number fields) Analogies in analytic number theory, especially prime number theory 1
3 A partial dictionary between Z and F q [T ] Primes Irreducibles {±1} F q [T ] = F q Positive integers Monic polynomials Usual absolute value f = q deg f Observe #Z/nZ = n and #F q [T ]/(p(t )) = p(t ). 2
4 Prime number theorem (Hadamard, de la Vallée Poussin). If π(x) denotes the number of primes p x, then π(x) x log x as x. Prime number theorem for polynomials. Let π(q; d) denote the number of monic, degree d irreducibles over the finite field F q. Then as q d, we have π(q; d) qd d. Notice that if X = q d, then q d /d = X/ log q X. 3
5 Gauss s take on the prime number theorem: Empirical observations suggest that the primes near x have a density of about 1/ log x. So we should have π(x) 1 log log log x. Theorem (von Koch). If the Riemann Hypothesis is true, then π(x) = 2 n x 1 log n + O(x1/2 log x). 4
6 In the polynomial setting, Gauss s proof shows that qd π(q; d) d 2qd/2 d. But perhaps irregularities surface if we introduce a finer count? Let p be a prime. To each nonnegative integer in base p, we associate a polynomial in F p [T ], a 0 + a 1 p + + a k p k a 0 + a 1 T + + a k T k. Say that f is encoded by the integer f. 5
7 Define π p (X) as the number of n x which encode irreducible polynomials over F p. We might hope that π p (X) f x 1 deg f. Theorem. If X p, then π p (X) = f x where p d X < p d+1. 1 deg f + O ( dp d/2+1 ), Notice dp d/2+1 p X 1/2 log X, so this is a von Koch analogue. 6
8 Proof idea: To each global function field K (finite extension of F q (T )) one associates a zeta function, ζ K (s) = a 0 1 Nm(a) s. A deep theorem of Weil asserts that these zeta functions all satisfy the analogue of the Riemann Hypothesis. Define Lfunctions which are sensitive to the behavior of the initial coefficients of a polynomial in F q [T ]. The analytic properties of this Lfunction can then be linked to the analytic properties of ζ K (s) for an appropriate K and the Riemann Hypothesis brought into play. 7
9 Twin primes Twin prime conjecture. There are infinitely many prime pairs p, p + 2. Hypothesis H (Schinzel). Let f 1 (T ),..., f r (T ) be nonconstant polynomials with integer coefficients and positive leading coefficients, all irreducible over Z. Suppose that there is no prime p for which p divides f 1 (n) f r (n) for all n. Then for infinitely many positive integers n, the specializations f 1 (n),..., f r (n) are simultaneously prime. Examples: Twin prime conjecture, or the infinitude of primes of the form n
10 Theorem (Hall). Suppose q > 3. Then there are infinitely many monic irreducibles P (T ) over F q for which P (T ) + 1 is also irreducible. Theorem (P.). Suppose q > 3. Then there are infinitely many monic irreducibles P (T ) over F q for which P (T ) + 1 is also irreducible. 9
11 Theorem (Capelli s Theorem). Let F be any field. The binomial T m a is reducible over F if and only if either of the following holds: there is a prime l dividing m for which a is an lth power in F, 4 divides m and a = 4b 4 for some b in F. Observe: We have x 4 + 4y 4 = (x 2 + 2y 2 ) 2 (2xy) 2. 10
12 Example: The cubes in F 7 = Z/7Z are 1, 0, 1. So by Capelli s theorem, T 3k 2 is irreducible over F 7 for k = 0, 1, 2, 3,.... Similarly, T 3k 3 is always irreducible. Hence: T 3k 2, T 3k 3 is a pair of prime polynomials over F 7 differing by 1 for every k. 11
13 A finite field analogue of Hypothesis H. Suppose f 1,..., f r are irreducible polynomials in F q [T ] and that there is no irreducible P in F q [T ] for which P (T ) always divides f 1 (h(t )) f r (h(t )). Then f 1 (h(t )),..., f r (h(t )) are simultaneously irreducible for infinitely many monic polynomials h(t ) F q [T ]. Example: Twin prime pairs: take f 1 (T ) := T and f 2 (T ) := T + 1. Observation: The local condition is always satisfied if q > r i=1 deg f i. 12
14 Theorem (P.). Suppose f 1,..., f r are irreducible polynomials in F q [T ]. Let D = r i=1 deg f i. If q > max{3, 2 2r 2 D 2 }, then there are infinitely many monic polynomials h(t ) for which all of f 1 (h(t )),..., f r (h(t )) are simultaneously irreducible. 13
15 Example: Primes one more than a square Let F q be a finite field without a square root of 1; i.e., with q 3 (mod 4). We prove there are infinitely many irreducibles of the form h(t ) 2 + 1, where h(t ) is monic. Fix a square root i of 1 from the extension F q 2. We have h(t ) irreducible over F q h(t ) i irreducible over F q 2. Try for h(t ) a binomial say h(t ) = T lk β, with l a fixed prime. By Capelli, it suffices to find β F q so that β + i is a nonlth power. 14
16 Choose any prime l dividing q 2 1, and let let χ be an lth powerresidue character on F q 2. If there is no such β, then β F q χ(β + i) = q. But Weil s Riemann Hypothesis gives a bound for this incomplete character sum of q a contradiction. 15
17 Quantitative problems and results Twin prime conjecture (quantitative version). The number of prime pairs p, p + 2 with p x is asymptotically x 2C 2 log 2 x as x, where C 2 = p>2(1 1/(p 1) 2 ). Can generalize to the full Hypothesis H situation (HardyLittlewood/BatemanHorn). 16
18 A quantitative finite field Hypothesis H. Let f 1 (T ),..., f r (T ) be nonassociated polynomials over F q satisfying the conditions of Hypothesis H. Then #{h(t ) : h monic, deg h = n, and f 1 (h(t )),..., f r (h(t )) are all prime} S(f 1,..., f r ) ri=1 deg f i q n n r as q n. Here the local factor S(f 1,..., f r ) is defined by S(f 1,..., f r ) := where ω(p ) := n=1 deg P =n P monic prime of F q [T ] 1 ω(p )/q n (1 1/q n ) r, #{h mod P : f 1 (h) f r (h) 0 (mod P )}. 17
19 Theorem. Let n be a positive integer. Let f 1 (T ),..., f r (T ) be pairwise nonassociated irreducible polynomials over F q with the degree of the product f 1 f r bounded by B. The number of univariate monic polynomials h of degree n for which all of f 1 (h(t )),..., f r (h(t )) are irreducible over F q is q n /n r + O((nB)n! B q n 1/2 ) provided gcd(q, 2n) = 1. Example: The number of monic polynomials h(t ) of degree 3 over F q for which h(t ) is irreducible is asymptotically q 3 /3 as q with q 3 (mod 4) and (q, 3) = 1. 18
20 Some ideas of the proof The inspiration: Conjecture (Chowla, 1966). Fix a positive integer n. Then for all large primes p, there is always an irreducible polynomial in F p [T ] of the form T n + T + a with a F p. In fact, for fixed n the number of such a is asymptotic to p/n as p. Proved by Ree and Cohen (independently) in
21 Idea of their proof: Kummer: For most a, the polynomial T n +T a factors over F q the same way as the prime u a of F q (u) factors over the field obtained by adjoining a root of T n + T u over F q (u). Chebotarev: The splitting type of primes from F q (u), on average, is governed by the Galois group of the splitting field of T n + T u over F q (u). (Chebotarev.) Birch and SwinnertonDyer: This splitting field is, if q is prime to n(n 1), a geometric Galois extension with Galois group the full symmetric group on n letters. The proportion of ncycles in S n is 1 in n, and this implies that about 1 in n polynomials of the form T n +T a, with a F q, are irreducible. 20
22 M M 1 K i,1 L 1,1 K 1,1 L1,j 1,j K 1,j F q D(u) K 1,d1 F q (u) L 1,d1 L i,1 M i L i,j K i,j K i,di Lr,1 r,1 L r,j Mr r K r,1 Kr,j Lr,j Kr,dr K r,dr L i,di L r,dr 21
23 Prime gaps Recall that the average gap between primes near N is about log N. Conjecture (Primes are Poisson distributed). Fix λ > 0. Suppose h and N tend to infinity in such a way that h λ log N. Then 1 #{n N : π(n + h) π(n) = k} e λλk N k! for every fixed integer k = 0, 1, 2,.... Gallagher has shown that this follows from a uniform version of the prime ktuples conjecture. 22
24 Polynomial prime gaps For a prime p and an integer a, let a denote the residue class of a in Z/pZ = F p. For each prime p and each integer h 0, define I(p; h) := {a 0 + a 1 T + + a j T j : 0 a 0,..., a j < p with a i p i < h}. Let P k (p; h, n) be the number of polynomials A(T ) of degree n over F p for which the translated interval A + I(p; h) contains exactly k primes. 23
25 Conjecture. Fix λ > 0. Suppose h and n tend to infinity in such a way that h λn. Then 1 p np k(p; h, n) e λλk k! (as n ) for each fixed k = 0, 1, 2, 3,..., uniformly in the prime p. 24
26 Theorem. Fix λ > 0. Suppose h and n tend t0o infinity in such a way that h λn. Then for each fixed integer k 0, 1 p np k(p; h, n) e λλk k!, if both n and p tend to infinity, with p tending to infinity faster than any power of n n2. 25
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