1. Solving series circuit problems

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Name: Skill Sheet 20. Parallel and Series Circuits There are two major types of electrical circuits: series and parallel. In a series circuit, current follows only one path. In a parallel circuit, the current has two or more possible paths. In both types of circuits, the current travels from the positive end of the battery toward the negative end. The amount of energy used by a circuit (series or parallel) must equal the energy supplied by the battery. In this way, electrical circuits follow the law of conservation of energy. Understanding these facts will help you solve problems that deal with series and parallel circuits.. Solving series circuit problems Now it is time for you to test your knowledge of series and parallel circuits by answering the questions below. You will have to use Ohm s law to solve many of the problems, so remember: Voltage (volts) Current (amps) = ------------------------------------------- Resistance (ohms) Some questions ask you to calculate a voltage drop. We often say that each resistor creates a separate voltage drop. As current flows along a series circuit, each resistor uses up some energy. As a result, the voltage gets lower after each resistor. If you know the current in the circuit and the resistance of a particular resistor, you can calculate the voltage drop using Ohm s law. Voltage drop (volts) = Current (amps) Resistance of one resistor (ohms). Use the series circuit pictured at right to answer questions a-e below. a. What is the total voltage of the circuit? b. What is the total resistance of the circuit? c. What is the current flowing through the circuit? d. What is the voltage drop across each light bulb? (Remember that voltage drop is calculated by multiplying current in the circuit by the resistance of a particular resistor: V = IR.) e. Draw the path of the current flow on the diagram.

Skill Sheet 20. Parallel and Series Circuits 2. Use the series circuit pictured at right to answer questions a-c below. Consider each resistor equal to all others. a. What is the resistance of each resistor? b. What is the voltage drop across each resistor? c. On the diagram, show the amount of voltage in the circuit before and after each resistor. 3. Use the series circuit pictured at right to answer questions a-d below. a. What is the resistance of the circuit? b. What is the current flowing through the circuit? c. What is the voltage drop across each resistor? d. On the diagram, show the amount of voltage in the circuit before and after each resistor. 2. Solving parallel circuit problems A parallel circuit has at least one point where the circuit divides, creating more than one path for current. Each path is called a branch. The current through a branch is called branch current. Remember that if current flows into a branch in a circuit, the same amount of current must flow out again. This rule is known as Kirchhoff s current law. For example, suppose you have three light bulbs connected in parallel, and each has a current of amp. The battery must supply 3 amps since each bulb draws amp. Before the first branch point, 3 amps are flowing. One amp goes down the first branch to the first bulb, and 2 amps flow on to supply the next two bulbs. 2

Skill Sheet 20. Parallel and Series Circuits. Use the parallel circuit pictured at right to answer questions a-c below. a. What is the total voltage for the circuit? b. What is the current flow through each branch? c. What is the voltage in each branch? 2. Compare the circuits in Part, question and Part 2, question. What is the current flow through each bulb in the series circuit compared with the current flow through each bulb in the parallel circuit? Which bulbs would be brighter? Explain your reasoning. 3. Use the parallel circuit pictured at right to answer questions a-d below. a. What is the voltage through each branch? b. What is the current flow through each branch? c. What is the power of each resistor? (Remember that power is current multiplied by voltage.) d. What is the relationship between current and power? 3

Name: Skill Sheet 20.2 Network Circuits Network circuits are combinations of series and parallel circuits. Therefore, solving problems that involve networks circuits require using one or two formulas. In this skill sheet, you will practice solving these kinds of problems.. The formulas for solving network circuit problems When solving resistor network circuits we have to remember the following formulas:. Ohm s law: V = IR 2. Combining resistors: R total equals total resistance for the circuit: a. In series: R total = R + R 2 +... b. In parallel: ----------- R total = ----- R + ----- +... R 2 3. Kirchhoff s voltage law: The sum of voltages around a loop is zero. 4. Kirchhoff s current law: The sum of currents into a node equals the sum of currents out of the node. Example problem: For the following circuit, calculate the total resistance and the total current drawn from the 6-volt battery. First notice that resistors R 5 and R 6 are in parallel and that they combine to give a resulting resistance of.5 ohms. Next, notice that resistors R 3 and R 4 are in series resulting in a resistance of 2 ohms. The resulting 2 ohms resistance is connected in parallel with another 2-ohm resistor. Thus the combined resistance of R 3, R 4, and R 2 is ohm. Now the circuit looks like: We see now that the -ohm resistors are connected in series. Therefore, they represent a 2-ohm resistor connected in parallel with the.5-ohm resistor. The 2-ohm resistor in parallel with the.5 ohm gives a total resistance of 6 7 or 0.86 ohms. The total current drawn from the battery can be now found by applying Ohm s law: I = V -- = 6 ---------------- volts = 7 A R 6/7Ω

Skill Sheet 20.2 Network Circuits 2. Problems. A 2-volt battery is connected to the resistor network shown on the schematic. Calculate the current through each resistor in the network. 2. Combine resistances and calculate the total resistance. 3. Calculate the total current drawn from the 9-volt battery. 4. For the circuit at right, trace the path of the current through the circuit and then answer the following questions: a. Does current flow through R5? Why or why not? b. Given your answer to (a), what is the total resistance for the circuit? c. Given your answer to (a), what is the total current leaving the battery? d. What is the current through resistor R 3? e. What is the voltage across R 5? Explain your answer. 2

Skill Sheet 20.2 Network Circuits 5. Find the total current drawn from the 6-volt battery. What is the voltage across resistor R 4? 6. What is the voltage across the 5-ohm resistor? 7. Calculate the voltage across points A and B (V AB ) when the resistor R 4 is 0 Ω. HINT: Find the voltage at A (V A ) and the voltage at B (V B ) and subtract. 3

Name: Skill Sheet 20.3 Electrical Power Which appliance in your kitchen uses the most power? The equation for electrical power is the tool you can use to answer this question. This skill sheet will help you sharpen your skills at calculating electrical power and analyzing the voltage, current, and power associated with electric circuits. You will also review the relationship between electrical power and Ohm s law. As you work through the problems, you will practice calculating the power used by common appliances in your home.. What is electrical power? Power is the rate at which work is performed. Power tells us how quickly work is being done or how much energy is being used per unit time. When you work with machines, power is calculated by dividing work by the amount of time it takes to perform the work. For electrical systems, the equation for power is: power = voltage current P = V I where P = power, V = voltage and I = current. This equation allows us to assess the rate at which an appliance or other device is using energy or performing work. The graphic below shows you why power is called a rate. The unit for voltage is joules per coulomb. The unit for current is coulombs per second. When you multiply voltage times current, the coulombs cancel so that the unit for power is joules per second. 2. The unit for electrical power One joule per second is equal to one watt of power. The watt (W) is a familiar unit of power to most people. You can look at any appliance and see how many watts of power it uses. For example, the heating element on a coffeemaker uses,050 watts of power. We can also say that the coffeemaker has a power rating of,050 watts. One watt of power represents one joule of energy being used per second of time. power = joules ------------- sec watt = ---------------- joule sec The more watts of power a circuit or appliance has, the more energy it uses or the more work it can do per second of time. A,500-watt microwave oven can perform the same amount of work as a 900-watt microwave; however, the rate at which the,500w microwave performs the work is faster. Also, the amount of energy used per second of time is greater (,500 joules in one second compared with 900 joules in one second). As a result, higher-wattage appliances are more expensive to operate.

Skill Sheet 20.3 Electrical Power 3. Practice problems Complete the following problems. Be sure to show your work. The first problem has been done for you.. A toaster oven has a power rating of 750 W. If the oven heats a piece of pizza for 360 seconds, how many joules of energy have been used by the toaster oven? power 750 W = = joules of energy ------------------------------------- time joules of energy ------------------------------------- 360 sec 750 W 360 sec = joules of energy = 270,000 joules 2. You use your 60-watt DVD player to watch your favorite movie. If the player uses 324,000 joules of energy playing the film, what is the running time of the movie? 3. The current flowing through an electrical circuit is 9 amps. If the voltage in the same circuit is 20 volts, what is the power of the circuit? 4. A 7,200 -watt electric clothes dryer operates with a current of 30 amps. What is the voltage associated with this circuit? 5. A CD player uses 85 joules of energy per second. If the voltage in the CD player is 70 V, what amount of current is required for the operation of player? 6. A girl wants to build a radio that operates using 9-volt batteries. If the girl wishes the radio to function with 75 watts of power, with what amount of current will she have to design her circuits? 2

Skill Sheet 20.3 Electrical Power 7. Your stereo has a power rating of 50 watts. Your friend buys a stereo with a power rating of 300 watts. If you both play your stereos for one hour, who will spend more money to listen to their music? Explain your answer. 8. The voltage supplied to household circuits is generally 20 V. However, individual circuits (circuits supplying the kitchen as opposed to the living room, for example) differ in the amount of current they carry. What does that tell you about the amount of power operating in different household circuits? Why do you think household circuits are designed in this way? 4. Comparing electrical power and mechanical power Power is a term that is used when you talk about machines that use electricity, like blenders and refrigerators, and mechanical machines, like pulleys. Look up the equation for mechanical power. Use this equation to answer the following questions.. Power can be calculated for electrical systems and mechanical systems. Write the equation for mechanical power. What are the units for mechanical power? 2. Compare the equations for electrical power and mechanical power. How are they alike, and how different? 3

Skill Sheet 20.3 Electrical Power 5. How do you calculate electrical power? In everyday life we hear the word watt mentioned in reference to things like light bulbs and electric bills. The watt is the unit that describes how much power is used when electricity flows. Therefore, the definition of power is the rate at which energy is flowing. And since energy is measured in joules, power is measured in joules per second. In fact, one joule per second is equal to one watt. You may also have heard of the word kilowatt. A kilowatt is,000 watts or,000 joules of energy flowing in one second. This term kilowatt is most often used with electrical use in houses and other large facilities. And on an electric bill you may have noticed the term kilowatt-hour. A kilowatt-hour means that one kilowatt of power has been used for one hour. We can calculate the amount of electrical power used by an appliance or other electrical component by multiplying the voltage by the current. voltage current = power, or P = VI 6. Solving problems Solve the following problems using the power equation and Ohm s law. Remember, power is measured in watts.. Your hair dryer has a power rating of,200 watts. a. How many kilowatts is this? current (amps) = voltage (volts) ----------------------------------------- resistance (ohms) b. If the hair dryer is used for 20 minutes per day, how many kilowatt-hours (kwh) per day is this? (HINT: Convert 20 minutes to hours.) c. Find the kilowatt-hours used by the hair dryer each month (assume 30 days/month). d. If your town charges $0.5/kWh, what is the cost to use the hair dryer per month? 2. Using the formula for power, calculate the amount of current through a 75-watt light bulb that is connected to a 20-volt circuit in your home. 4

Skill Sheet 20.3 Electrical Power 3. What is the power rating of a home appliance (in kilowatts) that uses 8 amps of current when plugged into a 20-volt outlet? 4. The following questions refer to the diagram at right. a. What is the total voltage for the circuit? b. What is the total resistance for the circuit in ohms (Ω)? c. What is the current that will flow through the circuit? d. What is the power in watts for this circuit? 5. A toaster is plugged into a 20-volt household circuit. It draws 5 amps of current. a. What is the resistance of the toaster in ohms (Ω)? b. What is the toaster s power in watts? What is that power stated in kilowatts? 6. A clothes dryer in a home has power of 4,500 watts and runs on a special 220-volt household circuit. a. What is the current traveling through the dryer? b. What is the clothes dryer s resistance in ohms (Ω)? 5

Skill Sheet 20.3 Electrical Power 7. A hair dryer is connected to a 20-volt household circuit. The current through the dryer is 0 amps. a. What is the resistance of the hair dryer? b. What is the hair dryer s power rating in kilowatts? c. If the dryer is used for 30 minutes per day, how many kilowatt-hours are used by the dryer each day? d. How many kilowatt-hours are used per month? (Assume month = 30 days.) e. If the town charges 4 cents per kwh, what is the cost to run the hair dryer per month? 6