Systems and Units. The three systems of units are:

Similar documents
Pump Formulas Imperial and SI Units

APPENDIX I SI AND ENGLISH UNITS AND CONVERSION FACTORS

Preferred SI (Metric) Units

For Water to Move a driving force is needed

Unit Conversions. Ben Logan Feb 10, 2005

INTERIM UNITS OF MEASURE As suggested by Federal Standard 376B January 27, hectare (ha) Hundred for traffic buttons.

Fluid Mechanics: Static s Kinematics Dynamics Fluid

Fluids and Solids: Fundamentals

MEASUREMENT. Historical records indicate that the first units of length were based on people s hands, feet and arms. The measurements were:

= 800 kg/m 3 (note that old units cancel out) J 1000 g = 4184 J/kg o C

METRIC CONVERSION TABLE Multiply By To Obtain Millimetres Inches Millimetres Feet Metres Feet Kilometres 0.

1. Metric system- developed in Europe (France) in 1700's, offered as an alternative to the British or English system of measurement.

Barometric Effects on Transducer Data and Groundwater Levels in Monitoring Wells D.A. Wardwell, October 2007

Physics Notes Class 11 CHAPTER 2 UNITS AND MEASUREMENTS

XI / PHYSICS FLUIDS IN MOTION 11/PA

WEEK 1. Engineering Calculations Processes Process Variables

Displacement (x) Velocity (v) Acceleration (a) x = f(t) differentiate v = dx Acceleration Velocity (v) Displacement x

CBE 6333, R. Levicky 1 Review of Fluid Mechanics Terminology

Conversion Formulas and Tables

Excel Invoice Format. SupplierWebsite - Excel Invoice Upload. Data Element Definition UCLA Supplier website (Rev. July 9, 2013)

2 1/2 Pipe. 40 = height. the gauge pressure inside the vessel from the gauge pressure at the nozzle inlet as shown:

CONTROL VALVE PRESSURE DROP AND SIZING

Handout Unit Conversions (Dimensional Analysis)

MEASUREMENTS. U.S. CUSTOMARY SYSTEM OF MEASUREMENT LENGTH The standard U.S. Customary System units of length are inch, foot, yard, and mile.

01 The Nature of Fluids

OUTCOME 3 TUTORIAL 5 DIMENSIONAL ANALYSIS

When the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid.

Worst Case Discharge (WCD)

1. Fluids Mechanics and Fluid Properties. 1.1 Objectives of this section. 1.2 Fluids

DIMENSIONAL ANALYSIS #2

VISCOSITY OF A LIQUID. To determine the viscosity of a lubricating oil. Time permitting, the temperature variation of viscosity can also be studied.

One basic concept in math is that if we multiply a number by 1, the result is equal to the original number. For example,

Appendix C: Conversions and Calculations

Tallahassee Community College PERIMETER

Measurement/Volume and Surface Area Long-Term Memory Review Grade 7, Standard 3.0 Review 1

Equivalents & Conversion Factors 406 Capacity Formulas for Steam Loads 407 Formulas for Control Valve Sizing

PHYS 101-4M, Fall 2005 Exam #3. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Waterflooding. A Tried and True Technique for Secondary Oil Recovery. Houston Bar Association Oil, Gas and Mineral Law Section March 26, 2013

Unit conversion problems, by Tony R. Kuphaldt (2006)

BS PROGRAM IN PETROLEUM ENGINEERING (VERSION 2010) Course Descriptions

Converting Units of Measure Measurement

Chapter 1 Problems. To do all three sections of this problem, we can first convert the radius to kilometers. r = km 1000m = 6.

Available online at Petroleum & Coal 55 (4) , 2013

RESERVOIR EVALUATION. The volume of hydrocarbons in a reservoir can be calculated:

Pressure drop in pipes...

The entire document shall be read and understood before proceeding with a test. ISTA 3B Page 1 of 35

Oil and Gas Exploration and Production Oil and gas exploration and production... 22a-472-1

HPHT CAPPING STACKS AND NEW TECHNOLOGY FOR SUBSEA WELL CONTROL. December 3, 2014 Presenter: Mike Cargol

Physics 1114: Unit 6 Homework: Answers

GUARDRAIL INNOVATION FLOWS FROM HERE

4D reservoir simulation workflow for optimizing inflow control device design a case study from a carbonate reservoir in Saudi Arabia

UNIT (1) MEASUREMENTS IN CHEMISTRY

Chapter 2 Measurement and Problem Solving

The University of Toledo Soil Mechanics Laboratory

Valve Sizing. Te chnic al Bulletin. Flow Calculation Principles. Scope. Sizing Valves. Safe Product Selection.

Packaged-Products for Parcel Delivery System Shipment 70 kg (150 lb) or Less

SIZING AND CAPACITIES OF GAS PIPING

Journal bearings/sliding bearings

Measurement: Converting Distances

Mercury is poured into a U-tube as in Figure (14.18a). The left arm of the tube has crosssectional

Physical Quantities, Symbols and Units

Systems of Units and Conversion Factors

W i f(x i ) x. i=1. f(x i ) x = i=1

Metric Mania Conversion Practice. Basic Unit. Overhead Copy. Kilo units. Hecto units. Deka - 10 units. Deci - 0.

Measurement. Customary Units of Measure

Example Calculations Evaluation for Fine Bubble Aeration System. Red Valve Company, Inc. 700 NORTH BELL AVENUE CARNEGIE, PA

For Multi-Parameter Meters see mvx

AP Physics C. Oscillations/SHM Review Packet

ADX ENERGY. Sidi Dhaher Well test Briefing Live Webcast, 4 July Wolfgang Zimmer, Paul Fink

Notes on Polymer Rheology Outline

CE 204 FLUID MECHANICS

CE 3500 Fluid Mechanics / Fall 2014 / City College of New York

NOTE: FOR PROJECTS REQUIRING CONTRACTOR MIX DESIGN, THE DESIGN PROCEDURES ARE SPECIFIED IN THE SPECIAL PROVISIONS OF THE CONTRACT.

Conversions. 12 in. 1 ft = 1.

SIZING AND CAPACITIES OF GAS PIPING

So if ω 0 increases 3-fold, the stopping angle increases 3 2 = 9-fold.

Practice Tests Answer Keys

CHAPTER 3: FORCES AND PRESSURE

Stanford Rock Physics Laboratory - Gary Mavko. Basic Geophysical Concepts

PHYSICAL QUANTITIES AND UNITS

How To Understand Fluid Mechanics

UNIT 1 MASS AND LENGTH

Quick Look Determination of Oil-in-Place in Oil Shale Resource Plays*

IV. POWER. P = W t. = E t. where W is the work done, t is the time required to do the work, and E is the energy used. 1 horsepower = 1 hp = 550

Measurement of Length, Mass, Volume and Density

General Physics 1. Class Goals

Pressure Coring, A New Tool for Unconventional Oil & Gas Characterization. Matt Bjorum Global Product Line Manager

Section 1 Tools and Measurement

Piping Hydraulic Line Design and Sizing Software KLM Technology Group

QUESTIONS THERMODYNAMICS PRACTICE PROBLEMS FOR NON-TECHNICAL MAJORS. Thermodynamic Properties

Vatten(byggnad) VVR145 Vatten. 2. Vätskors egenskaper (1.1, 4.1 och 2.8) (Föreläsningsanteckningar)

Periodical meeting CO2Monitor. Leakage characterization at the Sleipner injection site

Calculating Area and Volume of Ponds and Tanks

ACFM vs. SCFM vs. ICFM Series of Technical White Papers from Ohio Medical Corporation

Chapter 13 - Solutions

!"#$ Reservoir Fluid Properties. State of the Art and Outlook for Future Development. Dr. Muhammad Al-Marhoun

Chapter 1 Problems. 1micron m = microns. = cm. 1micron m = microns. 1 ft

Engineering Information

Appendix 1: Units of Measure Used in the Lead-Based Paint Field

Transcription:

The three systems of units are: 1. The English or the ft-lb-s System 2. The International or the m-kg-s System 3. The Laboratory or the cm-gm-s System Quantities fall into two main categories: 1. Principal Quantities Length (L) Mass (m) Time (t) Angle (θ) Temperature (T) 2. Derived Quantities Area (A) Volume (V) Velocity (ν) Frequency (Hz.) Acceleration (a) Angular Velocity (ω) Angular Acceleration (â) Volume Flow Rate (q) Mass Flow Rate ( o m ) Density (ρ) Specific Gravity (SG) Force (F) Force due to Inertia (F I ) Force due to Gravity (F G ) Force due to Viscosity (F µ ) Force due to Elasticity (F E ) Force due to Pressure (F P ) Specific Weight (γ) Energy (E) Moment of a Force (M) Work (W) Pressure (p) Stress (τ) Power (P) Dynamic Viscosity (µ) Kinematic Viscosity (ν) Systems and Units 1

1. Principal Quantities Quantity English System International System Length Mass Time Angle Temperature mile (mi) = 1760 yd yard (yd) = 3 ft foot (ft) = 12 in inch (in) = 2.54 cm slug (sl) = 32.17404856 lbm pound mass (lbm) = 453.592370 gm year = 365 d day = 24 h hour = 60 m minute = 60 s 1 rev. = 2B radians = 360E 1 r = 57.29578E 1 E = 0.017453r Ordinary EF= 1.8EC+32 Absolute ER= EF+459.688 ER= 1.8 K kilometer (km) = 1000 m meter (m) = 100 cm centimeter (cm) kilogram (kg) = 1000 gm gram (gm) year = 365 d day = 24 h hour = 60 m minute = 60 s 1 rev. = 2B radians = 360E 1 r = 57.29578E 1 E = 0.017453r Ordinary EC= (EF-32)/1.8 Absolute K= EC+273.16 K= ER/1.8 2

2. Derived Quantities Quantity Formula English Units SI Units Lab. Units Area A = L 2 1 mi 2 = 640 acres mi 2, ft 2, in 2, acre 1 acre = 43,560 ft 2 Volume V = L 3 bbl = 5.6146 ft 3 bbl, ft 3, gal, qt bbl = 42 gal gal = 4 qt = 3.785 ltr Velocity dl = dt m 2 m 3, ltr m 3 = 1000 ltr ltr = 1000 cc cm 2, darcy, md 1 cm 2 = 101,320,790 d 1 d = 1000 md cm 3 = cc ν ft/s m/s cm/s Frequency Hz. s -1 s -1 s -1 Acceleration dν a = dt ft/s 2 m/s 2 cm/s 2 Angle 2 rad and E 360E = 2B rad rad and E 360E = 2B rad rad and E 360E = 2B rad dθ Angular ω = Velocity dt rad/s rad/s rad/s dω Angular aˆ = Acceleration dt rad/s 2 rad/s 2 rad/s 2 Volume dv Flow Rate q = dt bbl/d, ft 3 /s m 3 /s, ltr/s cc/s Mass Flow dm m o = Rate dt slug/s, lbm/s kg/s gm/s Density m ρ = slug/ft 3, lb/ft 3, V lb/gal kg/m 3 gm/cc Specific Gravity ρ f SG = = ρ w 141.5 o 131.5+ API D w = 1.940 slug/ft 3 D w = 62.428 lbm/ft 3 D w = 8.345 lbm/gal D w = 0.433 D w = 10 EAPI D w = 10 3 kg/m 3 D w = 1 gm/cc 3

2. Derived Quantities (cont.) Quantity Formula English Units SI Units Lab. Units Force F = m a lbf = slug ft/s 2 lbf = 444,822 dyne lbf = 4.44822 N Force due to Inertia Force due to Gravity=Wt. Force due to Viscosity F N = kg m/s 2 1 N = 10 5 dynes dyne = gm cm/s 2 F I = m a lbf N dyne F G = m g µ lbf g = 32.17404856 ft/s 2 N g = 9.80665 m/s 2 dyne g = 980.665 cm/s 2 dν = µ A lbf N dyne dy Force due to Elasticity Force due to Pressure F E = E A lbf N dyne F P = p A lbf N dyne Specific Wt. ( = F G /V lbf/ft 3 N/m 3 dyne/cc Energy E = F L lbf-ft J = N-m erg = dyne cm Moment of a Force M = F L lbf-ft J erg = dyne cm Work W = F L lbf-ft J erg = dyne cm Pressure p = F N /A lbf/ft 2, lbf/in 2 = psi p sc = 14.69594877 psi 4 Pa = N/m 2 bar = 10 5 Pa p sc = 1.01325 bar p sc = 101325 Pa dyne/cm 2 p sc =1013250 d/cm 2 p sc = 1 atm p sc = 76 cm Hg Stress J = F T /A lbf/ft 2, lbf/in 2 = psi bar, Pa dyne/cm 2 Power P = E/t lbf-ft/s, hp 1 hp = 550 lbf-ft/s F Dynamic F Viscosity µ lbf-s/ft 2 = 47,880 µ dν / dya cp Kinematic Viscosity W = J/s N s/m 2 = 10 poise N s/m 2 = 1000 cp < = µ/d ft 2 /s = 929 stoke m 2 /s = 10 4 stoke erg/s dyne s/cm 2 = poise 1 poise = 100 cp cm 2 /s = stoke

EPS-441: Petroleum Development Geology Units and Conversion Semester: Homework #: Name: SS#: Problem #1: Do the following unit conversions: From 38 o API 12 o API 56 o API 40 o API 28 o API 31 o API 0.433 0.433 0.433 0.378 0.394 SG = 0.76 SG = 1.10 SG = 0.74 SG = 1.08 SG = 0.88 48.8 lb/ft 3 62.4 lb/ft 3 64.3 lb/ft 3 48.7 lb/ft 3 10.86 lb/gal 8.33 lb/gal 8.33 lb/gal 10.4 lb/gal 0.82 gm/cc 1.02 gm/cc 0.87 gm/cc 0.91 gm/cc To lb/ft 3 SG SG gm/cc lb/ft 3 lb/gal gm/cc o API o API lb/ft 3 lb/gal o API SG o API gm/cc gm/cc lb/ft 3 gm/cc SG lb/ft 3 Problem #2: Given a rectangular solid with dimensions 1000 ft x 400 ft x 40 ft. Calculate its volume in ft 3, bbl, acre-ft?. 5

Problem #3: Calculate pressure gradients of the following liquids: SG = 1.00 D w = 66.3 lb/ft 3 SG = 1.15 D w = 9.5 lb/gal SG = 0.85 EAPI = 42 EAPI = 32 EAPI = 45 D o = 58.1 lb/ft 3 Problem #4: A well drilled to 3000 ft penetrates a formation containing 28 EAPI oil. If reservoir pressure is 1300 psia, what is the shut-in surface pressure?. If reservoir pressure is 1000 psia, how many ft of oil will be standing in the wellbore?. Problem #5: In an area where ambient temperature is 78 EF, two wells, A and B, were drilled. The depth of well A is 7250 ft and the depth of well B is 8000 ft. The bottom hole temperature (BHT) in well B is 180 EF. What is the BHT in well A?. Problem #6: The areal extent of a reservoir as determined with seismic data is 1500 acres. From logs the following reservoir properties were determined: Zone N h, ft S w 1 0.28 4 0.28 2 0.32 7 0.40 3 0.18 3 0.31 4 0.20 11 0.27 a) Calculate the pore volume in the reservoir. Give your answers in acre-ft, ft 3, and bbl. b) Calculate the volume of oil in the reservoir. Give your answers in acre-ft, ft 3, and bbl. c) Calculate the STB of oil if B o = 1.34 RB/STB. 6

Problem #7: The average reservoir properties of a 300 acre reservoir are: N = 18% and S w = 36%. Estimated volume of oil originally in place = 410 MM STB. Formation thickness = 2000 ft. Determine the oil formation volume factor. Problem #8: Consider the sketch below. Given EAPI of oil = 35. water SG = 1.07. If well A penetrates the oil zone, find the shut-in surface pressure at well A?. 7

EPS-441: Petroleum Development Geology Units and Conversion Semester: Homework #: Name: SS#: Problem #1: A reservoir has an areal extent of 500 acres, an average thickness of 90 ft, and an average porosity of 20%. a) What is the reservoir volume available for hydrocarbons?. Answer in acre-ft, bbl, and ft 3. b) If the average water saturation is 35%, what is the reservoir volume available for oil?. Answer in acre-ft, bbl, and ft 3. c) Same as (b) except reservoir fluid is gas. d) If B o = 1.34 RB/STB. What is the oil volume from (b) in surface barrels?. in surface cubic feet?. e) If B g = 310 SCF/CF. What is the gas volume from (c) in surface cubic feet?. in surface barrels?. Problem #2: A well is being drilled to a depth of 10,000 ft. The wellbore diameter is 9 inches. The drill string has an inside diameter of 4.5 inches and an outer diameter of 5 inches. What is the volume of mud in the hole when it is at total depth (TD) and there is a complete drill string in the hole?. Ignore collars and bit volume and assume the mud is incompressible. Answer in cubic feet and barrels. 8

Problem #3: Data for the diagram shown below are: a) oil gravity = 38 EAPI b) water specific gravity = 1.05 c) average gas gradient = 0.055 d) only oil flows in oil zone e) reservoir B is in water communication with the surface f) pressure at oil zone datum in reservoir A = 3820 psig g) temperature gradient = 1.5 EF/100 ft. h) mean surface temperature = 61 EF i) ground level is 3000 ft above sea level j) elevations given are sub-sea but answers should be in subsurface a) Calculate pressure and temperature at each of the 7 zones indicated in the diagram. b) What is the bubble point pressure for the oil in reservoir A?. c) Did the oil accumulated before or after faulting in both reservoirs?. 9

Problem #4: Seismic data indicates an areal extent of a reservoir as one square mile. Other reservoir properties are: Zone N, % h, ft S w, % 1 15.3 10 36.2 2 26.9 8 13.1 3 18.1 15 24.7 4 22.0 12 19.6 a) Calculate hydrocarbon pore volume in the reservoir. Give your answers in acre-ft, ft 3, and bbl. b) Calculate the volume of oil in the reservoir. Give your answers in acre-ft, ft 3, bbl, and STB if B o = 1.18 RB/STB. c) How many SCF of gas in the reservoir if B g = 263 SCF/CF. Problem #5: A well drilled in an area had the following tests run: DST, temperature survey and a suite of logs. A surface gas and oil samples were taken and recombined at simulated reservoir conditions and a PVT analysis was done. From these measurements, the following reservoir rock and fluid properties were determined: EAPI of oil = 29 EAPI B o = 1.38 RB/STB SG g = 0.78 reservoir depth = 4520 ft initial reservoir pressure = 2952 psia bubble point pressure = 1831 psia reservoir temperature = 151 EF surface temperature = 70EF reservoir acreage = 640 acres Zone h, ft N (%) S w (%) 1 62 22 31 2 31 18 50 3 5 9 42 4 26 14 21 a) calculate the geothermal gradient in this area?. b) calculate the original oil in place (OOIP)?. 10

Problem #6: Consider the sketch below. If BHT at well A is 200 EF and BHT at well B is 232 EF. a) What is the BHT at well C?. b) What is the ambient temperature in this area?. 11

EPS-441: Petroleum Development Geology Units and Conversion Semester: Homework #: Name: SS#: Problem #1: A well was drilled offshore into an unconsolidated formation. The used sand control methods were not successful so the well was shut-in. The average annual surface temperature in that area is 84 EF and the temperature gradient is 1.6 EF/100 ft. The shut-in surface pressure is 850 psig and the shut-in bottom hole pressure is 2800 psig. It is known that the wellbore (diameter = 5.5 inches) is filled with gas (SG = 0.78, z = 0.85), oil (API = 32E), water (SG = 1.08), and water saturated sand (D = 35 gm/cc). Knowing that there is a 2500 ft of gas, a 2000 ft of sand-free water, and a 500 ft of water-saturated sand, calculate the following: a) Total depth of the well. b) B g in SCF/CF of the gas using average pressure and temperature. Problem #2: Define the following using equations only - include units: a) Oil formation volume factor (B o ) b) Porosity (N) c) Temperature gradient (G T ) d) Gas saturation (S g ) e) Oil gravity (EAPI) f) Fluid pressure gradient (() 12

Problem #3: Using the figure below and the following data: D w D o D g p atm = 1.02 gm/cc = 0.80 gm/cc = 0.10 gm/cc = 14.7 psia What does gauge A read?. 13