The Mole. S We are familiar with using a specific term to represent a number of items in a group.

Similar documents
Calculations and Chemical Equations. Example: Hydrogen atomic weight = amu Carbon atomic weight = amu

Chemical Calculations: Formula Masses, Moles, and Chemical Equations

Chemistry B11 Chapter 4 Chemical reactions

The Mole Concept and Atoms

The Mole Concept. The Mole. Masses of molecules

Translate chemical symbols and the chemical formulas of common substances to show the component parts of the substances including:

CHEM 110: CHAPTER 3: STOICHIOMETRY: CALCULATIONS WITH CHEMICAL FORMULAS AND EQUATIONS

Chapter 3! Stoichiometry: Calculations with Chemical Formulas and Equations. Stoichiometry

Other Stoich Calculations A. mole mass (mass mole) calculations. GIVEN mol A x CE mol B. PT g A CE mol A MOLE MASS :

Balance the following equation: KClO 3 + C 12 H 22 O 11 KCl + CO 2 + H 2 O

Moles. Balanced chemical equations Molar ratios Mass Composition Empirical and Molecular Mass Predicting Quantities Equations

Calculating Atoms, Ions, or Molecules Using Moles

Chapter 5 Chemical Quantities and Reactions. Collection Terms. 5.1 The Mole. A Mole of a Compound. A Mole of Atoms.

The Mole Notes. There are many ways to or measure things. In Chemistry we also have special ways to count and measure things, one of which is the.

Name: Teacher: Pd. Date:

IB Chemistry 1 Mole. One atom of C-12 has a mass of 12 amu. One mole of C-12 has a mass of 12 g. Grams we can use more easily.

Moles Lab mole. 1 mole = 6.02 x This is also known as Avagadro's number Demo amu amu amu

Moles. Moles. Moles. Moles. Balancing Eqns. Balancing. Balancing Eqns. Symbols Yields or Produces. Like a recipe:

Chapter 3: Stoichiometry

Tuesday, November 27, 2012 Expectations:

11-1 Stoichiometry. Represents

Chem 1100 Chapter Three Study Guide Answers Outline I. Molar Mass and Moles A. Calculations of Molar Masses

Chemistry 65 Chapter 6 THE MOLE CONCEPT

THE MOLE / COUNTING IN CHEMISTRY

Stoichiometry. What is the atomic mass for carbon? For zinc?

Calculations with Chemical Formulas and Equations

1. How many hydrogen atoms are in 1.00 g of hydrogen?

IB Chemistry. DP Chemistry Review

Chapter 3. Chemical Reactions and Reaction Stoichiometry. Lecture Presentation. James F. Kirby Quinnipiac University Hamden, CT

Chemical Reactions Practice Test

CHEMICAL FORMULAS AND EQUATIONS

Chemical Calculations: The Mole Concept and Chemical Formulas. AW Atomic weight (mass of the atom of an element) was determined by relative weights.

Element of same atomic number, but different atomic mass o Example: Hydrogen

Matter. Atomic weight, Molecular weight and Mole

Formulas, Equations and Moles

Steps for balancing a chemical equation

Unit 6 The Mole Concept

CHEMICAL REACTIONS. Chemistry 51 Chapter 6

Sample Problem: STOICHIOMETRY and percent yield calculations. How much H 2 O will be formed if 454 g of. decomposes? NH 4 NO 3 N 2 O + 2 H 2 O

Chapter 3. Mass Relationships in Chemical Reactions

Chemical Formulas, Equations, and Reactions Test Pre-AP Write all answers on your answer document.

Chemical Reactions 2 The Chemical Equation

20.2 Chemical Equations

Unit 3 Notepack Chapter 7 Chemical Quantities Qualifier for Test

CHEM 120 Online: Chapter 6 Sample problems Date: 2. Which of the following compounds has the largest formula mass? A) H2O B) NH3 C) CO D) BeH2

Writing and Balancing Chemical Equations

Chapter 8: Chemical Equations and Reactions

Chapter 5. Chemical Reactions and Equations. Introduction. Chapter 5 Topics. 5.1 What is a Chemical Reaction

CONSERVATION OF MASS During a chemical reaction, matter is neither created nor destroyed. - i. e. the number of atoms of each element remains constant

Word Equations and Balancing Equations. Video Notes

CP Chemistry Review for Stoichiometry Test

Chapter 8 - Chemical Equations and Reactions

Ch. 10 The Mole I. Molar Conversions

Stoichiometry Review

Chemical Equations and Chemical Reactions. Chapter 8.1

Chemical Reactions in Water Ron Robertson

Tutorial 4 SOLUTION STOICHIOMETRY. Solution stoichiometry calculations involve chemical reactions taking place in solution.

Chemical Equations & Stoichiometry

Unit 2: Quantities in Chemistry

Unit 7A - The Mole. We Need to Count atoms. The Mole and Molar Mass

Concept 1. The meaning and usefulness of the mole. The mole (or mol) represents a certain number of objects.

Honors Chemistry: Unit 6 Test Stoichiometry PRACTICE TEST ANSWER KEY Page 1. A chemical equation. (C-4.4)

Experiment 8: Chemical Moles: Converting Baking Soda to Table Salt

MOLES, MOLECULES, FORMULAS. Part I: What Is a Mole And Why Are Chemists Interested in It?

3.3 Moles, 3.4 Molar Mass, and 3.5 Percent Composition

Chapter 6: Writing and Balancing Chemical Equations. AB A + B. CaCO3 CaO + CO2 A + B C. AB + C AC + B (or AB + C CB + A)

The Mole x 10 23

Chapter 6 Chemical Calculations

Chapter 5, Calculations and the Chemical Equation

Part One: Mass and Moles of Substance. Molecular Mass = sum of the Atomic Masses in a molecule

Chemical Composition. Introductory Chemistry: A Foundation FOURTH EDITION. Atomic Masses. Atomic Masses. Atomic Masses. Chapter 8

Physical Changes and Chemical Reactions

Chapter 4. Chemical Composition. Chapter 4 Topics H 2 S. 4.1 Mole Quantities. The Mole Scale. Molar Mass The Mass of 1 Mole

Sample Exercise 3.1 Interpreting and Balancing Chemical Equations

Unit 10A Stoichiometry Notes

Mole Notes.notebook. October 29, 2014

Lecture Topics Atomic weight, Mole, Molecular Mass, Derivation of Formulas, Percent Composition

Lecture 5, The Mole. What is a mole?

UNIT (4) CALCULATIONS AND CHEMICAL REACTIONS

1. What is the molecular formula of a compound with the empirical formula PO and a gram-molecular mass of 284 grams?

Unit 9 Stoichiometry Notes (The Mole Continues)

CHAPTER 3 Calculations with Chemical Formulas and Equations. atoms in a FORMULA UNIT

Chem 31 Fall Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations. Writing and Balancing Chemical Equations

The Empirical Formula of a Compound

CHAPTER 3: MATTER. Active Learning Questions: 1-6, 9, 13-14; End-of-Chapter Questions: 1-18, 20, 24-32, 38-42, 44, 49-52, 55-56, 61-64

Introductory Chemistry, 3 rd Edition Nivaldo Tro. Roy Kennedy Massachusetts Bay Community College Wellesley Hills, Maqqwertd ygoijpk[l

MASS RELATIONSHIPS IN CHEMICAL REACTIONS

Chapter 4 Chemical Reactions

6 Reactions in Aqueous Solutions

We know from the information given that we have an equal mass of each compound, but no real numbers to plug in and find moles. So what can we do?

MOLES AND MOLE CALCULATIONS

Test Review # 9. Chemistry R: Form TR9.13A

Chemical Changes. Measuring a Chemical Reaction. Name(s)

Stoichiometry. Lecture Examples Answer Key

EXPERIMENT 12: Empirical Formula of a Compound

Formulae, stoichiometry and the mole concept

Appendix D. Reaction Stoichiometry D.1 INTRODUCTION

Chem 115 POGIL Worksheet - Week 4 Moles & Stoichiometry

Atomic mass is the mass of an atom in atomic mass units (amu)

Name Date Class CHEMICAL QUANTITIES. SECTION 10.1 THE MOLE: A MEASUREMENT OF MATTER (pages )

Transcription:

Unit 5 The Mole S

The Mole S We are familiar with using a specific term to represent a number of items in a group. S 1 dozen = 12 units of something S 1 case of Cokes = 24 Cokes S In chemistry we use the term MOLE to indicate a collection of particles that = 6.02 x 10 23 S 6.02 x 10 23 is referred to as Avogadro s number S 1 mole of an element has 6.02 x 10 23 particles

Avogadro s Number S To help you better visualize the enormous size of Avogadro's number, 6.02 x 10 23, consider the following analogies: S If we had 1 mole of rice grains, all the land area of the earth would be covered with rice to a depth of about 75 meters! (246 ft) S One mole of rice grains is more grains than the number of all grains grown since the beginning of time. S One mole of marshmallows (standard 1 in 3 size) would cover the United States to a depth of 650 miles.

Avagadro s Number S If the Mount St. Helens eruption had released a mole of particles the size of sand grains, the entire state of Washington would have been buried to a depth equal to the height of a 10-story building. S A mole of basketballs would just about fit perfectly into a ball bag the size of the earth.

The Mole S 1 mole of Aluminum = 6.02 x 10 23 atoms S 1 mole of Sulfur = 6.02 x 10 23 atoms S 1 mole of Water (H 2 O) = 6.02 x 10 23 molecules of H 2 O S 1 mole of NaCl = 6.02 x 10 23 molecules of NaCl

The Mole S We can use Avogadro s number to convert between the number of moles of a substance and the number of particles it contains. S If you have 4.00 moles of Sulfur (S), how many particles of S do you have? S 4.00 moles S x 6.02 x 10 23 S atoms = 2.41 x 10 24 S atoms 1 mole S atoms S If you have 3.01 x 10 24 molecules of CO 2 how many moles of CO 2 do you have? S 3.01 x 10 24 CO 2 molecules x 1 mole CO 2 = 5.00 moles CO 2 6.02 x 10 23 CO 2 molecules

The Mole S In a chemical formula the subscript numbers indicate the number of atoms of each type of element. S Aspirin s chemical formula is C 9 H 8 O 4 S In a molecule of aspirin there would be 9 Carbon atoms, 8 Hydrogen atoms, and 4 Oxygen atoms. S These number also indicate the number of moles of each element. S Using this information, you can calculate the number actual moles of each element.

Calculating Actual Moles of an Element in a Compound S For 1.50 moles of aspirin, C 9 H 8 O 4, how many moles of Carbon, Hydrogen & Oxygen are present? S Carbon: 1.50 moles C 9 H 8 O 4 x 9 moles C = 13.5 moles C 1 mole C 9 H 8 O 4 S Hydrogen:1.50 moles C 9 H 8 O 4 x 8 moles H = 12 moles H 1 mole C 9 H 8 O 4 S Oxygen: 1.50 moles C 9 H 8 O 4 x 4 moles O = 6 moles O 1 mole C 9 H 8 O 4 S How many moles of aspirin contain 0.480 moles of O atoms?

Molar Mass S For any element, the quantity called MOLAR MASS is the quantity in grams that equals the atomic mass of that element. S Atomic mass of C = 12.01 S Atomic mass of Ag = 107.9 S Atomic mass of S = 32.07 12.01 g C = 1 mole C 107.9 g Ag = 1 mole C 32.07 g S = 1 mole S

Molar Mass of a Compound S Molar mass of a compound is the sum of the molar mass of each element multiplied by the number of atoms in the compound. S Atomic mass SO 3 = Mass of S + 3 (Mass of O) = 32.07 g + 3 (16.0 g) = 80.1 g = 1 mole SO 3 S Atomic mass NaCl = Mass of Na + Mass of Cl = 22.99 g + 35.45 g = 58.44 g = 1 mole NaCl

Calculations Using Molar Mass S You can use the molar mass to change from moles of a substance to grams or from grams to moles. S If a piece of jewelry requires 0.750 moles Ag, how many grams of silver are needed? S 1 mole Ag = 107.9 g of Ag S 0.750 moles Ag x 107.9 g Ag = 80.93 g Ag 1 mole Ag

Calculations Using Molar Mass S A box of salt contains 737 g NaCl. How many moles of NaCl are present in that box? S 1 mole NaCl = 58.44 g NaCl S 737 g NaCl x 1 mole NaCl = 12.6 mole NaCl 58.44 g NaCl

Physical vs. Chemical Changes S What type of change did we see when water boiled? S Physical Change S Altered the appearance but not the formula S If physical change only changes appearance (physical properties), what other changes can happen? S Chemical change S Substances are changed on a molecular level to create new substances S Example: Our reaction to produce elephant toothpaste

Chemical Reactions S Chemical reactions produce chemical change. S Bonds between elements are broken and new bonds are formed. S Example: Alka Seltzer in Water: S NaHCO 3 (Sodium Hydrogen Carbonate) and C 6 H 8 O 7 (Citric Acid) react to form CO 2 and other products. S Evidence of chemical reactions: S Change in color S Formation of a gas (bubbles) S Formation of a solid (precipitate) S Heat (or a flame) produced or heat absorbed

Chemical Equations S Chemical equations are like a recipe that tells us the materials we need and what will be produced. S If you were going to make a cake: S Flour + Eggs + Sugar + Milk Cake S A simple chemical equation is similar. If you burn charcoal in a BBQ pit: S C (s) + O 2 (g) CO 2 (g) S C & O are called reactants S CO 2 is product S Abbreviations in parenthesis represent the physical state

Chemical Equations S Every chemical equation must be BALANCED meaning the number of atoms of reactants must equal the number of atoms of products. S H 2 (g) + O 2 (g) H 2 O (g) S Products: 2 atoms H, 2 atoms O S Reactants: 2 atoms H, 1 atom O S Is this balanced? S Balanced Equation: 2H 2 (g) + O 2 (g) 2H 2 O (g) S Coefficients are placed in front of the formulas S These multiply the formula by the number of the coefficient.

Types of Reactions S Most reactions fit into 4 general reaction types: S 1. Combination Reactions- two or more elements combine to form one product. S S (s) + O (g) SO 2 (g) S 2. Decomposition Reactions- a reactant splits into two or more simpler products. S 2HgO (s) 2Hg (l) + O 2 (g)

Types of Reactions S 3. Replacement Reactions elements in a compound are replaced by other elements. S Two Types: S Single Replacement a reacting element switches places with an element in the other reacting compound S A + BC AC + B S Zn (s) + 2HCl (aq) ZnCl 2 (aq) + H 2 (g) S Double Replacement the positive ions in the reacting compounds switch places. S AB + CD AD + CB S BaCl 2 (aq) + Na 2 SO 4 (aq) BaSO 4 (s) + 2NaCl (aq)