Magnetic Field and Magnetic Forces. Young and Freedman Chapter 27



Similar documents
Deflection of Electrons by Electric and Magnetic Fields

AP Physics Electromagnetic Wrap Up

Gauss Law. Physics 231 Lecture 2-1

Forces & Magnetic Dipoles. r r τ = μ B r

FXA Candidates should be able to : Describe how a mass creates a gravitational field in the space around it.

Determining solar characteristics using planetary data

Vector Calculus: Are you ready? Vectors in 2D and 3D Space: Review

Solution Derivations for Capa #8

Charges, Coulomb s Law, and Electric Fields

The force between electric charges. Comparing gravity and the interaction between charges. Coulomb s Law. Forces between two charges

Chapter 22. Outside a uniformly charged sphere, the field looks like that of a point charge at the center of the sphere.

The Role of Gravity in Orbital Motion

Physics 235 Chapter 5. Chapter 5 Gravitation

Voltage ( = Electric Potential )

Chapter 30: Magnetic Fields Due to Currents

The Electric Potential, Electric Potential Energy and Energy Conservation. V = U/q 0. V = U/q 0 = -W/q 0 1V [Volt] =1 Nm/C

Voltage ( = Electric Potential )

2 r2 θ = r2 t. (3.59) The equal area law is the statement that the term in parentheses,

Uniform Rectilinear Motion

Lesson 7 Gauss s Law and Electric Fields

Displacement, Velocity And Acceleration

Experiment 6: Centripetal Force

12. Rolling, Torque, and Angular Momentum

Gravitation. AP Physics C

Exam 3: Equation Summary

Mechanics 1: Work, Power and Kinetic Energy

Multiple choice questions [70 points]

2. Orbital dynamics and tides

PHYSICS 111 HOMEWORK SOLUTION #13. May 1, 2013

Chapter 4: Fluid Kinematics

7 Circular Motion. 7-1 Centripetal Acceleration and Force. Period, Frequency, and Speed. Vocabulary

Moment and couple. In 3-D, because the determination of the distance can be tedious, a vector approach becomes advantageous. r r

Phys 2101 Gabriela González. cos. sin. sin

Episode 401: Newton s law of universal gravitation

Lesson 8 Ampère s Law and Differential Operators

PY1052 Problem Set 8 Autumn 2004 Solutions

A r. (Can you see that this just gives the formula we had above?)

10. Collisions. Before During After

(a) The centripetal acceleration of a point on the equator of the Earth is given by v2. The velocity of the earth can be found by taking the ratio of

Lab M4: The Torsional Pendulum and Moment of Inertia

Experiment MF Magnetic Force

Gravitation and Kepler s Laws Newton s Law of Universal Gravitation in vectorial. Gm 1 m 2. r 2

Fluids Lecture 15 Notes

Spirotechnics! September 7, Amanda Zeringue, Michael Spannuth and Amanda Zeringue Dierential Geometry Project

TORQUE AND ANGULAR MOMENTUM IN CIRCULAR MOTION

Chapter 19: Electric Charges, Forces, and Fields ( ) ( 6 )( 6

Figure 2. So it is very likely that the Babylonians attributed 60 units to each side of the hexagon. Its resulting perimeter would then be 360!

Chapter 2. Electrostatics

F G r. Don't confuse G with g: "Big G" and "little g" are totally different things.

UNIT CIRCLE TRIGONOMETRY

Chapter 17 The Kepler Problem: Planetary Mechanics and the Bohr Atom

SELF-INDUCTANCE AND INDUCTORS

8.4. Motion of Charged Particles in Magnetic Fields

VISCOSITY OF BIO-DIESEL FUELS

Skills Needed for Success in Calculus 1

Lab #7: Energy Conservation

Introduction to Fluid Mechanics

Mechanics 1: Motion in a Central Force Field

CHAPTER 5 GRAVITATIONAL FIELD AND POTENTIAL

TECHNICAL DATA. JIS (Japanese Industrial Standard) Screw Thread. Specifications

4a 4ab b (count number of places from first non-zero digit to

Solutions for Physics 1301 Course Review (Problems 10 through 18)

Gravity. A. Law of Gravity. Gravity. Physics: Mechanics. A. The Law of Gravity. Dr. Bill Pezzaglia. B. Gravitational Field. C.

Physics HSC Course Stage 6. Space. Part 1: Earth s gravitational field

Multiple choice questions [60 points]

4.1 - Trigonometric Functions of Acute Angles

Chapter 4: Fluid Kinematics

Carter-Penrose diagrams and black holes


AN IMPLEMENTATION OF BINARY AND FLOATING POINT CHROMOSOME REPRESENTATION IN GENETIC ALGORITHM

Electrostatic properties of conductors and dielectrics

GAUSS S LAW APPLIED TO CYLINDRICAL AND PLANAR CHARGE DISTRIBUTIONS ` E MISN CHARGE DISTRIBUTIONS by Peter Signell, Michigan State University

Coordinate Systems L. M. Kalnins, March 2009

YARN PROPERTIES MEASUREMENT: AN OPTICAL APPROACH

1240 ev nm 2.5 ev. (4) r 2 or mv 2 = ke2

Pearson Physics Level 30 Unit VI Forces and Fields: Chapter 10 Solutions

Physics Core Topic 9.2 Space

Valuation of Floating Rate Bonds 1

Lecture 16: Color and Intensity. and he made him a coat of many colours. Genesis 37:3

Gravitational Mechanics of the Mars-Phobos System: Comparing Methods of Orbital Dynamics Modeling for Exploratory Mission Planning

Do Vibrations Make Sound?

Chapter 3 Savings, Present Value and Ricardian Equivalence

NUCLEAR MAGNETIC RESONANCE

Magnetic Bearing with Radial Magnetized Permanent Magnets

NURBS Drawing Week 5, Lecture 10

Graphs of Equations. A coordinate system is a way to graphically show the relationship between 2 quantities.

An Epidemic Model of Mobile Phone Virus

Problems of the 2 nd and 9 th International Physics Olympiads (Budapest, Hungary, 1968 and 1976)

PY106 Class13. Permanent Magnets. Magnetic Fields and Forces on Moving Charges. Interactions between magnetic north and south poles.

Model Question Paper Mathematics Class XII

Worked Examples. v max =?

Quantity Formula Meaning of variables. 5 C 1 32 F 5 degrees Fahrenheit, 1 bh A 5 area, b 5 base, h 5 height. P 5 2l 1 2w

An Introduction to Omega

SHORT REVISION SOLUTIONS OF TRIANGLE

Structure and evolution of circumstellar disks during the early phase of accretion from a parent cloud

Chapter 29: Magnetic Fields

DYNAMICS AND STRUCTURAL LOADING IN WIND TURBINES

Continuous Compounding and Annualization

Transcription:

Magnetic Field and Magnetic Foces Young and Feedman Chapte 27

Intoduction Reiew - electic fields 1) A chage (o collection of chages) poduces an electic field in the space aound it. 2) The electic field exets a foce on any othe chage q that is pesent in the field. What is coming up fo magnetic fields 1. A MOVING chage (o chages) poduce a magnetic field in the space aound it. 2. The magnetic field exets a foce on any othe MOVING chage o cuent that is pesent in the field.

Some Simple Phenomenology

The wold is a big magnet

Magnetic and Electic Foces Just Replace + & - with N & S???? This is an extemely good idea that is, unfotunately WRONG The basic poblem is that thee ae no Fee N & S poles.

Basic elationship between electic fields and magnetic cuents Demonstated in Oested s Expeiment Place a compass nea a wie N Compass deflects when an electic cuent flows in the wie

Motion of a chaged paticle in a magnetic field 1. A moing chage o a electic cuent poduces a magnetic field in the suounding space (It also poduces an electic field) 2. The magnetic field exets a foce on any othe moing chage o cuent that is in the field. Stategy: We will begin with a discussion of the foce on a moing chage (pat 2.) Then we will discuss how a moing chage makes the field (pat 1.)

Some examples of the foce on a moing chage in a magnetic field obseation #1- The magnetic foce is always pependicula to the magnetic field obseation #2- The magnetic foce is always pependicula to the paticle elocity

Magnetic Foces Fou obseations about a chage q moing in a magnetic field B The foce is: popotional to the chage q popotional to the elocity pependicula to both and B popotional to sinφ, whee φ is the angle between and B This can be summaized as: F = q " B The symbol epesents a coss poduct (not a multiplication) of the elocity ecto of the chaged paticle and the magnetic field ecto.

Moe on magnetic foces The magnetic foce is zeo if the elocity is eithe paallel o anti-paallel to the magnetic field. sin(0) = sin(180) = 0 The foce has its maximum alue when the elocity and magnetic field ae pependicula sin(90) = 1 The foce on a negatie chage is in the opposite diection

The ecto o coss poduct If C = A B then the magnitude of C = A B sin, whee θ is the angle between A and B. The diection of C is gien by the Right Hand Rule : Adice on using the Right Hand Rule: 1) Fist detemine the plane that contains A and B. The coss poduct will point pependicula to that plane. Thee ae only two choices. 2) Use the Right Hand Rule to pick which choice is coect. 3) If you ae using F = q B, Remembe that a negatie chage will eese the diection of the coss poduct

F Magnetic Foce and Magnetic Field = q " B F = q B Units of Magnetic Field: 1 Tesla = 1 T = 1 Newton/(Ampee mete) 10-4 T =1 Gauss ~ Magnetic field of the eath A steady 50 T field is ey lage (about the lagest possible today in a lab). The suface of a neuton sta is belieed to be ~10 8 T

Example A unifom magnetic field points into the sceen. The diection is indicated by the cosses, dots would be coming out of the sceen (imagine aows, you see the tail feathes, not the points). A positie chage moes fom point A to point C, the diection of the magnetic foce is: a) up and ight, b) up and left, c) down and ight, d) down and left

A unifom magnetic field points into the sceen. Example A positie chage moes fom point A to point C, the diection of the magnetic foce is: a) up and ight, b) up and left, c) down and ight, d) down and left The magnetic foce is gien by F = q B The coss poduce of the elocity and the magnetic field ecto is up and to the left. As the chage is positie, the foce is in the same diection

Motion of chaged paticles in EM fields F = F = ma q( E + B) + d = m dt 2 2 EM foce Loentz Foce Newton s 2 nd Law d q[ E( ) + B( )] = dt m d dt 2 2 Diffeential equation (t) Solution = Equation of Motion Fo constant foce thee ae two impotant simple cases: F is paallel to F is pependicula to Unifom linea acceleation + at Unifom cicula motion = 0

Unifom cicula motion (see Y&F chapte 3) Simila tiangles (i.e. same angle) gies t s R t s R R s = = = 1 1 1 Aeage acceleation R a t s R t a t t 2 0 1 0 lim lim = = = " " Unifom Cicula Motion implies a acceleation that is always diected towads the cente of the cicle. Amplitude of acceleation is constant: Diection of acceleation changes with time R m m a F 2 = =

Angula Velocity (see Y& F chapte 9) Unifom Cicula Motion is descibed by an Angula Velocity Since = s = 2 a = = F = m 2 Fequency Peiod and 2 2 = m f T " = 2 1 = f = ds dt " Angula Velocity (adians/s) cycles/s=hetz seconds " = d dt

Angula elocity as a ecto

Motion due to a Magnetic Foce What is the motion like if the elocity is not pependicula to B? Beak up the elocity into components along the magnetic field and pependicula to it The component pependicula will still poduce cicula motion The component paallel will poduce no foce, and this motion will be unaffected The combination of these two types of motion esult in a helical motion

Velocity Selecto A neat deice fo selecting ions by thei elocities (actually used in eseach) has cossed electic and magnetic fields. A chaged paticle (ion) expeiences both the E and the B field. The foces acting on the ion ae: F E = qe F B = q " B Fo a positie chage, foce due the electic field is to the left and foce due to the magnetic field is to the ight If the elocity of the ion is pecisely ight then the foces cancel out F E = F B = E B

Thomson s e/m Expeiment (1897) J.J. Thomson used the idea of a elocity selecto to measue the atio of chage to mass fo the electon. The hot cathode eleases electons which ae acceleated towads the two anodes. 1 2 m2 = ev = E B e m = E 2 2VB 2 Measue E,V and B, find e/m = 1.7588 x 10 11 C/kg egadless of mateial on cathode. Discoey of the electon

Magnetic foce on a cuent-caying conducto We e seen that thee is a foce on a chage moing in a magnetic field Now we e going to conside multiple chages moing togethe, such as a cuent in a conducto We stat with a wie of length l and coss section aea A in a magnetic field of stength B with the chages haing a dift elocity of d. The total numbe of chages in this section is then nal whee n is the chage density. The foce on a single chage is gien by F=q d B. So, the total foce on this segment is: F = nq d AlB

Magnetic foce on a cuent-caying conducto We e found: F = nq d AlB; howee we aleady know J=nq d. So F=JAIB = IlB The foce is popotional to the cuent though the wie, the length of the wie in the field and the magnetic field stength

Magnetic foce on a cuent-caying conducto But what if the magnetic field and the wie ae not pependicula? Only the component of B ( B " = Bsin# ) pependicula to the wie exets a foce. F = IlB " F = IlBsin# F = Il $ B