Finite Element Formulation for Beams - Handout 2 -



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Finite Element Formulation for Beams - Handout 2 - Dr Fehmi Cirak (fc286@) Completed Version

Review of Euler-Bernoulli Beam Physical beam model midline Beam domain in three-dimensions Midline, also called the neutral axis, has the coordinate Key assumptions: beam axis is in its unloaded configuration straight Loads are normal to the beam axis Page 25

Kinematics of Euler-Bernoulli Beam -1- Assumed displacements during loading deformed configuration reference configuration Kinematic assumption: Material points on the normal to the midline remain on the normal during the deformation Slope of midline: The kinematic assumption determines the axial displacement of the material points across thickness Note this is valid only for small deflections, else Page 26

Kinematics of Euler-Bernoulli Beam -2- Introducing the displacements into the strain equations of threedimensional elasticity leads to Axial strains Axial strains vary linearly across thickness All other strain components are zero Shear strain in the Through-the-thickness strain (no stretching of the midline normal during deformation) No deformations in and planes so that the corresponding strains are zero Page 27

Weak Form of Euler-Bernoulli Beam The beam strains introduced into the internal virtual work expression of three-dimensional elasticity with the standard definition of bending moment: External virtual work Weak work of beam equation Boundary terms only present if force/moment boundary conditions present Page 28

Stress-Strain Law The only non-zero stress component is given by Hooke s law This leads to the usual relationship between the moment and curvature with the second moment of area Weak form work as will be used for FE discretization EI assumed to be constant Page 29

Finite Element Method Beam is represented as a (disjoint) collection of finite elements On each element displacements and the test function are interpolated using shape functions and the corresponding nodal values Number of nodes per element Shape function of node K Nodal values of displacements Nodal values of test functions To obtain the FE equations the preceding interpolation equations are introduced into the weak form Note that the integrals in the weak form depend on the second order derivatives of u 3 and v Page 30

Aside: Smoothness of Functions A function f: Ω R is of class C k =C k (Ω) if its derivatives of order j, where 0 j k, exist and are continuous functions For example, a C 0 function is simply a continuous function For example, a C function is a function with all the derivatives continuous C 0 -continuous function C 1 -continuous function differentiation Page 31 The shape functions for the Euler-Bernoulli beam have to be C 1 -continuous so that their second order derivatives in the weak form can be integrated

Hermite Interpolation -1- To achieve C 1 -smoothness Hermite shape functions can be used Hermite shape functions for an element of length Shape functions of node 1 with Page 32

Hermite Interpolation -2- Shape functions of Node 2 with Page 33

Element Stiffness Matrix According to Hermite interpolation the degrees of freedom for each element are the displacements and slopes at the two nodes Interpolation of the displacements Test functions are interpolated in the same way like displacements Introducing the displacement and test functions interpolations into weak form gives the element stiffness matris Page 34

Element Load Vector Load vector computation analogous to the stiffness matrix derivation The global stiffness matrix and the global load vector are obtained by assembling the individual element contributions The assembly procedure is identical to usual finite elements Global stiffness matrix Global load vector All nodal displacements and rotations Page 35

Stiffness Matrix of Euler-Bernoulli Beam Element stiffness matrix of an element with length l e Page 36

Kinematics of Timoshenko Beam -1- Assumed displacements during loading deformed configuration reference configuration Kinematic assumption: a plane section originally normal to the centroid remains plane, but in addition also shear deformations occur Rotation angle of the normal: Angle of shearing: Slope of midline: The kinematic assumption determines the axial displacement of the material points across thickness Note that this is only valid for small rotations, else Page 37

Kinematics of Timoshenko Beam -2- Introducing the displacements into the strain equations of threedimensional elasticity leads to Axial strain Axial strain varies linearly across thickness Shear strain Shear strain is constant across thickness All the other strain components are zero Page 38

Weak Form of Timoshenko Beam The beam strains introduced into the internal virtual work expression of three-dimensional elasticity give Hookes s law Introducing the expressions for strain and Hooke s law into the weak form gives virtual displacements and rotations: shear correction factor necessary because across thickness shear stresses are parabolic according to elasticity theory but constant according to Timoshenko beam theory shear correction factor for a rectangular cross section shear modulus External virtual work similar to Euler-Bernoulli beam Page 39

Euler-Bernoulli vs. Timoshenko -1- Comparison of the displacements of a cantilever beam analytically computed with the Euler-Bernoulli and Timoshenko beam theories Bernoulli beam Governing equation: Boundary conditions: Timoshenko beam Governing equations: Boundary conditions: Page 40

Euler-Bernoulli vs. Timoshenko -2- Maximum tip deflection computed by integrating the differential equations Bernoulli beam Timoshenko beam Ratio For slender beams (L/t > 20) both theories give the same result For stocky beams (Lt < 10) Timoshenko beam is physically more realistic because it includes the shear deformations Page 41

Finite Element Discretization The weak form essentially contains and the corresponding test functions C 0 interpolation appears to be sufficient, e.g. linear interpolation Interpolation of displacements and rotation angle Page 42

Element Stiffness Matrix Shear angle Curvature Test functions are interpolated in the same way like displacements and rotations Introducing the interpolations into the weak form leads to the element stiffness matrices Shear component of the stiffness matrix Bending component of the stiffness matrix Page 43

Review: Numerical Integration Gaussian Quadrature The locations of the quadrature points and weights are determined for maximum accuracy n int =1 n int =2 n int =3 Note that polynomials with order (2n int -1) or less are exactly integrated The element domain is usually different from [-1,+1) and an isoparametric mapping can be used Page 44

Stiffness Matrix of the Timoshenko Beam -1- Necessary number of quadrature points for linear shape functions Bending stiffness: one integration point sufficient because is constant Shear stiffness: two integration points necessary because is linear Element bending stiffness matrix of an element with length l e and one integration point Element shear stiffness matrix of an element with length l e and two integration points Page 45

Limitations of the Timoshenko Beam FE Recap: Degrees of freedom for the Timoshenko beam Physics dictates that for t 0 (so-called Euler-Bernoulli limit) the shear angle has to go to zero ( ) If linear shape functions are used for u 3 and β Adding a constant and a linear function will never give zero! Hence, since the shear strains cannot be arbitrarily small everywhere, an erroneous shear strain energy will be included in the energy balance In practice, the computed finite element displacements will be much smaller than the exact solution Page 46

Shear Locking: Example -1- Displacements of a cantilever beam TWO integration points Influence of the beam thickness on the normalized tip displacement Thick beam # elem. 2 point 1 0.0416 2 0.445 4 0.762 8 0.927 Thin beam # elem. 2 point 1 0.0002 2 0.0008 4 0.0003 8 0.0013 from TJR Hughes, The finite element method. Page 47

Stiffness Matrix of the Timoshenko Beam -2- The beam element with only linear shape functions appears not to be ideal for very thin beams The problem is caused by non-matching u 3 and β interpolation For very thin beams it is not possible to reproduce How can we fix this problem? Lets try with using only one integration point for integrating the element shear stiffness matrix Element shear stiffness matrix of an element with length l e and one integration points Page 48

Shear Locking: Example -2- Displacements of a cantilever beam ONE integration point Influence of the beam thickness on the normalized displacement Thick beam Thin beam # elem. 1 2 4 8 1 point 0.762 0.940 0.985 0.996 # elem. 1 2 4 8 1 point 0.750 0.938 0.984 0.996 from TJR Hughes, The finite element method. Page 49

Reduced Integration Beam Elements If the displacements and rotations are interpolated with the same shape functions, there is tendency to lock (too stiff numerical behavior) Reduced integration is the most basic engineering approach to resolve this problem Shape function order Linear Quadratic Cubic Quadrature rule One-point Two-point Three-point Mathematically more rigorous approaches: Mixed variational principles based e.g. on the Hellinger-Reissner functional Page 50