Ph\sics 2210 Fall Novcmbcr 21 David Ailion

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Brittney Wood
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1 Ph\sics 2210 Fall Novcmbcr 21 David Ailion Unid: Discussion T A: Bryant Justin Will Yuan 1 Place answers in box provided for each question. Specify units for each answer. Circle correct answer(s) for each question! A. [5 pts.] Which of the following are true. Circle all correct answers. ~ (d) (e) Simple harmonic motion is always due to the oscillatory (back and forth) motion of springs. Gravitational forces may result in simple harmonic motion. The angular frequency of a mass m attached to a spring of spring constant k in a container containing a viscous medium is given by ro ::;.Jk 1m. A physical pendulum consisting of a large uniform stick ofmass m is oscillating with an angular frequency ro about a pivot point near one end. Ifthe pivot point is changed to the center ofmass the angular frequency will be unchanged because the moment of inertia the mass m and the length ofthe stick are all unchanged. None of the above are true. B. [5 pts.] Which ofthe following are true. Circle all correct answers. ~ (d) (e) A figure skater brings in her arms to increase her moment of inertia. The direction ofthe torque vector is always perpendicular to the force that created it. It is possibie for the angular momentum to vary with time even if the external torque is zero (and constant). The reason that we can use conservation ofenergy for a rolling wheel is that the friction force does not result in a torque about the center of mass. All ofthe above are false. C. [5 pis'] In an isolated system oftwo bodies that exert gravitational forces on one another and move in elliptical orbits which ofthe following remain constant? The total energy of the system. ~ The total angular momentum ofthe system. The speed ofeach body. (d) The gravitational force between the two bodies. (e) None of the above.

~ (d) (e) Simple harmonic motion is always due to the oscillatory (back and forth) motion of springs. Gravitational forces may result in simple harmonic motion.

2 Ph~sics 2210 Fall No\cmbcl' 21 David Ailion Unid: Discussion T A: Bryant Justin Will Yuan Final Exanl Place a circle or box around each answer. Specity units for each answer. Problem 1 - Continued - Place answers in box D. [5 pts.} Calculate the value of g for a 2.1 kg mass at a height 1.32 x 10 4 km above the earth's surface. ~ 'J::: q ~ fvlc ~~ - E. [5 pts.} A spring ofspring constant k is attached to a fixed point P on a smooth inclined plane ofangle e=30. When a mass m = 2.4 kg is attached to the spring p as shown the spring stretches by 4.8 cm. Calculate k in SI units.

1 kg mass at a height 1.32 x 10 4 km above the earth's surface. ~ 'J::: q ~ fvlc ~~ - E. [5 pts.

3 )::1\ id Ailion Vnid: Discussion TA: Bryant Justin Will Yuan 2 Place a circle or box around each answer. Specify units for each answer. A playground is on the flat roof of a city school 7.00 m above the street below. The vertical wall ofthe building is 8.00 m high forming a 1.00 m high railing around the I playground. A ball has fallen to the street below and a passerby returns it by I launching it at an angle of 53.0 above the horizontal at a point 27.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. I... --~..-- tl ti " h... I (a) [7 pts.] Find the speed at which the ball was launched. (b [7pts.} Find the vertical distance h by which the ball clears the wall..~ [6pts.} Find the distance d from the wall to the point on the roof where the ball lands. d

A ball has fallen to the street below and a passerby returns it by I launching it at an angle of 53.0 above the horizontal at a point 27.0 m from the base of the building wall. The ball takes 2.

4 Name: _-=""""-'''--=- --'-'-.>-- Vnid: Discussion TA: Bryant Justin Will Yuan 3 Place a circle or box around each answer. Specify units for each answer. A physical pendulum consists of a solid sphere and a rod that is rigidly attached to the sphere at point Q directly opposite to the pivot point P. The sphere has radius r and mass m and the rod has length L and mass M.

5 Name: ~_.G\A)_~~'_>_~-'-"~~._ Unid: Discussion TA: Bryant Justin Will Yuan 4 )a"id Ailion Place a circle or box around each answer. SpecifY units for each answer. A block of mass m = 0.20 kg is at rest at the height h = 4.0 m on a smooth inclined plane as shown. It slides down onto a frictionless surface and collides inelastically with a second block of identical mass. The velocity of the first block immediately after the collision is 1/3 its velocity immediately before the collision and is in the same direction. The floor to the right ofthe second block is rough with a coefficient of kinetic friction /lk = As result the second block slides a distance d before coming to rest. (a) (b)

It slides down onto a frictionless surface and collides inelastically with a second block of identical mass.

6 Name: ~~----~~~ Unid: Discussion T A: Bryant Justin Will Yuan 5 Final EXam Place a circle or box around each answer. Specify units for each answer. In class Adam did a demonstration in which he shot an arrow ofmass m 330 gm horizontally into a block ofmass M 5.00 kg which was suspended a distance L = 75 cm below a pivot point P. The arrow was embedded in the block and the system swung upwards such that the maximum horizontal displacement ~x was observed to be 15 cm. Treat the arrow as a point mass. m =-+ M p (a) (b) \ <\ \ [7 pis.] Calculate the maximum kinetic energy ofthe system consisting ofthe arrow embedded in the block. [7 pis.} Calculate the velocity ofthe arrow immediately before it struck the block. [6 pis.] Calculate the angular momentum ofthe arrow relative to the axis ofrotation immediately before impact. Will this be the same as the angular momentum of the system immediately after impact? Explain.

$m =-+ M p (a) (b) \ <\ \ [7 pis.] Calculate the maximum kinetic energy ofthe system consisting ofthe arrow embedded in the block. [7 pis.} Calculate the velocity ofthe arrow immediately before it struck the block.$

Exam 2 is at 7 pm tomorrow Conflict is at 5:15 pm in 151 Loomis

* By request, but I m not vouching for these since I didn t write them Exam 2 is at 7 pm tomorrow Conflict is at 5:15 pm in 151 Loomis There are extra office hours today & tomorrow Lots of practice exams