1 CHAPTER 1 Introduction and Mathematical Concepts PREVIEW In this chapter you will be introduced to the physical units most frequently encountered in physics. After completion of the chapter you will be able to convert between these systems of units and use them as an aid in problem solving. Also, after a review of trigonometry, you will become acquainted with vectors and the methods of vector addition. Upon completion of this material you should be able to add and subtract vectors graphically, decompose vectors into their components and use the components to reconstruct the vectors. Important terms QUICK REFERENCE Scalar quantity A quantity which can be described by a single number. Vector quantity A quantity which can be adequately described by a number (magnitude) and a direction. Vector components Two perpendicular vectors which added together produce the original vector. Systems of Units System Length Mass Time SI meter (m) kilogram (kg) seconds (s) BE foot (ft) slug (sl) seconds (s) CGS centimeters (cm) gram (g) seconds (s) Trigonometry sin θ = h h o (1.1) θ = sin -1 h h o (1.4) cos θ = h h a (1.2) θ = cos -1 h h a (1.5) h h tan θ = o (1.3) θ = tan -1 o ha h a (1.6)
2 h h o θ h a h 2 = ho 2 + ha 2 (1.7)
3 Graphical Addition of Vectors Vectors may be added (or subtracted) by placing them head to tail. -B A B R A R R = A + B R = A - B Components of a Vector The following expressions refer to the vector diagram shown below. A x = A cos θ A = A x 2 + Ay 2 y A y = A sin θ A y θ = tan -1 A x A y A θ A x x Addition of Vectors Using Components If C = A + B, then the components of C are: Cx = Ax + Bx Cy = Ay + By and the magnitude and direction of C are: C = C x 2 + Cy 2 C y θ = tan -1 C x where θ is measured counterclockwise from the + x axis.
5 DISCUSSION OF SELECTED SECTIONS 1.3 The Role of Units in Problem Solving Units are very important in the study of physics in that all physical quantities have units. These may be either the base units of length (m), mass (kg), and time (s), or derived units such as the joule (kg m 2 /s 2 ). When used in algebraic expressions, the units which accompany the numbers can be used to check not only the accuracy of the calculation, but also the validity of the equation. For this reason, the units will always be displayed along with the numbers in this study guide. You are encouraged to do the same in your solutions to problems. Remember, if the units do not work out, your solution is not right either. Example 1 Manipulating Units and Converting Between Systems Convert 5.00 mi/h to m/s. Conversion factors: 1 mi = 5280 ft 1 ft = m 1 km = 1000 m 1 h = 3600 s Each of the equalities above can be used to form a fraction or conversion factor that is equal to unity (i.e., equal to 1). In multiplying by unity we do not change the value of the physical quantity; we are merely expressing the same quantity in a different set of units. One side of the equality will appear in the numerator and the other side will appear in the denominator of the fraction. The specific choice will be made so that the unwanted units cancel and the desired units appear in the final answer mi/h = 5.00 mi h 5280 ft 1 mi m 1 h = 2.24 m 1 ft 3600 s s. Notice that the first conversion factor changes miles to feet, the second changes feet to meters, and the third conversion factor changes hours to seconds. Again notice that in each conversion factor, the numerator is equal to the denominator and, therefore, the conversion factor equal to unity. Example 2 Another Look at Converting Units Convert 2.00 mi2 to ft2. We will start with the fact that 1 mi = 5280 ft. In setting up the conversion factor as a fraction equal to unity, however, we must square the fraction so that it converts square miles (mi2) to square feet (ft2) mi 2 = 2.00 mi ft 1 mi = ft 2 Notice that the conversion factor is still equal to unity (12 = 1). Also notice that the final answer is expressed in scientific notation to preserve the correct number of significant figures; three in this case.
6 Example 3 Using Units to Check Equations An equation which may result from the application of the conservation of energy principle is 1 mv 2 = mgh 2 where m is a mass with the units of kg, v is a velocity with the units of m/s, g is an acceleration with the units of m/s 2 and h is a height with the units of m. This equation may be checked for validity by simply substituting the units into it and manipulating them as if they were numbers. If the units on the right and left side of the equation do not match, the equation is definitely NOT VALID. (kg) ( m s ) 2 = (kg) ( m s 2 ) (m) ( ) ( ) (kg) m2 s 2 = (kg) m2 s 2 kg m 2 s 2 = kg m 2 s 2 In this case, the units on each side of the equation do match and the equation may be a valid one. This procedure does NOT guarantee that the equation has any "true" meaning, however. By the way, the above combination of units appear so often in physics that they are given the special name of joules (J). This is the unit of ENERGY. 1.4 Trigonometry Most likely, you have already become acquainted with the basic trigonometric functions in a high school or college course. These can be found in the Quick Reference section of this book. Many times the use of the "trig" functions in physics involve finding the length of one side of a right triangle when you know one other side and one of the acute angles. This is particularly important in finding the components of a vector which will be studied in the next section. Other variations are, of course, possible and useful. For instance, if two sides of a right triangle are known, then the trigonometric functions can be used to find the angle. Example 4 Finding one side of a right triangle if one other side and an angle are known An observer, whose eyes are 6.0 ft above the ground, is standing 105 ft away from a tree. The ground is level, and the tree is growing perpendicular to it. The observer's line of sight with the tree top makes an angle of 20.0 above the horizontal. How tall is the tree? The observer's eye, the tree top, and a point on the trunk are the vertices of a right triangle. The height of the tree is H = 6.0 ft + ho
7 Now ho can be found from the right triangle by using equation (1.3) h θ h o H h a ho = ha tan θ = (105 ft) tan 20.0 = 38.2 ft. H = 6.0 ft ft = 44.2 ft. Another common need in physics is to find one side of a triangle when the other two sides are known but no acute angle is given. Then you should use the Pythagorean theorem (1.7) or one of its variants. Example 5 Using the Pythagorean theorem In the previous example, it is desired to know the straight line distance from the person's eye to the top of the tree. The Pythagorean theorem gives h = h ha 2 = (105 ft) 2 + (38.2 ft) 2 = 112 ft. 1.6 Vector Addition and Subtraction If vectors are colinear, then they may be added or subtracted by simply adding or subtracting their magnitudes. The directions of the vectors are usually specified by calling a vector pointing to the right (or up) positive and a vector pointing to the left (or down) negative. Then the sign of the resultant vector tells which way it points. Example 6 Adding and subtracting colinear vectors Find the resultant, C, of the following vectors (u is an arbitrary unit). Case 1 Case 2 A = +3.0 u A = +3.0 u B = +2.0 u B = -2.0 u In both cases the vectors are colinear. One could imagine placing the vectors A and B in a "tail-to-head" fashion. In case 1, both A and B point in the same direction. The resultant vector will have a magnitude equal to the length of A plus the length of B. Since both vectors are directed to the right, the resultant will also point to the right. In case 2, the vectors A and B point in opposite directions. If they are placed in a tail-to-head fashion it will be clear
8 that part of A is canceled by B. The resultant will have a magnitude that is equal to the magnitude of A minus the magnitude of B. Since A has the greater magnitude, the resultant will point in the direction of A. The resultant C is shown below for both cases. Case 1 Case 2 C = +5.0 u C = +1.0 u When vectors are not colinear but perpendicular, they may be added by using the Pythagorean theorem and the tangent function. This method yields the magnitude and direction of the resultant vector as a number and an angle. Example 7 Adding perpendicular vectors Find the resultant, C, of the vectors shown where A = u and B = u. The resultant is C = A + B as shown in the diagram. Notice that it was constructed by placing the vectors A and B in a "tail-to-head" fashion and then connecting the "head" of A to the "tail" of B. The length of the resultant vector, C, is given by the Pythagorean theorem to be C = A 2 + B 2 C = (2.0 u) 2 + (5.0 u) 2 C = 5.4 u. C A θ B The direction of C, as specified by the angle, θ, is given by (1.6) to be θ = tan -1 A B = tan u 5.0 u = 22 o. Now C = 5.4 u, 22 counterclockwise from B.
9 1.7 The Components of a Vector As you might infer from the preceding example, any vector, C, may be expressed as the sum of two perpendicular vectors. When these perpendicular vectors are placed along the x and y axes of a Cartesian coordinate system, they are referred to as the x and y components (Cx and Cy) of the vector. The components of a vector may be found by using a vector diagram similar to the above and equations (1.1) and (1.2). Please keep in mind that if equations (1.1) and (1.2) are used to find the components of a vector, the angle, θ, is defined as being measured from the x axis. Example 8 Finding the components of a vector Find the components of the vector A = 5.0 u, θ = 30. An application of (1.2) to the vector shown in the figure gives Ax = A cos θ = (5.0 u) cos 30 Ax = 4.3 u. A similar application of (1.1) gives Ay = A sin θ = (5.0 u) sin 30 Ay = 2.5 u. y A y A θ A x x Sometimes you will encounter situations where you will need to find the x and y components of a vector, but the angle given, φ, is NOT measured from the x axis. In this case, the components may NOT be given by Ax = A cos φ and Ay = A sin φ. You now have two choices. You may either find the angle, φ, in terms of the angle, θ, or you may try to find a different right triangle in which to apply equations (1.1) and (1.2). Example 9 Finding the components of a vector when the angle is not measured from the +x axis Find the x and y components of the vector, A, whose magnitude is 10.0 u and which makes an angle of 45 with the +y axis. Refer to the figure shown. We may use Ax = A cos θ and Ay = A sin θ if we can find the angle, θ. From the figure it is seen that
10 θ = 90 + φ so that θ = = 135. A x y A y A φ θ x Now Ax = (10.0 u) cos 135 Ax = u Ay = (10.0 u) sin 135 Ay = u. We may also apply equations (1.1) and (1.2) to the right triangle shown in the figure to obtain and Ax = - A sin φ = - (10.0 u) sin 45 = u Ay = + A cos φ = + (10.0 u) cos 45 = u. 1.8 Addition of Vectors by Means of Components Since like components of two or more vectors are colinear, they may simply be added, as in example 6, to give the corresponding component of the resultant vector. In this way, all of the components of the resultant vector may be found. The magnitude and direction of the resultant vector may then be determined by equations (1.3) and (1.7). Example 10 Adding vectors by the component method Add the vectors A, B, and C shown in the figure using the component method. A = 5.0 m, B = 7.0 m and C = 4.0 m. An application of equations (1.1) and (1.2) to each of the triangles shown in the figure gives Ax = + A cos 20 Ax = + (5.0 m) cos 20 Ax = m. Bx = - B cos 40
11 Bx = - (7.0 m) cos 40 Bx = m. Cx = + C sin 25 Cx = + (4.0 m) sin 25 Cx = m. y B 40 A 20 C x 25 The x component of the resultant vector is Rx = Ax + Bx + Cx Rx = 4.7 m m m Rx = 1.0 m. Repeating the above for the y component gives Ay = + A sin 20 = + (5.0 m) sin 20 = m. By = + B sin 40 = + (7.0 m) sin 40 = m. Cy = - C cos 25 = - (4.0 m) cos 25 = m. The y component of the resultant vector is Ry = Ay + By + Cy = 1.7 m m m Ry = 2.6 m. Now the magnitude of the resultant can be found from the Pythagorean theorem R = R x 2 + Ry 2 R = (1.0 m) 2 + (2.6 m) 2 = 2.8 m The angle that R makes with the +x axis is
12 θ = tan -1 (Ry/Rx) = tan -1 (2.6 m/1.0 m) = 69.
13 PRACTICE PROBLEMS The following problems are provided to give you additional practice solving single concept problems. Some work space has been left for you after or to the right of the problem. The solutions to these problems will be found at the end of this chapter. 1. How many significant figures are in the numbers a b c. 2.8 X 10 5 d e X Convert the following into the indicated units. a m to ft b. 1.2 ft/s to m/s c mi/h to km/h d m/s 2 to ft/s 2 e. 535 kg to slugs 3. A basketball coach insists that his players be at least cm tall. Would a player of height 5 ft 11.5 in tall qualify for the team? 4. A football field is yards long. Express this distance in millimeters.
14 5. Check the following equations for possible validity. a. x 2 = 1/2 gt where x is in m, g is in m/s 2, t is in s. b. v 2 = 2 ax where v is in m/s, a is in m/s 2 and x is in ft. 6. A right triangle has a side of length 3.5 m. The angle opposite the 3.5 m side is 25. Find the length of the other sides. 7. A m tall building casts a shadow m long over level ground. What is the sun's elevation angle above the horizon? 8. A right triangle has two sides of length 25 ft and 15 ft. Find the length of the hypotenuse and all angles. 9. A bridge 50.0 m long crosses a chasm. If the bridge is inclined at an angle of 20.0 to the horizontal, what is the difference in height between the two ends?
15 10. A displacement vector of magnitude 5.0 m points in an easterly direction. A second displacement vector points north and has a magnitude of 9.7 m. Find the magnitude and direction of the vector sum. 11. An electric field vector, E, has a magnitude of 1.0 newtons per coul (N/C) and makes an angle of 33 CCW from the +x axis of a Cartesian coordinate system. Find the components of E. 12. A magnetic field vector, B, is oriented 65 clockwise from the -y axis. It has a magnitude of tesla (T). Find the x and y components of B. 13. A vector, A, has a magnitude of 10.0 u and points 21.0 north of west. A second vector, B, has a magnitude of 5.2 u and points 47.0 east of south. Find the magnitude and direction of the sum by the component method. 14. A car drives 2 km west, then 8 km south, and then 10.0 km at an angle 53 north of east. Find the car's final displacement. (magnitude and direction)
16 HELPFUL SUGGESTIONS 1. When expressing a vector quantity for an answer, be sure to specify both its magnitude and direction. 2. Vectors may be moved from place to place, providing that you maintain the same length and direction. 3. Calculating the components of a vector as Ax = A cos θ and Ay = A sin θ is correct only if θ is an angle measured with respect to the x axis. 4. When giving the answer to a problem, ALWAYS include the units. The units can be used as a tool for checking whether or not the answer is "dimensionally" correct. 5. Try to avoid just "plugging in" numbers into equations. Try to understand the ideas and concepts rather than just memorizing equations. 6. When you obtain your solution, always ask yourself, "is the solution reasonable?", "does it make sense?", and "are the units consistent?" EVERYDAY PHYSICS 1. If you want to lay out a garden, build a foundation or anything which should have 90 degree corners, use a right triangle. Use a string to roughly define two adjacent sides of your garden, measure 3 ft along one side and 4 ft along the other side and mark the location of each point. Measure from mark to mark and adjust the angle between the strings until the measurement yields exactly 5 ft. The strings will then be 90 degrees from each other. For more accuracy you may want to use a right triangle or even a right triangle. 2. Most of us are familiar with the SI units of meter and kilogram, but the British units of foot and pound are deeply ingrained since they are the ones we use in everyday life. Become more familiar with the SI units by lifting 1 kg of a common substance like sugar. Also, measure several common objects like your car in both meters and feet. 3. Determine the height of a tall object by measuring its shadow and estimating the angle of elevation of the sun. If it is possible, find the actual height of the object and compare with your results. Can you think of ways to determine the angle more accurately?
17 CHAPTER QUIZ This quiz has been provided to help you diagnose possible weak areas in the understanding of the key chapter concepts. The answers can be found at the end of the chapter in this guide. 1. How many significant figures are in the answer of ? a. one b. two c. three d. four 2. How many significant figures are in the result of 1600/2.80? a. one b. two c. three d. four 3. The derived unit (kg 2 m 2 )/(kg m s 2 ) is equivalent to a. (kg 2 )/s 2 b. (kg m/s 2 ) c. (kg m)/s d. (kg m 2 )/m 4. How many feet are in 25 m? a. 82 b c d If you are given one angle and the length of the side opposite in a right triangle, which trig function would allow you, in a single step, to find the length of the hypotenuse? a. sine b. cosine c. tangent d. any 6. If you are given one angle and the length of the hypotenuse of a right triangle, which trig function would you use to find the side adjacent to the angle? a. sine b. cosine c. tangent d. any 7. Vectors may be added graphically by placing them a. tail to tail. b. parallel. c. tail to head. d. head to head. 8. Which of the following is an example of a scalar? a. force b. volume c. displacement d. velocity 9. The parts of a vector which lie in perpendicular directions are called a. magnitudes b. resultants c. components d. scalars 10. If the angle, less than 90, specifying the direction of a vector is given as measured from the y axis, then the x component will ALWAYS involve what trig function? a. sine b. cosine c. tangent d. any 11. Which of the following is NOT a vector quantity? a. time b. velocity c. force d. displacement 12. Two displacement vectors have magnitudes of 8 m and 12 m, respectively. When these two vectors are added the magnitude of the sum a. is 20 m c. is larger than 20 m. b. is 4 m. d. could be as large as 20 m or as small as 4 m. 13. A physical quantity is calculated from the formula K = 3π c (a2 + b2) where a, b, and c are all lengths. What is the dimension of K? a. [L] c. 3π [L]2 b. [L]2 d. [L]3
18 SOLUTIONS AND ANSWERS Practice Problems 1. a has THREE significant figure. b has TWO significant figures. Note that it can be written as 5.4 X10-3. c. 2.8 X 10 5 has TWO significant figures. d has TWO significant figures since both zeros are in doubt. e X 10-4 has TWO significant figures. 2. a. We have 5.00 m = (5.00 m)(3.28 ft/1 m) = 16.4 ft. b. Also 1.2 ft/s = (1.2 ft/s)(0.305 m/1 ft) = 0.37 m/s. c. We know 60.0 mi/h = (60.0 mi/1 h)(5280 ft/1 mi)(0.305 m/1 ft)(1/1000 km/1 m)= 96.6 km/h. d. In this case e. Finally 9.80 m/s 2 = (9.80 m/s 2 )(3.28 ft/1 m) = 32.1 ft/s kg = (535 kg)(6.85 X 10-2 sl/1 kg) = 36.6 sl. 3. The conversion looks like cm = (180.0 cm)/(1 in/2.54 cm) = 70.9 in = 5 ft 10.9 in. YES 4. In this case yds = (100.0 yds)(3 ft/yd)(12 in/ft)(2.54 cm/in)(10 mm/cm) = mm. 5. a. Substitute the units into the equation to see if both sides match. m 2 = (m/s 2 )(s) = m/s The units on each side do NOT match so the equation is not valid. b. Similarly, m 2 /s 2 = (m/s 2 )(m) = m 2 /s 2. The units DO match so the equation MAY be valid. 6. The hypotenuse is given by (1.1) The side adjacent is given by (1.2), h = (3.5 m)/sin 25 = 8.3 m. ha = (8.3 m)cos 25 = 7.5 m.
20 7. The shadow, the building, and a line drawn from the top of the building to the corresponding point on the end of the shadow form a right triangle. The angle between this latter line and the horizontal is the elevation angle of the sun and is θ = tan -1 (500.0 m/800.0 m) = The length of the hypotenuse is given by (1.7), The angle opposite the 25 ft side is given by (1.6), h 2 = (25 ft) 2 + (15 ft) 2, h = 29 ft. The angle opposite the 15 ft side is θ = tan -1 (25/15). θ = 59. θ = tan -1 (15/25) = 31. Note that the angles add to 90 as they should. 9. We are given the hypotenuse and one angle in a right triangle. (1.1) gives the side opposite the angle to be ho = (50.0 m) sin 20.0 = 17.1 m. 10. The vectors are perpendicular; hence the magnitude of the vector sum can be found from the Pythagorean theorem. magnitude = 11 m. The angle the vector makes with the east-west line (+x) is θ = tan -1 (9.7/5.0) = 63 N of E. 11. The x component is The y component is Ex = (1.0 N/C) cos 33 = 0.84 N/C. Ey = (1.0 N/C) sin 33 = 0.54 N/C. 12. The angle as measured from the +x axis is θ = = 205. Then Bx = (0.010 T) cos 205 = T and By = (0.010 T) sin 205 = T. 13. The x components are: Ax = -(10.0 u) cos 21.0 = u, Bx = (5.2 u) sin 47.0 = 3.80 u, Rx = u.
22 The y components are: Ay = (10.0 u) sin 21.0 = 3.58 u, By = -(5.2 u) cos 47.0 = u, Ry = 0.03 u. The magnitude of the resultant vector is found from the Pythagorean theorem to be The angle is R = ( u) 2 + (0.03 u) 2 = 5.54 u. θ = tan -1 (0.03/5.54) = N of W. 14. Let A be the westerly displacements, B the southerly displacement, and C be the remaining displacement. Taking east and north to be positive, the east-west (x) components are: Ax = -2 km, Bx = 0 km, Cx = +(10.0 km) cos 53 = 6 km. Rx = +4 km. The north-south (y) components are: Ay = 0 km, By = -8 km, Cy = +(10.0 km) sin 53 = +8 km. Ry = 0 km. The magnitude of the resultant vector is given by the Pythagorean theorem to be and the direction is R = (4 km) 2 + (0 km) 2 = 4 km. θ = tan -1 (0/4) = 0. That is, EAST. Quiz answers 1. b 4. a 7. c 10. a 13. d 2. b 5. a 8. b 11. a 3. b 6. b 9. c 12. d
23 MCAT REVIEW PROBLEMS When an airplane flies, its total velocity with respect to the ground is vtotal = vplane + vwind, where vplane denotes the plane s velocity through motionless air, and vwind denotes the wind s velocity. Crucially, all the quantities in this equation are vectors. The magnitude of a velocity vector is often called the speed. Consider an airplane whose speed through motionless air is 100 meters per second (m/s). To reach its destination, the plane must fly east. The heading of a plane is the direction in which the nose of the plane points. So, it is the direction in which the engines propel the plane. 1. If the plane has an eastward heading, and a 20 m/s wind blows towards the southwest, then the plane s speed is: A. 80 m/s B. more than 80 m/s but less than 100 m/s C. 100 m/s D. more than 100 m/s 2. The pilot maintains an eastward heading while a 20 m/s wind blows northward. The plane s velocity is deflected from due east by what angle? A. sin B. cos C. tan D. none of the above 3. Let φ denote the answer to question 2. The plane in question 2 has what speed with respect to the ground? A. (100 m/s)sin φ B. (100 m/s)cos φ 100 m/s 100 m/s C. sin φ D. cos φ 4. Because the 20 m/s northward wind persists, the pilot adjusts the heading so that the plane s total velocity is eastward. By what angle does the new heading differ from due east? A. sin B. cos C. tan D. none of the above 5. Let θ denote the answer to question 4. What is the total speed, with respect to the ground, of the plane in
24 question 4? A. (100 m/s)sin θ B. (100 m/s)cos θ C. 100 m/s sin θ D. 100 m/s cos θ ANSWERS TO MCAT REVIEW PROBLEMS 1. B. In all of these problems, a good diagram gets you half way to the answer. For this plane, v plane = 100 m/s eastward, and v wind = 20 m/s towards the southwest. To represent the total velocity, add these two vectors: FIGURE 1 Just by looking at this rough diagram, you can see that the wind slows down the plane. So, the answer must be A or B. Since the wind does not blow westward, it does not directly oppose the plane s motion. Therefore, the wind cannot slow the plane down by a full 20 m/s from the plane s default velocity of 100 m/s. 2. C. Because the pilot maintains an eastward heading, the engines still push the plane due east. So, v plane = 100 m/s eastward. But the wind blows at v wind = 20 m/s northward, thereby knocking the plane off course by angle φ. FIGURE 2 In this triangle, we know the two legs but not the hypotenuse. Specifically, in units of m/s, the opposite leg has length h o = 20, while the adjacent leg has length h a = 100. Therefore, by the definition of tangent,
25 tan φ = Take the inverse tangent of both sides to get φ = tan -1 h o h a = D. By looking at figure 2, and remembering the definition of cosine, we get h v ah plane 100 m/s cos φ = = v total = v total. Multiply through by vtotal, and then divide through by cos φ, to get vtotal = 100 m/s cos φ. 4. A. The pilot now adjusts the heading so that v total points due east. Since the wind knocks the plane northward, the plane must head slightly southward, to offset the wind:
26 [--- Unable To Translate Graphic ---]
27 FIGURE 3 Here, v plane is the hypotenuse. From figure 3, we get sin θ = h o h = v wind v plane = 20 m / s 100 m / s, and hence, θ = sin B. Again from figure 3, the hypotenuse has length h = v plane = 100 m/s, while the adjacent leg has length h a = v total. So, cos θ = h a h = v total v plane = v total 100 m / s. Multiply through by 100 m/s to get (100 m/s)cos θ = v total.
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Lecture 6 Weight Tension Normal Force Static Friction Cutnell+Johnson: 4.8-4.12, second half of section 4.7 In this lecture, I m going to discuss four different kinds of forces: weight, tension, the normal
11 Vectors and the Geometry of Space 11.1 Vectors in the Plane Copyright Cengage Learning. All rights reserved. Copyright Cengage Learning. All rights reserved. 2 Objectives! Write the component form of
Plotting and Adjusting Your Course: Using Vectors and Trigonometry in Navigation ED 5661 Mathematics & Navigation Teacher Institute August 2011 By Serena Gay Target: Precalculus (grades 11 or 12) Lesson
Chapter 2 One Dimensional Kinematics How would you describe the following motion? Ex: random 1-D path speeding up and slowing down In order to describe motion you need to describe the following properties.
Chapter 3 Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1. Which of the following is a physical quantity that has both magnitude and direction?
Candidates should be able to : Examples of Scalar and Vector Quantities 1 QUANTITY VECTOR SCALAR Define scalar and vector quantities and give examples. Draw and use a vector triangle to determine the resultant
The student will be able to: Geometry and Measurement 1. Demonstrate an understanding of the principles of geometry and measurement and operations using measurements Use the US system of measurement for
1 The Force Table Introduction: "The Force Table" is a simple tool for demonstrating Newton s First Law and the vector nature of forces. This tool is based on the principle of equilibrium. An object is
Vector has a magnitude and a direction Scalar has a magnitude Vector has a magnitude and a direction Scalar has a magnitude a brick on a table Vector has a magnitude and a direction Scalar has a magnitude
Extra Credit Assignment Lesson plan The following assignment is optional and can be completed to receive up to 5 points on a previously taken exam. The extra credit assignment is to create a typed up lesson
Right Triangle Trigonometry Page 1 of 15 RIGHT TRIANGLE TRIGONOMETRY Objectives: After completing this section, you should be able to do the following: Calculate the lengths of sides and angles of a right
More Chapter 3 Projectile motion simulator http://www.walter-fendt.de/ph11e/projectile.htm The equations of motion for constant acceleration from chapter 2 are valid separately for both motion in the x
The Dot and Cross Products Two common operations involving vectors are the dot product and the cross product. Let two vectors =,, and =,, be given. The Dot Product The dot product of and is written and
mathematics College Algebra Geometry Trigonometry Sample Test Questions A Guide for Students and Parents act.org/compass Note to Students Welcome to the ACT Compass Sample Mathematics Test! You are about
Part I Basic Maths for Game Design 1 Chapter 1 Basic Vector Algebra 1.1 What's a vector? Why do you need it? A vector is a mathematical object used to represent some magnitudes. For example, temperature
G.1 EE1.el3 (EEE1023): Electronics III Mechanics lecture 7 Moment of a force, torque, equilibrium of a body Dr Philip Jackson http://www.ee.surrey.ac.uk/teaching/courses/ee1.el3/ G.2 Moments, torque and
RIGHT TRIANGLE TRIGONOMETRY The word Trigonometry can be broken into the parts Tri, gon, and metry, which means Three angle measurement, or equivalently Triangle measurement. Throughout this unit, we will
Trigonometry It is possible to solve many force and velocity problems by drawing vector diagrams. However, the degree of accuracy is dependent upon the exactness of the person doing the drawing and measuring.
Solutions to old Exam 1 problems Hi students! I am putting this old version of my review for the first midterm review, place and time to be announced. Check for updates on the web site as to which sections
Vectors and Scalars P Physics Scalar SCLR is NY quantity in physics that has MGNITUDE, but NOT a direction associated with it. Magnitude numerical value with units. Scalar Example Speed Distance ge Magnitude
COMPONENTS OF VECTORS To describe motion in two dimensions we need a coordinate sstem with two perpendicular aes, and. In such a coordinate sstem, an vector A can be uniquel decomposed into a sum of two
Physics 201 Homework 8 Feb 27, 2013 1. A ceiling fan is turned on and a net torque of 1.8 N-m is applied to the blades. 8.2 rad/s 2 The blades have a total moment of inertia of 0.22 kg-m 2. What is the
The verbal answers to all of the following questions should be memorized before completion of pre-algebra. Answers that are not memorized will hinder your ability to succeed in algebra 1. Number Basics
Physical Quantities and Units 1 Revision Objectives This chapter will explain the SI system of units used for measuring physical quantities and will distinguish between vector and scalar quantities. You
The Scalar Product 9.4 Introduction There are two kinds of multiplication involving vectors. The first is known as the scalar product or dot product. This is so-called because when the scalar product of
Perimeter and Area Page 1 of 57 PERIMETER AND AREA Objectives: After completing this section, you should be able to do the following: Calculate the area of given geometric figures. Calculate the perimeter
Page 1 9 Trigonometry of Right Triangles Right Triangles A right triangle, as the one shown in Figure 5, is a triangle that has one angle measuring 90. The side opposite to the right angle is the longest
Mathematics Revision Guides Further Vectors (MEI) (column notation) Page of MK HOME TUITION Mathematics Revision Guides Level: AS / A Level - MEI OCR MEI: C FURTHER VECTORS (MEI) Version : Date: -9-7 Mathematics
Thnkwell s Homeschool Precalculus Course Lesson Plan: 36 weeks Welcome to Thinkwell s Homeschool Precalculus! We re thrilled that you ve decided to make us part of your homeschool curriculum. This lesson
Revised Pages PART ONE Mechanics CHAPTER Motion Along a Line 2 Despite its enormous mass (425 to 9 kg), the Cape buffalo is capable of running at a top speed of about 55 km/h (34 mi/h). Since the top speed
TRIGONOMETRY FOR ANIMATION What is Trigonometry? Trigonometry is basically the study of triangles and the relationship of their sides and angles. For example, if you take any triangle and make one of the
Higher Education Math Placement Placement Assessment Problem Types 1. Whole Numbers, Fractions, and Decimals 1.1 Operations with Whole Numbers Addition with carry Subtraction with borrowing Multiplication
Trigonometry for AC circuits This worksheet and all related files are licensed under the Creative Commons Attribution License, version 1.0. To view a copy of this license, visit http://creativecommons.org/licenses/by/1.0/,
What You ll Learn You will represent vector quantities both graphically and algebraically. You will use Newton s laws to analyze motion when friction is involved. You will use Newton s laws and your knowledge
2312 test 2 Fall 2010 Form B 1. Write the slope-intercept form of the equation of the line through the given point perpendicular to the given lin point: ( 7, 8) line: 9x 45y = 9 2. Evaluate the function
TIME OF COMPLETION NAME DEPARTMENT OF NATURAL SCIENCES PHYS 1111, Exam 2 Section 1 Version 1 October 30, 2002 Total Weight: 100 points 1. Check your examination for completeness prior to starting. There
Math, Trigonometr and Vectors Geometr 33º What is the angle equal to? a) α = 7 b) α = 57 c) α = 33 d) α = 90 e) α cannot be determined α Trig Definitions Here's a familiar image. To make predictive models
Chapter 2 3 Space: lines and planes In this chapter we discuss how to describe points, lines and planes in 3 space. introduce the language of vectors. discuss various matters concerning the relative position
Chapter Additional Topics in Math In addition to the questions in Heart of Algebra, Problem Solving and Data Analysis, and Passport to Advanced Math, the SAT Math Test includes several questions that are
5. Forces and Motion-I 1 Force is an interaction that causes the acceleration of a body. A vector quantity. Newton's First Law: Consider a body on which no net force acts. If the body is at rest, it will
A Second Course in Mathematics Concepts for Elementary Teachers: Theory, Problems, and Solutions Marcel B. Finan Arkansas Tech University c All Rights Reserved First Draft February 8, 2006 1 Contents 25
476 CHAPTER 7 Graphs, Equations, and Inequalities 7. Quadratic Equations Now Work the Are You Prepared? problems on page 48. OBJECTIVES 1 Solve Quadratic Equations by Factoring (p. 476) Solve Quadratic
Chapter 1 Units, Physical Quantities, and Vectors 1 The Nature of Physics Physics is an experimental science. Physicists make observations of physical phenomena. They try to find patterns and principles
Math Placement Test Practice Problems The following problems cover material that is used on the math placement test to place students into Math 1111 College Algebra, Math 1113 Precalculus, and Math 2211
AP PHYSICS C Mechanics - SUMMER ASSIGNMENT FOR 2016-2017 Dear Student: The AP physics course you have signed up for is designed to prepare you for a superior performance on the AP test. To complete material
Name Period Date Show all work neatly on separate paper. (You may use both sides of your paper.) Problems should be labeled clearly. If I can t find a problem, I ll assume it s not there, so USE THE TEMPLATE
Trigonometric Functions: The Unit Circle This chapter deals with the subject of trigonometry, which likely had its origins in the study of distances and angles by the ancient Greeks. The word trigonometry
Page 1 In game development, there are a lot of situations where you need to use the trigonometric functions. The functions are used to calculate an angle of a triangle with one corner of 90 degrees. By
TRIGONOMETRY Compound & Double angle formulae In order to master this section you must first learn the formulae, even though they will be given to you on the matric formula sheet. We call these formulae
Chapter 28: MAGNETIC FIELDS 1 Units of a magnetic field might be: A C m/s B C s/m C C/kg D kg/c s E N/C m 2 In the formula F = q v B: A F must be perpendicular to v but not necessarily to B B F must be
This file is distributed FREE OF CHARGE by the publisher Quick Reference Handbooks and the author. Quick Reference ebook Click on Contents or Index in the left panel to locate a topic. The math facts listed
Work Force If an object is moving in a straight line with position function s(t), then the force F on the object at time t is the product of the mass of the object times its acceleration. F = m d2 s dt