Primary 6 Chapter 7 Circles Practice 6
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1 Primary 6 Chapter 7 Circles Practice 6 1) Match the figures that have the same shaded area. P6 Chapter 7 Circles Practice 6-1- Just Education Tuition Centre Pte Ltd
2 Solve the following problem sums. All essential workings must be shown clearly. Calculators are allowed. Students are drilled and exposed to different types of problem sums to prepare them for examination. 2) Take π = 22 7 and solve the following questions. (a) The figure shows a square with a quadrant cut out. Find the area of the shaded part. 14 cm 14 cm (b) Using the answer in (a), find the area of the shaded part. 14 cm 14 cm (c) Using the answer in (b), find the area of the shaded part. 14 cm 14 cm P6 Chapter 7 Circles Practice 6-2- Just Education Tuition Centre Pte Ltd
3 As much as we would love to show you everything, we cannot be showing you the best. Do drop by any Just Education centre to view the full set! P6 Chapter 7 Circles Practice 6-3- Just Education Tuition Centre Pte Ltd
4 Worked Example 1 The figure shows 3 identical circles overlapping one another where X, Y and Z are the centers of the 3 circles. Each shaded area is 60 cm 2. Find the area of the whole figure given that XY = YZ = 7 cm. (Take π = 22 ) 7 Solution: X 7 cm Y 7 cm Z Worked examples are used to guide students on the answering of the question. It is also useful for students to refer to when revising. Area of one circle cm 7 cm = 154 cm² Area of 3 circles cm² = 462 cm² Area of figure 462 cm² (2 60) cm² = 462 cm² 120 cm² = 342 cm² Or Area of 1 circle shaded area 154 cm 2 60 cm 2 = 94 cm cm 2 = 188 cm 2 Area of figure 188 cm cm 2 = 342 cm 2 The area of the whole figure is 342 cm 2. P6 Chapter 7 Circles Practice 6-4- Just Education Tuition Centre Pte Ltd
5 3) The fan below is made up of two quadrants overlapping each other. The area of the shaded part is 40 cm 2. Find the total area of the unshaded part. (Take π = 22 ) 7 14 cm 4) The figure shows a rectangle ABCD overlapping a circle (centre A) with radius 7 m. If AB is twice AD, find the perimeter of the figure. (Take π = 22 7 ) A O B D C P6 Chapter 7 Circles Practice 6-5- Just Education Tuition Centre Pte Ltd
6 5) The figure below shows a pattern made up of 4 identical squares, 4 semicircles and 4 quadrants. (a) Find the total area of the shaded regions. (b) Find the total perimeter of the shaded regions. (Take π = 22 ) 7 14 cm 14 cm 14 cm 14 cm Ans:(a) (b) P6 Chapter 7 Circles Practice 6-6- Just Education Tuition Centre Pte Ltd
7 Do drop by our centre to view the full set of materials. P6 Chapter 7 Circles Practice 6-7- Just Education Tuition Centre Pte Ltd
8 Do drop by our centre to view the full set of materials. P6 Chapter 7 Circles Practice 6-8- Just Education Tuition Centre Pte Ltd
9 6) The figure below is made up of 2 identical small semicircles enclosed in a large semicircle. The area of region QOR is 76 cm 2 and its perimeter is 35.8 cm. Given that PQ = QR = RS = 10 cm, find (a) the area of the shaded region and (b) the perimeter of the shaded region. (Take π = 3.14) O P Q R S Ans:(a) (b) P6 Chapter 7 Circles Practice 6-9- Just Education Tuition Centre Pte Ltd
10 7) The figure below is made up of a big quadrant ONP, a small quadrant OMR and a square OMQR. The area of the big quadrant is thrice the area of the small quadrant. Given that the length of NO is 72 cm, what is the area of the shaded part? Leave your answer in terms of π. Do drop by our centre to view the full set of materials. P6 Chapter 7 Circles Practice Just Education Tuition Centre Pte Ltd
11 Primary 6 Challenging Word Problems: Area & Perimeter Practice 1 Challenging word problems worksheets are given to further expose students to more challenging questions which help them in scoring their A* in PSLE. Please refer to Maths Power Guide: Power Summary Pg 26 Calculators are allowed. 1) A piece of wire is bent to form 6 similar semicircles as shown in the figure. The area of the enclosed rectangle is 32 cm 2. Find the length of the piece of wire. (Take π = 3.14) Worksheets are designed to complement our own inhouse assessment book which comprises of Notes and some Practice questions to further enhance students understanding of the new topic. P6 Challenging Word Problems: Area & Perimeter Practice 1-1- Just Education Tuition Centre Pte Ltd
12 2) The figure shown is made up of 4 identical circles, which are drawn in such a way that each circle intersects two other circles. The 4 circles meet at a common point E. Point E is also the centre of the square ABCD. The length of the square ABCD is 14 cm. A B (a) Find the area of the shaded part. E (b) Find the perimeter of the shaded part. (Take π = 22 ) 7 D C Ans:(a) (b) P6 Challenging Word Problems: Area & Perimeter Practice 1-2- Just Education Tuition Centre Pte Ltd
13 * 3) The figure below is made up of two semi-circles that overlapped each other. Express the area of the shaded regions in terms of π. 16 cm 20 cm P6 Challenging Word Problems: Area & Perimeter Practice 1-3- Just Education Tuition Centre Pte Ltd
14 Do drop by our centre to view the full set of materials. 4) P6 Challenging Word Problems: Area & Perimeter Practice 1-4- Just Education Tuition Centre Pte Ltd
15 Do drop by our centre to view the full set of materials. P6 Challenging Word Problems: Area & Perimeter Practice 1-5- Just Education Tuition Centre Pte Ltd
16 Do drop by our centre to view the full set of materials. P6 Challenging Word Problems: Area & Perimeter Practice 1-6- Just Education Tuition Centre Pte Ltd
17 * 5) Oscar cut two triangles from a piece of rectangular paper as shown. The area of Triangle P is 25.5 cm 2 more than the area of Triangle Q. The length and breadth of the paper is 17 cm and 9 cm respectively. Find the base of Triangle Q. Q? 9 cm P 17 cm P6 Challenging Word Problems: Area & Perimeter Practice 1-7- Just Education Tuition Centre Pte Ltd
18 6) In the diagram below, ABCD is a rectangle. The area of Triangle ABE is 50 m 2 and the area of Triangle BCE is 34 m 2. Given that BE = EC and DF = FC, find the area of AEFD. A B E D F C P6 Challenging Word Problems: Area & Perimeter Practice 1-8- Just Education Tuition Centre Pte Ltd
19 Primary 6 Challenging Word Problems: Area & Perimeter Practice 1 Worksheets are given at the end for students to revise challenging questions and answers are provided to promote independent learning. Calculators are allowed. 7) The figure below is made up of Rectangle BCDE, Triangle ABD and Square ABEF. The length of Square ABEF is 48 cm. Find the difference between the shaded areas. F E D 48 cm A B C P6 Challenging Word Problems: Area & Perimeter Practice1-1- Just Education Tuition Centre Pte Ltd
20 8) In the figure below, two triangles are enclosed in Rectangle WXYZ. The length of VZ : WZ is 1 : 2 and the length of ZU : ZY is 1 : 4. The length of WX is 48 cm. Given that the area of Triangle UVW is 27 cm 2, find the perimeter of Rectangle WXYZ. W X V Z U Y P6 Challenging Word Problems: Area & Perimeter Practice1-2- Just Education Tuition Centre Pte Ltd
21 Do drop by our centre to view the full set of materials. P6 Challenging Word Problems: Area & Perimeter Practice1-3- Just Education Tuition Centre Pte Ltd
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