DERIVATIVES: RULES. Find the derivative of the constant function f(x) = c using the definition of derivative.

Similar documents
MPE Review Section III: Logarithmic & Exponential Functions

10.1. Solving Quadratic Equations. Investigation: Rocket Science CONDENSED

Algebra. Exponents. Absolute Value. Simplify each of the following as much as possible. 2x y x + y y. xxx 3. x x x xx x. 1. Evaluate 5 and 123

2008 AP Calculus AB Multiple Choice Exam

Review of Fundamental Mathematics

Student Performance Q&A:

Review of Intermediate Algebra Content

Polynomial Degree and Finite Differences

AP Calculus AB First Semester Final Exam Practice Test Content covers chapters 1-3 Name: Date: Period:

Polynomial and Synthetic Division. Long Division of Polynomials. Example 1. 6x 2 7x 2 x 2) 19x 2 16x 4 6x3 12x 2 7x 2 16x 7x 2 14x. 2x 4.

Mathematics 31 Pre-calculus and Limits

POLYNOMIAL FUNCTIONS

Core Maths C1. Revision Notes

Exponential and Logarithmic Functions

Calculus 1st Semester Final Review

Partial f (x; y) x f (x; x2 y2 and then we evaluate the derivative as if y is a constant.

Graphing Trigonometric Skills

Functions: Piecewise, Even and Odd.

Functions and their Graphs

Answer Key for California State Standards: Algebra I

Chapter 4. Polynomial and Rational Functions. 4.1 Polynomial Functions and Their Graphs

Section 1.1 Linear Equations: Slope and Equations of Lines

Negative Integral Exponents. If x is nonzero, the reciprocal of x is written as 1 x. For example, the reciprocal of 23 is written as 2

How To Understand And Solve Algebraic Equations

Core Maths C3. Revision Notes

The numerical values that you find are called the solutions of the equation.

Section 3-7. Marginal Analysis in Business and Economics. Marginal Cost, Revenue, and Profit. 202 Chapter 3 The Derivative

TOPIC 4: DERIVATIVES

7.7 Solving Rational Equations

MEMORANDUM. All students taking the CLC Math Placement Exam PLACEMENT INTO CALCULUS AND ANALYTIC GEOMETRY I, MTH 145:

Students Currently in Algebra 2 Maine East Math Placement Exam Review Problems

LIMITS AND CONTINUITY

9.3 OPERATIONS WITH RADICALS

Solving Quadratic Equations

Definition: A vector is a directed line segment that has and. Each vector has an initial point and a terminal point.

correct-choice plot f(x) and draw an approximate tangent line at x = a and use geometry to estimate its slope comment The choices were:

The Method of Partial Fractions Math 121 Calculus II Spring 2015

6. Vectors Scott Surgent (surgent@asu.edu)

1. Which of the 12 parent functions we know from chapter 1 are power functions? List their equations and names.

Section 6-3 Double-Angle and Half-Angle Identities

Microeconomic Theory: Basic Math Concepts

100. In general, we can define this as if b x = a then x = log b

Readings this week. 1 Parametric Equations Supplement. 2 Section Sections Professor Christopher Hoffman Math 124

TSI College Level Math Practice Test

C3: Functions. Learning objectives

2-5 Rational Functions

Math 120 Final Exam Practice Problems, Form: A

Chapter 4 One Dimensional Kinematics

The Derivative. Philippe B. Laval Kennesaw State University

x x y y Then, my slope is =. Notice, if we use the slope formula, we ll get the same thing: m =

UNIT 1: ANALYTICAL METHODS FOR ENGINEERS

Higher Education Math Placement

Algebra 2 Unit 8 (Chapter 7) CALCULATORS ARE NOT ALLOWED

By Clicking on the Worksheet you are in an active Math Region. In order to insert a text region either go to INSERT -TEXT REGION or simply

x 2 + y 2 = 1 y 1 = x 2 + 2x y = x 2 + 2x + 1

Parallel and Perpendicular. We show a small box in one of the angles to show that the lines are perpendicular.

3 e) x f) 2. Precalculus Worksheet P Complete the following questions from your textbook: p11: # Why would you never write 5 < x > 7?

Algebra 1 Course Title

Georgia Department of Education Kathy Cox, State Superintendent of Schools 7/19/2005 All Rights Reserved 1

MATH 60 NOTEBOOK CERTIFICATIONS

Thnkwell s Homeschool Precalculus Course Lesson Plan: 36 weeks

Core Maths C2. Revision Notes

G. GRAPHING FUNCTIONS

List the elements of the given set that are natural numbers, integers, rational numbers, and irrational numbers. (Enter your answers as commaseparated

MATH ADVISEMENT GUIDE

Algebra and Geometry Review (61 topics, no due date)

3.3. Solving Polynomial Equations. Introduction. Prerequisites. Learning Outcomes

Prentice Hall Mathematics: Algebra Correlated to: Utah Core Curriculum for Math, Intermediate Algebra (Secondary)

STRAND: ALGEBRA Unit 3 Solving Equations

36 CHAPTER 1. LIMITS AND CONTINUITY. Figure 1.17: At which points is f not continuous?

Figure 1.1 Vector A and Vector F

Five 5. Rational Expressions and Equations C H A P T E R

Exponents. Learning Objectives 4-1

Solutions of Linear Equations in One Variable

Indiana State Core Curriculum Standards updated 2009 Algebra I

Midterm 2 Review Problems (the first 7 pages) Math Intermediate Algebra Online Spring 2013

A Resource for Free-standing Mathematics Qualifications

AP Calculus AB Syllabus

SUNY ECC. ACCUPLACER Preparation Workshop. Algebra Skills

Lesson 9.1 Solving Quadratic Equations

ab = c a If the coefficients a,b and c are real then either α and β are real or α and β are complex conjugates

MATH 121 FINAL EXAM FALL December 6, 2010

Average rate of change of y = f(x) with respect to x as x changes from a to a + h:

2.2 Derivative as a Function

Understanding Basic Calculus

RELEASED. Student Booklet. Precalculus. Fall 2014 NC Final Exam. Released Items

AP Calculus AB 2007 Scoring Guidelines Form B

Trigonometric Functions and Equations

15.1. Exact Differential Equations. Exact First-Order Equations. Exact Differential Equations Integrating Factors

AP Calculus AB 2004 Scoring Guidelines

In order to describe motion you need to describe the following properties.

South Carolina College- and Career-Ready (SCCCR) Pre-Calculus

GRAPHING IN POLAR COORDINATES SYMMETRY

PRE-CALCULUS GRADE 12

1.3 LINEAR EQUATIONS IN TWO VARIABLES. Copyright Cengage Learning. All rights reserved.

Average rate of change

Course outline, MA 113, Spring 2014 Part A, Functions and limits Functions, domain and ranges, A Review (9 problems)

MATH 095, College Prep Mathematics: Unit Coverage Pre-algebra topics (arithmetic skills) offered through BSE (Basic Skills Education)

Microeconomics Sept. 16, 2010 NOTES ON CALCULUS AND UTILITY FUNCTIONS

Transcription:

Part : Derivatives of Polynomial Functions DERIVATIVES: RULES We can use the definition of the derivative in order to generalize solutions and develop rules to find derivatives. The simplest derivatives to find are those of polynomial functions. Eample : Find the derivative of the constant function f() c using the definition of derivative. Solution: f ( + ) f ( ) c c lim lim 0 0 0 So, the derivative of a constant is 0. This corresponds to the graphing of derivatives we did earlier. The graph of a constant function is a horizontal line and the slope of a horizontal line is 0. f() c f () 0 Symbolically, we write Constant Rule: If f() c, then f () 0. Eample : Find the derivative of each of the following functions based on their functions. The function and its derivative are pictured in each diagram. A table of values for f and f is also shown. Study the values carefully. The function is given at the right. Complete the list of derivatives f f f() f () f f f() f ()

f f f() f () f f f() f () A pattern is emerging when we take the derivative of a power. The eponent becomes the coefficient of the derivative and the power of the derivative is one less than the power of the function. This is called the power rule and symbolically it is written as follows. Power Rule: If f() n, then f () n n-. We noted above that the derivative of f ( ) is. What is the derivative of 5? 6? 0? Is there a rule that governs multiplying a function by a constant? It is possible to answer this question by once again going back to the definition of the derivative. The question we are asking is what is the derivative of k? f ( + ) f ( ) k( + ) k lim lim k + k + k k lim 0 lim ( k k ) 0 0 0 k k( ) So, the derivative of a function multiplied by a constant is the constant multiplied by the derivative. Or, Constant Multiple Rule: The derivative of kf() is kf (). What is the derivative of a sum or difference of several powers; i.e., what is the derivative of a polynomial? Sum Rule: The derivative of a sum f() + g() is the sum of the derivatives, f () + g (). Likewise, the derivative of a difference is the difference of the derivatives. Difference Rule: The derivative of a difference f() - g() is the difference of the derivatives, f () - g (). With these few simple rules, we can now find the derivative of any polynomial.

Eample : Find the derivative of f + + 6 ( ) 5 8 7 Solution: Find the derivative of each term of the polynomial using the constant multiple rule and power rules. Then, add or subtract the derivative of each term, as appropriate. 6 The derivative of 5 is The derivative of is The derivative of is The derivative of The derivative of 7 is 0.. 5(6 ) 0 5 5 ( ). ( ) 6. 8 is 8( ) 6. So, the derivative of 6 f ( ) 5 + 8 + 7 is 5 f '( ) 0 6 6 +. Eample : Find the slope of the tangent line to the curve f ( ) + at. Solution: Using the derivative rules, f '( ) 6. At, the derivative is 6() -. This can also be written as f (). Homework Eercises Part : Derivatives of Polynomial Functions Find the derivative of each of the following.... f ( ) 5 5. f ( ) + + 6. 0 5 f ( ) 0. 0.5 0. 0.5 7.. ( ) 6 f ( ) 8 f ( ) + 6 5 f ( ) + + + + + + f ( ) 8. f ( ) ( + 7)( ) Find the indicated derivative. 9. f '() if 0. f ( ) 5 +. '() f if f ' if f ( ) 5 + 6. f '( ) if Write the equation of the tangent line at the indicated point. f 5 ( ) + f ( ) + + 6.. f ( ) f at (, ) 5. ( ) ( ) + at (, ) 6. f ( ) at (-, ) f ( ) ( ) at (-, -7) 7. Use the definition of derivative to prove that the derivative of a linear function is a constant; i.e., prove that if f ( ) a + b then f '( ) a, using f ( + ) f ( ) lim 0.

8. Use the definition of derivative to prove that the derivative of a quadratic function is a linear function; i.e., prove that if f ( ) a b c 9. Find all points on the graph of 0. Find all points on the graph of + +, then f '( ) a + b, using lim 0 y where the tangent line is horizontal. y f ( + ) f ( ) + + where the tangent line has slope. 6t + 0t + 00. The height in feet of a ball above the ground at t seconds is given by the equation a. What is the instantaneous velocity at t? b. When is the instantaneous velocity equal to 0?.. There are two tangent lines to the curve both of them. y that go through the point (, 5). Find the equations of. Suppose f '(0), and g '(0), find a. The derivative of f (0) + g(0) b. The derivative of f (0) g(0) Part : Derivatives of Negative and Fractional Powers In the last set of eercises, you proved that the derivative of a linear function is a constant function; the derivative of a quadratic function is a linear function; the derivative of a cubic function is a quadratic function. It is possible to continue these proofs for any n. We generalized these derivatives by using the power rule and constant, sum and difference rules. Thus far, we have used the power rule for positive integer powers only. What of negative and fractional powers? Eample : Find the derivative of Solution: f ( ) Substituting into the definition, we get f ( + ) f ( ) ( + ) lim lim ( + + ) lim 0 + + ( + + ) ( + + ) lim 0 ( + + ) lim 0 ( + + ) 0 0 lim 0 + + ( lim 0 ( + + ) )

So, the derivative of f ( ) is f '( ). Therefore, the power rule applies to negative eponents. Study the graphs of y and y below. Is differentiable at every point? From the graphs, we see that is not differentiable at 0. Is it possible to apply the power rule to fractional eponents? Consider the function f ( ). Eample : Find the derivative of f ( ) Solution: Substituting into the definition, we get f ( + ) f ( ) + lim lim 0 0 lim 0 + + + + + + lim 0 ( + + ) lim 0 ( + + ) lim 0 + + So, the derivative of f ( ) or f ( ) is f '( ). Again, the power rule applies. Homework Eercises Part : Derivatives of Negative and Fractional Powers Find the derivatives of each of the following functions.. f ( ).. f ( ) 5. 5 f ( ) + 6.. f ( ) f ( ) f ( ) 5 5

Find the indicated derivative. 5 7. f '() if f ( ) + π 9. '() 8. f ' if 5 f ( ) + 6 0. '(6) Write the equation of the tangent line at the indicated point. f if f if f 5 ( ) + f ( ) + + 6. f ( ) at (, ). f ( ) + at (, ). If f ( ) 8 + and '( ), f c find c. Part : Derivatives of the Sine and Cosine Functions Look at the graph of f ( ) sin and its derivative. What is the derivative of sin? If f() sin, then f () cos. Do the same for f ( ) cos. What is the derivative of cos? Be careful! The temptation is to say that the derivative of f ( ) cos is sin, but note that it is f '( ) sin. If f() cos, then f () -sin. Eample : Find the derivative of f ( ) sin cos. Solution: The derivative of sin is cos The derivative of cos is ( sin ) sin. So, the derivative of the function is f '( ) cos + sin. π Eample : Find the equation of the tangent line to the graph of y sin at 6

Solution: The derivative of f ( ) sin is f '( ) cos. The value of the derivative at is cos π The y value at is So, the tangent line is π π π sin π y Homework Eercises Part : Derivatives of the Sine and Cosine Functions Find the derivative of each of the following functions.. f ( ) sin + 6cos. f ( ) cos. f ( ) sin 5. f ( ) cos. f ( ) sin 6. f ( ) sin + cos 7. Find the equation of the tangent line to y sin at. 8. At time t seconds, the center of a bobbing buoy is sin velocity of the cork at t 0, / and? t meters above or below water level. What is the 9. A weight is hanging from a spring. It is compressed 5 cm above its rest position ( 0) and released at time t 0 seconds to bob up and down. Its position at any later time t is 5cos t. What is its velocity at time t? You can simulate the up and down motion of the spring y using parametric equations. Graph simultaneously << π Use the TRACE key on your calculator to eplore the position and velocity functions. If you change to, you can see the up and down motion of the spring. 0. A normal line is perpendicular to the tangent line. Find the equations for the lines that are tangent and normal to the curve π y cos at the point,. 7

Part : Derivatives of the Natural Eponential and Logarithmic Functions Look at the graph of f ( ) e and its derivative. What is the derivative of e? If f() e, then f () e. The natural eponential function is the only function that has itself as its derivative. Do the same for f ( ) ln. What is the derivative of ln? If f() ln, then f () /, > 0. It is possible to use the laws of logarithms to aid in finding derivatives of natural logarithmic functions. Eample : Find the derivative of f ( ) ln.. So, ln ln (when > 0 ). Now, we can apply the constant multiple rule and find the derivative of b Solution: We know that log a b log a f ( ) : f '( ) Eample : Find the derivative of f ( ) ln ( e ) Solution: Again, apply a log rule: ln( ab) ln a + ln b. ln e ln + ln e ln + ln e. So, ( ). What is ln e? Recall that the natural logarithmic function and natural eponential functions are inverses of each other. e Therefore, ln e. So, ln + ln ln +. Now, that we have simplified the function, finding the derivative is simple. f '( ) + +. 8

Homework Eercises Part : Derivatives of the Natural Eponential & Logarithmic Fns. Find the derivatives of each of the following..... 5. f ( ) 5 + e 6. ( ) ln f f ( ) (ln ) (ln ) e 7. f ( ) πe + f ( ) ln 8. f ( ) ln e 5 f ( ) ln f ( ) ln e 9. ( ) f ( ) ln e 0. Find the equation of the tangent line to the graph of the function at the point (, 0). a. f ( ) ln b. f ( ) ln. Consider the function f ( ) e. a. Find the slope of f() at the point where it crosses the -ais. b. Find the equation of the tangent line to the curve at this point. c. Find the equation of the normal line to the curve at this point.. Find the equation of the tangent line to the function f ( ) ln at the point (, ). Part 5: Differentiability When we eamined functions with negative eponents as well as the natural eponential and logarithmic functions, we found that there were certain values where we could not find the derivative of a function. There are actually several situations that destroy differentiability at a point. In order to determine whether a function is differentiable at a given point, we will again return to the definition of the derivative. Eample : Consider the function f ( ). Find the derivative of this function at. Solution: Substituting into the definition, we get f ( + ) f ( ) + lim lim lim 0 0 0 The limit does not eist, because the limit from the left and from the right differ: lim + 0 but lim 0 Therefore, the derivative does not eist at. Or, in other words, the function f ( ) is not differentiable at. 9

Eamine the graph of the function at. The graph comes to a sharp point at. Now, study the graph of the derivative as given by the calculator. It supports the results found by using the definition of the derivative. Now, use the command on your calculator to find the derivative of the function at. Obviously, the calculator is giving an incorrect answer. Why is that? Recall that your calculator uses the symmetric difference quotient when computing the derivative. Essentially, it is averaging the right and left hand limits as it approaches the given value. In this case, the left and right hand limits are - and, and when averaged they give 0. No matter how small a you choose, you will always get left and right hand limits of - and and you will get an averaged value of 0. The calculator will always give an incorrect answer when the graph comes to a sharp point, so it is important to eamine the graph of a function when using the calculator to find the numeric derivative. Note, the derivative of f() does eist at other points. You can find f. '(0) f '(0). It is -. And, Eample : Consider the function ( ) f. Find the derivative of this function at 0. Solution: Using the power rule, we know f '( ) Obviously, when we try to evaluate this at 0, we get an undefined value. What does this mean? 0

Study the graph of the function. At 0, the graph becomes very steep. When you eamine the graph of the derivative you find an asymptote at 0: What does your calculator tell you? There are two values displayed below, one for a of 0.000000 and one for a of 0.0000000000. Note that the values are getting very large; they are approaching infinity. This means that the function has a vertical tangent line at the point 0, a tangent line with an undefined slope. Again, you cannot trust your calculator to find the correct derivative for you at this particular value. It is possible to find the derivative of this function at any other value on your calculator or by using the power rule. Eample : Consider the piecewise function of the function at. f ( ) + if < if and find the derivative Solution: f '( ) if < and f '( ) if. For both of these, if we substitute, we get a value of 0. This implies that there is a horizontal tangent line for the function at. But does this make sense? Again, eamine the graph of the function. There is a discontinuity at. It doesn t make sense that there is a tangent line at a point of discontinuity.

These three eamples illustrate three ways that differentiability can be destroyed:. When the graph of a function comes to a sharp point. There is no tangent line at this point.. When the derivative of a function is undefined at a particular value and the graph of the function becomes so steep that it appears almost vertical itself. The tangent line is a vertical line with an undefined slope.. When the graph of a function is not continuous at a value. There is no tangent line at this point. These situations are illustrated below. a b c d At points a and b, the function is discontinuous and therefore not differentiable. There are no tangent lines to the curve at these points. At point c, the function is continuous but not differentiable since the curve comes to a sharp point. There is no tangent line at this point. At point d, the function is again continuous, but not differentiable. However, there is a vertical tangent line at this point. Homework Eercises Part 5: Differentiability Eamine the graphs of each of the following functions. Indicate the points at which the functions are not differentiable, and give the reason this occurs.. f ( ) 5.... f ( ) f ( ) f f ( ) f ( ) 5 6. ( ) 7. ( ) 8. 9. Determine whether the functions below are differentiable at. f ( ) f ( ) a. + if f ( ) if > b. + if < g( ) if

0. Consider the pictured function below: a. Where on the interval < < 7 does the limit of the function fail to eist? b. Where on the interval < < 7 does the function fail to be continuous? c. Where on the interval < < 7 does the function fail to be differentiable? d. Where on the interval < < 7 is f '( ) 0? Determine if the following statements are true or false.. If f '( ) g '( ) for all, then f ( ) g( ). If f ( ) π, then f '( ) π.. If f '( c ) eists, then f is continuous at c. for all.. The graph of y has a tangent line at 0 but the derivative of the function does not eist there. 5. The derivative of a polynomial is a polynomial. 6. If a function is continuous at a point, then it is differentiable at that point. 7. If a function has derivatives from both the right- and the left-sides of a point, then it is differentiable at that point. Part 6: Other Notations and Higher Order Derivatives The f '( ) notation is one of the most common notations for derivatives, but there are others: dy, D f, d d d ( f ) These three notations use d or D to indicate taking the derivative of a function named y or f: the derivative of y with respect to or the derivative of f with respect to. In these cases, y or f is the dependent variable; is the independent variable. Eample : Find each of the indicated derivatives: a. ( t sin t) b. D ( a + b + c) Solutions: For part a, you are being asked to find the derivative of the given function with respect to the d dt independent variable t: ( ) d dt sin 6 cos t t t t

For part b, you are being asked to find the derivative of the given function with respect to the independent variable. This indicates that a, b, and c are constants. ( ) D a + b + c a + b There are several applications for higher order derivatives; i.e., derivatives of derivatives. We will eamine these applications in the net chapter. It is important to learn the notation and practice the process before learning the applications. The derivative of the first derivative is the second derivative. It can be denoted by f '( ), D y or d y d. A summary of notations is given below. Derivative f notation D notation dy first f '( ) D y second f '( ) D y third f '( ) D y fourth iv f ( ) fifth v f ( ) n th ( n f ) ( ) D y 5 D y n D y d notation dy d d y d d y d d y d 5 d y 5 d n d y n d Eample : Find the first five derivatives of f ( ) sin Solution: f '( ) cos f '( ) sin f '( ) cos iv f ( ) sin v f ( ) cos Eample : Find the first four derivatives of y ln Solution: d y dy d d d y d y 6 d d

One type of problem that we have studied throughout the last two units has been position and velocity. We learned that the change in position () with respect to time (t) yielded velocity; i.e., velocity d. The change in velocity (v) with respect to time yields acceleration; i.e., acceleration Eample : dv dt dt d An object moves along a path so that its position is defined by the function ( t) t t + 8, where is measured in centimeters and t in seconds (t > 0). Determine the velocity when t and t 6. When is the velocity 0? Determine the acceleration at t. d Solution: Velocity 6t. So, at t, the velocity is -8 cm/sec. At t 6, the dt velocity is 9 cm/sec. The velocity is 0 when 6t 0. Solving this equation, we get 6t 6( t ) 6( t )( t + ) t ±. Since t > 0, the velocity is 0 dv at t seconds. Acceleration t. At t, the acceleration is cm/sec. dt Homework Eercises Part 6: Other Notations and Higher Order Derivatives Find the first three derivatives for each of the following functions.. + 6 5 5. f ( ) y. y cos. y 6. f ( ) e 7. y ln ( ) f ( ) 8. f ( ) sin + cos. 9. Without using any formulas, find the following derivatives. Eplain your reasoning. 5 a. D ( + 5 7) 5 b. D ( sin ) c. D 9 ( e ) dt 0. Suppose + + and f () 5, f '(), f '(). Find a, b, and c. f ( ) a b c. The position of an object moving along a coordinate line is given by ( t) sin t. Find the velocity and π acceleration of the object at time t.. The position of an object thrown upward on the moon is given by the function ( t).7t + 7t + 6 where is measured in feet and t is measured in seconds. a. Find epressions for the velocity and acceleration of the object. b. Find the time when the object is at its highest point by finding the time when the velocity is 0. What is the height at this time? 5

. The graphs of f(), f'() and f''() are shown. Choose the letter (a, b, or c) that represents each. b c a True/False 5 d y. If y ( )( + )( + 5)( 7) then 0 5 d. 5. The second derivative represents the rate of change of the first derivative. 6. If the velocity of an object is constant, then its acceleration is 0. Part 7: Other Differentiation Rules Consider the function, y sin. This is a product of two functions for which we know the derivatives. We also know that the derivative of the sum of two functions is the sum of the derivatives. Is this true of the product of two derivatives? If it was true that the derivative of the product of two functions is the product of the derivatives of the two functions, then the derivative of sin should be ()(cos ). We can check this graphically with the calculator. The function and its derivative are pictured below. Y It is obvious that the graph of the derivative of sin functions is NOT the product of the derivatives of the two functions. What of the derivative of the quotient of two functions? Consider the function is not cos. Therefore, the derivative of the product of two y e Y. If the derivative of the quotient of two functions is the quotient of the derivatives of the two functions, then the derivative should be or e e Y Y This is not the graph of e. Therefore, the derivative of the quotient of two functions is NOT the quotient of the derivatives of the two functions. 6

What of the derivative of the function of a function (the composite of two functions)? Consider the function y sin ( + ) Is the derivative of this function simply cos ( ) +? Y Y y cos( + ) Again, the rule is not so simple. The derivative of the composite of two functions is NOT simply the derivative of the principal function composed with the given function. A special rule called the chain rule is needed in this case. Chain Rule: If f is differentiable at, g is differentiable at f(), and h() g(f()), then h is differentiable at and h () g (f()). f (). For the eample above, if we let f ( ) + and g( ) sin, then h( ) g( f ( )), f '( ), and g '( ) cos. Therefore, according to the rule, ( ) h '( ) cos( f ( )) cos( + ) cos +. The graph of this function is pictured below. Note that it is the same function pictured in Y above, the derivative of y sin ( + ) So, in order to apply the Chain Rule, a composite function must be decomposed into its component parts, the derivatives of each of these component parts must be determined and the Rule applied. 7

Eample : Find the derivative of Solution: Let Thus, f ( ) h( ) and g( ). f '( ) and g '( ). Using the rule, we get Eample : Find the derivative of ( ) ( ) h '( ) f ( ) ( ) ( ) h( ) e Solution: Let f ( ) and g( ) e. Thus, f '( ) and g '( ) e. Using the rule, we get h '( ) e () e () e f ( ) The two rules yet to be learned are the product and quotient rules; and, the chain rule must be more completely eplored. In combination with the rules already learned, they will allow you to find the derivative of any function. The product and quotient rules will be studied net year in calculus, as well as combinations of all the rules in much more complicated functions. Homework Eercises Part 7: Other Differentiation Rules For problems - 6, find h '( )... h( ) ( + ) 0. h( ) ( cos ). h( ) ln ( ) 5. h( ) sin ( ). h( ) sin e 6. h( ) For problems 7-6, determine if the derivatives rules from this chapter apply. If they do, find the derivative. If they do not, indicate why. 7. y. y sin 8. y π. y 9. y. y e 0.. y y 5. y (ln ) e e 6. y π + e + 8

True/False 7. If 8. If 9. If y dy. d 0. If f ( ) dy y π, then π. d. If y +, then dy y, then. π d π Optional Eercises:, then. Using the function f ( ) sin, verify the product rule: ( fg )' f ' g + fg '.. Using the function f ( ) e, verify the quotient rule: ' f f ' g fg ' g g f '( ) +. dy d. Homework Eercises Review Find the derivative of each of the following:... f ( ) 7. f ( ) sin cos f ( ) 8. f ( ) e ln π f ( ) 9. f ( ) π f ( ) 0. f ( ) ( tan )( cos ) f ( ) ( )( + ). f ( ) + f ( ) ln e. f ( ). 5. 6. ( )( ) Find the second derivative for each of the following:. f ( ) 5. f ( ) sin cos. f ( ) ( )( ) f ( ) ln + 6. ( ) 7. Find the equation of the normal line and the tangent line to the curve y ln at. 8. Sketch the graph of f ( ). a. Is f continuous at? Why or why not? b. Is f differentiable at? Why or why not? 9

9. Sketch the graph of + + if < f ( ) if a. Is f continuous at -? Why or why not? b. Is f differentiable at -? Why or why not? 0. Let f be the real-valued functioned defined by f ( ) a. Give the domain and range of f. b. Determine the slope of the line tangent to the graph of f at. c. Determine the y-intercept of the line tangent to the graph of f at. d. Give the coordinates of the point on the graph of f where the tangent line is parallel to y. AP Calculus Problem: 978 AB Given True/False. f ( ) +. The point (a, b) is on f() and a tangent line passes through (a, b) and (0, -8), which is not on the graph of f(). Find a and b.. If a function is continuous, then it is differentiable.. If f ( ) g( ) + c, then f '( ) g '( ).. If f() is an n th degree polynomial, then 5. If f() is an n th degree polynomial, then 6. The acceleration of an object can be negative. ( n f ) ( ) 0. ( n+ f ) ( ) 0 ( ) 7. If f ( ), then f ( ). 5 8. If f() is differentiable at c, then f'() is differentiable at c. 9. If a graph of a function has a tangent line at a point, then it is differentiable at that point. dy 0. If y f ( ) g( ), then f '( ) g '( ) d. 0