AP CHEMISTRY 2009 SCORING GUIDELINES

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AP CHEMISTRY 2009 SCORING GUIDELINES Question 1 (10 points) Answer the following questions that relate to the chemistry of halogen oxoacids. (a) Use the information in the table below to answer part (a)(i). Acid HOCl K a at 298 K 2.9 10 8 HOBr 2.4 10 9 (i) Which of the two acids is stronger, HOCl or HOBr? Justify your answer in terms of K a. HOCl is the stronger acid because its K a value is greater than the K a value of HOBr. One point is earned for the correct answer with justification. (ii) Draw a complete Lewis electrondot diagram for the acid that you identified in part (a)(i). One point is earned for a correct diagram. (iii) Hypoiodous acid has the formula HOI. Predict whether HOI is a stronger acid or a weaker acid than the acid that you identified in part (a)(i). Justify your prediction in terms of chemical bonding. HOI is a weaker acid than HOCl because the O H bond in HOI is stronger than the O H bond in HOCl. The lower electronegativity (electrondrawing ability) of I compared with that of Cl results in an electron density that is higher (hence a bond that is stronger) between the H and O atoms in HOI compared with the electron density between the H and O atoms in HOCl. OR The conjugate base OCl is more stable than OI because Cl, being more electronegative, is better able to accommodate the negative charge. One point is earned for predicting that HOI is a weaker acid than HOCl and stating that iodine has a lower electronegativity than chlorine and EITHER stating that this results in a stronger O H bond in HOI OR stating that this decreases the stability of the OI ion in solution. 2009 The College Board. All rights reserved.

AP CHEMISTRY 2009 SCORING GUIDELINES Question 1 (continued) (b) Write the equation for the reaction that occurs between hypochlorous acid and water. HOCl + H 2 O Æ OCl + H 3 O + OR HOCl Æ OCl + H + One point is earned for the correct equation. (c) A 1.2 M NaOCl solution is prepared by dissolving solid NaOCl in distilled water at 298 K. The hydrolysis reaction OCl (aq) + H 2 O(l) Æ HOCl(aq) + OH (aq) occurs. (i) Write the equilibriumconstant expression for the hydrolysis reaction that occurs between OCl (aq) and H 2 O(l). K b = [HOCl][OH ] [OCl ] One point is earned for the correct expression. (ii) Calculate the value of the equilibrium constant at 298 K for the hydrolysis reaction. K b = K K w a = 1.0 10 2.9 10 14 8 = 3.4 10 7 One point is earned for the correct value with supporting work. (iii) Calculate the value of [OH ] in the 1.2 M NaOCl solution at 298 K. [OCl ] [HOCl] [OH ] initial value 1.2 0 0 change x x x equilibrium value 1.2 x x x One point is earned for the correct setup. K hyd = 3.4 10 7 = [OH ][HOCl] [OCl ] = ( x)( x) (1.2 x) 2 x 1.2 One point is earned for the correct answer with supporting calculations. (1.2)(3.4 10 7 ) = x 2 x = [OH ] = 6.4 10 4 M 2009 The College Board. All rights reserved.

AP CHEMISTRY 2009 SCORING GUIDELINES Question 1 (continued) (d) A buffer solution is prepared by dissolving some solid NaOCl in a solution of HOCl at 298 K. The ph of the buffer solution is determined to be 6.48. (i) Calculate the value of [H 3 O + ] in the buffer solution. [H + ] = 10 6.48 = 3.3 10 7 M One point is earned for the correct value. (ii) Indicate which of HOCl(aq) or OCl (aq) is present at the higher concentration in the buffer solution. Support your answer with a calculation. [H + ] = 3.3 10 7 M and K a for HOCl = 2.9 10 8 K a = 2.9 10 8 = + [H ][OCl ] [HOCl] 7 (3.3 10 )[OCl ] [HOCl] One point is earned for the correct answer with supporting buffer calculations. [OCl ] [HOCl] = 2.9 10 3.3 10 8 7 = 0.088 [HOCl] > [OCl ] 2009 The College Board. All rights reserved.

1A 1 of 2

1A 2 of 2

1B 1 of 2

1B 2 of 2

1 of 2 1C 1 of 2

1C 2 of 2

AP CHEMISTRY 2009 SCORING COMMENTARY Question 1 Overview This question assessed the breadth of students understanding of weak acid/weak base/buffer equilibria in aqueous solution and their ability to apply the concepts to solve problems. In part (a)(i) students were required to interpret given K a values of two halogen oxoacids to determine their relative acid strengths. In part (a)(ii) students were asked to draw a complete Lewis electrondot diagram for one of the halogen oxoacids, and in part (a)(iii) they had to predict and justify the relative strength of a third oxoacid in terms of principles of chemical bonding. In part (b) students were asked to write a balanced chemical equation for the reaction of a weak acid in aqueous solution. In part (c) they were required to write a hydrolysis expression, calculate the value of K b (hydrolysis equilibrium constant) from the given value of K a, and calculate [OH ] for a solution of the conjugate base of one of the oxoacids of given concentration. Finally, in part (d) students had to determine [H 3 O + ] in a buffer solution of given ph and to apply the definition of K a (or the Henderson Hasselbalch equation) to determine the relative concentrations of HOCl and OCl in the buffer solution. Sample: 1A Score: 10 This response earned all 10 points: 1 for part (a)(i), 1 for part (a)(ii), 1 for part (a)(iii), 1 for part (b), 1 for part (c)(i), 1 for part (c)(ii), 2 for part (c)(iii), 1 for part (d)(i), and 1 for part (d)(ii). Sample: 1B Score: 8 The point was not earned in part (c)(i) because the denominator is omitted from the expression. The point was not earned in part (d)(ii) because the justification is incorrect. Sample: 1C Score: 4 The point was not earned in part (a)(i) because the response incorrectly states the relative magnitudes of the K a values given. The point was not earned in part (a)(iii) because the statement that [t]he stronger the bonds, the stronger the acid is vague and incorrect. None of the possible 3 points was earned in parts (c)(ii) and (c)(iii). The point was not earned in part (d)(ii) because the justification is incorrect. 2009 The College Board. All rights reserved.