1.4 Linear Models. Cost, Revenue, and Profit Functions. Example 1 Linear Cost Function



Similar documents
3.3 Applications of Linear Functions

1 Mathematical Models of Cost, Revenue and Profit

1 Functions, Graphs and Limits

Section 1.1 Linear Equations: Slope and Equations of Lines

EQUATIONS and INEQUALITIES

CHAPTER 1 Linear Equations

Week 1: Functions and Equations

Math 113 Review for Exam I

The Point-Slope Form

Math 120 Final Exam Practice Problems, Form: A

1.2 Break-Even Analysis and Market Equilibrium

Name: Class: Date: ID: A

What does the number m in y = mx + b measure? To find out, suppose (x 1, y 1 ) and (x 2, y 2 ) are two points on the graph of y = mx + b.

Section 1.5 Linear Models

Lesson 4: Solving and Graphing Linear Equations

Warm Up. Write an equation given the slope and y-intercept. Write an equation of the line shown.

Slope-Intercept Form of a Linear Equation Examples

Section 3-7. Marginal Analysis in Business and Economics. Marginal Cost, Revenue, and Profit. 202 Chapter 3 The Derivative

Applied Finite Mathematics Second Edition. Rupinder Sekhon De Anza College Cupertino, California. Page 1

Graphing Linear Equations

Slope-Intercept Equation. Example

MA.8.A.1.2 Interpret the slope and the x- and y-intercepts when graphing a linear equation for a real-world problem. Constant Rate of Change/Slope

Worksheet A5: Slope Intercept Form

Marginal Cost. Example 1: Suppose the total cost in dollars per week by ABC Corporation for 2

Math 1314 Lesson 8 Business Applications: Break Even Analysis, Equilibrium Quantity/Price

-2- Reason: This is harder. I'll give an argument in an Addendum to this handout.

Graphing Linear Equations in Two Variables

Exhibit 7.5: Graph of Total Costs vs. Quantity Produced and Total Revenue vs. Quantity Sold

Chapter 6: Break-Even & CVP Analysis

1.3 LINEAR EQUATIONS IN TWO VARIABLES. Copyright Cengage Learning. All rights reserved.

MATH 60 NOTEBOOK CERTIFICATIONS

Part 1 Expressions, Equations, and Inequalities: Simplifying and Solving

Homework #1 Solutions

MATH Fundamental Mathematics IV

Elements of a graph. Click on the links below to jump directly to the relevant section

Write the Equation of the Line Review

Let s explore the content and skills assessed by Heart of Algebra questions.

Quiz Chapter 7 - Solution

Linear Equations. Find the domain and the range of the following set. {(4,5), (7,8), (-1,3), (3,3), (2,-3)}

Chapter 1 Linear Models page Linear Models Part 1 2 Linear Models Activities 1 17 Linear Models Part 2 21 Linear Models Activities 2 28

Lines, Lines, Lines!!! Slope-Intercept Form ~ Lesson Plan

Overview. Observations. Activities. Chapter 3: Linear Functions Linear Functions: Slope-Intercept Form

Linear Equations. 5- Day Lesson Plan Unit: Linear Equations Grade Level: Grade 9 Time Span: 50 minute class periods By: Richard Weber

Pricing I: Linear Demand

2013 MBA Jump Start Program

Unit 1 Equations, Inequalities, Functions

Systems of Linear Equations: Two Variables

Business and Economic Applications

Algebra I. In this technological age, mathematics is more important than ever. When students

1.2 GRAPHS OF EQUATIONS. Copyright Cengage Learning. All rights reserved.

Models of a Vending Machine Business

01 In any business, or, indeed, in life in general, hindsight is a beautiful thing. If only we could look into a

Business and Economics Applications

Temperature Scales. The metric system that we are now using includes a unit that is specific for the representation of measured temperatures.

IV. ALGEBRAIC CONCEPTS

EdExcel Decision Mathematics 1

3.2. Solving quadratic equations. Introduction. Prerequisites. Learning Outcomes. Learning Style

Solving Quadratic Equations

Vectors. Objectives. Assessment. Assessment. Equations. Physics terms 5/15/14. State the definition and give examples of vector and scalar variables.

Acquisition Lesson Plan for the Concept, Topic or Skill---Not for the Day

Intro to Linear Equations Algebra 6.0

1 Solve problems using. 2 Use functions to model. 3 Perform a break-even SECTION PROBLEM SOLVING AND BUSINESS APPLICATIONS USING SYSTEMS OF EQUATIONS

1 Determine whether an. 2 Solve systems of linear. 3 Solve systems of linear. 4 Solve systems of linear. 5 Select the most efficient

Review of Fundamental Mathematics

A synonym is a word that has the same or almost the same definition of

ANSWERS TO END-OF-CHAPTER QUESTIONS

Application. Outline. 3-1 Polynomial Functions 3-2 Finding Rational Zeros of. Polynomial. 3-3 Approximating Real Zeros of.

Practice Test Answer and Alignment Document Mathematics: Algebra II Performance Based Assessment - Paper

Lecture 8 : Coordinate Geometry. The coordinate plane The points on a line can be referenced if we choose an origin and a unit of 20

Section 2.5 Average Rate of Change

Linear Equations and Inequalities

Lesson 7 - The Aggregate Expenditure Model

Example SECTION X-AXIS - the horizontal number line. Y-AXIS - the vertical number line ORIGIN - the point where the x-axis and y-axis cross

volume-profit relationships

Learning Objectives for Section 1.1 Linear Equations and Inequalities

Math 1526 Consumer and Producer Surplus

Microeconomics Sept. 16, 2010 NOTES ON CALCULUS AND UTILITY FUNCTIONS

Solving Equations Involving Parallel and Perpendicular Lines Examples

This unit has primarily been about quadratics, and parabolas. Answer the following questions to aid yourselves in creating your own study guide.

Part Three. Cost Behavior Analysis

Part II Management Accounting Decision-Making Tools

Graphing - Slope-Intercept Form

Midterm 2 Review Problems (the first 7 pages) Math Intermediate Algebra Online Spring 2013

Algebraic expressions are a combination of numbers and variables. Here are examples of some basic algebraic expressions.

Session 7 Bivariate Data and Analysis

Florida Algebra 1 End-of-Course Assessment Item Bank, Polk County School District

Fractions Practice: Answers

LINEAR EQUATIONS IN TWO VARIABLES

TI-83/84 Plus Graphing Calculator Worksheet #2

In the Herb Business, Part III Factoring and Quadratic Equations

Lecture 2. Marginal Functions, Average Functions, Elasticity, the Marginal Principle, and Constrained Optimization

The term marginal cost refers to the additional costs incurred in providing a unit of

Money Math for Teens. Break-Even Point

Student Activity: To investigate an ESB bill

1.7 Graphs of Functions

Problem Solving and Data Analysis

Part 1: Background - Graphing

Transcription:

16314_02_ch1_p033-112.qxd 7/17/06 4:10 PM Page 66 66 Chapter 1 Functions and Linear Models 77. If y and x are related by the linear expression y = mx + b, how will y change as x changes if m is positive? negative? zero? 78. Your friend April tells you that y = f (x) has the property that, whenever x is changed by x, the corresponding change in y is y = x. What can you tell her about f? 79. tech Ex Consider the following worksheet: What is the effect on the slope of increasing the y-coordinate of the second point (the point whose coordinates are in Row 3)? Explain. 80. tech Ex Referring to the worksheet in Exercise 79, what is the effect on the slope of increasing the x-coordinate of the second point (the point whose coordinates are in row 3)? Explain. basic skills tech Ex technology exercise 1.4 Linear Models Using linear functions to describe or approximate relationships in the real world is called linear modeling. We start with some examples involving cost, revenue, and profit. Cost, Revenue, and Profit Functions Example 1 Linear Cost Function As of January, 2005, Yellow Cab Chicago s rates were $1.90 on entering the cab plus $1.60 for each mile. * a. Find the cost C of an x-mile trip. b. Use your answer to calculate the cost of a 40-mile trip. c. What is the cost of the second mile? What is the cost of the tenth mile? d. Graph C as a function of x. Photodisc/Getty Images Solution a. We are being asked to find how the cost C depends on the length x of the trip, or to find C as a function of x. Here is the cost in a few cases: Cost of a 1-mile trip: C 1.60(1) 1.90 3.50 1 mile @ $1.60 per mile plus $1.90 Cost of a 2-mile trip: C 1.60(2) 1.90 5.10 2 miles @ $1.60 per mile plus $1.90 Cost of a 3-mile trip: C 1.60(3) 1.90 6.70 3 miles @ $1.60 per mile plus $1.90 Do you see the pattern? The cost of an x-mile trip is given by the linear function: C(x) = 1.60x + 1.90 Notice that the slope 1.60 is the incremental cost per mile. In this context we call 1.60 the marginal cost; the varying quantity 1.60x is called the variable cost. The * According to their website at www.yellowcabchicago.com/.

16314_02_ch1_p033-112.qxd 7/17/06 4:10 PM Page 67 1.4 Linear Models 67 C-intercept 1.90 is the cost to enter the cab, which we call the fixed cost. In general, a linear cost function has the following form: Variable cost } C(x) = mx + b Marginal cost Fixed cost b. We can use the formula for the cost function to calculate the cost of a 40-mile trip as: C(40) = 1.60(40) + 1.90 = $65.90 c. To calculate the cost of the second mile, we could proceed as follows: 1 C (dollars) 1 C 1.60x 1.90 Marginal cost Slope 1.60 Fixed cost C-intercept 1.90 Figure 16 x (miles) Find the cost of a 1-mile trip: C(1) 1.60(1) 1.90 $3.50 Find the cost of a 2-mile trip: C(2) 1.60(2) 1.90 $5.10 Therefore, the cost of the second mile is $5.10 $3.50 $1.60 But notice that this is just the marginal cost. In fact, the marginal cost is the cost of each additional mile, so we could have done this more simply: Cost of second mile Cost of tenth mile Marginal cost $1.60 d. Figure 16 shows the graph of the cost function, which we can interpret as a cost vs. miles graph. The fixed cost is the starting height on the left, while the marginal cost is the slope of the line. + Before we go on... In general, the slope m measures the number of units of change in y per 1-unit change in x, so we measure m in units of y per unit of x: Units of Slope = Units of y per unit of x In Example 1, y is the cost C, measured in dollars, and x is the length of a trip, measured in miles. Hence, Units of Slope Units of y per Unit of x Dollars per mile The y-intercept b, being a value of y, is measured in the same units as y. In Example 1, b is measured in dollars. Here is a summary of the terms used in the preceding example, along with an introduction to some new terms. Cost, Revenue, and Profit Functions A cost function specifies the cost C as a function of the number of items x. Thus, C(x) is the cost of x items. A cost function of the form C(x) = mx + b is called a linear cost function. The quantity mx is called the variable cost and the intercept b is called the fixed cost. The slope m, the marginal cost, measures the incremental cost per item.

16314_02_ch1_p033-112.qxd 7/17/06 4:10 PM Page 68 mathematics At Work Regimen is a retail shop and online merchant of high-end men s grooming products, a small business venture under my development. I came up with this concept in order fill the growing demand for men s grooming products from both graying baby boomers wanting to retain their competitive edge and young men who are increasingly accepting of the idea that is essential to be well styled and well groomed. The currently $3.5 billion a year men s grooming market is ever-expanding and there is tremendous opportunity for Regimen to take advantage of this untapped potential. In the initial stages of this business venture I have relied on math to calculate the amount of capital needed to launch and sustain the business until it becomes profitable. Using spreadsheets I input projected sales figures and estimated monthly expenses to formulate if it is possible to realistically Patrick Farace Esteban Silva Owner Regimen TITLE INSTITUTION meet targets and achieve break-even in a timely matter. With assistance from a professional interior designer, I have drawn up plans which include space acquisition, contracting, and construction costs in order budget for build-out expenses. I have teamed up with Yahoo! Small Business Solutions and devised an online advertising strategy which allows me to reach out to the niche customers my company s products are geared towards. Using a sponsored search method of advertising I pre-determine how much I am willing to spend for each combination of keywords which drive traffic onto my website via Yahoo! I can track on a daily basis the number of matches each combination of keywords are receiving and, therefore, determine if any of them need to be altered. It s very important that I analyze these figures frequently so I can redirect the limited marketing resources of this start-up company into the most effective channels available. Thankfully, the applied mathematics techniques I learned in college have helped me live the dream of owning my own business and being my own boss. quick Example The revenue resulting from one or more business transactions is the total payment received, sometimes called the gross proceeds. If R(x) is the revenue from selling x items at a price of m each, then R is the linear function R(x) = mx and the selling price m can also be called the marginal revenue. The profit, on the other hand, is the net proceeds, or what remains of the revenue when costs are subtracted. If the profit depends linearly on the number of items, the slope m is called the marginal profit. Profit, revenue, and cost are related by the following formula: Profit = Revenue Cost P = R C If the profit is negative, say $500, we refer to a loss (of $500 in this case). To breakeven means to make neither a profit nor a loss. Thus, break-even occurs when P = 0, or R = C Break-even The break-even point is the number of items x at which break-even occurs. If the daily cost (including operating costs) of manufacturing x T-shirts is C(x) = 8x + 100, and the revenue obtained by selling x T-shirts is R(x) = 10x, then the daily profit resulting from the manufacture and sale of x T-shirts is P(x) = R(x) C(x) = 10x (8x + 100) = 2x 100 Break-even occurs when P(x) = 0, or x = 50.

16314_02_ch1_p033-112.qxd 7/17/06 4:10 PM Page 69 1.4 Linear Models 69 Example 2 Cost, Revenue, and Profit The manager of the FrozenAir Refrigerator factory notices that on Monday it cost the company a total of $25,000 to build 30 refrigerators and on Tuesday it cost $30,000 to build 40 refrigerators. a. Find a linear cost function based on this information. What is the daily fixed cost, and what is the marginal cost? b. FrozenAir sells its refrigerators for $1500 each. What is the revenue function? c. What is the profit function? How many refrigerators must FrozenAir sell in a day in order to break even for that day? What will happen if it sells fewer refrigerators? If it sells more? Solution a. We are seeking C as a linear function of x, the number of refrigerators sold: C = mx + b We are told that C = 25,000 when x = 30, and this amounts to being told that (30, 25,000) is a point on the graph of the cost function. Similarly, (40, 30,000) is another point on the line (Figure 17). Cost (dollars) 35,000 C 30,000 25,000 20,000 15,000 10,000 5,000 0 0 10 20 30 40 50 x 60 Number of refrigerators Figure 17 We can now use the point-slope formula to construct a linear cost equation. Recall that we need two items of information: a point on the line and the slope: Point Let s use the first point: (x 1, C 1 ) (30,25,000) C plays the role of y Slope m = C 2 C 1 30,000 25,000 = 500 Marginal cost $500 x 2 x 1 40 30 The cost function is therefore C(x) = 500x + b where b = C 1 mx 1 = 25,000 (500)(30) = 10,000 Fixed cost $10,000 so C(x) = 500x + 10,000 Because m = 500 and b = 10,000 the factory s fixed cost is $10,000 each day, and its marginal cost is $500 per refrigerator. b. The revenue FrozenAir obtains from the sale of a single refrigerator is $1500. So, if it sells x refrigerators, it earns a revenue of R(x) = 1500x

16314_02_ch1_p033-112.qxd 7/17/06 4:10 PM Page 70 70 Chapter 1 Functions and Linear Models + c. For the profit, we use the formula Profit = Revenue Cost For the cost and revenue, we can substitute the answers from parts (a) and (b) and obtain P(x) = R(x) C(x) Formula for profit = 1500x (500x + 10,000) Substitute R(x) and C(x) = 1000x 10,000 Here, P(x) is the daily profit FrozenAir makes by making and selling x refrigerators. Finally, to break even means to make zero profit. So, we need to find the x such that P(x) = 0. All we have to do is set P(x) = 0 and solve for x: 1000x 10,000 = 0 giving x = 10,000 1000 = 10 To break even, FrozenAir needs to manufacture and sell 10 refrigerators in a day. For values of x less than the break-even point, 10, P(x) is negative, so the company will have a loss. For values of x greater than the break-even point, P(x) is positive, so the company will make a profit. This is the reason why we are interested in the point where P(x) = 0. Since P(x) = R(x) C(x), we can also look at the break-even point as the point where Revenue Cost: R(x) = C(x) (see Figure 18). Before we go on... We can graph the cost and revenue functions from Example 2, and find the break-even point graphically (Figure 18): Cost: C(x) = 500x + 10,000 Revenue: R(x) = 1500x 45,000 40,000 35,000 30,000 25,000 20,000 15,000 10,000 5,000 C Loss Break-even Revenue Cost 0 0 5 10 15 20 25 Profit Break-even occurs at the point of intersection of the graphs of revenue and cost. Figure 18 The break-even point is the point where the revenue and cost are equal that is, where the graphs of cost and revenue cross. Figure 18 confirms that break-even occurs when x = 10 refrigerators. Or, we can use the graph to find the break-even point in the first x

16314_02_ch1_p033-112.qxd 7/17/06 4:10 PM Page 71 1.4 Linear Models 71 place. If we use technology, we can zoom in for an accurate estimate of the point of intersection. Excel has an interesting feature called Goal Seek that can be used to find the point of intersection of two lines numerically (rather than graphically). The downloadable Excel tutorial for this section contains detailed instructions on using Goal Seek to find break-even points. Demand and Supply Functions The demand for a commodity usually goes down as its price goes up. It is traditional to use the letter q for the (quantity of ) demand, as measured, for example, in weekly sales. Consider the following example. Example 3 Linear Demand Function You run a small supermarket, and must determine how much to charge for Hot n Spicy brand baked beans. The following chart shows weekly sales figures for Hot n Spicy at two different prices. Price/Can ( p) $0.50 $0.75 Demand (cans sold/week) (q) 400 350 a. Model the data by expressing the demand q as a linear function of the price p. b. How do we interpret the slope? The q-intercept? c. How much should you charge for a can of Hot n Spicy beans if you want the demand to increase to 410 cans per week? Solution Demand (cans sold per week) q 500 400 300 200 100 0 p 0 0.2 0.4 0.6 0.8 1 Price per can ($) Figure 19 a. A demand equation or demand function expresses demand q (in this case, the number of cans of beans sold per week) as a function of the unit price p (in this case, price per can). We model the demand using the two points we are given: (0.50, 400) and (0.75, 350). Point: (0.50, 400) Slope: m = q 2 q 1 350 400 = p 2 p 1 0.75 0.50 = 50 0.25 = 200 Thus, the demand equation is q = mp + b = 200p + (400 ( 200)(0.50)) or q = 200p + 500 Figure 19 shows the data points and the linear model. b. The key to interpreting the slope, m = 200, is to recall (see Example 1) that we measure the slope in units of y per unit of x. In this example, we mean units of q per unit of p, or the number of cans sold per dollar change in the price. Because m is negative, we see that the number of cans sold decreases as the price increases. We conclude that the weekly sales will drop by 200 cans per $1-increase in the price.