Question 3.1.1 Question Answers a. 123 01111011 b. 202 11001010 c. 67 01000011 d. 7 00000111 e. 252 11111100 f. 91 01011011 g. 116.127.71.3 01110100.01111111.01010001.00000011 h. 255.255.255.0 11111111.11111111.11111111.00000000 i. 192.143.255.255 11000000.10001111.11111111.11111111 j. 12.101.9.16 00001100.01100100.00001001.00010000 Question 3.2.1 Question Answers a. 1110 14 b. 100110 38 c. 11111111 255 d. 11010011 211 e. 01000001 65 f. 11001110 206 g. 01110101 117 h. 10001111 143 i. 11101001.00011011.10000000.10100100 233.27.128.164 j. 10101010.00110100.11100110.00010111 170.52.230.23 Question 3.3.1 1. What is the decimal and binary range of the first octet of all possible Class B IP addresses? Decimal: From: 128 To: 191 Binary: From: 10000000 To: 10111111 2. Which octet(s) represent the network portion of a Class C IP address? First, second & third 3. Which octet(s) represent the host portion of a Class A IP address? Second, third & fourth 4. What is the maximum number of useable hosts with a Class C network address? 254 5. How many Class B networks are there? 16384 6. How many hosts can each Class B network have? 65534 7. How many octets are there in an IP address? How many bits per octet? 4 octets, 8 bits per octet
Question 3.3.2 Host IP Class Network Host Network Broadcast 216.14.55.137 C 216.14.55 137 216.14.55.255 Default Subnet Mask 255.255.255.0 123.1.1.15 A 123 1.1.15. 123.255.255.255 255.0.0.0 150.127.221.244 B 150.127 221.244 150.127.255.255 255.255.0.0 194.125.35.199 C 194.125.35 35 194.125.35.255 255.255.255.0 175.12.239.244 B 175.12 239.244 175.12.255.255 255.255.0.0 Question 3.3.3 IP Host Valid? Why or Why Not (Yes/No) 150.100.255.255 No This is a class B network broadcast address 175.100.255.18 Yes This is a valid class B network address 195.234.253.0 No The last octet cannot be 0 in a valid address, this is subnet address 100.0.0.23 Yes This is a valid class A network address 188.258.221.176 No Octet range cannot be greater than 255 (second octet is not valid) 127.34.25.189 No The first octet is 127, which is reserved for loopback testing 224.156.217.73 No This is a class D address, for multicasting, only valid for servers
Question 3.4.1 Subnet No. Subnet Bits Borrowed Binary Value Subnet Bits Decimal and Subnet No. Host Bits Possible Binary Values (Range) (5 Bits) Subnet/Host Decimal Range Use? 0 Subnet 00 0 00000-11111 0-31 No no subnet 1st Subnet 01 32 00000-11111 32-63 Yes 2nd Subnet 10 64 00000-11111 64-95 Yes 3rd Subnet 11 96 00000-11111 96-127 Yes 4th Subnet 100 128 00000-11111 128-159 Yes 5th Subnet 101 160 00000-11111 160-191 Yes 6th Subnet 110 192 00000-11111 192-223 Yes 7th Subnet 111 224 00000-11111 224-255 No reserved for network broadcast Use the table just developed to help answer the following questions: 1. Which octet(s) represent the network portion of a Class C IP address? 1 st, 2 nd & 3 rd octets 2. Which octet(s) represent the host portion of a Class C IP address? 4 th octet 3. What is the binary equivalent of the Class C network address in the scenario? Decimal network address: 197.15.22.0 Binary network address: 11000101.00001111.00010110.00000000 4. How many high- order bits were borrowed from the host bits in the fourth octet? 3 5. What subnet mask must be used? Show the subnet mask in decimal and binary. Decimal subnet mask: 255.255.255.224 Binary subnet mask: 11111111.11111111.11111111.11100000 6. What is the maximum number of subnets that can be created with this subnet mask? 8 7. What is the maximum number of useable subnets that can be created with this mask? 6 8. How many bits were left in the fourth octet for host IDs? 5 9. How many hosts per subnet can be defined with this subnet mask? 30 10. What is the maximum number of hosts that can be defined for all subnets with this scenario? Assume the lowest and highest subnet numbers and the lowest and highest host ID on each subnet cannot be used. 180 11. Is 197.15.22.63 a valid host IP address with this scenario? Why or why not? No, it is the broadcast address for the first subnet.
12. Is 197.15.22.160 a valid host IP address with this scenario? Why or why not? No, it is the subnet identification address (subnet number) for the 5 th subnet. 13. Host A has an IP address of 197.15.22.126. Host B has an IP address of 197.15.22.129. Are these hosts on the same subnet? Why? No. Host A is on the 3 rd subnet but Host B is on the 4 th subnet.
Question 3.5.1 Given a Class A network address of 10.0.0.0 / 24 answer the following questions 1. How many bits were borrowed from the host portion of this address? 16 2. What is the subnet mask for this network? Dotted decimal? 255.255.255.0 Binary? 11111111.11111111.11111111.00000000 3. How many usable subnetworks are there? 65536 4. How many usable hosts are there per subnet? 254 5. What is the host range for usable subnet sixteen? 1-254 6. What is the network address for usable subnet sixteen? 10.0.16 7. What is the broadcast address for usable subnet sixteen? 10.0.16.255 8. What is the broadcast address for the last usable subnet? 10.255.254.255 9. What is the broadcast address for the major network? 10.255.255.255 Question 3.6.1 Given this Class B network address and these requirements answer the following questions 172.16.0.0 1. How many subnets are needed for this network? 70 2. What is the minimum number of bits that can be borrowed? 7 3. What is the subnet mask for this network? Dotted decimal? 255.255.254.0 Binary? 11111111.11111111.11111110.00000000 4. Slash format /23 5. How many usable subnetworks are there? 126 6. How many usable hosts are there per subnet? 510
Question 3.6.2 Subnetwork # Subnetwork ID Host Range Broadcast ID 0 172.16.0.0 172.16.0.0 172.16.1.254 172.16.1.255 (non- useable) 1 172.16.2.0 172.16.2.1-172.16.3.254 172.16.3.255 2 172.16.4.0 172.16.4.1-172.16.5.254 172.16.5.255 124 172.16.248.0 172.16.248.1-172.16.249.254 172.16.248.255 125 172.16.250.0 172.16.250.1-172.16.251.254 172.16.250.255 126 172.16.252.0 172.16.252.1-172.16.253.254 172.16.252.255 127 172.16.254.0 172.16.254.1 172.16.255.254 (non- useable) 172.16.255.255 (Network Broadcast) 1. What is the host range for subnet two? 172.16.3.1-172.16.5.254 2. What is the broadcast address for the 126th subnet? 172.16.250.255 3. What is the broadcast address for the major network? 172.16.255.255 Question 3.7.1 Given this Class C network address and these requirements answer the following questions 1. How many subnets are needed for this network? 5 useable (7 total) 2. What is the subnet mask for this network? Dotted decimal? 255.255.255.224 Binary? 11111111.11111111.11111111.11100000 3. Slash format 192.168.1.0 /27 4. How many usable hosts are there per subnet? 30
Question 3.7.2 Subnetwork # Subnetwork IP Host Range Broadcast ID 0 192.168.1.0 192.168.1.1-192.168.1.30 (non- 192.168.1.31 useable) 1 192.168.1.32 192.168.1.33-192.168.1.62 192.168.1.63 2 192.168.1.64 192.168.1.65-192.168.1.94 192.168.1.95 3 192.168.1.96 192.168.1.97-192.168.1.126 192.168.1.127 4 192.168.1.128 192.168.1.129-192.168.1.158 192.168.1.159 5 192.168.1.160 192.168.1.161-192.168.1.190 192.168.1.191 6 192.168.1.192 192.168.1.193-192.168.1.222 192.168.1.223 7 192.168.1.224 192.168.1.225-192.168.1.254 (non- useable) 192.168.1.255 (network address) 1. What is the host range for subnet six? 192.168.1.193-192.168.1.222 2. What is the broadcast address for the 3rd subnet? 192.168.1.95 3. What is the broadcast address for the major network? 192.168.1.255