Alloys & Their Phase Diagrams



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Alloys & Their Phase Diagrams

Objectives of the class Gibbs phase rule Introduction to phase diagram Practice phase diagram Lever rule Important Observation: One question in the midterm

Consider the Earth

Gibbs phase rule P + F = C +2 P: number of phases (ie, solid, liquid, or gas) C: number of components F: Degree of freedom

Simple Example Water: a) At the triple point: P = 3 (solid, liquid, and gas) C= 1 (water) P + F = C + 2 F = 0 (no degree of freedom) b) liquid-solid curve P = 2 2+F = 1 + 2 F= 1 One variable (T or P) can be changed c) Liquid P =1 So F =2 Two variables (T and P) can be varied independently and the system will remains a single phase

Unlimited Solutibity

Limited solubility

No Solubility

Solid-Solutions Similar concepts apply to solid solutions: Copper Cu and Nickel Ni are mutually soluble in any amount (unlimited solid solubility). Carbon C has a limited solubility in Iron Fe.

Binary Isomorphous Alloy Systems A mixture of two metals is called a binary alloy and constitutes a two-component system. Each metallic element in an alloy is called a separate component. Isomorphous systems contain metals which are completely soluble in each other and have a single type of crystal structure.

Cu-Ni: A Substitutional Solid Solution (when foreign atoms occupy normal lattice sites occupied) by matrix atoms)

Cu-Ni: Binary Isomorphous Alloy Example

The Lever Rule

Cu-Ni: The Lever Rule

Cu-Ni: Cooling Curves

Cu-Ni: Microstructure during solidification

Cooling curve

Binary Eutectic Alloys

Binary Eutectic Alloy Systems

Eutectic composition:

Example: Point D

Example: Point E

So what?

A Eutectic Cooling Curve

Binary Eutectic Alloy Microstructures

Eutectic Microstructures There are a number of different morphologies # for the two phases in a binary eutectic alloy. Of prime importance is the minimization of the interfacial area between the phases. The rate of cooling can also have an important effect.

Eutectic Microstructures Schematic illustration of the various eutectic microstructures: (a) lamellar, (b) rodlike, (c) globular, and (d) acicular (or needlelike). Morphology means the form, shape or outward microstructure of a phase.

Microstructure evolution

Equilibrium Microstructure of Steel Alloys

The Iron-Iron Carbide Phase Diagram

Steels and Irons

Forging

Forging

Plain-Carbon Steel Steel can be defined as an Iron alloy which transforms to Austenite on heating. A plain-carbon steels has no other major alloying element beside carbon. When a plain-carbon steel is slowly cooled from the Austenitic range it undergoes the eutectoid transformation.

Carbon Steel (90% of the steel production) Low alloy steel (up to 6% of chromium, nickel, etc) Stainless steel (18% chromium and 8% nickel) Tool steels (heavy alloyed with chromium, molybdenum, tungsten, vanadium, and cobalt).

Construction steel Construction steel alloys used for concrete reinforcing bars and structural shapes have been traditionally been 0.1-0.2% C plain-carbon steels with only minor additional elements. In general these alloys are called Low-alloy Steel and for most purposes they can be considered plain-carbon steel.

Eutectoid System Just below the eutectoid point: Note: pearlite is not a phase, but a combination of ferrite and cementite

Eutectoid

Eutectoid Microstructures Just like the eutectic systems there are a number of different morphologies # for the two phases in a binary eutectic alloy. The most common morphology for eutectoid areas in the Fe- Fe 3 C system is lamellar. (This is because most steel is relatively slowly cooled through the eutectoid phase transformation.)

Evolution of Eutectoid Steel Microstructure Hypoeutectoid Hypereutectoid

Slow Cooling of Plain-Carbon Steels Transformation of a 0.4% C hypoeutectoid plain-carbon steel with slow cooling.

Hypoeutectoid

Slow Cooling of Plain-Carbon Steels Transformation of a 1.2% C hypereutectoid plain-carbon steel with slow cooling.

Hypereutectoid

Problem A 0.45%C hypoeutectoid plain-carbon steel is slowly cooled from 950 C to a temperature just slightly above 723 C. Calculate the weight percent austenite and weight percent proeutectoid ferrite in this steel. 0.45 Austenite = (0.45-0.02)/(0.80-0.02) = 55.1% 0.02 0.80 Proeutectoid Ferrite =(0.80-0.45)/(0.8-0.02) = 44.9

A 0.45%C hypoeutectoid plain-carbon steel is slowly cooled from 950 C to a temperature just slightly below 723 C. (a)calculate the weight percent proeutectoid ferrite in this steel. (b) Calculate the weight percent eutectoid ferrite and the weight percent eutectoid cementite in this steel. 0.45 Proeutectoid Ferrite =(0.80-0.45)/(0.8-0.02) =44.9% Cementite = (0.45-0.02)/(6.67-0.02) = 6.5% 0.80 0.02 Total ferrite = (6.67-0.45)/(6.67-0.02) = 93.5% Eutectoid ferrite = total ferrite proeutectoid ferrite = 93.5 44.9 = 48.6%

Problem A hypoeutectoid steel contains 22.5% eutectoid ferrite. What is the average carbon content? Total ferrite= proeutectoid ferrite + eutectoid ferrite (6.67-x)/(6.67-0.02) = (0.80 x)/(0.8-0.02) + 0.225 X =0.2

Jominy Hardenability Test

Intermediate Phases - Cu-Zn Example

Hypoeutectoid Phase Diagram If a steel with a composition x% carbon is cooled from the Austenite region at about 770 C ferrite begins to form. This is called proeutectoid (or pre-eutectoid) ferrite since it forms before the eutectoid temperature.